What is the work energy theorem

Answer: See the diagram,from the vevtor addition we can say,net force acting on the apple is =

√

2.25

2

+

1.05

2

+

2

⋅

2.25

⋅

1.05

cos

90

=

2.48

N

And,this resultant force makes an angle of

tan

−

1

(

1.05

2.25

)

or,

25

degrees w.r.t vertical

Answer:

Upwards

Explanation:

when drawing free body diagrams you always point he arrow in the direction that it would move that object.

So gravity would move the object down, therfore the arrow is pointed down.

Normal force pushes the object up to oppose gravity therefore the arrow is also pointed up.

Furthermore...

If you push an object to the right, your force is moving the object to the right therefore the arrow would be pointed to the right also.

The  energy she has at each position shown are:

Velocity is known to be a term that connote the direction of any kind of a moving body or an object.

Note that the Speed is known to be a a scalar quantity and as such,  Velocity is said to be a vector quantity.

Note also that from the question given,  Jessica's height of the swing 3 meters above the ground, therefore:

Jessica Position at maximum height :

PE = mgh

PE = 44kg x  9.8m/s² x 3

PE = 1,294 J

Jessica  Position at minimum height:

PE = 0 J

Jessica  Position at maximum velocity:

KE = 1/2 x mv²

KE = 1/2 x 44kg x (5m/s²)²

KE = 550 J

Jessica  Position at minimum velocity:

KE = 0 J

Therefore, The  energy she has at each position shown are:

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Answer:

Explanation:

To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.

Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):

R = r + R1 + R2

Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:

R = 1Ω + 3Ω + 3Ω = 7Ω

Now we can calculate the current (I):

I = V / R = 14 V / 7Ω = 2 A

Therefore, the current flowing in the circuit is 2 Amperes.

Answer:

Wheres the table?

Explanation:

Answer:

L = 169.5 m

Explanation:

Using Ohm's Law:

V = IR

where,

V = Voltage = 1.5 V

I = Current = 10 mA = 0.01 A

R = Resistance = ?

Therefore,

1.5 V = (0.01 A)R

R = 150 Ω

But the resistance of a wire is given by the following formula:

\(R = \frac{\rho L}{A}\)

where,

ρ = resistivity = 1 x 10⁻⁶ Ω.m

L = length of wire = ?

A = cross-sectional area of wire = πr² = π(0.6 mm)² = π(0.6 x 10⁻³ m)²

A = 1.13 x 10⁻⁶ m²

Therefore,

\(150\ \Omega = \frac{(1\ x\ 10^{-6}\ \Omega .m)L}{1.13\ x\ 10^{-6}\ m^2}\\\\L = \frac{150\ \Omega(1.13\ x\ 10^{-6}\ m^2)}{1\ x\ 10^{-6}\ \Omega .m}\\\\\)

L = 169.5 m

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Answer:

the answer to ur questioj is 10 kg

Answer:82. Since you have a distance and a force, then the easiest principle to use is energy, i.e. work.

The work done by friction is F * d. This work cancels out the kinetic energy of the stone (1/2)mv^2

Fd = (1/2)mv^2

F = (1/2)mv^2/d.

Plug in m = 20 kg, v = 3 m/sec, d = 40 m.

83. With more mass, the kinetic energy is higher now. The work needed is higher. W = F * d and F is the same.

Explanation:Hope I helped :)

The average acceleration of the bus is −6.00 m/s².

a = ? ; Δt = 1.50 s ; v1 = 9.00 m/s ; v2 = 0.00m/s

The formula to use in this case is the definition of acceleration stating that the acceleration a = Δv / Δt or a = (v2- v1) / Δt where v2 is the final velocity and v1 is the initial velocity.

Solving for the acceleration a

a = (v2- v1) / Δt

a = (0 - 9.00 m/s) / 1.50 s

a = - 9.00 m/s / 1.50 s

a = −6.00 m/s^2

The average acceleration of the bus is −6.00 m/s^2.

The complete question is,
When a bus comes to a sudden stop to avoid hitting a dog, it slows from 9.00 m/s to 0.00m/s in 1.50 seconds. What is the average acceleration of the bus?

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The activation energy for the diffusion process of Al in Al2O3 is approximately 225,744 J/mol.

To calculate the activation energy for the diffusion process of Al in Al2O3, we can use the Arrhenius equation:

D = D0 * exp(-Q/RT)

where D is the diffusion coefficient, D0 is a constant, Q is the activation energy, R is the gas constant, and T is the absolute temperature.

Taking the natural logarithm of both sides, we get:

ln(D/D0) = -Q/RT

We can then use the given diffusion coefficients and temperatures to obtain two equations:

ln(D1/D0) = -Q/RT1

ln(D2/D0) = -Q/RT2

where D1 and T1 are the diffusion coefficient and temperature at 1000C, and D2 and T2 are the diffusion coefficient and temperature at 1500C.

Taking the ratio of the two equations, we get:

ln(D2/D1) = Q/R * (1/T1 - 1/T2)

Solving for Q, we get:

Q = -R * ln(D2/D1) / (1/T1 - 1/T2)

Plugging in the given values, we get:

Q = -8.314 J/mol-K * ln(2.48 x 10^-14 m^2/s / 7.48 x 10^-23 m^2/s) / (1/1273 K - 1/1773 K)

Q ≈ 225,744 J/mol

Therefore, the activation energy for the diffusion process of Al in Al2O3 is approximately 225,744 J/mol.

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Answer:

(1) 0.04 ohms (2) 55 ohms (3) 13 volt

Explanation:

(1) The resistance of an electric device is 40,000 microhms.

We need to convert it into ohms.

\(1\ \mu \Omega =10^{-6}\ \Omega\)

To covert 40,000 microhms to ohms, multiply 40,000 and 10⁻⁶ as follows :

\(40000 \ \mu \Omega =40000 \times 10^{-6}\ \Omega\\\\=0.04\ \Omega\)

(2) Voltage used, V = 110 V

Current, I = 2 A

We need to find the resistance of the iron. Using Ohms law to find it as follows :

V = IR, where R is resistance

\(R=\dfrac{V}{I}\\\\R=\dfrac{110}{2}\\\\R=55\ \Omega\)

(3) Current, I = 0.2 A

Resistance, R = 65 ohms

We need to find the applied voltage in the circuit. Using Ohms law to find it as follows :

V=IR

V = 0.2 × 65

V = 13 volt

Answer:

1. 0.04 Ohms

2. 55 Ohms

3. 13 Volts

Explanation:

Penn Foster

The relationships between average speed (s), velocity (v), and acceleration can be shown shown graphically by plotting their values with time

a. The time required for the entire process is 22 seconds

The required graphs to question b, c, and d are attached

The reasons the above value for time and the attached graph are correct are given as follows:

The given parameters are;

The distance due west travelled by the train = 70 m

The speed in the western direction = 5 m/s

The distance due east the train then travelled = 32 m

The speed of the train while travelling east = 4 m/s

a. The time required for the entire process, t, is given as follows;

\(Time = \dfrac{Distance}{Velocity}\)

Therefore, the total time, t = (70 m/(5 m/s)) + (32 m/(4 m/s)) = 22 s

The time required for the entire process is 22 seconds

b. The table of values (obtained with MS Excel) are as follows;

Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

Avg. Speed: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 4.9, 4.875, 4.8, 4.78, 4.74, 4.7, 4.67, 4.64

Please find attached the required graph of average speed versus time

c. The table of values are as follows;

Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

Velocity: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, -4, -4, -4, -4, -4, -4, -4, -4

Please find attached the required graph of velocity versus time

d. The table of values are as follows;

Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

Acceleration: DNE, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -9, 0, 0, 0, 0, 0, 0, 0

Please find attached the required graph of acceleration versus time

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- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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Answer:

the distance x increases as the student increase the mass of the cannon.

Explanation:

a) From the question ; we get to understand that for each launch, the students use a different mass which is launch at  speed v relative to the ground.

This changes in the mass used brought about a change in the momentum at the same speed v ; perhaps an increase in momentum. However; since the conservation of the momentum is considered at each launching.

The momentum of the marble = momentum of the cannon

But since the momentum of the cannon increase ; therefore the same equivalent changes takes place in its kinetic energy . Therefore , the kinetic energy will increase and the distance will also increase in the bid to quench the amount of energy generated. Thus, the distance x increases as the student increase the mass of the cannon.

b)We all know that  conservation of the momentum will definitely  takes place after launching of the cannon.

Let assume that \(\rho\) is the momentum of the cannon with mass \(M_C\)

The kinetic energy of the canon will be:

\(\frac{\rho ^2 }{2 M_C}\)

Also the frictional force acting on the cannon is :

\(f = \mu mg\)

If the cannon move at an  additional distance x; the frictional force acting at this area quench the amount of the energy generated and consume the kinetic energy of the cannon;

So;

\(fx = K.E\)

\(fx = \frac{\rho ^2 }{2 M_C}\)

\(\mu mg x = \frac{\rho ^2 }{2 M_C}\)

\(x = \frac{\rho ^2 }{2 \mu mg M_C}\)

\(x = \frac{m_m^2 V^2 }{2 \mu mg M_C}\)

Thus; it is consistent with the answer in (a) as increase in the mass of the marble will bring about an increase in distance x

The increase in the mass of the marble increase the distance of the cannon.

Momentum:

Momentum of an object is equal to the product of the mass and the velocity of the object.

The kinetic energy of the cannon

\(K_C = \dfrac {\rho^2}{2 M_C}\)

Where,

\(\bold{\rho}\) - momentum of the cannon

Mc -  mass

The frictional force on cannon

\(\bold{F_f = \mu mg}\)

Cannon move a distance x,

Hence,

\(\bold {F_f \times x = K_C}\\\\\bold {\mu m g \times x = \dfrac {\rho^2}{2 M_C }}\\\\\bold {x = \dfrac {\rho^2}{2\mu m g M_C }} }\\\\\bold {x = \dfrac {m^2 V^2}{2\mu m g M_C } }\)

Therefore, The increase in the mass of the marble increase the distance of the cannon.

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The spaces labeled 1 through 14 in the diagram using the following terms are:

Plate tectonics is the scientific theory that explains the large-scale motions of Earth's lithosphere (the outermost layer of the Earth) and the processes that cause these motions. The lithosphere is divided into a number of large plates that move relative to each other over the asthenosphere, the more plastic, ductile, and weaker layer below the lithosphere.

Plate tectonics explains a variety of geologic phenomena, including the formation of mountains, earthquakes, volcanoes, and the distribution of continents and oceans. According to this theory, the lithospheric plates move due to the motions of convection cells in the Earth's mantle, which is the layer below the asthenosphere.

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Answer:

C. the core

Explanation:

since it has the most energy and the hottest layer

Answer: its d

Explanation:

5.48 V is the potential drop across the cable for a copper transmission cable of 50.0 km long and 10.0 cm in diameter carries a current of 105 A

Ohm's Law states that the potential drop is determined by the equation: V = IR, where I is the current and R is the wire resistance.
R=PL/A
Under the assumption that all physical parameters and temperatures remain constant, Ohm's law asserts that the voltage across a conductor is directly proportional to the current flowing through it.

Only when the given temperature and the other physical variables remain constant does Ohm's law apply. Increasing the current causes the temperature to rise in some components. The filament of a light bulb serves as an illustration of this, where the temperature increases as the current increases. Ohm's law cannot be applied in this situation. The filament of the lightbulb defies Ohm's Law.

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The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms

The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

With the above formula, we can obtain the value of R₂. Details below:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

2 = (6 × R₂) / (6 + R₂)

2 = 6R₂ / (6 + R₂)

Cross multiply

2 × (6 + R₂) = 6R₂

Clear bracket

12 + 2R₂ = 6R₂

Collect like terms

12 = 6R₂ - 2R₂

12 = 4R₂

Divide both sides by 4

R₂ = 12 / 4

R₂ = 3 ohms

Thus, we can conclude that the value of R₂ is 3 ohms

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Explanation:

The power P dissipated by a heater is defined as

\(P = VI\)

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

\(I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}\)

b) The resistance R of the heater is

\(P = VI = (IR)I = I^2R\)

where \(V= IR\) is our familiar Ohm's Law.

\(\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}\)

\(R = 110.8\:Ω\)

The current running through the heater when it is operating is 1.08 A.

The resistance of the heater is 110.8 ohm.

So, from the above equation we can calculate,

              current I = P/V

                      ∴   I = 130 / 120

                      ∴   I = 1.08 A

So, from the equation we can calculate,

                   Resistance R = P/I^2

                                  ∴  R = 130/(1.08)^2

                                  ∴  R = 110.8 ohm

Thus, the current running through the heater when it is operating is 1.08 A.

The resistance of the heater is 110.8 ohm.

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Answer:

The correct option 50.0 m (the units of the answers are wrong, they should be in meters and not in millimeters).  

Explanation:

From the first second we can find the acceleration of the object:

\( X_{f} = X_{0} + V_{0}t + \frac{1}{2}at^{2} \)

Where:

\(X_{f}\): is the final position = 2.00 m

\(X_{0}\): is the initial position = 0

\(V_{0}\): is the initial speed = 0 (starts from rest)

t: is the time = 1 s

The acceleration is:

\( a = \frac{2X_{f}}{t^{2}} = \frac{4.00 m}{(1 s)^{2}} = 4.00 m/s^{2} \)      

Now, we can find the distance after 5 seconds:

\(X_{f} = X_{0} + V_{0}t + \frac{1}{2}at^{2} = \frac{1}{2}*4.00 m/s^{2}*(5 s)^{2} = 50.0 m\)                  

Therefore, the correct answer is 50.0 m. All the options have the units in millimeters and not in meters hence, the units of the options are wrong.

I hope it helps you!        

The final position of the object after 5 seconds is 50 m.

Option D is the correct answer.

Given that the object starts from rest and accelerates uniformly. It moves 2.00m during the first second.

Let us consider that the initial velocity is v and the initial position is x and the final position is x' for time interval t.

Hence for the given condition, t = 1 s, x' = 2 m, v = 0 m/s and x = 0 m. The acceleration can be calculated as given below.

\(a = \dfrac {2x'}{t^2}\)

\(a = \dfrac {2\times 2}{1}\)

\(a = 4 \;\rm m/s^2\)

The final position of the object after 5 seconds is given below.

\(x (\rm final) = x + vt + \dfrac {1}{2}at^2\)

Substituting the values in the above equation.

\(x(\rm final) = 0 + 0 + \dfrac {1}{2}\times 4 \times 5^2\)

\(x (\rm final) = 50 \;\rm m\)

Hence we can conclude that the final position of the object after 5 seconds is 50 m. Option D is the correct answer.

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This question involves the concepts of heat capacity, temperature, and heat.

The heat absorbed by ethanol is "1228 cal".

The heat capacity of a substance is defined as the amount of heat absorbed by a unit amount of that substance for a degree rise in temperature. Mathematically,

\(Q = mc\Delta T\)

where,

Therefore,

Q = (50 g)(0.614 cal/g°C)(40° C)

Q = 1228 cal

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The given statement is false.

Atlanta which is in Georgia have high temperatures during summer.

Although Georgia is near ocean but Atlanta is landlocked.

This place is also located a bit towards the tropic of cancer and this altitude is near to the equator.

With such a location, it is justified for the summers to be hot.

But in comparison to car, medium sized homes tend to cool down faster.

This is because of the good ventilation in the houses.

While in car, already the body is heat absorbing and traps heat in summer which then leads to the switching on of ACs in the car.

While in such hot summer when the AC is turned on then the ventilation becomes null. Which makes the hot air rise above and the cool air settle down.

But since there's no way for hot air to move, it remains inside the car and make it hotter in the summer and this in turn make people turn on their AC at cooler temperature and for longer time, thus consuming in more energy.

While in house, due to proper ventilation, there's a movement maintained in the atmosphere.

Therefore, it takes more energy to cool a hot car than it does to cool a medium-sized house in Atlanta during summer.

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The reflection law allows us to find that the correct statement for  where a ray is located in a concave mirror is:

Geometric optics studies the geometric properties of light rays by surfaces. It has two laws that describe it:

                     \(\theta_i = \theta_r\)

Now we can analyze the expressions.

a) False. This only happens if the object is at infinity

b) True. This is the law of reflection that the angles are equal and it always complies

c) False the optical axis is a perpedicular line to the mirror, therefore the ray must be parallel to the mirror and is not reflected.

In conclusion using the reflection law we can find which statement is correct

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Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.

To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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The three significant figures are ΔV2-3 = -785 J, W2-3 = 785.7 J and W3-1 = -558.72 J

Number of moles n=0.350

r = 1.40

| ΔV1-2 | = 2180 J   | ΔV2-3| = 785 J

| Δ V3-1 | = 1396 J

From first law of thermodynamic

Q = ΔV + W

Internal Energy increases in this case as the temperature is increasing ΔV is positive and work done in a constant volume process is 0 as

W1-2 = P ΔV = P (O) = O

Q1-2 = Δ V1-2 + W1-2 = ΔV1-2 + O

Q1-2 = 2180 J

Change in internal energy is negative since temperature is decreasing as

R = 8.314 J

Δv2-3 = -785 J

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Answer:

A. The water

Explanation:

i got it right on A-P-E-X

The volume of the gas is calculated as 1827.87cm^3

Data;

To find the final volume of oxygen, we have to use Boyle's law which states that the volume of a gas is inversely proportional to the pressure of the gas provided that temperature remains constant.

v ∝ 1/p

\(v = \frac{k}{p} \\k = pv\\p_1 v_1 = p_2 v_2\)

Let's substitute the values into the equation and solve.

\(p_1v_1 = p_2v_2\\101325*300 = 16630 * v_2\\30397500 = 16630v_2\\v_2 = \frac{30397500}{16630} \\v_2 = 1827.87cm^3\)

The volume of the gas is calculated as 1827.87cm^3

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