You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment building. You travel in the elevator 22.0 m upward to your floor, walk 12.0 m north to the door of your apartment, and then walk 6.0 m due east to your balcony that overlooks the street. Your friend is standing where you left her.
Now how far are you from your friend?
Express your answer with the appropriate units.

We will have the followin:

We know that:

So, the measurements are:

So, the measurements are approximately 7.87inch * 13.78inch * 19.69inch.

Answer:

The tension in the light rope must be equal to the weight of the bucket

Explanation:

Given that,

Constant velocity of bucket and direction of bucket in downward

We need to find the tension in the rope

Using given data,

When a bucket  moves downward with a constant velocity then the net force does not applied on the bucket.

So, The weight of the bucket will be equal to the tension in the light rope

In mathematically,

\(T=mg\)

Where, T = tension

m = mass of bucket

g = acceleration due to gravity

Hence, The tension in the light rope must be equal to the weight of the bucket.

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

Explanation:

According to work energy theorem

change in kinetic energy of truck = work done against it

work done against it = force x displacement

= - 850 x 8 = 6800 J

change in kinetic energy of truck = - 6800 J .

energy will be reduced by 6800 J

Answer:-6800

Explanation:

The phrase that most accurately describes its apparent motion in our sky against the background stars is west then Prograde - moving slower then Retrograde then Prograde - moving faster and at last east.

The apparent motion of a planet or other object as seen from Earth against a background of stars, moving from west to east (looking or viewing to the south - apparent right to left) which is called Prograde motion.

Retrograde motion is defined as "the apparent motion of a planet or other object as seen from Earth against the background of stars, moving from east to west (looking/viewing to the south - apparent left to right) motion."

When a superior planet (Mars, Jupiter, Saturn, Uranus, etc.) orbits the Sun at a distance greater than that of the Earth and is passed by the latter, which is moving with a higher relative velocity, the 'Superior' planet's normal direct motion appears to stop and then temporarily turn retrograde, giving it the appearance of undergoing a loop or zigzag in the sky.

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It is possible to study the connection between motivation, rewards, and production from a variety of angles, including those of economics, psychology, and physics.

Because producers are motivated to satisfy consumer demand, free markets offer a larger variety of commodities than any other system. What is created is under the control of the consumer.

In theory, free markets work best because supply and demand are efficiently distributed by an invisible hand. Yet, in practise, open markets are prone to manipulation, false information, and imbalances of power and knowledge, which also contribute to wealth disparity.

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Longitudinal waves

In a longitudinal wave the particles are displaced parallel to the direction the wave travels.

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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Answer:

30 degrees

Explanation:

Reflects off of mirror 1  at   60 degrees....this makes it incident to second mirror at 30 degrees ....then angle of reflection equals this angle of incidence = 30 degrees

See atached diagram

Answer:

C. The wax will cool down and become a solid again because the heat was removed.

Explanation:

The exploded star is called a black hole.

The time horizon of the black hole is an area of spacetime where gravitational pull is so intense that nothing, not even light or other electromagnetic waves, have the energy to pass through it.

It is believed that the first black holes appeared shortly after the big bang, in the beginning of the cosmos. When the core of an extremely massive star is collapsed on itself, stellar black holes are created.

A supernova, also known as an exploding star, is also brought on by this collapse and sends a portion of the star into space.

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Answer:

a) \(V_2=8m/s\)

b) \(P_2=9.54*10^4 Pa\)

Explanation

From the question we are told that:

Initial Area of pipe  \(A_1=8.00 cm^2\)

Initial Fluid flow speed \(r_1 =320 cm/s,\approx 320*10^{-2}\)

Initial Pressure of \(\rho_1 =1.40*10^5 Pa\)

Final area of pipe \(A_2 =3.70 *10^{-2} cm^2\)

Density of acid \(\rho=1660kg/m^3\)

a)

Generally the equation for continuity is mathematically given by

\(A_1V_1=A_2V_2\\\\V_2=\frac{A_1*V_1}{A_2}\)

Since volume is directly proportional to rate of flow

\(V_2=\frac{8*320}{3.20} *10^{-2}\)

\(V_2=8m/s\)

b)

Generally the Bernoulli's equation is mathematically given by

\(p_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_2+\frac{1}{2}\rho v_2^2+\rho gh_2\\\\with\ h_1=h_2\\\\p_1+\frac{1}{2}\rho v_1^2=P_2+\frac{1}{2}\rho v_2^2\)

Therefore

\(P_2=P_1+\frac{1}{2}\rho(v_1^2-V_2^2)\\\\P_2=(1.40*10^5)+\frac{1}{2}(1660)(v_1^2-V_2^2)\)

\(P_2=9.54*10^4 Pa\)

Explanation:

The satement that can be made about sound wave A and sound wave B is, they will slow down.

Relationship between sound wave and temperature

The relationship between sound waves and temperature is given by the following formula;

v= √γRT

The speed of sound wave increases with increase in temperature, and vice versa.

Speed of sound wave in liquid and gaseous medium

Sound wave is mechanical wave, because it requires material medium for its propagation. Sound will travel faster in liquid medium than gaseous medium because of number of molecules per unit volume.

Thus, the satement that can be made about sound wave A and sound wave B is, they will slow down.

Answer:

9000m

Explanation:

Given parameters:

Time  = 30s

Acceleration  = 20m/s²  

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use one of the kinematics equation.

     S  = ut + \(\frac{1}{2}\)at²  

u is the initial velocity = 0m/s

t is the time taken

a is the acceleration

           S  = (0 x 30) + ( \(\frac{1}{2}\) x 20 x 30² ) = 9000m

The slope of the graph represent for ohmic material is as per the graph is that the current will increases with increase in potential.

