why is the uncertainity principle or the wave nature of particles not significant when looking at macroscopic objects

I can provide guidance on how to structure your lab report based on the questions you have provided.

In the first paragraph, you should briefly state the purpose of the lab. This should include a clear statement of the problem or question that the lab is addressing. For example, "The purpose of this lab was to investigate the effect of temperature on the rate of enzyme activity."

In the first part of this section, you should include any charts, tables, or drawings that would clearly show what you have learned in the lab. Each chart, table, or drawing should have an appropriate title and appropriate labels.

When complete, the lab report should be read as a coherent whole. Make sure you connect different pieces with relevant transitions. Review for proper grammar, spelling, punctuation, formatting, and other conventions of organization and good writing. It is important to be clear and concise in your writing and to use appropriate scientific language and terminology.

The initial velocity of the car as it slow to rest with an acceleration of -5 m/s² is 11.5 m/s.

This can be defined as the ratio of displacement to the time of a body

To calculate the initial velocity of the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the initial velocity of the car is 11.5 m/s

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Answer:

volume = 30cm^3

Explanation:

For the designing of differential amplifier following were found out :

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

To design the differential amplifier according to the given specifications, we will follow these steps:

Step 1: Calculate the small-signal gain (Av)

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Step 4: Calculate the tail current (Itail) based on the specified Iss

Step 5: Determine the resistance (R) value

Step 6: Calculate the width (Wp) of the PMOS transistor

Step 7: Calculate the width (Wn) of the NMOS transistors

Now let's go through each step in detail.

Step 1: Calculate the small-signal gain (Av)

Given: Av = 10, VOP = VON = 3.5V

Av = (vop - von) / (vip - vin)

10 = (3.5 - 3.5) / (0.1)

10 = 0 / 0.1

Since the numerator is zero, the small-signal gain is zero.

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

ro = 1 / (lambda * unCox * (W/L))

We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.

For the NMOS transistors:

Vgs = 0 (since Vin = Vbias)

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

  = 2 * 400 μA/V² * (W/L) * (0 - 0.8)

  = -640 * (W/L) μA/V

ro = 1 / (lambda * unCox * (W/L))

  = 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))

  = 1 / (8 * (W/L)) kΩ

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm

Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.

For the PMOS transistors:

Vsg = 0 (since Vin = Vbias)

gm = 2 * upCox * (W/L) * (Vtp - Vsg)

  = 2 * 200 μA/V² * (W/L) * (-0.8 - 0)

  = -320 * (W/L) μA/V

ro = 1 / (lambda * upCox * (W/L))

  = 1 / (0.04 V^(-1) * 200 μA/V² *

  = 1 / (5 * (W/L)) kΩ

Step 4: Calculate the tail current (Itail) based on the specified Iss

Given: Iss = 2 mA

Itail = Iss / 2

= 2 mA / 2

= 1 mA

Step 5: Determine the resistance (R) value

Given: Vs = 0.3 V, VDD = 5 V

We can calculate the resistance (R) value using Ohm's Law:

Vs = Itail * R

0.3 V = 1 mA * R

R = 0.3 kΩ

Step 6: Calculate the width (Wp) of the PMOS transistor

To calculate Wp, we'll use the equation for the tail current:

Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2

Solving for Wp:

Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)

Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)

Wp ≈ 0.0075 μm

Step 7: Calculate the width (Wn) of the NMOS transistors

Given: Wn = 4 * Wp

Wn = 4 * 0.0075 μm

Wn = 0.03 μm

So, the design parameters for the differential amplifier are as follows:

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

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Answer:

try the formula v=s/t

v= velocity

s= speed

t=time

Explanation:

Explanation:

In order to get to 2 atmospheres worth of air pressure, you would need to get to the point where there's 29.4 psi (2 times 14.7 psi). To get to 29.4 psi, it turns out that you would need to be 33 feet deep.

hope it helps you

Answer:

Explanation:hffdghbjhhfgdvbjnjhjvcfgdfcvhjkm,kjjhgjh

No work is done to move the ball to the right.

Initial velocity = -  30 m/s

Final velocity = + 30 m/s

Kinetic energy :

ΔK = 1/2 mv² - 1/2 mu²

Δk = 1/2m ( v² - u² )

ΔK = 1/2 × m ( 30² - 30² )

ΔK = 0

thus no work is done on the ball

However, the work done to bring the ball to stop is :

W = 0.5 × 0.02 × - 900

W = - 9 J

Work done for the acceleration of the ball to come to rest is :

W2 = + 9 J

The work done again  would be :

Work done = - 9 + 9 = 0 Joule

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Answer:

The quadratic function models the path of the rocket. When we substitute an x value, we can determine the height in feet of the rocket.

To determine the height it was launched from, we would look at the y-intercept. This represents the starting value, as time = 0 in this point (cannot have negative time).

To determine how far the rocket traveled, we would look at the positive x-intercept of the expression. At this point, height = 0, so we can see the distance from start to finish of the rocket.

To determine the greatest height achieve, we would look at the vertex of the parabola generated from the given function. Using (-b/a, f(-b/a)), we can determine the greatest height achieved.

Answer:

its A Weathering breaks down rocks; deposition leaves them in new places

Explanation:

A piston is placed inside a gas-filled cylinder. It is calculated to be the gas's starting pressure. expanding the gas until it reaches its final volume and 18.4 kPa of pressure.

We know that P1V1 = P2V2

Now P1 = 90.1 kPa

        V1 = 10 L

       V2 = 49 L

therefore

90.1 x 10 = P2 x 49

therefore P = 18.387

P = 18.4 kPa

In order to measure an object's surface tension, a force must be applied perpendicularly to the object's surface over a given area. Alternatively spelled gauge pressure, gauge pressure is the pressure in relation to atmospheric pressure.

Pressure is expressed using a number of different units. The SI unit of pressure, the pascal (Pa), for instance, is equal to one newton per square meter (N/m2); similarly, the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi). Some of these measurements are the result of dividing a unit of force by a unit of area. The atmosphere (atm), which is equal to this pressure, and the tour, which is defined as 1760 of it, can also be used to describe pressure.

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The equilibrium fraction of lattice sites that are vacant in silver (Ag) at 700° C is approximately \(1.17 \times 10^{-8}\) or 1.17 parts per billion (ppb).

Partial separation of isotopes between two or more substances in chemical equilibrium is called equilibrium isotope fractionation.

The equilibrium fraction of lattice sites that are vacant in silver (Ag) at 700 °C can be calculated using the expression:

\($\mathrm{\frac{nv}{n} = exp\left(\frac{-Qv}{kT} \right)}\)

nv = number of vacancies

n = total number of lattice sites

Qv = energy required to create a vacancy

k = Boltzmann constant = \(1.38 \times 10^{-23}\) J/K

T = temperature in Kelvin

\($\mathrm{\frac{nv}{n} = exp\left(\frac{-Qv}{kT} \right)}\)

\($\mathrm{\frac{nv}{n} = e^{\left(\tfrac{-Qv}{kT} \right)}}\)

Qv = Ed - kT ln(Dv)

Ed = activation energy for vacancy formation

Dv = pre-exponential factor for vacancy formation

\(\mathrm{Qv = 1.03 eV - (1.38 \times 10^{-23} J/K) (973 K) \ln(3.3 \times 10^{13} s^{-1})}\)

Qv = 1.03 eV - 1.32 eV

Qv = -0.29 eV

\($\mathrm{\frac{nv}{n} = e^{\tfrac{-Qv}{kT}}}\)

nv/n = e^(-(-0.29 eV)/(1.38 × 10⁻²³ J/K × 973 K))

\($\mathrm{\frac{nv}{n} = e^{\left(\tfrac{-(-0.29eV)}{1.3\times 10^{-23}J/K \times 973 K}\right)}}\)

\($\mathrm{\frac{nv}{n} = e^{(1.81 \times 10^{13})}}\)

\(\mathrm{ \dfrac{nv}{n} = 1.17 \times 10^{-8}}\)

Therefore, the equilibrium fraction of lattice sites that are vacant in silver (Ag) at 700° C is approximately \(1.17 \times 10^{-8}\) or 1.17 parts per billion (ppb).

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Answer:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Explanation:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Answer:

mass is not eager to be accelerated or in this case slowed down.

Explanation:

In general, Newton's 1st law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

What this means is that a mass is not eager to be accelerated or in this case slowed down. It will require an external force (muscle power) to get the mass of a running man to slow down. It is not instant also, because it takes time to slow down.

EXTRA

Supose the running man would try to stop instantly by purposely running against a brick wall. Even in that case, there is a small amount of time needed ( a fraction of a second perhaps) in which the moving mass of the man is forced to stop moving. That force is usually so huge, that it will injure someone in case of a crash, which might result even in death!

The purpose of an airbag or wearing a helmet, is to extend the time during a crash, FROM 0 to close to zero.

The layer of foam inside a helmet, protects the head in case of a crash, because it takes an amount of time for the head to squash the foam inside the helmet because the mass needs to be stopped ALMOST instantly. That difference between zero seconds and maybe 1 second, is sometimes enough to be able to survive a crash.

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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Light bulbs can be used to indicate current flow in a circuit. The brightness of a bulb is proportional to the amount of current passing throw it. The figure shows a battery, a switch, two light bulbs, and a capacitor that is initially uncharged The brightness of a lightbulb is given by its power. P = I2R, and so brightness depends on current and resistance

A stream of charged particles, such as electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated. [622 Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles. Electrons flowing over a wire are frequently used as charge carriers in electric circuits. They can be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons are the charge carriers in plasma, an ionized gas.

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Answer: The  Answer Is A

Explanation:

In the very distant future, given our best model of the accelerating universe, the universe will look like: (d) all the galaxies will start showing blue-shifts.

Everything is included in the universe. All of the stuff and energy that are present in space are included in it. It even covers the passage of time. The Earth and Moon, as well as the other planets and their many dozens of moons, are all part of the cosmos.

According to one theory, the cosmos is made up of "dark energy," "dark matter," and "regular matter." Normal matter is made up of atoms, which are the building blocks of stars, planets, humans, and everything else observable in the Universe.

By bursting into space itself, the Big Bang formed our universe. Space expanded, the cosmos cooled, and the basic elements were created, beginning with extraordinarily high density and temperature. To create the earliest stars and galaxies, gravity gradually pulled stuff together.

Thus, the best model of the accelerating universe is - d.all the galaxies will start showing blue-shifts.

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The mass (in grams) Ricardo should measure out on the scale, given that he has 2500 mg is 2.5 g (Option B)

To obtain the mass that Ricardo should measure out on the scale, we shall convert 2500 milligrams (mg) to grams (g). This is illustrated below:

Conversion scale

1000 mg = 1 g

Therefore

2500 mg = (2500 mg × 1 g) / 1000 mg

2500 mg = 2.5 g

From the above, we can see that 2500 mg is equivalent to 2.5 g

Thus, we can conclude from the above illustration that the mass Ricardo should measure out on the scale is 2.5 g (Option B)

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In Sound Navigation and Ranging (SONAR), the sound wave is transmitted through water and it will reflect by hard surfaces. Option B) is correct.

SONAR is used to create nautical charts, find underwater navigation hazards, search for and map things on the seafloor such as shipwrecks and map the seafloor itself, waves are transmitted into the waver and reflected by hard surfaces.

The transmission and receiving of sound waves are involved in active sonar. For example, when a submarine is used to map the topography of the ocean floor.

It emits sound pulses known as pings towards the bottom of the ocean in its area.

Thus, 'Sound is transmitted through water and reflected by hard surfaces is the correct option'.

The question is incomplete. The options are missing in the question. They are A) Sound is transmitted through the water and diffracted by hard surfaces. B) Sound is transmitted through the water and reflected by hard surfaces. C) Sound is diffracted through the water and transmitted by hard surfaces. D) Sound is diffracted through the water and reflected by hard surfaces.

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Answer:

Motion

Acceleration is the change of velocity per unit time, so if there is no force, all we know is that the acceleration is zero. Therefore, the velocity is not changing. If the object was already moving, then it will just keep moving. So, the object can be moving even when there is no force applied to it.

Forces may cause an object to change its state if it is unable to move. The force make the object to move from its state of rest.

Force is an external agent acting on an object to deform it or to change it state of rest or motion. There are various kinds of forces such as gravitational force, nuclear force, magnetic force, frictional force etc.

Force is a vector quantity thus, it is characterised by its magnitude and direction. According to Newton's first law of motion, an object will continue in its state or motion or rest until an external force acts on it.

Therefore, force changes the state of an object. Force is dependant on the mass of the object. Greater the mass, greater will be the force required to move the object from stationary to stop it from motion.

According to second law of motion, force is the product of mass and acceleration of the object. Hence, force accelerates the body and a change in force changes the acceleration of the object.

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Answer:

2.4 secs.

Explanation:

Current (A) = Charge (coulomb)/Time(sec)

We are looking for time. So:

Time (sec) = Charge (coulomb)/Current (A)

↓

12coulombs/5.0A = 2.4 secs

Yes, if the electric field (e) is constant in magnitude over the surface of a charged conductor, then the charge must be uniformly distributed over it. This is because the electric field is directly proportional to the charge density, which is the amount of charge per unit area. If the electric field is constant, then the charge density must also be constant, resulting in a uniform distribution of charge over the conductor's surface.

The electric field at any point on the surface of a conductor is directly proportional to the surface charge density (σ) at that point, which is defined as the charge per unit area. Mathematically, we can express this relationship as E = σ / ε0, where ε0 is the electric constant.

If e is constant over the surface, then the surface charge density σ must also be constant. Therefore, the charge per unit area must be the same everywhere on the surface, which implies that the charge is uniformly distributed over the surface.

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Fick's law of diffusion is an important principle in biomedical engineering that describes the movement of one substance through another.

Specifically, the law explains how a solvent (such as water) moves through a membrane. The rate of diffusion is influenced by several factors, including the size of the molecules involved, the temperature of the system, and the concentration gradient of the substance.
In order to fully understand diffusion, it is important to understand the concept of a solvent. A solvent is a substance that is able to dissolve other substances, creating a solution. For example, water is a common solvent that can dissolve many different substances. When a solvent (like water) moves through a membrane, it is able to dissolve and transport other substances with it.
Fick's law of diffusion is an essential concept in biomedical engineering because it helps us understand how drugs and other therapeutic substances are able to move through membranes in the body. By understanding the principles of diffusion, engineers and scientists can develop more effective drug delivery systems that can target specific areas of the body and release drugs in a controlled and sustained manner.

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Answer:

The ability of humans to see clothing's and other objects depends on diffuse reflection.

Explanation:

Hoped that helped

Answer:

gravity

Explanation:

Room will be a cuboid .

Hence

\(\\ \sf\longmapsto Volume=LBH\)

\(\\ \sf\longmapsto Volume=Length\times Breadth\times Height\)

The crane uses a heavy concrete block as a counterweight to balance itself when lifting and moving heavy loads.

The counterweight is attached to one end of the crane's arm to prevent it from tipping over due to uneven weight distribution. Additionally, concrete blocks are placed around the crane's base to further enhance its stability and prevent tipping. These measures ensure the safe and efficient operation of the crane.

These blocks act as a foundation and further enhance the crane's overall balance and resistance to tipping over. By distributing the weight across a wider base, the crane becomes more stable and secure during operation.

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