Answer:
You can add graph by using the edit button and uploading a picture of the screen. if you then cut the picture before uploading so it just shows the graphand not the question. We cna then try answer for you.
Step-by-step explanation:
Generally graphs starting at point x=0 would show a different value for y by looking and counting up to its temperature.
if this shows positive it would be above the x axis line if it shows negative it would be a minus value below the x axis line under zero on y.
Therefore when we get to hr 2 and see this change you can count across and count up and see the rate of change is either 1,2,3,4,56,7,8 etc difference or 1x 2x 3x 4 x 5x 6 x as multiples.This then indicates a scale change at certain points.
The graph of function f is shown. Function g is represented by the table. x -1 0 1 2 3 4 g(x) 24 6 0 -2 Which statement correctly compares the two functions? A. They have different end behavior as x approaches -∞ and different end behavior as x approaches ∞. B. They have the same end behavior as x approaches -∞ but different end behavior as x approaches ∞. C. They have the same end behavior as x approaches -∞ and the same end behavior as x approaches ∞. D. They have different end behavior as x approaches -∞ but the same end behavior as x approaches ∞.
The answer choice which correctly draws a comparison between the end behaviors of the functions is; Choice C; They have the same end behavior as x approaches -∞ and same end behavior as x approaches ∞.
As given in the task content; the graph of the exponential function passes through (-4, 9), (0, 1), (1, 0), and (5, -2).
It therefore follows that as; x reduces (approaches -∞), the y value increases.
And, as x -increases (approaches +∞), the y-value decreases.
For the table, the values can be written as coordinates as follows; (-1,2), (0,4), (1,6), (2, 0), (3,-2).
Consequently, as x reduces (approaches -∞), the y- values decrease.
And, as x increases (approaches +∞), the y-values decrease.
Ultimately, the two functions in discuss can be concluded to have; Choice C.
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When can you write ratios as a fraction?
Answer:
In a mathequation when needed
Step-by-step explanation:
The pyramid and prism above have the same triangular base and height. The volume of the pyramid is 18 cubic inches. What is the volume of the prism?
A. 36 cubic inches
B. 72 cubic inches
C. 6 cubic inches
D. 54 cubic inches
Solve the quadratic equation below :
2x^2 + 12x =66
Answer:
-3 + sqrt 42
-3 - sqrt42
Step-by-step explanation:
assuming you want me to factor it and then find the roots:
2x^2 +12x-66
2(x^2 + 6x-33)
What is the probability of drawing a heart card from a full deck of cards and
randomly selecting the letter j from a list of the alphabet?
a) 26.92%
Ob) 23%
c) 3.85%
Od d) 0.82%
Answer:
26.92%
Answer choice “A”
Explanation:
14 cards of hearts in a deck out of 52.
14/52 = 26.92%
The probability of drawing a heart card from a full deck of cards is 26.92%
What is Probability?Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favorable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.
Probability(Event) = Favorable Outcomes/Total Outcomes = x/n
Experiment: A trial or an operation conducted to produce an outcome is called an experiment.
Sample Space: All the possible outcomes of an experiment together constitute a sample space. For example, the sample space of tossing a coin is head and tail.
Favorable Outcome: An event that has produced the desired result or expected event is called a favorable outcome. For example, when we roll two dice, the possible/favorable outcomes of getting the sum of numbers on the two dice as 4 are (1,3), (2,2), and (3,1).
Trial: A trial denotes doing a random experiment.
As, we know there we have 14 cards of hearts in a deck out of 52.
So,
probability of drawing a heart card from a full deck of cards
=14/52
= 26.92%
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I neead a fast answer 50pts fast (+Brainliest for right answer)!!!!
Answer: The description of that transformation is the triangle is rotated 90 degrees clockwise. Then, it's moved to the right TWICE. Finally, you go down 2 times.
Step-by-step explanation:
Hope this helps :)
triangle B is in dofferent orientation from triangle B so we know it was either mirrored or rotated. Triangle B isnt in the exact opposite orientation as A so we know it wasnt mirrored. So we now know that it was rotated and know we have to find the point of rotation. we can tell that the rotation was 270 degrees anti clockwise since it cant be clockwise because no points of rotation match. since we know triangle A was rotated 270 degrees anti clockwise to get triangle B we cant find the point of rotation by seeing which point works and if we test the points we will see that (0;-1) is the point of rotation. So triangle A was rotated 270 degrees anti clockwise on the point (0;-1) to make triangle B
2. The length of a rectangle is 5 cm more than its width. If the perimeter of the rectangle is 40cm, find the area of the rectangle.