Ohmic material is defined as anything that complies with Ohm's law, according to which the current flowing through a device is proportional to the applied voltage. Ohmic materials are those that adhere to Ohm's law.

Ohm's Law describes the relationship between voltage and current, and the resistance in a circuit is represented by the slope of the line from a graph of the two quantities. The slope of the distance-time plot, or the speed of the body, is the ratio of the distance traveled by the body to the time required for travel.

Thus, the slope of the graph represent for ohmic material is as per the graph is that the current will increases with increase in potential.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer: kooi kooi

how r u and thanks for the free points :)

Answer:

The more massive an object is, the greater the gravitational force. Since gravitational force is inversely proportional to the distance between two interacting objects, more separation distance will result in weaker gravitational forces.

Explanation:

hope this help:)

Following are the answers:

1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:

Pressure = force/area

The force is the weight of the water column and the area is the cross-sectional area of the container.

The weight of the water column is given by the mass of the water times the acceleration due to gravity:

mass = density x volume

volume = area x height

So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg

Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N

The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)

So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa

2. To calculate the density of the oil, we can use the formula:

density = mass/volume

Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.

We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:

Pressure = force/area = density x acceleration due to gravity x height

So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.

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Answer:

The correct option is  C

Explanation:

From the question we are told that

    The distance between axles of the car  is  \(d_a = 6.2\)

     The position of the car's center of mass is  \(D = 2.2 \ m \ in \ front \ of \ the \ axel\)

Now  we can evaluate the distance of the center of mass to the rear axle as follows

        \(k = d_a - D\)

substituting values

      \(k = 6.2 - 2.2\)

      \(k = 4 \ m\)

assuming the car is   at equilibrium,  taking moment about the center of mass

          \(W_{front \ axle} * D - W_{rear \ axle} * k = 0\)

=>        \(W_{front \ axle} * D = W_{rear \ axle} * k\)

=>       \(\frac{W_{front \ axle}}{W_{rear \ axle} } = \frac{k}{D}\)

substituting values

             \(\frac{W_{front \ axle}}{W_{rear \ axle} } = \frac{4}{2.2}\)

           \(\frac{W_{front \ axle}}{W_{rear \ axle} } = 1.81\)       Note [\(W_{front \ axle}\) is the front axle weight  and  

                                                      \(W_{rear \ axle}\) is the rear axle weight  ]

Answer:

potential is at maximum

kinetic energy is zero

The displacement of the runner according to the graph is obtained as 250 m.

The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.

Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.

Given the graph as we have it, we can be bale to pick out the following from the graph;

1) Displacement of the runner at 100 s = 500 m

2) Displacement of the runner at 300 s = 750 m

Therefore;

Displacement of the runner between 100 and 300 seconds;

750 m - 500 m = 250 m

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It is defined as the stress that results in the elongation of the material

Answer:

False.

Explanation:

provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.

Answer:

These destructive frequencies entrain the thoughts towards disruption, disharmony, and disunity. Additionally, they also stimulate the controlling organ of the body — the brain — into disharmonious resonance, which ultimately creates disease and war.

If a frictionless plane is 10.0 m long and inclined at 36.0°.

We can use conservation of energy to find the distance that the first sled travels up the incline. The potential energy of the sled at the bottom of the incline is zero, and its kinetic energy is:

KE = (1/2)mv^2

where m is the mass of the sled and v is its speed. At the point where the sled stops, all of its kinetic energy has been converted into potential energy, so we can write:

mgh = (1/2)mv^2

where h is the height that the sled has traveled up the incline. Solving for h, we get:

h = (v^2)/(2g)

where g is the acceleration due to gravity. Using the given values, we have:

h = (6.00 m/s)^2 / (2 * 9.81 m/s^2) = 1.83 m

So the first sled travels a distance of 10.0 m - 1.83 m = 8.17 m up the incline.

b. To find the initial speed of the second sled, we can use conservation of energy again. At the top of the incline, the sled has potential energy:

PE = mgh

where h is the height of the incline. As the sled slides down the incline, its potential energy is converted into kinetic energy:

KE = (1/2)mv^2

where v is the speed of the sled at the bottom of the incline. We can equate these two expressions and solve for v:

mgh = (1/2)mv^2

v = sqrt(2gh)

Using the given values, we have:

v = sqrt(2 * 9.81 m/s^2 * 10.0 m * sin(36.0°)) = 12.2 m/s

So the second sled must be released from the top of the incline with an initial speed of 12.2 m/s.

The position of the sled as a function of time is given by:

y = -0.5gt^2 + Vi*t + h

where y is the vertical position of the sled, t is the time, Vi is the initial speed of the sled, and h is the height of the incline. At the bottom of the incline, y = 0, so we can solve for the time it takes for the second sled to reach the bottom:

0 = -0.5gt^2 + Vi*t + h

t = (Vi ± sqrt(Vi^2 - 2gh)) / g

Since we want both sleds to reach the bottom at the same time, we set the time for the first sled to slide down the incline equal to this expression for t and solve for Vi:

t = sqrt(2h/g) = sqrt(2 * 1.83 m / 9.81 m/s^2) = 0.619 s

0 = -0.5gt^2 + Vi*t + h

Vi = (h - 0.5gt^2) / t

Vi = (1.83 m - 0.5 * 9.81 m/s^2 * (0.619 s)^2) / 0.619 s

Vi = 5.68 m/s

So the initial speed of the second sled is about  5.68 m/s

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