What happens to the intensity of a sound wave as it spreads out from a point source?
Answers
The intensity of a sound wave as it spreads out from a point source decreases due to the inverse square law.
A point source emits sound waves uniformly in all directions.
As the sound waves travel away from the source, they spread out over a larger area.
According to the inverse square law, the intensity of the sound wave is inversely proportional to the square of the distance from the source.
Mathematically, this can be represented as Intensity \(= Power / (4\pi * Distance^2).\)
In summary, the intensity of a sound wave decreases as it spreads out from a point source due to the inverse square law, which states that intensity is inversely proportional to the square of the distance from the source.
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Related Questions
you slide a slab of dielectric between the plates of a parallel-plate capacitor while keeping the charges on the plates constant. what happens to v, the potential difference between the two plates, and u, the potential energy of the capacitor?
Answers
Decrease in potential difference causes decrease in potential energy.
A dielectric produces an internal electric field when it is exposed to an electric field because the dielectric is polarized. The potential difference between the plates is caused by the internal electric field within the dielectric, which is in the opposite direction of the field between the plates of the capacitor. As a result, the effective electric field between the plates of the capacitor diminishes.
E = ΔV/Δr
Where, Δr = distance between plates, which is constant
Potential energy of a capacitor is;
U = (1/2)qΔV
Where, Charge is constant .
Therefore, potential energy U likewise drops as a result of the potential difference V being smaller.
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help please :)))))))))))
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How much will stretch a spring that has spring constant of 735 N/m, if you vertically hung a 2. 30 kg object from it. How much work must an external agent do to stretch the same spring 6. 50 cm from its unstretched position?
Answers
Answer:
Part 1 = 0.03m, Part 2 = 1.4651J
Answer:
F = - K X
X = -F / K = M g / K = 9.8 * 2.3 / 735 = .03 m = 3 cm
W = 1/2 K X^2
W = 1/2 * 735 N/m * .065^2 m^2 = 1.55 Joules
One exciting fairground ride acts like a gaint catapuit. The capsule which the 'rider' is strapped in is fired high into the sky by rubber straps Explain the erengy changes taking place in the ride.
Answers
Elastic energy of rubber straps is converted into the kinetic energy of the capsule which is converted into gravitational potential energy as capsule.
What is energy transformation?In accordance with the law of energy conservation, energy is neither created nor destroyed but can be converted from one form to another. This implies that energy is not lost and continues to exist.
The energy conversion that takes place as the 'rider' is strapped in is fired high into the sky by rubber straps is elastic energy of rubber straps is converted into the kinetic energy of the capsule which is converted into gravitational potential energy as capsule.
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how do the allowed orbits for electrons in atoms differ from the allowed orbits for planets around the sun? explain how the correspondence principle applies here.
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The movement occurs as . Each orbit has a different energy, and electrons can move to other orbits by emitting or absorbing energy, which is also quantized.
The correspondence principle in physics states that the behavior of systems described by quantum mechanics theory reproduces classical physics in the limit of large quantum numbers.Bohr's correspondence principle is best understood as the statement that each allowed quantum transition between stationary states corresponds to one harmonic component of classical motion, according to the selection rule interpretation.To know more about Correspondence principle here
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A man walks 200m for 10s to the west then continue in the same directions for another 100m for another 10s. what is the velocity of the man?
Answers
Answer:
15m/s
Explanation:
velocity = displacement/time
= (200+100)/20 = 300/20 = 15m/s
An object is in projectile motion if it?
Answers
Answer:
A projectile is an object upon which the only force is gravity. ... The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity. Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity.
At the observation location, what is the direction of propagation of the electromagnetic radiation?
Answers
The electromagnetic radiation propagates in a direction perpendicular to the plane in which the electric field and magnetic field are located.
Electromagnetic radiation is a phenomenon that takes the form of self-propagating energy waves as it travels through space (vacuum or matter). It consists of both electric and magnetic field components. The energy waves oscillate in phase perpendicular to each other and perpendicular to the direction of energy propagation. It is observed that the longer the wavelength involved, the lower would be the frequency as well as the energy. Electromagnetic radiation is classified into several types according to the frequency of its wave. These types include (in order of decreasing frequency and increasing wavelength) cosmic radiation, gamma radiation, X-ray radiation, ultraviolet radiation, visible radiation, IR radiation, terahertz radiation, microwave radiation, and radio waves.
