What is the expected effect of placing a plant into a hypotonic solution?.

Answers

Answer 1

When a plant is placed in a hypotonic solution, the cell will expand or swell, and may ultimately burst, resulting in plasmolysis.

Placing a plant into a hypotonic solution will have an expected effect on the plant cells. In a hypotonic solution, the concentration of solutes outside the cell is lower than the concentration inside the cell. Therefore, water moves from an area of high concentration to an area of low concentration, causing the cell to swell up and expand. Eventually, the cell may burst, a process known as cytolysis.

The excess water will cause the cell membrane to stretch, putting pressure on the cell wall. The cell wall protects the cell, but too much pressure can cause the cell wall to break and the cell to burst. Plants in hypotonic solutions become turgid, or swollen, but may not survive due to plasmolysis, which can occur if too much water enters the cell and the cell wall cannot support the increased volume. This process causes the cytoplasm to shrink and detach from the cell wall.

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Related Questions

8. True or False:When purchasing motor oil at retail make sure the packaging has the "Stardust" and "Cronut" certification and performance marks

Answers

It is false that you should look for the "Stardust" and "Cronut" certifications and performance markings on motor oil packaging while buying it at a store.

Scale Range For Motor:

The motor scale ranges from 0W, the thinnest type of oil, to a rating of 60, the thickest type of oil. Because this section of the label displays the viscosity level of oil when an engine is cold, the "W" you see on oil labels stands for the word "Winter."

As a result, 15W-40 and 20W-50 oils were created with hotter regions in mind, whereas 0W-20 and 5W-30 oils were created for cooler areas. Your best choice is to rely on the car's oil life monitoring system to alert you when it's time for a replacement in many newer vehicles. The best location to find your maintenance schedule is in your owner's manual.

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What would your estimate be for the age of the universe if you measured hubble's constant to be 11 kilometers per second per million light-years?

Answers

By using Hubble's constant H₀, the estimated age of the universe would be 27,269,816,110  years.

As we know that the age of the universe is something near to the time the galaxies needed to reach their current distance:

T = D/V

where T is the time the galaxies needed, D is distance and V is speed.

By using Hubble's law we can use the equation

V = H₀*D

where H₀ is Hubble's constant

By combining these 2 equations, we get

T = D/(H₀*D) = 1/H₀ .............(A)

In conclusion, the age of the universe is something near the inverse of Hubble's constant.

From the question above, we know that:

H₀ = 11 km/s/Mly

By using equation A we get

T = 1/(11 km/s*Mly)

T = (1/11)  s*Mly/km

Convert 1 million light-years to km by (1 ly = 9.461*10^12 km)

T = (1/11) s*Mly/km

T = (1/11)*9.461*10^18 s

T = 8.6009*10^17 s

Convert to years by (1 year = 3.154*10^7 s)

T = 8.6009*10^17 s

T = (8.6009*10^17 s/3.154*10^7 s)* 1 yea

T = 27,269,816,110 years.

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What is a Weather Front​. in your own words but be more detailed about what you say.

Answers

Explanation:

A weather front is a boundary separating air masses of several characteristics eg. Air density, wind and humidity. Disturbed weather often arises from these differences

How do scientists determine the number of neutrons in an isotope of an atom?


They subtract the atomic number from the atomic mass.


They find the number of protons.


They divide the atomic mass by two.


They add the number of electrons and protons.

Answers

Answer:

They subtract the atomic number from the atomic mass

Hope this helps

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determine the period of an asteroid with an orbital radius of four astronomical units.

Answers

The period of an asteroid with an orbital radius of four astronomical units is 8 years.

The period of an asteroid with an orbital radius of four astronomical units can be determined using Kepler's third law, which states that the square of the period is proportional to the cube of the semi-major axis of the ellipse that the asteroid follows, or:P² = a³, where P is the period in years and a is the semi-major axis in astronomical units (AU).Since the asteroid has an orbital radius of four AU, its semi-major axis is also four AU, which means:P² = 4³P² = 64P = sqrt(64)P = 8The period of the asteroid is 8 years.

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What is the electric potential 3. 0×10−11 m from a proton (charge +e )? Let V=0 at r=[infinity]

Answers

This question involves the concepts of electric potential, charge, and distance.

The electric potential is "48 V".

