What is the value of 10 ^4

Objects commonly found in a locality include residential buildings, commercial establishments, public facilities, transportation infrastructure, landmarks, natural features, utilities, street furniture, and vehicles.

The type of objects that can be found in a locality can vary greatly depending on the specific location and its surroundings. Here are some common types of objects that can be found in a locality:

Residential Buildings: Houses, apartments, condominiums, and other types of residential structures are commonly found in localities where people live.

Commercial Establishments: Localities often have various types of commercial establishments such as stores, shops, restaurants, cafes, banks, offices, and shopping centers.

Public Facilities: Localities typically have public facilities such as schools, libraries, hospitals, community centers, parks, playgrounds, and sports facilities.

Transportation Infrastructure: Localities usually have roads, sidewalks, bridges, and public transportation systems like bus stops or train stations.

Landmarks and Monuments: Some localities may have landmarks, historical sites, monuments, or cultural attractions that represent the area's heritage or significance.

Natural Features: Depending on the locality's geographical characteristics, natural features like parks, lakes, rivers, mountains, forests, or beaches can be present.

Utilities: Localities have infrastructure for utilities such as water supply systems, electrical grids, sewage systems, and telecommunications networks.

Street Furniture: Localities often have street furniture like benches, streetlights, waste bins, traffic signs, and public art installations.

Vehicles: Various types of vehicles can be found in a locality, including cars, bicycles, motorcycles, buses, trucks, and possibly other modes of transportation.

It's important to note that the objects present in a locality can significantly differ based on factors such as urban or rural setting, cultural context, economic development, and geographical location.

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The distance between points P and Q is √73

First, remember that the distance between two points whose coordinates are (a, b) and (c, d) is given by:

distance = √( (a - c)² + (b - d)²)

Here we can see that the coordinates of the two shown points are:

P = (-3, 2)

Q = (5, -1)

Replacing that in the distance formula we will get:

distance = √( (-3 - 5)² + (2 + 1)²)

distance = √( (-8)² + (3)²)

distance = √73

So the correct option is the third one.

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The value of the radical √48 is 4√3.

Radical is a symbol (√) that denotes square roots and nth roots. The number inside the symbol is called Radicand and the expression containing the radical or a square root is called a Radical expression.

Here, we are given the radical √48

To find the value of the radical, we will factorize 48

i.e., 48 = 2×2×2×2×3

           = 16×3

Now, the square root of 48, that is, √48

                                                       = \(\sqrt{16\cdot3}\) =\(\sqrt{16} \cdot \sqrt{3}\)

We know 16 is a perfect square of 4, that is, the square root of 16= 4

⇒√16=4

Using this, we have √48= 4√3

The correct answer is 4√3.

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Answer: $19.10

Step-by-step explanation:

To be honestly im not sure if this is 100% correct but, i did the work so it should be. So what i did was move the decimal from $27.50 one place to the left which is= 2.750. i then rounded the easiest number which then gave me the answer $2.80. Now the percentage, its 30% so you then change it to .30

then you multiply that number (.30 which is basically 3) with $2.80.

$2.80

x   .30

--------

you then get $8.40

which is the total cost of tax AND tip.

you subtract that with the cost of the dinner. ( $27.50 - $8.40 ) and you get the answer $19.10! I hope this helps! :))

Answer:

15 pieces

Step-by-step explanation:

a ratio of 1:3 has 4 total parts, meaning that each part is 5.

20/3 = 15 so that means he has 5 pieces of chocolate and 15 of hard candy.

Answer:

15

Step-by-step explanation:

The total amount the man had = 52,200 rupees. Out of this, he gave 21,750 rupees to his son, 13,050 rupees to his daughter, and 17,400 rupees to his wife , the total amount given away by the man = 21,750 + 13,050 + 17,400 = 52,200 rupees.

A man gave 5/12 of his money to his son, 3/7 of the remainder to his daughter, and the remaining to his wife. If his wife gets Rs. 8,700, what is the total amount?