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If a grasshopper can jump straight upward to a height of 0.430 , what is its initial speed as it leaves the ground?
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The initial velocity of the grasshopper as it leaves the ground is 1.90 m/s. We can calculate the initial velocity using the kinematic equation vf² = vi² + 2ad where vf = 0, a = g = 9.81 m/s², and d = 0.430 m. The initial velocity of the grasshopper is found to be 1.90 m/s.
The initial speed at which the grasshopper leaves the ground is to be determined given that the grasshopper can jump straight upwards to a height of 0.430 m.
To determine the initial speed, we will use the kinematic equation:
vf² = vi² + 2ad where, vi is the initial velocity of the grasshopper
vf is the final velocity of the grasshopper
d is the height attained by the grasshopper
a is the acceleration due to gravity
We know that the acceleration due to gravity is a constant, g = 9.81 m/s², since the grasshopper jumps straight upwards, the final velocity is zero, and the distance travelled is equal to the height attained, which is 0.430 m.
Substituting these values in the above equation, we have:
0 = vi² + 2 × 9.81 × 0.430
Simplifying the equation, we get
vi = √(2 × 9.81 × 0.430) = 1.90 m/s
Therefore, the initial speed at which the grasshopper leaves the ground is 1.90 m/s.
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A bus covers 200m in 5 second.Calculate its speed.
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A FORCE OF 3,200 N WEST is applied to a 160 kg mass. What is the acceleration of the mass
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. Hi I’m sorry to hear about the family and stuff but I’m still coming in for the day so I’m not going out to the beach today or just a little later lol lol I’m going on the beach with the girls lol I just need a shower lol I need a shower lol I’m just going on the
shear stress developed in regions BC and DE of the shaft. ... at a section located at A due to the rod's weight. ... 0.008488 rad = 0.486°.
Answers
Shear stress can be caused by a variety of factors, including torsional loading, bending, and twisting, in regions BC and DE of the shaft. These stresses can cause deformation, which can lead to shaft failure if not properly designed and manufactured.
The weight of the rod also contributes to the shear stress in section A. The shear stress equation, which is proportional to the force applied and the area over which the force is applied, can be used to calculate the amount of stress.
The angle of 0.008488 radians or 0.486° may represent the shaft's angle of twist due to torsional loading, which can also cause shear stress in the shaft. It is critical to consider the angle of twist when designing and analyzing the shaft to ensure that it can withstand the applied loads without failure.
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explain how increasing the volume in which a gas is contained, at constant temperature can lead to a decrease in pressure
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When the volume in which a gas is contained is increased at a constant temperature, the pressure of the gas will decrease. This relationship between volume, pressure, and temperature is described by Boyle's law, which states that the pressure of a gas is inversely proportional to its volume, at constant temperature.
Here's how increasing the volume of a gas can lead to a decrease in pressure:
1. Gas molecules have kinetic energy: Gas molecules are in constant random motion and have kinetic energy. When gas is contained in a smaller volume, the gas molecules collide more frequently with the walls of the container, resulting in higher pressure.
2. Decreased number of collisions: When the volume of the container is increased, the gas molecules have more space to move around, and the frequency of collisions with the walls of the container decreases. This reduction in collisions leads to a decrease in pressure.
3. Decreased concentration of gas molecules: Increasing the volume of a gas container also leads to a decrease in the concentration of gas molecules in the container. This means that there are fewer gas molecules per unit of volume, resulting in lower pressure.
4. Decreased force per unit area: When the volume of the container is increased, the same number of gas molecules now occupy a larger volume, resulting in a lower force per unit area exerted by the gas molecules on the walls of the container. This lower force per unit area leads to a decrease in pressure.
Therefore, when the volume in which a gas is contained is increased at a constant temperature, the pressure of the gas decreases due to the decreased number of collisions, decreased concentration of gas molecules, and decreased force per unit area exerted by the gas molecules on the walls of the container. This relationship is described by Boyle's law, which is an important principle in the study of gases.
