While looking out the window, you see lightning flash and then two seconds later, you hear the thunder. How far was the lightening from you

Answer:

Letter A. \(y=4.55 m\)

Explanation:

Let's use the wave equation:

\(y=Asin(kx-\omega t)\)

Therefore the displacement y will be:

\(y=6.44*sin(2.34*1.21-2.88*0.71)\)

\(y=4.55 m\)

The answer is letter A.

I hope it helps you!

Answer:

Explanation:

Find the displacement of a simple harmonic wave of amplitude 6.44 m at t = 0.71 s. Assume that the wave number is 2.34 m-1, the angular frequency is 2.88 rad/s, and that the wave is propagating in the +x direction at x = 1.21 m.

Amplitude (A) of the simple harmonic wave = 6.44 m

wave number (k) of the given wave = 2.34 m-1

Angular frequency (ω) of the given wave = 2.88 rad/s

Displacement x = 1.21 m and time t = 0.71 s

Then the general equation for the displacement of the given simple harmonic wave at given x and time t is given by

y = Asin(kx - ωt)

= (6.44 m)sin[(2.34 m-1)(1.21 m) - (2.88 rad/s)(0.71 s)]

Y=6.44sin(0.7866 rad)

0.7866rad*(180 degrees/pi rad) =45.1

Y=6.44sin(45.1)

Y=4.55m

Answer:

12.483 Kpa

46.806 Kpa

Explanation:

Man's height = 1.8m

Pheart = 13.3 * 10^3

Density of blood (ρ) = 1060 kg/m³

Height difference between heart and brain (Hh - Hb) = 0.35m

g = acceleration due to gravity = 9.8 m/s²

Acceleration (a) = 12 m/s²

Blood pressure in brain :

Pbrain = Pheart - ρ(a - g) * (Hh - Hb)

Pbrain = 13.3 * 10^3 - 1060(12 - 9.8) * 0.35

Pbrain = 13300 - (2332 * 0.35)

Pbrain = 13300 - 816.2

Pbrain = 12483.8 pascal = 12.483 Kpa

Blood pressure in feet :

Pbrain = Pheart + ρ(a + g) * 1.8 - (Hh - Hb)

Pbrain = 13.3 * 10^3 + 1060(12 + 9.8)*(1.8 - 0.35)

Pbrain = 13300 + 1060(21.8 * 1.45)

Pbrain = 13300 + 33506.6

Pbrain = 46806.6 pascal = 46.806 Kpa

Answer:

Fluorine

Explanation:

The more number of electrons on the outer shell makes the atom more reactive

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

3000 seconds

Explanation:

Answer:

Kindly check explanation

Explanation:

The trampling and violation of human rights individuals, groups and corporate organizations is really alarming ad as such, the government who are charged to protect the right and interest of its citizen. In other to curtail the trending issues of human right violation, it is imperative if sensitization programmes could be organiz d in other to keep people informed of the various ways in which people's right may be trampled upon. With these education, the ignorance can be expunged leaving only those who genuinely decides to relate and threaten the right of his fellow country person.

The laws on human right violation should be reviewed and capital punishment metted on violators in other to send a strong warning to those who still nurture the intention.

Answer:

\(1.6 \,\,\,10^{-4}\)

Explanation:

Recall that scientific notation involves expressing the number in powers of ten, and using a multiplicative factor whose value is larger than or equal to 1 (one) and strictly smaller than 10 in the form:

\(a\,\,\,10^n\\with\,\,\,1\leq a<10\)

and with n an integer value.

in our case, notice that 0.00016 = 16 / 100000 = 1.6 / 10000

and that denominator can be expressed as: 10^4, and can also be brought to the numerator as a negative power of ten:

1.6 / 10000 = 1.6 / 10^4 = 1.6 * 10^(-4)

\(\frac{16}{100000} =\frac{1.6}{10000}=\frac{1.6}{10^4}=1.6\,\,\,10^{-4}\)

B and C is the answer

Answer:

B and C

Explanation:

A P E X

(a) the shell's horizontal range = 285839 m.

