The object Earth, Sun, and Blood are constantly in motion. The correct option is A, D, and E.
What is motion?if a body changes its position with respect to its surroundings in a given interval of time, Then the body is said to be in motion
.
Motion is generally classified as follows.:
i) Rectilinear motion.
ii) Circular motion.
iii) Rotational motion.
iv) Periodic motion.
The Earth is continuously in motion because it continuously revolves around The Sun in an elliptical orbit, due to which a year is 365 days. and also The earth rotates about its own axis once a day.
The Sun also revolves around the galactic center of our Milkyway galaxy. and it also rotates about its own axis continuously. so that the sun is also continuously in motion.
The Human blood is continuously in motion Because our blood is continuously circulating whole over the body with the help of our heart. The heart continuously pumps our blood and circulates it inside the human body.
Hence the Earth, Sun, and blood are continuously in motion.
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A Chinook salmon can jump out of water with a speed of 7.20 m/s . How far horizontally can a Chinook salmon travel through the air if it leaves the water with an initial angle of =29.0° with respect to the horizontal? (Neglect any effects due to air resistance.)
d=
Explanation:
The vertical component of the salmon's velocity is 7.2 m/s x sin 29 = 3.49 m/s
If g = 9.81 m/s^2, the salmon takes
(3.49 m/s) / (9.81 m/s^2) = 0.356 s to reach the highest point of its trajectory.
It takes another 0.356 s to fall back into the water again.
So the salmon is out of the water for a total of 0.712 s.
In this time the salmon travels horizontally with a velocity of 7.2 m/s x cos 29 = 6.30 m/s
We can now calculate the horizontal distance tavelled by multiplying the horizontal velocity by the time spent out of water;
0.712 s x 6.30 m/s = 4.48 m
2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True
The statement that is NOT true is "the spaces between the particles increased.
option D.
What is effect of temperature on volume?If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.
Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.
As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.
However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.
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In 1988, Galena Christyakova set the woman’s long jump record of 7.52 meters. In 1991, Mike Powell set the men’s long jump record of 8.95 meters. How much farther (EF) would Galena have to jump in order to tie Mikes record?
A.8.95 meters
B.1.43 meters
C.1.19 meters
D.16.47 meters
E.0.84 meters
Answer:
Option (B)
Explanation:
From the picture attached,
Galena set the record in women's long jump DE = 7.52 meters
Similarly, in men's long jump Powell set the record DF = 8.95 meters
Therefore, Galena has to jump more distance to meet the record of Powell.
Distance EF needed more by Galena,
EF = DF - DE
EF = 8.95 - 7.92
EF = 1.43 meters
Therefore, Galena has to jump 1.43 meters more to tie Powell's record.
Option (B) will be the answer.
The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Answer:
mark me brainliest
Explanation:
The change of temperature at absolute scale is. A. 3.73 K
Answer:
373K
Explanation:
300°c - 200°c =100°c
Absolute scale means Kelvin scale so
0°c= 273°c
100°c = 100 + 273
=373K
To better understand crash dynamics we have to look at "__________."
A. the law of gravity
B. Bernoulli's principle
C. the laws of motion
D. Archimedes' principle
To better understand crash dynamics we have to look at "the laws of motion."
The laws of motion
The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.
It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.
Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.
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Two loudspeakers are located 2.65 m apart on an outdoor stage. A listener is 19.1 m from one and 20.1 m from the other. During the sound check, a signal generator drives the two speakers in phase with the same amplitude and frequency. The transmitted frequency is swept through the audible range (20 Hz–20 kHz). The speed of sound in the air is 343 m/s. What are the three lowest frequencies that give minimum signal (destructive interference) at the listener's location?
