a polymeric cylinder initially experiences a stress with magnitude (absolute value) of 1.1 mpa when compressed. after 50 days the magnitude of the stress is found to have decreased to 0.52 mpa. determine approximately how long, in days, it will take until the magnitude of the stress reaches 1/10 (one-tenth) of its initial value?
Answers
Number of days are 210 which are needed to make the magnitude of stress to 1/10
Given A = 0.52Mpa
A = 0.9 Mpa
T = 50 days
We have the relation A = A 0e ^-rt
Substituting al the values we get
0.9 = 0.52 e ^ -r(50)
There fore value is -0.0197
Also we need to consider A = 1/10A0
That gives A/A0 = 1/10
By applying limit ln(1/10) = e ^ 0.01097
T = 209.87 where the days cant be negative we will consider as 210 days since rounding off to nearest value
What is stress?
Stress is the force applied to a material's unit area. Strain is the term for a body's reaction to stress. The body can distort under stress. The stress unit can be used to measure how much force a material experiences.
Thus 210 days are needed to get the magnitude of the stress which is 1/10th of initial value
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Related Questions
A specimen of 100 mm length along the stroke of a shaper is machined with 15° rake angle tool. Determine the shear plane angle and chip thickness if uncut chip thickness is 1.5 mm and chip length obtained is 40 mm.
Answers
The shear plane angle is approximately -88.43°, and the chip thickness is approximately 8.69 mm.
To determine the shear plane angle and chip thickness in a machining process, we need to consider the rake angle, uncut chip thickness, and chip length obtained.
Given:
Length of the specimen (L): 100 mm
Rake angle (α): 15°
Uncut chip thickness (t₀): 1.5 mm
Chip length obtained (l): 40 mm
The shear plane angle (φ) can be determined using the formula:
tan(φ) = (l - L) / (2 * t₀)
Substituting the given values:
tan(φ) = (40 - 100) / (2 * 1.5)
tan(φ) = -60 / 3
tan(φ) = -20
Now, we can determine the shear plane angle (φ) using the arctan function:
φ = arctan(-20)
φ ≈ -88.43°
Note: The negative value indicates that the shear plane is inclined in the opposite direction to the cutting direction.
The chip thickness (t) can be calculated using the formula:
t = t₀ / cos(φ - α)
Substituting the given values:
t = 1.5 / cos(-88.43° - 15°)
t = 1.5 / cos(-103.43°)
t ≈ 1.5 / 0.1726
t ≈ 8.69 mm
Therefore, the shear plane angle is approximately -88.43°, and the chip thickness is approximately 8.69 mm.
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The ______________________________ instruction transfers either a number or content of a register to a destination register.
Answers
The MOV instruction transfers either number or content of a register to a destination register.
What is mov education?The mov instruction replicates the data item referred to by its second operand (i.e. register contents, memory contents, or a constant value) into the location directed to by its first operand (i.e. a register or memory). While register-to-register moves are possible, natural memory-to-memory moves are not.
What is mov in opcode?
"mov" is an instruction, encoded with the system code or "opcode" 0xb8. Since mov takes an opinion, the next 4 bytes are endless to move into eax. The opcode 0xb9 carries a constant into ecx. 0xba carries a constant into edx.
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For the floor plan shown, if a = sm b= 8m, specify type of Load on Beam AHS
D
B В
Answers
the voltage valve at which a zirconia O2S switches from rich to lean and lean to rich is
A) 0.5v (500mv)
B) 0.45v (450mv)
C) 0.25v (250mv)
D) 0.90v (900)
Answers
When the process is in control but does not meet specification which type of error is it?
Answers
When the process is in control but does not meet specification, it is referred to as a special cause error.
What is the term for a process in control but not meeting specification?In statistical process control, a process is considered to be in control when it operates within the defined limits and shows only random variations. However, when a process is in control but does not meet the desired specifications, it indicates the presence of a special cause error.
Special cause errors are attributed to specific factors or events that cause the process to deviate from the expected outcome. These errors are typically unpredictable and require investigation and corrective action to bring the process back within the desired specifications.
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A Class III two-lane highway is on level terrain, has a measured free-flow speed of 45 mi/h, and has 100% no-passing zones. During the peak hour, the analysis direction flow rate is 150 veh/h, the opposing direction flow rate is 100 veh/h, and the PHF-0.95. There are 5% large trucks and 10% recreational vehicles. Determine the level of service.
