Answer:
Compound
Explanation:
how can you change the amplitude of a wave?
Answer:
"Changing the amplitude of a signal is straightforward: We just need to multiply each sample with some constant number. In the case of sine waves, if what we want is a wave with amplitude a, our wave function becomes y = a * Math.sin(x)."
Explanation:
Risk*
Imagine repeating the timing experiments you ran in this lab, only this time starting with a partially-charged capacitor. Describe how the timings differ from above. Explain how this difference originates from specific electrical quantities in the circuit (e.g. charge, voltage, etc.).
The timing experiments with a partially-charged capacitor result in shorter charging and discharging times, and the voltage across the capacitor starts at a certain level determined by the initial charge.
How do timing experiments differ with a partially-charged capacitor?When repeating the timing experiments with a partially-charged capacitor, the differences can be summarized in the following points:
Charging Time:
Shorter compared to starting with a fully discharged capacitor.Capacitor already holds some charge, requiring less time to reach the desired voltage level.Higher initial charge leads to a shorter charging time.Voltage Rise:
Capacitor starts with a certain voltage level determined by the initial charge.Voltage across the capacitor increases until it reaches the supply voltage.Rate of voltage rise depends on circuit parameters like resistance and capacitance values.Discharging Time:
Discharge process starts from a higher voltage level compared to starting with a fully charged capacitor.Shorter discharging time compared to starting from a fully charged capacitor.Timing Dependency:
Specific timings depend on circuit parameters such as resistance, capacitance, and initial charge on the capacitor.Interaction between these quantities determines the behavior of the circuit and resulting timing measurements.Learn more about capacitor
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The heat anticipator in a thermostat prevents the temperature in the conditioned space from rising above the thermostat setting. True/False
The heat anticipator in a thermostat prevents the temperature in the conditioned space from rising above the thermostat setting. This statement is false.
What is a thermostat?A thermostat is a temperature-regulating device that maintains a constant temperature in a heating and cooling system. When the temperature reaches a certain level, the thermostat causes the system to turn on or off. It is an important part of an HVAC system since it helps maintain the temperature within a room or building.
The thermostat's heat anticipator is an electrical device that determines when to shut off the heating or cooling system before the set temperature is reached. It accomplishes this by adding a small amount of resistance to the thermostat's circuit, which results in a little current flowing through the heating element of the thermostat.
It reduces overshooting by turning off the heating or cooling system before it reaches the set temperature, ensuring that the space temperature does not go beyond the thermostat setting. So, in conclusion, the correct explanation is false because the heat anticipator helps to maintain the temperature from overshooting the thermostat setting.
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Find the velocity and acceleration at (1,2,3) after 1 sec, for a three dimensional flow by u = yz+t √= xz-t ₁w=xy
Velocity at (1, 2, 3) after 1 second: V = (1, (z/2√(xz - t)), 0).
Acceleration at (1, 2, 3) after 1 second: A = (0, 0, 0).
To find the velocity and acceleration at the point (1, 2, 3) after 1 second for the given three-dimensional flow, we need to calculate the derivatives of the flow field equations with respect to time (t) and evaluate them at the given point and time.
The given flow field equations are:
u = yz + t
v = √(xz - t)
w = xy
To find the velocity, we take the time derivatives of each component:
du/dt = 0 + 1 = 1
dv/dt = (1/2) * (1/sqrt(xz - t)) * (z - 0) = (1/2) * (z/sqrt(xz - t))
dw/dt = x * 0 = 0
Therefore, the velocity vector at the point (1, 2, 3) after 1 second is:
V = (1, (z/2√(xz - t)), 0).
To find the acceleration, we take the time derivatives of the velocity components:
d²u/dt² = 0
d²v/dt² = (1/2) * (1/sqrt(xz - t)) * (0 - 0) = 0
d²w/dt² = 0
Therefore, the acceleration vector at the point (1, 2, 3) after 1 second is:
A = (0, 0, 0).
In summary:
Velocity at (1, 2, 3) after 1 second: V = (1, (z/2√(xz - t)), 0).
Acceleration at (1, 2, 3) after 1 second: A = (0, 0, 0).
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which galaxy is moving away from earth the fastest? which galaxy is moving away from earth the fastest? m 77 m105 m 104 m60
m105 is moving away from earth the fastest
Define a galaxy
A galaxy is a vast collection of stars, solar systems, gas, and dust. Gravity holds a galaxy together. A supermassive black hole also resides in the center of our galaxy, the Milky Way. You see additional stars in the Milky Way as you look up at the stars in the night sky.
While the greatest galaxies can have up to 100 trillion stars, the tiniest galaxies only have a "mere" few hundred million stars! Spiral, elliptical, peculiar, and irregular galaxies are the four main types that have been identified by scientists.
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A brick, milk, and ice cubes are all examples of matter.
true because
brick: solid
milk: liquid
ice cube: solid
Advanced Wireless Services (AWS) is a wireless telecommunications spectrum band used for mobile voice and data services, video, and messaging. The AWS band uses frequencies in several segments: from 1695 to 2200 MHz. a) Determine the corresponding range of wavelengths used by the AWS mobile devices. b) To what region/band of electromagnetic spectrum does the range belong
Given data
*The given frequency is
\(f_1_{}=1695\text{ MHz}=1695\times10^6\text{ Hz}\)*The another given frequency is
\(f_2=2200\text{ MHz=}2200\times10^6\text{ Hz}\)*The given speed of light is c = 3.0 × 10^8 m/s
(a)
The formula for the wavelength is given as
\(\lambda_1=\frac{c}{f_1}\)Substitute the known values in the above expression as
\(\begin{gathered} \lambda_1=\frac{(3\times10^8)}{(1695\times10^6)^{}} \\ =0.176\text{ m} \end{gathered}\)The another wavelength for the another frequency is calculated as
\(\begin{gathered} \lambda_2=\frac{c}{f_2} \\ =\frac{(3.0\times10^8)}{(2200\times10^6)} \\ =0.136\text{ m} \end{gathered}\)(b)
Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.
a power plant uses a 912 kelvin boiler and a river at 320 kelvin for cooling. what is the heat engine efficiency (in percent) of this power plant? use exact numbers; do not estimate.
The efficiency of this power plant is approximately 64.91% (to two decimal places).
What do you understand by the efficiency of a heat engine?The efficiency of a heat engine refers to the ratio of the useful work output of the engine to the heat energy input. In other words, it is a measure of how much of the heat energy put into the engine is converted into useful work, and how much is wasted.
The efficiency of a heat engine is given by:
η = 1 - T_c/T_h
where η is the efficiency, T_c is the temperature of the cold reservoir (in Kelvin), and T_h is the temperature of the hot reservoir (in Kelvin).
In this case, the temperature of the boiler (hot reservoir) is T_h = 912 K, and the temperature of the river (cold reservoir) is T_c = 320 K. Plugging these values into the efficiency equation, we get:
η = 1 - 320/912
= 1 - 0.35087719298...
= 0.64912280701...
Therefore, the efficiency of this power plant is approximately 64.91% (to two decimal places).
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if a surface is a diffuse emitter, then the intensity of the emitted radiation is independent of
a.wavelength
b.direction
c.temperature
If a surface is a diffuse emitter, then the intensity of the emitted radiation is independent of both wavelength and direction.
When a surface is a diffuse emitter, the intensity of the emitted radiation is independent of direction. This means that the emitted radiation is uniformly distributed across all angles. However, the intensity of emitted radiation may still depend on factors such as wavelength and temperature.
However, it is dependent on temperature as per the Stefan-Boltzmann law, which states that the total amount of energy radiated per unit surface area of a black body is proportional to the fourth power of its absolute temperature.
a surface is a diffuse emitter, then the intensity of the emitted radiation is independent of which factor b. direction
When a surface is a diffuse emitter, the intensity of the emitted radiation is independent of direction. This means that the emitted radiation is uniformly distributed across all angles. However, the intensity of emitted radiation may still depend on factors such as wavelength and temperature.
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If a ball is given a push so that it has an initial velocity of 6 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation s(t) = 6t + 5t2 (a) Find the velocity after 2 seconds. m/s (b) How long does it take for the velocity to reach 40 m/s? (Round your answer to two decimal places.)
The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.
Given the equation s(t) = 6t + 5t²
Let's find the velocity after 2 seconds.
(a) Velocity = (ds)/(dt)
Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t
At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s
Therefore, the velocity after 2 seconds is 26 m/s.
(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at
We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s
Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.
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A copper wire is stretched with a stress of 70 mpa at 20°c. if the length is held constant, to what temperature must the wire be heated to reduce the stress to 35 mpa?
The wire must be heated to a temperature of 20°C + 53.8°C = 73.8°C to reduce the stress to 35 MPa while holding the length constant.
The stress-strain relationship for a material is given by its modulus of elasticity, which is a constant for a given material. In this problem, we can assume that the modulus of elasticity for copper is constant over the temperature range of interest.
The stress-strain relationship for a material can be written as:
σ = Eε
where σ is the stress, E is the modulus of elasticity, and ε is the strain. For a wire under tension, the strain is given by:
ε = ΔL/L
where ΔL is the change in length of the wire and L is the original length.
If the length of the wire is held constant, then ΔL = 0, and the strain is zero. Therefore, the stress in the wire is given by:
σ = 0 = Eε
Now, we can use the fact that the stress is proportional to the temperature to write:
σ = σ₀(1 + αΔT)
where σ₀ is the stress at a reference temperature (in this case, 20°C), α is the coefficient of linear expansion for copper, and ΔT is the change in temperature.
To reduce the stress from 70 MPa to 35 MPa while holding the length constant, we need to find the temperature at which the stress is reduced by a factor of 2. Using the stress-strain relationship and the equation for stress as a function of temperature, we can write:
Eε = σ₀(1 + αΔT)
ε = ΔL/L = 0
σ = σ₀(1 + αΔT/2)
Equating these two expressions for σ, we get:
Eε = σ₀(1 + αΔT/2)
or
E(0) = σ₀(1 + αΔT/2)
Since ε = 0, we can simplify this equation to:
1 + αΔT/2 = σ₀/E
Solving for ΔT, we get:
ΔT = 2(E/α)(σ₀/E - 1)
Plugging in the given values for copper (E = 117 GPa, α = 16.5 × 10^-6 /°C, and σ₀ = 70 MPa), we get:
ΔT = 2(117 × 10^9 Pa)/(16.5 × 10^-6 /°C)(70 × 10^6 Pa/117 × 10^9 Pa - 1) = 53.8°C
Therefore, the wire must be heated to a temperature of 20°C + 53.8°C = 73.8°C to reduce the stress to 35 MPa while holding the length constant.
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Clusters of galaxies clump together to form larger structures known as ________________ which are held together by their mutual gravitational attraction.
Select one:
a. Supergroups
b. Galaxy neighborhoods
c. Galaxy spheres
d. Gravitational webs
e. Superclusters
The correct answer is e. Superclusters.
Clusters of galaxies clump together to form larger structures known as superclusters, which are held together by their mutual gravitational attraction.
Superclusters are large-scale structures in the universe composed of groups of galaxies. They are the largest known structures in the cosmic web and are characterized by their vast size and gravitational interactions.
Galaxies tend to cluster together due to the gravitational attraction between them. These galaxy clusters are interconnected by filaments and sheets of galaxies, creating a complex web-like structure known as the large-scale structure of the universe. Superclusters are the largest coherent structures within this framework.
Superclusters can contain dozens or even hundreds of galaxy clusters, as well as numerous individual galaxies. They can span hundreds of millions of light-years across and contain billions of galaxies. The Milky Way, our own galaxy, belongs to a supercluster called the Laniakea Supercluster.
The formation of superclusters is believed to be driven by the gravitational pull of dark matter, a mysterious substance that constitutes a significant portion of the universe's mass. Over billions of years, the gravitational attraction of dark matter causes galaxies and galaxy clusters to come together, forming superclusters.
Studying superclusters provides valuable insights into the structure and evolution of the universe on the largest scales. Astronomers use various observational techniques, such as galaxy redshift surveys, to map the distribution of galaxies and identify superclusters. By understanding the formation and dynamics of superclusters, scientists can further investigate the fundamental principles that govern the universe's growth and structure.
It's important to note that the knowledge and understanding of superclusters are based on current scientific theories and observations, and further research and discoveries may refine our understanding of these cosmic structures.
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How do labels protect us at the grocery store? Will gove Brainliest to RIGHT answer :)
to guide us on where stuff are or what the stuff are called and used for
After landing on Mars, you drop a marker from the door of your landing module and observe that it takes 2.1 ss to fall to the ground. When you dropped the marker from the module door on Earth, it took 1.3 ss to hit the ground.What is the magnitude of the acceleration due to gravity near the surface of Mars?Express your answer with the appropriate units.
Answer:
Approximately \(3.43\; {\rm m\cdot s^{-2}}\), assuming that air resistance is negligible in both occasions, and that \(g_{\text{earth}} = 9.81\; {\rm m\cdot s^{-2}}\) near the surface of the Earth.
Explanation:
Let \(x\) denote the displacement of the marker. Let \(a\) denote the acceleration of the marker. Let \(t\) denote the time it takes for the marker to reach the ground.
Under the assumptions, acceleration of the marker would be constant, and the SUVAT equations would apply. Rearrange the SUVAT equation \(x = (1/2)\, a\, t^{2}\) to find acceleration \(a\):
\(\begin{aligned}a &= \frac{2\, x}{t^{2}}\end{aligned}\).
Let \(a_{\text{Mars}}\) and \(t_{\text{Mars}}\) denote the acceleration and time taken on Mars. Similarly, let \(a_{\text{Earth}}\) and \(t_{\text{Earth}}\) denote the acceleration and time taken on Earth. It is implied that the Marker travelled the same distance (same displacement, \(x\)) both on Earth and on Mars.
Using the SUVAT equation from above:
\(\begin{aligned}a_{\text{Mars}} &= \frac{2\, x}{{t_{\text{Mars}}}^{2}}\end{aligned}\).
\(\begin{aligned}a_{\text{Earth}} &= \frac{2\, x}{{t_{\text{Earth}}}^{2}}\end{aligned}\).
\(\begin{aligned}\frac{a_{\text{Mars}}}{a_{\text{Earth}}} &= \frac{\displaystyle \frac{2\, x}{{{t_{\text{Mars}}}^{2}}}}{\displaystyle \frac{2\, x}{{{t_{\text{Earth}}}^{2}}}} \end{aligned}\).
\(\begin{aligned}\frac{a_{\text{Mars}}}{a_{\text{Earth}}} &= \left(\frac{{t_{\text{Earth}}}}{{t_{\text{Mars}}}}\right)^{2}\end{aligned}\).
\(\begin{aligned}a_{\text{Mars}} &= \left(\frac{{t_{\text{Earth}}}}{{t_{\text{Mars}}}}\right)^{2}\, a_{\text{Earth}} \\ &= \left(\frac{1.3\; {\rm s}}{2.2\; {\rm s}}\right)^{2}\, (9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 3.43\; {\rm m\cdot s^{-2}}\end{aligned}\).
Which of the following procedures demonstrates repetition?
A.
Marco places a toy car at the top of a ramp. He releases the car and measures how long it takes for the car to reach the bottom of the ramp. Then, he returns the car to the top of the ramp, releases the car again, and makes an additional measurement.
B.
Kasey performs a scientific investigation on the effects of using soda instead of water to hydrate plants. Caleb uses Kasey's procedure and performs the same experiment during the following month.
C.
Jeremiah measures the mass of five different strips of metal. He places the strips in five different test tubes filled with hydrochloric acid. He observes if heat and bubbles are produced after the metal strips and acid are combined.
D.
Cynthia monitors the growth rate of her pet turtle. She measures the length and weight of her turtle every Sunday over the course of six months.
Answer: A. Marco places a toy car at the top of a ramp. He releases the car and measures how long it takes for the car to reach the bottom of the ramp. Then, he returns the car to the top of the ramp, releases the car again, and makes an additional measurement
Jonathan throws a ball that moves at an average speed of 45 meters per second and travels for a total of 7 seconds. What distance did the ball travel?
Answer:
315 meters
Explanation:
You just multiply 45 by 7
An electromagnetic standing wave in air of frequency 750 MHz is set up between two conducting planes 80.0 cm apart.
The positions the point charge will be placed at rest and still stay at rest standing 20 cm, 40 cm, and 60 cm between the ends.
What is Electromagnetic wave?Electromagnetic waves exist created when an electric field comes in contact with a magnetic field. They exist hence understood as 'electromagnetic' waves. The electric field and magnetic field of an electromagnetic wave exist perpendicular (at right angles) to each other.
Radio waves, microwaves, visible light, and x-rays exist all examples of electromagnetic waves that vary from each other in wavelength. (a) Longer wavelength; (b) shorter wavelength. Electromagnetic waves exist created by the motion of electrically charged particles.
Given;
Distance between the conducting planes, d = 80 cm
Frequency of the electromagnetic wave, f = 750 MHz
Speed of light, c = 3 x 10⁸ m/s²
Define the wavelength
λ = C/f
Where;
λ exists the wavelength
C exists the speed of light
f exists the frequency
λ = C/f
λ = (3 x 10⁸) / (750 x 10⁶)
λ = 0.4 m = 40 cm
One complete cycle = one wavelength = 40 cm
Half of the wavelength ( λ / 2) = 20 cm
One wavelength + half wavelength (3λ / 2) = 60 cm
The positions of the wave at zero amplitude (between 0 and 80 cm) = 20 cm, 40 cm, 60 cm
Thus, the positions the point charge will be placed at rest and still stay at rest standing 20 cm, 40 cm, and 60 cm between the ends.
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A conducting bar moves along a circuit with a
constant velocity. A constant magnetic field of
1.23 T is perpendicular to the bar and circuit.
The bar covers 2.00 m2 of area in
1.00 second. What is the EMF
induced in the circuit?
[?] V
Explanation:
\(E = \frac{BA}{t} \sin( \theta) \\ = \frac{1.23 \times 2}{1} \\ = 2.46 \: V\)
. While at the dentist’s office, Marion noticed the x-ray images of her teeth looked very
different than a photograph image of her teeth. She recalled x-ray images are
produced from x-rays and photograph images are produced from visible light waves.
What can be inferred about the energy difference between x-rays and visible light
waves?
A. X-rays have higher energy than visible light waves.
B. Visible light waves have higher energy than x-rays.
C. X-rays and visible light waves have the same energy.
D. Visible light waves and x-rays can have varying amounts of energy
Answer:
B
Explanation:
which of the following statements about einstein's general theory of relativity (gr) is false?
One false statement about Einstein's General Theory of Relativity (GR) is that it explains the behavior of objects on a quantum level.
While GR provides a mathematical framework for understanding the interactions of gravity on a large scale, it does not account for the behavior of subatomic particles. Another false statement is that GR is incompatible with the theory of quantum mechanics. While the two theories have not yet been fully reconciled, there have been efforts to unify them in theories such as loop quantum gravity and string theory. Finally, it is false to say that GR applies only to objects in space. The theory applies to any object with mass, regardless of its location.
Among the following statements about Einstein's General Theory of Relativity (GR), the false one is that it predicts that time passes at the same rate everywhere in the universe. In reality, GR explains that gravity influences the passage of time, causing it to slow down near massive objects. This phenomenon is known as time dilation. The theory also encompasses the curvature of spacetime caused by mass, gravitational waves, and the expansion of the universe. It's essential to distinguish the false statement to better understand the true implications of GR on our perception of time and gravity.
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When a +0.00235 C charge
moves from point A to point B, its
electric potential energy increases
by 0.418 J. What is the potential
difference between A and B?
Include the correct sign, + or -.
(Unit = V)
Answer:
177.87
Explanation:
acellus
The potential difference between the points A and B is 177.9 V.
What is meant by potential difference ?Potential difference between any two points is the amount of work required to move a unit positive charge along any path from point A to point B without accelerating is referred to as the electric field.
Here,
The charge on the particle, q = +0.00235 C
The change in electric potential energy, ΔU = 0.418 J
The potential difference can be defined as the electric potential energy per unit charge.
Therefore, the potential difference between A and B,
V = ΔU/q
V = 0.418/0.00235
V = 177.9 Volt
Hence,
The potential difference between the points A and B is 177.9 V.
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You have been using an analogy between a row of sticky notes and the sandpaper surface to develop your ideas about how a frictional force is produced when a block slides across sandpaper. However, you have seen that even when the block slides across an apparently smooth tabletop, it still slows down. Consider how our analogy might be extended to explain how a frictional force is produced when the block slides across an apparently smooth surface. What do you think you would see if you looked at a smooth tabletop with a powerful magnifier? A A thin layer of moisture on the surface that makes it somewhat 'sticky' B. Very small bumps and grooves in the surface C. Nothing. It would still look perfectly smooth
The following will happen if we looked at a smooth tabletop with a powerful magnifier:
A thin layer of moisture on the surface makes it somewhat 'sticky'
Hence, option (a) is the correct choice.
If you looked at a smooth tabletop with a powerful magnifier, you would likely see very small bumps and grooves on the surface.
These small imperfections in the surface can cause a frictional force to be produced when a block slides across it.
The frictional force is due to the interaction between the small bumps and grooves in the surface and the surface of the block.
The bumps and grooves can create small points of contact between the two surfaces, which resist the motion of the block and produce a frictional force.
This is similar to the way that the sticky notes in the analogy produce a frictional force by sticking to each other.
The small imperfections in the surface can be thought of as the 'stickiness' in the analogy.
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An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?
The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,
F = kx
Therefore,
k = F/x
We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,
K = 50.174/0.25 N/m
K = 200.696 N/m
Therefore, The Spring Constant is 200.696 N/m
On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:
h = \(1/2 kx^{2}\)
We know that k=200.696 N/m and x=0.25 m. Therefore the height is:
h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)
h = 2.5087 m
Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
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(b) What is the probability that the electron can be detected in the middle one third of well, region (b)
In order to determine the probability that an electron can be detected in the middle one-third of a well region, we need to take into account the wave function and the boundary conditions.The wave function represents the probability density of finding the electron in a particular location within the well. The boundary conditions are determined by the geometry of the well, which can be rectangular, triangular, or other shapes.
The Schrodinger equation is used to calculate the wave function and determine the probability density of finding the electron in a particular location. The wave function is a complex function that describes the position and momentum of the electron. It is also used to calculate the energy of the electron in the well.The probability of finding the electron in the middle one-third of the well can be determined by integrating the probability density over the middle one-third of the well region. This will give us the probability of finding the electron in that region. The integral can be evaluated using numerical methods or analytical methods, depending on the complexity of the wave function and the boundary conditions.In general, the probability of finding the electron in the middle one-third of the well will depend on the shape of the well, the energy of the electron, and the boundary conditions. For example, if the well is rectangular and the electron is in the ground state, then the probability of finding the electron in the middle one-third of the well will be high. However, if the well is triangular and the electron is in an excited state, then the probability of finding the electron in the middle one-third of the well will be lower.For such more question on probability
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Use a ballistic cart to shoot a small ball into the air. Push the cart along a track, allowing it
to release the ball. What explains why the cart always catches the ball, and the ball doesn't
fall behind the moving cart?
Answer:
Explained below.
Explanation:
The ball doesn't fall behind the moving cart because the horizontal motion of the ballistic cart is not affected by the forces that act in the vertical direction. Therefore, when the cart is pushed, it means that the ball will shoot up and then it will land right back in the barrel.
help please .....
what is the effect of gravity on a falling object? write the conclusion obtained from the coin and feather experiment ?
Answer:
Pick something up with your hand and drop it. When you release it from your hand, its speed is zero. On the way down its speed increases. The longer it falls the faster it travels. Sounds like acceleration to me.
But acceleration is more than just increasing speed. Pick up this same object and toss it vertically into the air. On the way up its speed will decrease until it stops and reverses direction. Decreasing speed is also considered acceleration.
But acceleration is more than just changing speed. Pick up your battered object and launch it one last time. This time throw it horizontally and notice how its horizontal velocity gradually becomes more and more vertical. Since acceleration is the rate of change of velocity with time and velocity is a vector quantity, this change in direction is also considered acceleration.
In each of these examples the acceleration was the result of gravity. Your object was accelerating because gravity was pulling it down. Even the object tossed straight up is falling — and it begins falling the minute it leaves your hand. If it wasn't, it would have continued moving away from you in a straight line. This is the acceleration due to gravity.
In this initial experiment the bowling ball drops straight to the ground whereas the feathers float, owing to air resistance.
He alludes to the earlier experiment by Galileo that tested the same hypothesis.
"Galileo’s experiment was simple," he explains. "He took a heavy object, and a light one, and dropped them at the same time to see which fell fastest."
Although Galileo’s experiment proved two similarly shaped objects would fall at the same speed despite being different weights, he didn’t have access to a vacuum chamber in the 17th Century to conduct Professor Cox's more extravagant experiment.
Professor Cox also used the bowling ball and feather to prove a hypothesis put forward by Albert Einstein.
His Special Theory of Relativity argued that items would not be falling but standing still due to lack of force acting on them.
"Isaac Newton would say that the ball and the feather fall because there’s a force pulling them down: gravity,’ Professor Cox said.
"But Einstein imagined the scene very differently.
"The “happiest thought of his life” [as Einstein called it] was this; the reason the bowling ball and the feather fall together is because they’re not falling.
"They’re standing still. There is no force acting on them at all.
"He reasoned that if you couldn’t see the background, there’d be no way of knowing that the ball and the feathers were being accelerated towards the Earth.
"So he concluded they weren’t."
The tweaking of Newton’s earlier theory enabled Einstein to more accurately define his own theory, which regards the relationship between space and time.
hope it helps you
A tennis ball moves 18 meters northward, then 22 meters
southward, then 14 meters northward, and finally 28 meters
southward.
What is the magnitude and direction of the displacement
Answer:
Magnitude = 18 m
Direction = southward
Explanation:
Given that a tennis ball moves 18 meters northward, then 22 meterssouthward, then 14 meters northward, and finally 28 meters
southward.
To calculate the displacement, let the
Northward = positive direction
Southward = negative direction
Displacement = 18 - 22 + 14 - 28
Displacement = 32 - 50
Displacement = - 18
Since the answer is negative,
The magnitude will be 18 m and direction of the displacement is southward
what muscle are controlled by the autonomic muscle system and are involuntary
What is the difference between average speed and constant speed?
Answer:
Explanation:
constant speed is where the speed is the same throughout and instantaneous speed is speed given at any moment and average speed is a total distance traveled divided by the amount of time it took to travel it.
Answer:
Average speed is a measurement of velocity over a period of time.
Constant speed refers to your velocity at any point in time or period
If the rock was going 90m/s when it hit the ground. How many seconds would it have been falling for?
Answer:
it will hit 80
Explanation:
because evey sec
is 10