A difference in the mass of the pod would greatly affect the force required by the thrusters to stop it. The larger the mass of the pod, the more force will be required to stop it. This is because the larger the mass, the more momentum it has and the harder it will be to stop.
The formula for momentum is p = mv, where p is the momentum, m is the mass, and v is the velocity. This means that the larger the mass and velocity of the pod, the more momentum it will have, and the more force will be required to stop it.
To stop the pod, the thrusters will need to exert an equal and opposite force to the momentum of the pod. This will cancel out the momentum and bring the pod to a stop. The larger the mass of the pod, the more force the thrusters will need to exert to cancel out the momentum and bring the pod to a stop.
Several factors can affect the mass of the pod, including the materials used in its construction, the payload it carries, and any additional equipment or systems it may have. For example, if the pod is made of lighter materials, it will have a lower mass and require less force to stop it. On the other hand, if the pod carries a heavy payload or has additional equipment installed, it will have a higher mass and require more force to stop it.
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A difference in the mass of the pod would have an effect on the amount of force needed to be exerted by the thrusters to stop it. This is because a pod with a large mass would require a lot of force to stop it. An object with a large mass will gain more momentum requiring more force to stop it.
The momentum formula is p = mv;
p represents momentum,
m is the mass,
v is the velocity.
This explains why a pod with a large mass will have more momentum and requiring more force to exerted to stop it.
So as to stop the pod, the thrusters will be required to exert an opposite and force which will eventually bring the pod to a stop.
The pod mass is determined by some factors such as the materials its made of and any load that its carrying. So, a pod made of heavy materials will need a lot of to be exert to stop it but one made of lighter materials will require less force to bring to a stop
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Rafael lives near a road at the bottom of the hill. His parents are concerned that soil will wash off the hill and rocks will fall onto the road. Rafeal converts an investigation to find out if grass growing on a hillside will help stop soil erosion. He collects two samples of the same size and type of soil. One sample of soil has grass growing on it and the other does not. He places each sample of soil in a small tray. For his investigation, Rafael pours the same amount of water onto both samples of soil. He uses a large tray to collect water that may flow through the soil. Which practice shows the best way for Rafael to set up this investigation?
Answer:
The first picture/option
Explanation:
The first picture/option shows the best way for Rafael to set up the investigation.
The experimental set-up must be in a sloppy position in order to simulate the condition that is characteristic of the bottom of the hill where he stays. Hence, the two soil samples must be tilted in order to determine if the grass can help to stop the washing down of the soil from the top of the hill.
The two options following the first option do not fulfill the condition of the same treatment. Both soil samples must be subjected to the same treatment condition in order for the outcome to be valid. The last option could have also been admissible but did not simulate the hill/slope conditions of where Rafael stays.
To set up his investigation on whether grass can help stop soil erosion on a hillside, Rafael can follow these steps: 1. Collect two samples of the same size and type of soil. This ensures that the only difference between the two samples is the presence of grass.
2. Place each sample of soil in a small tray. This allows Rafael to contain the soil and prevent it from mixing with each other.
3. Pour the same amount of water onto both samples of soil. This ensures that the water input is consistent for both samples, allowing Rafael to compare the effects of grass on soil erosion.
4. Use a large tray to collect water that may flow through the soil. This allows Rafael to measure and compare the amount of water runoff from both samples. By collecting the water, Rafael can determine if the grass on the hillside helps to retain more water and prevent soil erosion.
By following these steps, Rafael can compare the water runoff and soil erosion between the sample with grass and the sample without grass. This will provide him with evidence to determine if grass can effectively help stop soil erosion on a hillside.
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1. If a ball is rolling horizontally on the floor with a velocity of 2.5 m/s, what are the x and y
components of the velocity?
Vx =
Vy =
Answer: Vx = 2.5m/s and Vy = 0m/s
Explanation: The ball is rolling horizontally on the floor, meaning there isn't a change in the vertical position, only horizontal. The ball is rolling with pure horizontal motion and isn't moving in the vertical direction.
Un bloque de 30.0 kg esta sobre un plano inclinado 28 grados con respecto a la horizontal, si el coeficiente de fricción cinética es 0.200, calcula la fuerza paralela al plano que se debe ejercer sobre el bloque para que suba con velocidad constante.
Responder:
229.17NExplicación:
Las fuerzas que actúan paralelas al plano son la fuerza de movimiento y la fuerza de fricción.
La fuerza de movimiento Fm = Wsinθ y la fuerza de fricción Ff = nR donde;
W es el peso del objeto = mg = 30.0 * 10
W = 300N
θ es el ángulo de inclinación = 28 °
n es el coeficiente de fricción = 0,20
R es la reacción normal = Wcosθ
La fuerza paralela al plano que se debe ejercer sobre el bloque para que se eleve con rapidez constante será la suma de la fuerza de movimiento y la fuerza frictioal (son las dos fuerzas que empujarán el cuerpo hacia arriba del plano)
Fuerza total requerida = Fm + Ff
Fuerza total requerida = Wsinθ + n (Wcosθ)
Fuerza total requerida = 300sin28 ° + 0.2 (300cos28 °)
Fuerza total requerida = 140,84 + 52,98
Fuerza total requerida = 229.17N
Por tanto, la fuerza paralela al plano que se debe ejercer sobre el bloque para que se eleve con rapidez constante es aproximadamente 229,17 N
. A small toy car having 300 grams of mass and going straight with an initial velocity of 13 m/s. When the toy car collides with an obstacle, a resistive force of 4 N acts upon it. The speed of the toy car reduced and reached 8 m/s. Draw its free body diagram and then find the time for the toy car to be into rest position?
The free-body diagram is attached in the image below. The time for the toy car to be in rest position is 0.6 s
From the given information:
The mass of the toy car = 300 g = 0.3 kgThe initial velocity (u) of the car = 13 m/sThe resistive force F_r acting on the car = 4 NThe speed of the car (v) = 8 m/sA force is regarded as a push that causes an alteration in motion of an object within a specified distance. It is usually expressed by the formula:
Force = mass × acceleration∴
acceleration = Force/massacceleration = (4 / 0.3) m/s²acceleration = 13.33 m/s²Using the first equation of motion for the time to bring the car to rest from it reduced speed of 8 m/s;
v' = v + atsince the final speed to bring the car in rest position is (0), then:
0 = 8 - 13.33(t)
13.33(t) = 8
t = 8/13.33
t = 0.6 seconds
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The Bugatti Chiron is currently the fastest production car in the world reaching a top speed of 261 mph
the eskimo pushes the same 50.0-kg sled over level ground with a force of 2.30 102 n exerted horizontally, moving it a distance of 5.55 m over new terrain. if the net work done on the sled is 2.50 102 j find the coefficient of kinetic friction.
The coefficient of kinetic friction will be 0.376
What is kinetic friction?The quantity of decelerating force between two moving objects is known as kinetic friction, also known as sliding friction or moving friction. Understanding this is necessary to comprehend the coefficient of kinetic friction, which is calculated by dividing the force needed to keep an object moving by the force holding the two sliding surfaces together.
Given:
Mass of sled (m) = 50 kg
Force (f) = 2.30 x 10^2 N = 230 N
Distance (s) = 5.55 m
net work done on the sled = 2.50 x 10 ^2 N = 250 N
Acceleration due to gravity (g) = 9.8 m/s^2
Coefficient of friction = μ
Lets first calculate the frictional force (ff)
ff = μ x m x g
= μ x 50 x 9.8
= 490 μ
Work done on the slide by the applied force (W1)= f x s = 230 x 5.5 = 1265 j
Work done on slide by frictional force (W2) = ff x s = 490 μ x 5.5 = 2695μj
The work done by the frictional force is now deducted from the work done by the applied force to create the net work.
net work done = W1 - W2
250 = 1265 - 2695μ
2695μ = 1265 - 250
μ = 1015 / 2695
μ = 0.37
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Easy question pls help
which organic compound provides insulation and long-term energy storage
The organic compound that provides insulation and long-term energy storage are lipids.
option D.
What is a lipid?Lipids are a broad group of naturally-occurring molecules which includes;
fatswaxessterolsfat-soluble vitaminsmonoglyceridesdiglyceridesphospholipids, etc.The functions of lipids include storing energy, signaling, and acting as structural components of cell membranes.
Also, lipids are fatty, waxy, or oily compounds that are soluble in organic solvents and insoluble in polar solvents such as water.
Thus, the organic compound that provides insulation and long-term energy storage are lipids.
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Answer:
YOU ANSWER IS D.
Explanation:
Lipids perform many different functions in a cell. Cells store energy for long-term use in the form of lipids called fats. Lipids also provide insulation from the environment for plants and animals.
Which of the following statements are true about whether atoms tend to gain
or lose electrons?
A. Atoms with four valence electrons will always lose electrons.
B. Atoms with eight valence electrons easily lose electrons.
C. Atoms with five, six, or seven valence electrons will gain
electrons.
D. Atoms with one, two, or three valence electrons will lose
electrons.
Answer:
The true statements are;
C and D
Explanation:
The tendency of an atom to gain or lose electrons in a chemical reaction are given by its electronegativity and electropositivity respectively
Electronegativity is a measure of an atom's capacity to attract electrons from neighboring particles, with atoms that are more likely to gain an electron, being described as having a higher electronegativity
Electronegativity increases across the period with increasing number of valence electrons, therefore, elements with five, six, or seven electrons, which are located on the far right of the periodic table are said to have higher electronegativity and therefore more likely to gain electrons in a chemical reaction
Electropositivity is the quantification or measure of an element to donate or give electrons and become positively charged ions in a chemical reaction
The fewer the number of valence electrons an element has, the more likely the element will undergo a reaction by donating the valence electrons to a more electronegative atom and become positively charged
Electropositivity decreases across the period and therefore, elements with one, two, or three valence electrons which are located in groups I, II, and III, are more likely to lose electrons in a chemical reaction
Answer:
C+D
Explanation:
A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS AND
RAREFACTIONS IS SHOWN BELOW. A CENTIMETER RULER IS INCLUDED BELOW THE
PATTERN THE WAVELENGTH OF THIS SOUND WAVE IS HOW MANY cm?
A 2 cm
B 3 cm
C 35 cm
D. 85 cm
וייייייייייייייייי
U
0
1
2
3
4
5
6
7
8
9
10
Answer:
The wavelength is 1.7cm
Explanation:
Given
See attachment for wave pattern
Required
What is the wavelength
To do this, we simply calculate the distance between successive waves (see attachment 2 for point A and B)
Using the ruler, points A and B are at:
\(A = 0.6cm\)
\(B = 2.3cm\)
So, the wavelength is:
\(\lambda = B - A\)
\(\lambda = 2.3cm - 0.6cm\)
\(\lambda = 1.7cm\)
If approximated, the wavelength is:
\(\lambda \approx 2cm\)
kinetic energy is _____ proportional to the ____ velocity
directly amount
directly square
directly cube
inversely square
Answer:
Kinetic energy is DIRECTLY PROPORTIONAL TO MASS AND VELOCITY
Find the fundamental period (To) and frequency (Wo) of the following signal:
student submitted image, transcription available below
The fundamental period (To) of a signal is the smallest T for which it repeats. Frequency (Wo) is the reciprocal of To. Example: To = 0.5s, Wo = 2Hz.
The fundamental period (To) of a periodic signal is the smallest positive value of T for which the signal repeats itself exactly. The frequency (Wo) of a periodic signal is the reciprocal of the fundamental period,
Wo = 1/To.
To find the fundamental period and frequency of a signal, we need to analyze its waveform.
First, let's identify the period of the signal. The period is the horizontal distance between two adjacent peaks (or troughs) of the waveform. If the signal repeats itself exactly, it is periodic.
Once we have identified the period, we can calculate the fundamental period (To) by measuring the distance between two adjacent peaks (or troughs) and taking the smallest positive value.
To calculate the frequency (Wo), we can use the formula Wo = 1/To. Here's an example to illustrate this process:
Let's say the signal waveform repeats itself every 2 seconds. This means the period is 2 seconds.
To calculate the fundamental period (To), we measure the distance between two adjacent peaks (or troughs) and find it to be 0.5 seconds.
Therefore, the fundamental period (To) is 0.5 seconds.
To calculate the frequency (Wo), we use the formula Wo = 1/To. In this case, Wo = 1/0.5 = 2 Hz. So, the fundamental period (To) of the signal is 0.5 seconds and the frequency (Wo) is 2 Hz.
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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (30pts)
Answer:
5
Explanation:
From the attachement,
M.A = Load(L)/Effort(E)
M.A = L/E...................... Equation 1
Where M.A = .Mechanical Advantage, L = Load, E = Effort.
Given: L = 500 N, E = 100 N
Substitute these values into equation 1
M.A = 500/100
M.A = 5.
Hence the actual mechanical advantage of the pulley is 5
fill in the blanks (about force)
depends on _____ and _____
. Work done by a force depends upon force applied and displacement produced.
Complete each statement to identify the form of asexual reproduction.
During
, a new plant grows from parts of the parent plant.
During
, a cell divides to produce a new, genetically identical cell.
During vegetative propagation, a new plant grows from parts of the parent plant.
During binary fission, a cell divides to produce a new genetically identical cell.
Asexual reproduction involves fission, budding, fragmentation, and parthenogenesis, whereas sexual reproduction is achieved by combining the germ cells of two individuals. The statement describing asexual reproduction is Offspring are born that have the same DNA as the parent.
Only one parent is needed to produce a child. Includes cell division similar to cell division in mitosis. Asexual reproduction is a form of reproduction in which the offspring produced are exactly like their parents. Also, there is no formation of two different gametes, nor the involvement of two different sexes. In unicellular organisms, mitosis is the mode of asexual reproduction.
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What is the polarity of each of the earths magnetic poles ? Explain you answer
Answer:
When you put un-like poles together (South facing North) you can feel magnetic attraction. In the Northern Hemisphere, your compass needle points North, but if you think about it for a moment, you will discover that the magnetic pole in the Earth's Northern Hemisphere has to be a South polarity.
Holly is conducting an experiment in which she changes the voltage across a circuit and records the relative brightness of a light bulb in the circuit. She takes notes in the notebook below.
How might these notes be useful?
A.
They could help her teacher to understand what she did in the experiment.
B.
They could help someone interested in conducting the same experiment.
C.
They could help her remember the experiment in the future.
D.
all of these
Reset Submit
Answer:
all of these
Explanation:
Answer:
D.all of there
Explanation:
A ball is thrown up into the air with an initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed for the ball to reach its max height.
Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f} =v_{o} -g*t\)
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
\(y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\\)
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
Which object would sink in honey, which has a density of 1.4 g/cm³?
Object 1 (0.9 g/cm³)
Object 2 (1.2g /cm³)
Object 3 (0.2 g/cm³)
Object 4 (2.3 g/cm³)
Answer:
objective 4
Explanation:
i took the unit test review and the regular unit test
Object 4 with a density of 2.3 g/cm³ would sink in honey, which has a density of 1.4 g/cm³, therefore the correct option is option D.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
The mathematical formula for density is given below
ρ =m /v
where ρ is the density of the substance
m is the mass of the substance
v is the volume of the substance
As per the law of floatation, the objects those have less density than the honey do not sink in the honey which has a density of 1.4 g/cm³.
As per the given options, object 1 has a density of 0.9 g/cm³ which is less than the density of honey 1.4 g/cm³, therefore it would not sink in the honey. similarly, objects 2 and object, 3 have a density that is less than the density of the honey, therefore they would float instead of sinking in the honey.
The only object 4 has a density of 2.3 g/cm³ which is more than the density of honey, therefore it would sink on the honey.
Hence, the correct answer is object 4.
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In an evacuated tube electrons produce X-rays by accelerating from rest through a voltage of 0.39kV and striking a copper plate. Nonrelativistically, what would be the maximum speed of these electrons, in meters per second? v=
The maximum speed of these electrons, in meters per second would be 7.21 × 10⁵ m/s.
We know that kinetic energy of a charged particle in an electric field is given by qV= (1/2)mv² where, q is the charge of the particle, V is the voltage through which the particle has been accelerated, m is the mass of the particle, v is the velocity of the particle.
Using the above formula for v, we have; v= sqrt(2qV/m) Where v is the speed of the electrons. Non-relativistically, we can assume that the mass of an electron is 9.11 x 10⁻³¹ kg. q = 1.60 × 10⁻¹⁹ C (charge of the electron) and V = 0.39 kV.
v = sqrt((2 × 1.60 × 10⁻¹⁹ C × 0.39 kV)/(9.11 x 10⁻³¹ kg))v = 7.21 x 10⁵ m/s.
Therefore, the maximum speed of these electrons, in meters per second would be 7.21 × 10⁵ m/s.
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please help me solve all
parts
< Question 13 of 25) Heat is added to 1.00 mol of air at constant pressure, resulting in a temperature increase of 100'C. The molar specific heat ratio & for the air is 1.40. 7= If the same amount of
The molar specific heat ratio \(\gamma =\) \(C_p/C_v\) for the air is 1.40. Suppose the same amount of heat is instead added at constant volume. The temperature increase at constant volume is approximate \(71.43^0C\).
In this scenario, the molar specific heat ratio \(\gamma = C_p/C_v\) represents the ratio of the specific heat at constant pressure (\(C_p\)) to the specific heat at constant volume (\(C_v\)). For an ideal gas, this ratio is given by
\(\gamma = 1 + (2/\alpha)\),
where α is the degree of freedom.
Since air is a diatomic gas, it has five degrees of freedom (three translational and two rotational). Therefore, α = 5, and substitute this value into the equation
\(\gamma = 1 + (2/\alpha)\) to find \(\gamma = 1 + (2/5) = 1.40\).
When heat is added at constant pressure, and know that \(C_p = C_v + R\), where R is the gas constant. With this information, rearrange the equation to \(C_v = C_p - R\).
To determine the temperature increase\(\Delta T_v\) at constant volume, need to use the relationship \(\Delta Q = C_v\Delta T_v\), where ΔQ represents the amount of heat added. Since the same amount of heat is added in both cases and can equate the heat equations:
\(C_p\Delta T_p = C_v\Delta T_v\).
Using the known values,
\(C_p(100) = (C_p - R)\Delta T_v\)
By substituting
\(\gamma = C_p/C_v = 1.40\)
solving for \(\Delta T_v\),
\(\Delta T_v = 71.43^0C\)
Therefore, the temperature increase at constant volume is approximate \(71.43^0C\).
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The complete question is:
Heat is added to 1.00 mol of air at constant pressure, resulting in a temperature increase of \(100^0C\). The molar-specific heat ratio \(\gamma =\) \(C_p/C_v\) for the air is 1.40. Suppose the same amount of heat is instead added at constant volume. What is the temperature increase \(\Delta T_v\)?
Given: Rocket motor equation: " Ve + (Pe – Pa) AC Rocket weight (no propellant): 300 kg Propellant weight: 800 kg Acceleration at burnout: 10 18 G ur. First things first – the contribution of the pressure differential, (Pe - Pa)Ae is typically very small. Its contribution will be ignored for this problem. Compute the Isp required to develop a rocket with a burnout velocity of 1000 m/s. Compute the exit velocity (Ve or Vj) required for this rocket. Plot the rocket acceleration (in terms of G) and rocket weight as a function of time. What is the burn time of the rocket? Finally, plot the speed of the rocket, assuming a flight path angle of 45 degrees assuming no gravity. Plot the speed of the rocket considering gravity.
To develop a rocket with a burnout velocity of 1000 m/s, the specific impulse (Isp) required needs to be calculated. The exit velocity (Ve or Vj) required for the rocket can be determined using the rocket motor equation. The burn time of the rocket can be found by considering the rocket's weight and acceleration over time.
Additionally, the speed of the rocket, assuming a flight path angle of 45 degrees and considering gravity, can be plotted.
1. Calculating Required Isp:
To calculate the required Isp, we use the rocket motor equation: Ve + (Pe - Pa)AC = (m0 / mf) * g0 * Isp, where Ve is the exit velocity, Pe is the pressure at the exit, Pa is the ambient pressure, AC is the throat cross-sectional area, m0 is the initial total mass (rocket weight + propellant weight), mf is the final total mass (rocket weight), g0 is the acceleration due to gravity, and Isp is the specific impulse.
Since the contribution of the pressure differential is ignored, the equation simplifies to Ve = (m0 / mf) * g0 * Isp.
Given the burnout velocity of 1000 m/s, we can substitute the values and solve for Isp.
2. Determining Exit Velocity:
Using the rocket motor equation and the burnout velocity, we can solve for the exit velocity (Ve). This value represents the speed at which exhaust gases leave the rocket nozzle.
3. Plotting Rocket Acceleration and Weight:
To plot the rocket acceleration as a function of time, we need to consider the mass of the rocket over time. Initially, the rocket weight is the sum of the rocket weight (300 kg) and propellant weight (800 kg). As the propellant burns, the rocket weight decreases, resulting in a changing acceleration.
4. Calculating Burn Time:
The burn time of the rocket can be determined by dividing the propellant weight (800 kg) by the propellant consumption rate, which is the mass flow rate of the propellant.
5. Plotting Rocket Speed:
Assuming a flight path angle of 45 degrees and neglecting gravity, the rocket's speed can be plotted over time. This plot represents the rocket's horizontal velocity.
6. Considering Gravity:
To plot the rocket's speed while considering gravity, we need to account for the vertical acceleration due to gravity. By considering the rocket's horizontal and vertical velocities, we can determine the overall speed of the rocket.
By following these steps, the required Isp, exit velocity, burn time, and velocity plots can be determined for the given rocket scenario.
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describe two important geologic forces (volcanic activity and glaciers) at work in mt. rainer n. p. how have these forces changed the mountain over time?
Mount Rainier National Park is located in the Cascade Range of Washington state, and two important geologic forces at work in this area are volcanic activity and glaciers.
Volcanic activity has played a major role in shaping the landscape of Mount Rainier National Park. The mountain is a stratovolcano, which means that it is composed of layers of volcanic ash, rock, and lava flows. Over time, eruptions have built up the mountain and created the characteristic cone shape that we see today. Mount Rainier is still an active volcano, with the last eruption occurring in the mid-1800s. Volcanic activity in the area can cause earthquakes, landslides, and other hazards.
Glaciers have also had a significant impact on the landscape of Mount Rainier National Park. The park is home to the largest glacier system in the contiguous United States, with over 25 named glaciers covering the mountain. These glaciers are formed by snowfall that accumulates over time and compacts into ice. As the ice moves down the mountain, it can carve out valleys and create features such as moraines, cirques, and U-shaped valleys. Glaciers also play an important role in shaping the hydrology of the region, as they melt and feed into streams and rivers.
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what is the weight of a 1.8 kg computer
Answer:
17.64 Newtons
Explanation:
In order to find the weight of an object we take the mass in kilograms and multiply it by the gravitational constant (9.8), which is 1.8 * 9.8 = 17.74 Newtons.
Weight is force on the body of given mass 1.8 Kg. Weight is 17.64 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Weight of body is force due to gravity,
F = mg
F = 1.8*9.8
F = 17.64 N
Weight of the body is given as 17.64 N.
Weight is force on the body of given mass 1.8 Kg. Weight is 17.64 N.
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What are the angles for the two dark bands closest to the central maximum.
Express your answers in terms of b and λ. Separate the two angles with a comma.
asin(λb),asin(−λb)
The identical formula for the two angles is Asin(b),Asin(b).
The general word for interference effects involving edges or apertures is diffraction. In waves with longer wavelengths than those of light, diffraction is more common. Diffraction, for instance, is what causes sound to swell when it goes through a doorway or bend around corners. Diffraction causes water waves along a rocky coast to widen as they pass through the rocks. Usually, Fresnel and Fraunhofer diffraction regimes are distinguished.
Fresnel diffraction is the regime in which the diffracted waves are observed relatively close to the site of the diffraction (in comparison to the size of the item causing the diffraction). Working with Fresnel diffraction is typically very challenging. The Fraunhofer diffraction regime is the more manageable of the two.
angle 1 = asin(λb),
angle 2 = asin(−λb)
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Determine the orbits period of the moon when the distance between the earth and the moon is 3.82 x 10 to the power of 8
Answer:
3820000000
Explanation:
The long, light-colored lines extending from many craters on the Moon are called rays and are ______.
Answer:
The long, light-colored lines extending from many craters on the Moon are called rays and are "crater rays".
Explanation:
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three swimmers who all swim at the same speed discuss how to cross a river in the shortest amount of time. swimmer a will swim straight across the river at a right angle to the current. swimmer b reasons that the current will carry a downstream, meaning that a will cover a greater distance to get across and therefore will take a longer time interval. b says he will aim at an upstream angle such that, allowing for the current, he will reach the other side directly across from where he starts, thus covering the shortest distance and arriving first. swimmer c , reasoning that the time interval needed for b to cross will be longer than b expects because some of b 's effort will be spent battling the current, plans to aim at a downstream angle, so that the current assists rather than opposes him. this way he will be traveling at the highest speed and get across first. part a which swimmer gets across first? which swimmer gets across first? swimmer a gets across first. all swimmers get across at the same time. swimmer b gets across first. swimmer c gets across first. request answer provide feedback
Swimmer C gets across first. The reasoning behind the three swimmers crossing the river is different. Swimmer A swims directly across the river. Swimmer B swims upstream at an angle that allows him to be carried downstream by the current and reach the other side directly across from his starting point.
Swimmer C swims downstream at an angle that allows him to be carried downstream by the current, therefore, making the current work for him. Therefore, Swimmer C gets across first because he is swimming at the highest speed due to the help of the current. Swimmer B will take longer than he expects because some of his efforts will be spent battling the current. Swimmer A will cover the longest distance and will take longer than both Swimmer B and Swimmer C. Hence, Swimmer C is the one who gets across first.
Learn more about current here ;
https://brainly.com/question/23323183
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A 5-kg ball is moving at 8 m/s to the right, suddenly 15 N force is applied to the ball and the ball is now moving at 12 m/s. How long was the force applied to the ball
Answer:
t = 1.33 seconds
Explanation:
Given that,
The mass of the ball, m = 5 kg
Initial speed, u = 8 m/s
Final speed, v = 12 m/s
Force, F = 15 N
We need to find the time for long the force is applied. Let the time be t. The force is given by :
\(F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{5\times (12-8)}{15}\\\\=1.33\ s\)
So, the force is applied for 1.33 seconds.
help please 10 pts and quick!
Can Hockey players hold the puck with their open hand?
Answer:
Yes they can stop or bat the puck with their open hand
Explanation: