Which of the following are found in the nucleus?
A) electrons
B) neutrino
C) electron cloud
D) Protons

I agree with the application of such offenses where criminal responsibility is imposed on strict liability offenses because it is needed to protect public welfare, promote safety, and deter potential harm.

Strict liability offenses are those in which liability is imposed without requiring proof of intent or guilty mind. These offenses focus on the act itself rather than the mental state of the offender. The rationale behind strict liability offenses is often rooted in the need to protect public welfare, promote safety, and deter potential harm.

An argument in favor of strict liability offenses is that they ensure accountability for certain actions that pose a significant risk to society, even in the absence of intent or mens rea. By placing the burden on individuals to adhere to certain standards or regulations, strict liability offenses can help prevent accidents, protect public health, and maintain order.

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Explanation:

a) I = V / R

1.70 = 115 / R

R = 115 / 1.70

R = 67.647

R = 67.65 ohms

Therefore, equivalent resistance is 67.65 ohms

b) Equivalent resistance of circuit from above sum is 67.65 ohms

Given resistance of each bulb is 1.50 ohms

Number bulbs = Equivalent resistance / Resistance of each bulb

= 67.65 / 1.50

= 45

h = 7300 mD = 2.2 mmn = 1.35λ = 721 nm

We are to determine the expression, in terms of h, D, and n, for the minimum separation d two objects on the ground can have and still be distinguishable at the wavelength λ. The minimum separation d two objects on the ground can have and still be distinguishable at the wavelength λ is given by the formula;

d = nhD

Therefore, the expression in terms of h, D, and n for the minimum separation d two objects on the ground can have and still be distinguishable at the wavelength λ is

d = nhD = (1.35)(721 nm)(2.2 × 10⁻³ m) = 2.2413 mm

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The given average distance of the Moon from the Earth is 384,000 km and the sidereal period of the moon is 27.3 days. We need to find the average orbital speed of the moon.So, we can use the formula to calculate the average orbital speed of the Moon as follows:

Average orbital speed (V) = distance/time.

To get the distance covered by the moon in one orbit, we will multiply the distance of the Moon from the Earth by the circumference of the orbit:

Distance = 2 × π × r = 2 × π × 384000 = 2.41 × 10^6 km.

Therefore, the average orbital speed of the Moon is given by the formula:V = Distance / Time periodV = 2.41 × 10^6 km / 27.3 days.

We need to convert the time period from days to seconds:1 day = 24 hours1 hour = 60 minutes1 minute = 60 seconds1 day = 24 × 60 × 60 seconds1 day = 86400 seconds.

Therefore, the time period is:27.3 days = 27.3 × 86400 seconds27.3 days = 2.36 × 10^6 seconds.

Substituting this value in the formula we get:V = 2.41 × 10^6 km / 2.36 × 10^6 secondsV = 1.02 km/s.

Therefore, the average orbital speed of the moon is 1.02 km/s.

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Answer:

light bends away from the normal when it moves from air into water-refraction

Answer: C.) Light slows down when it moves from air into water.

Explanation: i hope this helps :)

Answer:

Below

Explanation:

To convert mm to m all you need to do is divide the value by 1,000

so : 3 / 1,000 = 0.003 meters

Hope this helped!

Answer:

Answering the following questions will help you to focus on the outcomes of these experiments:

1.How does the length to height ratio (the IMA) of trial 1 compare to trial 2?

= Trial 1 is 5.09, and Trial 2 is 3.25. Trial 1 is higher because the height of the trial is less than trial 2.

2.Why is the actual mechanical advantage less than the ideal mechanical advantage in each of the trials?

= It is because the machine's ideal mechanical advantage reflects the increase or decrease in force that would have occurred without friction. It is always greater than the actual mechanical advantage because all machines have to overcome friction.

3.If a machine was 100% efficient, how would the AMA compare to the IMA?

= In any real machine, some of the efforts are used to overcome friction. Thus, the resistance force ratio to the effort (AMA) is less than the (IMA).

A frictionless machine would have an efficiency of 100%.

If resultant force on the body is 0 the acceleration will also be 0.​

The term "acceleration" refers to the change in velocity with time. We must also recall that force is the product of mass and acceleration. If that is so, we can write; F = ma.

Now, we are told that the force on the body is zero so making the acceleration the subject of the formula; a = 0/mand a = 0.

Hence,  if resultant force on the body is 0 the acceleration will also be 0.​

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Hello! The angular size of the Moon as seen from Earth can be calculated using the diameter and average distance of the Moon's orbit.

The Moon has a diameter of 3,476 km and orbits Earth at an average distance of 384,400 km. To find the angular size, we can use the small-angle formula:

Angular size (in radians) = Diameter / Distance

Plugging in the values:

Angular size = 3,476 km / 384,400 km

Angular size ≈ 0.00904 radians

To convert radians to degrees, you can use the following formula:

Degrees = Radians × (180 / π)

So,

Angular size ≈ 0.00904 × (180 / π) ≈ 0.517°

The angular size of the Moon as seen from Earth is approximately 0.517 degrees. This value helps explain why the Moon appears to be roughly the same size as the Sun in the sky, even though the Sun is much larger in diameter. The Moon's smaller size and closer distance to Earth make its angular size appear similar to the Sun's angular size, allowing for solar eclipses to occur when the Moon passes in front of the Sun.

In summary, using the Moon's diameter of 3,476 km and its average orbit distance of 384,400 km, the angular size of the Moon as seen from Earth is approximately 0.517 degrees.

The angular size of the Moon as seen from Earth is approximately 0.0094 degrees.

The term "angular size" describes an object's size as expressed in degrees of arc when viewed from a specific angle. It is a measurement of an object's apparent size in the sky and is based on both the physical size of the item and how far away it is from the viewer.

For instance, although the Sun and the Moon both appear to be roughly the same size in the sky, the Sun is actually much bigger than the Moon. This is because the Sun is smaller in angular size than the Moon because it is considerably further away from us.

The angular size of the Moon as seen from Earth can be calculated using the formula:
Angular size = (diameter of the Moon / distance from Earth to Moon) x 57.3 degrees

Plugging in the values given, we get:
Angular size = (3476 km / 384,400 km) x 57.3 degrees
Angular size = 0.0094 degrees

Therefore, the angular size of the Moon as seen from Earth is approximately 0.0094 degrees.

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Answer:

-50.6 kJ

Explanation:

The work done (W) on an object is given by:

W = (Fcosθ) * S

where F is the force, S is the displacement and θ is the angle between the force and displacement.

i) During the first trip riding east, S₁ = 2.93 km = 2930 m, F₁ = 8.65 N.

The displacement is due east and the force is due west, hence θ₁ = 180°. Therefore:

W₁ = (F₁ * cosθ₁)S₁ = (8,65 * cos(180))2930 = -25.3 kJ

ii) i) During the second trip riding west, S₂ = 2.93 km = 2930 m, F₂ = 8.65 N.

The displacement is due west and the force is due east, hence θ₂ = 180°. Therefore:

W₂ = (F₂ * cosθ₂)S₂ = (8,65 * cos(180))2930 = -25.3 kJ

work done by the resistive force during the round trip is:

W = W₁ + W₂ = -25.3 kJ + (-25.3 kJ) = -50.6 kJ

One minute has 60 seconds, One hour has 60 minutes and one day has 24 hours. Thus, 80 x 60 x 24 = 86,400 seconds in a day.

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The runner's center of mass will be  0.40 meter raised during the jump.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Initial vertical speed of the Olympic  runner = 2.8 m/s

Acceleration due to gravity = 9.8 m/s²

Mass of the Olympic  runner = 65 kg

Hence, the runner's center of mass will be raised during the jump

=  (Initial vertical speed )² ÷ (2 ×  Acceleration due to gravity)

= 2.8²/(2 ×9.8) meter

= 0.40 meter.

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a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.

a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:

δθ = 1.22 * (λ / D)

Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.

Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:

D = 1.22 * (λ / δθ)

D = 1.22 * (0.21 m / 1 second of arc)

Calculating the result:

D ≈ 0.27 m

Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.

b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.

Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.

c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).

Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.

Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.

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We know the Sun is primarily made from hydrogen and helium on the basis of its spectrum. The option d is correct answer.

The spectrum of the sun is obtained by observing the light it emits. When sunlight passes through a prism or spectrometer, it is separated into a continuous spectrum by black absorption lines. These lines correspond to specific wavelengths of light absorbed by the elements in the solar wind.

By comparing these absorption lines with well-known ones of different elements, the researchers found that the main absorption lines in the solar spectrum are similar to those produced by hydrogen and helium. This indicates that these two elements are the main components of the solar wind.

Other evidence, such as the Sun's mass, brightness, age, and color, cannot provide direct information about its composition. While these conditions are important for understanding the properties and behavior of the sun, they do not specifically indicate the abundance of hydrogen and helium in its composition.

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The time that the rocket must fall before its engine starts is determined by calculating the time it takes for the rocket to fall to an altitude that is 1 km below the airliner's altitude (11 km).

Explanation:Initially, the rocket is dropped from an altitude of 12 km above sea level. There is no initial velocity because the airliner is flying at a constant speed in a straight line.The acceleration due to gravity is 9.8 m/s² and is directed vertically downwards. Hence, the acceleration in the horizontal direction is zero and the acceleration in the vertical direction is given by a = 9.8 m/s².The velocity of the rocket after it has fallen for time t is given by:v = u + atwhereu is the initial velocity, which is zero, and a is the acceleration due to gravity, which is directed vertically downwards. Substituting the values,v = 0 + (9.8 m/s²)t = 9.8t

The displacement of the rocket after it has fallen for time t is given by:s = ut + 1/2 at²whereu is the initial velocity, which is zero, and a is the acceleration due to gravity, which is directed vertically downwards. Substituting the values,s = 0 + 1/2 (9.8 m/s²)t² = 4.9t²The rocket should be at least 1 km in front of the airliner when it climbs through the airliner's altitude, which is 12 km. Therefore, the rocket must fall to an altitude of 11 km before its engine starts. Substituting s = 11 km = 11000 m in the equation for displacement,11000 m = 4.9t²Rearranging to find t,t = sqrt(11000/4.9) = 48.9 sHence, the minimum time that the rocket must fall before its engine starts is 48.9 s.

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To determine the minimum fall time before the rocket's engine starts, we use kinematic equations for the falling and accelerating phases. The rocket takes approximately 15.6 seconds to fall to the airliner's altitude and another 28.7 seconds to reach it again after accelerating. Thus, the minimum fall time is approximately 44.3 seconds.

To determine the minimum time that the rocket must fall before its engine starts, we can break down the motion of the rocket into two phases: the falling phase and the accelerating phase. In the falling phase, the rocket experiences only gravity, and in the accelerating phase, the rocket experiences both gravity and thrust. We'll use kinematic equations to solve for the time it takes for the rocket to reach the airliner's altitude.

In the falling phase, the rocket falls for a time t1 until it reaches the airliner's altitude of 12.0 km. We can use the equation d = (1/2)gt2 to find the time it takes to fall that distance. Since the rocket starts from rest, the equation simplifies to 12.0 km = (1/2)(9.8 m/s2)t12. Solving for t1, we find that it takes approximately 15.6 seconds for the rocket to fall to the airliner's altitude.

In the accelerating phase, the rocket's acceleration can be represented as a vector quantity with magnitude 3.00g and an angle of 30.0° above the horizontal. We can use the equation d = v0t + (1/2)at2, where d represents the horizontal displacement of the rocket, v0 is the initial horizontal velocity of the rocket, a is the horizontal acceleration of the rocket, and t represents the time it takes for the rocket to reach the airliner's altitude again. We know that the rocket must be at least 1.00 km in front of the airliner, so d = 1.00 km = 1000 m. We also know that the initial horizontal velocity of the rocket is the same as the airliner's velocity, so v0 = 850 km/h = 236.11 m/s. Setting a = 3.00g cos(30.0°), we can solve for t. Plugging in the known values, we find that it takes approximately 28.7 seconds for the rocket to reach the airliner's altitude again.

Therefore, the minimum time that the rocket must fall before its engine starts is the sum of the falling phase time and the accelerating phase time, which is approximately t1 + t = 15.6 s + 28.7 s = 44.3 seconds.

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Answer: f= 100n

Explanation: So you will have to multiply 20kg to 5m/s2 and that how you will get F= 100N

Answer:

current = 0.364 A

Explanation:

Resistance = Voltage / Current

33 ohms = 12 Volt / current

current = 12 / 33

current = 0.364 A

One and a half miles of distance  is required for a train to stop when traveling 50 miles per hour.

Rate of change in position, or speed, is equal to distance traveled divided by time. To solve for time, divide the distance traveled by the rate.

Rearranging the formula,

Speed = distance / time.

Distance = speed × time.

Time = distance / speed.

Hence,

Distance = Speed × Time

⇒ Distance = 50 × 60 / 2000

⇒ Distance = 1.5 miles

⇒ Thus, the distance which is required to stop a train is 1.5 miles, which is, One and a half miles.

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Answer:

Sorry I need points \( \boxed{}\)

Answer:

Your answer would be D.

Answer:

i dont know this one

Explanation:

sorry i wish i could help but if u look closley on that qyestion you will understand it mor

I'm not sure what you were trying to put here

The initial acceleration of trolley Y to the left is 4 m/s².

The initial speed and final speed of both trolley X and trolley Y is calculated by applying the principle of conservation of linear momentum as follows;

initial momentum of trolley Y = final momentum of trolley X

m₁u₁ = m₂u₂

where;

let the mass of trolley Y = m,

then the mass of trolley X = 2m

mu₁ = 2m(at)

where;

mu₁ = 2m(2t)

u₁ = 4t

Assuming, both trolley moved at time, t, then the initial acceleration of the trolley Y is 4 m/s².

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(a) To determine the total pressure in the flask, we need to consider the partial pressures of each gas present and add them together.

Using the ideal gas law, we can calculate the partial pressure of each gas:

PV = nRT

For Ne gas:

P₁V₁ = n₁RT

P₁ = (n₁/V₁)RT

For SF6 gas:

P₂V₂ = n₂RT

P₂ = (n₂/V₂)RT

To find the total pressure, we add the partial pressures:

P_total = P₁ + P₂

(b) The mole fraction (χ) of each gas can be calculated using the formula:

χ = moles of gas / total moles of gas

To find the moles of each gas, we use the ideal gas law rearranged:

n = PV / RT

Now, let's calculate the values.

Given:

Volume of Ne gas (V₁) = 435 mL = 0.435 L

Temperature of Ne gas (T₁) = 21 °C = 294 K

Pressure of Ne gas (P₁) = 1.09 atm

Volume of SF6 gas (V₂) = 456 mL = 0.456 L

Temperature of SF6 gas (T₂) = 25 °C = 298 K

Pressure of SF6 gas (P₂) = 0.89 atm

Volume of flask (V_total) = 325 mL = 0.325 L

Temperature of flask (T_total) = 30.2 °C = 303.2 K

Gas constant (R) = 0.0821 L·atm/(K·mol)

(a) To calculate the total pressure:

P₁ = (n₁/V₁)RT₁

P₁ = (PV₁/RT₁)

P₂ = (n₂/V₂)RT₂

P₂ = (PV₂/RT₂)

P_total = P₁ + P₂

(b) To calculate the mole fraction:

n₁ = P₁V_total / RT_total

n₂ = P₂V_total / RT_total

χ₁ = n₁ / (n₁ + n₂)

χ₂ = n₂ / (n₁ + n₂)

By plugging in the given values and performing the calculations, we can find the total pressure in the flask and the mole fraction of each gas.

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The potential energy of the 2-kg mass relative to the ground is approximately 80 J.

A sort of energy known as potential energy is one that an object holds as a result of its location or circumstance. It is the energy that is conserved inside a system and has the capacity to be transformed into different types of energy, such as thermal or kinetic energy. Affected by variables like height, distance, and forces operating on it, an object's potential energy relies on where it is in relation to other objects or reference points.

The correct answer is a) 80 J.

The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.8 \(m/s^2\)), and h is the height of the object above a reference level (in this case, the ground).

Using the given values, we have:

PE = (2 kg)(\(9.8 m/s^2\))(4 m)
PE = 78.4 J

Therefore, the potential energy of the 2-kg mass relative to the ground is approximately 80 J.

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Answer:

a thing or things belonging to someone; possessions collectively.

Explanation:

Answer:

The sum of momenta of each object before and after collision is equal . Thus when they collide , their momentum will change but its sum will be sane as the sum of the momentum before collision

Breaking the sound barrier, which is the transition from subsonic to supersonic speed, presented several challenges and obstacles for scientists and engineers. Some of the obstacles faced were:

1. Aerodynamic forces: As an aircraft approaches the speed of sound, it encounters a range of aerodynamic forces that can cause instability and vibrations. These forces include shock waves, which can create areas of high pressure and drag on the aircraft, making it difficult to maintain control.

2. Engine power: Breaking the sound barrier requires a significant amount of engine power to overcome the drag and other aerodynamic forces. Developing engines that were powerful enough to achieve supersonic speeds was a major challenge for scientists and engineers.

3. Structural integrity: The shock waves and other forces encountered during supersonic flight can place significant stress on an aircraft's structure, potentially leading to failure or damage. Designing and building aircraft that could withstand these forces was a major challenge.

4. Instrumentation: To safely break the sound barrier, pilots need accurate and reliable instrumentation to monitor the aircraft's speed, altitude, and other critical parameters.

Developing instrumentation that could function reliably at supersonic speeds was another obstacle that scientists and engineers had to overcome.

In summary, breaking the sound barrier presented several challenges and obstacles, including aerodynamic forces, engine power, structural integrity, and instrumentation. Overcoming these obstacles required significant advances in technology and engineering.

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