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Consider each of the electric- and magnetic- field orientations given next. In each case, what is the direction of propagation of the wave? ( a) E in the +x direction, B in the +y direction; ( b) E in the -y direction, B in the +x direction; ( c) E in the +z direction, B in the -x direction.
Answers
Given the electric- and magnetic- field orientations, we need to determine the direction of propagation of the wave.
This can be determined using the right-hand rule.
To apply the right-hand rule to determine the direction of an electromagnetic field, follow these steps:
Extend your right hand and orient your thumb, index finger, and middle finger perpendicular to each other, creating a three-dimensional coordinate system.Assign the following directions to your fingers: a) Thumb: Represents the direction of the motion of a positive charge or conventional current (from positive to negative). b) Index finger: Indicates the direction of the magnetic field lines. c) Middle finger: Indicates the direction of the induced electric field, if applicable.To determine the direction of the electromagnetic field, align your fingers according to the specific scenario you are considering.a) E in the +x direction, B in the +y direction:
For a wave with electric field in the +x direction and magnetic field in the +y direction, the direction of propagation of the wave is in the -z direction.
b) E in the -y direction, B in the +x direction:
For a wave with electric field in the -y direction and magnetic field in the +x direction, the direction of propagation of the wave is in the +z direction.
c) E in the +z direction, B in the -x direction:
For a wave with electric field in the +z direction and magnetic field in the -x direction, the direction of propagation of the wave is in the +y direction.
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3. Is it possible for an object at rest to have forces acting upon it? Explain.
Answers
Answer:
Yes
Explanation:
It is possible for an object at rest to have forces acting upon it. An object at rest has two distinct system of forces that can keep it at rest:
When no force is acting on an object, we can conclude that it is at rest. Also, when the forces acting on the object is balanced, it is also at rest.A body with balanced set of forces will be at rest.
Energy capturing bike Would the system be a good solution for the
rescue team? Why or why not?
Answers
Answer:
Human-powered generators are the best energy source for the rescue team. Evidence 1: Solar cells transfer energy from the sun to a battery. Evidence 2: Human-powered generators can be used to transfer energy any time someone is there to turn the crank.
hope it helps
pa brainliest po
An energy-capturing bike could potentially be a good solution for a rescue team, but its effectiveness would depend on several factors. Let's consider the pros and cons:
Pros:
1. Portability: A bike is a portable mode of transportation that can navigate through areas where larger vehicles might have difficulty reaching. This is particularly advantageous in rescue operations, where quick access to remote or rugged locations is often essential.
2. Energy Efficiency: The concept of an energy-capturing bike implies that the bike can generate and store energy while in use. If this energy can be harnessed to power essential equipment like communication devices, lighting, or even medical equipment, it can greatly extend the team's operational capabilities without relying solely on external power sources.
Cons:
1. Energy Generation Limits: The energy generated and captured by a bike might not be sufficient to power all the necessary equipment required in a rescue operation, especially if the operation lasts for an extended period or involves energy-intensive devices.
2. Physical Exertion: In rescue scenarios, the team members' physical energy and endurance are of paramount importance. If the energy-capturing system requires the rescuers to exert extra effort while riding the bike, it might negatively impact their overall performance and effectiveness.
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Planets A and B have the same mass, but planet A is half the size of planet B. Which statement correctly explains the weight you would experience on each planet? O A. You would weigh more on planet A because the distance between you and the planet's center of gravity would be smaller. B. You would weigh the same on both planets because the masses of the planets are the same. 2 C. You would weigh the same on both planets because your mass would be the same on both. D. You would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.
Answers
Answer:
I would say A
Explanation:
the closer you are to a planets center of gravity i feel you would weigh more.
Which way does the weight point in an FBD?
the answer would depend on the motion of the object
down
perpendicular to the surface
up
Answers
Answer:
the answer would depend on the motion if the surface
Which of these
is a term for the
process of
wearing rock
down by
friction?
A. rusting
B. dissolving
C. abrasion
D. exfoliation
Answers
Answer: C.
Explanation: Abrasion is where two things rub together causing friction, which in turn wears the rock down.
