Which is better, forward bias or reverse bias, and why ?!
​

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

Answer:

The speed of the box at the end of the 6 s interval is 7.5 m/s.

Explanation:

Given;

magnitude of the force, f = 15 N

mass of the box, m = 12 kg

initial velocity of the box, u = 0

time of the box motion, t = 6s

The applied force on the box is given by Newton's second law of motion;

f = ma

where;

a is the acceleration of the box

a = f / m

a = (15) / (12)

a = 1.25 m/s²

The final velocity of the box is calculated as;

v = u + at

v = 0 + (1.25 x 6)

v = 7.5 m/s.

Therefore, the speed of the box at the end of the 6 s interval is 7.5 m/s.

Answer:

5000 Pa

Explanation:

First collect the data you've been given already and make sure to convert into the right units;

Density = 1 g/cm³ ...... 1000 Kg/ m³

acceleration due to gravity = 10 m/s²

Height = 50 cm......0.5 m

after collecting the data, use the formula to solve

pressure = pgh

= 1000 × 10 × 0.5

= 5000 Pa

hope this helps

The solubility of a substance in a solvent is affected by many factors, including temperature. In general, increasing the temperature of a solvent increases the solubility of a solute in that solvent. This relationship is known as the temperature-solubility relationship.

There are a few different ways in which temperature can affect solubility, depending on the specific solute and solvent in question. For example:

For most solid solutes in liquid solvents, increasing the temperature of the solvent will increase the solubility of the solute. This is because increasing the temperature generally increases the kinetic energy of the solvent molecules, which in turn makes it easier for them to break apart the intermolecular forces holding the solute together and form new solute-solvent interactions.

In some cases, however, the opposite may be true: the solubility of a solute in a solvent may decrease with increasing temperature. This is often observed for gases dissolved in liquids, where increasing the temperature decreases the solubility of the gas. This is because increasing the temperature of the liquid also increases the kinetic energy of the gas molecules, making them more likely to escape from the liquid and form a gas phase.

In rare cases, the temperature-solubility relationship may be more complex and exhibit unusual behavior. For example, for some solutes, the solubility may initially increase with temperature but then decrease at higher temperatures.

Overall, the relationship between temperature and solubility is an important consideration in many chemical processes, including crystallization, precipitation, and dissolution. Understanding this relationship can help scientists and engineers optimize their processes and achieve their desired outcomes.

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The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.

The formula for net torque acting on an object is given as;

T(net) = Ia

where;

The  moment of inertia of an object is given as;

I ∝ MR²

where;

So mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.

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The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Given that,

A system dissipates 12 J of heat into the surroundings.

28 J of work is done on the system.

To find,

The internal energy of the system.

Solution,

The first law of thermodynamics is used here. According to this law,

\(\Delta E=Q-W\)

Q is heat and W is work done

Here,

Q = -12 J is the heat dissipated by the system

W = -28 J is the work done on the system

ATQ,

\(\Delta E=(-12)-(-28)\\\\=-12+28\\\\=16\ J\)

So, the change of internal energy of the system is 16 J.

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Answer:

A) v = 1.47 10⁶ m / s, v = 0.5426 10⁴ m / s , B)  T = 4.7 10⁴ K, C) n₂ = 42

Explanation:

A)  For this part, let's calculate the speed of an electron that has an energy of 6.11 eV.

Let's reduce the units to the SI system

        E₀ = 6.11eV (1.6 10⁻¹⁹ J / 1eV) = 9.776 10⁻¹⁹ J

The kinetic energy of the electron is

        K = ½ m v²

         E₀ = K

         v = √ 2E₀ / m

         v = √ (2 9.776 10⁻¹⁹ / 9.1 10⁻³¹)

         v = √ (2.14857 10¹²)

         v = 1.47 10⁶ m / s

now the speed of a calcium ion is asked, let's find sum

        m = 40 1.66 10⁻²⁷ = 66.4 10⁻²⁷ kg

        v = √ (2E₀ / M)

         v = √ (2 9.776 10⁻¹⁹ / 66.4 10⁻²⁷)

        v = √ (0.2994457 10⁸)

        v = 0.5426 10⁴ m / s

B) the terminal energy of an ideal gas is

             E = 3/2 kT

              T = ⅔ E / k

              T = ⅔ (9,776 10-19 / 1,381 10-23)

              T = 4.7 10⁴ K

C) To calculate the energy of these lines we use the Planck expression

              E = h f

where wavelength and frequency are related

              c =λ f

              f = c /λ

let's substitute

              E = h c /λ

let's look for the energies

λ = 396.8 nm

  E₁ = 6.63 10⁻³⁴ 3 10⁸ / 396.8 10⁻⁹

           E₁ = 5.0126 10⁻¹⁹ J

λ = 393.3 nm

           E₂ = 6.63 10⁻³⁴ 3 10⁸ / 3.93.3 10⁻⁹

           E₂ = 5.0572 10⁻¹⁹ J

The difference in energy between these two states is

          ΔE = E₂ -E₁

          ΔE = (5.0572 - 5.0126) 10⁻¹⁹ J

          ΔE = 0.0446 10⁻¹⁹ J

let's reduce eV

         ΔE = 0.0446 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

         ΔE = 2.787 10⁻² eV

Now let's use Bohr's atomic model for atoms with one electron,

               E = -13.606 Z² / n²

where 13,606 eV is the energy of the base state of the Hydrogen atom, Z is the atomic number of Calcium

               n = √ (13.606 Z² / E)

λ = 396.8 nm

E₁ = 5.0126 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹J) = 3.132875 eV

               n₁ = √ (13.606 20² / 3.132875)

               n₁ = 41.7

since n must be an integer we take

               n₁ = 42

λ = 393.3 nm

E₂ = 5.0572 10⁻¹⁹ J (1eV / 1.6 10⁻¹⁹ J) = 3.16075 eV

              n₂ = √ (13.606 20² / 3.16075)

              n₂ = 41.5

Again we take n as an integer

               n₂ = 42

We can see that the two lines have the same principal quantum number, so for the difference of these energies there must be other quantum numbers, which are not in the Bohr model, because of the small difference they are possibly due to small numbers of the moment angular orbital or spin

Answer:

(a). Check attachment.

(b). 280.305 J.

(c). 31.81 kpa; 38.26K.

(d). 24.05K.

(e). 24.05k; 40kpa.

(f). -138.6J.

Explanation:

(a). Kindly check the attached picture for the diagram showing the four process.

1 - 2 = adiabatic expansion process.

2 - 3 = Isochoric process.

3 - 4 = isothermal process.

4 - 1 = isochoric process.

(b). Recall that the process from 1 to is an adiabatic expansion process.

NB: b = 5/3 for a monoatomic gas.

Then, the workdone = (1/ 1 - 1.66) [ (p1 × v1^b)/ v2^b × v2 - (p1 × v1)].

= ( 1/ 1 - 5/3) [ (101 × 5^5/3) × 10^1 -5/3] - 101 × 5.

Thus, the workdone = 280.305 J.

(c). P2 = P1 × V1^b/ V2^b = 101 × 5^5/3/ 10^5/3 = 31.81 kpa.

T2 = P2 × V2/ R × 1 = 31.81 × 10/ 8.324 = 38.36k.

(d). The process 2 - 3 is an Isochoric process, then;

T3 = T2/P2 × P3 = 38.26/ 31.82 × 20 = 24.05K.

(e). The process 3 - 4 Is an isothermal process. Then, the temperature at 4 will be the same temperature at 3. Tus, we have the temperature; point 3 = point 4 = 24.05k.

The pressure can be determine as below;

P4 = P3 × V3/ V4 = 20 × 10/ 5 = 200/ 5 = 40 kpa.

(f) workdone = xRT ln( v4/v3) = 1 × 8.314 × 24.05 × ln (5/10) = - 138.6 J

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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A spacecraft can reduce its speed during a trip to Mars by firing reverse rockets to increase force acting opposite of the direction of travel.

option C.

To reduce the speed of a spacecraft during a trip to Mars, the most common method is to fire reverse rockets, also known as braking thrusters.

These thrusters are used to generate a force that acts in the opposite direction of the spacecraft's motion, slowing it down. This is called a deceleration burn, and it is an important step in the process of entering into orbit around a planet or landing on its surface.

The reverse thrust slows down the spacecraft, reducing its speed and allowing it to be captured by the planet's gravity. This is crucial for the success of the mission and ensures that the spacecraft can be safely guided into orbit or landed on the surface of the planet.

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Answer:

7 degree

Explanation:

given data

width = 4.1 inches

length = 35.4 inches

solution

we consider as per fig

O is mid point of BC

so  OB  = 2.05 inches

and

AB = \(\sqrt{OB^2 + OA^2}\)

AB = \(\sqrt{2.05^2 + 35.4^2}\)

AB = 35.078 inches

so

\(sin \frac{\alpha }{2} = \frac{OB}{AB}\)

\(sin \frac{\alpha }{2} = \frac{2.05}{35.078}\)

\(\alpha = 7 degree\)

Answer:

Red supergiant.

Explanation:

When our sun is going to become a red giant, it's going to be 256 times larger than itself now.

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Explanation:

The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).

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Answer:

Explanation:

Formula to calculate the distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is,

d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Therefore, length of CD having coordinates C(3,1) and D(3, 3),

CD = \(\sqrt{(3-3)^2+(1-3)^2}\)

     = 2 units

Formula to find the midpoint of CD is,

M = \((\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)

   = \((\frac{3+3}{2},\frac{1+3}{2})\)

   = (3, 2)

Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.

Kiran's average speed from Tortula to Cactus was 58.78 miles per hour.

Let's use "x" miles per hour as Kiran's speed from Tortula to Cactus.

The time it takes Kiran to traverse the 250 miles between Tortula and Cactus is calculated as follows: time = distance / speed time = 250 / x

We also know that she upped her speed by 10 miles per hour throughout the 360-mile distance from Cactus to Dry Junction.

For that portion of the journey, let's designate her new speed "x+10" mi/h.

Her trip time is calculated as follows: time = distance / speed

time = 360 / (x+10)

Given that the entire journey lasted 11 hours, we can construct the following equation:

Time from Dry Junction to Cactus plus the time from Cactus to Tortula equals 11

250/x + 360/(x+10) = 11

We can now determine x:

250(x+10) + 360x = 11x(x+10)

0 - 400 - 2500 = 250x + 2500 + 360x = 11x2 + 110x

The quadratic equation is as follows: x = [400 sqrt(4002 - 4(11)(-2500))]

/ (2(11)) x = [400 ± sqrt(176000)]

/ 22

Speed cannot be negative, so we can disregard the negative result. Therefore, x = [400 + sqrt(176000)]

/ 22\sx ≈ 58.78

Kiran travelled between Tortula and Cactus at a speed of almost 58.78 miles per hour.

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Answer:

1)   F = 8.789 10² N, 2)   F = 1.5 10⁴ N

Explanation:

We can solve this exercise using Coulomb's law

         F =\(k \frac{q_1q_2}{r^2}\)

Knowing that charges of the same sign repel

let's apply this equation to our case

1) the charges are q = - 0.0025 C and the distance between them r = 8 m

       we calculate

           F = 9 10⁹ 0.0025 0.0025 /8²

           F = 8.789 10² N

as the two charges are of the same sign the force is repulsive

2) q₁ = -0.004C and q₂ = -0.003 C with a distance of r = 3.0 m

    we calculate

             F = 9 10⁹ 0.004 0.003 / 3²

             F = 1.5 10⁴ N

Answer:

option d is the answer of given statement

The surface area of the right cone is 54π units². Hence option D correct.

The surface area of a solid object is a total area measured that the surface of the object occupies. the surface area of the cube is 6 times side², cause it has 6 faces.

The surface area is total area occupied by the surface of the object.

A cone is geometrical shape which is having circular base and cone shaped body. when a line is drawn from tip to the center of the base it will make right angle between radius and height of the cone. We can apply Pythagoras theorem to get values of radius, height and hypotenuse.

The total area of the cone is nothing but area of the base plus curved area of the body.

Hence area of the cone is,

A = πr²+πr\(\sqrt[]{r^{2}+h^{2} }\)

Given,

r = 3

hypotenuse = \(\sqrt[]{r^{2}+h^{2} }\) = 15

A = ?

A = π3²+π3*15

A = π (9+45)

A = 54π units²

Hence area of the cone is 54π units².

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The moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

To calculate the moment M applied to the disc that holds the system in equilibrium, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the counterclockwise moments about the same point.

Let's consider point C as the pivot point. The clockwise moments are produced by the weight of BC and the unknown moment M, while the counterclockwise moments are produced by the weight of AB.

The weight of BC can be calculated as W_BC = linear density * length = 1 kg/m * 0.3 m = 0.3 kg.

The clockwise moment is given by M_clockwise = W_BC * BC = 0.3 kg * 0.3 m = 0.09 Nm.

Since the system is in equilibrium, the clockwise moments must balance the counterclockwise moments. Therefore, the counterclockwise moment produced by the weight of AB is also 0.09 Nm.

Hence, the moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

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Answer:

Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.

Explanation:

hoped it helped!!

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

Explanation:

i am sorry i needed points

Main answer (final answer) – 1473515.58J

Supporting answer- Collision occurs when two objects come into contact with each other for a brief period of time. In other words, collision is a short-term reciprocal interaction between two masses in which the momentum and energy of the colliding masses change.

Body of the answer-

Final answer- therefore kinetic energy for the collision is 1473515.58J

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The force acting on the particle at t = 1 s is 24.4 N.

Mass of the particle, m = 2 units

Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k

The velocity of the particle,

v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k

The acceleration of the particle,

a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k

Let the time for which the force is acting be 1 second.

Therefore, acceleration at t = 1 is,

a₁ = 2i + 12k

Hence, the magnitude of acceleration,

|a₁| = √(2²+ 12²)

|a₁| = √148

|a₁| = 12.2 unit/s²

Therefore, the force acting on the particle at t = 1 s is,

F₁ = m x |a₁|

F₁ = 2 x 12.2

F₁ = 24.4 N

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Answer: Can't see clearly.

Explanation:

The net force on particle 1 or charge 1 is determined as 32.73 N.

The net force acting on charge 1 is calculated by applying Coulomb's law as shown below;

Force due to charge 2;

F12 = (9 x 10⁹ x 5.16 x 10⁻⁶ x 8.99 x 10⁻⁶)/ (0.22²)

F12 = 8.625 N

Force due to charge 3;

F12 = (9 x 10⁹ x 89.9 x 10⁻⁶ x 8.99 x 10⁻⁶)/ (0.55²)

F12 = 24.1 N

The net force on charge 1 is calculated as;

F (net) = 8.625 N + 24.1 N

F (net) = 32.73 N

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