The given problem can be solved using the concept of ratios and fractions. Let us solve the problem step-by-step.Assume the man had x rupees with him.The man gave 5/12 of his money to his son.

The remaining amount left with the man = x - 5x/12= (12x/12) - (5x/12) = (7x/12)The man gave 3/7 of the remainder to his daughter.'

Amount left with the man after giving it to his son = (7x/12)The amount given to the daughter = (3/7) x (7x/12)= (3x/4)The remaining amount left with the man = (7x/12) - (3x/4)= (7x/12) - (9x/12) = - (2x/12) = - (x/6) (As the man has given more money than what he had with him).

Therefore, the daughter's amount is (3x/4) and the remaining amount left with the man is (x/6).The man gave all the remaining amount to his wife.

Therefore, the amount given to the wife is (x/6) = 8700Let us find the value of x.x/6 = 8700 x = 6 x 8700 = 52,200

Therefore, the man had 52,200 rupees with him.He gave 5/12 of his money to his son. Therefore, the amount given to his son is (5/12) x 52,200 = 21,750 rupees.

The remaining amount left with the man = (7/12) x 52,200 = 30,450 rupees.He gave 3/7 of the remainder to his daughter. Therefore, the amount given to his daughter is (3/7) x 30,450 = 13,050 rupees.

The amount left with the man = (4/7) x 30,450 = 17,400 rupees.The man gave 17,400 rupees to his wife.
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Mean: 34.125, Median: 31.5, Mode: 38

Mean: 19.222, Median: 18, No mode

Mean: 8.611, Median: 8, Mode: 8

Let's find the mean, median, and mode for each set of numbers:

Set: 40, 38, 29, 34, 37, 22, 15, 38

Mean: To find the mean, we sum up all the numbers and divide by the total count:

Mean = (40 + 38 + 29 + 34 + 37 + 22 + 15 + 38) / 8 = 273 / 8 = 34.125

Median: To find the median, we arrange the numbers in ascending order and find the middle value:

Arranged set: 15, 22, 29, 34, 37, 38, 38, 40

Median = (29 + 34) / 2 = 63 / 2 = 31.5

Mode: The mode is the number(s) that appear(s) most frequently in the set:

Mode = 38 (appears twice)

Set: 26, 32, 12, 18, 11, 14, 21, 12, 27

Mean: Mean = (26 + 32 + 12 + 18 + 11 + 14 + 21 + 12 + 27) / 9 = 173 / 9 ≈ 19.222

Median: Arranged set: 11, 12, 12, 14, 18, 21, 26, 27, 32

Median = 18

Mode: No mode (all numbers appear only once)

Set: 3, 3, 4, 7, 5, 7, 6, 7, 8, 8, 8, 9, 8, 10, 12, 9, 15, 15

Mean: Mean = (3 + 3 + 4 + 7 + 5 + 7 + 6 + 7 + 8 + 8 + 8 + 9 + 8 + 10 + 12 + 9 + 15 + 15) / 18 ≈ 8.611

Median: Arranged set: 3, 3, 4, 5, 6, 7, 7, 7, 8, 8, 8, 8, 9, 9, 10, 12, 15, 15

Median = 8

Mode: Mode = 8 (appears 4 times)

Mean: 34.125, Median: 31.5, Mode: 38

Mean: 19.222, Median: 18, No mode

Mean: 8.611, Median: 8, Mode: 8

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Answer:

  94.3

Step-by-step explanation:

You want to know how to fill in the proportion associated with the question, "What is 115% of 82?"

The diagram is intended to help you match parts of the question to parts of the proportion. The attachment shows the intended relation.

The solution is found by multiplying both sides by 82:

  (x/82)·82 = (115/100)·82

  x = 94.3

The question can also be written as a statement:

  "what" is 115% of 82

When written as an equation, "is" means "equals", and "of" means "times":

  what = 115% × 82

Of course, you can use any variable name of your choosing in place of "what". In your diagram, that is "x". And, you know how to write a percentage as a fraction or decimal, so this becomes ...

  x = 115/100 × 82 = 1.15 × 82

All that remains is to evaluate this expression.

  x = 1.15 × 82 = 94.3

So, the answer to the question is ...

  94.3 is 115% of 82.

Answer:

33 days

Step-by-step explanation:

Divide $899.00 by 27 days.

Sorry if Im wrong

Answer:

This would be 6 of 1/8 pound of serving

Answer:

6 out of 1/8

Step-by-step explanation:

The value of side length x in diagram a) is 4.3mm and side length x in diagram b) is 309.7 m.

The figures in the image are right triangles.

A)

angle D = 17 degree

Adjacent to angle D = 14 mm

Opposite to angle D = x

To solve for the missing side length x, we use the trigonometric ratio.

Note that: tangent = opposite / adjacent

Hence:

tan( 17 ) = x/14

x = tan( 17 ) × 14

x = 4.3mm

B)

angle Z = 82 degree

Adjacent to angle Z = 43.1 m

Hypotenuse = x

Using trigonometric ratio,

cosine = adjacent / hypotenuse

cos( 82 ) = 43.1 / x

x = 43.1 / cos( 82 )

x = 309.7 m

Therefore, the measure of x is 309.7 meters.

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Answer:

Step-by-step explanation:

In each case, the answer is the product of the three given numbers.

  i = Prt

a) $500×0.032×3 = $48.00

b) $450×0.031×4 = $55.80

c) $515×0.03×3 = $46.35

3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.

To express 3 1/2 cups as a multiplication expression using the unit "1 cup" as a factor, you can write it as:

3 1/2 cups = (3 + 1/2) cups = 3 cups + 1/2 cup

Since there are 1 cup in each term, we can rewrite it as:

3 cups + (1/2) cup

Now, we can express each term as a multiplication expression:

3 cups = 3 * 1 cup = 3

(1/2) cup = (1/2) * 1 cup = 1/2

Putting it all together, the multiplication expression is:

3 * 1 cup + (1/2) * 1 cup = 3 + 1/2

Therefore, 3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.

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Answer:

A business person will use algebra to determine whether a piece of equipment does not lose its worth if it is in stock.

Step-by-step explanation:

Answer: -4

Step-by-step explanation:

f(x) = -x+2

-6+2

=-4

The best numerical descriptive measure for comparing average store sales by region would be the mean or average.

This measure would provide an accurate representation of the overall store sales across the entire region and would allow the manager to easily identify which region has the lowest store sales.

Additionally, the median and mode could also be used as descriptive measures to compare the store sales by region.

For example, if there is a single store with particularly high sales, the mean will be heavily influenced by this one store. The median and mode would be more likely to provide a better representation of the overall sales across the region, as they are not as heavily influenced by extreme values.

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Step-by-step explanation:

| Equation | Solution |

| 6+x=15 | x = 9 |

| 9x = 18 | x = 2 |

The table would look like:

| Equation | Solution |

| 6+x=15 | X |

| 9x = 18 | X |

\({\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}\)

\(\star\:{\underline{\underline{\sf{\purple{Solution:}}}}}\)

\( \bullet \sf \: {(a + b)}^{ab} \)

Putting value of a as 3 and b as -2, we get :

\( \longrightarrow \sf \: {( 3 + (- 2))}^{3 \times - 2} \)

\(\longrightarrow \sf \: {( 3 - 2)}^{3 \times - 2} \)

\(\longrightarrow \sf \: {( 1)}^{ - 6} \)

• Using negative Exponents Law

\(\longrightarrow \sf \dfrac{1}{ {1}^{6} } \)

\(\longrightarrow \sf \dfrac{1}{ 1 \times 1 \times 1 \times 1 \times 1 \times 1 } \)

\(\longrightarrow \sf \dfrac{1}{ 1 } \)

\(\longrightarrow \sf \purple{1}\)

\({\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}\)

\(\star\:{\underline{\underline{\sf{\red{Solution:}}}}}\)

\( \bullet \sf \: \dfrac{ {8}^{ - 1} \times {5}^{3} }{ {2}^{ - 4}} \)

\( \longrightarrow \sf \: {8}^{ - 1} \times {5}^{3} \times \dfrac{1}{{2}^{ - 4}} \)

• Using negative Exponents Law

\(\longrightarrow \sf \: {8}^{ - 1} \times {5}^{3} \times {2}^{4} \)

\(\longrightarrow \sf \: {8}^{ - 1} \times 5 \times 5 \times 5 \times {2}^{4} \)

\(\longrightarrow \sf \: {8}^{ - 1} \times 125 \times {2}^{4}\)

\(\longrightarrow \sf \: {8}^{ - 1} \times 125 \times 2 \times 2 \times 2 \times 2\)

• Using negative Exponents Law

\(\longrightarrow \sf \: \dfrac{1}{ \cancel{8}_{4}} \times 125 \times \cancel{2}_{1} \times 2 \times 2 \times 2\)

\(\longrightarrow \sf \: \dfrac{1}{ \cancel4_{2}} \times 125 \times \cancel{2}_{1} \times 2 \times 2\)

\(\longrightarrow \sf \: \dfrac{1}{ \cancel2} \times 125 \times \cancel{2} \times 2\)

\(\longrightarrow \sf \: 125 \times 2\)

\(\longrightarrow \sf \red{ 250}\)

\({\large{\textsf{\textbf{\underline{\underline{Question \: 3 :}}}}}}\)

\(\star\:{\underline{\underline{\sf{\green{Solution(1):}}}}}\)

\( \bullet \sf \dfrac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} } \)

\( \longrightarrow \sf \dfrac{ \sqrt{4 \times 4 \times 2} + \sqrt{4 \times 4 \times 3} }{ \sqrt{2 \times 2 \times 2} + \sqrt{2 \times 2 \times 3} } \)

\( \longrightarrow \sf \dfrac{ \sqrt{ {4}^{2} \times 2} + \sqrt{ {4}^{2} \times 3} }{ \sqrt{ {2}^{2} \times 2} + \sqrt{ {2}^{2} \times 3} } \)

\( \longrightarrow \sf \dfrac{ 4\sqrt{ 2} + 4 \sqrt{ 3} }{ 2\sqrt{ 2} +2 \sqrt{ 3} } \)

\(\longrightarrow \sf \dfrac{ \cancel{ 4}_{2}(\sqrt{ 2} + \sqrt{ 3}) }{ \cancel{2}(\sqrt{ 2} + \sqrt{ 3}) } \)

\(\longrightarrow \sf \dfrac{ 2 \: \cancel{(\sqrt{ 2} + \sqrt{ 3}) } }{ \cancel{(\sqrt{ 2} + \sqrt{ 3})} } \)

\(\longrightarrow \sf \green{2}\)

\(\star\:{\underline{\underline{\sf{\blue{Solution(2):}}}}}\)

\( \bullet \sf \dfrac{ \sqrt{5} + \sqrt{3} }{ \sqrt{80} + \sqrt{48} - \sqrt{45} - \sqrt{27} } \)

\(\begin{gathered} \longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{ \sqrt{4 \times 4 \times 5} + \sqrt{4 \times 4 \times 3} - \sqrt{3 \times 3 \times 5} - \sqrt{3 \times 3 \times 3} } \end{gathered} \)

\(\begin{gathered}\longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{ \sqrt{ {4}^{2} \times 5} + \sqrt{ {4}^{2} \times 3} - \sqrt{ {3}^{2} \times 5} - \sqrt{ {3}^{2} \times 3} } \end{gathered} \)

\(\longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{4 \sqrt{ 5} + 4 \sqrt{ 3} - 3\sqrt{ 5} - 3\sqrt{ 3} } \)

\(\longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{4 \sqrt{ 5} - 3\sqrt{ 5} + 4 \sqrt{ 3} - 3\sqrt{ 3} } \)

\(\longrightarrow \sf \dfrac{ \cancel{ \sqrt{5} + \sqrt{3}} }{ \cancel{\sqrt{ 5} + \sqrt{ 3} } }\)

\(\longrightarrow \blue{1}\)

\({\large{\textsf{\textbf{\underline{\underline{Answers :}}}}}}\)

• Question 1 - \(\purple{1}\)

• Question 2 - \(\red{250}\)

• Question 3(1) - \(\green{2}\)

• Question 3(2) - \(\blue{1}\)

\({\large{\textsf{\textbf{\underline{\underline{ Concept \: :}}}}}}\)

★ Negative Exponents Law -

\( \bullet \sf \: {a}^{ - m} = \dfrac{1}{ {a}^{m} } \)

★ \( \sqrt{32} \) can be written as \(4 \sqrt{2} \)

‣ \( \sqrt{48} \) can be written as \(4 \sqrt{3} \)

‣ \( \sqrt{8} \) can be written as \(2 \sqrt{2} \)

‣ \( \sqrt{12} \) can be written as \(2 \sqrt{3} \)

‣ \( \sqrt{80} \) can be written as \(4 \sqrt{5} \)

‣ \( \sqrt{48} \) can be written as \(4 \sqrt{3} \)

‣ \( \sqrt{45} \) can be written as \(3 \sqrt{5} \)

‣ \( \sqrt{27} \) can be written as \(3 \sqrt{3} \)

★ During Addition and Subtraction

• minus (-) minus (-) gives plus (+)

• minus (-) plus (+) gives minus (-)

• plus (+) minus (-) gives minus (-)

• plus (+) plus (+) gives plus (+)

• Also the sign of the resultant term depends upon the sign of the largest number.

\({\large{\textsf{\textbf{\underline{\underline{ Note \: :}}}}}}\)

• Swipe to see the full answer.

\(\begin{gathered} {\underline{\rule{330pt}{3pt}}} \end{gathered}\)

Answer:

13 + 10 + 10= 23, 33

11 + 11 + 11 = 22, 33

Angela is cheaper for two

Same price for 3

Teresa is cheaper for 4

Step-by-step explanation:

You should choose who you want by the hours you will be gone knowing who is more and less

On solving the given equation, we have - 125 adult tickets and 179= children tickets.

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated by the symbol "equal."

301= 104

6.40 =2.25

4.00=1.75

Suppose the number of adult ticket bought =x

And number of children tickets bought =  (301-x).

equation is

6.40(x) + 4(301-x) = 1504

6.40x + 1204 - 4x = 1504

2.40x = 300

x= 125

125 adult tickets and 179= children tickets.

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Answer:

60 km

Step-by-step explanation:

the line is constant around 3

Considering the equations of a circle and of a parabola, we have that:

a) Tunnel A is a circle, with it's radius meaning that both the width and the height are of 12.

b) Tunnel B is a parabola, with it's vertex and it's roots meaning that it has a width of 32 feet and a height of 16 feet.

c) The maximum height of Tunnel A is of 12 feet and of Tunnel B is of 16 feet, hence, since the height of the truck is of 13.5 feet, it can pass through Tunnel B without damage, as it's height is greater than 13.5 feet.

The equation of a circle of center \((x_0, y_0)\) and radius r is given by:

\((x - x_0)^2 + (y - y_0)^2 = r^2\)

For Tunnel A, the equation is given by:

x² + y² + 28x + 52 = 0

Completing the squares:

(x + 14)² + y² = -52 + 14²

(x + 14)² + y² = 144.

Hence:

Tunnel A is a circle, with it's radius meaning that both the width and the height are of 12.

A parabolic(quadratic) equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

\((x_v, y_v)\)

In which:

For Tunnel B, the equation is given as follows:

x² - 36x + 16y + 68 = 0.

16y = -x² + 36x - 68.

Simplifying by 16:

y = -0.0625x² + 2.25x - 4.25.

Hence the coefficients are a = -0.0625, b = 2.25, c = -4.25, and the maximum height is:

\(y_v = -\frac{(2.25)^2 - 4(-0.0625)(-4.25)}{(-0.0625)} = 16\)

The width is the difference between the roots, which, using a calculator, are:

2 and 34, hence the width is of 32 feet, as 34 - 2 = 32.

Hence:

Tunnel B is a parabola, with it's vertex and it's roots meaning that it has a width of 32 feet and a height of 16 feet.

For item c, considering the previous items, we have that:

The maximum height of Tunnel A is of 12 feet and of Tunnel B is of 16 feet, hence, since the height of the truck is of 13.5 feet, it can pass through Tunnel B without damage, as it's height is greater than 13.5 feet.

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Answer: 125 miles a day

Step-by-step explanation: Divide 1875 by 15 to get 125 miles a day.

Answer:

The door

Step-by-step explanation:

The profit function for this problem is given as follows:

P(x) = -0.5x³ + 100x² - 500x + 300.

The profit function is obtained as the subtraction of the revenue function by the cost function, as follows:

P(x) = R(x) - C(x).

The functions for this problem are given as follows:

Hence the profit function is given as follows:

P(x) = -0.5x³ + 600x² - 200x + 300 - 500x² - 300x

P(x) = -0.5x³ + 100x² - 500x + 300.

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a) Comparing the two functions, Scooter's business has a lower slope of 15 compared to Karissa's business with a slope of 35. b) Both Scooter and Karissa earned a total of $500 in that month. Therefore, they had an equal month in terms of total money earned.

a) In the context of Scooter's business, the slope of the function f(x) = 200 + 15x represents the rate at which the total money earned increases with each additional sale. Each unit increase in x (number of sales) results in an increase of $15 in total money earned. The y-intercept of 200 represents the initial amount of money Scooter already had before making any sales.

In the context of Karissa's business, the slope of the function f(x) = 80 + 35x represents the rate at which the total money earned increases with each additional repair job. Each unit increase in x (number of repairs) results in an increase of $35 in total money earned. The y-intercept of 80 represents the initial amount of money Karissa already had before doing any repair jobs.

Comparing the two functions, Scooter's business has a lower slope of 15 compared to Karissa's business with a slope of 35. This means that Karissa's business earns more money per repair job compared to Scooter's business per t-shirt sale.

b) To determine who had the better month, we need to calculate the total money earned by each individual based on the given sales/repairs.

For Scooter, with x = 20 (number of shirts sold):

f(x) = 200 + 15x

f(20) = 200 + 15 * 20

f(20) = 200 + 300

f(20) = 500

For Karissa, with x = 12 (number of repairs):

f(x) = 80 + 35x

f(12) = 80 + 35 * 12

f(12) = 80 + 420

f(12) = 500

Both Scooter and Karissa earned a total of $500 in that month. Therefore, they had an equal month in terms of total money earned.

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Answer:

Step-by-step explanation:

tan30 = opp/adj = x/1

x = tan30 = ⅓√3 or approximately 0.577

The sequence is decreasing as n increases and sequence converges to the value 0.

The given sequence is defined as aₙ = 1 / (7n + 3).

To determine if the sequence converges or diverges, we need to analyze its behavior as n approaches infinity.

As n increases, the denominator 7n + 3 also increases which means that the values of aₙ will get smaller and smaller, approaching zero as n becomes larger.

The sequence converges to the value 0.

The sequence is decreasing as n increases.

The sequence converges to the value 0.

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