where is ΔH the equation

2 NaCl --> 2 Na + Cl2

ΔH = -411 kJ/mol. Write the balanced equation for the reaction, being sure to include energy as a reactant or product.

Answer:

Generally the internal filling volume needs to be a higher volume level than the external volume level of the sample while the probe is submerged at all times.

Explanation:

Hope this helps you!

The reaction : Pb(NO3)₂ + KCl ---->  PbCl₂ + KNO₃ , the specie which will precipitate in the queous solution is the correct option is D)  PbCl₂ .

The complete balanced equation is as :

Pb(NO3)₂(aq) + 2KCl(aq) ---->  PbCl₂(s) + 2KNO₃(aq)

The potassium ion belongs to the 1 group. The 1 group salt are generally soluble salts. Therefore the KCl is soluble in water. Most of the salt containing the nitrates ion are soluble in the salt. Therefore , the Pb(NO3)₂ and KNO₃ are soluble in the aqueous solution. The salts of lead halide are not soluble.

Therefore, the PbCl₂ will form the precipitate in the chemical reaction.

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As per the balanced reaction given, 4 moles of ammonia reacts with 6 moles of NO. Therefore, the number of moles of NO required to react with 2.45 moles of ammonia is 3.46.

Nitric oxide is a covalent compound formed from the electron sharing between nitrogen and oxygen atom. Nitric oxide is a common gas found in atmosphere.

NO reacts with ammonia gas produces nitrogen gas and water as per the balanced chemical equation given. It is clear that 4 moles of ammonia reacts with 6 moles of NO.

The number of moles of NO required to react with 2.45 moles of ammonia is calculated as follows:

number of moles of NO  = 2.45 × 6 /4 = 3.46.

Therefore, 3.46 moles of NO is required to completely react with 2.45 moles of ammonia.

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Answer: Electrons are shared to fill outer electron shells

Explanation: It is the sharing of electrons between atoms with an electronegativity difference above 1.7.

The units of the rate constant are \(M^-^1s^-^1.\)

The overall order of a reaction is the sum of the orders of the reactants in the rate law. For a reaction with an overall order of 2, the rate law has the form:

rate =\(k[A]^m[B]^n\)

where k is the rate constant, A and B are reactants, and m and n are the orders of A and B, respectively. Since the overall order is 2, we have m + n = 2.

The units of the rate constant depend on the overall order of the reaction and the units of the concentration of the reactants. For a second-order reaction, the units of the rate constant are:

k = \(M^-^1s^-^1\)

This can be derived from the rate law:

rate = \(k[A]^2\)

where the units of rate are M/s and the units of [A] are M. Substituting the units, we get:

M/s = (M-1s-1) ×\(M^2\)

Simplifying, we get:

M/s =\(M^3s^-^1\)

Dividing by\(M^2\), we get:

1/s =\(M^-^1s^-^1\)

Therefore, the units of the rate constant are\(M^-^1s^-^1\).

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Answer:

This is a tough one, because all three seem correct. If your lesson has a direct definition of 'observation', I would take a look and see if it applies to any of these.

Explanation:

However, in science, an observation is just the starting to point for an experiment or hypothesis. So, if we were to look at the 'starting point' of the journey of this apple, option a is the general starting point. It isn't too specific, but it provides an observation of a process that happens.

The molecular formula for the substance with a molar mass of 1644.28 g/mol and an empirical formula of Bg₂DGr₃ is Bg₁₀D₅Gr₁₅.

To determine the molecular formula, we need to calculate the molecular weight of the empirical formula, which can be done by adding up the molar masses of the atoms in the empirical formula.

The molar mass of Bg₂DGr₃ is:

(2 x 10.81 g/mol) + (3 x 2.01 g/mol) + (3 x 72.63 g/mol) = 328.50 g/mol

Next, we can divide the given molar mass by the empirical formula mass to get the ratio between the empirical formula and the molecular formula:

1644.28 g/mol ÷ 328.50 g/mol = 5

This tells us that the molecular formula contains 5 times as many atoms as the empirical formula. To find the molecular formula, we simply multiply the subscripts in the empirical formula by 5:

Bg₁₀D₅Gr₁₅

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Answer:

-205.7kj

Explanation:

Now adding reaction 2 and twice of reaction 3 and reverse of reaction 1, we get the enthalpy of the reaction.