Answers
Answer:
LOS = A
Explanation:
Given all the parameters the level of service as seen from the attached graph
is LOS = A
To determine the LOS from the attached graph
calculate the trial value of Vp
Vp = V / PHF
= (100 + 150) / 0.95 = 263 pc/h
since the trial value of Vp = ( 0 to 600 ) pc/h . hence E.T = 1.7 , ER = 1
next we will calculate the flow rate
flow rate = 1 / [ ( 1 + PT(ET - 1 ) + PR ( ER - 1 ) ]
Fhr = 1 / 1.035 = 0.966 ≈ 1
next calculate the real value of Vp
Vp = V / ( PHF * N * Fhr * Fp )
= ( 100 + 150 ) / ( 0.95 * 2 * 1 * 1 )
Vp ≈ 126 pc/h/In
Next calculate the density
D = Vp / S = 126 / ( 45 * 1.61 ) = 1.74 pc/km/In
Water is the working fluid in an ideal Rankine cycle. Superheatedvapor enters the turbine at 10MPa, 480°C, and the condenser pressure is6 kPa. Isentropic efficiencies of the turbine and pump are 80% and 75%,respectively. Determine for the cyclea.the actual heat transfer to the working fluid passing through thesteam generator, in kJ per kg of steam flowing.b.the thermal efficiency.c.the actual heat transfer from the working fluid passing through thecondenser to the cooling water, in kJ per kg of steam flowing
Answers
Answer:
Explanation:
Given that:
Superheated vapor enters the turbine at 10 MPa, 480°C,
From the tables of superheated steam tables; the following values are obtained
\(h_1 = 3322.02 \ kJ/kg\\\\ s_1 = 6.52846 \ kJ/kg.K\)
Also; from the system, the isentropic line is 1-2 in which s_2 is in wet state
\(s_2 = s_{f \ 6 kpa} +xs_{fg \ 6 kpa}\)
\(s_2 =0.51624 + x(7.82)\)
\(s_2 =0.51624 + 7.82x\)
From the values obtained;
\(s_1 =s_2= 6.52846 \ kJ/kg.K\)
Therefore;
6.52846 = 0.51624+7.82x
6.52846 - 0.51624 = 7.82 x
6.01222 = 7.82 x
x = 6.01222/7.82
x = 0.7688
The enthalpy for this process at state (s_2) can be determined as follows:
\(h_2 = h _f +xh_{fg} \\ \\ h_2 = 150.15 +(0.77 \times 2415.92) \\ \\ h_2 =150.15 +( 1629.2584 ) \\ \\ h_2 =2010.4084 \ kJ/kg\)
The actual enthalpy at s_2 by using the isentropic efficiency of the turbine can determined by using the expression:
\(n_T = \dfrac{h_1-h_{2a}}{h_1-h_2}\)
\(0.8 = \dfrac{3322.02-h_{2a}}{3322.02-2010.4084}\)
\(0.8 = \dfrac{3322.02-h_{2a}}{1311.6116}\)
\(0.8 * {1311.6116}= {3322.02-h_{2a}\)
\(1049.28928= {3322.02-h_{2a}\)
\(h_{2a}= {3322.02- 1049.28928\)
\(h_{2a}= 2272.73072\) kJ/kg
The work pump is calculated by applying the formula:
\(w_p = v_{f \ 6 kpa} (p_4-p_3)\)
\(w_p = 0.0010062 * (10000-6)\)
\(w_p = 0.0010062 *9994\)
\(w_p = 10.0559628 \ kJ/kg\)
However;
\(w_p = h_4 -h_3\)
From the process;
\(h_3 = h_{f(6 kpa)} = 150.15 \ kJ/kg\)
\(10.0559628 = h_4 - 150.15\)
\(10.0559628+ 150.15 = h_4\)
\(160.2059628= h_4\)
\(h_4= 160.2059628 \ kJ/kg\)
The actual enthalpy at s_4 by using the isentropic efficiency of the turbine can determined by using the expression:
\(n_P = \dfrac{h_4-h_{3}}{h_{4a}-h_3}\)
When trying to prevent a rollover, it is important that the driver does not
A. overcorrect
B. grab the steering wheel
C. slam the brakes
D. undercorrect
Answers
classify each of the following failures by identifying its category in fig. 1.1, and explain the reasons for each choice in one or two sentences: (a) the plastic frames on eyeglasses gradually spread and become loose. (b) a glass bowl with a small crack breaks into two pieces when it is immersed, while still hot, into cold water. (c) the steel radiator fan blades in an automobile develop small cracks near the base of the blades. (d) a large steel artillery tube (barrel), which previously had cracks emanating from the rifling, suddenly bursts into pieces. classify both the cracks and the final fracture (e) the nickel-alloy blades in an aircraft turbine engine lengthen during service and rub the casing.