Answer:
171.5Hz,514.5Hz and 857.5Hz
Explanation:
We are given that
Distance between two loudspeaker,d=2.65 m
Distance of listener from one end=19.1 m
Distance of listener from other end=20.1 m
\(\Delta L=20.1-19.1=1\)m
Speed of sound,v=343m/s
For destructive interference
\(f_{min,n}=\frac{(n-0.5)v}{\Delta L}\)
Using the formula and substitute n=1
\(f_{min,1}=\frac{(1-0.5)\times 343}{1}=171.5Hz\)
For n=2
\(f_{min,2}=\frac{(2-0.5)\times 343}{1}=514.5Hz\)
For n=3
\(f_{min,3}=(3-0.5)\times 343=857.5Hz\)
Hence, the three lowest frequencies that give minimum signal (destructive interference) at the listener's location is given by
171.5Hz,514.5Hz and 857.5Hz
a dog lifts a 1.5 kg bone straight up through a distance of 0.2 m. How much work was done by the dog?
Answer:
see below
Explanation:
we have ,
mass = 1.5kg height = 0.2 mWe know,
Work = mgh
Work = 1.5kg * 10m/s² * 0.2m
Work= 3J
and we are done!
Choose one human-made object in motion on Earth. Draw a picture of the object and add arrows showing the forces acting on the object while it is in motion. Be sure to show the overall direction in which the object is moving by scaling your arrows.
Be sure to label the forces.
You need to include at least 2 forces for full credit.
The arrow pointing downward is gravitational force, F(g), The left arrow is the applied force, F(t), The right arrow is frictional force, F(f) and the arrow pointing upward is the net force, F(n).
What is a force?A force is a push or pull upon an object resulting from the object's interaction with another object. Forces can cause an object to accelerate or change its direction of motion.
Forces can be described by their magnitude and direction. In physics, forces can be caused by many interactions, including gravity, electromagnetic forces, and the strong and weak nuclear forces.
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If a vehicle is traveling at constant velocity and then comes to a sudden stop, has it undergone negative acceleration or positive acceleration? Explain your answer
Answer:
Negative acceleration
Explanation:
Let us assume a vehicle is moving with a constant velocity u and then it comes to a sudden stop.
The initial velocity of the vehicle is u and finally it comes to rest, it means final velocity is 0.
As we know that,
Acceleration is equal to change in velocity divided by time taken.
\(a=\dfrac{v-u}{t}\\\\\text{Put v=0}\\\\a=\dfrac{-u}{t}\)
We can see that the value of acceleration is negative. Hence, it leads to negative acceleration.
In 1994, a pumpkin with a mass of 449 kg was grown in Canada. Suppose you want to push a pumpkin with this mass along a smooth, horizontal ramp. You give the pumpkin a good push, only to find yourself sliding backwards at a speed of 4.0 m/s. How far will the pumpkin slide 3.0 s after the push? Assume your mass to be 60.0 kg.
After pushing the pumpkin hard, you find yourself reversing direction at a speed of 4.0 m/s. 3.0 seconds after being pushed, the pumpkin will slide 12 m. Assume you weigh 60.0 kg.
We can use the conservation of momentum to solve this problem. After the push, the momentum of the system is given by:
p = (449 kg + 60 kg) * v
where v is the speed of the pumpkin and you after the push. Since you end up sliding backward at 4.0 m/s, we have:
v = -4.0 m/s
Substituting this into the expression for momentum, we find:
p = (449 kg + 60 kg) * (-4.0 m/s) = -2036 kg·m/s
The negative sign indicates that the momentum of the system is in the opposite direction of your motion.
During the sliding motion, the net force on the system is given by:
Fnet = (449 kg + 60 kg) * g * sin(θ)
where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of the ramp. Since the ramp is smooth and horizontal, θ = 0 and Fnet = 0. Therefore, there is no net force to change the momentum of the system.
Using the equation for motion with constant acceleration, we can find the distance the pumpkin slides in 3.0 seconds:
x = x0 + v0t + (1/2)at²
Since the initial speed of the pumpkin is -4.0 m/s and there is no net force acting on it, its speed remains constant during the slide. Therefore, v0 = -4.0 m/s and a = 0. Substituting these values, we find:
x = x0 + v0t = (-4.0 m/s) * (3.0 s) = -12 m
The negative sign indicates that the pumpkin slides in the opposite direction to your motion. Therefore, the pumpkin slides 12 meters backward (i.e., towards you) in 3.0 seconds after the push.
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Exercise II: A ball (C) of small dimensions of mass m=2kg is launched from A without initial speed, the force of friction exerted on (C) between A and B is f-IN. Take g=10m/s. (C) 0-30° B a) Applying Newton's second law between A and B, determine the nature of motion and the value of AB such that V 3m/s. b) Between B and C the force of friction fexerted on (C) is supposed to be constant. Determine its value such that Vc=2m/s and BC-2.5m. GOODWORK C
A) The nature of motion is decelerating motion and the value of AB = 5m. B) Between B and C the force of friction fexerted on 2.5m and the force of friction exerted on (C) between B and C is 17.6N
(a) Applying Newton's second law between A and B, determine the nature of motion and the value of AB such that V=3m/s.
From A to B, the ball experiences a force of friction and the gravitational force acting downwards. The force of friction opposes the motion of the ball, while the gravitational force acts in the direction of motion.
Since the ball is launched from A without any initial speed, it will initially move downwards due to the force of gravity until it reaches its lowest point at B. To determine the value of AB such that V=3m/s, we can use the conservation of energy principle.
The potential energy at A is zero, and the kinetic energy at B is (1/2)mv^2, where m is the mass of the ball and v is the velocity at B. The work done by the force of friction is fABd, where d is the distance from A to B. The work done by the gravitational force is -mg(h/2), where h is the height difference between A and B. Thus, we have (1/2)mv^2 = fABd - mg(h/2).
Since the ball is moving upwards at B, the net force acting on it is in the upward direction. Using Newton's second law, we have fAB - mg = ma, where a is the acceleration of the ball. Since the ball is moving upwards, a = -g. Solving these equations simultaneously, we obtain AB = 5m and the nature of motion is a decelerating motion.
(b) Between B and C, the force of friction f exerted on (C) is supposed to be constant. Determine its value such that Vc=2m/s and BC=2.5m.
Between B and C, the ball moves upwards due to the force of friction and the gravitational force acting downwards. To determine the force of friction f, we can use the conservation of energy principle again. The potential energy at B is mgh/2, where h is the height difference between A and B.
The kinetic energy at C is (1/2)mv^2, where v is the velocity at C. The work done by the force of friction is fBCd, where d is the distance from B to C. Thus, we have (1/2)mv^2 = fBCd + mgh/2. Using Newton's second law, we have fBC - mg = ma, where a is the acceleration of the ball. Since the ball is moving upwards, a = -g. Solving these equations simultaneously and substituting the given values, we obtain f = 17.6N. Therefore, the force of friction exerted on (C) between B and C is 17.6N.
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Bryan rolls a 2kg ball across a rough, grassy field. The field slows the ball with an acceleration of -0.5 m/s^2.
a. Draw the FBD
b. Determine the frictional force the field acts on the ball.
The drawing of free body diagram is attached in answer.
The frictional force the field acts on the ball is 1 newton.
What is acceleration?
Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the ball: m = 2 kg.
Acceleration of the ball during slow down: a = -0.5 m/s².
We have to find: the frictional force the field acts on the ball: f =?
In this case, the frictional force the field acts on the ball: f = mass × acceleration = 2 kg × 0.5 m/s² = 1 newton.
Hence, the frictional force the field acts on the ball is 1 newton.
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If an object can make 10 revolutions in two minutes what’s it’s period
Answer:
12\(s^{-1}\)
Explanation:
Period= how long for each revolution
Since we have 10 revolutions in 120 seconds.
120/10=12s
Many of the world's deserts are located at latitudes slightly below 30° N. This includes the region marked with an X on the map. Which of the following statements best explains this? A. The air descending from the upper atmosphere contains very little moisture. B. Air near the equator moves quickly as Earth rotates, so it cannot carry much moisture. C. Moist air near the equator tends to flow away from land and toward the oceans. D. Most of the moisture is removed from the air before it rises into the upper atmosphere.
The statement that best explains why many of the world's deserts are located at latitudes slightly below 30° N is
A. The air descending from the upper atmosphere contains very little moisture.What are deserts?Deserts typically occur in regions where there is little precipitation, and the air is often very dry. One of the primary factors that contributes to the dryness of desert regions is the presence of high-pressure systems in the upper atmosphere. As air rises and cools, it loses moisture through precipitation, which creates regions of low pressure. Conversely, as air sinks and warms, it becomes more dry and creates regions of high pressure.
At latitudes around 30° N, there are often high-pressure systems in the upper atmosphere that cause dry, descending air. This results in relatively arid conditions that are conducive to the formation of deserts. Therefore, option A is the best explanation for why many of the world's deserts are located at latitudes slightly below 30° N.
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1. According to its computer, a rocket launched
traveled 1200 m, had an average speed of 100.0
m/s. How-long did the trip take?
Answer:
I think it's = 12 seconds
Explanation:
the formula for speed is:
speed=\(\frac{distance}{time}\) SO, time is equal to:
time=\(\frac{distance}{speed}\)
(sub the numbers in the formula)
distance=1200m, speed=100m/s
time=\(\frac{1200}{100}\)
=12 seconds
Katie rolls a toy car off the end of a table. Which path will the car follow when it leaves the table? A. B. C. D.
Answer:
parabolic path
Explanation:
As the cart reaches the end of the table with a horizontally directed velocity (only horizontal component), the cart will follow a parabolic path given by the combined action of:
(1) kinematic equation for motion under constant velocity in the horizontal direction (linear expression in terms of time), and
(2) kinematic equation for motion under constant acceleration (that of gravity) in the vertical direction (quadratic expression in terms of time)
Answer:
C.
Explanation:
Due to gravity and air resistance— its gonna make a curved path
A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad
Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.
1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.
This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.
2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.
The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.
Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.
However, the thrust force continues to be the dominant force propelling the rocket upward.
It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.
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The rabbit flea Spilopsyllus has a mass of 0.45 mg. It can jump vertically to aheight of about 3.5 cm. Biologists have hypothesized that the energy for the jump is most likely derived from the elastic potential energy stored in the resilin pads ofthe two rear legs of the flea. Each pad is estimated to have a volume of about and its strain typically reaches a value of 100%. The elastic modulus of resilience is about . Is the hypothesis plausible
Answer:
Therefore The hypothesis is not plausible Because
\(P.E \geq P.E_e\)
\(P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J\)
Explanation:
From the question we are told that:
Mass \(M=0.45mg\)
Jump height \(h=3.5cm \approx 0.03m\)
Percentage strain \(\mu =100\%\)
Generally the equation for potential energy is mathematically given by
\(P.E=mgh\)
\(P.E=0.45*10^{-3}*9.8*0.03\)
\(P.E=12.435*10^{-5}J\)
Generally the equation for Elastic potential energy is mathematically given by
\(P.E_e=0.5*stress*strain *volume\)
\(P.E_e=0.5*1*2*10^6*1*1.4*10^{-4*(10^-3)^3}\)
\(P.E_e=1.4*10^{-7}J\)
The hypothesis is only plausible at conditions where
\(P.E\leq P.E_e\)
Therefore The hypothesis is not plausible Because
\(P.E \geq P.E_e\)
\(P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J\)
What is the cost per month to operate an A.C. 10hours per day whose power is 3kW and 1KWH cost 79francs
The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.
What is Power?Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.
Cost of operation for 10 hours a day;
Daily consumption = 3kW x 10 hours
Daily Consumption = 30kW
Since 1kWH = 79 francs;
Daily consumption amount = 30 x 79 francs
Daily consumption amount = 2,370 francs
Therefore, the monthly consumption (using 30days) will be;
2,370 francs x 30 = 71,100 francs
In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.
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Which process describes the warm ocean that transfers heat to the air above it?
O conduction
O convection
O reflection
O radiation
Answer:
convection is the answer
The process that describes the warm ocean that transfers heat to the air above it is known as Convection. Thus, the correct option for this question is B.
What are some characteristics of heat?Some characteristics of heat are as follows:
It has no mass, shape, color, odor, volume, and weight.It is one of the invisible forms of energy.It stimulates the presence of warmth.It gets remarkably transferred from one body to another.This form of energy has the capacity to flow in each and every direction.The process of convection transfers heat with the help of the migration of a fluid (liquid or gas) between areas of different temperatures. It is an approach that signifies the transfer of heat between two bodies by involving currents of moving gas or fluid.
Therefore, convection is the process that describes the warm ocean that transfers heat to the air above it. Thus, the correct option for this question is B.
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For a given motor vehicle, the maximum achievable deceleration from braking is approximately 8 m/sec2 on dry concrete. On wet asphalt, it is approximately 2.5 m/sec2. Given that 1 mph corresponds to 0.447 m/sec, find the total distance that a car travels in meters on dry concrete after the brakes are applied until it comes to a complete stop if the initial velocity is 67 mph (30 m/sec) or if the initial braking velocity is 56 mph (25 m/sec).
Answer:
\(1.875\ \text{m}\)
\(1.5625\ \text{m}\)
Explanation:
\(a\) = Acceleration on dry concrete = \(-8\ \text{m/s}^2\)
\(v\) = Final velocity = 0
\(u\) = Initial velocity
\(s\) = Displacement
For \(u=30\ \text{m/s}\)
\(v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-30}{2\times -8}\\\Rightarrow s=1.875\ \text{m}\)
The distance traveled to come to a stop is \(1.875\ \text{m}\)
For \(u=25\ \text{m/s}\)
\(s=\dfrac{0-25}{2\times -8}\\\Rightarrow s=1.5625\ \text{m}\)
The distance traveled to come to a stop is \(1.5625\ \text{m}\).
outline the reason for gay luccas law of volume
Gay-Lussac's law of volume states that for a fixed mass of an ideal gas kept at a fixed pressure, the volume and temperature are directly proportional.
What is Gay-Lussac's law about?This means that if the temperature of a gas is increased, its volume will also increase, and vice versa.
The reason for Gay-Lussac's law of volume is that the average kinetic energy of the gas molecules is directly proportional to the temperature. As the temperature increases, the molecules move faster and collide with the walls of the container more often. This causes the pressure to increase. However, if the pressure is kept constant, the increase in pressure will cause the volume to increase.
Gay-Lussac's law of volume can be expressed mathematically as follows:
V₁ / T₁ = V₂ / T₂
where:
V₁ = initial volume of the gas
T₁ = initial temperature of the gas
V₂ = final volume of the gas
T₂ = final temperature of the gas
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Gay-Lussac's Law of Volume provides a useful relationship between the volumes of reactant and product gases, allowing for predictions and calculations in chemical reactions involving gaseous substances.
Understanding Gay-Lussac's Law of VolumeGay-Lussac's Law of Volume, also known as the Law of Combining Volumes of Gases, states that "the volumes of gases involved in a chemical reaction at constant temperature and pressure are in the ratio of small whole numbers."
Reason for Gay-Lussac's Law of Volume
1. Avogadro's Law: According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of particles (atoms, molecules, or ions). This law established the concept of the mole, which is a unit of measurement representing a fixed number of particles. Since the number of particles is the same, the volume occupied by these particles should also be the same.
2. Stoichiometry: Chemical reactions involve the rearrangement of atoms and molecules to form new substances. The coefficients in a balanced chemical equation represent the relative amounts of reactants and products. In the gaseous state, these coefficients can be directly related to the volumes of the gases involved. For example, if the balanced equation shows that two volumes of gas A react with three volumes of gas B to form four volumes of gas C, it implies that the gases react in simple volume ratios.
3. Gas Behavior: Gases follow certain ideal gas laws, such as Boyle's Law (pressure-volume relationship), Charles's Law (temperature-volume relationship), and Gay-Lussac's Law (pressure-temperature relationship). These laws describe how the physical properties of gases change under different conditions. Gay-Lussac's Law of Volume specifically relates the volumes of gases involved in a chemical reaction and shows that the volumes are proportional to each other.
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the filament of an electric lamp, which draws a current of 0.5 a is used for 2 hours. calculate the amount of charge flowing through the circuit
Answer:
I = 0.25 AND T= 4 HOURS, Q = ??
multiply both min and sec , 240 and 60
we get 1400 sec
the formula for current is I = Q/T
substitute the given data in the formula and simplify it
so , Q = 3600C
An open vertical tube has water in it. a tuning fork vibrates over its mouth. as the water level is lowered in the tube, a resonance is heard when the water level is 180 cm below the top of the tube, and again after the water level is 220 cm below the top of the tube a resonance is heard. what is the frequency of the tuning fork? the speed of sound in air is 343 m/s. answer in units
Answer:
\(428.75\ \text{Hz}\)
Explanation:
\(\Delta y\) = Change in water level = \(220-180=40\ \text{cm}\)
\(\lambda\) = Wavelength
\(v\) = Speed of sound = 343 m/s
Between the points of resonance there exists \(\dfrac{1}{2}\lambda\)
\(\dfrac{1}{2}\lambda=\Delta y\\\Rightarrow \lambda=2\Delta y\\\Rightarrow \lambda=2\times 40\\\Rightarrow \lambda=80\ \text{cm}\)
Wavelength is given by
\(f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{343}{0.8}\\\Rightarrow f=428.75\ \text{Hz}\)
The frequency of the tuning fork is \(428.75\ \text{Hz}\).
What do we mean by internal and external structure of a substance in solid state?
The external structure of a solid refers to the overall structure of the solid due to the arrangement of its particles..
The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.
What is a solid?A solid is a substance which has a definite shape and volume.
Solids are one of the three states of matter.
The particles in a solid are arrange in regular repeating patterns due to the strong intermolecular forces of attraction between the particles in the solid.
The external structure of a solid refers to the overall structure of the solid due to the arrangement of its particles.
The external structure of a solid may be a crystal or amorphous in shape.
The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.
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The radius of a circle of area A and circumference C is doubled. find the new circumference of the circle in terms of C.
If the radius of a circle of area A and circumference C is doubled, the new circumference of the circle, in terms of C, will be equal to 2C.
The area (A) of a circle is given by:
\( A = \pi r^{2} \) (1)
And a circumference (C) is:
\( C = 2\pi r \) (2)
Where:
r: is the radius
If the radius of a circle and circumference is doubled, the new circumference of the circle is:
\( C_{2} = 2 (2 \pi r) = 2C \)
Therefore, the new circumference of the circle in terms of C is equal to 2C.
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As shown in the figure, a given force is applied to a rod in several different ways. In which case is the torque about the pivot P due to this force the smallest?
Answer:
OPTION 5
Explanation:
As the force has no moment arm, it creates no torque about point P.
The option with the smallets torque is about the pivot P is option 5.
Torque about a pointThe about a given point due to the applied force acting at a perpendicular distance is determined from the product of the applied force and the perpendicular distance.
τ = rFsinθ
where;
r is the perpendicular distanceF is the applied forceθ is the angle of the inclinationFor option 5, the angle of the applied force = 0
τ = rFsin(0)
τ = 0
Thus, the option with the smallets torque is about the pivot P is option 5.
Learn more about torque here: https://brainly.com/question/14839816
Ist Law: a object continues in a state of
rest or motion unless an external force
applied to it
This image shows an example of
the first law because:
Answer:
Explanation:
This image is the example of Newton's first law of motion because:
As per Newton's first law, football will remain in the state of rest until a player applies an external force by kicking the ball.
And the ball will keep on moving until unless the net of a goal post exerts the external force to stop the ball.
27. The electric field around a positive charge is shown in the diagram. Describe the nature of these lines. Please use 2 content related sentences
Answer:
Once we place a positive test at a point close to the sphere, we find that an electrostatic force is applied to the outside of the sphere. Therefore, at any point around the sphere, the electric field vector is radially outward.
NEED HELP ASAP!!!!!
A car speeds up from 15 m/s to 30 m/s in 12 seconds. What is the acceleration of the car?
A. 1.25 m/s2
B. 0.8 m/s2
C. 1.50 m/s2
D. 1.75 m/s2
Answer:
A, 1.25m/s^2
Explanation:
use formula v=v0+at to solve for a
a= v-v0/t
Plug in givens
30-15/12 to get 15/12 = 1.25m/s^2