Answer:
c. hope this helped
Explanation:
what would you find if you took apart a grain of salt
PLZ NEED ANS ASAP research on the principle behind how these huge ships are able to float on water. Does salt or fresh water make a difference? I WILL GIVE BRAINLIEST
Answer:
Since the density of salt water is higher than that of fresh water.
Explanation:
Less salt water will be displaces and the ship will float higher.
what is the minimum coefficient of friction between the tires and the road that the car could have and still make the turn?
The minimum coefficient of friction between the tires and the road that the car could have and still make the turn is 0.7 for dry roads and 0.4 for wet roads.
The value of minimum coefficient of friction is usually between 0 and 1 but can be greater than one. A value of zero means there is no friction between the objects such is possible with a lubricant material . All objects, should have friction between them when they come in contact with each other.
The coefficient of friction is as low as 0.05 between dry sliding surfaces will be achieved when the mechanical interconnections are removed. This outcome has been attained based on a theoretical model of an ideal surface for low friction.
The coefficient of friction having value 1 is a perfect positive correlation. A coefficient of correlation zero means there is no linear relationship. Correlation coefficients are used in science to assess the degree of association between two variables, factors, or data sets.
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five properties of light
Answer:
Light is electromagnetic radiation that has properties of waves. The electromagnetic spectrum can be divided into several bands based on the wavelength. As we have discussed before, visible light represents a narrow group of wavelengths between about 380 nm and 730 nm.
OR
The primary properties of visible light are intensity, propagation-direction, frequency or wavelength spectrum and polarization, while its speed in a vacuum, 299 792 458 m/s, is one of the fundamental constants of nature.
What does the area of an acceleration time graph represent?
The area under the acceleration time graph represents change in velocity
The graph is plotted with acceleration on the vertical axis and time on the horizontal axis. The area under such graph represents change in velocity
The area of an acceleration- time graph represents the change in velocity. The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The formula for acceleration is;
\(\rm a = \frac{v-u}{t}\)
u is the initial speed
v is the final speed
t is the time interval
a is the acceleration of a ball
Hence the area of an acceleration- time graph represents the change in velocity.
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if the depth of the ocean at a particualr place is 1817.5m how long would it take a sonar siglnal to travel from a ship to the ocean bottom and back again
If the depth of the ocean at a particular place is 1817.5m, the time it would take a sonar signal to travel from a ship to the ocean bottom and back again would depend on the speed of sound in seawater.
The speed of sound in seawater at a temperature of 15°C (59°F) is around 1,530 meters per second. Therefore, to find the time it would take for the sonar signal to travel from the ship to the ocean bottom and back again, we can use the formula: Time = (2 x Depth) / Speed of Sound.
As we know that the depth of the ocean at a particular place is 1817.5 meters. Therefore, we can find out the time it would take for the sonar signal to travel from the ship to the ocean bottom and back again by substituting these values into the formula:
Time = (2 x Depth) / Speed of Sound Time = (2 x 1817.5) / 1530Time = 2.38 seconds.
Therefore, it would take approximately 2.38 seconds for a sonar signal to travel from a ship to the ocean bottom and back again at that particular location in the ocean. It's important to note that this is just an estimate and the actual time may vary depending on factors such as the temperature, pressure, and salinity of the seawater.
The time it would take for a sonar signal to travel from a ship to the ocean bottom and back again would depend on the depth of the ocean and the speed of sound in seawater. Using the formula Time = (2 x Depth) / Speed of Sound, we can estimate the time it would take for the sonar signal to travel based on these factors. In this case, the depth of the ocean was 1817.5 meters and the speed of sound in seawater was 1530 meters per second, so the estimated time it would take for the sonar signal to travel was 2.38 seconds.
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Use both the washer method and the shell method to find the volume of the solid that is generated when the region in the first quadrant bounded by y=x", y= 4, and x = 0 is revolved about the line y= -6. Set up the integral that gives the volume of the solid as a single integral if possible using the disk/washer method. Select the correct choice below and fill in any answer boxes within your choice. (Type exact answers.) A. dx ON [O« OB. Say
To find the volume of the solid generated by revolving the region in the first quadrant bounded by y = x², y = 4, and x = 0 about the line y = -6, we can use both the washer method and the shell method.