Answers
Each of the following failures was categorized by identifying its category
Plastic eyeglass frames flex and loosen with time. This is an illustration of creep failure.
When a glass bowl with a minor crack is plunged in cold water while still hot, it splits into two pieces. This is an illustration of thermal shock failure.
A little fracture appears directly in front of one of the finger rings on a pair of plastic scissors. This is an illustration of fatigue failure.
A copper water pipe freezes, causing a longitudinal break and a leak. Brittle fracture is seen here.
The radiator fan's steel fan blades are leaking. This is an illustration of creep failure.
Explanation of each of the aforementioned failures This is an example of creep failure, which happens when a material is subjected to continual tension over time and deforms. Because of the frequent tension of wearing them, plastic eyeglass frames flex and loosen. Thermal shock failure occurs when a material is subjected to a quick shift in temperature, causing it to fracture or shatter.
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(a) Design a high-pass filter with a cutoff frequency of 40 kHz. Use0.01 uF capacitor and an appropriate resistor. B) Sketch and label the circuit. C) What is the gain of the filter at the cutoff frequency? Give your answer both as ratio (Vout/Vin) and in dB. D) What is the gain of the filter at a frequency of 55 kHz? Give your answer both as a ratio (Vout/Vin) and in dB.
Answers
Answer:
a) 397.89 ohm
b) attached below
c) 0.707 as a ratio
Gain in dB = 20 log 0.707 = -3 dB
d) 0.8087
Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB
Explanation:
A) Find the appropriate resistor
c = 0.01 uf
fc = 40 kHz
cut-off frequency ; fo = \(\frac{1}{2\pi RC }\)
from the above equation R = \(\frac{1}{2\pi foC}\) = 397.89 ohm
B) sketch of the circuit is attached
C) The gain of the filter at the cutoff frequency
fc = 40 kHz,
C = 0.01 uF ⇒ \(\frac{-j}{2\pi foC }\) = -j 397.89
Vout = Vin * ( R / R- C )
Vout = Vin * ( 397.89 / (397.89 - j 397.89))
Vout = \(\frac{1}{\sqrt{2} }\) Vin ∠45⁰
therefore gain = |\(\frac{Vout}{Vin }\)| = \(\frac{1}{\sqrt{2} }\) = 0.707 as a ratio
Gain in dB = 20 log 0.707 = -3 dB
D) Gain of filter at 55 kHz
c = 0.01 uF = \(\frac{-J}{2\pi foC }\) = -j 289.373 ohms
Vout = Vin * \(\frac{R}{R-C}\)
= Vin * ( 397.89 / ( 397.89 - j 289.373))
Gain in ratio \(|\frac{Vout}{Vin}|\) = 0.8087 ∠ 36.03⁰
therefore gain in ratio = 0.8087
Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB
ASAP PLease electrical engineering problem
Answers
Answer:
see attached
Explanation:
As you know, a full adder produces the binary value in (carry, output) that is the the number of true input bits among the (carry in, A, B) inputs.
The annotated diagram attached shows the bit values for a 4-bit full adder/subtractor.
__
Additional comment
If the numbers are considered "signed", then the top diagram will generate an "overflow" based on the difference between the carry C4 and the output O4.
The rafter is fastened to the outside wall so that the plumb cut in the birdsmouth is tight to the exterior wall sheathing
Select one:
O True
O False
Answers
when should ads-b equipment be operated on the ground while taxiing?
Answers
The ADS-B equipment should be operated on the ground while taxiing, this is called ADS-B Out.
What is ADS-B equipment?Automatic Dependent Surveillance-Broadcast (ADS-B) is a type of surveillance system that uses an aircraft's onboard Global Navigation Satellite System (GNSS) receiver to transmit position, velocity, and identification data to other aircraft and ground stations.
ADS-B Out is a system that enables an aircraft to transmit this data to ground stations and other aircraft, as well as to the ATC system, which uses it to provide separation between aircraft.
ADS-B Out is required in most airspace around the world, and it is a critical component of NextGen, the FAA's modernization program for the air traffic control system.
When the aircraft is taxiing on the ground, ADS-B equipment should be operated. ADS-B Out is required for all operations in Class A, B, and C airspace, as well as in airspace designated as "Class E" above 10,000 feet msl (mean sea level).
