For a visible light that has a frequency of 2.1 x 1014 Hz, the wavelength is approximately 1430 nm.
To calculate the wavelength of visible light with a frequency of 2.1 x 10^14 Hz, we can use the formula:
Wavelength (λ) = Speed of light (c) / Frequency (f)
The speed of light (c) is approximately 3.0 x 10^8 meters per second (m/s). So, we can plug in the given frequency (f) into the formula:
Wavelength (λ) = (3.0 x 10^8 m/s) / (2.1 x 10^14 Hz)
Wavelength (λ) ≈ 1.43 x 10^-6 meters
Now, to convert this to nanometers (nm), we multiply by 10^9:
Wavelength (λ) ≈ 1.43 x 10^3 nm
Rounded to the nearest integer, the wavelength is approximately 1430 nm.
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A river flows with a speed of 3km/h in still water. A man who can swim with a speed of 5km/h wishes to reach a point on the other bank just opposite to the starting point. In which direction should he put his strokes and how long will he take to cross the river of width 1.2km? Please try to provide a diagram and step by step explanation.
Answer:
Explanation:
Let the angle required be θ with direction opposite to current .
cos θ = 3 / 5
θ = 53° .
Resultant velocity towards the opposite side
= √ ( 5 ² - 3²)
= 4 km /h
distance covered = 1.2 km
time taken = 1.2 / 4 = .3 h
= 18 min .
please answer asignment due today
Answer:
Give me some time okkkk
Homework-3 Question 1: A cam is to give the following motion to a knife-edge follower: 1 Outstroke during \( 30^{\circ} \) of cam rotation: 2 Dwell for the next \( 60^{\circ} \) of cam rotation : 3. R
Cam is a mechanical device that is used to convert rotary motion into linear motion. The cam follower mechanism is used to convert the rotary motion of a cam into a reciprocating motion of a follower. It consists of a cam and a follower. The cam is a rotating element that imparts a specified motion to the follower.
The follower is a sliding element that follows the motion of the cam.
Cam specifications for knife-edge follower motion: Outstroke during 30° of cam rotation: During the first 30° of cam rotation, the cam must provide the follower with a motion that moves it away from the cam centerline.2 Dwell for the next 60° of cam rotation: During the next 60° of cam rotation, the follower must remain in its outstroke position.
3. Return Stroke for the remaining 270° of cam rotation:
The cam must now provide a motion to the follower that moves it back towards the cam centerline. The return stroke motion should be such that the follower returns to its initial position by the end of 360° of cam rotation.
In conclusion, this is the cam specification for a knife-edge follower motion:
1 Outstroke during 30° of cam rotation:
2 Dwell for the next 60° of cam rotation :
3. Return Stroke for the remaining 270° of cam rotation.
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Which type of wave is most affected by gravity from the Sun and the moon?
Answer:
A tidal is a type of wave is most affected by gravity from the sun and the moon.
Explanation:
I hope it helps ❤❤
Tidal wave is the type of wave which is most affected by gravity from the
Sun and the moon
The sun and the moon's gravitational pull results to the tidal force being
generated. The tidal force from the tidal wave generated has some effects
on the earth.
It causes the Earth and its water content to bulge out on two sides of the
earth. It bulges in the area with the highest proximity to the moon and areas
with the lowest proximity. This is responsible for the formation of high tides
in water bodies.
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Proton 1 moves with a speed v from the east coast to the west coast in the continental United States; proton 2 moves with the same speed from the southern United States toward Canada. (a) Is the magnitude of the magnetic force experienced by proton 2 greater than, less than, or equal to the force experienced by proton 1? (b) Choose the best explanation from among the following: I. The protons experience the same force because the magnetic field is the same and their speeds are the same. II. Proton 1 experiences the greater force because it moves at right angles to the magnetic field. III. Proton 2 experiences the greater force because it moves in the same direction as the magnetic field.
(a) The magnitude of the magnetic force experienced by proton 1 and proton 2 is the same.
(b) The correct explanation is I. The protons experience the same force because the magnetic field is the same and their speeds are the same.
The magnitude of the magnetic force experienced by a charged particle moving in a magnetic field depends on the velocity of the particle and the strength of the magnetic field. Since both protons have the same velocity and are moving in the same magnetic field, they experience the same magnetic force.
The first explanation "The protons experience the same force because the magnetic field is the same and their speeds are the same" is correct. Since both protons have the same velocity and are moving in the same magnetic field, they experience the same magnetic force.
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does sound travel faster in warm air or in cold air? in humid air or dry air?
In warm air, sound travels more quickly than in cold air. Since the speed of sound is directly inversely proportional to the square root of the air's absolute temperature, the speed of sound rises with temperature.
Additionally, dry air travels faster than humid air for sound. The speed of sound is slightly affected by humidity, with sound traveling slightly slower in more humid air. This is due to the fact that airborne water vapor has the ability to slow down sound waves by absorbing some of their energy.
What is moisture?The amount of water vapor in the air is measured by humidity. At a given temperature, it is typically expressed as a percentage of the maximum amount of water vapor that the air can hold.
It is said that the air has a humidity of 100 percent when it is saturated. Any additional water vapor will condense into liquid or solid form (such as dew, fog, clouds, or precipitation) because the air cannot hold any more water vapor at this point. The air can hold more water vapor and is less likely to reach 100% humidity as the temperature rises.
Specific humidity or mixing ratio, which is the ratio of the mass of water vapor in the air to the mass of the air as a whole, is another way to measure humidity.
The weather and climate can be significantly affected by humidity. High humidity can cause clouds to form and precipitation to fall. It can also make the air feel hotter. Low humidity can make the air feel cooler, make it dry, and make wildfires more likely. The human body is also affected by humidity; low humidity can dry out the skin and nasal passages, while high humidity can make it difficult to cool down and can exacerbate respiratory issues.
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A student compared a sample of isooctane with some petrol. The student found that the octane boiled at
99C while the petrol boiled between 45 and 95C. Which of these is a pure substance? Explain your
answer.
Isooctane is the pure substance, while petrol is a mixture of different compounds.
Based on the given information, isooctane and petrol are being compared in terms of their boiling points. Isooctane, also known as 2,2,4-trimethylpentane, is a pure substance.
It is a hydrocarbon compound and is one of the primary components of gasoline (petrol).
Being a specific compound with a well-defined molecular structure, isooctane has a fixed boiling point, which in this case is stated as 99°C.
On the other hand, petrol refers to a mixture of various hydrocarbons, which can vary in composition depending on its source and the refining processes it undergoes.
Petrol is a complex mixture containing multiple compounds with different boiling points. The given range of boiling points, between 45°C and 95°C, suggests that petrol is composed of several components that vaporize at different temperatures.
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According to a scientific realist, scientific terms for unobservable phenomena like "atom" and "black hole" to entities that really exist. However, the scientific antirealist claims that scientific terms that refer to unobservable phenomena to something in reality.
It is important to note that the debate between scientific realism and antirealism is ongoing and complex, with various nuances and perspectives within each position. Different philosophers of science and scientists may hold different views on the nature of scientific terms and their relationship to reality.
According to a scientific realist perspective, scientific terms for unobservable phenomena such as "atom" and "black hole" are seen as referring to entities that truly exist in reality. Scientific realists believe that scientific theories and concepts accurately capture aspects of the world, including unobservable entities and phenomena. They argue that scientific theories provide the best explanation of the natural world and aim to describe the underlying structure and mechanisms of reality.
On the other hand, scientific antirealists hold a different view. They argue that scientific terms that refer to unobservable phenomena do not necessarily correspond to something that exists independently in reality. Antirealists often emphasize the instrumentalist view of science, which suggests that scientific theories are simply tools or frameworks that help us organize and predict observable phenomena, without making claims about the ultimate nature of reality.
Antirealists may argue that scientific theories are subject to revision and change over time as new evidence emerges, suggesting that the terms used to describe unobservable phenomena are not fixed and may not have a one-to-one correspondence with actual entities in reality. They may also highlight the role of social and cultural factors in shaping scientific knowledge, suggesting that scientific terms are influenced by human conventions and interpretations.
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SOMEONE ANSWER ME ASAPPP ILL GIVE U BRAINLIEST ANSWER
Options are
a)6.5km
b)9.0km
c)10.5km
d)2.5km
Answer:
2.5 km because displacement is xf -xi
xf = 2.5
xi= 0
2.5 - 0 =2.5 km
How would I find the average distance for this?
