The domain for (a) , (b) , (c) is all set of real numbers , for (d) (x ε R except x = 3/8.
The complete question is
a) (f + g)(x), (b) (f – g)(x), (c) (f × g)(x), (d) (f / g)(x), (e) (f + g)(7), (f) (f - g)(2), (g) (f.g)(3), (h) (f/g)(27)
What is a Function ?A function is the law that defines the relation between independent and a dependent variable.
It is given that
f(x) = 3x+8
g(x) = 8x-3
(a) (f + g)(x) = 3x+8 +8x-3 = 11x+5
(b) (f – g)(x) = 3x+8 -8x+3 = -5x +11
(c) (f × g)(x) = (3x+8)(8x-3) = 24x²-9x+64x -24 = 24x² +55x-24
(d)(f / g)(x) = (3x+8)/(8x-3)
(e) (f + g)(7) = 11*7+5 = 77+5 = 82
(f) (f - g)(2)= -5*2 +11 = 1
(g) (f.g)(3) =24*9 +55*3 -24 = 357
(h) (f/g)(27) = (3x+8)/(8x-3) = (3 * 27 +8)/(8*27-3) = 89/213
The domain for (a) , (b) , (c) is all set of real numbers , for (d) (x ε R except x = 3/8)
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Please help me understand the question
Answer:
○ \(\displaystyle \textcolor{black}{C.}\:triangle\)
Explanation:
This is a triangular prism. Its faces are triangular, but the lateral faces are rectangular. All prisms will have lateral faces shaped as rectangles. Do not ever forget this.
I am joyous to assist you at any time.
what is the product of 4x and 3x^2y+7xy^4
The product of the monomial 4x and the polynomial 3x²y + 7xy⁴ is 12x³y + 28x²y⁴.
How to multiply a monomial expression with a polynomial expression?The product of a monomial and a polynomial is as follows:
Step 1: multiply the monomial with each term in the polynomial
Step 2: Check for any like terms, if present adds or subtract them as per their sign.
Step 3: thus, we get the product.
Calculation:The given monomial is 4x and the polynomial is 3x²y + 7xy⁴.
So, their product is
4x × (3x²y + 7xy⁴) = 4x(3x²y) + 4x(7xy⁴)
⇒ (4×3)(x × x²)(y) + (4×7)(x × x)(y⁴)
⇒ 12x³y + 28x²y⁴
Since there are no like terms and do not need any further simplification, the given product is 12x³y + 28x²y⁴.
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What is the circumference of a circle with a diameter of 12 inches?
A.36.78 inches
B.37.68 inches
C.75.36 inches
D.38.96 inches
Answer:
B.37.68
Step-by-step explanation:
lets say pi is 3.14
12 x 3.14
37.68
The table represents the quadratic functions f(x) and g(x).
x f(x) g(x)
−2 12 4
−1 3 1
0 0 0
1 3 1
2 12 4
What transformation of f(x) will produce g(x)?
The transformation of f(x) that will produce g(x) is f(x) = 4(x+2)^2.
jackson is conducting an experiment for his physics class. he attaches a weight to the bottom of a metal spring. he then pulls the weight down so that it is a distance of six inches from its equilibrium position. jackson then releases the weight and finds that it takes four seconds for the spring to complete one oscillation. Which function best models the position of the weight?a. s(t) = 6cos(2πt)b. s(t) = 6sin(π/2 t)c. s(t) = 6sin(2πt)d. s(t) = 6cos (π/2 t)
6 cos(π/2 t) is the best model for the position of the weight.
The motion of the weight on the spring can be modeled by a sine or cosine function because it oscillates back and forth around its equilibrium position.
We know that, the weight is initially pulled down 6 inches from its equilibrium position, so the function should have an amplitude of 6.
The time it takes for the spring to complete one oscillation is 4 seconds, so the period of the function is 4 seconds.
The general form of a sine or cosine function with amplitude A and period T is:
f(t) = A sin(2πt/T) or f(t)
= A cos(2πt/T)
Substituting the given values,
we get:
f(t) = 6 sin(2πt/4) or f(t)
= 6 cos(2πt/4)
Simplifying, we get:
f(t) = 6 sin(π/2 t) or f(t)
= 6 cos(π/2 t)
Therefore,
the function that best models the position of the weight is
s(t) = 6 cos(π/2 t).
So, the answer is option (D).
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(Pythagorean Theorem, Right Angle) for 100 POINTS!
(Will even give Branliest for this easy work)
Are these answers correct?
Step-by-step explanation:
there is nothing missing. this is a complete proof.
yes, the various steps are correct.
