We find that the distance from A to C, representing the velocity of the ball relative to the ground, is approximately 17.20 m/s (option C).
The distance from A to C, which represents the velocity of the ball relative to the ground, can be determined using vector addition.
Given that the velocity of the train relative to the ground is represented by the distance from A to B in the diagram, and the velocity of the ball thrown inside the train at an angle of 66° relative to the train is represented by the distance from B to C, we need to find the resultant velocity from A to C.
To find the resultant velocity, we can use the concept of vector addition. We can break down the velocity of the ball into its horizontal and vertical components.
Let's assume the velocity of the train relative to the ground is v_train and the velocity of the ball relative to the train is v_ball. We can use trigonometry to find the horizontal and vertical components of v_ball.
The horizontal component, v_ball_x, can be calculated as v_ball * cos(66°), and the vertical component, v_ball_y, can be calculated as v_ball * sin(66°).
Now, we can add the horizontal components and vertical components separately.
The horizontal component of the resultant velocity, v_resultant_x, is the sum of v_train and v_ball_x. Similarly, the vertical component of the resultant velocity, v_resultant_y, is the sum of v_ball_y.
Finally, we can find the magnitude of the resultant velocity, v_resultant, using the Pythagorean theorem: v_resultant = sqrt(v_resultant_x^2 + v_resultant_y^2).
Calculating the values, we find that the distance from A to C, representing the velocity of the ball relative to the ground, is approximately 17.20 m/s (option C).
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A car traveling at a velocity of 25 m/s increases its velocity to 30.0 m/s in 10.0 seconds. What is the magnitude of its acceleration?
Hi there!
We can use the kinematic equation:
vf = vi + at
vf = final velocity (m/s)
vi = initial velocity (m/s)
a = acceleration (m/s²)
t = time (sec)
Rearrange to solve for acceleration:
(vf - vi)/t = a
(30 - 25)/10 = 5/10 = 0.5 m/s²
Answer:
Explanation: vf-vi/t = a
a=30m/s -25 m/s/10 s
a =5m/s /10s
a =1/2 m/s²
taking vtp measurement of pmos as an example, explain the idea on which the simple evaluation technique of vt is based.
The simple evaluation technique of VT is based on the idea that threshold voltage (VT) is equal to the gate voltage at which the inversion layer charge density is zero.
Explanation:
The simple evaluation technique of VT is based on the idea that threshold voltage (VT) is equal to the gate voltage at which the inversion layer charge density is zero. When measuring the threshold voltage of a PMOS device using the VTP method, a positive voltage is applied to the drain terminal and a negative voltage is applied to the source terminal. This causes the transistor to be turned off since the body is positively biased and the PMOS channel will not conduct current. A negative voltage is then applied to the gate, which is gradually increased.
The device is turned on when the threshold voltage is reached, and the inversion layer charge density is no longer zero. Therefore, the gate voltage at which the device is turned on is equal to the threshold voltage (VT). Thus, the VTP measurement technique for PMOS devices is based on the simple evaluation technique of VT, which is the gate voltage at which the inversion layer charge density is zero.
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Problem #1- In the first scene in which Miss Clark appears, she is supposed to be wearing a BLACK dress.
The only available dress that will fit the student playing this role is RED. There is no money in the budget to
purchase another dress. What can be done to the lighting on the stage to make the RED dress APPEAR
BLACK?
Answer:
Blue Lighting
Explanation:
In order to make red look black, you must use blue light. The blue would be absorbed and there would be no red light to reflect.
Answer:
You would have to shine green Light on the actress to make the dress appear to be red.
Explanation:
The reason it would appear to be red is because green reflects the red colour and absorbs the rest. So, when green light is shone on the dress, it absorbs all of the green light and not reflecting anything.The dress then appears to beblack.
is the relationship between gravitational force and the distance between the planet centers an inverse or direct relationship?
The relationship between gravitational force and the distance between the centers of two planets is an inverse relationship.
According to Newton's law of universal gravitation, the force of attraction between two objects is directly proportional to their masses and inversely proportional to the square of the distance between their centers. In other words, as the distance between two planets increases, the force of gravity between them decreases.
This relationship can be explained by considering the way gravity works. Gravity is a force that results from the curvature of spacetime caused by massive objects. The more massive an object is, the more it curves the surrounding spacetime, and the stronger its gravitational pull. However, as the distance between two massive objects increases, the curvature of spacetime caused by one object becomes less and less significant on the other object. Therefore, the gravitational force between them decreases as the distance between them increases.
This inverse relationship between gravitational force and distance has important implications for our understanding of the universe. For example, it helps explain why planets in our solar system have stable orbits around the sun. As the planets move farther away from the sun, the gravitational force decreases, but their orbital speed decreases as well, keeping them in balance.
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assume that you come in contact with a 120 v electrical circuit. the current (in milliamps) with the above voltage through wet (contact resistance of 1,000 ohms) hands is:
The current through wet hands when in contact with a 120 V electrical circuit would be 120 milliamps (mA).
Voltage (V) = 120 V
Resistance (R) = 1,000 ohms
According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them. According to Ohm's Law, we can compute the electrical current in a circuit by dividing the voltage by the resistance. If the resistance is reduced, the current will alter.
Calculating the current by using Ohm's law -
I = V / R
Substituting the values:
I = 120 / 1,000
= 0.12 A
Converting 0.12 A to milliamps by multiplying by 1,000 -
= 0.12 x 1,000
= 120
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radiation is a(n) when it produces leukemia in radiologists and survivors of atomic bomb explosions.
Radiation is a significant risk factor when it produces leukemia in radiologists and survivors of atomic bomb explosions.
Ionizing radiation, such as that emitted from radioactive materials, medical equipment, and atomic bombs, has enough energy to remove tightly bound electrons from atoms, causing them to become charged particles or ions. These ions can damage cellular structures, including DNA, which can lead to mutations and ultimately cause cancer, such as leukemia. Radiologists, who are regularly exposed to ionizing radiation during their work with diagnostic imaging equipment, are at an increased risk of developing leukemia. Similarly, survivors of atomic bomb explosions have been exposed to high levels of ionizing radiation, which can also result in the development of leukemia, this increased risk is due to the mutagenic nature of ionizing radiation, which directly influences the genetic material of cells.
In both scenarios, safety measures and guidelines should be in place to minimize the exposure to ionizing radiation. For radiologists, this may include wearing protective gear and limiting the duration of their exposure to radiation sources. For survivors of atomic bomb explosions, monitoring and assessing long-term health risks become vital for early detection and treatment of radiation-induced leukemia. In conclusion, radiation is a significant risk factor for leukemia development in both radiologists and survivors of atomic bomb explosions due to the damage it causes to the cellular structures, particularly DNA.
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A car travels at a constant speed of 40 miles per hour down the street for around 0.25 hours. What is its acceleration?
Answer:
55
Explanation:
was moving at 25 miles per hour
Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100. 0 m each. If Margy is walking at 1. 4 m/s and accelerates at 0. 20 m/s2 during one of the running portions, what is her final velocity at the end of the 100. 0 m? Round your answer to the nearest tenth. M/s.
To find Margy's final velocity at the end of the 100.0 m, we can use the equation of motion: v^2 = u^2 + 2as
where:
v = final velocity
u = initial velocity
a = acceleration
s = distance
Given:
u = 1.4 m/s (walking speed)
a = 0.20 m/s^2 (acceleration)
s = 100.0 m. Plugging in the values into the equation, we have: v^2 = (1.4 m/s)^2 + 2 * (0.20 m/s^2) * 100.0 m. v^2 = 1.96 m^2/s^2 + 40.0 m^2/s^2. v^2 = 41.96 m^2/s^2. Taking the square root of both sides to solve for v: v = √(41.96 m^2/s^2). v ≈ 6.5 m/s. Therefore, Margy's final velocity at the end of the 100.0 m is approximately 6.5 m/s.
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you push a freezer with a force of 250 N. if you move it a distance of 15 m, how much work was done?
Answer:
375J
Explanation:
W=F x d
=250 x 15
=375J
The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea. If the force is applied at an angle to the displacement, the work is W = fd cos.
What force is related to work done?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, For a constant force that is oriented in the same direction as the motion, it is easiest expressed as the product of the force's magnitude and the distance travelled.
A desk is being subjected to applied force if someone is pushing it across the room. The person's force applied to the desk is known as the applied force.
Mass and weight are not the same.The normal force is the supporting force exerted on an object when it collides with another stable object.
Therefore, W=F × d =250 × 15 =375J
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Which property of the water molecule causes two water molecules to be attracted to each other? (2 points)
Polar bonds between H and O atoms
Ionic bonding between water molecules
Hydrogen bonds between H atoms
Ionic bonding between O atoms
Answer:
hydrogen bonding between H atoms.
Explanation:
Newton's law of cooling states that the temperature of an object T, in surrounding air with temperature T, will behave according to the formula: T() = Aekt +Ts where t is time in minutes, A is the difference between the temperature of the object and the temperature of its surroundings and k is a constant A turkey is taken out of the oven with an internal temperature of 165°F and is allowed to cool in a a 75°Froom. After half an hour, the internal temperature of the turkey is 145°F. a. Find the formula that models this situation we need A, Ts and k. Here is a little help: Internal temperature of the turkey when it came out of the oven The Temperature of the room the Turkey in in after leaving the oven = A= (The difference in the two temperatures above) (this is Ts) Replace A and Tg in the equation T(t) = Aekt +Ts. To find k, use the information that when t = 30, T(30) = 145, and solve for k. b. To the nearest degree what will the temperature of the turkey be 50 minutes after it leaves the oven? c. To the nearest minute, how long will it take the turkey to cool to 110 °F?
According to Newton's law of cooling, The formula that models the cooling of the turkey is T(t) = (165 - 75) * e^(k * t) + 75. The temperature of the turkey 50 minutes after it leaves the oven will be approximately 118°F.
(a) The formula that models the cooling of the turkey is T(t) = (165 - 75) * e^(k * t) + 75.
In this case, the temperature difference between the turkey and the room, when it came out of the oven, is A = 165 - 75 = 90°F, and Ts (the temperature of the room) is 75°F. By substituting these values into the equation T(t) = A * e^(k * t) + Ts, we get T(t) = 90 * e^(k * t) + 75.
To find the value of k, we can use the information that when t = 30 minutes, T(30) = 145°F. Substituting these values into the equation and solving for k, we have 145 = 90 * e^(k * 30) + 75. Rearranging and solving, we find k ≈ -0.0207.
(b) The temperature of the turkey 50 minutes after it leaves the oven will be approximately 118°F.
To calculate the temperature at t = 50 minutes, we can use the formula T(t) = 90 * e^(-0.0207 * t) + 75. Substituting t = 50, we have T(50) = 90 * e^(-0.0207 * 50) + 75. Evaluating this expression, we find T(50) ≈ 118°F.
(c) It will take approximately 145 minutes for the turkey to cool to 110°F.
To determine the time it takes for the turkey to reach a temperature of 110°F, we can rearrange the equation T(t) = 90 * e^(-0.0207 * t) + 75 and solve for t. So, 110 = 90 * e^(-0.0207 * t) + 75. Solving this equation, we find t ≈ 145 minutes.
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What is the answer for the first part of a? In kN
We are asked to determine the magnitude of the force that acts parallel to the nail. To do that we will add the torque that acts on the point of contact. First, we draw a free-body diagram of the situation:
We have decomposed the force of the nail into its horizontal and vertical components. The horizontal component does no torque since there is no distance parallel to the force to the point of contact.
Now, we add the torques. We consider counterclockwise as positive:
\(\Sigma T=-(30cm)F+(5cm)(R_y)\)Since we consider the moment before there is no angular acceleration the sum of torques adds up to zero:
\(-(30cm)F+(5cm)(R_y)=0\)Now, we determine the value of Ry as a function of "R" using the trigonometric function cosine:
\(\cos \theta=\frac{R_y}{R}\)Now, we multiply both sides by "R":
\(R\cos \theta=R_y\)Now, we substitute in the sum of torques:
\(-(30cm)F+(5cm)(R\cos \theta_{})=0\)Now, we solve for "R". First, we add "30F" to both sides:
\((5cm)(R\cos \theta)=(30cm)F\)Now, we divide both sides by 5cm:
\((R\cos \theta)=\frac{(30cm)F}{5cm}\)Now, we divide both sides by cosine:
\(R=\frac{(30cm)F}{5cm\cos \theta}\)Now, we substitute the values:
\(R=\frac{(30cm)(155N)}{(5cm)\cos 26.9}\)Solving the operations:
\(R=1042.8N\)Therefore, the force on the nail is 1042.8 Newtons.
True or false. The period of a particle moving in a circle in a uniform B field is independent of the radius and speed of the particle.
Answer:
False. The period of a particle moving in a circle in a uniform B field is dependent on the radius and speed of the particle. Specifically, the period is given by T = 2πm/(qB), where m is the mass of the particle, q is its charge, B is the magnitude of the magnetic field, and the radius is given by R = mv/(qB), where v is the speed of the particle.
The period of a particle moving in a circle in a uniform B field is independent of the radius and speed of the particle is true because when a charged particle moves in a uniform magnetic field (B field), it experiences a magnetic force, which causes it to move in a circular path.
The period of this motion can be determined by the following equation:
T = 2πm / (qB)
In this equation:
- T represents the period of the particle's motion.
- m is the mass of the particle.
- q is the charge of the particle.
- B is the magnitude of the magnetic field.
As you can see, the period (T) is determined only by the mass (m), charge (q), and magnetic field strength (B). The radius and speed of the particle do not appear in this equation, which means the period is independent of these factors.
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The nuclear potential energy that binds protons and neutrons in a nucleus is often approximated by a square well. Imagine a proton confined in an infinitely high square well of length 10.0 fm , a typical nuclear diameter. Assuming the proton makes a transition from the n=2 state to the ground state, calculate
(b) the wavelength of the emitted photon.
The wavelength of the emitted photon in the square well system is approximately 4.96 x 10⁻⁷ meters, calculated using the energy difference between the n=2 state and the ground state.
To calculate the wavelength of the emitted photon, we can use the energy difference between the n=2 state and the ground state of the proton in the square well.
In the square well, the energy levels are given by the equation Eₙ = (n² * h²)/(8mL²), where n is the quantum number, h is the Planck's constant (6.626 x 10⁻³⁴ J.s), m is the mass of the proton (1.67 x 10⁻²⁷ kg), and L is the length of the square well (10.0 fm = 10.0 x 10⁻¹⁵ m).
For the n=2 state, we have E₂ = (2² * h²)/(8mL²) = (4 * (6.626 x 10⁻³⁴)²)/(8 * 1.67 x 10⁻²⁷ * (10.0 x 10⁻¹⁵)²) = 3.97 x 10⁻¹⁴ J.
For the ground state (n=1), we have E₁ = (1² * h²)/(8mL²) = (1 * (6.626 x 10⁻³⁴)²)/(8 * 1.67 x 10⁻²⁷ * (10.0 x 10⁻¹⁵)²) = 9.92 x 10⁻¹⁵ J.
The energy difference is ΔE = E₂ - E₁ = 3.97 x 10⁻¹⁴ J - 9.92 x 10⁻¹⁵ J = 3.98 x 10⁻¹⁴ J.
Now, we can use the equation E = hc/λ, where E is the energy of the photon, h is the Planck's constant, c is the speed of light (3.00 x 10⁸ m/s), and λ is the wavelength of the photon.
Rearranging the equation, we have λ = hc/E = (6.626 x 10⁻³⁴ J.s * 3.00 x 10⁸ m/s)/(3.98 x 10⁻¹⁴ J) = 4.96 x 10⁻⁷ m.
Therefore, the wavelength of the emitted photon is approximately 4.96 x 10⁻⁷ meters.
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what is the density to the object g/cm3
What is the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air?
A. 30. 2°F
B. 35. 1°F
C. 40. 4°F
D. 45. 6°F
The answer to the given question is option C: 40.4°F. Let's see the explanation below.How to find the temperature difference across a properly operating electric furnace?
]We know that the temperature difference across a properly operating electric furnace is given by:ΔT = (Q / (1.08 * CFM))where,Q is the rate of heat input in BTU/hr,1.08 is the factor to convert CFM to lb/min,and CFM is the rate of air flow in cubic feet per minute.So, here,ΔT = (Q / (1.08 * CFM))
Given,The rate of heat input = 10 kW = 34,120 BTU/hrThe rate of air flow = 900 CFMPlugging these values in the above equation, we get:ΔT = (34,120 / (1.08 × 900))ΔT = 40.4°FTherefore, the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air is 40.4°F. Hence, the main answer is option C.
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The temperature difference across the electric furnace is approximately 30.2°F (option A).
To calculate the temperature difference across the electric furnace, we can use the formula:
Temperature difference (ΔT) = Heat (Q) / (Airflow rate * Specific heat capacity * Density)
First, let's convert the power of the electric heater from kilowatts (kW) to watts (W):
10 kW = 10,000 W
Next, we need to determine the specific heat capacity of air. Typically, it is around 0.24 BTU/lb°F.
Since the given airflow rate is in cubic feet per minute (cfm), we need to convert it to pounds per minute (lb/min) using the density of air. The density of air at standard conditions is approximately 0.075 lb/ft³.
Converting 900 cfm to lb/min:
900 cfm * 0.075 lb/ft³ = 67.5 lb/min
Now we can substitute the values into the formula:
ΔT = 10,000 W / (67.5 lb/min * 0.24 BTU/lb°F * 0.075 lb/ft³)
Simplifying the equation:
ΔT = 10,000 W / (67.5 * 0.24 * 0.075) (lb/min * BTU/lb°F * lb/ft³)
Calculating the result:
ΔT ≈ 30.2°F
Therefore, the temperature difference across the electric furnace is approximately 30.2°F, which corresponds to option A.
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Jack travels 80 km in 50 minutes. What is his speed in m/s?
Answer:
1.6 m/s?
Explanation:
80 ÷ 50 = 1.6 m/s
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The half life of a radioactive substance is the time taken for the activity to halve. Use the graph to calculate the half life of the radioactive isotope.
Radioactive element which keeps on decaying over the time. Decay of radioactive element always comes under first order kinetics. Therefore the half life time of radioactive substance is 2seconds.
What is half life?Half life tells about the time at which the radioactive material decays to half of its initial concentration.
Mathematically,
half life time=0.693/ rate constant of the decay
The half life of a radioactive substance is the time taken for the activity to halve. Using the graph to calculate the half life of the radioactive isotope, we find that activity that is 3500 so, half of this activity is 17500 which is corresponding to time 2 seconds.
Therefore the half life time of radioactive substance is 2seconds.
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A crate is being lifted into a truck. If it is moved with a 2470 N force and 4850 J of work is done, then how far is the crate being lifted?
Answer:1.96m
Explanation:
Work=4850J
Force=2470N
Distance =work ➗ force
Distance =4850 ➗ 2470
Distance =1.96m
A baseball sits motionless near first base on a baseball diamond. What statement best explains why the baseball remains motionless?
Answer:
Explanation:
Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.
hope this helps :))
There is no force acting on the baseball the statement best explains why the baseball remains motionless.
What is inertia?A body wants to remain in its original position until or unless the external force is not applied to it. Such a phenomenon is known as inertia.
Newton's first law asserts that if a body is at rest or traveling at a uniform speed in a straight direction,
It will remain at rest or continue to move in a straight path at a constant speed until acted on by a force. This is referred to as the law of inertia.
There is no force acting on the baseball the statement best explains why the baseball remains motionless.
Hence option B is correct.
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Write step by step solutions and justify your answers. Question 1: Evaluate a) (10 points) L {e+ (2t - 1)2 + sin(–3t) + cos 5t}. - b) (10 points) L-1 1 (s + 1)(s2 + 5 – 12) +- }
Evaluate
a) L{e+(2t - 1)² + sin(-3t) + cos(5t)}
To evaluate this Laplace transform, we'll use the basic Laplace transform properties and formulas.
Step 1: Apply the Laplace transform to each term separately.
L{e} = 1/s [Using the Laplace transform of the exponential function]
L{(2t - 1)²} = (2/s)² [Using the Laplace transform of (at + b)^n, where a, b are constants]
L{sin(-3t)} = -3/(s² + 9) [Using the Laplace transform of sin(at)]
L{cos(5t)} = s/(s² + 25) [Using the Laplace transform of cos(at)]
Step 2: Apply the linearity property of the Laplace transform to combine the individual transforms.
L{e+(2t - 1)² + sin(-3t) + cos(5t)} = L{e} + L{(2t - 1)²} + L{sin(-3t)} + L{cos(5t)}
= 1/s + (2/s)² - 3/(s² + 9) + s/(s² + 25)
= 1/s + 4/s² - 3/(s² + 9) + s/(s² + 25)
Therefore, the Laplace transform of the given expression is 1/s + 4/s² - 3/(s² + 9) + s/(s² + 25).
b) L^(-1) {1 / [(s + 1)(s² + 5 - 12)]}
To evaluate the inverse Laplace transform, we'll use partial fraction decomposition and the inverse Laplace transform formulas.
Step 1: Factorize the denominator.
(s + 1)(s² + 5 - 12) = (s + 1)(s² + 5 - 12)
= (s + 1)(s² + 4s - 7)
= (s + 1)(s + 7)(s - 1)
1 / [(s + 1)(s + 7)(s - 1)] = A / (s + 1) + B / (s + 7) + C / (s - 1)
For s^2 term: 0 = A + B + C
For s term: 0 = 6A - 6B + 8C
For constant term: 1 = -7A
From the third equation, A = -1/7. Substituting this into the second equation, we get -6/7 - 6B + 8C = 0, which simplifies to -6B + 8C = 6/7.
From the first equation, we get C = -A - B, which simplifies to C = 1/7 - B.
Substituting C into the equation -6B + 8C = 6/7, we have -6B
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Find the efficiency of a machine that does 800J of work if the input work is 2,000J
Answer:
Efficiency: 0.4 (40%)
Explanation:
The efficiency of a simple machine is given by the ratio
n = w¹/w²
where
w² is the input work of the machine
w¹ is the output work of the machine
For the machine in this problem, we have:
w¹ = 800j is the output work
w² = 2000j is the input work
Therefore, the efficiency of the machine is
n = 800/2000 = 0.4
Which can be also written as percentage:
n = 0.4 × 100 = 40%
hope it helps you
how to find change in velocity with my speed data?
Answer:
ΔV = 9
Explanation:
Given your speed data, we can simply think about it graphically and calculate the slope. When your data is layed out on a graph there is a linear relationship, so it has a constant slope. We can calculate slope easily with your data using y2-y1/x2-x1 so 18-9/2-1. This gets us a constant change in velocity (slope) of 9.
According to the conservation of angular momentum, if an ice-skater starts spinning with her arms out wide, then slowly pulls them close to her body, this will cause her to: ____________
According to the conservation of angular momentum, if an ice-skater starts spinning with her arms out wide, and then slowly pulls them close to her body, this will cause her to spin faster. The conservation of angular momentum states that the total angular momentum of a system remains constant as long as no external torque acts on it. This means that if a spinning object pulls its arms closer to its body, its rotational speed will increase.
This is because the moment of inertia of the system is reduced as the mass is brought closer to the axis of rotation. Since the angular momentum of the system must remain constant, an increase in rotational speed must occur to compensate for the decrease in moment of inertia. The principle of conservation of angular momentum can be observed in many physical systems, such as figure skating, where an ice skater spinning with her arms extended can increase her rotational speed by pulling her arms closer to her body. This is because the total angular momentum of the skater is conserved, and the decrease in moment of inertia is compensated by an increase in rotational speed.
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A weather balloon has a volume of 35 L at sea level (1.0 atm). After the balloon is released it rises to where the air pressure is 0.75 atm. What will the new volume of the weather balloon be
Answer:
P₁ = 1.0 atm
V₁ = 35 L
P₂ = 0.75 atm
Formula:
P₁V₁ = P₂V₂
Solution:
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = (1.0 atm)(35 L) / 0.75 atm
V₂ = 47 L
Final Answer:
V₂ = 47 L
a tree is blank relative to earth a tree is blank relative to the sun
hmmmmmmmmmmmmmmmmm ask someone else sorry if im not helping
A 100 meter dash was held with 20 contestants. The best time was 10.7 seconds, and the worst time was 15.3 seconds. Only the fastest 10 contestants advance to the final race.
Which measure of central tendency should be used to calculate the cutoff time for the final race?
A.
range
B.
mode
C.
median
D.
mean
The measure of central tendency that should be used to calculate the cutoff time for the final race is the median.
Option C.
What is median?The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.
To find the median: Arrange the data points from smallest to largest. If the number of data points is odd, the median is the middle data point in the list.
So from the given data of the 100 meter dash, the measure of central tendency that should be used to calculate the cutoff time for the final race is the median.
The median will help to separate half of the data points that are smaller than the cutoff time and half of the data points are larger than the cutoff time.
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Can you guys help me explain why Lisa from the amplify 6th grade science doesn't have anemia? Please provide evidence from the article. It can be located in the library on amplify, and explain how molecules move through the body when someone has anemia, and compare that to elisa's test results. This can be located in Amplify Microbiome lesson 2.7. Please yalll helpp
You will learn about the requirements for each system and cell in your body as we go along by using the anemia metabolism simulation.
What are anemia's three main causes?Blood's red color is due to the iron-rich protein known as hemoglobin. From the lungs, it transports oxygen to the rest of the body. Blood loss, a lack of red blood cell formation, and excessive red blood cell breakdown rates are the three basic causes of anemia.
What occurs when someone has anemia?When you have anemia, your body doesn't produce enough strong red blood cells to supply enough oxygen to the tissues. You may experience fatigue and weakness if you have anemia, commonly known as low hemoglobin.
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I need help with this question:
A transmitter operating at 2.4 GHz is connected to an
antenna by 94 feet of LMR-600 cable. Assuming that a cable
connector has a loss of 0.47 dB, what is the total sign
The problem requires us to determine the total signal loss of a transmitter that operates at 2.4 GHz and is connected to an antenna by a 94 feet long LMR-600 cable, given that the cable connector has a loss of 0.47 dB.What is signal loss.
The signal loss refers to the reduction of strength of a signal while it travels through a medium or transmission system from the transmitter to the receiver. In communication systems, signal loss can occur in a cable, antenna, or other components. The total signal loss depends on the specific system used, cable attenuation, connector type, and the distance between the transmitter and receiver.
The total signal loss can be determined as the sum of the cable loss and the connector loss. Total Signal Loss(dB) = Cable Loss(dB) + Connector Loss(dB) = 0.508 dB + 0.47 dB = 0.978 dBTherefore, the total signal loss of the transmitter connected to the antenna by a 94 feet long LMR-600 cable, assuming that the cable connector has a loss of 0.47 dB, is 0.978 dB, approximately.
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You open a laptop facing you. What is the direction of the applied torque?
Downward.
Leftward.
Frontward.
Rightward.
Upward.
When you open a laptop facing you, the direction of the applied torque is upward.
What is torque?Torque is a measure of the force that can cause an object to rotate about an axis.
Also torque can be defined as a twisting or turning force that tends to cause rotation around an axis.
Mathematically, the formula for torque is given as;
τ = rF sinθ
where;
r is the radius F is the applied forceθ is the direction of the turnThus, when you open a laptop facing you, the direction of the applied torque is upward.
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