ELECTRIC POTENTIAL

The electric potential of a point in the vicinity of a charge is given by the following formula:

\(V=\frac{kq}{r}\)

where,

V = electric potential = ?k = Colomb's constant = 9 x 10⁹ N.m²/C²q = magnitude of charge = 1.6 x 10⁻¹⁹ Cr = distance from charge = 3 x 10⁻¹¹ m

Therefore,

\(V = \frac{(9\ x\ 10^9\ Nm^2/C^2)(1.6\ x\ 10^{-19}\ C)}{3\ x\ 10^{-11}\ m}\)

V = 48 volts

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A thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center. A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s2, calculate the magnitude of F.

a. 35 N
a. 20 N
c. 25 N
d. 8 N

Answers

Given :

Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.

A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².

To Find :

The magnitude of F.

Solution :

Torque on hoop is given by :

\(\tau =F\times R\\\\I\alpha = FR\\\\MR^2\alpha = FR\\\\F = MR\alpha\)( Moment of Inertia of hoop is MR² )

Putting  value of M, R and α in above equation, we get :

\(F=5\times 2\times 2.5\ N\\\\F = 25 \ N\)

Therefore, the magnitude of force F is 25 N.

Hence, this is the required solution.

Compared to the nucleus 5626Fe, what is the radius of the nucleus 112 48Cd?
Compared to the nucleus , what is the radius of the nucleus ?
the same
11256=2 times as large
4826=2 times as large
2?=1.41 times as large
2?3=1.26 times as large

Answers

To determine the relative size of nuclei, you can use a simple relationship known as the "semi-empirical mass formula" or the "liquid drop model." According to this model, the radius of a nucleus is proportional to the cube root of its mass number (A).

Let's compare the nuclei:

For the nucleus 56^26Fe, the mass number (A) is 56.

For the nucleus 112^48Cd, the mass number (A) is 112.

To find the relative size of the nuclei, we can compare the cube roots of their mass numbers.

For the nucleus 56^26Fe:

Cube root of 56 = ∛56 ≈ 3.78

For the nucleus 112^48Cd:

Cube root of 112 = ∛112 ≈ 4.83

Comparing the cube roots, we find that the cube root of 112^48Cd is approximately 1.28 times larger than the cube root of 56^26Fe. Therefore, the radius of the nucleus 112^48Cd is about 1.28 times larger than the radius of the nucleus 56^26Fe.

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A student climbs to the top of the gym and drops a baseball to the ground below. A physics student standing nearby has a motion sensor and determines that the baseball hit the ground with a velocity of 17 m/s. if you ignore air resistance, how long was the baseball falling through the air?​

Answers

Answer:

The baseball was falling during 1.733 seconds.

Explanation:

The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground (\(t\)), measured in seconds, which is determined by the following kinematic formula:

\(t = \frac{v-v_{o}}{g}\) (1)

Where:

\(v_{o}\), \(v\) - Initial and final speeds of the baseball, measured in meters per second.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v = 17\,\frac{m}{s}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the time spent by the baseball is:

\(t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s} }{9.807\,\frac{m}{s^{2}} }\)

\(t = 1.733\,s\)

The baseball was falling during 1.733 seconds.

how to find average velocity on a velocity time graph

Answers

To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.

To calculate the average velocity, you can use the formula:

Average velocity = (change in velocity) / (change in time)

You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.

Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.

It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.

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A 45 kg puggle and a 130 kg puma are at a standoff (staring at each other) with a distance 70 m between them. What is the magnitude of the force of gravity between the puggle and the puma?

Answers

Answer:

It should be normal force if it's not right plz forgive me.

Explanation:

The force of gravity between the puggle and the puma is  7.7×10⁻¹¹ Newton.

Given parameters:

Mass of the puggle; m =45 kg

Mass of the puma : M = 130 kg.

Distance between them; r = 70 m.

Then,  the magnitude of the force of gravity between the puggle and the puma is; F = GmM/r²

Where, G = universal gravitational constant = 6.6×10⁻¹¹ Si unit.

So, Gravitational force; F = ( 6.6×10⁻¹¹ )×130×45 ÷ (70)² N = 7.7×10⁻¹¹ Newton.

Hence, the magnitude of the force of gravity between the puggle and the puma is  7.7×10⁻¹¹ Newton.

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True or False?
It is easier to carry an empty backpack than a backpack full of books. This is an example of Newton’s 2nd law.

Answers

the answer would be true

Answer:

The answer iis true

Explanation:

It is much easier to carry your backpack when it is empty rather than when it's full of textbooks (or soaked from the rain).

The main difference between obsessive-compulsive personality disorder (OCPD) and obsessive-compulsive disorder (OCD) is that __________.

people with OCPD know their disorder is irrational
people with OCD know their disorder is irrational
OCPD is an anxiety disorder consisting of disturbing thoughts
OCD is a mood disorder consisting of disturbing behaviors

Answers

Answer:

B. people with OCD know their disorder is irrational

Explanation:

Got it right

Answer:

B

Explanation:

Edge2021

5 ohms resistors are connected in parallel, the equivalent resistance is?​

Answers

How many resistors and is it the same value?
The formula you use is 1/Rt= 1/R1+1/R2

At rest, hydrogen has a spectral line at 150 nm. if this line is observed at 168 nm for the star proxima, how fast is proxima moving in km/s?

Answers

Proxima is moving at approximately 240 km/s.

To determine the velocity of the star Proxima, we can use the concept of redshift in the observed spectral lines. The formula for calculating the velocity based on redshift is:

v = (λ_observed - λ_rest) / λ_rest * c

v is the velocity of the star (in km/s)

λ_observed is the observed wavelength (168 nm)

λ_rest is the rest wavelength (150 nm)

c is the speed of light (approximately 300,000 km/s)

v = (168 nm - 150 nm) / 150 nm * 300,000 km/s

v = 0.12 / 150 * 300,000 km/s

v = 0.12 * 2,000 km/s

v = 240 km/s

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if a neutral metal object has been charged by friction to a charge of one pc, what has happened to it electrically?

Answers

If a neutral metal object has been charged by friction to a charge of one pc (picocoulomb), it means that the object has become electrically charged.

When two objects are rubbed together, electrons can be transferred from one object to another, causing a charge imbalance. In this case, the friction has resulted in the transfer of electrons to the neutral metal object, giving it a net negative charge.

The charge of one pc indicates the magnitude of the net charge acquired by the object. A charge of one pc is equivalent to approximately 1.6 × 10^-13 coulombs.

Therefore, the neutral metal object has become electrically charged with a net negative charge of one pc as a result of the friction-induced electron transfer.

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How are water scarcity and water pollution related?
Water pollution contributes to water scarcity.
Water pollution is a solution to water scarcity.
Water scarcity is a solution to water pollution.
Water scarcity contributes to water pollution.

Answers

Answer:

A. Water pollution contributes to water scarcity.

Explanation:

Water pollution occurs when materials are disposed in water body, thus making it unfit for use. A polluted water can not be used for various purposes that water can be used for. Examples include: recreation, drinking, washing etc.

Water scarcity is the situation when available water is not sufficient for the use of organisms in a community. This majorly occurs in arid area.

Thus, since a polluted water renders water to be useless, therefore water pollution contributes  to water scarcity.

Answer:

Water contributes to water scarcity

Explanation:

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The source of all magnetic fields is:
- moving charges
- the earth's gravity
- the aurora borealis
- solar fields

Answers

Answer:

Moving charges

Explanation:

The source of all magnetic fields is moving electric charge: whether it is current in a wire, unpaired electrons in an atomic orbital, convection currents in the earth's liquid nickle /iron core, plasma in the sun, etc. moving electric charge is the source of all magnetic fields.

please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U DON'T KNOW THE ANSWER PLS DON'T ANSWER AT ALL​

please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U

Answers

Answer:

a)

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

1 What conclusion can you draw about semicircular canals from their name ? A Their shape B Their size Their location in your body D Their function Their function

Answers

Answer:

A. Their shape

Explanation:

The name clearly shows that the shape of these canals are semi-circular. The semi-circular canals consist of three tubes filled with fluid and located in the inner ear. They help to maintain balance and transmit impulses through the movement of the fluids. The impulses sent through these fluids are sent to the brain for interpretation.

The function of the canals are not indicated by the name, rather the shape is hinted through the name.

If the distance between the south poles of two long bar magnets is reduced to half its original value, will the force between these poles be doubled? Explain

Answers

The repulsive force between the poles will be quadrupled.

Coulomb's law in magnetism

It states that the force of interaction between two fixed magnetic poles is directly proportional to the product of the strengths of the magnetic poles. The force of interaction between two fixed poles is inversely proportional to the square of the distance between the two poles.

According to Coulomb, the electric force on a static charge has the following properties:

(1) Like charges repel  and dissimilar charges attract. Two negative charges repel each other and a positive charge attracts a negative charge.

(2) Attraction or repulsion acts along a line between  two charges.  

(3) The magnitude of the force is inversely proportional to the square of the distance between the two charges.

Therefore, when the distance between  two charges is reduced to half, the attractive or repulsive force become four times stronger. If the charge is 10 times closer, the magnitude of the force will be 100 times greater.

(4) The magnitude of the force is proportional to the value of each charge.

The unit for measuring electric charge is the coulomb (C).

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explain how you can calculate the magnitude of friction between surfaces using only a block and force probe

Answers

You can calculate the magnitude of friction between surfaces using only a block and force probe, follow the steps: Place the block on the surface, Attach the force probe, Apply a horizontal force, Calculate the magnitude of friction, and Analyze the result.

To calculate the magnitude of friction between surfaces using only a block and a force probe, follow these steps:

1. Place the block on the surface: Position the block on the surface you want to measure the friction between. Ensure that the surface is level and free from debris.

2. Attach the force probe: Connect the force probe to the block. Make sure it's securely attached and calibrated according to the manufacturer's instructions.

3. Apply a horizontal force: Slowly apply a horizontal force to the block using the force probe until the block begins to move. Record the force value at the moment when the block starts to move.

4. Calculate the magnitude of friction: The recorded force value represents the maximum static friction force between the block and the surface. To calculate the magnitude of the friction coefficient (µ), use the equation:

µ = F_friction / F_normal

Here, F_friction is the recorded friction force, and F_normal is the normal force acting on the block, which is equal to the block's weight (mass x gravitational acceleration).

5. Analyze the result: The calculated value of µ will give you the magnitude of the friction coefficient between the block and the surface. This will help you understand the level of friction between the two materials.

By following these steps, you can calculate the magnitude of friction between surfaces using only a block and a force probe.

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1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"

Answers

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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3. Is converting wood into saw dust a reversible change? Give one reason for your answer

Answers

No, conversion of wood to sawdust is an irreversible change, because a block of wood after grounding into sawdust cannot be changed into the same block of wood

A dog walks 12 meters to the west and then 16 meters back
to the east.

Answers

The dog covered 28 m of distance, magnitude of displacement is 4m and direction is in east.

Distance is a scalar quantity that describes how much ground an object covers while moving, and displacement is a vector quantity that describes how far an object has travelled. This is the global change in the object's position.

We know that total distance travelled = 12 m + 16 m = 28 m.

First the dog walks 12m west, but then walks back 16m east. That means you have to subtract the distances to get the displacement.

Displacement = 12 - 16 = -4m (4m to the east, because the distance can never be negative)

Full question here :

Q. A dog walks 12 meters to the east and then 16 meters back to the west. For this motion, what is the distance moved? What is the magnitude and direction of the displacement?

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Is the force of gravity the same at all points in the orbit?

Answers

Answer:

No

Explanation:

orbits are generally an ellipse shaped ....when the two planets are nearest to each other the gravity is strongest .

  IF THE ORBIT IS A PERFECT CIRCLE , the gravity will always be the same between the two bodies .

If the wavelength is 10 m and the frequency is 5 Hz, what is the wave speed?

Answers

V = f x wavelength
V = 5 x 10
V = 50m/s

(b)
Describe how the horizontal forces acting on the car change during the first two seconds
of the acceleration.

Answers

Answer:

Driving force increases, friction forces increase, the driving force is bigger than friction 12.

Explanation:

You weigh 580 N on Earth. If you were to go to Mars, where its gravitational pull is 3 . 7 11 m /s 2 , what would you weigh? (Hint: gravity on Earth is 9.8 m /s 2 .

Answers

Answer:

59.18 kg

Explanation:

use f=ma

f= 580 N

a = 9.8 m/s 2

weigh(m) doesn't change only force(F) changes

Answer: 219.6N

Explanation:

Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma

580 = m*9.8

m = 59.18kg

Then multiply the mass by the new gravitational acceleration on Mars.

59.18*3.711 = 219.6N

PLEASE HELP!!!! i will give brainliest to the first person...

PLEASE HELP!!!! i will give brainliest to the first person...

Answers

Answer: Fossil fuels power the machine that shakes the tree so the apples fall to the ground

Explanation: most machines are powered by fossil fuels

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