The expression for enthalpy for the following reaction will be,

where,

n = number of moles

Now put all the given values in the above expression, we get:

Therefore, the enthalpy of the following reaction is,  -205.7kj

Answer:

If they mean the type of animal in the first question, they are both foxes.

They have different fur colors and are in different location/habitats

Yes, they are the same animal because they have almost the same features; Their fur color is different so they can blend better into the environment around it.

Explanation:

I hope this helps

Answer: because its more scientific and "formal"? I guess.

Explanation:

Answer:

Synthesis

Explanation:

 The reaction:

                 2Mg + O₂   →   2MgO

This reaction above is a synthesis or combination reaction. In such reaction, several products combines to give a single product.

The formation of a single product from two or more reactants is classified under this type of reaction

The driving force for this reaction type is the large and negative heat of formation of the product.

Answer:

The best example of direct observation is when the researcher of animal behavior directly observe how animal lives in a reservation.

Answer:

Explanation:

the ions have different number of electron and the charge is different aswell the neutrons they have different mass

Both have similar number of proton as well as different number of neutron and electron.

The particle composition of nitrogen atom and two nitrogen ions are similar because both have present same atomic number i.e. 7 as well as number of proton i.e. 7 while on the other hand, nitrogen atom and two nitrogen ions have differences such as both have different number of neutron and electron as well as charges on it.

Nitrogen atom has 7 electrons but the nitrogen ion which have negative charge has 10 electrons whereas nitrogen which has positive charge has 4 electrons in its shell so we can conclude that both have similarities i.e. number of proton as well as differences i.e. number of neutron and electron.

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The balanced chemical equation of the reaction between sodium sulfate and water to form sodium hydroxide and hydrogen sulfate is as follows:

Na₂SO₄ + 2H₂O → 2Na(OH) + H₂SO₄

A chemical reaction is a process, typically involving the breaking or making of interatomic bonds, in which one or more substances are changed into others.

A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, sodium sulfate and water react to form sodium hydroxide and hydrogen sulfate. The balanced chemical equation is as follows:

Na₂SO₄ + 2H₂O → 2Na(OH) + H₂SO₄

The equation is said to be balanced because the number of atoms of each element are the same on both sides of the equation.

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Answer:

22.4 Liters at STP

Explanation:

General Rule => Any (ALL) gas will occupy 22.4 Liters at Standard Conditions (STP).

A photosynthetic reaction is the formation of the glucose and oxygen molecule by water and carbon dioxide. 12 moles of water will be used in the reaction.

Moles are the ratio of the mass of the substance to the molar mass of the substance.

In the photosynthetic reaction, 6 moles of carbon dioxide and 6 moles of water are utilized to produce 1 mole of a glucose molecule and 6 moles of oxygen.

From this, it can be said that the number of moles consumed of carbon dioxide and water will be equal and in the ratio of 1:1.

The number of moles of carbon dioxide will be equal to that of the water molecule and will also be equal to the ratio of the mass of carbon dioxide to the molar mass of carbon dioxide.

The moles of water will be calculated as:

\(\begin{aligned}\rm moles &= \rm \dfrac{\text{mass of CO}_{2}}{\text{molar mass of CO}_{2}}\\\\&= \dfrac{528}{44.01}\\\\&= 12\;\rm moles\end{aligned}\)

Therefore, option A. 12 moles of water will be used.

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  The density of cork is around 0.24 to 0.32 g/cm³.

Cork is a lightweight and porous material, and its density varies depending on factors such as the type of cork and its production process. The density of natural cork ranges from 0.24 to 0.32 g/cm³, while the density of agglomerated cork (made by compressing cork granules) can be higher, ranging from 0.40 to 0.70 g/cm³. The low density of cork makes it a popular choice for a variety of applications, including wine bottle stoppers, insulation, and flooring.  

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Antibodies against nicotinic acetylcholine receptors (nAChR), present at neuromuscular junction (NMJ), can affect function of junction by interfering with normal signaling between nerve and muscle.

Antibodies against nicotinic acetylcholine receptors (nAChR), which are present at neuromuscular junction (NMJ), can affect the function of junction by interfering with normal signaling between nerve and muscle.

At NMJ, the nerve terminal releases acetylcholine (ACh), which binds to nAChR on muscle cell membrane, leading to depolarization of muscle cell and muscle contraction. If antibodies bind to nAChR, they can block or reduce the number of available receptors for ACh, leading to decrease or even complete loss of the normal muscle response to nerve stimulation.

This can result in muscle weakness, fatigue, and even paralysis, depending on the severity of antibody binding and amount of functional nAChR remaining at the NMJ.

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Explanation:

1. If you measure the value of Hydronium concentration is 3.0x10-3 M/L, the solution can be predicted to be acidic. This is because the concentration of hydronium ions, H3O+, is greater than the concentration of hydroxide ions, OH-. The pH value of an acidic solution is less than 7. Since hydronium ions are present in a high concentration, the pH value of the solution will be less than 7.

2. If you measure the number of Hydronium ions is 3.0x1012, the solution can be predicted to be acidic. This is because the concentration of hydronium ions is greater than 1.0 x 10^-7 M/L. The pH value of an acidic solution is less than 7.

3. If you measure the number of Hydroxide ions is 3.0x10-2 moles, the solution can be predicted to be basic. This is because the concentration of hydroxide ions is greater than 1.0 x 10^-7 M/L. The pH value of a basic solution is greater than 7. Hence, if the number of hydroxide ions is greater than 1.0 x 10^-7 M/L, the solution will be basic.

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The name of the process shown in the diagram is of filtration which is a separation technique.

Filtration is defined as a process by which solid particles which are present in liquid or gaseous medium are allowed to be removed using a filter medium which retains the particles but allows the liquid to pass through.

The requirements for filtration are a filter medium ,fluid containing particles , a mechanical device usually a filter and a driving force.The filter media is classified depending on the pore size of particles which are to be filtered.

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Sodium chloride solution cannot be used as the electrolyte to produce sodium metal because water is present in the solution, and water molecules can be electrolyzed to produce hydrogen gas, interfering with the desired production of sodium metal.

In more detail, during electrolysis, the electric current is passed through the electrolyte to facilitate the breakdown of the compound into its constituent elements. In the case of sodium chloride solution, water (H2O) molecules are also present. At the cathode, where reduction occurs, water can be electrolyzed instead of sodium ions (Na+) to produce hydrogen gas (H2) and hydroxide ions (OH-). This means that instead of obtaining sodium metal, the electrolysis of sodium chloride solution would predominantly yield hydrogen gas. To produce sodium metal, it is necessary to use molten sodium chloride, where water molecules are absent and the sodium ions can be selectively reduced to form sodium metal.

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Cody's vehicle accelerates by 3 m/s2 (northward) in the 15 seconds it takes to go from 0 m/s to 45 m/s (northward).

Newton's second law, which states that the force acting on a body is equal to the mass of the body, is the fundamental equation of motion in classical mechanics acceleration an of its center of mass, or F = ma.

When the final velocity is 45 m/s (northward), the beginning velocity is 0 m/s, and the time is 15 seconds, we can calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.

When these values are added to the formula, we obtain:

acceleration = (45 m/s - 0 m/s) / 15

acceleration = 3 m/s² (northward).

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(1) Here you first calculate the amount of substance from the mass and the molar mass. Then you multiply by the constant.

first: n = m / M             then: n * 6 * 10²³ = number of atoms

a) n = 4 g / 24 g/mol            number of atoms = 0,166 mol * 6 * 10²³ 1/mol

   n = 0,166 mol                   number of atoms = 0,96 * 10²³

b) n = 0,12 g / 12 g/mol       number of atoms = 0,01 mol * 6 * 10²³ 1/mol

   n = 0,01 mol                    number of atoms = 0,06 * 10²³

c) n = 32 g /48 g/mol         number of molecules = 0,666 mol * 6 * 10²³ 1/mol

   n = 0,666 mol                number of molecules = 4 * 10²³

d) n = 14,2 g / 71 g/mol      number of molecules = 0,2 mol * 6 * 10²³ 1/mol

   n = 0,2 mol                     number of molecules = 1,2 * 10²³

   Sodium sulfate has the formula Na2SO4, so it has two sodium atoms per  

   molecule. So you have to multiply the number of molecules by 2.

   number of atoms = number of molecules * 2

   number of atoms = 1,2 * 10²³ * 2

   number of atoms = 2,4 * 10²³

(2) The amount of substance can easily be calculated:

n = m / M

a) n = 16 g / 16 g/mol

   n = 1 mol

b) n = 0,14 g / 14 g/mol

   n = 0,01 mol

c) n = 5,4 g / 108 g/mol

   n = 0,05 mol

d) n = 8,88 g / 35,5 g/mol

   n = 0,25 mol

(3) With the same formula the mass can now be calculated, for this it only has to be converted according to the mass:

n = m / M      | *M

m = n * M

a) m = 0,05 mol * 16 g/mol

   m = 0,8 g

b) m = 10 mol * 23 g/mol

   m = 230 g

c) m = 0,01 mol * 1 g/mol

   m = 0,01 g

d) m = 0,25 mol * 65,4 g/mol

   m = 16,35 g

(4) The molar mass of a molecule is obtained by adding the molar masses of the individual atoms:

a) Br = 80 g/mol → Br2 = 2 * 80 g/mol = 160 g/mol

b) C = 12 g/mol, O = 16 g/mol → CO2 = 12 g/mol + 2 * 16 g/mol = 44 g/mol

c) H = 1 g/mol, N = 14 g/mol, O = 16 g/mol

  → HNO3 = 1 g/mol + 14 g/mol + 3* 16 g/mol = 63 g/mol

d) Cu = 64 g/mol, S = 32 g/mol, O = 16 g/mol,  H = 1 g/mol

   →CuSO4*5H2O = 64 g/mol + 32 g/mol + 4 * 16 g/mol + 5 * (2 * 1 g/mol +

     16 g/mol) = 250 g/mol

(5) Exercise 5 works exactly like exercise 2 and 4:

first: Calculate molar mass                    then: n = m / M

a) n = 128 g / 16 g/mol

   n = 8 mol

b) M = 39 g/mol + 14 g/mol + 3 * 16 g/mol

   M = 101 g/mol

   n = 25,25 g / 101 g/mol

   n = 0,25 mol

c) M = 2 * 12 g/mol + 6 * 1 g/mol + 16 g/mol

   M = 46 g/mol

   n = 414 g / 46 g/mol

   n = 9 mol

(6) Exercise 6 works exactly the same as exercises 3 and 4:

first: Calculate molar mass                    then: m = n * M

a) M = 32 g/mol + 2 * 16 g/mol

   M = 64 g/mol

   m = 2 mol * 64 g/mol

   m = 128 g

b) M = 2 * 1 g/mol + 32 g/mol + 4 * 16 g/mol

   M = 98 g/mol

   m = 20 mol * 98 g/mol

   m = 1960 g

c) M = 23 g/mol + 16 g/mol + 1 g/mol

   M = 40 g/mol

   m = 0,5 mol * 40 g/mol

   m = 20 g

(a) The molarity of the solution is approximately 0.0141 M.N (b) The molarity of the solution is 0.03 M.

To calculate the molarity of a solution, we use the formula;

Molarity (M) = moles of solute/volume of solution (in liters)

Let's calculate the molarity for each of the given solutions;

30 g of Co(NO₃)₂.6H₂O in 4.3 L of the solution;

First, we need to determine the number of moles of Co(NO₃)₂.6H₂O.

The molar mass of Co(NO₃)₂.6H₂O can be calculated as follows;

1 mole of Co = 58.93 g/mol

2 moles of N = 2 × 14.01 g/mol = 28.02 g/mol

12 moles of O = 12 × 16.00 g/mol = 192.00 g/mol

12 moles of H₂O = 12 × (2 × 1.01 g/mol + 16.00 g/mol)

= 216.36 g/mol

Total molar mass = 58.93 g/mol + 28.02 g/mol + 192.00 g/mol + 216.36 g/mol = 495.31 g/mol

Now, let's calculate the moles of Co(NO₃)₂.6H₂O;

moles = mass / molar mass = 30 g / 495.31 g/mol

≈ 0.06058 mol

Now, we can calculate the molarity;

Molarity (M) = moles / volume

= 0.06058 mol / 4.3 L ≈ 0.0141 M

Therefore, the molarity of the solution is approximately 0.0141 M.

30 mL of 0.5 M H₂SO₄ diluted to 500 mL:

First, let's determine the moles of H₂SO₄ in the 30 mL solution.

Moles = Molarity × Volume (in liters)

= 0.5 mol/L × 0.030 L = 0.015 mol

Since the solution is diluted to 500 mL, we need to consider the final volume of the solution.

Molarity (M) = moles / volume

= 0.015 mol / 0.500 L

= 0.03 M

Therefore, the molarity of the solution is 0.03 M.

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