What is another name for NASA's space shuttle?A: Manned Space VoyageB: Galactic Exploration UnitC: Universal Planetary ExpeditionD: Space Transportation System

Answer: 6 m/s squared

Explanation:

6m/s squared. Hope this helped

Plz give brainliest

Answer:

v = 28 m/s

Explanation:

Since energy is conserved:

Eg = Ek

mgh = 1/2mv^2

masses cancel

gh = 1/2v^2

(9.8)(40) = 1/2v^2

(2)(40)(9.8) = v^2

v = sqrt(784)

v = 28 m/s

Answer:

The below diagram shows pure spectrum with white light

Explanation:

Astronomers can use how long it takes an object's brightness to vary to estimate the physical size of the object through a method known as photometry. This method involves observing an object's brightness over time and analyzing the patterns of variation.

For example, consider a binary star system in which two stars orbit each other. As one star passes in front of the other, the combined brightness of the system will decrease. The duration of this decrease in brightness can be used to estimate the physical size of the stars, as the duration of the decrease is related to the size of the stars and the distance between them.

Similarly, if an asteroid or other small body passes in front of a star, the star's brightness will decrease for a short period of time. The duration of this decrease can be used to estimate the size of the asteroid, as the duration is related to the size of the asteroid and the distance between it and the observer.

In general, the size of an object can be estimated using photometry by comparing the observed variation in brightness to the expected variation based on the physical characteristics of the object. This can provide valuable information about the properties and behavior of celestial objects and can help astronomers to better understand the structure and evolution of the universe.

Answer:

\(P=2.57\times 10^{-7}\ N/m^2\)

Explanation:

Given that,

A radio wave transmits 38.5 W/m² of power per unit area.

A flat surface of area A is perpendicular to the direction of propagation of the wave.

We need to find the radiation pressure on it. It is given by the formula as follows :

\(P=\dfrac{2I}{c}\)

Where

c is speed of light

Putting all the values, we get :

\(P=\dfrac{2\times 38.5}{3\times 10^8}\\\\=2.57\times 10^{-7}\ N/m^2\)

So, the radiation pressure is \(2.57\times 10^{-7}\ N/m^2\).

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

6.9m

Explanation:

I divide 75m by 12 seconds.

Please give BRAINLIEST

Explanation:

Object is under the effect of the acceleration of gravity

v = 1/2 a t^2       a = 9.81 m/s^2   t = 2.3

v = 25.9 m/s^2 = ~ 26 m/s   ( two significant digits)

Answer:

Elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

Explanation:

Most of the elements heavier than iron are formed during the death of stars through neutron capture processes, specifically the R-Process and the S-Process. The R-Process is a rapid capture of neutrons, while the S-Process is a slow capture of neutrons. These processes either directly form elements or indirectly form them through decay processes [^1]. Elements heavier than iron are primarily made in environments with free-neutron densities in excess of a million particles per cubic centimeter [^2]. In the extreme energetic conditions of supernovae, atoms are bombarded by a very large number of neutrons, and rapid successive neutron capture, followed by beta decay, produces the heavier atoms [^5].

So, elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

[^1

The appliance that is being examined here is the television

Television uses energy to power its electronic components, including the display screen, sound system, and various electronic circuits that control and process the incoming signals. The amount of energy a television uses can vary depending on the type of TV, size, display technology, and usage patterns.

For example, older CRT (cathode ray tube) TVs use more energy than modern LED (light-emitting diode) TVs. Energy is consumed when the TV is turned on, and the amount of energy used can increase when the TV is displaying brighter images or using built-in features like speakers or smart TV functions. Additionally, leaving a TV on standby mode can still consume some energy.

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A color.......................................................................yeah the color of your socks is a color :}

Answer:

E = 1,720,779.221 or 1.720779221 * 10^ 6V/m

Explanation:

The electric field between the parallel conducting plates is given by

E =V / d

where V is the potential difference and d is the distance between the plates.

E = 26.5 kV/ 1.54 cm

Now we have to convert into proper units

26.5 kv= 26.5 * 1000 v=  26500 volts

1  kv= 1000 volts

1.54 cm = 1.54/ 100 m= 0.0154m

1m = 100cm

Now putting the values

E= 26500/0.0154 = 1,720,779.221 V/m

The Electric field is equal to E= 1,720,799.221 or 1.7220799221 * 10 ^6 Volts per meter.

In scientific notation this can be written as 1.7220799221 *10^6 V/m

The gas's internal energy that expands from I to F changes by 1015 J.

Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:

ΔU = Q - W

where ΔU = change in internal energy,

Q = heat added to the system, 465 J and

W = work done by the system.

Assuming that the process is quasi-static use approximation known as the "staircase approximation."

By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.

Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:

ΔU = Q - W

ΔU = 465 J - (-550 J)

ΔU = 1015 J

Therefore, the change in internal energy of the gas is 1015 J.

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Answer:

\(3.031\times 10^{-5}\ \text{m}\)

Explanation:

\(y\) = Distance between central maxima and first minimum

m = Order = 1

d = Thickness of hair

\(\lambda\) = Wavelength = 632.8 nm

L = Distance between light source and screen = 1.25 m

Width of central maximum is given by

\(2y=5.22\times 10^{-2}\\\Rightarrow y=\dfrac{5.22\times 10^{-2}}{2}\\\Rightarrow y=0.0261\ \text{m}\)

Distance between central maxima and first minimum is given by

\(y=L\tan\theta_{min}\\\Rightarrow \tan\theta_{min}=\dfrac{y}{L}\\\Rightarrow \tan\theta_{min}=\dfrac{0.0261}{1.25}\\\Rightarrow \theta_{min}=\tan^{-1}0.02088\\\Rightarrow \theta_{min}=1.1962^{\circ}\)

Since \(\theta\) is small \(\tan\theta_{min}=\sin\theta_{min}\)

\(\sin\theta_{min}=\dfrac{m\lambda}{d}\\\Rightarrow d=\dfrac{m\lambda}{\sin\theta}\\\Rightarrow d=\dfrac{1\times 632.8\times 10^{-9}}{\sin1.1962^{\circ}}\\\Rightarrow d=3.031\times 10^{-5}\ \text{m}\)

The strand of hair is \(3.031\times 10^{-5}\ \text{m}\) thick.

Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.

System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.

In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.

In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.

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Answer:

3 amps

Explanation:

Volts divided by ohms

Answer:

The value is \(R = 0.321 \ \Omega\)

Explanation:

From the question we are told that

   The diameter is  \(d = 8.252 \ mm = 0.008252 \ m\)

    The length of the wire is  \(l = 1.0 \ km = 1000 \ m\)

   Generally the cross sectional area of the copper wire is mathematically represented as

           \(A = \pi * \frac{d^2}{4}\)

=>        \(A = 3.142 * \frac{ 0.008252^2}{4}\)

=>         \(A = 5.349 *10^{ - 5} \ m^2\)

Generally the resistance is mathematically represented as

      \(R = \frac{\rho * l }{A }\)

Here \(\rho\) is the resistivity of copper with the value  \(\rho = 1.72*10^{-8} \ \Omega \cdot m\)

=>    \(R = \frac{1.72 *10^{-8} * 1000 }{5.349 *10^{ - 5} }\)

=>    \(R = 0.321 \ \Omega\)

The efficiency of an engine is defined as ratio of the useful work done to the heat provided or,

in terms of temperature of the source and the sink the efficiency of heat engine is given by \(1-\frac{T_{2} }{T_{1} }\)

Thus, we have two formulae to calculate the efficiency of a heat engine.

η= \(\frac{useful work done}{heat absorbed}\) ....1

η= \(1-\frac{T_2}{T_1}\)             ....2   (where \(T_{2}\) and \(T_{1}\) are temperatures of sink and source respectively)

Given quantities are,

Now, by equating (1) and (2) equation,

⇒ \(1-\frac{T_2}{T_1}\) = \(\frac{Useful work done}{Heat absorbed}\)

Substituting the given values;

⇒ \(1-\frac{288}{830}\) = \(\frac{230000}{heat absorbed}\)

⇒therefore, heat absorbed = 353846.15 J

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Answer:

1.2 g/cm³

Explanation:

From the question given above, the following data were obtained:

Mass of solid = 180 g

Length (L) of solid = 10 cm

Width (W) of solid = 5 cm

Height (H) of solid = 3 cm

Density of solid =?

Next, we shall determine the volume of the solid. This can be obtained as follow:

Length (L) of solid = 10 cm

Width (W) of solid = 5 cm

Height (H) of solid = 3 cm

Volume (V) of solid =?

V = L× W × H

V = 10 × 5 × 3

V = 150 cm³

Finally, we shall determine the density of the solid. This can be obtained as follow:

Mass of solid = 180 g

Volume of solid = 150 cm³

Density of solid =?

Density = mass / volume

Density = 180 g / 150 cm³

Density of solid = 1.2 g/cm³

Answer:

117/60*50

Explanation:

Trust me bc I'm smart

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Answer:

Hurricanes are dangerous because they often carry high winds, in which destroy our homes and other recreational buildings. They also cause flooding, which is a threat to crops, animals, and shelters.

Explanation:

If you enjoyed my answer I would very much appreciate a brainliest. Thank you, and have a great day.

~Kai~

Answer:

Force X distance  = work

Explanation:

Work on an object =   force acting on object  X  distance

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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Answer:               6,857.14m/h        (6.86km/h or 1.90m/s)

Explanation:

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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