Ms. R has run an experiment that compares which fruit (apples, oranges, bananas, pears, and peaches) are people's favorites. Which type of graph should she use?
scatter plot graph
line graph
bar graph
Answers
Answer:
Its scatter plot graph.
Explanation:
I took the test and got it right soo your welcome.
What is the electric potential 3. 0×10−11 m from a proton (charge +e )? Let V=0 at r=[infinity]
Answers
This question involves the concepts of electric potential, charge, and distance.
The electric potential is "48 V".
ELECTRIC POTENTIALThe electric potential of a point in the vicinity of a charge is given by the following formula:
\(V=\frac{kq}{r}\)
where,
V = electric potential = ?k = Colomb's constant = 9 x 10⁹ N.m²/C²q = magnitude of charge = 1.6 x 10⁻¹⁹ Cr = distance from charge = 3 x 10⁻¹¹ mTherefore,
\(V = \frac{(9\ x\ 10^9\ Nm^2/C^2)(1.6\ x\ 10^{-19}\ C)}{3\ x\ 10^{-11}\ m}\)
V = 48 volts
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……………………………………………………………..?
Answers
Answer:
last is the answer.
increase the voltage in order to send energy faster.
The position of a particle along a straight-line path is defined by s=(t³−6t²−15t+7)ft, where t is in seconds. Determine the total distance traveled when t=9.00 s. What is the particle's average velocity at time t=9.00 s ? What is the particle's average speed at time t=9.00 s ?
Answers
To determine the total distance traveled when t = 9.00 s, we need to find the displacement between the initial and final positions of the particle.
Given:
s = t³ - 6t² - 15t + 7
To find the initial position, substitute t = 0:
s(0) = (0³) - 6(0²) - 15(0) + 7
s(0) = 7 ft
To find the final position, substitute t = 9.00 s:
s(9) = (9³) - 6(9²) - 15(9) + 7
s(9) = 729 - 486 - 135 + 7
s(9) = 115 ft
The displacement between the initial and final positions is:
Δs = s(9) - s(0)
Δs = 115 - 7
Δs = 108 ft
Therefore, the total distance traveled when t = 9.00 s is 108 ft.
To calculate the average velocity at time t = 9.00 s, we need to find the instantaneous velocity at that time.
The velocity function is the derivative of the position function:
v = ds/dt
Given:
s = t³ - 6t² - 15t + 7
Differentiating s with respect to t:
v = ds/dt = 3t² - 12t - 15
Substitute t = 9.00 s:
v(9) = 3(9²) - 12(9) - 15
v(9) = 243 - 108 - 15
v(9) = 120 ft/s
Therefore, the particle's average velocity at time t = 9.00 s is 120 ft/s.
To calculate the average speed at time t = 9.00 s, we need to find the total distance traveled divided by the time taken.
Average speed = total distance / time
Given:
Total distance = 108 ft
Time = 9.00 s
Average speed = 108 ft / 9.00 s
Average speed = 12 ft/s
Therefore, the particle's average speed at time t = 9.00 s is 12 ft/s.
Total distance traveled when t = 9.00 s: 108 ft
Particle's average velocity at time t = 9.00 s: 120 ft/s
Particle's average speed at time t = 9.00 s: 12 ft/s
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the length breadth and height of an object are 20 cm 15 cm 25 cm.find the volume and density
Answers
Complete Question:
The length, breadth and height of an object are 20 cm, 15 cm and 25 cm respectively. Its mass is 7 kg. Find its volume and density
Answer:
a. Volume of cuboid = 7500 cm³
b. Density = 0.000933 Kg/cm³
Explanation:
Given the following data;
Length = 20 cmBreadth = 15 cmHeight = 25 cmMass = 7 kga. To find the volume of the object.
An object that has a length, breadth and height is a cuboid.
Mathematically, the volume of a cuboid is given by the formula;
Volume of cuboid = length * breadth * height
Substituting into the formula, we have;
Volume of cuboid = 20 * 15 * 25
Volume of cuboid = 7500 cm³
b. To find the density of the object;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the formula;
\( Density = \frac {mass}{volume} \)
Substituting into the formula, we have;
\( Density = \frac {7}{7500} \)
Density = 0.000933 Kg/cm³
(c) if the angular speed of the ferris wheel is 0.025 rad/s, what is its radius?