ADS-B Out is required for all aircraft with a maximum takeoff weight of more than 12,500 pounds, and it must be operable in all airspace where a Mode C transponder is currently required.
ADS-B In, which is not required by the FAA, is an optional feature that allows aircraft to receive traffic and weather information from ground stations and other aircraft.
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calculate how much work is required to launch a spacecraft
Answers
The work required to launch the spacecraft to a height of 200 km is approximately \(\(1.96 \times 10^9 \, \text{J}\)\) (joules).
To provide a general understanding, we can consider a simplified scenario where we calculate the work required to overcome the gravitational potential energy of the spacecraft during the launch from the surface of the Earth to a certain altitude.
The formula to calculate the work done against gravity is:
\(\[W = mgh\]\)
Where:
\(\(W\)\) is the work done (in joules)
\(\(m\)\) is the mass of the spacecraft (in kilograms)
\(\(g\)\) is the acceleration due to gravity (approximately \(\(9.8 \, \text{m/s}^2\)\) on Earth)
\(\(h\)\) is the change in height (in meters)
Let's assume the mass of the spacecraft is \(\(m = 10,000 \, \text{kg}\)\) and we want to calculate the work required to reach a height of \(\(h = 200 \, \text{km}\)\) above the Earth's surface.
First, we need to convert the height to meters by multiplying by 1,000:
\(\[h = 200 \, \text{km} \times 1,000 \\= 200,000 \, \text{m}\]\)
Next, we can substitute the values into the formula and calculate the work:
\(\[W = 10,000 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 200,000 \, \text{m} \\\\= 1.96 \times 10^9 \, \text{J}\]\)
Therefore, the work required to launch the spacecraft to a height of 200 km is approximately \(\(1.96 \times 10^9 \, \text{J}\) (joules)\).
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Give an example of one technology that is well matched to the needs of the environment, and one technology that is not.
Answers
Answer:
oh god... i have no idea lm.ao
Explanation:
he critical buckling load of an ideal column of circular cross section can be reduced by: The critical buckling load of an ideal column of circular cross section can be reduced by: increasing the Poisson's ratio of the column material increasing the length of the column increasing the modulus of elasticity of the column material increasing the diameter of the column
Answers
The critical buckling load of an ideal column of circular cross section can be reduced by increasing the diameter of the column.
What is critical load of buckling of column?The critical load is known to be that factor that is labeled the greatest load that is one which is unable to cause lateral deflection (buckling).
Note that For loads greater than the critical load, the column will tend to decrease laterally. The critical load is known to be one that puts the column in what we call the state of an unstable form of equilibrium.
The critical buckling load is based on the shape and dimensions of beam section that is said to have constant cross sectional area.
Hence, The critical buckling load of an ideal column of circular cross section can be reduced by increasing the diameter of the column.
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CASE STUDY
"Comparing Social Security Benefits"
Background
When Sheryl graduated from Northeastern University in 2000 and went to work for BAE Systems,
she did not pay much attention to the monthly payroll deduction for social security. It was a "necessary evil"
that may be helpful in retirement years. However, this was so far in the future that she fully expected this
government retirement benefit system to be broke and gone by the time she could reap any benefits from
her years of contributions.
This year, Sheryl and Brad, another engineer at BAE, got married. Recently, they both received
notices from the Social Security Administration of their potential retirement amounts, were they to retire and
start social security benefits at preset ages. Since both of them hope to retire a few years early, they
decided to pay closer attention to the predicted amount of retirement benefits and to do some analysis on
the numbers.
Information
They found that their projected benefits are substantially the same, which makes sense since their
salaries are very close to each other. Although the numbers were slightly different in their two mailings, the
similar messages to Brad and Sheryl can be summarized as follows:
If you stop working and start receiving benefits . . .
At age 62, your payment would be about $1,400 per month
At you full retirement age (67 years), your payment would be about $2,000 per month
At age 70, your payment would be about $2,480 per month
These numbers represent a reduction of 30% for early retirement (age 62) and an increase of 24%
for delayed retirement (age 70).
This couple also learned that it is possible for a spouse to take spousal benefits at the time that one
of them is at full retirement age. In other words, if Sheryl starts her $2000 benefit at age 67, Brad can
receive a benefit equal to 50% of hers. Then, when Brad reaches 70 years of age, he can discontinue spousal benefits and start his own. In the meantime, his benefits will have increased by 24%. Of course, this strategy could be switched with Brad taking his benefits and Sheryl receiving spousal benefits until age 70.
All these options led them to define four alternative plans.
A. Each takes early benefits at age 62 with a 30% reduction to $1400 per month.
B. Each takes full benefits at full retirement age of 67 and receives $2000 per month.
C. Each delays benefits until age 70 with a 24% increase to $2480 per month.
D. One person takes full benefits of $2000 per month at age 67, and the other person
receives spousal benefits ($1000 per month at age 67) and switches to delayed
benefits of $2480 at age 70.
They realize, of course, that the numbers will change over time, based on their respective salaries
and number of years of contribution to the social security system by them and by their employers.
Case Study Exercises
Brad and Sheryl are the same age. Brad determined that most of their investments make an average
of 6% per year. With this as the interest rate, the analysis for the four alternatives is possible. Sheryl and
Brad plan to answer the following questions, but don’t have time this week. Can you please help them? (Do
the analysis for one person at a time, not the couple, and stop at the age of 85.)
1. How much in total (without the time value of money considered) will each plan A through D
pay through age 85?
2. What is the future worth at 6% per year of each plan at age 85?
3. Economically, what is the best combination of plans for Brad and Sheryl, assuming they both
live to be 85 years old?
4. Develop at least one additional question that you think Sheryl and Brad may have. Answer
the question.
Answers
1. Total Social Security benefits without the time value of money considered at 85 years of age:Plan A: Early Retirement at 62Brad will receive $168,000 ($1,400/month * 12 months/year * 10 years)Sheryl will receive $168,000 ($1,400/month * 12 months/year * 10 years)Total $336,000
Plan B: Full Retirement at 67Brad will receive $216,000 ($2,000/month * 12 months/year * 9 years)Sheryl will receive $216,000 ($2,000/month * 12 months/year * 9 years)Total $432,000Plan C: Late Retirement at 70Brad will receive $297,600 ($2,480/month * 12 months/year * 5 years)Sheryl will receive $297,600 ($2,480/month * 12 months/year * 5 years)Total $595,200Plan D: Combined StrategyBrad will receive $216,000 ($2,000/month * 12 months/year * 9 years)Sheryl will receive $117,600 ($1,000/month * 12 months/year * 9 years) plusBrad will receive $357,840 ($2,480/month * 12 months/year * 8 years)Total $691,4402. Future worth at 6% per year of each plan at age 85:Plan A: $336,000Plan B: $432,000Plan C: $595,200Plan D: $691,4403
. Economically, the best combination of plans for Brad and Sheryl, assuming they both live to be 85 years old is Plan D (Combined Strategy) as it provides the highest total benefit of $691,440.4. Develop at least one additional question that you think Sheryl and Brad may have. Answer the question.The couple may want to know how Social Security benefits will be taxed and if they should delay withdrawing them to avoid or minimize taxes on their benefits. The taxation of Social Security benefits is dependent on the couple’s income. If the total income (which includes 50% of Social Security benefits) is more than $32,000 for couples filing jointly.
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you are to evaluate a solar pv investment in a sunny location where each 1 kw of capacity generates on average 115 kwh/month year-round. the system size is 5 kw rated, and electricity in the region costs $0.12/kwh. what is the value of the output from the system per year?
Answers
The value of the output from the 5 kW solar PV system per year in a sunny location where each 1 kW of capacity generates 115 kWh/month year-round is estimated to be $1,620.
The calculation is as follows: (5 kW x 115 kWh/month x 12 months) x $0.12/kWh = $1,620. This figure is calculated by multiplying the system size of 5 kW with the monthly output of 115 kWh/month and then multiplying that by 12 months to get the total output for the year. This figure is then multiplied by the cost of electricity of $0.12/kWh to get the value of the output from the system per year.
The solar PV investment in a sunny location with a system size of 5 kW rated and electricity cost of $0.12/kWh is estimated to be worth $1,620 per year.
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13. What two major safety problems does hydrogen present?
Answers
Answer:
The risks associated with the handling of liquid hydrogen are fire, explosion, asphyxiation and extremely low temperature exposure.
Answer:
fire, explosion, asphyxiation, extremely low temperature exposure/cold burns
Explanation:
A plant engineer is evaluating the purchase of two possible motors. Both motors are each rated at 125hp, but have different efficiencies and purchase costs. The less expensive motor has an initial purchase cost of $1000 and is 88% efficient. The more expensive motor has an initial purchase cost of $1500 and is 92% efficient. The plant pays $0.07/kW⋅h, which reflects the cost if the total electricity costs are paid at the end of year 10 . The annual effective interest rate over a 10 -year period of life is 10%. If both options have the same net present worth and the same operating time per year, what is most nearly the operating time per year? (A) 250 h/yr (B) 400 h/yr (C) 690 h/yr (D) 720 h/yr
Answers
We are required to determine the operating time per year in the given case. Here's how we can solve this problem:A plant engineer is evaluating the purchase of two possible motors.
Both motors are each rated at 125hp, but have different efficiencies and purchase costs. The less expensive motor has an initial purchase cost of $1000 and is 88% efficient. The more expensive motor has an initial purchase cost of $1500 and is 92% efficient.
The plant pays
$0.07/kW⋅h,
which reflects the cost if the total electricity costs are paid at the end of year 10. The annual effective interest rate over a 10-year period of life is 10%.The net present value (NPV) formula to compare two different options of investment (purchase of a motor in this case) is
NPV = C1 + C2/(1+i)² + C3/(1+i)³ + ….. - CI/(1+i)n
where,Ci = Cash inflow/outflow for year i (year 0 is usually the present year)
i = Discount rate
N = life of the investment
As both the options have the same net present value, we can assume that the net present value for both the options would be equal.
Calculating the net present value of Option 1 (Less expensive motor):Initial purchase cost
= $1000Operating cost (electricity)
= (125hp × 0.746 kW/hp) × (1/0.88 - 1) × 365 × 24 h/yr × $0.07/kWh =$6158.01
Net Present Value of Option
1 = -$1000 - $6158.01/(1+0.10)²
= -$4641.63
Calculating the net present value of Option 2 (More expensive motor):Initial purchase cost
= $1500O
perating cost (electricity)
= (125hp × 0.746 kW/hp) × (1/0.92 - 1) × 365 × 24 h/yr × $0.07/kWh
= $5337.69Net Present Value of Option 2
= -$1500 - $5337.69/(1+0.10)² = -$4665.
14Now we can use the following equation:Operating time per year
= (annual electricity cost)/(125hp × 0.746 kW/hp × (1/η - 1))where,η
= Efficiency of the motorUsing the above equation for both the options, we get:Operating time per year for Option 1
= $6158.01/(125hp × 0.746 kW/hp × (1/0.88 - 1))
= 614.36 h/yrOperating time per year for Option 2
= $5337.69/(125hp × 0.746 kW/hp × (1/0.92 - 1))
= 690.47 h/yr
Therefore, the most nearly operating time per year is (C) 690 h/yr.
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A 1000 mm wide steel sheet made of C35 is normalized by cold rolling 10 mm thick
deformed to 5 mm. The rollers, 600 mm in diameter, run at a peripheral speed of 0.12 m/s.
The deformation efficiency is 55%.
Find out:
a) the roller force
b) the roller torque
c) the performance on the pair of rollers.
Answers
Answer:
a. 20.265 MN
b. 0.555 MNm
c. 403.44 KW
Explanation:
Given:-
- The width ( w ) = 1000 mm
- Original thickness ( to ) = 10 mm
- Final thickness ( t ) = 5 mm
- The radius of the rollers ( R ) = 600 mm
- The peripheral speed of the roller ( v ) = 0.12
- Deformation efficiency ( ε ) = 55%
Find:-
a) the roller force ( F )
b) the roller torque ( T )
c) the performance on the pair of rollers. ( P )
Solution:-
- The process of flat rolling entails a pair of compressive forces ( F ) exerted by the rollers on the steel sheet that permanently deforms.
- The permanent deformation of sheet metal is seen as reduced thickness.
- We will assume that the compressive force ( F ) acts normal to the point of contact between rollers and metal sheet.