HELP
Brainleist
and 15 points
Answer: x=20
Step-by-step explanation:
The two angles provided are vertical angles.
Vertical angles are equal in measurement.
This means we can set (3x+50) and (6x-10) equal to each other and solve for x
\(3x+50=6x-10\)
Add 10 to both sides
\(3x+50=6x-10\\3x+50+10=6x-10+10\\3x+60=6x\)
Subtract 3x from both sides
\(3x-3x+60=6x-3x\\60=3x\)
Divide both sides by 3
\(\frac{60}{3} =\frac{3x}{3} \\20=x\)
Answer:
Step-by-step explanation:
(3x + 50)° = (6x - 10)°
3x - 6x = -50 - 10
3x = -60
\(\frac{-3x}{-3}\) = \(\frac{-60}{3}\)
x=20°
Find the LCM of A= 3^2 x 5^4 x 7 and B= 3^4 x 5^3 x 7 x11
The LCM of A = 3² × 5⁴ × 7 and B = 3⁴ × 5³ × 7 × 11 is 3898125 using Prime factorization.
Given are two numbers which are showed in the prime factorized form.
A = 3² × 5⁴ × 7
B = 3⁴ × 5³ × 7 × 11
Prime factorization is the factorization of a number in terms of prime numbers.
In order to find the LCM of these two numbers, we have to first match the common primes and write down vertically when possible and then bring down the primes in each column.
A = 3² × 5³ × 5 × 7
B = 3² × 3² × 5³ × 7 × 11
Bring down the primes in each column.
LCM = 3² × 3² × 5³ × 5 × 7 × 11
= 3898125
Hence the LCM is 3898125.
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What is the range of possible sizes for side x?
\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)
The value of third side should be lesser than the the sum of other two sides ~
\(\qquad \sf \dashrightarrow \:x < 2.8 + 2.8\)
\(\qquad \sf \dashrightarrow \:x < 5.6\)
and, value of third side should also be greater than the difference of other two sides ~
\(\qquad \sf \dashrightarrow \: x> 2.8 - 2.8\)
\(\qquad \sf \dashrightarrow \:x > 0\)
Now, combine the two inequalities, we will get ~
\(\qquad \sf \dashrightarrow \:0 < x < 5.6\)
I hope you got the required Answer ~
Mr rosier users 3/8 tank of gas each week to get to work how much does he use in 9 weeks
Answer:
3.375 or 3 3/8 or 27/8 (all the same answer just in different forms)
Step-by-step explanation:
3/8 x 9 (or 9/1)
Guillermo ha acertado en un examen de matemáticas 8 problemas lo que supone un 72% del examen ¿ de cuántos problemas constaba el examen?
nose si entendí bien el problema pero espero poder ayudar
Step-by-step explanation:
8 es igual a 100%, por lo que podemos guardarlo como 8 = 100% El valor que buscamos puede llamarse x Ahora sabemos que xes 72 del valor de salida, por lo que podemos escribirlo como x = 72. Así que tenemos dos ecuaciones simples: 1) 8=100% 2) = 72%Cuando comparamos estas dos ecuaciones, obtenemos: 8 / x = (100%) / (72%)Ahora solo tenemos que resolver la ecuación simple. Nosotros calculamos 72 por ciento de 8: 8 / x = 100/72(8 / x) * x = (100/72) * x8 = 1,3888888888889 * X8 / 1.3888888888889 = X5.76 = xx = 5,76
66. Hillary's bakery makes vanilla cakes with three layers. She uses 18 eggsfor every 7 cups of sugar.What is the ratio of eggs to cups of sugar for the recipe?A7:18B18 : 7©7:250 18:25
Hillary's bakery makes vanilla cakes.
She uses 18 eggs for 7 cups of sugar.
Now to find the ratio of eggs to cups of sugar.
Since there 18 eggs for each 7 cups of sugar, the required ratio is 18:7
Hence the answer is
B 18:7
4. Amy, Betty and Carol have 96 books altogether. Betty has 6 books less than Amy and Carol has half as many as Betty. How many books does each girl have?
The Amy has 42 books, Betty has 36 books, and Carol has 18 books.
Let's set up equations to represent the given information:
Let A represent the number of books Amy has.
Let B represent the number of books Betty has.
Let C represent the number of books Carol has.
Let's say Amy has x books.
Betty has 6 books less than Amy, so Betty has (x - 6) books.
Carol has half as many books as Betty, so Carol has (x - 6)/2 books.
According to the problem, the total number of books they have is 96.
So, we can write the equation:
x + (x - 6) + (x - 6)/2 = 96
To solve the equation, we can simplify it by multiplying through by 2 to remove the fraction:
2x + 2(x - 6) + (x - 6) = 192
2x + 2x - 12 + x - 6 = 192
5x - 18 = 192
5x = 210
x = 42
Amy has 42 books.
Betty has (42 - 6) = 36 books.
Carol has (36)/2 = 18 books.
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My Account Need Help? Table of Contents
Module 5: Alcohol and Other Drugs
Time Elapred: OC-S57:45
The Remaining:00-00:00
Please answer the following question about the video you just watched.
Video Question: What noise sounds at the end of a
segment?
a) A horn blows
b) A bell rings
c) A song plays
d) There is no sound
Copyright 2014, American Safety Council, Inc. - All Rights Reserved
A
Logout
C
The horns are frequently used as a signal to indicate the end of a segment or a specific task. Hence, a horn blows is the noise that sounds at the end of a segment.
The noise that sounds at the end of a segment is A horn blows.
In geometry, a segment is a part of a line that connects two points.
For example, line segment AB, which is denoted by AB, connects point A and point B and can be visualized as a portion of a line.
In general, line segments are denoted by their endpoints.
A horn is a cone-shaped instrument that is often used as a warning signal or a musical instrument.
However, it is important to note that noise can occur at the end of a segment in certain contexts and situations.
For example, in the context of audio or video editing, you can apply fade-out effects or specific sound effects to signal the end of a segment.
However, these sounds are not universally applicable and depend on the specific creative choices and technical aspects of the project.
In the transportation sector, horns are commonly used to alert pedestrians and other drivers of an oncoming vehicle's presence.
The sound of a horn is usually a sharp and loud noise that is difficult to ignore.
As a result, horns are frequently used as a signal to indicate the end of a segment or a specific task. Hence, a horn blows is the noise that sounds at the end of a segment.
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Solve the following absolute value equation for the unknown. Show all of your work for full credit. |-3h – 6| ≤ 3
Answer:
\(-3 \le h \le 1\).
Step-by-step explanation:
Apply the property of absolute values: if \(a \ge 0\), then \(|x| \le a \iff -a \le x \le a\). By this property, \(|- 3\, h - 6 | \le 3\) is equivalent to \(-3 \le -3\, h - 6\le 3\). That's the same as saying that \(-3\, h - 6 \ge -3\) and \(-3\, h - 6 \le 3\).
Add \(6\) to both sides of both inequalities:
\(-3\, h \ge 3\) and \(-3\, h \le 9\).
Divide both sides of both inequalities by \((-3)\). Note that because \(-3 < 0\), dividing both sides of an equality by this number will flip the direction of the inequality sign.
\(-3\, h \ge 3\) would become \(h \le -1\).\(-3\, h \le 9\) would become \(h \ge -3\).Both inequalities are supposed to be true. Combining the two inequalities to obtain:
\(-3 \le h \le 1\).
Can someone please help me with this?
Answer:
yes
Step-by-step explanation:
The answer is "are" because it adds 3 each time!!! =)
Answer: yes
Step-by-step explanation: the answer is “are” because in the y column you add 3 to each one so it is proportional.
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed frequencies for the outcomes of 1, 2, 3, 4, 5, and 6, respectively: 29, 31, 49, 37, 26, 28. Use a 0.025 significance level to test the claim that the outcomes are not equally likely. Does it appear that the loaded die behaves differently than a fair die?
The loaded die appears to behave differently from a fair die.Based on the chi-square test, the loaded die does not exhibit equal probabilities for each outcome.
To test the claim that the outcomes of the loaded die are not equally likely, we can use the chi-square goodness-of-fit test. The null hypothesis (H₀) assumes that the outcomes are equally likely, while the alternative hypothesis (H₁) assumes that they are not equally likely.
Step 1: Set up hypotheses
H₀: The outcomes of the die are equally likely.
H₁: The outcomes of the die are not equally likely.
Step 2: Select the significance level
The significance level is given as 0.025, which means we have a two-tailed test and an alpha level of 0.025 for each tail.
Step 3: Compute the test statistic
We calculate the chi-square test statistic using the observed frequencies and the expected frequencies assuming equal probabilities for each outcome.
Expected frequencies (fair die):
1: 200/6 = 33.33
2: 200/6 = 33.33
3: 200/6 = 33.33
4: 200/6 = 33.33
5: 200/6 = 33.33
6: 200/6 = 33.33
Applying the chi-square formula, we get the test statistic:
χ² = ∑((observed - expected)² / expected)
Calculating this value, we get χ² ≈ 13.97.