Answers
The radius of the ferris wheel is approximately 125.6 meters.
The angular speed of a ferris wheel is the rate at which it rotates, measured in radians per second. To find the radius of the ferris wheel given its angular speed, we can use the formula:
Angular speed = linear speed / radius
We can rearrange this formula to solve for the radius:
Radius = linear speed / angular speed
We know that the angular speed of the ferris wheel is 0.025 rad/s, but we need to find the linear speed. To do this, we need to know the diameter of the ferris wheel. Let's assume the diameter is 60 meters.
The circumference of a circle is given by the formula:
Circumference = pi x diameter
So the circumference of the ferris wheel is:
Circumference = pi x 60 m
Circumference = 188.5 m
Since the ferris wheel takes one minute to complete a full revolution, the time it takes to complete one revolution is 60 seconds. Therefore, the linear speed of the ferris wheel is:
Linear speed = circumference / time
Linear speed = 188.5 m / 60 s
Linear speed = 3.14 m/s
Now we can substitute the values we know into the formula for radius:
Radius = linear speed / angular speed
Radius = 3.14 m/s / 0.025 rad/s
Radius = 125.6 meters
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2. A javelin is thrown through an angle of 30o to the horizontal. Find the time taken by the javelin to reach the maximum height if the initial velocity is 60ms-1 [ take g =10 ms-1]
Answers
Answer:
3 seconds
Explanation:
The initial velocity is 60 m/s at an angle of 30° to the horizontal, so we can calculate the initial velocity in the vertical direction as
Viy = Vi sin(θ)
Viy = 60 sin(30)
Viy = 60(0.5)
Viy = 30 m/s
Then, we can use the following equation to calculate the time that it takes to reach the maximum height.
\(\begin{gathered} v_{fy}=v_{iy}-gt \\ v_{fy}+gt=v_{iy} \\ gt=v_{iy}-v_{fy} \\ \\ t=\frac{v_{iy}-v_{fy}}{g} \end{gathered}\)At a maximum height the vertical velocity is 0 m/s, so replacing viy = 30 m/s, vfy = 0 m/s and g = 10 m/s², we get
\(\begin{gathered} t=\frac{30\text{ m/s-0m/s}}{10\text{ m/s}^2} \\ \\ t=\frac{30\text{ m/s}}{10\text{ m/s}^2} \\ \\ t=3\text{ s} \end{gathered}\)Therefore, the answer is 3 seconds
list the four possible subshells in the quantum-mechanical model.
Answers
S, P, D, and f are the four potential subshells in quantum mechanical theories. The angle momentum quantum number, l, is represented by these letters in numerical form.
What is subshells?A subshell is a group of states that make up a shell and are identified by the azimuthal quantum number, l. Subshells s, p, d, and f are represented by the values l = 0, 1, 2, and 3, respectively. The equation 2(2l + 1) states how many electrons can fit into a subshell at once.
The circular routes that electrons take in an atom's shells as they circle its nucleus. (In line with the Bohr Model). The primary quantum number, n, serves as a representation of the shells. Additionally, each shell is divided once more into many subshells.
Four subshells are present: s, p, d, and f.
For instance, the first shell has just one sub-shell, which is s.
There are two sub-shells in the second shell: s and p.There are three sub-shells in the third shell: s, p, and d.The remaining shells are made up of all four subshells: s, p, d, and f.
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differentiate between Physical and chemical changes with example
please help me !
Answers
Answer:
Physical change is a temporary change. A chemical change is a permanent change
examples of physical change are freezing of water, melting of wax, boiling of water, etc. A few examples of chemical change are digestion of food, burning of coal, rusting, etc.
I HOPE THIS WILL HELP YOUHAVE A GREAT DAY :)
Help, due in 10 minutes. Really confused. Thank you.
Answers
Answer: animal 4
Explanation: I think it is correct
kyle has a mass of 54kg and is moving at 3 m/s what is his kinetic energy
Answers
Answer:
243J
Explanation:
K.E = 1/2 x 54 x 3^2
K.E = 1/2 x 54 x 9
K.E = 1/2 x 486
K.E = 486/2
K.E = 243J