Which graph represents the solution set for the inequality StartFraction one-half EndFraction x is less than or equal to 18.x ≤ 18?

In linear equation, 3 number of cups will be needed to marinade 4 pounds of chicken for grill.

What are a definition and an example of a linear equation?

Here we have the data from the question:-

Marcy will use 6 fluid ounces of lemon-garlic marinade for every pound of chicken.

Marcy plans to grill 4 pounds of chicken.

So total marinade required will be:-

Total marinade  =6x4=24 ounces

Now we know that the conversion:-

1 fluid Ounce = 0.125 Cup

24 fluid ounce =0.125 Cup

Hence 3 number of cups will be needed to marinade 4 pounds of chicken for grill.

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The perimeter of the polygon with vertices Q(-3, 2), R(1, 2), S(1,-2), and T(-3,-2) is 16 units.

Perimeter is a circumferential measure of the figure, for example, the perimeter of a square is the sum of all its sides.

Here,

To find the perimeter of a polygon, we need to add up the lengths of all its sides. In this case, we have a quadrilateral with vertices Q(-3, 2), R(1, 2), S(1,-2), and T(-3,-2).

We can use the distance formula to find the lengths of each side:

Length of QR = √[(1 - (-3))² + (2 - 2)²] =  4

Similarly,

Length of RS= 4

Length of ST= 4

Length of TQ= 4

Therefore, the perimeter of the polygon is 4 + 4 + 4 + 4 = 16

So the perimeter of the polygon with vertices Q(-3, 2), R(1, 2), S(1,-2), and T(-3,-2) is 16 units.

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To solve the recurrence relation T(n) = T(n/2) + 2^n using the master theorem, we need to compare the function 2^n with n^(log_b a) = n^(log_2 1) = n^0 = 1.

Since 2^n grows much faster than n^0, we can apply case 3 of the master theorem, which states that if f(n) = 2^n, and if there exists a constant ε > 0 such that f(n) = Ω(n^(log_b a + ε)), then T(n) = Θ(f(n)).

In our case, since 2^n = Ω(n^(0 + ε)) for any ε > 0, we can conclude that T(n) = Θ(2^n).

Therefore, the solution to the recurrence relation T(n) = T(n/2) + 2^n is T(n) = Θ(2^n).

The actual length of the swing set area is 0.5 * 20 feet = 10 feet.

Since the scale drawing represents the actual dimensions of the park,

We can use the ratio of the scale drawing dimensions to the actual dimensions to find the actual length of the swing set area.

Let's call the actual length of the swing set area L.

Then, on the scale drawing, the length of the swing set area is 0.5 inches.

The ratio of the actual length to the scale drawing length is 20 inches : L feet.

We can set up an equation to find L:

L * (20 inches / L feet) = 0.5 inches

Solving for L, we find:

L = (0.5 inches * L feet) / (20 inches / L feet)

= (0.5 * L feet) / (20 / L feet)

= (0.5 * L feet) / (20 / L feet)

= 0.5 * (L feet / 12 inches/foot)

= 0.5 * 20 feet

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Answer:

The answer is 100 feet. I took the quiz and it was 100 feet.

Step-by-step explanation:

5x + 8

easyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Answer:

3.2

Step-by-step explanation:

Answer:

-10

Step-by-step explanation:

i just did it

Answer: 11, 30

Step-by-step explanation:

Given

There were a total of 41 national battlefields and national memorials

Suppose there are \(x\) national battlefields

So, national memorials are \(3x-3\)

The sum of the two must be 41

\(\Rightarrow x+3x-3=41\\\Rightarrow 4x=44\\\Rightarrow x=11\)

So, there are 11 national battlefields and \(3\times 11-3=30\) national memorials.

Answer:

8 x (5 - 2) = ( 8 x 5) - ( 8 x 2)

Step-by-step explanation:

8 x (5 - 2) = ( _ x 5) - ( _ x 2)

Distribute

8 x (5 - 2) = ( 8 x 5) - ( 8 x 2)

From the given sets, the elements will be AU (CAB)' = {a, b, c, d, e, f, g, i, j, k}.

To determine AU (CAB)', we first need to find CAB and then take its complement with respect to U.

CAB represents the elements that are common to all three sets A, B, and C. From the given sets, we can see that the elements common to A, B, and C are {h}. Therefore, CAB = {h}.

Now, to find the complement of {h} with respect to U, we need to find the elements in U that are not in {h}. The complement of {h} in U is {a, b, c, d, e, f, g, i, j, k}.

Therefore, AU (CAB)' = {a, b, c, d, e, f, g, i, j, k}.

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MidPoint that \($PQ/FH = 1+1 = \boxed{2}$\)

Since M is the midpoint of EF, we have EM = FM.

Similarly, since N is the midpoint of EH, we have EN = HN.

Since EFGH is a parallelogram, we have FG || EH, so by the parallel lines proportionality theorem, we have

\(FP/FH\) = \(GM/GH\) and \(HQ/FH\)

​ = \(GN/GH\)

​Adding these two equations, we get

\((FP+HQ)/FH\)

​ = \((GM+GN)/GH\)

​But \($GM+GN\) = MN = \(\frac{1}{2}EH = \frac{1}{2}FG$\), since EFGH is a parallelogram.

\((FP+HQ)/FH\) = \(\frac{1}{2} FG / GH\)

That \($\triangle FGH$ and $\triangle FGP$\) are similar (since \($\angle FGP = \angle FGH$ and $\angle GPF = \angle HFG$\)), so we have \($GP/GH = FG/FH$\). Similarly, we have\($HQ/GH = EH/FH = FG/FH$\) (since EFGH is a parallelogram).

Therefore,

\({(FP+HQ)}/FH\)= \({(\frac{1}{2} FG)}/GH\) = \({(GP+HQ)} /GH\)

Implies that \($PQ/FH = FP/GP + HQ/HQ$\). But \($FP/GP = 1$\) (since \($\triangle FGP$\) is isosceles with \($FG = GP$\)), and \($HQ/HQ = 1$\) as well.

we have \($PQ/FH = 1+1 = \boxed{2}$\).

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Answer:

i think one of them is

(-1,5) and (8,3)

Step-by-step explanation:

just count up how much is on both x and y axes and you'll get ur answer.

goodluck!

also, dont put my answer cuz im afraid u'll get it wrong cuz i tried my best, so jus wait untill someone else answers if u want <3

goodluck

The dimensions of the rectangle is 3.33 by 5.33

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Third side of triangle, w = 12 - 5 - 1/2l

The perimeter of the rectangle is then calculated a

2 * (1/2l + 1/2l + 12 - 5 - 1/2l) = 22

So, we have

(1/2l + 1/2l + 12 - 5 - 1/2l) = 11

Evaluate

1 1/2l + 7 = 11

This gives

3/2l = 5

Evaluate

l = 10/3

The dimension is then represented as

l by 12 - 5 - 1/2l

This gives

10/3 by 12 - 5 - 1/2 * 10/3

Evaluate

3.33 by 5.33

Hence, the dimension is 3.33 by 5.33

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Answer:

12%

Step-by-step explanation:

As per the provided information in the given question, we have :

We are asked to calculate,

As we know that,

\( \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{Price \; increase}{Original \; price} \times 100 \Bigg ) \; \%}} \\ \)

→ Price increase = New price - Original price

→ Price increase = Rs. ( 53.76 - 48 )

→ Price increase = Rs. 5.76

Substituting values,

\( \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{5.76}{48} \times 100 \Bigg ) \; \%}} \\ \)

\( \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{576}{4800} \times 100 \Bigg ) \; \%}} \\ \)

\( \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{57600}{4800} \Bigg ) \; \%}} \\ \)

\( \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{576}{48} \Bigg ) \; \%}} \\ \)

\( \\ \longrightarrow \bf{\quad\underline { \% \; increase = 12\; \%}} \\ \)

Therefore, percentage increase is 12 %.

Answer:

8b

Step-by-step explanation:

You can factor the b-term out since b-term exists for all terms in the expression. By factoring out, you are basically dividing the factored term off and put it outside of the bracket, thus:

\(\displaystyle{16b-8b=\left(16-8\right)b}\)

Then evaluate and simplify:

\(\displaystyle{\left(16-8\right)b=8\cdot b}\\\\\displaystyle{=8b}\)

The value of result after executing the statement is 30.

To evaluate the expression and find the value of result, let's break down the operations step by step, following the order of operations (PEMDAS/BODMAS):

Inside the parentheses, we have:

3 × 5 = 15

Next, the expression becomes:

15 × 24 / (15 - (7 - 4))

Inside the inner parentheses:

7 - 4 = 3

Now, the expression becomes:

15 × 24 / (15 - 3)

Inside the parentheses:

15 - 3 = 12

The expression simplifies to:

15 × 24 / 12

Multiplication:

15 × 24 = 360

Division:

360 / 12 = 30

Therefore, the value of result after executing the statement is 30.

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The mathematical expression 'result = (3 * 5) * 24 / (15 - (7 - 4))' simplifies to 'result = 15 * 24 / 12', leading to a final value of 30.

The task here is to understand and solve the provided mathematical expression, which is result = (3 * 5) 24 / (15 - (7 - 4)). However, this expression seems to contain a typo - there's an operation missing between (3 * 5) and 24. Let's assume that the operation is multiplication, turning the expression into result = (3 * 5) * 24 / (15 - (7 - 4)).

Then, performing the multiplication and division in order from left to right gives the result as 30.

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Answer:the answer for part A is SAS.

Step-by-step explanation:

We already know that side PQ is the same length for both the triangles. We were then given the information that sides PM and PN were equal. So now we already have two sides that are the same. Then we were given the information that angle MPQ and angle NPQ were also equal. So now we have two sides and an angle that are equal. This is how we got SAS (side angle side). I tried my best to explain. I added a photo so you could see what I was trying to explain. Hopefully this helped!

Answer:  5/8 cm^3

Step-by-step explanation:

V = l x w x h

l = 3/4 cm

w = 1/3 cm

h = 5/2 cm

V = (3/4 cm) x (1/3 cm) x (5/2 cm) = 15/24 cm^3 = 5/8 cm^3

A)the density of |x| is f(|x|) = 1/(1-0) = 1. B) the density of p|x| is f(p|x|) = 1/(p-0) = 1/p. C) the density of -ln|x| is f(-ln|x|) = 1/(∞-0) = 0. D) the density of sin(x) is f(sin(x)) = 1/(sin(1)-(-sin(1))).

(a) To find the density of |x|, we need to consider the range of values that |x| can take. Since x is uniformly distributed on the interval (-1, 1), the absolute value of x can take values between 0 and 1. The density function of |x| is given by f(|x|) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a = 0 and b = 1. Therefore, the density of |x| is f(|x|) = 1/(1-0) = 1.

(b) To find the density of p|x|, we need to consider the range of values that p|x| can take. Since x is uniformly distributed on the interval (-1, 1), p|x| can take values between 0 and p. The density function of p|x| is given by f(p|x|) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a = 0 and b = p. Therefore, the density of p|x| is f(p|x|) = 1/(p-0) = 1/p.

(c) To find the density of -ln|x|, we need to consider the range of values that -ln|x| can take. Since x is uniformly distributed on the interval (-1, 1), -ln|x| can take values between 0 and ∞. The density function of -ln|x| is given by f(-ln|x|) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a  = 0 and b = ∞. Therefore, the density of -ln|x| is f(-ln|x|) = 1/(∞-0) = 0.

(d) To find the density of sin(x), we need to consider the range of values that sin(x) can take. Since x is uniformly distributed on the interval (-1, 1), sin(x) can take values between -sin(1) and sin(1). The density function of sin(x) is given by f(sin(x)) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a = -sin(1) and b = sin(1). Therefore, the density of sin(x) is f(sin(x)) = 1/(sin(1)-(-sin(1))).

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\(4(7s+3t)-7(8s-t) \\ \\ =28s+12t-56s+7t \\ \\ =\boxed{-28s+19t}\)

Answer:

I think it's a I might be wrong..

Answer:

a

Step-by-step explanation: edge 2022

There are a total of three numbers in a combination lock, and no digit can be repeated. To open the lock,

The correct answer is B. 720.

The first number can be any of the 10 digits, and the second number can be any of the 9 remaining digits because no digit can be repeated.

Finally, since there are 8 digits left, the third digit can be any of these.

The combination can be created in the following manner:

The total number of possible combinations = (Number of ways to select the first number) x (Number of ways to select the second number) x (Number of ways to select the third number).

= 10 x 9 x 8 ⇒ 720.

Therefore, the sequence of the combination is 720, and option (B) is correct.

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Answer:

9

Step-by-step explanation:

27/3=9. 9x3=27

Answer:

Why might he think that and what would you tell him?

He thought perhaps that numbers were formed by rational numbers of the form \(\frac{1}{x}\), where \(x\in \mathbb{N}\). I would tell him that there are rational numbers \(\frac{y}{z}\), such that \(\frac{1}{x}\le \frac{y}{z} \le \frac{1}{x+1}\), where \(x\), \(y\), \(z \in \mathbb{N}\).

Is there a number that falls between these?

\(\frac{7}{24}\) is a rational number between \(\frac{1}{3}\) and \(\frac{1}{4}\).

Step-by-step explanation:

Why might he think that and what would you tell him?

He thought perhaps that numbers were formed by rational numbers of the form \(\frac{1}{x}\), where \(x\in \mathbb{N}\). I would tell him that there are rational numbers \(\frac{y}{z}\), such that \(\frac{1}{x}\le \frac{y}{z} \le \frac{1}{x+1}\), where \(x\), \(y\), \(z \in \mathbb{N}\).

Is there a number that falls between these?

Indeed, the average number of \(\frac{1}{3}\) and \(\frac{1}{4}\), for instance. That is:

\(\frac{y}{z} = \frac{\frac{1}{3}+\frac{1}{4} }{2}\)

\(\frac{y}{z} = \frac{\frac{7}{12} }{2}\)

\(\frac{y}{z} = \frac{7}{24}\)

\(\frac{7}{24}\) is a rational number between \(\frac{1}{3}\) and \(\frac{1}{4}\).