Step 4: Determine the critical value
Since the significance level is 0.025 and the test is two-tailed, we divide the significance level by 2 to find the critical value associated with each tail. With 5 degrees of freedom (6 categories - 1), the critical value is approximately 11.07.
Step 5: Make a decision
The test statistic (13.97) is greater than the critical value (11.07), which leads us to reject the null hypothesis. Thus, we have evidence to suggest that the outcomes of the loaded die are not equally likely.
The loaded die appears to behave differently from a fair die.
In conclusion, based on the chi-square test, the loaded die does not exhibit equal probabilities for each outcome.
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Kyle has 64 baseball cards and must give away 1/4 of his figures away. How many cards will Kyle give away? What fractions of his cards does he have left?
kyle regalara 16 figuras y le quedara 3/4 de ellas
Which function is graphed below?
Answer:
f(x) = cos(x)
Step-by-step explanation:
In a cos wave, y value is -1 when x value is pi
Determine whether f(x) = 4x^2 – 16x + 6 has a maximum or a minimum value and find that value.
a
maximum; –10
b
minimum; –10
c
maximum; 2
d
minimum; 2
Answer:
minium:-2................
The function f(x) = 4x² – 16x + 6 has a minimum value is –10 when the value of x is 2. Then the correct option is B.
What is differentiation?
The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.
The function is given below.
\(f(x) = 4x^2 -16x + 6\)
Differentiate the function, then we have
\(\dfrac{d }{dx} f(x) =\dfrac{d}{dx}(4x^2 -16x + 6) \\\\ \dfrac{d }{dx} f(x) =8x - 16 \\\)
The value of x will be
\(8x - 16 = 0\\x = 2\)
Then again differentiate the function, if the value comes negative then maxima and if the value is positive then minima.
\(f''(x) = \dfrac{d }{dx} f'(x) \\\\f''(x)=8x - 16 \\\\f''(x) = 8\\\\ f''(x) > 0\)
Then the function is minimum at 2.
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Question one answer: S²=3V/H
What is the opposite operation of squaring? Using this opposite operation, rewrite the equation from question 1 so s is by itself on one side of the equation.
Step by step answer
Answer:
\(\ S=\sqrt{\dfrac{3V}{H}}}\)
Step-by-step explanation:
The opposite operation of squaring is taking the square root.
\(\ S=\sqrt{\dfrac{3V}{H}}}\)
We know that the denominator of a fractional power is the index of the corresponding root:
\(\displaystyle x^\frac{1}{n}=\sqrt[n]{x}\)
For n=2, we don't usually write the index in the root symbol:
\(x^{\frac{1}{2}}=\sqrt{x}\)
In the case of this problem, ...
\((S^2)^{\frac{1}{2}}=\left(\dfrac{3V}{H}\right)^{\frac{1}{2}}\\\\S=\sqrt{\dfrac{3V}{H}}\)
help!!
differentiate
\( { {e}^{x} }^{2} log_{10}(2x) \)
Rewrite the function using the change-of-base identity as
\(e^{x^2} \log_{10}(2x) = e^{x^2} \dfrac{\ln(2x)}{\ln(10)}\)
Apply the product rule:
\(\left(e^{x^2} \log_{10}(2x)\right)' = \left(e^{x^2}\right)' \dfrac{\ln(2x)}{\ln(10)} + e^{x^2} \left(\dfrac{\ln(2x)}{\ln(10)}\right)'\)
Use the chain rule:
\(\left(e^{x^2} \log_{10}(2x)\right)' = e^{x^2}\left(x^2\right)' \dfrac{\ln(2x)}{\ln(10)} + e^{x^2} \dfrac{(2x)'}{2\ln(10)x}\)
Compute the remaining derivatives:
\(\left(e^{x^2} \log_{10}(2x)\right)' = 2xe^{x^2} \dfrac{\ln(2x)}{\ln(10)} + e^{x^2} \dfrac2{2\ln(10)x} = e^{x^2}\left(\dfrac{2x\ln(2x)}{\ln(10)} + \dfrac1{\ln(10)x}\right)\)
If you like, you can convert back to base-10 logarithms:
ln(2x) / ln(10) = log₁₀(2x)
1 / ln(10) = ln(e) / ln(10) = log₁₀(e)
Then
\(\left(e^{x^2} \log_{10}(2x)\right)' = e^{x^2}\left(2x\log_{10}(2x)+\frac{\log_{10}(e)}x\right)\)
Which of the decimals or fractions is not equal to 0.825 or ?
loo
.
O
0.625
10
16
O 0.85
33
40
I'm confused can u tell me the question in comments
Help I need the intercept please.
y = 1/3x -1
x-intercept (3,0)
How did they get this answer? Somebody please help
Answer:
Step-by-step explanation:
x-intercept is where the line cuts the x-axis. That is, when y=0.
Substitute y=0 and we get:
\(0=\frac{1}{3} x-1\)
\(1=\frac{1}{3} x\)
\(x=3\)
So x-intercept is the point (3,0).
The function that assigns every positive three- digit integer the difference between the largest and the smallest digits. State the number of elements in the Domain and Range for this part.
77777
77777
77777
77777
77777
Let f(x,y,z)=(x^2)(y^3)+(z^3) and x=(s^2)*(t^3),y=s*t , and z=(s^2)*t .∂x/∂s=?
The value of ∂x/∂s is 4s^2 * t^6.
To find ∂x/∂s, we need to differentiate x with respect to s while treating t as a constant. Let's begin by substituting the given expressions for x, y, and z into the function f(x, y, z):
f(x, y, z) = (x^2)(y^3) + z^3
Substituting x, y, and z:
f(s, t) = ((s^2)(t^3))^2 * (s*t)^3 + ((s^2)*t)^3
Expanding the expression:
f(s, t) = (s^4 * t^6) * (s^3 * t^3) + (s^6 * t^3)
Now, let's differentiate x with respect to s:
∂x/∂s = ∂/∂s [(s^2)(t^3)]^2
Using the chain rule, we can differentiate each term separately:
∂x/∂s = 2 * (s^2 * t^3)^1 * ∂/∂s [(s^2)(t^3)]
Differentiating (s^2)(t^3) with respect to s:
∂/∂s [(s^2)(t^3)] = 2s * t^3
Substituting back into the expression for ∂x/∂s:
∂x/∂s = 2 * (s^2 * t^3)^1 * 2s * t^3
Simplifying:
∂x/∂s = 4s^2 * t^6
Therefore, ∂x/∂s = 4s^2 * t^6.
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Carmen has taken out a loan for $800 to buy a car. She plans to pay back the loan at a rate of $40 per month. Ramona has borrowed $500 to buy a car, which she plans to pay back at a rate of $20 per month.
How long will it take Ramona to pay back her loan?
Answer:
It will take Ramona 25 months or 2 years and 1 month to pay back for the car.
The Venn diagram shows the number of customers who have purchased different types of pets from a pet store, where C represents customers who have purchased cats, D represents customers who have purchased dogs, and F represents customers who have purchased fish.
Circles C, D, and F overlap. Circle C contains 15, circle D contains 21, and circle F contains 12. The overlap of C and F contains 2, the overlap of F and D contains 0, and the overlap of D and C contains 3. The overlap of all 3 circles contains 1. Number 14 is outside of the circles.
How many people are in the set C ∩ D?
4
6
36
38
The number of people in the set C ∩ D (customers who purchased both cats and dogs) is obtained by adding the overlap of D and C (3) with the overlap of all 3 circles (1), resulting in a total of 4 individuals.
The correct answer is 4.
To determine the number of people in the set C ∩ D (customers who have purchased both cats and dogs), we need to analyze the overlapping regions in the Venn diagram.
Given information:
- Circle C (cats): 15
- Circle D (dogs): 21
- Circle F (fish): 12
- Overlap of C and F: 2
- Overlap of F and D: 0
- Overlap of D and C: 3
- Overlap of all 3 circles: 1
- Number outside of circles: 14
To determine the number of people in the set C ∩ D (customers who have purchased both cats and dogs), we need to consider the overlapping region between circles C and D.
From the information given, we know that the overlap of D and C is 3. Additionally, we have the overlap of all 3 circles, which is 1. The overlap of all 3 circles includes the region where customers have purchased cats, dogs, and fish.
To calculate the number of people in the set C ∩ D, we add the overlap of D and C (3) to the overlap of all 3 circles (1). This gives us 3 + 1 = 4.
Therefore, from the options given correct one is 4.
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Answer: 4
Step-by-step explanation:
trust me bro
The theater was full when the movie began. Seventy-six people left
before the movie ended. One hundred twenty-four people remained.
How many people were in the theater when it was full?
The number of people were 200 in the theater when it was full.
What is a theater?
In architecture, a theatre, usually spelled theatre, is a structure or area where a play can be conducted in front of spectators. The term comes from the Greek theatron, which means "a place of seeing." The actual performance usually takes place on a stage in a theatre.
Given that, the theater was full when the movie began.
76 people leave the theater before end the movie. At the end of the movie, there is 124 people left.
Apply algebraical operation that is addition to find the required answer.
Therefore, the number of people that was present at the beginning of the movie is (76 + 124) = 200.
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