Answer:
Explanation:add them then divide them by 100 I think
A 5.0 kg block of ice is at rest at the top of a smooth inclined plane. The block is released and slides 2.0 m down the plane. Assuming there is no friction between the block and the surface, calculate
a) the gravitational potential energy at the top of the plane
b) the component of the weight parallel to the plane
c) the acceleration of the block
d) the velocity of the block at the bottom of the plane
e) the kinetic energy at the bottom of the plane.
Answer:
a) 98.1 Joules
b) 49.05 N × sin(θ)
c) 9.81 × sin(θ)
d) The velocity of the block at the bottom of the plane, v is approximately 6.264 m/s
e) 98.1 Joules
Explanation:
The given parameters of the block are;
The mass of the block, m = 5.0 kg
The distance down the plane the block slides, h = 2.0 m
The friction between the block and the surface = 0
Let θ represent the angle of inclination oof the plane
a) The gravitational potential energy, P.E. = m·g·h
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
∴ P.E. ≈ 5.0 kg × 9.81 m/s² × 2.0 m = 98.1 Joules
The gravitational potential energy, P.E. ≈ 98.1 Joules
b) The component of the weight of the block parallel to the plane, \(w_{\parallel}\), is given as follows;
\(w_{\parallel}\) = w × sin(θ) = m·g·sin(θ)
∴ \(w_{\parallel}\) ≈ 5.0 kg × 9.81 m/s² × sin(θ) = 49.05 × sin(θ) N
The component of the weight of the block parallel to the plane, \(w_{\parallel}\) ≈ 49.05 N × sin(θ)
c) The component of the weight along the inclined plane = The force with which the block moves along the inclined plane, therefore;
\(w_{\parallel}\) = m·g·sin(θ) = m·a
Where a represents the acceleration of the block along the plane
Therefore, by comparison, we have;
g·sin(θ) = a
∴ a ≈ 9.81 × sin(θ)
d) Given that the motion of the block is 2.0 m downwards, we have;
The velocity of the block at the bottom of the plane, v² = 2·g·h
Therefore, v² ≈ 2 × 9.81 m/s²× 2.0 m = 39.24 m²/s²
v = √(39.24 m²/s²) ≈ 6.264 m/s
e) The kinetic energy at the bottom of the plane, K.E. = (1/2)·m·v²
∴ K.E. = (1/2) × 5.0 kg × 39.24 m²/s² = 98.1 J
true or false: one way to live on the moon or mars and be protected from radiation would be to live underground.
True. Living underground can provide significant protection from radiation as the soil and rock above can act as a shield.
This is one of the proposed methods for protecting astronauts from radiation exposure on the moon and Mars.
What is radiation?
Radiation refers to the emission of energy in the form of waves or particles, such as electromagnetic radiation or particles like alpha, beta, or gamma rays. It can come from natural sources, such as the sun or radioactive materials, or man-made sources, such as X-rays or nuclear power plants. Radiation can have both beneficial and harmful effects on living organisms, depending on the type, dose, and exposure time.
What are the Mars?
Mars is a planet in our solar system that is known as the fourth planet from the Sun. It is often referred to as the "Red Planet" due to its reddish appearance in the night sky. Mars has a thin atmosphere, polar ice caps, and evidence of past liquid water on its surface. It is currently being studied by various space agencies, including NASA, for its potential habitability and as a target for future manned missions.
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If Saturn takes about 30 years to orbit the Sun, and its rings were seen edge-on in 2009, when will they appear edge-on next?
Select one:
a. 2015
b. 2024
c. 2039
d. 2012
e. 2019
Answer:
b the answer
Explanation:
It is correct
Which of the pictures below shows a concave lens?Select one:a. Ab. Bc. Cd. D
(D)
Explanation
A concave lens is thinner in the middle than it is at the edges. This causes parallel rays to diverge
now, in the options we have
A plano concave lens is an optical lens with one concave surface and one flat surface. It has a negative focal length,
so, the answer is
(D)
I hope this helps you
We dont got the force so i got no clue what to do
⦁ How much work is it to lift a 20 kg sack of potatoes vertically 6.5 m?
Answer:
work = 1275.3 J
Explanation:
work = (force)(distance)cosø ------- force = ma
=(mass*acceleration)(distance)cosø
=(20*9.81)(6.5)cos0
=1275.3J
nite that the angle of cosine is the difference between the angle of force and the distance. in this case, the force and the distance are in the same direction. :)
4) A 200 kg empty cart moves east at 15 m/s. A 50kg rock is dropped straight down into th
moving cart. What is the final speed of the railroad cart?
The final speed of the railroad cart is equal to 12 m/s.
What is law of conservation of linear momentum?According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁u₁ + m₂u₂ = m₁ v₁ + m₂ v₂
Where m₁ and m₂ are the mass of the objects, u₁ and u₂ are the initial speed while v₁ & v₂ is the final speed.
The momentum of an object is defined as the product of the mass times the velocity of that object.
Given the mass of the empty cart, m₁ = 200 Kg
The mass of the rock, m₂ = 50 Kg
The initial velocity of the empty cart, u₁ = 0
m₁ u₁ + m₂ u₂ = (m₁ + m₂)× V
200 × 15 + 50 × 0= (200 + 50) × V
V = 12 m/s
Therefore, the final speed of the railroad cart is equal to 12 m/s.
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A bat hits a baseball with a force of 500N. The magnitude of the force that the baseball exerts on the bat is...
Answer:
45
Explanation:
because
The magnitude of the force that the baseball exerts on the bat is 500 N.
The given parameters;
force applied on the baseball by the bat, F₁ = 500 NAccording to Newton's third law of motion, action and reaction are equal and opposite. That is, when an object A exerts a certain force on another object B, the reaction of object B is equal to the magnitude of the force exerted by object A but in opposite direction.
Let the force the baseball exerts on the bat = F₂
then, from Newton's third law, we will have the following;
F₁ = -F₂
500 = -F₂
-500 N = F₂ (500 N is magnitude while the negative sign is the direction)
Thus, the magnitude of the force that the baseball exerts on the bat is 500 N.
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A driver of a car traveling at -15m/s applies the brakes, causing a uniform acceleration of +2.0m/s2. If the brakes are applied for 2.5s, what is the velocity of the car at the end of the braking period? How far has the car moved during the braking period?
Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
\(v = u+at\\\\v=-15 + 2\times 2.5\\\\v=-10 \ m/s\)
Now, distance covered by car is :
\(s=ut+\dfrac{at^2}{2}\\\\s=(-15)(2.5)+\dfrac{2(2.5)^2}{2}\\\\s=-31.25\ m\)
Hence, this is the required solution.
3. compare the means of each group (aspd and no aspd). what can you say about the narcissism scores of the aspd group compared to the no aspd group? (5 pts)
The mean of the ASPD group is likely higher than the mean of the no ASPD group.
ASPD stands for Antisocial Personality Disorder, which is a mental health condition characterized by a persistent pattern of disregarding the rights of others and engaging in illegal or unethical behavior. If a study were conducted to compare the means of the ASPD and no ASPD groups in terms of narcissism scores, it would likely show that the mean of the ASPD group is higher than the mean of the no ASPD group.
Narcissism is a personality trait characterized by a grandiose sense of self-importance, a sense of entitlement, and a lack of empathy for others. People with ASPD are often considered to be narcissistic, so it is likely that the mean narcissism score for the ASPD group would be higher than the mean score for the no ASPD group.
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Write the cautions which are taken to keep the magnetic properties of magnetsa) Don’t hammer it b) don’t drop it c) don’t heat it d) all of these
PLS HELP GUYS ITS URGENTTT!! I AM IN CLASS ...PLEASE!!
Answer:
D
Explanation:
These all can impact the magnetic properties
Calculate the expected chain-length (number of repeating units
per chain) that would be formed in your experiment, assuming all
initiators initiate chains and all monomers add onto the chains.
That is
The expected chain length (number of repeating units per chain) that would be formed in the experiment, assuming all initiators initiate chains and all monomers add onto the chains can be calculated using the following formula.
Expected chain length = (Number of moles of monomers used/Number of moles of initiators used) + 1Where,+ 1 denotes the length of the initiator's unit and is added to the average number of monomer units. Hence, it indicates the length of the polymer's first unit.The number of moles of monomers used can be determined as follows
The number of moles of initiators used can be determined as follows:Number of moles of initiators = (Mass of initiators used/Molecular weight of initiators)Example:If the mass of monomers used is 0.05 g and the molecular weight of monomers is 100 g/mol, then the number of moles of monomers used
= (0.05/100) mol
= 5 × 10⁻⁴ molIf the mass of initiators used is 0.01 g and the molecular weight of initiators is 200 g/mol
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D Omph 515 mph Okm/h 830 km/hr 792 mph 1.275 km/hr 163 mph 1,550 km/hr 1,025 mph 1,650 km/h 1.550 km/hr 1.275 km/hr At the equator, the circumference of the Earth is 24,600 miles, and the day is 24 hours long so the speed of the Earth at the equator is 1,025 miles/hr. This decreases by the cosine of your latitude. To calculate how fast you are spinning you take the (cos) of your latitude and multiply it times the speed at the equator (1,025 mph). Latitude of Baton Rouge: 30.45N Cos of 30.45 = .568 15. How fast is the Earth spinning in Baton Rouge?
The Earth's spinning at approximately 582.2 mph in Baton Rouge.
To find out how fast the Earth is spinning in Baton Rouge, we need to consider the latitude of Baton Rouge, which is 30.45N. We know that the speed of Earth at the equator is 1,025 mph, and this speed decreases by the cosine of the latitude.
Here's a step-by-step calculation:
1. Determine the latitude of Baton Rouge: 30.45N
2. Calculate the cosine of the latitude: cos(30.45) = 0.568
3. Multiply the cosine of the latitude by the speed of Earth at the equator (1,025 mph): 0.568 × 1,025 mph = 582.2 mph
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How does the force work
Answer:
A force is a push or a pull.
Explanation:
Example: A boy is pushing a box. He has to push the box to go forward or pull it to go backwards.
Hope this helped
Light travels at a speed of about 3.0 108 m/s.(a) How many miles does a pulse of light travel in a time interval of 0.1 s, which is about the blink of an eye?Δx = mi(b) Compare this distance to the diameter of Earth. (Use 6.38 106 m for the radius of the Earth.)ΔxDE =
Given:
Speed of light = 3 x 10⁸ m/s
Let's solve for the following:
• (a). How many miles does a pulse of light travel in a time interval of 0.1 s, which is about the blink of an eye?
Apply the formula:
\(\Delta x=v*t\)Where:
v is the speed of light
t is the time.
Thus, we have:
\(\begin{gathered} \Delta x=3.0\times10^8*0.1 \\ \\ \Delta x=3.0\operatorname{\times}10^7\text{ m} \end{gathered}\)Now let's convert the answer from meters to miles.
Where:
1 mile = 1609.34 meters
\(\begin{gathered} 3.0\times10^7=\frac{3.0\times10^7}{1609.34} \\ \\ =18641.14\text{ mi} \end{gathered}\)Δx = 18641.14 mi
• (b). Compare this distance to the diameter of Earth.
Apply the formula:
\(\frac{\Delta x}{D_E}=\frac{\Delta x}{2*r}\)Where:
r = 6.38 x 10⁶ m.
Thus, we have:
\(\frac{\Delta x}{D_E}=\frac{3.0\times10^7}{2*6.38\times10^6}=2.35\)ANSWER:
• (a). 18641.14 mi
,• (b). 2.35
terms used to measure motion
Answer:
velocity term
Explanation:
Answer:velocity term
Explanation:
In a typical golf swing the club is in contact with the ball for about 0.0010 s. If the .045 kg ball experiences a force of 4000 N, what is the final velocity of the golf ball?
Answer:
v = 88.89 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.
We must make up the following equation:
\(F*t = m*v\)
where:
F = force applied = 4000 [N]
t = time = 0.001 [s]
m = mass = 0.045 [kg]
v = velocity [m/s]
\(4000*0.001=0.045*v\\v=88.89[m/s]\)
45 POINTS!! IF ANYONE IS WILLING TO DO THIS YOU'RE A HERO
Pretend you are in a world with no friction or air resistance. You are on your bicycle at the top of a small hill. You kick off and without pedaling, you roll down the hill. How far will you go without pedaling in this pretend world? How does it compare with how far you might go in the real world? If there is a difference between the two worlds, why is this so? Explain as precisely as you can, using the law of conservation of energy in your explanation.
A 2-4 paragraph expository essay. This will include a full explanation of the normal conditions scenario and the frictionless world scenario in paragraph form.
No matter the format, the work must include:
A description of the bike’s behavior in our normal world with friction and air resistance, including distance traveled.
A description of the bike’s behavior in a frictionless, air resistance free world including distance traveled.
An explanation of forces at play in both scenarios and the kinetic and potential energy levels of the bike at various points in its travel down the hill. This will include application of the Law of Conservation of Energy using appropriate vocabulary words.
Spelling, grammar conventions, sentence structure and visual choices that allow your reader to access the information you are providing.
Answer:
you will go no where as far as you wish because there is no air resistance or friction, causing you to not stop. In the real world, you would stop a little bit after you got done with the hill because you have friction and air Resistance to bring you to a stop. There is a huge difference because in real life, there is a lot of friction and air resistance in the real world, which will eventually bring someone to a stop no matter how fast they are going.
Explanation:
The work you do when pushing a shopping cart twice as far while applying double the force is
A) half as much
.B) twice as much.
C) four times as much.
D) the same amount.
The work you do when pushing a shopping cart twice as far while applying double the force is twice as much as force.
What is Force?
A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects. The force is no longer felt by the two objects when the interaction ends.
Contact forces are the kinds of forces that develop when two objects interact and appear to be in physical contact with one another. Frictional forces, tensional forces, normal forces, air resistance forces, and applied forces are a few examples of contact forces.
Forces that come from action at a distance.
Therefore, The work you do when pushing a shopping cart twice as far while applying double the force is twice as much as force.
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PLEASE ANSWERRRRRRRRRR
Looking at the solubility curve above for KClO3, at 30 degrees Celsius how many grams will dissolve to make a saturated solution?
At 30 degrees Celsius, a saturated solution of KClO3 will contain approximately 24 grams.
What is solution ?Solution: Plagiarism is the act of taking someone else's work or ideas and passing them off as your own. It is an unethical practice and is considered an academic offense. To avoid plagiarism, it is important to properly cite any sources that are used, including quotes, facts, images, and any other type of borrowed material. Additionally, it is important to give credit to the original authors of any ideas or works that are used. It is also recommended to paraphrase or re-word any material that is borrowed, so that it is not presented in the same exact form as the original. By following these steps, you can ensure that your work is completely plagiarism-free.
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Consider a circle whose size can vary. Let r represent the radius of the circle (in cm) and let c represent the circumference of the circle (in cm). Suppose the function f determines the circumference of the circle in cm, c , given its radius length in cm, r.
For the function g(x)=(√x−4x) / (x-11), its range is all real numbers less than or equal to 0, expressed as the interval \($(-\infty, 0]$\).
The function formula for f is \($C = 2 \pi r$\).
This implies that f(15) addresses the circumference (in cm) of a circle whose range is 15 cm.
On the off chance that f(a)=15, addresses the range (in cm) of a circle whose circumference is 15 cm.
The qualities that r can accept in this setting are genuine numbers more noteworthy than or equivalent to 0, communicated as the span \($[0,\infty)$\). The values that f(r) can assume in this context are all real numbers greater than or equal to 0, expressed as the interval \($[0,\infty)$\).
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The question is -
Consider a circle whose size can shift. Allow r to address the sweep of the circle (in cm) and allow C to address the periphery of the circle (in cm). Assume the capability f decides the boundary of the circle in cm, C, given its sweep length in cm, r.
Compose a capability equation for f.
What does f ( 15 ) address in this unique circumstance? Select all that apply.
A circle with a range of 15 cm.
The periphery (in cm) of a circle whose span is 15 cm.
A circle with a periphery of 15 cm.
The range (in cm) of a circle whose outline is 15 cm.
If f ( a ) = 15, what does an address in this specific circumstance? Select all that apply.
The sweep (in cm) of a circle whose periphery is 15 cm.
A circle with a periphery of 15 cm. A circle with a range of 15 cm.
The periphery (in cm) of a circle whose span is 15 cm.
What values could r at any point expect in this unique situation? Express your response as a span.
What values can f ( r ) expect in this specific circumstance? Express your response as a stretch.
Suppose g(x)=√x−4x/x-11.
Find the range of g.