- The roll force ( F ) is defined as:
\(F =L*w*Y_a_v_g\)
Where,
L: The projected length of strip under compression
Y_avg: The yielding stress of the material = 370 MPa
- The projected length of strip under compression is approximated by the following relation:
\(L = \sqrt{R*( t_o - t_f )} \\\\L = \sqrt{0.6*( 0.01 - 0.005 )} \\\\L = 0.05477 m\)
- The Roll force ( F ) can be determined as follows:
\(F = (0.05477)*(1 )*(370*10^6 )\\\\F = 20.265 MN\)
- The roll torque ( T ) is given by the following relation as follows:
\(T = \frac{L}{2} * F\\\\T = \frac{0.05477}{2} * 20.265\\\\T = 0.555 MNm\)
- The rotational speed of the rollers ( N ) is determined by the following procedure:
\(f = \frac{v}{2\pi* R} = \frac{0.12}{2*\pi 0.6} = 0.03181818 \frac{rev}{s} \\\\N = f*60 = 1.9090 rpm\)
- The power consumed by the pair of rollers ( P ) is given by:
\(P = \frac{2\pi * F * L * N}{e*60,000} KW \\\\P = \frac{2\pi * ( 20.265*10^6) * (0.05477) * (1.90909 ) }{60,000*0.55} KW\\\\P = 403.44 KW\)
Explain why the scenario below fails to illustrate an understanding of the importance of metrology. Situation: Natalie is a calibration technician at a food production plant. Natalie: "The oven is just a couple of degrees off. I will just wait a few hours to see if it will level out on its own"
Answers
Answer:
Explanation:
The situation being described completely fails in regard to the importance of metrology. This is because the main importance of metrology is making sure that all of the measurements in a process are as accurate as possible. This accuracy allows an entire process to function efficiently and without errors. In a food production plant, each individual department of the plant relies on the previous function to have completed their job with the correct and accurate instructions so that they can fulfill their functions correctly and end up with a perfect product. If the oven (like in this scenario) is a couple of degrees off it can cause the product to come out burned or undercooked, which will then get transferred to the next part of production which will also fail due to the failed input (burned or undercooked product). This will ultimately lead to an unusable product at the end of the process and money wasted. Which in a large production plant means thousands of products in a single batch are thrown away.
In terms of the necessity of metrology, the situation stated absolutely fails. This is because metrology's primary goal is to ensure that all measurements in a process are as precise as feasible. This precision allows a whole process to run smoothly and error-free. If the oven temperature is wrong by a few degrees, the product will come out charred or undercooked, and the product will be sent to the next step of the process, which will also fail owing to the failed input. This will result in a useless product and a waste of money at the end of the procedure. In a big manufacturing facility, this means thousands of goods are discarded in a single batch.
How large a force is required to accelerate a 1300 kg car from rest to a speed of 20 m/s in a distance of 80 m?
Answers
F=m*a
F=80*20
F =1600 ans"
Answer: basically we are asked to find it's force and the formula that helps us to find force is Force= Mass× Acceleration
so let's put out the given and what we need to find
GIVEN. Solution
F=m.a
Mass= 1300. F=1300kg×20m/s
speed (Acceleration)=20m/2. F=26000Kg.m/s
Force=? F=26000N
N stands for Newton and the reason that it comes Newton is because it is the SI-unit of Force and the result of kg×m/s.
how is an nmos and gate implemented? group of answer choices a single nmos transistor. 2 nmos transistors in series. 2 nmos transistors in parallel. the output of 2 nmos transistors in series connected to the input of a single nmos transistor. the output of 2 nmos transistors in parallel connected to the input of a single nmos transistor. the output of a single nmos transistor connected to the input of 2 nmos transistors in series. the output of a single nmos transistor connected to the input of 2 nmos transistors in parallel.
Answers
An nmos and gate can be implemented using 2 nmos transistors in series, or the output of 2 nmos transistors in parallel connected to the input of a single nmos transistor.
Implementing an nmos AND gate using two transistors in series or in parallelIn the first implementation, the two nmos transistors are connected in series, with the input signal connected to the gate of the first transistor and the output taken from the drain of the second transistor. When the input signal is high, the first transistor is turned on, allowing current to flow to the second transistor. If the second transistor is also turned on, the output will be low, otherwise, the output will be high.
In the second implementation, the two nmos transistors are connected in parallel, with their sources and gates connected together, and the output taken from the drains. When the input signal is high, both transistors are turned on, allowing current to flow to the output. If either of the transistors is turned off, the output will be low.
Both of these implementations use two nmos transistors, but they are connected differently to achieve the desired logic function. A single nmos transistor can be used to implement a NOT gate or an inverter, but it cannot implement an AND gate
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FILL THE BLANK.a tyrosine trna has ___________ in its folded structure.
Answers
a tyrosine tRNA has a sequence of three nucleotides in its anticodon loop that corresponds to the three nucleotides in the mRNA codon for tyrosine, which is UAC.
A tyrosine tRNA has an anticodon in its folded structure.What are tRNAs?tRNAs or transfer RNAs are short, single-stranded RNA molecules that are about 70 to 80 nucleotides in length. They assist in protein synthesis by conveying amino acids to the ribosome. They bind with a particular amino acid on one end and have a specific anticodon sequence on the other. A tRNA molecule has a unique tertiary structure, a cloverleaf shape, formed by intramolecular base-pairing among four regions known as arms.
In its folded structure, a tyrosine tRNA has an anticodon, which is a three-nucleotide sequence in the tRNA molecule that recognizes the corresponding codon on mRNA during translation. Thus, a tyrosine tRNA has a sequence of three nucleotides in its anticodon loop that corresponds to the three nucleotides in the mRNA codon for tyrosine, which is UAC.
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Which step in the reverse-engineering process involves the identification of subsystems and their relationship to one another?
Answers
The answer is analyze
Assign distancePointer with the address of the greater distance. If the distances are the same, then assign distancePointer with nullptr.
Ex: If the input is 37.5 42.5, then the output is:
42.5 is the greater distance.
#include
#include
using namespace std;
int main() {
double distance1;
double distance2;
double* distancePointer;
cin >> distance1;
cin >> distance2;
/* Your code goes here */
if (distancePointer == nullptr) {
cout << "The distances are the same." << endl;
}
else {
cout << fixed << setprecision(1) << *distancePointer << " is the greater distance." << endl;
}
return 0;
}
Answers
When it comes to the given code, we have to create code that assigns the value of the greater distance to the distancePointer. If the two distances are the same, then we have to set the pointer to a nullpr.
The code can be completed with these steps: Create a pointer distancePointer for double type. Then, Assign it to the address of distance1.
After that, compare distance1 with distance2, and if distance2 is greater, then assign the address of distance2 to distance Pointer instead of distance1.
If distance1 is greater, do not change the value of distancePointer and if distance1 and distance2 are equal, assign distancePointer to a nullptr. Finally, output the greater distance. Here is the code for the same.Example
#include
#include
using namespace std;
int main() {
double distance1;
double distance2;
double* distancePointer;
cin >> distance1;
cin >> distance2;
distancePointer = &distance1;
if (distance2 > distance1) {
distancePointer = &distance2;
}
else if (distance1 == distance2) {
distancePointer = nullptr;
}
if (distancePointer == nullptr) {
cout << "The distances are the same." << endl;
}
else {
cout << fixed << setprecision(1) << *distancePointer << " is the greater distance." << endl;
}
return 0;
}
The output of this code for the input 37.5 42.5 should be “42.5 is the greater distance.”.
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If Nick's average stride length is 2.7 feet, how many strides will it take him to walk to school?
Answers
Answer: how far is the school?
Explanation:
20.5 LAB: Area of a triangle Using Heronis formula, you can calculate the area of a triangle if you know the lengths of all three sides Given the length of each side of a triangle as input, calculate the area of the triangle using Heronis formula as follows 1.s = half of the triangles penmeter 2. area = the square root of s (s-a)(s-b)(s-c), where a, b, and care each sides of the triangle
Hot Use the son function from the math module to calculate the square root Outpat the floating point value of the area with three digits after the decimal point, which can be achieved as follows print("The area of the triangle is: t:.3f).format(your_value))
Ex if the input for a, b, and is 3.0
4.0 5.0
the output is The area of the triangle list 6.000
Answers
To calculate the area of a triangle using Heron's Formula, you must first calculate the perimeter, 's'. This is done by taking half of the sum of the lengths of the sides of the triangle (a, b, and c). Once you have 's', you can then calculate the area of the triangle using the following equation:
Area = square root of s (s-a)(s-b)(s-c),
where:
a, b, and c are each side lengths of the triangle.For example, if the input for a, b, and c are 3.0, 4.0, and 5.0 respectively, the perimeter, 's' would be 6.0. Then the area of the triangle can be calculated as follows:
Area = square root of 6.0 (6.0-3.0)(6.0-4.0)(6.0-5.0) = 6.000Therefore, the output for the given example is: The area of the triangle is: 6.000
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How have changes in the media and modern technology most changed how candidates campaign?Candidates often spend less on advertisements and more on polling.Candidates must explain their positions well in written newspaper articles.Candidates often effectively use social media to reach voters.Candidates must be able to give convincing in-person speeches.
Answers
Answer:
The changes in media and modern technology have had a significant impact on how candidates campaign. One of the most significant changes is the increasing use of social media by candidates to reach voters. This has made it easier for candidates to directly engage with voters and share their message without having to rely on traditional forms of media, such as television and print ads.
Additionally, the rise of online news sources and the ability for individuals to access information instantly on their phones has made it important for candidates to be able to clearly and concisely explain their positions in written articles. This has led to a greater emphasis on messaging and communication strategies in campaigns.
Overall, the changes in media and technology have made it easier for candidates to connect with voters and share their message, but have also raised the bar for how effectively they must do so in order to be successful.
Explanation: