write a java class which models a household appliance (e.g. oven, microwave, refrigerator, washing machine, etc.). your class should have at least two meaningful attributes, one method to do some action on or for the object, and one method to display the values of the attributes to the console. in your main method show an instance of the object and call your methods.
Answers
CODE :
public class HouseholdAppliance {
// Attributes
private String name;
private int voltage;
// Constructor
public HouseholdAppliance(String name, int voltage){
this.name = name;
this.voltage = voltage;
}
// Getters
public String getName(){
return this.name;
}
public int getVoltage(){
return this.voltage;
}
// Method to do an action
public void turnOn(){
System.out.println("The " + this.name + " is now turned on!");
}
// Method to display values
public void displayValues(){
System.out.println("Name: " + this.name + "\nVoltage: " + this.voltage);
}
// Main method
public static void main(String[] args){
HouseholdAppliance washingMachine = new HouseholdAppliance("Washing Machine", 220);
washingMachine.turnOn();
washingMachine.displayValues();
}
}
These are the two meaning attributes one method in the code .
What is code ?
For the purposes of communication and information processing, a code is a set of principles that technology is getting as a letter, word, sound, picture, or gesture—into another form, often shorter or secret, for storage on a storage device or for transmission over a channel of communication. An early example is the development of language, which allowed people to express verbally what they were thinking, seeing, hearing, or feeling to others. However, speaking restricts the audience to those present at the time the speech is delivered and limits that range of communication towards the distance a voice may travel. The ability to communicate across space and time was greatly expanded by the discovery of printing, which converted spoken language into pictorial symbols.
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Related Questions
Which of the following tools would best give a graphical representation of a sequence of activities and decisions?
A.Control Chart
B.Flowchart
C.Run Chart
D.Histogram
Answers
B. Flowchart. If the goal is to represent a sequence of activities and decisions in a graphical form, a flowchart is the most suitable tool to use. It visually represents the flow of steps, actions, and decision points, allowing for easy understanding and analysis of the process.
A flowchart is the best tool for giving a graphical representation of a sequence of activities and decisions. A flowchart is a diagrammatic representation of a process or system that uses various symbols and arrows to illustrate the flow of activities, decisions, and information. It visually presents the steps, actions, and decision points in a sequential manner, allowing for easy understanding and analysis of the process.
Flowcharts are commonly used in various fields such as software development, project management, business process analysis, and problem-solving. They provide a clear and concise visualization of the sequence of activities and decisions involved in a process, highlighting the different paths and outcomes based on specific conditions or choices.
Control charts, run charts, and histograms, on the other hand, are statistical tools used for analyzing data and monitoring process performance. They are not specifically designed to represent a sequence of activities and decisions but rather to display data distributions, trends, and variations.
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Write a program that can take a tree as input and travers it in 3 different format (pre-order, in-order and post-order). Write a report, you can follow the attached file. You can modify the report as you want.
Answers
Answer:
Let us see different corner cases.
Complexity function T(n) — for all problem where tree traversal is involved — can be defined as:
T(n) = T(k) + T(n – k – 1) + c
Where k is the number of nodes on one side of root and n-k-1 on the other side.
Let’s do an analysis of boundary conditions
Case 1: Skewed tree (One of the subtrees is empty and other subtree is non-empty )
k is 0 in this case.
T(n) = T(0) + T(n-1) + c
T(n) = 2T(0) + T(n-2) + 2c
T(n) = 3T(0) + T(n-3) + 3c
T(n) = 4T(0) + T(n-4) + 4c
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0. 5 kilograms. The company wishes to test the hypothesis H0:μ=12 against H1:μ<12 using a random sample of n=4 specimens. Calculate the P-value if the observed statistic is x⎯⎯=11. 25. Suppose that the distribution of the sample mean is approximately normal. Round your final answer to five decimal places (e. G. 98. 76543). Enter your answer in accordance to the question statement
Answers
Answer:
The p-value of the hypothsis 0.00135
Explanation:
How to create Profit Centric Design Professionals ?
Answers
Profit-Centric Design Professionals can be developed by training and educating people on design principles, business strategies, and user research in order to create profitable solutions.
What does profit-centric mean?A profit center is a branch or division of a company that directly contributes to the bottom-line profitability of the corporation. A profit center is treated as a separate business, with revenues recorded separately.
Developing Profit Centric Design Professionals entails design, business, and user research training in order to create profitable solutions for clients.
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A standard 20° pressure angle, 20 tooth pinion with a diametral pitch of 12 rotates at 1776 rpm driving a mating gear at 740 rpm.a) How many teeth are there on the gear?b) What are the pitch diameters of the pinion and gear?c) What are the standard addendum and dedendum diameters of the pinion and gear?d) What is the theoretically correct center distance?e) What are the radial, tangential and normal tooth loads when contact between the pinion and the gear occurs at the pitch point and the gearset is transmitting ½ hp?
Answers
Answer:
A) 48
B) Pitch diameters : pinion = 42.164 mm, Gear = 101.19 mm
C) standard addendum : pinion = 46.3804, Gear = 105.406
standard dedendum : pinion = 37.265 mm, Gear = 96.312 mm
D) 71.672 mm
E) 94.989 N , 101.0858 N, 34.573 N
Explanation:
Given Data :
∅ = 20⁰ , Tp = 20 ( tooth pinion ),
diameter pitch = 12, Np = 1776 rpm ,
Ng = 740 rpm,
attached below is the detailed solution of the given problems
Is the impedance of the capacitor purely reactive, and how does it compare to the nominal value of the ideal capacitor? Why or why not is it purely reactive?
Answers
In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.
What is the impedance of an ideal capacitor?An perfect capacitor has an infinite resistance. For all frequencies and capacitance levels, the reactance of a perfect capacitor, and consequently its impedance, is negative.A capacitor that has no resistance and therefore doesn't lose any energy while it's operating is the ideal capacitor. It just possesses capacitance. There is no dielectric loss in a perfect capacitor. High temperature stability characterizes the ideal capacitor.As capacitance and frequency increase, capacitive reactance falls. Impedance is the complete opposition that reactance and resistance give.Similar to inductors, the ideal capacitor is a totally reactive device with no resistive (power dissipative) effects whatsoever. Of course, nothing is so flawless in the actual world. Capacitors, however, have the advantage of often being more pure reactive componentsTo learn more about Ideal capacitor refer to:
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The yield stress for a zirconium-magnesium alloy is σY = 15. 3 ksi. A machine part is made of this material and a critical point in the material is subjected to in-plane principal stresses σ1 and σ2 = −0. 54 σ1.
Determine the magnitude of σ1 that will cause yielding according to the maximum-shear-stress theory
Answers
The magnitude of σ1 that will cause yielding according to the maximum-shear-stress theory is 9.94 ksi.
Yield stress for the zirconium-magnesium alloy, σY = 15.3 ksi
In-plane principal stresses are σ1 and σ2 = −0.54σ1
To find the maximum shear stress theory, the equation used is τ_max=1/2(σ1-σ2)
The maximum shear stress theory states that yielding begins when the maximum shear stress in a part equals or exceeds the shear strength of the material. It is represented as τ_max = τ_yield
Where τ_max is the maximum shear stress in a part and τ_yield is the shear strength of the material. In-plane principal stresses are σ1 and σ2 = −0.54σ1
Let us replace the value of σ2 in terms of σ1σ2 = −0.54σ1,σ1 = 1.85σ2
Substitute the values in the τ_max=1/2(σ1-σ2)
τ_max=1/2(σ1-(-0.54σ1))
τ_max=0.77σ1
Now, τ_yield= σY/2 = 7.65 ksi
Therefore, 0.77σ1 = 7.65
σ1 = 9.94 ksi
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A station supplies 250 kVA at a lagging power factor of 0.8. A synchronous motor is connected in parallel with the load. If combined load is 250 kW with lagging p.f. of 0.9, determine:
Answers
Answer:al part of question
Explanation:voltage
Consider a regenerative gas-turbine power plant with two stages of compression and two stages of expansion. The overall pressure ratio of the cycle is 9. The air enters each stage of the compressor at 300 K and each stage of the turbine at 1200 K. Accounting for the variation of specific heats with temperature, determine the minimum mass flow rate of air needed to develop a net power output of 105 MW.
Answers
Answer: the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s
Explanation:
from the T-S diagram, we get the overall pressure ratio of the cycle is 9
Calculate the pressure ratio in each stage of compression and expansion. P1/P2 = P4/P3 = √9 = 3
P5/P6 = P7/P8 = √9 =3
get the properties of air from, "TABLE A-17 Ideal-gas properties of air", in the text book.
At temperature T1 =300K
Specific enthalpy of air h1 = 300.19 kJ/kg
Relative pressure pr1 = 1.3860
At temperature T5 = 1200 K
Specific enthalpy h5 = 1277.79 kJ/kg
Relative pressure pr5 = 238
Calculate the relative pressure at state 2
Pr2 = (P2/P1) Pr5
Pr2 =3 x 1.3860 = 4.158
get the two values of relative pressure between which the relative pressure at state 2 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.
Relative pressure pr = 4.153
The corresponding specific enthalpy h = 411.12 kJ/kg
Relative pressure pr = 4.522
The corresponding specific enthalpy h = 421.26 kJ/kg
Find the specific enthalpy of state 2 by the method of interpolation
(h2 - 411.12) / ( 421.26 - 411.12) =
(4.158 - 4.153) / (4.522 - 4.153 )
h2 - 411.12 = (421.26 - 411.12) ((4.158 - 4.153) / (4.522 - 4.153))
h2 - 411.12 = 0.137
h2 = 411.257kJ/kg
Calculate the relative pressure at state 6.
Pr6 = (P6/P5) Pr5
Pr6 = 1/3 x 238 = 79.33
Obtain the two values of relative pressure between which the relative pressure at state 6 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.
Relative pressure Pr = 75.29
The corresponding specific enthalpy h = 932.93 kJ/kg
Relative pressure pr = 82.05
The corresponding specific enthalpy h = 955.38 kJ/kg
Find the specific enthalpy of state 6 by the method of interpolation.
(h6 - 932.93) / ( 955.38 - 932.93) =
(79.33 - 75.29) / ( 82.05 - 75.29 )
(h6 - 932.93) = ( 955.38 - 932.93) ((79.33 - 75.29) / ( 82.05 - 75.29 )
h6 - 932.93 = 13.427
h6 = 946.357 kJ/kg
Calculate the total work input of the first and second stage compressors
(Wcomp)in = 2(h2 - h1 ) = 2( 411.257 - 300.19 )
= 222.134 kJ/kg
Calculate the total work output of the first and second stage turbines.
(Wturb)out = 2(h5 - h6) = 2( 1277.79 - 946.357 )
= 662.866 kJ/kg
Calculate the net work done
Wnet = (Wturb)out - (Wcomp)in
= 662.866 - 222.134
= 440.732 kJ/kg
Calculate the minimum mass flow rate of air required to generate a power output of 105 MW
W = m × Wnet
(105 x 10³) kW = m(440.732 kJ/kg)
m = (105 x 10³) / 440.732
m = 238.2 kg/s
therefore the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s
What can be used to measure the alcohol content in gasoline? A. Graduated cylinder B. Electronic tester C. Scan tool D. Either a graduated cylinder or an electronic tester
Answers
Answer:
GRADUATED CYLINDER
Explanation:
key components of wait line simulations include all of the following except
Answers
Key components of wait line simulations include: Arrival Process, Service Process, Queue Discipline, System Capacity, Performance Measures.
Arrival Process: The process that determines how customers arrive at the system.
Service Process: The process that determines how customers are served or processed.
Queue Discipline: The rules that govern the order in which customers are served.
System Capacity: The maximum number of customers the system can accommodate at a given time.
Performance Measures: The metrics used to evaluate the performance of the system, such as average waiting time, utilization, or throughput.
Based on the options provided, the key components of wait line simulations include all of the above. Therefore, none of the options should be excluded.
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Joe, a technician, is attempting to connect two hubs to add a new segment to his local network. He uses one of his CAT5 patch cables to connect them; however, he is unable to reach the new network segment from his workstation. He can only connect to it from a workstation within that segment. Which of the following is MOST likely the problem?
A. One of the hubs is defective.
B. The new hub is powered down.
C. The patch cable needs to be a CAT6 patch cable.
D. The technician used a straight-through cable.
Answers
Answer:
Option D. is correct
Explanation:
Joe uses one of his CAT5 patch cables to connect two hubs to add a new segment to his local network. As he can only connect to it from a workstation within that segment, he is not able to reach the new network segment from his workstation.
The most problem is that the technician used a straight-through cable.
Option D. is correct.
"geophysical exploration definition"
Answers
Answer:
Exploration geophysics is an applied branch of geophysics and economic geology, which uses physical methods, such as seismic, gravitational, magnetic, electrical and electromagnetic at the surface of the Earth to measure the physical properties of the subsurface, along with the anomalies in those properties
what is time dependent
Answers
Answer:
Adjective. time-dependent (not comparable) (mathematics, physics) Determined by the value of a variable representing time.
Explanation:
Plz mark brainliest thanks
Answer: Adjective. time-dependent (not comparable) (mathematics, physics) Determined by the value of a variable representing time
An ideal gas is contained in a closed assembly with an initial pressure and temperature of
250kN/m² and 115°C respectively. If the final volume of the system is increased 1.5 times and
the temperature drops to 35°C, identify the final pressure of the gas.
Answers
Answer:
Two identical containers each of volume V 0 are joined by a small pipe. The containers contain identical gases at temperature T 0 and pressure P 0 .One container is heated to temperature 2T 0 while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T 0
Explanation:
True or False: Conditions, like the number of times repeated, are used to end a [Repeat] block.
Answers
Answer:
True. needa type in 20 more letters
Explanation:
ye.
*sapnap teaching you how to drive*
"Skeppy and Badboyhalo are crossing the street, what do you hit?"
"Skeppy, I would never hurt Bad."
"whA- THE BRAKES YOU HIT THE BREAKS!!"
*Dream wheezing from the back*
Answers
Answer:
yes dream
Explanation:
Answer:
Me: "i would just hit you, sapnap. In the freaking face" LOL
what is the largest unsigned (positive) 4-bit binary number?
Answers
The largest unsigned (positive) 4-bit binary number is 1111, which is equivalent to 15 in decimal.
In binary, 4 bits can represent a maximum of 16 different numbers, ranging from 0000 to 1111. The largest unsigned 4-bit binary number would be 1111, which is equal to 15 in decimal form. Therefore, the largest unsigned 4-bit binary number is 15. A binary number is a number that is expressed in the binary system or base 2 numeral system, according to digital technology and mathematics. It uses the symbols 1 (one) and 0 to represent different numeric values (zero). The positional notation with 2 as a radix is known as the base-2 system.
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Neglect the mass of various members and all friction in this problem. Determine the pin force at A. ABC is a single bar. Caution: This problem is not metric!
Answers
To determine the pin force at point A, we need additional information such as the applied loads, dimensions, and geometry of the bar ABC. Without these specific details, it is not possible to provide a precise answer.
However, in general, to calculate the pin force at point A, we would need to perform an equilibrium analysis of the forces acting on the bar. This would involve considering external loads, reactions at the supports, and any internal forces within the bar. By applying the principles of statics and summing the forces and moments, we can solve for the pin force at point A.
To proceed with a detailed analysis and provide an accurate answer, please provide the necessary information, such as the applied loads, dimensions, and any other relevant details about the bar ABC.
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Jay decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jay traveling?
Answers
Answer: jay is traveling at 4 miles per hour :)
Explanation:
Both forms of the rmf illustrate a(n) _______ engineering process as a way to plan, design, and build a complicated system.
Answers
Both forms of the Risk Management Framework (RMF) illustrate a systems engineering process as a way to plan, design, and build a complicated system.
What is engineering?Engineering is a discipline and profession that involves the application of scientific, mathematical, and practical knowledge to design, develop, build, and improve various systems, structures, machines, processes, and technologies.
Engineers utilize their expertise to solve complex problems and create practical solutions that meet societal needs.
Engineers employ a systematic and analytical approach, combining creativity, technical skills, and scientific principles to tackle challenges across different fields.
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The supply and furthest outlet The minumum value of insulation resistance test performed on a small extra low voltage installation is a) 99.0 MOhm c) 0.3 MOhm b) 2.0 MOhm d) 0.5 MOhm
Answers
Explanation:
The minimum value of insulation resistance test performed on a small extra low voltage installation is B) 2.0 MOhm. This resistance is required to ensure the safety of the installation by preventing electric shocks and other hazards.
A furnace wall composed of 200 mm, of fire brick. 120 mm common brick 50mm 80% magnesia and 3mm of steel plate on the outside. If the inside surface temperature is 1450 °C and outer surface temperature is 90°C, estimate the temperature between layers and calculate the heat loss in KJ/h-m2. Assume k for fire brick 4 KJ/m-h°C, k for common brick= 2.8 KJ/m-h°C, k for 85% magnesia = 0.25 KJ/m-h°C and k for steel 240 KJ/m-h°C, k
Answers
Answer:
fire brick / common brick : 1218 °Ccommon brick / magnesia : 1019 °Cmagnesia / steel : 90.06 °Cheat loss: 4644 kJ/m^2/hExplanation:
The thermal resistance (R) of a layer of thickness d given in °C·m²·h/kJ is ...
R = d/k
so the thermal resistances of the layers of furnace wall are ...
R₁ = 0.200/4 = 0.05 °C·m²·h/kJ
R₂ = 0.120 2.8 = 3/70 °C·m²·h/kJ
R₃ = 0.05/0.25 = 0.2 °C·m²·h/kJ
R₄ = 0.003/240 = 1.25×10⁻⁵ °C·m²·h/kJ
So, the total thermal resistance is ...
R₁ +R₂ +R₃ +R₄ = R ≈ 0.29286 °C·m²·h/kJ
__
The rate of heat loss is ΔT/R = (1450 -90)/0.29286 = 4643.70 kJ/(m²·h)
__
The temperature drops across the various layers will be found by multiplying this heat rate by the thermal resistance for the layer:
fire brick: (4543.79 kJ/(m²·h))(0.05 °C·m²·h/kJ) = 232 °C
so, the fire brick interface temperature at the common brick is ...
1450 -232 = 1218 °C
For the next layers, the interface temperatures are ...
common brick to magnesia = 1218 °C - (3/70)(4643.7) = 1019 °C
magnesia to steel = 1019 °C -0.2(4643.7) = 90.06 °C
_____
Comment on temperatures
Most temperatures are rounded to the nearest degree. We wanted to show the small temperature drop across the steel plate, so we showed the inside boundary temperature to enough digits to give the idea of the magnitude of that.
Faster air movement over an airfoil creates a _________ pressure field, which in turn allows lift.
a
Higher
b
Lower
Answers
Hai
Your answer will be A.
If you lower the Air Pressure your Object will Float Down ward. The Air Pressure allows it to Fly.
The pressure field created by faster air movement over an airfoil is; A: higher
What is pressure field?When the air hits the front of the wing, the air will flow in a steeper curve upward, than the bottom wing flow which will lead to the creation of a vacuum on top of the wing that pulls more air towards the top of the wing.
Finally, this air above does the same thing but it will move faster as a result of the vacuum pulling it in, and as such the vacuum now lifts the wing. Thus, Faster air movement over an airfoil creates a higher pressure field.
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PLEASE HELP I NEED THIS ASP!!
Answers
Answer:
up up down down
Explanation:
left right left right b a select start
Leland wants to work in a Production career operating heavy machinery. Which type of education or training should Leland seek?
a bachelor’s degree then a master’s degree
vocational school certificate or master’s degree
on-the-job training or vocational school certificate
associate’s degree then a bachelor’s degree
Answers
Answer:
it is indeed C
Explanation:
Answer:
c
Explanation:
Coal can contain up to about 2000 ppm (by mass) of natural uranium. Compare the chemical energy content of the coal with the available fission energy from the 235U content of the uranium (as used in a thermal reactor) and the total available fission energy from the uranium including 238U (as might be used in a breeder reactor).
Answers
About 1 MW is released each day when 1 g of uranium or plutonium fissions. This is roughly equivalent to 3 tons of coal or 600 gallons of fuel oil burned each day, which releases about 1/4 tonne of carbon dioxide when burned. (One metric ton, or tonne, is equal to 1000 kg.)
How much energy is released during a fission of uranium-235?The total binding energy released during the fission of an atomic nucleus varies depending on the exact breakdown but typically ranges between 200 MeV* and 3.2 x 10-11 joules for U-235. About 82 TJ/kg is this.
How much more energy is contained in one gram of 235U than one gram of coal?In actuality, burning 3 tons of coal produces the same amount of energy as fissioning 1 gram of uranium 235 (1)! It is possible to use the energy generated by the fission of uranium or plutonium to generate electricity, launch spacecraft, and power weapons like the atomic bomb.
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During the busy period of work on a maintenance shutdown, workers arrive at the safety engineer trailer at an average rate of 8 per hour, seeking welding permits. The safety engineer can issue a welding permit in an average of 6 minutes. Determine the average number of workers at the trailer (including the one whose permit is being worked on). Consider the trailer as the system we are analyzing. Group of answer choices
4 workers
3 workers
5 workers
6 workers
Answers
To determine the average number of workers at the trailer, we can use the M/M/1 queuing model, where arrivals follow a Poisson process and service times follow an exponential distribution.So, the correct answer is:2 workers
Given that workers arrive at an average rate of 8 per hour, the arrival rate (λ) is 8 per hour. The average service time (1/μ) is 6 minutes, which can be converted to hours by dividing by 60, resulting in μ = 1/10 per hour.
Using the M/M/1 queuing formula for the average number of workers (N) in the system:
N = λ / (μ - λ)
Substituting the values, we have:
N = 8 / (1/10 - 8) = 8 / (1/10 - 80) = 8 / (-79/10) = -80/79 ≈ -1.01
Since the number of workers cannot be negative, we take the absolute value, resulting in approximately 1.01 workers.
However, since the question asks for the average number of workers at the trailer, including the one whose permit is being worked on, we need to consider at least one worker. Therefore, we round up the result to the nearest whole number, which gives us an average of 2 workers at the trailer.
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the probability that a bolt meets a strength specification is 0.79. what is the probability that the bolt does not meet the specification? (round the final answer to two decimal places.)
Answers
If the probability of a bolt meeting a strength specification is 0.79, then the probability of it not meeting the specification is 0.21.
The probability that a bolt meets a strength specification is 0.79. Therefore, the probability that it does not meet the specification can be calculated by subtracting the probability of meeting the specification from 1.
The calculation is as follows:
1 - 0.79 = 0.21
So, the probability that the bolt does not meet the specification is 0.21 or 21%.
In conclusion, It's important to note that these probabilities are complementary to each other, meaning they add up to 1 or 100%. This information can be useful for quality control and ensuring that bolts meet certain standards.
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