Answer:
area of the rectangle =
\( {93.75cm}^{2} \)
Step-by-step explanation:
width = x cm
length = x + 5 cm
Perimeter = 2(length + width)
\(p = 2(x + (x + 5)) \\ 40 = 2(x + x + 5) \\ 40 = 2(2x + 5) \\ 40 = 4x + 10 \\ 40 - 10 = 4x \\ 30 = 4x \\ \frac{30}{4} = x \\ 7.5 = x\)
width = 7.5cm
length = 7.5 + 5 = 12.5cm
Area of the rectangle = length × width
\(a = 12.5cm \times 7.5 cm\\ a = 93.75 {cm}^{2} \)
URGENT Write the equations of a line parallel to y = -1/3x-4 thru (6,-4)
y=-1/3x-2. Hope this helped! :)
Answer:
y = -1/3x - 2Step-by-step explanation:
Given line:
y = -1/3x - 4Parallel line has the same slope:
y = -1/3x + bUse the given point to find the y-intercept:
-4 = -1/3*6 + b-4 = - 2 + bb = -4 + 2b = -2The line is:
y = -1/3x - 2Ariane borrows $200 on a 2−year loan. She is charged 5% simple interest per year. How much interest is she charged for 2 years? What is the total amount she has to pay back?
Answer:
Interest charged over two years: $20
Total amount: $220
Step-by-step explanation:
The formula for simple interest is A = P ( 1 + rt ).
A = 200 ( 1 + (0.05 * 2))
A is the total amount ( interest + principle )
A = 220
P is the principle ( initial amount deposited )
P = 200
R refers to rate (in percent)
R = 0.05
T = time period (in years)
T = 2
Let Q be an orthogonal matrix with an eigenvalue λ1=1. Let x be an eighenvector beloinging to λ1. Show that x is also an eigenvector of QT
If Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).
To show that x is also an eigenvector of QT, we need to demonstrate that QT * x is a scalar multiple of x.
Given that Q is an orthogonal matrix, we know that QT * Q = I, where I is the identity matrix. This implies that Q * QT = I as well.
Let's denote x as the eigenvector corresponding to the eigenvalue λ1 This means that Q * x = λ1 * x.
Now, let's consider QT * x. We can multiply both sides of the equation Q * x = λ1 * x by QT:
QT * (Q * x) = QT * (λ1 * x)
Applying the associative property of matrix multiplication, we have:
(QT * Q) * x = λ1 * (QT * x)
Using the fact that Q * QT = I, we can simplify further:
I * x = λ1 * (QT * x)
Since I * x equals x, we have:
x = λ1 * (QT * x)
Now, notice that λ1 * (QT * x) is a scalar multiple of x, where the scalar is λ1. Therefore, we can rewrite the equation as:
x = λ2 * x
where λ2 = λ1 * (QT * x).
This shows that x is indeed an eigenvector of QT, with the eigenvalue λ2 = λ1 * (QT * x).
In conclusion, if Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).
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The universities budget covers cost for nine months what is Amy’s monthly budget for textbooks in course supplies? What is her monthly budget for rent on utilities and food? What is your monthly budget for a personal and miscellaneous cost? what is her total monthly budget?
We can compute Amy's monthly budget for each question using division operations, as follows:
1. Amy's monthly budget for textbooks and course supplies is $100.
2. Amy's monthly budget for rent, utilities, and food is $1,422.
3. Amy's monthly budget for personal and miscellaneous costs is $251.
4. Amy's total monthly budget is $1,825.
How to determine the monthly budget:The total monthly budget is the total budget divided by the period (nine months).
Division operations can be used to determine the individual monthly budgets for each expense class by dividing the total cost by 9.
Living On/Off-Campus:Textbooks and Course Supplies = $900 $100
Rent, Utilities, and Food = $12,798 $1,422
Personal & Miscellaneous Expense = $2,259 $251
Transportation = $468 $52
Total non-tuition expenses = $16,425 $1,825 ($16,425/9)
The number of months for the year = 9 months
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plssss help!!!!!! #1
Step-by-step explanation:
According to the diagram:
The base is 6 unitsThe height is 3 unitsThe area is:
A = bh = 6*3 = 18 units²The perimeter of the figure below is 133.6 .find the length of the missing side please don’t answer the question if u don’t know it
Answer:
20.5 cm
Step-by-step explanation:
The perimeter of a shape is the lengths of all the sides.
Add up all the given sides in the picture and you get 93.1
Subtract 113.6 - 93.1 and you get 20.5
PLEASE HELP
y = 4x-9
y=x-3
Your work using substitution
Answer:
-36
-3y
Step-by-step explanation:
F
Answer:
(4,-7)
Step-by-step explanation:
y=4x-9
y+3=x
y=4(y+3)-9
y=4y+12+9
y=4y+21
y-4y=21
-3y=21
y=-7
Now use y to find x
y+3=x
-7+3=4
x=4
To find the x-intercept of
the graph of a linear equation, can you substitute 0
for x and solve the equation? Explain.
Answer: no, you cannot because you would get an undefined line which isn't a true function. You always substitute 1 for x to get a basic function which site and teachers will want you to use unless you've been told to do difrently. :)
I hope this is what your looking for
A school has 500 students. 340 are boys
a student is chosen at random. find the probability that student is a girl
Answer:
p = 8/25
Step-by-step explanation:
500 - 340 = 160 girls
p = 160/500
p = 8/25
Write 5√7 using rational exponents
Answer:
7*(5)^0,5
:D hope it helps
Mia hired a moving company. The company charged $500 or its services, and Mia gives the movers a 16% tip.
Answer:
The company charged $500 for its services,and Mia gives the movers a 16% tip. Now, we can add the tip amount to the cost of the service to find the total amount Mia paid: Total amount = Cost of service + Tip amount = $500 + $80 = $580
Step-by-step explanation:
Which statement is true about the system x-3y=2 and y=x+6?
1. (8, 2) is not a solution to either equation, so it is not a solution to the system.
2. (8, 2) is a solution to one equation but not the other one, so it is a solution to the system.
3. (8,2) is a solution to both equations, so it is a solution to the system.
4. (8, 2) is a solution to one equation but not the other one, so it is not a solution to the system.
The true statement about the system of equations is the fourth one:
"(8, 2) is a solution to one equation but not the other one, so it is not a solution to the system."
Which statement is true about the system?The system of equations is:
x - 3y = 2
y = x + 6
We want to see which statement is true, all of them refer to the point (8, 2), so let's see if it is a solution of the system.
Replacing the values in the first equation we will get:
8 - 3*2 = 2
8 - 6 =2
2 = 2
For the second equation:
2 =8 + 6
2 = 14
This is false, so (8, 2) is not a solution of the second equation.
Then the true statement is:
" (8, 2) is a solution to one equation but not the other one, so it is not a solution to the system."
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help please?
What is the value of 4x + 3y - z, when x = 2, y = -3 and z = 1 *
Answer:
-2
Step-by-step explanation:
When you fill it in you get 4(2)+3(-3)-1 then multiply and add
what is the value of the expression 5²5
Answer:
5^2×5
=25×5
=125
hope this will help you
Answer:
125
Step-by-step explanation:
hope this helps you
=25×5
=125
A certain forest covers an area of 2100 km^2. Suppose that each year this area decreases by 5.25%. What will the area be after 6 years
Answer:
The area after 6 years is \(1519.49km^2\)
Step-by-step explanation:
Given
\(a = 2100\) --- Initial Value
\(r = 5.25\%\) --- Rate
Required
Determine the area after 6 years
Because the area reduces,, the following formula will be used to solve the question.
\(y = a*(1 - r)^t\)
Here
\(t = 6\)
So, we have:
\(y = 2100*(1 - 5.25\%)^6\)
Convert percentage to decimal
\(y = 2100*(1 - 0.0525)^6\)
\(y = 2100*(0.9475)^6\)
\(y = 1519.47866516\)
\(y = 1519.49\) -- approximated
The area after 6 years is \(1519.49km^2\)
For each value of u determine whether it is a solution to -2u-6<-20
Answer:
u > 7
Step-by-step explanation:
-2u -6 < -20 Add 6 to both sides
-2u - 6 + 6 < -20 + 6
-2u < -14 Divide both sides by -2. When you multiply or divide both sides by a negative number, you must flig the sign.
\(\frac{-2u}{-2}\) > \(\frac{-14}{-2}\)
u > 7
Helping in the name of Jesus.
The answer is:
u > 7
In-depth explanation:
You haven't told me what the values of u are, but I'll solve the equation for u.
Add 6 on each side:
\(\bf{-2u-6 < -20}\)
\(\bf{-2u < -14}\)
Divide each side by -1 and reverse the sign:
\(\bf{2u > 14}\)
Now divide each side by 2
\(\bf{u > 7}\)
3.8 times 24 long multipilcalion
A circular plate with radius 7 m is submerged vertically in water as shown. Express the hydrostatic force against one side of
the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s? for the
acceleration due to gravity. Recall that the mass density of water is 1000 kg/m²)
pg
XN
dy
х
3 m
m
Answer:
\(pg\int\limits^7_7(10-y)2\sqrt{7^2-y^2} \, dy\)
*The last bound is negative 7
Then it equals 15085928 or 1.5E7
Step-by-step explanation:
\(x^2+y^2=7^2\)
area = 2xdy
depth = (7+3)-y -> (10-y)
total force = \(pg\int\limits^7_7 {(10-y)2x} \, dy\)
Substitute 2x from the first equation as x=\(\sqrt{7^2-y^2}\)
total force = \(pg\int\limits^7_7 {(10-y)2\sqrt{49-y^2} } \, dy\)
=pg1539.38
=(1,000)(9.8)(1539.38)=1.5E7 N
*Lower bound is -7, can't get the program to allow me to put it as a negative
The hydrostatic force against one side of the plate is an integral 1.5E7 N.
What is the equation of a circle at the origin?The general equation of a circle is \((x-h)^{2} +(y-k)^{2} = r^{2}\). The coordinate is (0, 0) at the origin, so the equation will become \((x)^{2} +(y)^{2} = r^{2}\).
\((x)^{2} +(y)^{2} = 7^{2}\)
area of circular plate = 2xdy
depth = (7+3)-y = (10-y)
The total force = \(pg\int\limits^7_7[ {10-y} ]2xdy\)
Substitute 2x from the first equation as x = \(\sqrt{7^{2} -y^{2} }\)\(pg\int\limits^7_7[ {10-y} ]\sqrt{49 -y^{2} }dy\)
= pg 1539.38
= (1,000)(9.8)(1539.38)
= 1.5E7 N
Thus, The hydrostatic force against one side of the plate is an integral 1.5E7 N.
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Evaluate The Integral.(Sec2(T) I + T(T2 +1)4 J + T6 Ln(T) K) Dt
The Integral \(\int \sec ^2\left(t\right)i+t\left(t^2+1\right)^4j+t^6\ln \left(t\right)kdt = i\tan \left(t\right)+\frac{j\left(t^2+1\right)^5}{10}+k\left(\frac{1}{7}t^7\ln \left(t\right)-\frac{t^7}{49}\right)\)
Given integral;
\(\int \sec ^2\left(t\right)i+t\left(t^2+1\right)^4j+t^6\ln \left(t\right)kdt\)
By solving the above integral, we have;
⇒ \(\int \sec ^2\left(t\right)i+t\left(t^2+1\right)^4j+t^6\ln \left(t\right)kdt\)
By applying the sum rule,
⇒ \(\int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\)
\(=\int \sec ^2\left(t\right)idt+\int \:t\left(t^2+1\right)^4jdt+\int \:t^6\ln \left(t\right)kdt\)
\(\int \sec ^2\left(t\right)idt=i\tan \left(t\right)\)
\(\int \:t\left(t^2+1\right)^4jdt = \frac{j\left(t^2+1\right)^5}{10}\)
\(\int \:t^6\ln \left(t\right)kdt = k\left(\frac{1}{7}t^7\ln \left(t\right)-\frac{t^7}{49}\right)\)
⇒ \(i\tan \left(t\right)+\frac{j\left(t^2+1\right)^5}{10}+k\left(\frac{1}{7}t^7\ln \left(t\right)-\frac{t^7}{49}\right)\)
Therefore, the integral \(\int \sec ^2\left(t\right)i+t\left(t^2+1\right)^4j+t^6\ln \left(t\right)kdt = i\tan \left(t\right)+\frac{j\left(t^2+1\right)^5}{10}+k\left(\frac{1}{7}t^7\ln \left(t\right)-\frac{t^7}{49}\right)\)
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A student solves the following problem:
Problem: 2(x−3)+3x=19
Step 1: 2x−6+3x=19
Step 2: 6x−6=19
Step 3: 6x−6 + 6=19 + 6
Step 4: 6x=25
Step 5: 6x6=256
Step 6: x≈4.17
Where is the mistake? What did the student do incorrectly?
Responses
Step 3: Student should have subtracted 6 from both sides, not added 6.
Step 5: Student should have subtracted 6 from both sides, not divided by 6
Step 1: Student should have only distributed the 2 to the x and not the x & 3.
Step 2: Student should have added 2x + 3x = 5x, not 2 x 3 = 6x
Answer:
error in Step 2
Step-by-step explanation:
2(x - 3) + 3x = 19
Step 1 : 2x - 6 + 3x = 19 ← simplify left side by collecting like terms
Step 2 : 5x - 6 = 19 ← add 6 to both sides
Step 3 : 5x - 6 + 6 = 19 + 6
Step 4 : 5x = 25 ← divide both sides by 5
Step 5 : x = 5
Error was made by student in Step 2 who should have added 2x and 3x, not multiplied 2 × 3
13x=-21-6y and -8x=36+6y
Answer:
\(x=3\\y=-10\)
Step-by-step explanation:
\(13x=-21-6y\\-8x=36+6y\)
Let's take one of the equations and solve for x. I'll take the first one.
\(13x=-21-6y\)
Divide by 13.
\(x=\frac{-21-6y}{13}\)
Now replace x in the second equation.
\(-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y\)
Distribute -8
\(\frac{168+48y}{13}=36+6y\)
Break down the fraction.
\(\frac{168}{13}+\frac{48}{13}y=36+6y\)
Subtract \(\frac{168}{13}\)
\(\frac{48}{13}y=36+6y-\frac{168}{13}\)
Subtract 6y
\(\frac{48}{13}y-6y=36-\frac{168}{13}\)
Combine like terms;
\(\frac{48-13*6}{13}y=\frac{36*13-168}{13}\)
Solve;
\(\frac{48-78}{13}y=\frac{468-168}{13}\)
Keep solving;
\(\frac{-30}{13}y=\frac{300}{13}\)
Multiply by the negative reciprocal of the fraction next to y.
\((-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )\)
On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10
\(y=-10\)
After having found y, replace it in any of the equations to find x.
\(13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3\)
Answer:
x=3
y=-10
Step-by-step explanation:
13x=-21-6y...............(1)
-8x=36+6y................(11)
Add (11) to (1)
5x=15-6y+6y
5x=15
Divide both sides by 5
5x/5=15/5
x=3
Substitute x=3 in 13x=-21-6y
13(3)=-21-6y
39=-21-6y
Collect like terms
39+21=-6y
60=-6y
Divide both sides by -6
60/-6=-6y/-6
-10=y
y=-10
66% of 62 is...? **SHOW YOUR WORK** PLEASE HELP!! :'(
Step-by-step explanation:
divide 62 by 100 and then multiply that number by 66. I don't have a calculator on me rn sorry
Answer:
Fraction:
\(\frac{1023}{25}\)
Decimal:
40.92
Mixed Number:
\(40\frac{23}{25}\)
Step-by-step explanation:
66% is the same this as \(\frac{66}{100}\). You can simplify \(\frac{66}{100}\) to \(\frac{33}{50}\). Then, find \(\frac{33}{50}\) of 62, which is the same thing as \(\frac{33}{50}\) x 62. You’ll get either of the three options, a fraction, decimal, or a mixed number, but all three are the same thing (you get to choose which one).
Hope this helps! :)
Complete the table shown below. f(x) = 2x2 - 8x + 6 1 0 2 y 3 4. 6 X= y = Z
Answer:
x = 6, y = -2, z = 0
Step-by-step explanation:
To find x, we have to plug 0 into f(x). Therefore, x = f(0) = 2 * 0² - 8 * 0 + 6 = 6. Similarly, to find y, we have to plug 2 into f(x) so y = f(2) = 2 * 2² - 8 * 2 + 6 = -2. Finally, z = f(3) = 2 * 3² - 8 * 3 + 6 = 0.
Answer:
6, -2, 0
Step-by-step explanation: