h2o(s)→ h2o(l) physical or chemical changel

During hyperventilation, the pH of the blood increases (becomes more alkaline), while the carbon dioxide (CO2) level decreases. These changes are consistent with the prediction.

Hyperventilation refers to an increased rate and depth of breathing, leading to the removal of excess carbon dioxide from the body. As a result, the concentration of carbon dioxide in the blood decreases. Carbon dioxide reacts with water to form carbonic acid (H2CO3), which dissociates into bicarbonate ions (HCO3-) and hydrogen ions (H+). By reducing the carbon dioxide level, there is less production of H+ ions, resulting in an increase in blood pH, making it more alkaline.

The observed changes in pH and carbon dioxide levels during hyperventilation are consistent with the predicted response. Increased ventilation causes more carbon dioxide to be expelled from the body, shifting the equilibrium of the carbonic acid-bicarbonate buffer system. As a consequence, the pH of the blood rises, leading to alkalosis. These changes can be confirmed through blood gas analysis or other diagnostic tests.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{7.15 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 11.87707641...\)

We have the final answer as

Hope this helps you

Answer:

Physical change

Explanation:

while the wax is melting its still wax no chemical change

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FALSE. The presence of a plaster ring does not affect the available volume for box fill calculations.

When a plaster ring is installed on a four-inch square junction box, it does not increase the available volume for the purposes of calculating box fill. The volume of the junction box remains the same regardless of the presence of a plaster ring.

The purpose of a plaster ring is to provide a surface for attaching the box to a wall or ceiling and to help protect the electrical wiring and connections within the box. It does not alter the internal volume of the junction box.

The volume of a junction box is important for determining the number and size of wires and devices that can be safely installed within the box while complying with electrical code regulations. The box fill calculation considers the internal dimensions of the junction box itself and does not take into account any external attachments or accessories like plaster rings.

Therefore, the presence of a plaster ring does not affect the available volume for box fill calculations.

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A complex is a compound that is composed of a central metal atom/ion and then ligands.   MnO4- is a d^0 specie hence it has no d electron.

A complex is a compound that is composed of a central metal atom/ion and then ligands. These ligands may lead to the color of the complex. However, the color of complexes more commonly result from the d-orbital transition in the metal atom/ion.

Now we know that the neutral electron configuration of Mn is [Ar]. 3d5. 4s2. It then follows that MnO4- is a d^0 specie hence it has no d electron.

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Answer:

Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons and electrons. The difference in the number of neutrons between the various isotopes of an element means that the various isotopes have different masses.

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Answer:

Number of protons

Explanation:

Isotopes are the same atom of an element with same

number of protons but different number of Neutrons.

Answer:

fluorine (f) lies in group 17 and 2 period

Answer:

Explanation:

Answer: fluorine (f) lies in group 17 and 2 period

Fossil fuels (coal, natural gas, and petroleum), air, water, salt, limestone, sulphur, and some specialty raw materials for special goods, like phosphates and the mineral fluorspar, are all examples of raw materials.

Sand (including silica sand), clay, hard rock, limestone (including metallurgical limestone), gravel, and other building and road-building supplies are considered basic raw materials (BRM). It also includes elements used to improve agricultural soil, such as limesand and gypsum.

Direct and indirect raw materials can be separated into two categories. The finished product contains direct materials. Examples are the fabric used to produce clothing or the wood used to make furniture. Throughout the process, indirect materials are used.

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The complete question is -

What are the sources of chemical raw material ?

The net ionic equation for the reaction between copper(II) sulfate and ammonium hydroxide depends on whether a reaction occurs.

If a reaction occurs, the balanced net ionic equation will be provided. Otherwise, if no reaction occurs, the notation "nr" will be used to indicate no reaction.When copper(II) sulfate (CuSO4) and ammonium hydroxide (NH4OH) are mixed in aqueous solution, they may undergo a precipitation reaction if a reaction occurs.

In this case, the copper(II) ion (Cu2+) from copper(II) sulfate reacts with the hydroxide ion (OH-) from ammonium hydroxide to form a precipitate of copper(II) hydroxide (Cu(OH)2).The balanced net ionic equation for the reaction, assuming a precipitation occurs, is:

Cu2+ (aq) + 2 OH- (aq) → Cu(OH)2 (s)

On the other hand, if no reaction occurs, it means that there are no significant chemical changes taking place when the two solutions are mixed. In this case, the notation "nr" (no reaction) would be used to indicate that no reaction occurs.

It is important to note that the precise conditions, concentrations, and stoichiometric ratios of the reactants can influence whether a reaction occurs or not. Conducting the actual experiment and observing the formation or lack of formation of a precipitate would provide definitive evidence of whether a reaction takes place.

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Answer:

Explanation: b

As assumptions are incorrect. we cannot calculate the resulting acceleration experienced by the combined object.

To solve this problem, we need to apply the law of conservation of momentum and the law of conservation of energy.

First, let's calculate the initial momentum and energy of the system before the collision:

The momentum of the system before the collision is given by:

p = m1v1 + m2v2 + m3v3 + m4v4

where m1, v1, m2, v2, m3, v3, m4, and v4 are the masses and velocities of objects A, B, C, and D, respectively.

p = (1.0 kg)(2.0 m/s2)(-45°) + (2.0 kg)(3.0 m/s2)(135°) + (1.0 kg)(4.0 m/s2)(225°) + (2.0 kg)(2.0 m/s2)(45°)

= -2.83 kg m/s

The initial kinetic energy of the system before the collision is given by:

K = (1/2)m1v1^2 + (1/2)m2v2^2 + (1/2)m3v3^2 + (1/2)m4v4^2

K = (1/2)(1.0 kg)(2.0 m/s2)^2 + (1/2)(2.0 kg)(3.0 m/s2)^2 + (1/2)(1.0 kg)(4.0 m/s2)^2 + (1/2)(2.0 kg)(2.0 m/s2)^2

= 11.0 J

Now, let's calculate the momentum and energy of the system after the collision. Since the objects stick together, the final velocity of the combined object will be the same for all objects. Let's call this velocity v.

The total mass of the combined object is:

m = m1 + m2 + m3 + m4 = 1.0 kg + 2.0 kg + 1.0 kg + 2.0 kg = 6.0 kg

The momentum of the combined object after the collision is:

p' = mv

The law of conservation of momentum states that the total momentum of a closed system is conserved. Therefore, we have:

p = p'

-2.83 kg m/s = (6.0 kg) v

v = -0.4717 m/s

The negative sign indicates that the direction of the velocity is opposite to the initial motion of the objects.

Finally, let's calculate the final kinetic energy of the combined object:

K' = (1/2)mv^2

K' = (1/2)(6.0 kg)(-0.4717 m/s)^2

= 0.67 J

The law of conservation of energy states that the total energy of a closed system is conserved. Therefore, we have:

K = K'

11.0 J = 0.67 J

This is a contradiction, which means that our assumptions are incorrect. We have neglected some external forces or other factors that affect the system. Therefore, we cannot calculate the resulting acceleration experienced by the combined object without further information.

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Answer:

Explanation:

if an object is heavy,the acceleration decreases because the acceleration produced on a body is inversely proportional to its mass.

Neutron activation analysis (NAA) is a nuclear analytical technique used to identify the composition and concentration of elements in a sample. The process involves irradiating the sample with neutrons, which induces nuclear reactions that produce radioactive isotopes. These isotopes can then be detected and quantified using gamma-ray spectroscopy.

In NAA, the sample is typically irradiated in a nuclear reactor or with a neutron generator. The neutrons react with the atomic nuclei in the sample, producing radioactive isotopes that have a characteristic decay pattern. After irradiation, the sample is typically allowed to decay for a period of time to allow the radioactivity to decay to a measurable level.

The radioactive isotopes produced during irradiation emit gamma rays with specific energies, which can be detected and quantified using gamma-ray spectroscopy. By measuring the gamma-ray spectrum, the forensic scientist can determine which isotopes are present in the sample and their relative concentrations.

Forensic scientists can use NAA to identify isotopes in a sample because different isotopes have different decay patterns and emit gamma rays with characteristic energies. By comparing the gamma-ray spectrum of the sample to a database of known gamma-ray spectra for different isotopes, the forensic scientist can identify which isotopes are present in the sample. Additionally, by measuring the relative concentrations of different isotopes, the forensic scientist can determine the origin and history of the sample.

Overall, NAA is a powerful technique that allows forensic scientists to identify isotopes in a sample by inducing nuclear reactions and detecting the characteristic gamma rays emitted by the resulting radioactive isotopes.

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Answer- im pretty sure it's 2

In BaF₂ the solubility will decreases on adding NaF

the solubility will increases on adding HCl

Hence the barium fluoride the solubility decreases on adding NaF and increases on adding HCl.

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In the given redox reaction, the element which is the reducing agent is silver as it is getting oxidized from zero to +1 by the gain of an electron.

Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.

While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.

The ion or molecule which accepts electrons is called as oxidizing agent while the ion or molecule which donates electrons is called as a reducing agent.

In the given equation silver is getting oxidized thus acting as a reducing agent.Thus, option B is correct.

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The molar mass of a compound can be determined using the atomic masses of each element present and the number of their atoms. The molar mass of Ca(NO₃)₂ is 164 g/mol.

The molar mass of a compound is the mass of one mole of that compound. One mole of any compound contains 6.02 × 10²³ atoms. This number is called Avogadro number.

The given compound contains the elements Ca, N and O.

atomic mass of Ca = 40 g/mol

atomic mass of N = 14 g/mol

atomic mass of O = 16 g/mol.

mass of 3 O = 48 g.

then mass of NO₃ = 48 + 14 = 62 g.

The total mass of the compound = 40 g + (62 ×2) = 164 g.

Therefore, the molar mass of the compound Ca(NO₃)₂ is 164 g.

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Explanation:

Physical change can observe by physical appearance

OA = No change in color

other choices are chemistry change

Answer

the first question is march im sure and the 2nd one is june the 3rd is the second answer hope this helps .!

Explanation:

Answer:

Thermal energy in the form of heat moved from the fire to the skewer and marshmallow.

Explanation:

He holds a marshmallow on a metal skewer over a fire. A few seconds late, the marshmallow is cooked and the skewer feels warm.

The heat generated from the marshmallow flowed in the form of thermal energy to the skewer and fire.

The term thermal energy refers to a form of energy that exists as a result of the temperature difference between two bodies. Thermal energy will always flow from the hotter to the cooler body.

Hence, the marshmallow is cooked and the skewer feels warm shortly after because the heat generated from the marshmallow flowed in the form of thermal energy to the skewer and fire.

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Answer:

radiation takes place with energy between a heat source and an object

Explanation:

g o o g l e

Answer: get frogged person

Explanation:

Answer:

Magnets can be used in space. ... One class of magnets, called electromagnets, does need electricity to work.

Explanation:

Answer:

Yes its vinegar

Explanation:

Actually \( \bold{\red {C_2H_4O_2}} \) is the formula for acetic acid which is found in vinegar.

To calculate the equilibrium constant (K_eq) at 25 degrees Celsius for a reaction with ΔH = -6.3 kJ/mol and ΔS = 70.5 J/(mol·K), we can use the equation:

ΔG = ΔH - TΔS

where ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, ΔS is the change in entropy, and T is the temperature in Kelvin.

At equilibrium, ΔG = 0, so we can rearrange the equation to solve for the equilibrium constant:

ΔG = -RT ln(K_eq)

Since ΔG = 0 at equilibrium, we have:

0 = -RT ln(K_eq)

R is the gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin (25 + 273.15 = 298.15 K). By substituting these values into the equation, we can solve for ln(K_eq) and then calculate K_eq.

Explanation:

In thermodynamics, the equilibrium constant (K_eq) relates the concentrations of products and reactants at equilibrium. It is a measure of the extent to which a reaction proceeds in the forward or reverse direction. The equilibrium constant can be determined using the Gibbs free energy change (ΔG), which combines the enthalpy change (ΔH) and the entropy change (ΔS) of the reaction.

In this case, we are given ΔH = -6.3 kJ/mol and ΔS = 70.5 J/(mol·K) for the reaction. By substituting these values into the equation ΔG = ΔH - TΔS, we can find the value of ΔG at the given temperature of 25 degrees Celsius (or 298.15 K).

Since ΔG is zero at equilibrium, we can rearrange the equation to -RT ln(K_eq) = 0 and solve for ln(K_eq). By substituting the appropriate values for R (gas constant) and T (temperature), we can calculate ln(K_eq). Finally, taking the exponential of ln(K_eq) gives us the equilibrium constant K_eq for the reaction at 25 degrees Celsius.

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Without having access to the specific graph you are referring to, I cannot definitively determine which gas is plotted using the y-axis on the right. However, the gases you mentioned are methane (CH4), carbon dioxide (CO2), and nitrous oxide (N2O). It is possible that the graph shows the total of all three gases as well. Please refer to the graph's labels or legend for clarification on which gas is plotted on the right y-axis.

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So technicaly the answer is D