(b) the amount of time the shell is in motion is: 273.11 sec.

The length of the horizontal axis is a projectile's horizontal range. In addition, it would move before returning to the original vertical position.

Horizontal range is equal to Initial Speed in the horizontal direction, multiplied by the time the shell is in motion.  Therefore, both questions can be solved at the same time.

Step 1.  Find Velocity in the Horizontal direction by:  

Vx = (1.70 x 10³) × cos(52°)

Vx = 1046.6 m/sec

Step 2.  Find Velocity in the Vertical direction by:

Vy = (1.70 x 10³) × sin (52°)

Vy = 1339.6 m/sec

Step 3. Find the amount of time the shell is in motion by:  

t= (2 × Vy)/gravity

t = (2 × 1339.6) / 9.81       [ Gravity = 9.81m/s²]

t = 273.11 sec

Step 4. Find the shell's horizontal range:  

Distance = Vx × t

or, distance = (1046.6 × 273.11)

or, distance = 285839 m

Thus, (a) the shell's horizontal range = 285839 m.

(b) the amount of time the shell is in motion is: 273.11 sec.

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Answer:

B

Explanation:

To solve this we must be knowing each and every concept related to  electrical energy.  Therefore, the correct option is option B among all the given options.        

The work done by an electric charge is referred to as electrical energy. For time t seconds, if electricity I ampere passes throughout a conductor or any other conducting element with a potential differential v volts across it.

The kilowatt hour is both a practical as well as an economic unit of electrical energy. The basic commercial unit is the watt-hour, one and kilowatt hour equals 1000 watt hours. Electric supply providers charge their customers every kilowatt hour unit of electricity used. This kilowatt hour seems to be a BOT unit, or board of trade unit.  The electrical energy that does not become light energy, the lightbulb transforms it into thermal energy.

Therefore, the correct option is option B among all the given options.        

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Answer:

Well, this teacher is pretty dumb if you ask me.

Explanation:

5 N, i think this is right.

Answer:

a. Red and Orange

b. Yes, they are

Explanation:

a. This is because, since the yellow light is reflected back into the water, it undergoes total internal reflection and its wavelength in water is not long enough to allow it penetrate the water surface. Since the wavelength decreases from left to right, both the green and blue light have shorter wavelength than the yellow light, so they get reflected back. The red and orange lights are more likely to penetrate since they have longer wavelengths than the yellow light.

b. This is because the red and orange light have longer wavelengths and are thus more likely to penetrate the water surface and not get reflected back.

Answer:

Explanation:

charge on each proton = 1.6 x 10⁻¹⁹ C

mass of proton = 1.67 x 10⁻²⁷ kg

Electrostatic force of repulsion Fe = 9 x 10⁹ x ( 1.6 x 10⁻¹⁹ )² / d²

= 23.04 x 10⁻²⁹ / d²

Gravitational  force of attraction = G Mm / d²

M = m = 1.67 x 10⁻²⁷ kg

Gravitational  force of attraction  Fg = 6.67  x 10⁻¹¹ x ( 1.67 x 10⁻²⁷ )² / d²

= 18.60 x 10⁻⁻⁶⁵ / d²

So Fg is far less than Fe and former is attractive , later is repulsive .

Fe > Fg, opposite direction , is the answer .

Take into account that the static friction supplies the centripetal force, then, you can write:

where,

m: mass of the truck = 1700 kg

v: speed of the truck = 20 m/s

r: turning radius = ?

Fr: maximum frictional force = 12,000 N

Solve the equation above for r, replace the values of the other parameters and simplify:

Hence, the turing radius of the car is approximately 56.67m

Answer:

roasting,

broiling,

pan-broiling,

pan-frying,

grilling.

Explanation:

good luck

Answer:

Explanation:

1. Stir frying

2. Pan frying

3. Grilling /BBQ

4. Baking/roasting

Answer:

Iron deficiency

Explanation:

or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.

Answer:

The path difference will be zero.

Explanation:

Given that,

In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.

Suppose, we find the multiple of wavelength

In young's double slit experiment,

We need to calculate the multiple of wavelength

Using formula of path difference

\(\Delta x=d\sin\theta\)....(I)

\(d\sin\theta=m\lambda\)

Where, m = fringe number

\(\lambda\) = wavelength

For center of a bright fringe ,

m = 0

Put the value into the formula

\(d\sin\theta=0\times\lambda\)

\(d\sin\theta=0\)

Put the value in equation (I)

\(\Delta x=0\)

Hence, The path difference will be zero.

Answer:

2. The temperature is not rising because the heat is being used to break the connections between the molecules.

Explanation:

I remember doing this question and this is the correct answer i just know it by heart.

just trust me by the heart

Answer:

76rsfy7zfyuutfzufyztudzutdT7dFy9y8fr6s

Explanation:

rshyyjfshfsgfshfsyhrsyhuydtufhr6ra6yris7toe7r9w7rr6w996ryrowosotusuogsuoufsutot

Answer:

Acceleration = 8.27 cm/s²

Explanation:

We are given;

initial velocity; v_i = 10.5 cm/s

Initial position; x_i = 2.72 cm

Time; t = 2.30 s

final position; x_f = 5.00 cm

To find the acceleration, we will make use of the formula;

x_f - x_i = (v_i * t) - (½at²)

Plugging in the relevant values, we have;

5 - 2.72 = (10.5 × 2.3) - (½ × a × 2.3²)

2.28 = 24.15 - 2.645a

24.15 - 2.28 = 2.645a

2.645a = 21.87

a = 21.87/2.645

a = 8.27 cm/s²

Answer:

d

Explanation:

The expression for the initial velocity at point A is:

0 = (velocity at point A - 0) / time

Simplifying the equation, we find:

Velocity at point A = 0

The initial velocity at point A is zero, indicating that the object starts from rest before sliding on the horizontal plane AB.

To write an expression for the initial velocity at point A, we need to analyze the forces acting on the object and apply the principles of motion.

Given:

Mass of the object, m

Radius of the semi circle, R

Coefficient of kinetic friction, μ\(_k\) = 0.5

Force applied at point C, F = 3mg

The object is initially at rest.

Let's break down the motion into two parts: the motion on the horizontal plane AB and the motion along the semi circle BCD.

1. Motion on the horizontal plane AB:

The only force acting on the object on the horizontal plane is the force of kinetic friction. The frictional force can be calculated using:

Frictional force, f = μ\(_k\)* Normal force

The normal force is equal to the weight of the object, which is mg.

Normal force, N = mg

Frictional force, f = μ\(_k\) * mg

The frictional force acts in the opposite direction to the motion, so its magnitude is negative. Thus, the net force on the object on the horizontal plane is:

Net force = -f = -μ\(_k\)* mg

Using Newton's second law, we can relate the net force to the acceleration:

Net force = mass * acceleration

-μ\(_k\) * mg = m * acceleration

The acceleration can be expressed as the rate of change of velocity:

Acceleration = (final velocity - initial velocity) / time

Since the object is initially at rest, the initial velocity is zero.

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(a) The pilot's apparent weight at the lowest point of the circle is 0 N.

(b) The pilot's apparent weight at the highest point of the circle is 1240 N.

(d) The speed that would have resulted in the pilot experiencing weightlessness at the top of the loop is approximately 54.9 m/s.

(a) To find the pilot's apparent weight at the lowest point of the circle, consider the net force acting on the pilot. At the lowest point, the net force will be the sum of the gravitational force and the centripetal force.

The gravitational force acting on the pilot is equal to his true weight, which is 620 N.

The centripetal force required to keep the pilot moving in a circular path is given by:

Fc = m × ac

Where Fc = centripetal force, m = mass of the pilot, and ac = centripetal acceleration.

The centripetal acceleration can be calculated using the formula:

ac = v² / r

Where v = speed of the airplane and r = radius of the circle.

Substituting the given values:

ac = (2.35 x 10² m/s)² / (3.35 x 10³ m) = 1.65 m/s²

Now calculate the centripetal force:

Fc = m × ac = 620 N

Since the net force is the sum of the gravitational force and the centripetal force:

Net force = Fc - Fg

Apparent weight = Net force

Substituting the values,:

Apparent weight = 620 N - 620 N = 0 N

Therefore, the pilot's apparent weight at the lowest point of the circle is 0 N.

(b) At the highest point of the circle, the pilot's apparent weight will be the sum of the gravitational force and the centripetal force. The centripetal force remains the same as in part (a).

The net force is given by:

Net force = Fc + Fg

Apparent weight = Net force

Substituting the values:

Apparent weight = Fc + Fg = 620 N + 620 N = 1240 N

Therefore, the pilot's apparent weight at the highest point of the circle is 1240 N.

(d) For the pilot to experience weightlessness at the top of the loop, the net force acting on him should be zero. This means that the centripetal force should be equal to the gravitational force.

Fc = Fg

Using the formulas from part (a):

m × c = mg

ac = g

v² / r = g

v² = rg

Solving for v:

v = √(rg)

Substituting the given values:

v = √((3.35 x 10³ m) × (9.8 m/s²))

v ≈ 54.9 m/s

Therefore, the speed that would have resulted in the pilot experiencing weightlessness at the top of the loop is approximately 54.9 m/s.

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Answer:

f. 80 and 90

Explanation:

1 x 10⁻¹² W/m² sound intensity falls within 0 sound level

1 x 10⁻¹¹ W/m² sound intensity falls within 10 sound level

1 x 10⁻¹⁰ W/m² sound intensity falls within 20 sound level

1 x 10⁻⁹ W/m² sound intensity falls within 30 sound level

1 x 10⁻⁸ W/m² sound intensity falls within 40 sound level

1 x 10⁻⁷ W/m² sound intensity falls within 50 sound level

1 x 10⁻⁶ W/m² sound intensity falls within 60 sound level

1 x 10⁻⁵ W/m² sound intensity falls within 70 sound level

1 x 10⁻⁴ W/m² sound intensity falls within 80 sound level

1 x 10⁻³ W/m² sound intensity falls within 90 sound level

Given sound intensity (3.66 x 10⁻⁴ W/m²) falls with 1 x 10⁻⁴ W/m² of intensity which is within 80 and 90 sound level.

f. 80 and 90

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

3/4

Explanation:

Answer:Lack of experience.

Explanation:

Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.

Length = (75.00 m)

Length = (75 meter) x (3.28084 foot/meter) x (12 inch/foot)

Length = (75 x 3.28084 x 12) (meter-foot-inch / meter-foot)

Length = 2,952.76 inches

The velocity of the third piece is v₃ = -12500 kg·m/s / m₃

The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.

velocity of the third piece =  v₃.

The total initial momentum before the explosion = 0

The total final momentum after the explosion= 0

Initial momentum = 0 kg·m/s (since the bomb is at rest)

Final momentum = m₁v₁ + m₂v₂ + m₃v₃

m₁ = mass of the first piece = 150 kg

v₁ = velocity of the first piece = 150 m/s (to the east)

m₂ = mass of the second piece = 100 kg

v₂ = velocity of the second piece = 200 m/s (south 60° west)

m₃ = mass of the third piece = unknown

v₃ = velocity of the third piece = unknown

0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)

final momentum = 0 and hence  v₃ is found as :

0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)

-12500 kg·m/s = (m₃)(v₃)

v₃ = -12500 kg·m/s / m₃

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Answer:

Explanation:

v = at

t = v/a

t = 20 m/s / 9.8 m/s²

t = 2.0408163...

t = 2.0 s