what is the definition of equilibrium? do chemical reactions stop occurring once cquilibrium is reached?

The specific heat/temperature of aluminum is 523.4 J/g °C.

The specific heat of aluminum can be determined by utilizing the following formula:Heat lost by aluminum = heat gained by water + heat gained by calorime terInitial temperature of Al = 83.85 °C Final temperature of Al = final temperature of water and calorimeter = 23.90 °C Density of water = 1.00 g/mlVolume of water = 51.8 mlCalorimeter constant = 22.44 J/°CInitial temperature of water = 20.30 °CSpecific heat of water = 4.184 J/g. °CCalorimeter's mass is assumed to be negligible.The heat lost by aluminum = Heat gained by water + Heat gained by calorimeter, so we can say,Heat lost by aluminum = m × s × ΔT (1)Where, m = mass of aluminum, s = specific heat of aluminum, and ΔT = temperature change in aluminumHeat gained by water = m × s × ΔT (2)Where, m = mass of water, s = specific heat of water, and ΔT = temperature change in waterHeat gained by calorimeter = C × ΔT (3)Where, C = calorimeter constant, and ΔT = temperature change in calorimeterSubstitute the given values in equations 1, 2 and 3 and solve for the specific heat of aluminum:m × s × ΔT = m × s × ΔT + C × ΔTs = C × ΔT/m - ΔT = (23.9 °C - 20.3 °C) = 3.6 °CTemperature change in aluminum = (83.85 - 23.90) = 59.95 °CCalorimeter constant = 22.44 J/°CMass of aluminum = 16.27 gVolume of water = 51.8 mlDensity of water = 1.00 g/mlMass of water = volume × density = 51.8 gUsing equation (1) and (2), we have:m × s × ΔT = m × s × ΔT + C × ΔT16.27 g × s × 59.95°C = 51.8 g × 4.184 J/g. °C × 3.6°C + 22.44 J/°C × 3.6°C16.27 g × s = 8513.21 J/°Cs = 8513.21 J/°C ÷ 16.27 g = 523.4 J/g °C. Therefore, the specific heat of aluminum is 523.4 J/g °C.

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The dot and cross diagram is a way of representing a molecule along with its valence electrons and respective bonds. Valence electrons are drawn as a dot or a cross, each element will have a different connotation. Around the atoms, circles are drawn that indicate the bonds and how the electrons are shared.

Carbon has 4 valence electrons and oxygen has 6, the dot-and-cross diagram of CO2 will be:

Answer:

solid liquid and gas

Explanation:

ice is a solid then it melts to liquid and evaporates into gas

Answer:

Snow is basically water;

ice/snow is solid state

water is liquid state

vapour is gaseous state

Explanation:

Answer:

The isopropanol evaporated while the water did not because the molecules don't stick together as strongly as the molecules in the water do. The water would need more energy transferred in, in order to evaporate.

Explanation:

The isopropanol evaporates and the water does not because the heat capacity and the latent heat of isopropanol is far lesser than that of water.

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Answer:

i think its the first one

Explanation:

im new to chemistry as while but im not completely sure.

Answer: The given statement is True.

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

Thus the given statement is True.

In the given reaction, the compound Cr2O7 2- is reduced.

In the balanced chemical equation provided, the compound Cr2O7 2- undergoes reduction. Reduction refers to the gain of electrons or a decrease in the oxidation state of an element in a chemical reaction. In this reaction, Cr2O7 2- is reduced to Cr3+. The oxidation state of chromium (Cr) in Cr2O7 2- is +6, while in Cr3+, it is +3. This reduction process involves the transfer of electrons from the Cr2O7 2- ion to another species involved in the reaction. The reduction of Cr2O7 2- results in the formation of Cr3+ ions as one of the products of the reaction.

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Answer:

A weather balloon also known as sounding balloon is a balloon that carries instruments aloft to send back information on atmospheric pressure, temperature, humidity and wind speed by means of a small, expendable measuring device called a radiosonde

Explanation:

Answer:

A weather balloon also known as sounding balloon is a balloon that carries instruments aloft to send back information on atmospheric pressure, temperature, humidity and wind speed by means of a small, expendable measuring device called a radiosonde.

Explanation:

I hope this helps :)

Answer:

$8.00

Explanation:

5 yards = $40.00

1 yard = x

therefore, x = $40.00/5

x = $8.00

i.e, 1 yard = $8.00

Answer:

we know that it was the vinegar and baking soda because gas had been created, the gas was held within the bubbles. the gas that was created was called Carbon Dioxide or CO2

Answer:

it is ductile

Explanation:

i took the test

Answer:

b

Explanation:

The molarity of the solution is 0.08 M.

First, we need to calculate the number of moles of Na2CO3 present in the solution:

moles Na2CO3 = mass / molar mass

moles Na2CO3 = 10.6 g / 106 g/mol

moles Na2CO3 = 0.1 mol

Next, we can calculate the molarity of the solution:

Molarity = moles of solute / liters of solution

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M

Therefore, the molarity of the solution is 0.08 M.

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The molarity of the solution is 0.08 M.

What is Molarity?

Molarity is a useful measure in chemistry because it allows us to compare the concentration of different solutions on a common scale. For example, if we have two solutions with different volumes and concentrations, we can calculate their molarities and compare them directly.

The unit of molarity is typically expressed as "moles per liter" (mol/L), although it can also be written as "molar" or "M".

First, we need to calculate the number of moles of Na2CO3 present in the solution:

moles Na2CO3 = mass / molar mass

moles Na2CO3 = 10.6 g / 106 g/mol

moles Na2CO3 = 0.1 mol

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M

Therefore, the molarity of the solution is 0.08 M.

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Answer:

A i believe

Explanation:

The majority of valence electrons are negatively charged particles, and they are all grouped in various orbitals or shells. Additionally, these electrons are in charge of how atoms interact with one another and create chemical bonds.

An element is defined as the pure substance which consists of only one type of atom which all have the same numbers of protons in their nuclei. Elements are the simplest chemical forms which cannot be broken down through chemical reactions.

Here the element potassium has the atomic number 19 and its electronic configuration is 2, 8, 8, 1. It contains the four energy levels, they are 'K', 'L', 'M' and 'N'. The number of valence electrons in potassium is 1.

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Your question is incomplete, most probably your full question was:

Which element has 1 valence electron and 4 energy levels?

Answer:

The earth's crust is the thickest under high mountains.

Explanation: Continental crust

Answer:

36.2874 $

Explanation:

1 ton = 907.185 kilograms.

907.185 x 0.04 =

36.2874

-kiniwih426

According to unit conversion,cost of coal in dollars per ton if it costs $0.04 per kilogram is 80 dollars per ton.

Unit conversion is defined as a multi-step process which involves multiplication or a division operation by a numerical factor.The process of unit conversion requires selection of appropriate number of significant figures and the rounding off procedure.

It involves a conversion factor which is an expression for expressing the relationship between the two units.A conversion ratio always has value which equals to one which indicates that numerator and denominator have values which are expressed in different units.

First, we need to convert the cost per kilogram to dollars per ton. There are 2000 kilograms in a ton. So, the cost per ton is $0.04/kilogram × 2000 kilograms/ton = $80/ton.

So the answer is 80 dollars per ton.

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The balanced reduction half reaction is:

8H+ + 5e- + \(MnO_4\)- → \(Mn^2\)+ + \(_4H_2O\)

1. Identify the elements undergoing oxidation and reduction in the given reaction:

  - \(MN^2\)+ is being oxidized to \(MN^4\)+.

  - \(H_2SO_3\) is being reduced to \(HNO_2\).

2. Write the half-reactions for each process:

  Oxidation half-reaction: \(MN^2\) + → \(MN^4\) + + 2e-

  Reduction half-reaction: \(H_2SO_3\) + 2H+ + 2e- → \(HNO_2\) + \(H_2O\)

3. Balance the number of atoms in each half-reaction:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_2HNO_2\) + \(_2H_2O\)

4. Balance the number of hydrogen atoms by adding H+ ions to the side lacking hydrogen:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_ 2HNO_2\) + \(_2H_2O\)

5. Balance the number of oxygen atoms by adding H2O molecules to the side lacking oxygen:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- →\(_ 2HNO_2\) + \(_2H_2O\)

6. Balance the charge on both sides of the equation by adding electrons:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_2HNO_2\) + \(_2H_2O\)

7. Multiply each half-reaction by the appropriate factor to equalize the number of electrons transferred:

  Oxidation half-reaction: \(2MN^2\)+ → \(2MN^4\)+ + 4e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_2HNO_2\) + \(_2H_2O\)

8. Finally, combine the half-reactions and cancel out any common terms:

  2\(MN^2\)+ + \(_2H_2SO_3\) + 4H+ + 4e- → \(2MN^4\)+ + \(_2HNO_2\) + \(_2H_2O\)

9. Simplify the equation by dividing through by 2:

  \(MN^2\)+ + \(H_2SO_3\) + 2H+ + 2e- → \(MN^4\)+ + \(HNO_2\) + \(H_2O\)

Therefore, the balanced reduction half-reaction is:

8H+ + 5e- + \(MnO_4\)- → \(MN^2\)+ + \(4H_2O\)

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Reducing half-reaction:\(MN^2+ + 4H^+ + 2e^- → MnO2 + 2H2O\)

To write the balanced reduction half-reaction, we need to identify the species that undergoes reduction, which is the one that gains electrons. In this case,\(MN^2+\)is reduced to \(MnO2\).

To balance the reduction half-reaction, we first balance the atoms of all elements except hydrogen and oxygen. Then, we balance the oxygen atoms by adding \(H2O\) to the side that lacks oxygen. Finally, we balance the hydrogen atoms by adding H^+ to the opposite side. We also add electrons to balance the charge. In this case, the balanced reduction half-reaction requires 2 electrons.

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Any atom's atomic number is indicated to the left of its atomic symbol and is equal to the number of electrons in its nucleus. False: Any atom's atomic number is given as a subscript to the left of its atomic symbol and is equal to the number of electrons in its nucleus.

An atom is made up of a core negatively charged nucleus and one or more circling electrons. The positively charged, relatively large protons and neutrons that make up the nucleus could be present. But for the origin of the name "atom," we must look to 400 B.C. in ancient Greece. Greek philosopher Democritus proposed the usage of the word atomos, which meaning "uncuttable," in this sentence. Ultimately, he asserted, all matter may be reduced to singular, tiny particles called atomos.

An atom is made up of protons, neutrons, and electrons that orbit a core nucleus. Uranium splits into smaller atoms and creates new atoms during the fission process. There have been a tremendous number of atoms generated, as evidenced by the Big Bang and supernova events.

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When 2.00 moles of N2 react with sufficient H2, the balanced chemical equation for the synthesis of ammonia (NH3) is N2(g) + 3H2(g) → 2NH3(g).

According to the stoichiometry of the reaction, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Since you have 2.00 moles of N2 reacting, you can use the mole ratio to determine the moles of NH3 produced:
(2 moles NH3 / 1 mole N2) × 2.00 moles N2 = 4.00 moles NH3,

So, when 2.00 moles of N2 react with sufficient H2, 4.00 moles of NH3 will be produced.

38.5 g is the mass of nitrogen.

generated moles of ammonia Chemical formula

N₂ + 3H₂ → 2NH₃

Number of nitrogen moles: Mass x molar mass equals number of moles 38.5 g/28 g/mol is the weight in moles.

1.375 mol is the number of moles.

The moles of ammonia and nitrogen from the balance chemical equation will now be compared.

 N₂ : NH₃ 1 : 2

1.375 : 2×1.375 = 2.75 mole..Thus, from 38.5 g of nitrogen, 2.75 moles of ammonia are created.

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Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Bonds that possess between 5 and 50 ionic character are considered to be polar covalent bonds. Polar covalent bonds occur when two atoms with different electronegativities share electrons unequally.

This results in a partial positive charge on the less electronegative atom and a partial negative charge on the more electronegative atom. The greater the difference in electronegativity between the two atoms, the more polar the bond will be.

When the electronegativity difference is large enough (greater than 1.7), the bond is considered ionic, meaning that one atom has completely lost its electron(s) to the other atom. However, when the electronegativity difference is between 0.5 and 1.7, the bond is considered polar covalent.

In the case of bonds with between 5 and 50 ionic character, the electronegativity difference is not large enough for the bond to be considered fully ionic, but it is significant enough for the bond to be polar covalent. Therefore, bonds with between 5 and 50 ionic character are classified as polar covalent bonds.

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The amount of the compound \(XY_2\) that can be generated would be 11.28 grams

From the equation of the reaction, the mole ratio of X and Y is 1:1.

Mole of 3.5 grams of X = 3.4/24 = 0.1417 moles

Mole of 4.2 grams of Y = 4.2/35 = 0.12 moles

Thus, Y is the limiting reactant because it is present in a lower amount than needed.

Mole ratio of Y and  \(XY_2\) = 1:1

Equivalent mole of  \(XY_2\) = 0.12 moles

Molar mass of  \(XY_2\) = 24 + (35x2) = 94 g/mol

Mass of 0.12 moles of  \(XY_2\) = 0.12 x 94 = 11.28 grams

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The specific heat capacity of the substance can be calculated using the formula Q = m x c x ΔT, where Q is the amount of heat absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, we know that Q = 7.6 J, m = 264.0 mg (or 0.2640 g), ΔT = (21.7 - 9.9) = 11.8 °C. Substituting these values in the formula, we get 7.6 J = 0.2640 g x c x 11.8 °C. Solving for c, we get c = 0.00098 J/g°C. Rounding this to 3 significant digits, we get the final answer as 0.000980 J/g°C. Therefore, the chemist can report the specific heat capacity of the substance as 0.000980 J/g°C.
A chemist measures the heat required to raise the temperature of a 264.0 mg sample of a pure substance from 9.9°C to 21.7°C. The experiment reveals that 7.6 J of heat are needed. To calculate the specific heat capacity (c), we can use the formula q = mcΔT, where q is the heat energy (7.6 J), m is the mass (0.264 g, since 1 g = 1000 mg), and ΔT is the change in temperature (21.7°C - 9.9°C = 11.8°C). Rearranging the formula, we get c = q / (mΔT). Substituting the values, c = 7.6 J / (0.264 g × 11.8°C) ≈ 2.47 J/(g·°C). The specific heat capacity is approximately 2.47 J/(g·°C).

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Answer:

14 grams of calcium oxide would be produced by thermal decomposition of 25 grams of calcium carbonate.

Explanation:

You know:

CaCO₃ → CaO + CO₂

In the first place, by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) the following quantities react and are produced:

Being:

the molar mass of the compounds participating in the reaction is:

Then, by stoichiometry of the reaction, the following mass amounts of the compounds participating in the reaction react and are produced:

You can then apply the following rule of three: if by stoichiometry of the reaction 100 grams of calcium carbonate CaCO₃ produce 56 grams of calcium oxide CaO, 25 grams of CaCO₃ how much mass of CaO will it produce?

\(mass of calcium oxide=\frac{25 grams of CaCO_{3} *56 grams of CaO}{100 grams of CaCO_{3} }\)

mass of calcium oxide= 14 grams

14 grams of calcium oxide would be produced by thermal decomposition of 25 grams of calcium carbonate.

Answer:

I can only see b

Explanation:

Answer:

Carbon- 11 has 6 protons in its nucleus and boron- 11 has 5 protons in its nucleus.

Explanation:

note: Carbon has an atomic number of 6

and Boron has an atomic number of 5.

Answer:

B

Explanation:

The statement "Adjustments are recorded in the general journal as adjusting journal entries and are posted to the general ledger" is actually correct.

Adjustments, also known as adjusting entries, are recorded in the general journal to update accounts at the end of an accounting period. These adjusting journal entries are then posted to the general ledger, which is the central repository for all the accounts of a company.such as accruals, deferrals, and estimates. These entries are recorded in the general journal and then posted to the general ledger, where they update the respective accounts' balances.

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False. The distance between molecules decreases for all solids when they turn into liquids.

When a solid turns into a liquid, the distances between molecules generally decrease, rather than increase.

In a solid, molecules are typically arranged in a regular, ordered pattern and are closely packed together. As the solid is heated and melts, the molecules gain kinetic energy, causing them to vibrate and move more rapidly.

This increase in motion allows the molecules to break free of their ordered positions and slide past one another, resulting in a decrease in intermolecular distances and a transition from a solid to a liquid state.

There are some exceptions to this general trend, such as in cases where the solid structure is more porous and loosely packed than the liquid, but in most cases, the statement is false.

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Answer: 9.97 g (corrected to 3 significant figures.)

Explanation:

mass = no. of moles x molar mass

Atomic mass of Barium = 137.327; oxygen = 15.999,

so the molar mass of BaO = 137.327 + 15.999

=153.326

Hence, the mass is

0.065 x 153.326

=9.97 g (corrected to 3 significant figures.)