Uranus has a force of Gravity of 8.87 m/s^2. Sam has a MASS of 85 kg. What is his weight in Uranus? *

The question requires us to write the chemical reaction equation that represents the basic equilibrium for ammonia (NH3).

A general basic equilibrium equation can be written as:

where the substance B "accpets" a H+ ion and the reaction produces OH- ions as product.

Considering the information above, we can write the following basic equation for NH3:

where ammonia receives an H+ ion, forming NH4+ ion and OH- ions.

2 moles of water produces from 2 moles of hydrogen and 1 moles of oxygen. 2 molecules of water produces from 2 molecules of hydrogen and 1 molecules of oxygen. 2 liters of water produces from 2 liters of hydrogen and 1 liter of oxygen

Water is a substance that exists in gaseous, liquid, & solid phases and is made up of chemical components such as hydrogen and oxygen. Of the most prevalent and necessary substances is it. a liquid that is flavourless and odourless at normal temperature.

It has the critical capacity to dissolve a wide variety of other compounds. In fact, living things depend on water's adaptability as a solvent. It is thought that life first appeared in the water-based solutions of the oceans of the earth.

2H\(_2\)(g) + 0\(_2\)(g) → 2H\(_2\)O(g)

2 moles of water produces from 2 moles of hydrogen and 1 moles of oxygen

2 molecules of water produces from 2 molecules of hydrogen and 1 molecules of oxygen

2 liters of water produces from 2 liters of hydrogen and 1 liter of oxygen

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To answer this question, we need to know the concentration of the RbOH solution. Without this information, we cannot determine the amount of RbOH present in the 28.3 mL sample.
However, if we assume that the concentration of the RbOH solution is known, we can use the formula:
moles of solute = concentration x volume

To find the number of moles of RbOH in the 28.3 mL sample. From there, we can use the molar mass of RbOH (102.47 g/mol) to calculate the mass of RbOH in the sample.
For example, if the concentration of the RbOH solution is 0.1 M, then:
moles of RbOH = 0.1 M x 0.0283 L = 0.00283 moles
mass of RbOH = 0.00283 moles x 102.47 g/mol = 0.290 g
So, a 28.3 mL sample of a 0.1 M RbOH solution would contain 0.290 g of RbOH.
In summary, the amount of RbOH present in a 28.3 mL sample of a solution depends on the concentration of the solution. Without knowing the concentration, we cannot determine the amount of RbOH in the sample.

complete question not found in the search engine.

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Answer:

Reaction product A is more likely to form in the epoxide ring-opening reaction

Explanation:

The diagram for the reaction can be seen in the image attached below.

An epoxide is any class of organic compound, cyclic ethers, having a three-membered ring; they are usually prepared by selective oxidation of alkenes or by ring-closure of halohydrins(any class of organic compound having a hydroxyl functional group and a halogen on neighboring carbon atom ) which are used in making plastic.

Answer:

the degree of their disorderliness increases

Answer:

Yeast is living.

Explanation:

Yeast is a type of fungus used in making bread. Fungus is a group of living organisms.

An ion is an atom or molecule that has one or more electric positive or negative electric charges.

Na+1 is a sodium ion carrying a positively charged particle. This ion is a monoatomic monocation that is obtained from sodium. The single positively charged ions show that the sodium atom contains one valence electron in its outermost shell and can easily donate this one electron to other elements. They are therefore called donors.

Cu2+ is an ion of a copper atom carrying a double positive charge While Cu2+ ion is known to be basic, Na+ ion is neither basic nor acidic.

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Answer:

Read Below

Explanation:

Electrolysis is not possible with solid lead (II) bromide. This is because the ions are held in a three-dimensional lattice, unable to move freely to the electrodes. Melting enables the ions to become mobile and to travel to the respective electrodes.

The bulb won't glow when the electrodes are embedded in solid lead bromide.  The bulb will glow when the material surrounding the electrodes is molten lead bromide. When an ionic compound is in the molten (liquid) form the positive and negative ions are free to move around.

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The SI unit to the quantity it measures are:

Mass: The mass of an object is a measure of its amount of matter. The SI unit of mass is the kilogram (kg) or gram (g).

Temperature: Temperature is a measure of the average kinetic energy of the particles in a substance. The SI unit of temperature is the kelvin (K).

Time: Time is a measure of the interval between two events. The SI unit of time is the second (s).

Electric current: Electric current is a measure of the flow of electric charge. The SI unit of electric current is the ampere (A).

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Complete question:

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Match each SI unit to the quantity it measures.

The optimal pH for any buffer is when its pKa value coincides with the pH of the solution. A buffer typically functions well throughout a pH range that is 1 unit on either side of the pKa value.

The buffer in the pH range of 6.6 to 8.6 is made up of lactic acid, whose pKa value is 3.86, a PIPES buffer at pH 2.9 to 4.9, an acetic acid buffer at pH 5.8 to 7.8, and a HEPES buffer at pH 3.8 to 5.8. An amalgam of a weak acid and its conjugate base is known as a buffer solution. When basic or acidic components are added, it resists any pH shift. We can divide buffer solutions into two categories. Acidic and basic buffer solutions are the two categories into which we can divide buffer solutions. Because they produce unionised acid or base when they react with acid or base, a buffer solution resists any pH shift.

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Answer:

1. East on the box they are facing, West on the side from behind, North on the left side, South on the right side.

2. Because they all were facing towards the sun and the sun rise from east.

3. This one's answer is in the first answer.

4. The picture shows early morning because the shadow of the boys are in a flat position but if would have been late morning then it would not been covering that much area.

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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the density of the proton is 3.2×10−11g/cm3 3.2 × 10 − 11 g / c m 3 . if Calculate the density of a proton, given that the mass of a proton is 1.0073 amu.

Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick.

Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).

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Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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The mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.

The equation of the synthesis of water from hydrogen and oxygen is given as follows:

The grams of oxygen required is given below:

\(19.2 g\:of H_{2} \times\frac{1\:mol H_{2}}{18 g\:H_{2}} \times\frac{1mol\:O_{2}}{2 mol\:H_{2}}\times\frac{32g\:O_{2}}{1 mol\:O_{2}} = 17.06 g\: O_{2}\)

The equation of the combustion of propane is given as follows:

\(C_{3}H_{8} + 5\:O_{2}\rightarrow3\:CO_{2}+4\:H_{2}O\)

The mass of carbon dioxide produced is given below:

\(100 g\:of\:C_{3}H_{8} \times\frac{1\:mol\:C_{3}H_{8}}{44 g\:C_{3}H_{8}} \times\frac{3\:mol\:CO_{2}}{1\:mol\:C_{3}H_{8}}\times\frac{44g\:CO_{2}}{1 mol\:CO_{2}} = 300 g\:CO_{2}\)

The equation of the reaction of copper and silver nitrate is given as follows:

\(Cu + 2\:AgNO_{3}\rightarrow Cu(NO_{3})_{2} + 2\:Ag\)

\(5.7 g\:Cu \times\frac{1\:mol\:Cu}{64 g\:Cu} \times\frac{1mol\:Cu(NO_{3})_{2}}{1mol\:Cu}\times\frac{188g\:Cu(NO_{3})_{2}}{1 mol\:Cu(NO_{3})_{2}} = 16.7 g\:Cu(NO_{3})_{2}\)

Therefore, the mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.

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Answer:

B.) 36.0 grams

Explanation:

To find the mass of water, you need to (1) convert grams H₂ to moles (using the molar mass), then (2) convert moles H₂ to moles H₂O (using mole-to-mole ratio from reaction coefficients), and then (3) convert moles H₂O to grams (using the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units.

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

2 H₂ + O₂ -----> 2 H₂O
^                        ^

4.0 g H₂            1 mole             2 moles H₂O           18.014 g
---------------  x  ----------------  x  ------------------------  x  ---------------  = 36 g H₂O
                          2.016 g             2 moles H₂              1 mole

The affirmation  "They were only able to find class characteristics." is true, therefore, option B is correct.

Class characteristics are part of the physical evidence. These are those objects that tell us if a crime has been committed or that they would have a connection with a crime or with the perpetrator of this crime with the victim.  In this case it would be the type of paint chip that was taken from the suspect that matched the one found at the scene.

Class characteristics specifically, they are the properties that we are going to associate with a specific group of suspects, which decreases the number of suspects but does not connect us directly with just one culprit. Such as paint, blood or fibers.

Therefore, we can confirm that the correct option is B. They were only able to find class characteristics.

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Answer:

Rating approx 17.)(0784c. Dilute would be 2o clicks 75c apha neta soc

Explanation:

Answer: nice, is this a quistion? xd

Explanation:

Answer:

O-O

Explanation:

mmmmmmmmmmmmmmmmmmmmmmmmmmm

Answer: 22.78KJ/ mol

Explanation:

The computation of activation energy \(E_0\) follows by formula:

\(\ln (\dfrac{K_2}{K_1}) = (\dfrac{E_a }{ R}) (\dfrac{1}{T_1} -\dfrac{ 1}{T_2})\)

Given:\(T_1 = 376.0^{\circ}C =376+273K= 649 K\)

\(K_1 = 4.8 \times10^8\)

\(T_2 = 280.0^{\circ}C = 273+280K=553 K ,\ \ \ K_2 = 2.3 \times 10^8\)

\(\ln(\dfrac{2.3 \times10^8 }{ 4.8 \times 10^8}) = (\dfrac{E_a }{ 8.314}) (\dfrac{1}{649} - \dfrac{1}{553})\\\\\Rightarrow\ \ln(0.479) = (\dfrac{E_a }{ 8.314}) (-\dfrac{96}{358897})\\\\\Rightarrow\ -0.73605468= (\dfrac{E_a }{ 8.314}) (-\dfrac{96}{358897})\\\\\Rightarrow\E_a=-0.73605468\times 8.314\times\dfrac{-358897}{96}=22878.033\\\\\Rightarrow\E_a=22878.033\ J/mol=22.78 KJ /mol\)

Hence, the activation energy for this reaction =22.78KJ/ mol

Answer:

Before we can sketch the Lewis structures of molecules, we must first understand the octet rule. The octet rule asserts that when atoms combine to create compounds, electrons are gained, lost, or shared among them, resulting in a stable electron configuration defined by eight valence electrons as a result. These rules are used in conjunction with the main-group components of the second period.

Explanation:

Hope it helps:)

Answer:

B) Germanium atoms have more electrons than titanium atoms

Explanation:

Trust me I did this but for those who are hesitant

---> Conductors : It is a type of substance which conduct electricity that means it allow the electrons to flow through them.

Example of conductors are, iron, aluminium, gold, etc.

Insulators : It is a type of substance which does not conduct electricity that means it does not allow the electrons to flow through them.

Examples of insulators are, glass, rubber, ceramics, etc.

Semiconductors : It is a type of substance which conduct electricity under certain conditions that means it allow the electrons to flow through them. The conductivity level of semiconductors lie between the conductors and the insulators.

The good examples of semiconductors are silicon, germanium, gallium, and  selenium.

In the given options, aluminium, gold are the metals which conduct electricity and concrete is an insulator which do not conduct electricity while the germanium is the good semiconductor.

The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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Option B, where [OH-] is 1.0 x 10-13 mol dm-³3, is the only one that can be considered basic. Therefore, Option B is the correct answer.

To determine whether a solution is basic or acidic at 25 °C, we can compare the concentration of hydroxide ions ([OH-]) with the concentration of hydronium ions ([\(H_3O\)+]). In a neutral solution, the concentrations of [\(H_3O\)+] and [OH-] are equal, resulting in a pH of 7.

Option A states that the concentration of [\(H_3O\)+] is 1.0 x 10-3 mol dm-3. Since [\(H_3O\)+] represents the concentration of hydronium ions, this solution would be acidic because the concentration of [\(H_3O\)+] is higher than [OH-], indicating an excess of hydronium ions.

Option B states that the concentration of [OH-] is 1.0 x 10-13 mol dm-³3. In this case, [OH-] is higher than [\(H_3O\)+], indicating an excess of hydroxide ions. Therefore, this solution would be considered basic.

Option C states that the solution has a pH of 4.00. A pH of 4.00 is below the neutral pH of 7, indicating an excess of hydronium ions and an acidic solution. Therefore, this option does not represent a basic solution.

Option D states that the concentration of [\(H_3O\)+] is 1.0 x 10-13 mol dm-3. Similar to Option A, this concentration of [\(H_3O\)+] indicates an acidic solution, not a basic one.

Option B

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Answer:

D is the correct answer

Explanation:

In order for a solution to be basic at 25 C, the H+ concentration has to be less than the OH- concentration, and given that H+ times OH- is 10^-14, we deduce that H+ must be less than 10^-7 for the solution to be acidic. Thus, A can be eliminated, and so can C. With B, we calculate an H+ concentration of 0.1M, which also fails to be less than 10^-7
Thus, D is the correct answer and we can verify that as H+ is less than 10^-7.



Note: I do not know why my previous answer was deleted for "being incorrect", and i'm not sure how the incorrect answer was "expert verified", but I am as certain that D is the correct answer as i am sure of 3*(4+5-1) being equal to 24.

The interdependent relationship between advances in technology and scientific discoveries has enhanced our understanding of the universe. schooling, merchandising, and different multidisciplinary efforts by way of fostering higher information about the multidimensional nature of research.

Development in technological know-how and technology studies seeks to improve the techniques of technology and technology studies, Clinical expertise is used to create new technologies. New technology regularly allows scientists to explore nature in distinct ways and make new discoveries.

Technological know-how is the have a look at the natural world through a scientific approach i.e. collecting facts via a systematic procedure. And era is in which we observe science to create gadgets that can solve issues and perform distinct responsibilities. technology is literally the utility of science.

Society drives technological improvements and scientific inquiry. technology offers us a perception of what form of technology we should doubtlessly create and a way to create them, even as technology allows us to behave in addition to medical studies.

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Answer:

60 pounds of CO₂ are emited into the air

Explanation:

The combustion of gasoline occurs as follows:

C₈H₁₈(l) + 25/2O₂(g) ⇄ 8CO₂(g) + 9H₂O

Where 1 mole of gasoline produce 8 moles of CO₂

To solve this question we must find the moles of gasoline in 3.1 gallons. 8 times these moles are the moles of CO₂ produced. With the moles of CO₂ we can find its pounds as follows:

Pounds gasoline:

3.1 gallons * (6.3 pounds / gallon) = 19.53 pounds

Grams gasoline:

19.53 pounds * (453.592g / pound) = 8859g

Moles gasoline -Molar mass C8H18: 114.23g/mol-

8859g * (1mol / 114.23g) = 77.55 moles gasoline

Moles CO₂:

77.55 moles gasoline * (8 mol CO₂ / mol Gasoline) = 620.4 moles CO₂

Mass CO₂ - Molar mass: 44.01g/mol-

620.4 moles CO₂ * (44.01g / mol) = 27304g CO₂

Pounds CO₂:

27304g CO₂ * (1lb / 453.592g) =