The bandwidth of the light source in the unit of GHz is 193.54 GHz.
The spectrum width of a light source is 0.1nm and the central wavelength is 1550nm. To calculate the bandwidth of the light source in the unit of GHz, we can use the formula:
Bandwidth (GHz) = (Speed of light)/(Central wavelength (nm) × 10⁹)
From the given question, the central wavelength of light source = 1550 nm
The spectrum width of light source = 0.1 nm
Bandwidth (GHz) = ?
We need to convert central wavelength from nm to meters before we can calculate the bandwidth.
Because, speed of light is given in m/s.
Speed of light = 3 × 10⁸ m/s
So, 1550 nm = 1.55 × 10⁻⁶ m
Bandwidth (GHz) = (Speed of light)/(Central wavelength (nm) × 10⁹)
= (3 × 10⁸ m/s) / (1.55 × 10⁻⁶ m × 10⁹)
= 193.54 GHz
Therefore, the bandwidth of the light source is 193.54 GHz.
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At the end of a quiet inspiration, an additional volume of air can be inhaled. What is this additional amount of air called
Inspiratory reserve volume is the additional amount of air that can be inhaled at the end of quiet inspiration.
Inhalation : The act of drawing air into the lungs during inspiration, also known as inhalation.
By establishing a pressure differential between the lungs and the atmosphere, it is accomplished.
The diaphragm contracts toward the abdominal cavity as air enters the lungs, creating more room in the thoracic cavity for the air to fit.
Inspiratory reserve volume is the additional volume of air that can be maximally inspired after finishing a typical, quiet inspiration.
Or the volume of air that can be inhaled following a regular breath is known as the inspiratory reserve volume.
It is denoted by IRV.
In men average IRV is 3.3 L whereas in women it is about 1.9 L
Hence, Inspiratory reserve volume is the additional amount of air that can be inhaled at the end of quiet inspiration.
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What will happen if a renewable resource is used up faster than it can be
replenished or regenerated? *
Answer:
there will be no more if a resource is used up you have to find a new aource
When light hits a surface it usually bounces off at a larger angle. True or false? Justify
Answer:That only applies to highly polished surfaces, eg mirrors.
If you take a high quality laser (ie with low divergence) and aim it at a wall, you can see the spot where the laser beam reaches the wall from anywhere with a direct line-of-sight to the spot where the laser beam reaches the wall. This due to micro imperfections on the surface of the wall. At a microscopic level, the wall surface is very rough and pointing in all directions.
As to why, a beam of light bounces of a highly polished surface, I can only surmise that it is essentially due to kinematics, ie the only force opposing the light beam is normal to the surface, hence there no forces along the reflective surface. Since there are no forces along the reflective surface, the speed component of light along the reflective surface remains unchanged. However, on the plane perpendicular to the reflective surface the, the light photons bounce off at the same speed at which the hit the reflective surface because the mass of the reflective surface is much much much larger than the mass of the photons, which means that the reflective surface won’t move at all. Since conservation of momentum requires that momentum after the collision be the same as the momentum before the collision then the only way for that to happen is if the velocity of the photon perpendicular to the reflective surface is of exactly the same magnitude but in the opposite direction. Vector resolution of the speed component of the reflected beam means that the angle of reflection must be the same as the angle of incidence.
Explanation:
!! i will mark as brainliest so pls answer quick !!
The student becomes negatively charged because of the friction between her socks and the carpet.
Explain why the friction causes the student to become charged
Answer:
A student becomes negatively charged because of the friction between his socks and the carpet. ... The electrons get rubbed and move towards the carpet so the carpets electrons move away and the student becomes negatively charged.
A pendulum bob swings along its characteristic arc as shown. Rank the gravitational potential energy of the pendulum bob at the three marked locations
Answer:
Gravitational potential energy is the maximum at point C and lowest at point A
Explanation:
The image for the question is provide in the attached file
The energy of pendulum is governed by mechanical energy. Mechanical energy is the sum of potential energy and kinetic energy
Potential energy increases with increasing height. Thus, when the pendulum bob is at maximum height, then its potential energy is also the highest.
Thus, At point C, the gravitational potential energy is the highest
At point A, the gravitational potential energy is substantial but lower than that of gravitational potential energy at point C
AT point A, gravitational energy is the lowest
As a city planner, you receive complaints from local residents about the safety of nearby roads and streets. One complaint concerns a stop sign at the corner of Pine Street and 1st Street. Residents complain that the speed limit in the area ( 8989 km/h) is too high to allow vehicles to stop in time. Under normal conditions this is not a problem, but when fog rolls in visibility can reduce to only 4747 meters. Because fog is a common occurrence in this region, you decide to investigate. The state highway department states that the effective coefficient of friction between a rolling wheel and asphalt ranges between 0. 5360. 536 and 0. 5990. 599 , whereas the effective coefficient of friction between a skidding (locked) wheel and asphalt ranges between 0. 3500. 350 and 0. 4800. 480. Vehicles of all types travel on the road, from small cars with a mass of 563563 kg to large trucks with a mass of 39513951 kg. Considering that some drivers will brake properly when slowing down and others will skid to stop, calculate the minimum and maximum braking distance needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection
The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:
- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m
- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m
To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.
The equation for the braking distance of a vehicle is given by:
d = (v^2) / (2 * μ * g)
where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.
Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.
For small cars with a mass of 563 kg:
- Minimum braking distance:
v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s
μ_min = 0.536
d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m
Maximum braking distance:
μ_max = 0.599
\(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)
For large trucks with a mass of 3951395 kg:
- Minimum braking distance:
v = 8989 km/h = 2496.944 m/s (same as for small cars)
μ_min = 0.350
\(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)
Maximum braking distance:
μ_max = 0.480
\(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)
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A submarine is 58.8 m from a whale. The sub sends out a sonar ping to locate the whale. The speed of sound underwater is 1520 m/s. How much time does it take for the sound wave to travel to the whale and back? (Unit = s)
Answer:
0.08
Explanation:
this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.
The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this
t = 2d/v
t = 2*58.8/1520
t = 117.6/1520
t = 0.077368 s
t ≈ 0.08 s (less then 1 s)
Answer:
0.0774s
Explanation:
The formula to find the time of an echo is time = (2)(distance) / (velocity)
So plug in the numbers to the formula
(2)(58.8) / (1520)
= 0.0774s
what will be the acceleration of vehicle if it started to move from rest and its velocity reached 12m/s after 4 second
Answer:
First of all, what is acceleration? — Acceleration is the rate of change of velocity per unit of time.
Now, we know that velocity is a vector quantity i.e we need both magnitude and direction to define it and so is acceleration. We can now say that in acceleration, the direction of motion is very important or to define acceleration we need both the magnitude of motion (here it is the speed) and its direction.
Now coming to your question. There are two possible answers to this question.
more
,Case 2 — When the body is not moving in a straight line or is constantly changing its direction. In this cas the speed still is constant but the direction is constantly changing, for example in the case of a circular motion the direction of motion constantly changes (the direction of a moving body in a circular path at any point is the direction of the tangent of the circle at that point). Hence the velocity changes as the body move along the circular or curved path.
Now, as I earlier mentioned to define acceleration we need to know it's magnitude and it's direction, and acceleration is the rate of change of velocity per unit of time — the speed remaining constant the direction constantly changing, and the velocity changes at different time intervals or rate of change of velocity is ≠ 0 unlike in case 1. Since there is the of and a change in velocity (speed constant but the direction is changing) there is some acceleration.
To sum everything up — in the case of linear motion i.e motion in a straight line when the speed is constant and direction is not changing, velocity will be zero and hence acceleration would be zero. In case of a non-linear motion i.e motion not in a straight line, in a circle or any path where the speed is constant but the direction is constantly changing, velocity will not be zero and hence the acceleration would not be equal to zero. Either it would be greater or less than zero.
A point charge q1=5. 00μC is held fixed in space. From a horizontal distance of 8. 00 cm, a small sphere with mass 4. 00×10−3kg and charge q2=+2. 00μC is fired toward the fixed charge with an initial speed of 35. 0 m/s. Gravity can be neglected.
What is the acceleration of the sphere at the instant when its speed is 27. 0 m/s
According to the given statement , the acceleration of the sphere at the instant when its speed is 27.0 m/s.
We can use the principles of electrostatics and kinematics. a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
1. Determine the electric force between the two charges:
- The electric force between two charges can be calculated using Coulomb's Law:
F = k * |q1 * q2| / r².
- In this case, q1 = 5.00 μC and q2 = +2.00 μC. The distance between them, r, is the horizontal distance of 8.00 cm (which is 0.08 m).
- The constant k is 9.00 x 10⁹ N * m^2 / C².
- Plugging in the values, we get F = (9.00 x 10^9 N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)².
2. Calculate the net force acting on the sphere:
- At any instant, the net force acting on the sphere is the sum of the electric force and the force due to gravity.
- However, in this case, gravity can be neglected, as stated in the question.
- Therefore, the net force acting on the sphere is equal to the electric force between the two charges.
3. Calculate the mass of the sphere:
- The mass of the sphere is given as 4.00 x 10⁻³ kg.
4. Apply Newton's second law:
- Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = m * a.
- In this case, the net force acting on the sphere is the electric force between the charges.
- Plugging in the values, we get (9.00 x 10⁹ N * m^2 / C²) * |5.00 μC * 2.00 μC| / (0.08 m)² = (4.00 x 10⁻³ kg) * a.
5. Solve for the acceleration:
- Rearranging the equation, we have a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
- Evaluating the expression, we find the value of acceleration.
By following these steps, you can find the acceleration of the sphere at the instant when its speed is 27.0 m/s.
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which or the following describes the shape of the Mid-Atlantic ridge?
Answer: The ridge formed by the same process that pushed the continents apart.
How much work is done using a 500-watt microwave oven for 5 minutes?
The amount of work that is done using a 500-watt microwave oven for 5 minutes is 150,000 J.
How to calculate work done?Work is a measure of energy expended in moving an object. It is generally said that "no work is done if the object does not move".
Power is a measure of the amount of work that can be done in a given amount of time. It can be represented by the following equation:
Power (J/s) = Work done (J) / time (s)
This means that work done = power × time
According to this question, a 500-watt microwave oven is used for 5 minutes. The amount of work done can be calculated as follows:
Work done = 500W × 300s
Work done = 150,000 J
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If your car is going 19 m/s at the beginning of the block (250 meters long), and your acceleration is 3.9
m/s?, how fast are you going at the end of the block?
Answer:
48 m/s
Explanation:
Given:
Δx = 250 m
v₀ = 19 m/s
a = 3.9 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (19 m/s)² + 2 (3.9 m/s²) (250 m)
v ≈ 48 m/s
Hurricanes are large storms that form over warm waters out in the ocean. hurricanes are associated with low-pressure regions in the atmosphere. how does the low pressure associated with a hurricane help them to grow big and powerful?
A hurricane is a big rotating storm system that forms over warm ocean waters and often moves toward the western coast of the United States.
A tropical storm is a hurricane in the northern Pacific Ocean or the Atlantic Ocean.
A hurricane is a big rotating storm system that forms over warm ocean waters and often moves toward the western coast of the United States. Hurricanes are either classified as tropical storms or hurricanes, depending on the greatest sustained wind speeds. Tropical storms have winds between 39 and 73 mph, whereas hurricanes have winds of 74 mph or greater.
When a hurricane makes landfall, storm surges, powerful winds, and copious amounts of rain can cause flooding. Storm surge refers to the rise in sea level that occurs as a cyclone approaches shore.
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In order for an object to have a perfectly circular orbit, what one thing must occur?
An object must have the exact mass to orbit in a circle.
An object must have the exact speed to achieve the circular orbit.
An object must have enough speed to create escape velocity.
In order for an object to have a perfectly circular orbit, an object must have the exact speed to achieve the circular orbit.
What is a circular orbit?A circular orbit is a circular path which an object continuously follow in the course of its movement.
The earth and planets have a circular orbit around the sun.
The circular orbit is maintained by a balance between centripetal and centrifugal forces.
Therefore, in order for an object to have a perfectly circular orbit, an object must have the exact speed to achieve the circular orbit.
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PLEASE EXPLAIN IN TWO PARAGRAPHS (A PARAGRAPH IS 4-5 SENTENCES) SOME HEALTHFUL TIPS THAT CAN HELP PREVENT YOU FROM GETTING PHYSICAL FITNESS INJURIES.
Answer:
A workout injury can happen to anyone, no matter your experience or fitness level. People hurt themselves in all kinds of ways when they work out. Even walking can cause an injury. But you can significantly cut your risk of getting hurt by following certain workout precautions. There are simple steps that can help keep you injury-free during your workout.
Every workout should begin with a warm-up and end with a cool-down period. A warm-up helps your body get ready for exercise. It gradually increases your heart rate and loosens your muscles and joints. Cool-down after you work out so, it brings your heart rate back to normal. Walking for 5 to 10 minutes after you work out is one way to cool down. Do dynamic stretching before and after you work out. This will help increase flexibility. Don't push yourself too hard. As your fitness abilities increase and you will be able to challenge yourself more.
Hope this helps
Maintaining physical fitness is very important in today's world. Each and everyone should be involved in physical fitness.nowaday people are so busy with their work that they have forgotten health is wealth.
Even if we get engaged in physical fitness activity we can some time get insuries . some of tips that can help prevent from getting physical fitness injury, warm up exercises should be done before exercise to avoid muscle strength.safety precautions should be taken if you are dealing with heavy objects .
hence we should maintain physical fitness with getting rid of injury that may occur
mark me
How long does an object accelerating at minus,−6.7m/s 2 take to change velocity from ,26m/s to,0m/s?
vf² = vi² + 2.a.d
0 = 26 + 2.(-6.7).d
13.4d = 26
d = 1.94 m
Speed limit signs on expressway exit ramps are generally colored __________ .
Answer:
White with black lettering
Explanation:
Generally they are yellow with black lettering but that's for highways at least the state I live in.
Hope this helps!
does anybody know?? Please help
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?
Answer:-Given,=> Force applied by Ryan = 10N
=> Distance covered by the book after applying force = 30 cm
And,30 cm = 0.3 m (distance)
So,=> Work done = Force × Distance
=> 10 × 0.3
=> 3 Joules
\( \small \boxed{work \: done \: by \: Ryan \: = 3 \: Joules}\)
A container of gas is held at a constant volume. Which will most likely happen to the temperature if the pressure of the gas increases?
The temperature will increase at the same rate as the pressure increases.
The temperature will decrease at the same rate as the pressure increases.
The temperature will increase at half the same rate as the increase in pressure.
The temperature will decrease at half the same rate as the increase in pressure.
Answer:
With more particles there will be more collisions and so a greater pressure. The number of particles is proportional to pressure, if the volume of the container and the temperature remain constant. ... This happens when the temperature is increased.
Explanation:
Assuming the gas to be an ideal gas, the temperature will increase at the same rate as the pressure increases.
Ideal gas:Let us assume that the gas in the container is an ideal gas. Then from the ideal gas equation, we get that:
PV = nRT
where P is the pressure of the gas
V is the volume
T is the temperature
n is the number of moles of the gas
R is the universal gas constant
Now, it is given that V is constant, R is already a constant, and n will also be constant, since the number of moles of gas in the container is not changing, so:
P = nRT/V
P = constant × T
P/T = constant
This means that the temperature will increase at the same rate as the pressure increases.
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You observe a quasar at a redshi , and determine that the observed flux of light from the quasar varies on a timescale days. ( is time measured by the observer.) if the observed variation in flux is due to a variation in the intrinsic luminosity of the quasar, what was the variation timescale
If the observed variation in flux is due to a variation in the intrinsic luminosity of the quasar, what was the variation timescale at the time the light was emitted will be found and Rmax is equals to 1.3*10^15 cm.
In particle physics experiments the energy available for the production of new effects is the most important parameter. The required large centre of mass energy can only be provided with colliding beams where little or no energy is lost in the motion of the centre of mass system (cms).
Besides the energy the number of useful interactions (events), is important. This is especially true when rare events with a small production cross section σp are studied.
The quantity that measures the ability of a particle accelerator to produce the required number of interactions is called the luminosity and is the proportionality factor between the number of events per second dR/dt and the cross section σp.
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A vehicle is traveling at a velocity of 30 meters per second. Exactly 5 second later, its velocity changed by a factor of 0.6. What was the vehicle's average acceleration over that time period?
Answer:
30MPH
Explanation:
30/5 = 6 x 5 = 30 mph
a spherical, convex mirror has a radius of curvature of 0.123 m. what is the focal length of the mirror? (in m; answer sign and magnitude)?
To find the spherical convex mirror radius, learn the focal length and magnitude.
What is focal length?
The focal length of a thin lens in air is measured from the lens's center to its primary foci, also known as focal points. The focal length of a converging lens, such as a convex lens, is positive and determines how far a collimated light beam must travel to focus on a single point.
What is magnitude?
Magnitude typically refers to size or distance. By comparing the size and motion speed of the object, we can relate magnitude to movement. The object's or quantity's size determines its magnitude.
R=0.123m
Focal length E= R/2
E= - 0.0615m.
Therefore, the focal length is 0.0615m.
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flix the cat ambles along at a leisurely cat-pace of 1 m/s when he suddenly spies an interesting mouse. flix then accelerates at 2 m/s2 until he reaches his top speed of 4 m/s. a) determine the time this acceleration takes. b) determine the distance flix moved while he was accelerating.
(A) The Flix takes 1.5 seconds to reach his top speed of 4 m/s. (B) Flix moved a distance of 3.75 meters while he was accelerating.
To solve this problem, we can use the equations of motion to calculate the time and distance traveled by Flix the cat.
To determine the time it takes for Flix to accelerate, we can use the equation;
v = u + at
Where;
v = final velocity (4 m/s)
u = initial velocity (1 m/s)
a = acceleration (2 m/s²)
t = time
Rearranging the equation, we have;
t = (v - u) / a
Substituting the given values;
t = (4 m/s - 1 m/s) / 2 m/s²
t = 3 m/s / 2 m/s²
t = 1.5 s
Therefore, Flix takes 1.5 seconds to reach his top speed of 4 m/s.
To determine the distance traveled while accelerating, we can use the equation;
s = ut + (1/2)at²
Where;
s = distance traveled
u = initial velocity (1 m/s)
t = time (1.5 s)
a = acceleration (2 m/s²)
Substituting the given values:
s = (1 m/s)(1.5 s) + (1/2)(2 m/s²)(1.5 s)²
s = 1.5 m + (1/2)(2 m/s²)(2.25 s²)
s = 1.5 m + (2 m/s²)(1.125 s²)
s = 1.5 m + 2.25 m
s = 3.75 m
Therefore, Flix moved a distance of 3.75 meters while he was accelerating.
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Pls help me with a physics question I am struggling
Answer:
It will condese to 47
Explanation:
As per as the table chart , Substance G melting point at 47 and boiling point at 120 so AS per as the chart
What is the probability that a randomly selected vehicle's speed is between 50 and 65 m/h? (Round your answer to four decimal places.)
To calculate the probability that a randomly selected vehicle's speed is between 50 and 65 m/h,
Step 1: Obtain the data
Gather the total number of vehicles and the number of vehicles with speeds between 50 and 65 m/h. Let's call the total number of vehicles 'N' and the number of vehicles with speeds between 50 and 65 m/h 'n'.
Step 2: Calculate the probability
Divide the number of vehicles with speeds between 50 and 65 m/h (n) by the total number of vehicles (N).
Probability = n/N
Step 3: Round to four decimal places
Round the resulting probability to four decimal places.
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As a student studying in South Korea, what changes you think must be made in the education system to make it better?
Explanation:
studying hard is the only thing that could make the educational system better
I think the student when he studying first time then first he want to speak Korean and study hard for that but if he try then only he can be better
Explanation:
and he or she should have interest to study if he or she have interest then only their education will be better
and if he / she didn't have interest on study then we can't do anything........
electrons are tiny particles with very small negative charges when two electrons are place near each other the electric force pushes them apart what does this tell you about the mass of an electron
Answer:
Explanation:
like charges repel each other if one group of electrons has more mass it will push the other smaller mass of electrons away
ve takes 3.50 s to complete 8.00 complete oscillations, what is the period of the wave? A. 0.438 s B. 4.50 s C. 2.29 s
0.438 s is the period of the wave.
So, the correct answer is A.
To determine the period of the wave, we need to divide the total time taken (3.50 s) by the number of complete oscillations (8.00).
The period (T) is the time required for one complete oscillation.
T = total time / number of oscillations
T = 3.50 s / 8.00
T = 0.4375 s
Rounded to three decimal places, the period of the wave is 0.438 s, which corresponds to option A.
Your question is incomplete but most probably your full question was:
If a wave takes 3.50 s to complete 8.00 complete oscillations, what is the period of the wave?
a. 0.438 s
b. 4.50 s
c 2.29 s
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imagine rigel, a star, rises at 6pm today. what time will it rise tomorrow and a month from now?
Assuming a constant rate of Earth's rotation and neglecting any axial tilt effects, Rigel, a star, would rise approximately 4 minutes earlier each day. Therefore, if Rigel rises at 6 PM today, it would rise at around 5:56 PM tomorrow. In one month, comprising roughly 30 days, Rigel would rise approximately 2 hours earlier, at around 4 PM. These calculations are based on the assumption that the observer's location on Earth remains constant, and no other factors, such as atmospheric conditions or the star's own motion, significantly affect the timing of Rigel's rise.
The Earth rotates approximately once every 24 hours, causing the stars to appear to rise and set each day. This rotation rate is relatively constant over short timescales. Therefore, if a star rises at a specific time on a given day, it will rise approximately 4 minutes earlier the following day, as 24 hours divided by 60 minutes gives an average of 4 minutes per minute of Earth rotation. Multiplying this by the number of days in a month (30) results in approximately 2 hours earlier for the star's rise time.
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