Which number is a part of the solutions for the inequality
7x- 5 ≥ −2
Answers
Answer:
Adding
(
−
x
+
5
)
on both sides, we get,
7
x
−
5
−
x
+
5
≥
x
+
1
−
x
+
5
⇒
6
x
≥
6
Step-by-step explanation:
Related Questions
Order the steps to show how to solve the equation 2(4x−11)+9=19.
Answers
Answer:
4
Step-by-step explanation:
2(4x-11)+9=19
8x-22+9=19
8x-13=19
8x=32
x=4
please help ASAP!!!!
Answers
Answer:
B.
Step-by-step explanation:
Plug in the x-values for x in the answer choices. The result will be the y-value of the table.
For example,
A. 3(-1)^2+3(-1)-2 = -2
That is not the y-value for -1, so A is not the answer.
B. 3(-1)^2-3(-1)-2=4.
4 works here, but make sure to try all the numbers.
3(0)^2-3(0)-2 = -2
3(3)^2-3(3)-2 = 16
B is the answer because with each x-value you substitute in for x, you get its corresponding y-value.
(-1,4) (0,-2) (3,16)
Hello! Please answer this question with all of the info it is asked for. Please be sure to include all of your work and share any of your thoughts you had when solving. Please do not answer unless you know the answer. Thanks! Good Luck!
A football is kicked straight up into the air from 3 feet above the ground with an initial velocity of 208 ft/s. The function that models the ball's height is: h(t) = -16t^2 + 208t + 3.
a) Find how long it takes for the football to reach its maximum height.
b) Determine how long the football was in the air (approximately). Why might this not quite be accurate?
c) Determine the maximum height of the football.
Answers
Answer:
a) 6.5 secondsb) 13 secondsc) 679 ftStep-by-step explanation:
Given function:
h(t) = -16t^2 + 208t + 3a) Maximum height is the vertex. The ball reaches the maximum after:
h = -208/2(-16) = 6.5 secondsb) Time the ball was in the air:
-16t^2 + 208t + 3 = 0Solving we get approximately t = 13 seconds
c) Maximum height is at vertex, we found t above:
h(6.5) = -16(6.5)^2 + 208*6.5 + 3 = 679 ftMolly works at an electronics store. Her last customer purchased a DVD player for $67.43 and five DVDs for $57.50, including taxes. If the customer paid her with two $100 bills, how much change should she give him?
A.
$75.07
B.
$132.57
C.
$66.27
D.
$142.50
Answers
Given f(x) = 2x2 − 3x + 7, find f(2.5)
Answers
Answer:
12
Step-by-step explanation:
Given that,
f(x) = 2x² - 3x + 7
To find the value of f ( 2.5 ), replace x with 2.5 and solve the equation.
Let us solve it now.
f(2.5) = 2(2.5)² - 3×2.5 + 7
f(2.5) = 12.5 - 7.5 + 7
f(2.5) = 12
Answer:
\(f(x) = 2 {x}^{2} - 3x + 7 \\ f(2.5) = 2 {(2.5)}^{2} - 3(2.5) + 7 \\ f(2.5) = 12.5 - 7.5 + 7 \\ \boxed{f(2.5) = 12}\)
f(2.5) = 12 is the right answer.help please
3/11 × 4/9 =
Answers
Answer:
4/33
Step-by-step explanation:
Multiply 3x4 across which equals 12
Multiply 11x9 across which equals 99
Simplify to equal 4/33
Hope this helps!! :)
Answer:
Exact Form:
433
Decimal Form:
0.¯¯12¯¯
Step-by-step explanation:
An aquarium holds 11.35 cubic feet of water, and is 2.6 feet long and 1.1 feet wide. What is its depth? Round your answer to the nearest whole number.
The depth is
feet.
Answers
The depth of the aquarium is approximately 4 feet when rounded to the nearest whole number (since 3.64 is closer to 4 than it is to 3 when rounded to the nearest whole number).
To calculate the depth of the aquarium, we need to use the formula for volume of a rectangular prism,
which is V = lwh where V is the volume, l is the length, w is the width, and h is the height (or depth, in this case).
Given that the aquarium holds 11.35 cubic feet of water, the volume of the aquarium can be represented by V = 11.35 cubic feet.We are also given that the length of the aquarium is 2.6 feet and the width is 1.1 feet.
Substituting these values into the formula for volume,
we get:11.35 = 2.6 × 1.1 × h
Simplifying this expression:
11.35 = 2.86h
Dividing both sides by 2.6 × 1.1,
we get:h ≈ 3.64 feet (rounded to two decimal places)
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Click on the graph to plot a point. Click a point to delete it.
Answers
The red dot on the graph is (2, -8)
A cylinder has a radius of 4 millimeters. Its volume is 200.96 cubic millimeters. What is the height of the cylinder?
Answers
Answer:
3.999 millimeters.
Step-by-step explanation:
To find the height of the cylinder, we can use the formula for the volume of a cylinder:
V = πr²h
Given that the radius (r) of the cylinder is 4 millimeters and the volume (V) is 200.96 cubic millimeters, we can substitute these values into the formula and solve for the height (h).
200.96 = π(4²)h
200.96 = 16πh
To solve for h, we can divide both sides of the equation by 16π:
200.96 / (16π) = h
Using a calculator, we can calculate the approximate value of h:
h ≈ 200.96 / (16 × 3.14159)
h ≈ 3.999
Therefore, the height of the cylinder is approximately 3.999 millimeters.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Which statement is true about the function f(x)= V-x?
• The domain of the graph is all real numbers.
• The range of the graph is all real numbers.
The domain of the
graph is all real numbers less than or equal to 0.
The
range of the graph is all real numbers less than or equal to 0.
Answers
Answer:
90
Step-by-step explanation:
1+1=2
For the equation f(x) = 1.1 * (0.44) ^ x state the initial value C, the growth or decay factor a, and percent change R for each unit increase in x
c = (Type an integer or a decimal)
a = (Type an integer or a decimal)
R = % (Simplify your answer. Type an integer or a decimal)
Answers
The parameters of the exponential function in this problem are given as follows:
c = 1.1.a = 0.56.R = -56%.What is an exponential function?The standard format of an exponential function is given as follows:
y = c(1 - a)^t.
This is the case for a decaying exponential function, and the meaning of each parameter is given as follows:
c is the initial value, value assumed by y when t = 0.a is the decay rate.In this problem, the function is given as follows:
f(x) = 1.1(0.44)^x.
Hence the values for the parameters are given as follows:
c = 1.1, which is the initial value.a = 0.56, as 1 - a = 0.44 -> a = 0.56.Then the percent of change is of -56%, as it is a decaying exponential function with a = 0.56.
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find the arthmetic and the geometric means of 4 and 9
Answers
Answer:
Step-by-step explanation:
first term (a) = 4
last term (b) = 9
Arithmetic mean (AM)
= ( a + b) / 2
= ( 4 + 9 ) / 2
= 13/2
= 6.5
Geometric mean (GM)
= √a *b
=√4 * 9
=√36
= 6
hope it helps :)
What the meaning of statement this?
Answers
This statement essentially establishes a relationship between the sets X, Y, and z, stating that there exists a subset Y for each element x in X such that the elements in Y are present in some subset z of X.
The given statement is a symbolic representation of a logical proposition involving quantifiers and logical connectives. Let's break down its meaning:
∀ X ∃ Y ∀u(u ∈ Y ↔ ∃z(z ∈ X ∧ u ∈ z))
The symbol ∀ (universal quantifier) indicates that the statement applies to all elements in the set X.
The symbol ∃ (existential quantifier) indicates that there exists at least one element in the set Y.
The statement can be interpreted as follows:
"For all elements x in the set X, there exists a set Y such that for every element u in Y, u is an element of Y if and only if there exists a set z in X such that u is an element of z."
In simpler terms, the statement asserts that for every element x in the set X, there is a set Y that contains elements u if and only if there exists a set z in X that also contains u.
It is important to note that the precise meaning and implications of this statement may depend on the context and interpretation of the sets X, Y, and their elements.
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Is 7-¹ a negative number? Explain.
Answers
Answer:
No
Step-by-step explanation:
\(7^{-1}\) is a fraction
using the rule of exponents
• \(a^{-m}\) = \(\frac{1}{a^{m} }\)
then
\(7^{-1}\) = \(\frac{1}{7^{1} }\) = \(\frac{1}{7}\) ← that is a fraction
The measure of one small angles of a right triangle is 45 less than twice the measure of the other small angle. Find the measure of both angles
Answers
Answer:
x + x - 45 = 90
2x - 45 = 90
2x = 135
x = 67.5, so x - 45 = 22.5
The other two angles measure 22.5° and 67.5°.
A rectangular room is
1.5
times as long as it is wide, and its perimeter is
35
meters. Find the dimension of the room.
The length is :
meters and the width is
meters.
Answers
The dimensions of the room are approximately 7 meters by 10.5 meters.
The length is 10.5 meters and the width is 7 meters.What are dimensions?In Mathematics, dimensions are referred to as measures of size such as length, width, and height of an object or a shape. A rectangle has length and width as its dimensions that define the area of a rectangle.
Let's start by using algebra to represent the information given in the problem. Let x be the width of the rectangular room, then the length is 1.5 times the width or 1.5x.
The perimeter of a rectangle is the sum of the lengths of all its sides, which can be expressed as:
\(\text{Perimeter} = 2(\text{length} + \text{width})\)
Substituting the values we have for length and width, we get:
\(\rightarrow35 = 2(1.5\text{x} + \text{x})\)
Simplifying the equation, we get:
\(\rightarrow35 = 2(2.5\text{x})\)
\(\rightarrow35 = 5\text{x}\)
\(\rightarrow\text{x}=\dfrac{35}{5}\)
\(\rightarrow\bold{x\thickapprox7}\)
So the width of the room is 7 meters.
To find the length, we can substitute x into the expression we have for the length:
\(\rightarrow\text{Length} = 1.5\text{x}\)
\(\rightarrow\text{Length} = 1.5(7)\)
\(\rightarrow\bold{Length=10.5}\)
So the length of the room is 10.5 meters.
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which of the following instructional adjustments can the teacher make to best assess all of the students' understanding of multiplying two-digit numbers?
Answers
the following instructional adjustments or educational adjustments can the teacher make to best assess all of the students' understanding of multiplying two-digit numbers : Asking multiple students to share and defend their solutions before acknowledging the correct answer.
The discussion allows the teacher to observe how students solve the problems that involves multiplying two-digit numbers. It will also allow students to express themselves before they realize their answer is incorrect.
Educational Adjustments to teaching could be described as the continuing adjustments that teachers develop to adjust teaching and learning based on research in order to enhance students' attainment of intended instructional aims.
Educational Adjustments are steps or changes that facilitate students to receive educational content and results on a comparable level to facilitate students to receive educational content and results on a comparable level as their peers.
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Complete question :
Which of the following instructional adjustments can the teacher make to best assess all of the students' understanding of multiplying two-digit numbers?
1. Allowing students to write their answers on paper, then collecting the papers at the end of the lesson
2. Asking multiple students to share and defend their solutions before acknowledging the correct answer
3. Asking students who did not hold up their thumbs to share their answer and explain
4. Having Billy work the problem out on the board in front of the class
The function f(x) = −(x + 5)(x + 1) is shown.What is the range of the function?
all real numbers less than or equal to 4
all real numbers less than or equal to −3
all real numbers greater than or equal to 4
all real numbers greater than or equal to −3
Answers
The range of the function include the following: A. all real numbers less than or equal to 4
What is a range?In Mathematics, a range is the set of all real numbers that connects with the elements of a domain.
Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.
By critically observing the graph shown below, we can reasonably and logically deduce the following domain and range:
Domain = -5 ≤ x ≤ 0 or [-5, 0].
Range = -5 ≤ y ≤ 5, {y|y ≤ 4}, or [-5, 4].
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I really need help doing this. please help me.
Answers
The bisector angle is angle PQT which is equal to angle RQT.
What is angle bisector?Angle bisector or a bisector angle is a type of angle obtained after dividing the initial angle into two equal parts.
The bisected angle can be obtained using a pair of compass and a pencil attached to it.
To bisect the given angle RQP; we will take the following steps;
place the compass on exactly point Qexpand the radius of the compass such that the pencil attached to the compass will be in between R and P.strike an arc with the pencil clock wisestrike another arc with the pencil anti clock wise such that the two arc intersects.draw a line from point Q to intersect the two arcs.label the point of intersection of the two arcs Tangle PQT is equal to angle RQTLearn more about bisector angles here: https://brainly.com/question/24334771
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Write the next three terms of the geometric sequence 81, -27, 9, -3,...
Answers
1, -1/3, 1/9
it is divided by negative 3 or -3
To find that you need to divide the the first term with the next term
81÷-27=-3
will report anybody who gives a link!
3,947 ÷ 45 = (?) R (?)
Answers
Answer:
87.7(1)
=
87 Remainder 32
An experiment consists of spinning the spinner once. a: Find the probability of landing on a 2. b: find the probability of landing on a 1. c: Is landing in each section of the spinner equally likely to occur? Explain.
Answers
Answer:
points
Step-by-step explanation:
Use the following frequency distribution of the weights in lb of 100 college students. Get the mean, the variance and the standard deviation. What is the range of weights from one standard deviation, below the mean to the mean?
Interval Frequency (f)
130 – 139
140 – 149
150 – 159
160 – 169
170 – 179
180 – 189
4
15
28
33
14
6
Total f=100
Answers
The required mean and standard deviation of the frequency distribution of weights is 160.10 and 11.94 respectively.
Statistic is the study of mathematics that deals with relations between comprehensive data.
Here,
From the table,
Mean = ∑fx / ∑f
Mean = 16010 / 100
Mean = 160.10
Standard deviation,
σ = √∑fd²/∑f
σ = √14265/100
σ = 11.94
The required range of weights from one standard deviation, below the mean is given as
= 160.10 - 11.94 ≤ mean
Thus, the required mean and standard deviation of the frequency distribution of weights is 160.10 and 11.94 respectively.
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A
B
C
D
Pick a letter
Answers
Answer: D
Step-by-step explanation:
1 in.=1488 milesx5=7440 miles.
Area= pi x r^2
=pi x (7440)^2 or option D.
Hope this helps :)
What is the value of y when x = 0? first person to answer I will mark brainiest
Answers
Answer:
The point in which the graph crosses the x-axis is called the x-intercept and the point in which the graph crosses the y-axis is called the y-intercept. The x-intercept is found by finding the value of x when y = 0, (x, 0), and the y-intercept is found by finding the value of y when x = 0, (0, y).
Step-by-step explanation:
Hope this helped! Have a nice day!
Let Xi = (i =1,2,3) be independently and normally distributed random variable with mean of 4 as variance i. state the distribution of the following random variable
i) V = X1+X2+X3
Answers
The sum of normally distributed random variables is also a normally distributed random variable.
Given \(n\) random variables with \(X_i\sim\mathrm{Normal}(\mu_i,\sigma_i^2)\), their sum is
\(\displaystyle\sum_{i=1}^n X_i \sim \mathrm{Normal}\left(\sum_{i=1}^n \mu_i, \sum_{i=1}^n \sigma_i^2\right)\)
i.e. normally distributed with mean and variance equal to the sums of the means and variances of the \(X_i\).
In this case, each of \(X_1,X_2,X_3\) are normally distributed with \(\mu=4\) and \(\sigma^2\) = ... I'm not sure what you meant for the variance, so I'll keep it symbolic. Then
\(V = X_1+X_2+X_3 \sim \mathrm{Normal}(12, 3\sigma^2)\)
A collection of dimes and nickels has a total value of two dollars and contains 28 coins. How many dimes are there in the collection?
A.)14 dimes
B.)8
C.)12
D.)10
Answers
Answer:
12 dimes
Step-by-step explanation:
Let :
Dime = x
Nickel = y
Dime is worth 10 cent = $0.1
Nickel is worth 5 cent = $0.05
x + y = 28 - - - (1)
0.1x + 0.05y = 2 - - - (2)
From (1)
x = 28 - y
0.1(28 - y) + 0.05y = 2
2.8 - 0.1y + 0.05y = 2
2.8 - 0.05y = 2
2.8 - 2 = 0.05y
0.8 = 0.05y
y = 0.8 / 0.05
y = 16
x = 28 - 16
x = 12
Estimate the slope of the tangent line (rate of change) to f(x) = ² at x = -1 by finding the slopes of
the secant lines through the points:
a. (-2,4) and (0,0)
secant slope, msec=
b. (-1.5, 2.25) and (-0.5, 0.25)
secant slope, msec=
Answers
a. The secant slope through (-2,4) and (0,0) is -2.
b. The secant slope through (-1.5,2.25) and (-0.5,0.25) is -2.
The estimated slope of the tangent line to f(x) = x^2 at x = -1 is approximately -2.
To estimate the slope of the tangent line to the function f(x) = x^2 at x = -1, we can find the slopes of the secant lines through different pairs of points.
a. (-2,4) and (0,0):
The coordinates of the two points are (-2, 4) and (0, 0). We can calculate the slope of the secant line passing through these points using the formula:
msec = (y2 - y1) / (x2 - x1)
Plugging in the values, we get:
msec = (0 - 4) / (0 - (-2))
= -4 / 2
= -2
So, the slope of the secant line passing through (-2, 4) and (0, 0) is -2.
b. (-1.5, 2.25) and (-0.5, 0.25):
The coordinates of the two points are (-1.5, 2.25) and (-0.5, 0.25). Using the slope formula, we can calculate the slope of the secant line passing through these points:
msec = (0.25 - 2.25) / (-0.5 - (-1.5))
= (-2) / (1)
= -2
So, the slope of the secant line passing through (-1.5, 2.25) and (-0.5, 0.25) is -2.
By finding the slopes of the secant lines, we have estimated the rate of change of the function f(x) = x^2 at x = -1. The slope of the tangent line at this point will be very close to these secant slopes, particularly as the two points used to calculate the secant lines get closer together.
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Identify the level of measurement of the data, and explain what is wrong with the given calculation. In a survey, the favorite sports of respondents are identified as 100 for basketball comma 200 for baseball comma 300 for football comma and 400 for anything else. The average (mean) is calculated for 597 respondents and the result is 256.1 .The data are at the _________________
level of measurement.
Answers
Answer:
The data are at the Nominal level of measurement.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement.
Step-by-step explanation:
The objective here is to Identify the level of measurement of the data, and explain what is wrong with the given calculation.
a)
The data are at the Nominal level of measurement due to the fact that it portrays the qualitative levels of naming and representing different hierarchies from 100 basketball, 200 basketball, 300 football, 400 anything else
b) We are being informed that, the average (mean) is calculated for 597 respondents and the result is 256.1.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement. At nominal level this type of data set do not measure at all , it is not significant to compute their average (mean).