First, let's consider the washer method:
The region bounded by y = x², y = 4, and x = 0 can be visualized as a parabolic shape below the line y = 4. When revolved around y = -6, it forms a solid with a hole in the center.
To calculate the volume using the washer method, we integrate the area of the cross-sections of the solid.
At a given x-value, the radius of the cross-section is the distance between the line y = -6 and the curve y = x². This can be expressed as (x² + 6).
The differential volume element can be represented as dV = π [(x² + 6)² - (-6)²] dx.
Now, we can set up the integral to find the volume using the washer method:
V = ∫[0 to b] π [(x² + 6)² - (-6)²] dx
Next, let's consider the shell method:
Using the shell method, we consider cylindrical shells that are formed by revolving a vertical strip of the region about the line y = -6.
The height of each shell is given by the difference between the upper and lower functions, which is 4 - x².
The circumference of each shell is given by 2π times the distance from the line x = 0 to the curve y = x², which is x.
The differential volume element can be represented as dV = 2π x (4 - x²) dx.
Now, we can set up the integral to find the volume using the shell method:
V = ∫[0 to b] 2π x (4 - x²) dx
Note: The value of b represents the rightmost x-coordinate where the region bounded by y = x², y = 4, and x = 0 ends.
So, the correct choice is A. dx on [0, b].
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HELP ASAP!!!An object with a mass of 7.5 kg accelerates 8.8 m/s2 when a force is applied. What is the amount of force being applied?
Answer:
The force is 66 N
Explanation:
Newton's Second Law states the force is the product of mass times acceleration: F = ma.
Mass = 7.5 kg
Acceleration = 8.8 m/s^2
Force = (7.5kg)*(8.8m/s^2)
Force = 66 kg*m/s^2
1 kg*m/s^2 is 1 Newton (N)
The force is 66 N
The position of a particle along a coordinate axis at time t (in seconds) is given by s(t)=−3t 2
−4t+1 (in meters). Find the function that describes its acceleration at time t. Provide your answer below: a(t)=m/s 2
Answer:
The function that describes the acceleration of the particle at time t is:
a(t) = -6 m/s^2.
Explanation:
To find the function that describes the acceleration of the particle at time t, we need to take the second derivative of the position function s(t).
Given:
s(t) = -3t^2 - 4t + 1
Taking the derivative of s(t) with respect to t will give us the velocity function v(t):
v(t) = d/dt [-3t^2 - 4t + 1]
= -6t - 4
Now, we can take the derivative of v(t) with respect to t to find the acceleration function a(t):
a(t) = d/dt [-6t - 4]
= -6
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what is a state of well being that is achieved through a combination of good die regular phisical exercises and other partices that promotes good health
The correct answer is physical fitness
What is a state of physical well-being?
The ability to maintain a healthy quality of life that allows us to get the most out of our everyday activities without undue weariness or physical stress is referred to as physical wellness. It entails taking care of our bodies and acknowledging that our everyday routines and behaviours have a substantial impact on our general health, well-being, and quality of life.
This section contains further information about:
keeping that body moving - benefits of regular mobility in your work or study periods
finding your 30 - recommendations for regular exercise while isolated eating well getting a good night's sleep maintaining routine health check-ups
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A body weighing 10 kg falls from a height of 20 m. Calculate the velocity and kinetic energy of the body when falling to the ground
Answer:
v = 19.8 m/s
KE = 1960.2 J
Explanation:
We can calculate the velocity of the body by using the formula:
\(v=\sqrt{2gh}\) since we are given the height, and we know that g = 9.8 m/s².Plug the known values into the equation.
\(v=\sqrt{2\cdot 9.8\cdot 20}\) \(v=\sqrt{392}\) \(\displaystyle v=19.8 \ \frac{m}{s}\)Now we can use the formula for kinetic energy to calculate the kinetic energy of the body:
\(\displaystyle KE = \frac{1}{2}mv^2\)Plug in 19.8 m/s for v and 10 kg for m.
\(\displaystyle KE =\frac{1}{2} (10)(19.8)^2\) \(\displaystyle KE=(5)(392.04)\) \(\displaystyle KE = 1960.2 \ J\)The kinetic energy of the body when falling to the ground is 1960.2 Joules.
An airplane is located at position (3, 4, 5) at noon and traveling with velocity 400i + 500j − k km/h. (Assume that the plane is flying over flat ground and that k points straight up.) (a) The pilot spots an airport at position (23, 29, 0). Will the plane pass directly over the airport? If yes, at what time and how high above the airport will the plane be when it passes?
(b) A second airport is at position (42,46,0). What is the closest distance to the second airport the plane will fly by? At what time does this happen?
(a) Yes, the plane will pass directly over the first airport at 0.05 hours (or 3 minutes) and be 0.05 km (or 50 meters) above it.
(b) The closest distance to the second airport the plane will fly by occurs at approximately 0.0988 hours.
To determine if the airplane will pass directly over the first airport and at what time and height it will pass, we need to analyze its position and velocity.
(a) Let's consider the position vector of the airplane as a function of time, denoted by r(t), where t represents time in hours. The position vector can be expressed as:
r(t) = (3 + 400t)i + (4 + 500t)j - tk
To find the time when the airplane passes directly over the first airport, we need to find a value of t that satisfies the condition:
r(t) = (23)i + (29)j + (0)k
Comparing the i, j, and k components, we have:
3 + 400t = 23
4 + 500t = 29
- t = 0
Solving these equations, we find:
400t = 20
500t = 25
t = 0
The first equation suggests that t = 20/400 = 0.05, and the second equation gives t = 25/500 = 0.05. Since these values of t are equal, we can conclude that the airplane will pass directly over the first airport when t = 0.05 hours.
To determine the height above the airport, we substitute the value of t into the k component of the position vector:
h = -t = -(0.05) = -0.05 km
Therefore, the plane will be 0.05 km (or 50 meters) above the first airport when it passes over it at a time of 0.05 hours (or 3 minutes).
(b) To find the closest distance to the second airport, we need to calculate the distance between the airplane's position and the second airport's position for various times and find the minimum distance.
The position vector of the second airport is:
r2(t) = (42)i + (46)j + (0)k
The distance between the airplane and the second airport can be found using the formula:
d(t) = ||r(t) - r2(t)||
Substituting the expressions for r(t) and r2(t):
d(t) = ||(3 + 400t - 42)i + (4 + 500t - 46)j - tk||
Expanding and simplifying the expression:
d(t) = sqrt((400t - 39)^2 + (500t - 50)^2 + t^2)
To find the minimum distance, we need to differentiate d(t) with respect to t and find where the derivative equals zero:
d'(t) = 0
Differentiating and simplifying the expression:
d'(t) = (800t - 78) + (1000t - 100) + 2t
Setting d'(t) equal to zero and solving for t:
(800t - 78) + (1000t - 100) + 2t = 0
1802t - 178 = 0
1802t = 178
t = 178/1802
t ≈ 0.0988
Therefore, the minimum distance to the second airport occurs when t ≈ 0.0988 hours.
Substituting this value of t back into the expression for d(t):
d(t) = sqrt((400(0.0988) - 39)^2 + (500(0.0988) - 50)^2 + (0.0988)^2)
Calculating this expression gives the closest distance to the second airport.
Note: It's important to mention that the calculations above assume a straight-line flight path between the airplane and the airports, and the distances are measured in kilometers.
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easy:- what are the instruments used in measuring temperature
Answer:
Instrumentos Para Medir La Temperatura
Termómetro de máxima y mínima:
Termómetro metálico:
Pirómetro:
Termohidrógrafo:
A 1.50 kg rock is thrown up into the air from ground level, reaches a maximum height of 7.00 m, then returns to the ground. Calculate the rock's momentum as it strikes the ground
Answer:
17.565 kgm/s
Explanation:
Momentum = mass × velocity
I = mv..................... Equation 1
But we can calculate the value of v using the equation of motion under gravity.
v² = u²+2gs............. Equation 2
Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.
Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.
Constant: g = 9.8 m/s²
Substitute these values into equation 2
v² = 0²+ 2×7×9.8
v² = 137.2
v = √137.2
v = 11.71 m/s.
Also given: m = 1.50 kg
substitute these values into equation 1
Therefore,
I = 1.5×11.71
I = 17.565 kgm/s
what is the net force 100n to the left 100 n to the right
Answer:
I believe 0 N
Explanation:
100 to the left can be said to be -100
100 to the right can be said to be +100
+100 + -100 = 0
A student walked 100 meters North, then 100 meters West. How many more meters did the student walk compared to their total displacement from their starting point?
A. The total distance walked is about 71 meters less than the student’s displacement.
B. The total distance walked is double the magnitude of the student’s displacement.
C. The total distance walked is about 59 meters more than the student’s displacement.
D. The total distance walked is equal to the magnitude of the student’s displacement.
Answer:
C. The total distance walked is about 59 meters more than the student’s displacement.
Explanation:
The total distance walked is equal to the magnitude of the student’s displacement is the correct option. The correct answer is (D).
The student walked 100 meters North.
Then, the student walked 100 meters West.
Total distance walked = √(North distance)² + (West distance)²
Total distance walked = √(100)² + (100)²
Total distance walked = √(10000 + 10000)
Total distance walked = √20000
Total distance walked = 141.42 meters
Displacement = √(North distance)² + (West distance)²
Displacement = √(100)² + (100)²
Displacement = √(10000 + 10000)
Displacement = √20000
Displacement = 141.42 meters
The student's total distance walked is 141.42 meters, and their displacement is also 141.42 meters.
The total distance walked to the displacement:
Total distance walked = 141.42 meters
Displacement = 141.42 meters
So, the correct option is D) The total distance walked is equal to the magnitude of the student’s displacement.
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A turtle travels 12 mile in 19 hour. At this rate, how far can the turtle travel in an hour?.
16.92 meter far can the turtle travel in an hour.
What is the formula for Speed, Distance & Time?
Speed (or rate, r) is a scalar quantity that measures the distance travelled (d) over the change in time (Δt), represented by the equation r = d/Δt
Given, 12 mile in 19 hours so we require to convert in SI unit.
12 mile = 19312.1 meters
19 Hour = 68400 sec
Applying in formula, speed = Distance / Time
Distance / Time = 19312.1 / 68400 = 0.282 m/ sec ²
Speed = 0.282 m / sec ²
1 hour = 60 second
Putting the above value in the below formula
speed = Distance / Time
Distance = Speed x Time = 0.282 x 60 = 16.92 meter
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a student placed 700g of water at 28C in a freezer. After 6 minutes and 15 seconds the water was transformed into ice. Calculate the latent heat of fusion given that 235200J of heat energy was transferred during the change of state
The latent heat of fusion is 335714.29 J/kg.
To calculate the latent heat of fusion, we can use the equation:
Q = m * L
Where:
Q = heat energy transferred
m = mass of the substance
L = latent heat of fusion
Given:
Mass of water (m) = 700 g = 0.7 kg
Heat energy transferred (Q) = 235200 J
To find the latent heat of fusion (L).
Since the water is being transformed into ice, we know that the heat energy transferred during this phase change is equal to the latent heat of fusion.
Rearrange the equation to solve for L:
L = Q / m
L = 235200 J / 0.7 kg
L ≈ 335714.29 J/kg
Therefore, the latent heat of fusion is approximately 335714.29 J/kg.
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calculates the speed of the satellite which performs orbital motion around the earth from an altitude of 3600km?
Answer:
Using the equation for orbital speed
orbital speed= square root of GM/r
Where
G= Gravitational Constant = 6.674x10^-11m^3/kg.s^2
M= mass of The Earth=5.972x10^24 kg
r= the combined radius of The Earth and the height of the satellite above The Earth=6378km+ 3600km= 9978km converting to meters gives (1000m=1km) 9978km*1000m/1km= 9,978,000m or 9.978x10^6m
orbital speed = square root of (6.674x10^-11*5.972x10^24/9.978x10^6= 63198m/s
Waves of a different sort. To ionize hydrogen to create the proton used in the Mass Spectrometer, a single photon strikes the electron and liberates it fully from the proton. A. Find the wavelength of light needed to liberate the electron. B. Find the de Broglie wavelength of the electron after it absorbs this photon. Use 500 nm for the photon when in doubt. C. Find the positional uncertainty of the proton if the KE is certain to be 10KV.
A. The wavelength needed to liberate the electron is approximately 91.2 nm.
B. The de Broglie wavelength of the electron after absorbing the photon is approximately 0.967 nm.
C. The positional uncertainty of the proton is approximately 1.56 x 10^-11 m.
A. To find the wavelength needed to liberate the electron, use the formula E = hc/λ, where E is the ionization energy of hydrogen (13.6 eV), h is Planck's constant (6.63 x 10^-34 Js), and c is the speed of light (3 x 10^8 m/s). Solving for λ gives λ ≈ 91.2 nm.
B. After absorbing the photon, use the de Broglie wavelength formula λ = h/p, where p is the momentum of the electron. First, calculate the energy of the absorbed photon (E = hc/λ) using 500 nm as the given wavelength. Then, find the momentum using E = (1/2)mv^2, where m is the electron mass (9.11 x 10^-31 kg) and v is its velocity. Finally, calculate the de Broglie wavelength (λ ≈ 0.967 nm).
C. To find the positional uncertainty of the proton, use the Heisenberg uncertainty principle (ΔxΔp ≥ ħ/2), where Δx is the positional uncertainty and Δp is the momentum uncertainty. First, find the KE of the proton (10 kV), then use KE = (1/2)mv^2 to find its momentum. Using the given certainty, find the momentum uncertainty and plug it into the Heisenberg equation to get the positional uncertainty (≈ 1.56 x 10^-11 m).
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3. A skydiver started his jump from the airplane. He fell 4.9 m in the 1st second, 14.7 m
in the 2nd second, 24,5 m in the 3rd second. How far did he fall between the 7th and the
10th seconds?
Arithmetic or geometric
The distance between the 7th and the tenth second is 29.4 m.
What is the progression?We know that we can have to formulate the information that has been given here so as to obtain a proper progression and this would help us to get the common difference of the progression that we are looking at.
Now we know that the progression would look something like; 4.9, 14.7, 24.5 ....
We can see that this is an arithmetic progression that has a common difference of 9.8.
U7 = a + (n - 1)d
a = first term
n = Number of terms
d = common difference
U7 = 4.9 + (7 - 1) 9.8
= 63.7
U10 = 4.9 + (10 - 1) 9.8
U10 = 93.1
Between the 7th and 10th seconds, we have;
93.1 - 63.7
= 29.4 m
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what reactions do catalytic converters catalyze
A 0.2 kg ball is caught in a 0.5 kg glove. The ball had been moving at 8.0 m/s and it required 5.0 N of force to stop it. What was the force on the glove?
The force on the glove is 12.8 N.
Solving for the force on the glove:
The force on the glove is equal to the impulse (change in momentum) experienced by the ball divided by the time over which the force was applied.
Impulse = force x time
= 5.0 N x (1/8.0 m/s)
Impulse = 0.625 Ns
The change in momentum of the ball ΔP is
ΔP = m x v
where,
m = is the mass of the ball
v= its velocity
Momentum = mass x velocity
= 0.2 kg x 8.0 m/s
Momentum= 1.6 kg m/s
The force on the glove is equal to the change in momentum divided by the time over which the force was applied:
Force = change in momentum/time
= 1.6 kg m/s
(1/8.0 m/s)
Force = 12.8 N
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What will not produce a pitching moment?a.) A camber airfoil that is developing zero liftb.) A camber airfoil that is at a POSITIVE Angle of Attackc.) symmetrical airfoil at a zero AOAd.)
A pitching moment is produced when there is a difference in pressure on the top and bottom surfaces of an airfoil. The pressure difference creates a torque around the aircraft's lateral axis, causing the aircraft to pitch up or down.
In other words, any situation that causes a difference in lift between the two wings or between the front and rear of the aircraft will produce a pitching moment.
Therefore, option A, a camber airfoil that is developing zero lift, will not produce a pitching moment since there is no difference in pressure between the top and bottom surfaces. Option B, a camber airfoil at a positive angle of attack, will produce a pitching moment since the difference in pressure between the top and bottom surfaces increases as the angle of attack increases. Option C, a symmetrical airfoil at a zero AOA, will not produce a pitching moment since the airfoil has no camber and there is no difference in pressure between the top and bottom surfaces.
In summary, a situation where there is no difference in pressure between the top and bottom surfaces of an airfoil will not produce a pitching moment.
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If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If it is displaced a distance 0.110 m from its equilibrium position and released with zero initial speed. Then after a time 0.815 s its displacement is found to be a distance 0.110 m on the opposite side, and it has passed the equilibrium position once during this interval.
Find (a) the amplitude; (b) the period; (c) the frequency.
a)The amplitude of the wave will be 0.120m.
b)The period of the wave will be 1.60s.
What is the frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
a)The amplitude of the wave will be 0.120m.
A is the initial displacement =0.120m
The amplitude represents the largest deviation from equilibrium. So that the amplitude of the wave will be equal to the maximum position.
Hence the amplitude of the wave will be 0.120m.
b)The period of the wave will be 1.60s.
The movement from maximum positive displacement to maximum negative displacement. The time period will be;
\(\rm \frac{T}{2} = 0.800 \\\\\ T= 1.6 \ sec\)
Hence the period of the wave will be 1.60s.
c) The frequency of the wave will be 0.625Hz.
The frequency is inversely proportional to the time period. Frequency is found as;
\(\rm f=\frac{1}{T} \\\\ \rm f=\frac{1}{0.625} \\\\ \rm f=0.625 \ Hz\)
Hence the frequency of the wave will be 0.625Hz.
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If a car has a mass of 4000 kg and the force applied to it is 10000 N. What is its acceleration?
Answer:
2.5 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the force
m is the mass
From the question we have
\(a = \frac{10000}{4000} = 2.5 \\ \)
We have the final answer as
2.5 m/s²Hope this helps you
when you heat a sample of a gas, what happens to the particles that make up that gas?
Answer:
the particles that heat up the gas become more active (vibrating around)
PLEASE HELP this is the last question to a hundred and I need to get be done yesterday (I forgot and now I have an F. ). The Moon orbits the Earth every 29.5 days in the Earth-Moon system. The Earth-Moon system is a part of____
A. The Universe
B. The Solar System
C. The Milky Way galaxy
D. all of these
The Earth-Moon system is a part of: D. all of these.
What is a solar system?A solar system simply refers to a collection of the outer and inner planetary or astronomical bodies alongside the Moon that are constantly in orbit around the Sun, in slightly elliptical orbits.
The planets in the solar system.According to astronomical records and information, there are nine (9) main planets in the solar system and these include;
MercuryVenusEarthMarsJupiterUranusNeptunePlutoSaturnIn conclusion, we can reasonably infer and logically deduce that the Earth-Moon system forms a part of the solar system, the Milky Way galaxy and the universe.
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a source of light moves in a circle with the speed v source =c/2. when the source is moving directly toward you, it’s observed frequency is f1. when the source is moving directly away from you it’s observed frequency is f2. is the ratio of f1/f2 equal to 1,2, or 3
The ratio of f1/f2 is slightly greater than 3.
What is the source of light?Sources of light are objects or phenomena that emit light, a form of electromagnetic radiation visible to the human eye. Some familiar natural light sources include the sun, stars, lightning, and fireflies.
What are the different sources of light?Sources of light can be categorized as either incandescent or luminescent. Incandescent sources produce light through heat, such as the glowing filament in an incandescent light bulb. In contrast, luminescent sources produce light through a chemical or physical process, such as a fluorescent light bulb or a neon sign.
f1 = (c + v(observer)) / (c - v(observer))
f2 = (c - v(observer)) / (c + v(observer))
Dividing the two equations, we get:
f1 / f2 = (c + v(observer)) / (c - v(observer)) * (c + v(observer)) / (c - v(observer))
the ratio of f1/f2 can be expressed in terms of the extremes of v(observer)and v(observer)as:
f1 / f2 = (c + v(observer)) / (c - v(observer)) * (c + v(observer)) / (c - v(observer))
= (c + v(observer)) / (c - v(observer)) * (c + c/2) / (c - c/2) (using v(source) = c/2 and -c/2)
= (3c + 2v(observer)) / (c - 2v(observer))
Since v(observer) is much smaller than c, we can approximate this as:
f1 / f2 ≈ (3c + 2v(observer)) / c
Thus, the ratio of f1/f2 is slightly greater than 3.
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The linear expansivity of metal P is twice that of another metal Q. When these materials are heated through the same temperature change, their increase in length is the same. Calculate the ratio of the original length of P to Q