Solve for x.

I’m confused can someone help ?

Answer:

64\ units^{3}

Step-by-step explanation:

we have

V=s^{3}

This is the formula to calculate the volume of a cube

where

s is the length side of the cube

In this problem we have

s=4\ units

substitute

V=4^{3}=64\ units^{3}

The distance KJ needs to be equal to the distance LM and KL need to be parallel to JM

distances

then we need to calculate the slope of LK and JM if they are equal we have parallel sides

for LK

for JM

This figure is a trapezoid because it has exactly one pair of parallel sides that can prove because the slopes of LK and JM are congruent, but the distances KJ and LM are not equal therefore it is not an isosceles trapezoid

Answer:

the answer and explanation is in the picture

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hope this helps

Dividend must be put in AX register when using DIV or IDIV.  True.

In x86 assembly language, the DIV instruction is used for unsigned division, and the IDIV instruction is used for signed division. Both instructions require the dividend to be placed in the AX register.

The AX register is a 16-bit general-purpose register in the x86 architecture. It stands for "accumulator" and is commonly used for arithmetic operations. When using the DIV or IDIV instructions, the dividend value should be loaded into the AX register before executing the instruction.

The DIV instruction divides the contents of the AX register by the specified divisor, and the quotient is stored in the AX register. The remainder of the division operation is stored in the DX register.

Similarly, the IDIV instruction performs signed division. The contents of the AX register (the dividend) are divided by the specified divisor, and the signed quotient is stored in the AX register. The remainder is stored in the DX register.

By placing the dividend in the AX register, the DIV or IDIV instructions know where to find the value to be divided and where to store the result of the division operation. This ensures that the division operation is performed correctly and the resulting quotient or remainder is properly handled.

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Hitting a red light three days in a row

The probability of selecting a T or a P on the second draw, given that an F was selected on the first draw is 0.39.

The probability of selecting a T or a P on the second draw, given that an F was selected on the first draw, can be calculated using conditional probability.

P(A|B) = P(A and B) / P(B)

P(A and B) = P(T or P on second draw and F on first draw) = P(T on second draw and F on first draw) + P(P on second draw and F on first draw)

= (3/9) x (4/10) + (2/9) x (4/10) = 14/90

To find P(B), we know that it is 0.4.

Therefore, the conditional probability of selecting a T or a P on the second draw, given that an F was selected on the first draw, is:

P(A|B) = P(A and B) / P(B) = (14/90) / 0.4 ≈ 0.39

So the probability of selecting a T or a P on the second draw, given that an F was selected on the first draw, is approximately 0.39.

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Step-by-step explanation:

1)

5/8 × 39/10

1/8 × 39/2

39/16

2) 1/3 × 9/10

3/10

3) 3/4 × 2/3

1/2

Answer:

$920

Step-by-step explanation:

800(1.15) = 920

Answer:

Step-by-step explanation:

ayayayayay! I'm your little butterfly ayayayaya

After set s1.addAll(s2), s1 is [1, 2, 5, 2, 3, 6].

After performing the operation s1.addAll(s2) on sets s1 [1, 2, 5] and s2 [2, 3, 6], the set s1 would become[1, 2, 5, 2, 3, 6].

To determine the value of s1, the following steps has to be taken:

1. Start with sets s1 [1, 2, 5] and s2 [2, 3, 6].

2. Apply the addAll operation with set s2: [2, 3, 6]

3. Add each element from set s2 to set s1, while avoiding duplicates (since sets cannot have duplicate elements).

4. Therefore, suppose if set s1 is [1, 2, 5] and set s2 is [2, 3, 6] then, after s1.addAll(s2), the set s1 becomes [1, 2, 5, 2, 3, 6].

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Answer:

C

Step-by-step explanation:

given the factors are (x - 7) and (x + 3)

equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 3 = 0 ⇒ x = - 3

Answer:

Step-by-step explanation:

10

Answer:

the correct answer is B

Step-by-step explanation:

Answer:

the second choise is the answer

Answer:

13

Step-by-step explanation:

g(4) will be found by putting 4 in for r.

g(4) = 25 - 3(4)

g(4)= 25 - 12

g(4) = 13

To solve this problem, we need to use the concepts of probabilities, distribution, and events.

(a) The probability of all children being of the same sex is the sum of the probabilities of having all boys and having all girls. Each child has a 50% chance of being a boy or a girl, so the probability of having all boys or all girls is (0.5)^5 = 0.03125. Therefore, the probability of all children being of the same sex is 0.03125 + 0.03125 = 0.0625.

(b) The probability of the first 3 children being boys and the last 2 girls is the product of the probabilities of each child being a boy or a girl, in the specified order. The probability of having a boy on the first child is 0.5, the probability of having a boy on the second child is also 0.5, and the probability of having a boy on the third child is also 0.5. The probability of having a girl on the fourth child is 0.5, and the probability of having a girl on the fifth child is also 0.5. Therefore, the probability of the specified event is (0.5)^5 = 0.03125.

(c) The probability of exactly 3 children being boys can be calculated using the binomial distribution. There are 10 possible ways to choose which 3 out of 5 children are boys, and each of these ways has a probability of (0.5)^3 * (1-0.5)^2 = 0.125. Therefore, the probability of exactly 3 children being boys is 10*0.125 = 1.25.

(d) The probability of the first 2 children being girls and the other 3 being boys is the product of the probabilities of each child being a boy or a girl, in the specified order. The probability of having a girl on the first child is 0.5, the probability of having a girl on the second child is also 0.5. The probability of having a boy on the third child is 0.5, and the probability of having a boy on the fourth child is also 0.5. The probability of having a boy on the fifth child is also 0.5. Therefore, the probability of the specified event is (0.5)^5 = 0.03125.

(e) The probability of at least 1 girl can be calculated by subtracting the probability of having all boys from 1. The probability of having all boys is 0.03125, so the probability of having at least 1 girl is 1-0.03125 = 0.96875. In summary, the probabilities of the specified events are: (a) 0.0625 (b) 0.03125 (c) 1.25 (d) 0.03125 (e) 0.96875

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The correct formula for finding the present value of an investment is given by option D) PV = FV x 1/(1 + r)^n.

The present value (PV) of an investment is the current value of future cash flows discounted at a specified rate. The formula for calculating the present value takes into account the future value (FV) of the investment, the interest rate (r), and the number of periods (n).

Option D) PV = FV x 1/(1 + r)^n represents the correct formula for finding the present value. It incorporates the concept of discounting future cash flows by dividing the future value by (1 + r)^n. This adjustment accounts for the time value of money, where the value of money decreases over time.

In contrast, options A), B), and C) do not accurately represent the present value formula and may lead to incorrect calculations.

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Answer:

-2

Step-by-step explanation:

Answer: x = -2

Step-by-step explanation:

3x + 8 = 2

3x = -6

x = -2

The graph of 3x-2y≤6 is the third graph, for 3x-2y<6 is the first graph, for 3x-2y>6 is the fourth graph and for 3x-2y≥6 is the second graph. The solution has been obtained using concept of linear inequality.

What is linear inequality?

A linear inequality is one that would produce a linear equation if the equals relation were used instead of the inequality. When multiplying or dividing both sides by a negative number in order to solve the inequality, the direction of the inequality is reversed. The entire set of solutions to an inequality is known as the solution set.

We are given for graphs, of which two graphs are dotted and two are simple straight line graphs.

The dotted graphs are drawn for the inequalities having < or >

Whereas the simple straight line graphs are drawn for the inequalities having ≤ or ≥.

Now, to notice the shaded pattern, we will see whether the equations are true for (0,0) or not

1. 3x-2y≤6

⇒ 0≤6

So, the equation is true for the point.

Hence, the third graph represents this equation.

2. 3x-2y<6

⇒ 0<6

So, the equation is true for the point.

Hence, the first graph represents this equation.

3. 3x-2y>6

⇒ 0>6

So, the equation is false for the point.

Hence, the fourth graph represents this equation.

4. 3x-2y≥6

⇒ 0≥6

So, the equation is false for the point.

Hence, the second graph represents this equation.

Hence, the graphs are matched with the inequalities.

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Since, there are multiple questions so, the question answered above is attached below.

Answer:

SAS, because vertical angles are congruent.

Answer:

Surface Area=600ft

Step-by-step explanation:

If 10ft is the edge each side has an area of 100ft.  Since its a cube it has 6 sides so you time 6 and 100 which gets you 600.

The sample standard deviation is approximately 5.61 and sample variance is approximately 31.46.

To compute the range of a sample,

we subtract the minimum value from the maximum value.

Range = Maximum value - Minimum value

For the given sample,

the minimum value is 15 and the maximum value is 34.

Range = 34 - 15 = 19

The range of the sample is 19.

To compute the interquartile range (IQR) of a sample, we need to find the difference between the third quartile (Q3) and the first quartile (Q1).

IQR = Q3 - Q1

To calculate the quartiles,

we first need to arrange the data in ascending order:

15, 20, 20, 24, 25, 27, 30, 34

The sample size is 8,

so the median (Q2) will be the average of the fourth and fifth values:

Q2 = (24 + 25) / 2 = 24.5

To find Q1, we take the median of the lower half of the data:

Q1 = (20 + 20) / 2 = 20

To find Q3, we take the median of the upper half of the data:

Q3 = (27 + 30) / 2 = 28.5

Now we can calculate the interquartile range:

IQR = 28.5 - 20 = 8.5

The interquartile range of the sample is 8.5.

To compute the sample variance, we use the formula:

Variance = Σ\([(x - X)^2]\) / (n - 1)

where Σ represents the sum of, x is each data value, X is the mean, and n is the sample size.

First, let's calculate the mean (X):

X = (24 + 20 + 25 + 15 + 30 + 34 + 27 + 20) / 8 = 24.625

Now we can calculate the sample variance:

Variance = \([(24 - 24.625)^2 + (20 - 24.625)^2 + (25 - 24.625)^2 + (15 - 24.625)^2 + (30 - 24.625)^2 + (34 - 24.625)^2 + (27 - 24.625)^2 + (20 - 24.625)^2]\) / (8 - 1)

Variance = 31.46

To compute the sample standard deviation,

we take the square root of the sample variance:

Standard deviation = √(Variance) = \(\sqrt{(31.46}\)) ≈ 5.61

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Answer:x=-6

Step-by-step explanation:

1-x=2x+19

1-x+x=2x+x-19

1=3x+19

1-19=3x+19-19

-18=3x

x=-6

Answer

12. x = 15, y = 21

13. x = 10, M = 37, N = 84, P =59

14. x = 19, R = 43, S = 20, T = 117

15. A = 21, B = 125, C = 34

16. J = 48, K = 57, L = 75

Explanation

12. 6x - 11 + x + 5 + 81 = 180

     7x + 75 = 180

     7x = 105

     x = 15

     4y - 18 + y + 14 + 6*15 - 11 = 180

     5y + 75 = 180

     5y = 105

     y = 21

13. 4x - 3 + 9x - 6 + 6x - 1 = 180

    19x - 10 = 180

    19x = 190

    x = 10

    M = 4*10 - 3 = 37

    N = 9*10 - 6 = 84

    P = 6*10 - 1 = 59

14. R = 2x + 5

    S = x + 1

    T = 7x - 16

    2x + 5 + x + 1 + 7x - 16 = 180

    10x - 10 = 180

    10x = 190

    x = 19

   R = 2*19 + 5 = 43

   S = 19 + 1 = 20

   T = 7*19 -16

15. A = C -13

    B = 4C - 11

    c - 13 + 4c - 11 + c = 180

    6c -24 = 180

    6c = 2-4

    C = 34

   A = 34 - 13 = 21

   B = 4*34 - 11 = 125

16. K = J + 9

     L = 2J -21

     j + 9 + 2j - 21 + j = 180

    4j -12 = 180

    4j = 192

    J = 48

    K = 48 + 9 = 57

    L = 2*48 -21 = 75

Answer:

ya no

Step-by-step explanation:

Answer:

Step-by-step explanation:

are you showing the entire question because that actually makes no sense

The solid has a 62.5 cubic unit volume. Finding the volume of a solid with a circular base of radius 5 units is the task at hand.

The following formula can be used to determine how much of the magical potion is left after a specific period of time:

Let h represent the solid's height. The volume can therefore be stated as follows:

V = (12.5 dh from 0 to h)

Combining, we obtain:

V = 12.5h

The height of the solid is equal to the radius of the circle, which is 5 units, because the slices are perpendicular to the base. Therefore:

V=12.5h=12.5(5)=62.50 cubic metres

Thus, the solid has a 62.5 cubic unit volume.

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Two values have frequency 2, so both are modes. They are 5 and 6. Therefore, the mode is 5 and 6.

Given measure: 3, 5, 4, 6, 10, 5, 6, 9, 2, 13.(D) To calculate \(x_2\), first we need to sort the data in ascending order: 2, 3, 4, 5, 5, 6, 6, 9, 10, 13

Now, we need to find the median, which is the middle value of the data. Since the data has even number of values, we will calculate the mean of middle two values, that is:(5+6)/2 = 5.5 Therefore, \(x_2 = 5.5\).\( \frac{2}{x}= \) To find the value of x, we will first cross-multiply and then take the reciprocal of both sides:\[\frac{2}{x} = y \Rightarrow 2 = xy \Rightarrow x = \frac{2}{y}\] Therefore, \( \frac{2}{x}= \frac{2}{y}\).

(b) To calculate Fried m, we will use the formula: \[f_m = L + \frac{(n/2 - F)}{f} \times c\]where L is the lower limit of the modal class, F is the cumulative frequency of the class preceding the modal class, f is the frequency of the modal class, c is the class interval, and n is the total number of values.

First, we will calculate the class interval:c = (upper limit of class - lower limit of class) = (7-6) = 1 Next, we will construct a frequency table to find the modal class:| Class Interval | Frequency ||-------------------|------------|| 2-3 | 1 || 3-4 | 1 || 4-5 | 1 || 5-6 | 2 || 6-7 | 2 || 7-8 | 1 || 9-10 | 1 || 10-11 | 1 || 13-14 | 1 |The modal class is the class with highest frequency.

Here, two classes have frequency 2, so both are modes. They are 5-6 and 6-7.

Therefore, L = 5, F = 2, f = 2, n = 10, and c = 1. Substituting the values, we get:\[f_m = L + \frac{(n/2 - F)}{f} \times c = 5 + \frac{(10/2 - 2)}{2} \times 1 = 7\] Therefore, Fried m = 7.

(c) To find the mode, we look for the value(s) with highest frequency. Here, two values have frequency 2, so both are modes. They are 5 and 6. Therefore, the mode is 5 and 6.

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The tree is approximately 27 ft tall if the answer is rounded off to the nearest foot when the similar triangle formula is applied.

Two triangles can be said to be similar if their corresponding angles are seen as congruent and thereafter their corresponding sides are in proportion.

Similar Triangles Definition

Angle - Angle (AA)

Side - Angle - Side (SAS)

Side - Side - Side (SSS)Similar triangles are triangles that have the same shape, but their sizes may vary.

If Diane, mirror, and the exact bottom of the tree are placed as points on the ground all lying on one line, then the two right triangles can be stated as:

LEFT: y and 35 as the legs and unknown hypotenuse.

RIGHT: 6 and 7.9 as the legs and unknown hypotenuse.

The two angles pointed at the mirror are seen as of same measure that means that 35 and the hypotenuse of LEFT triangle makes same angle measure as the 7.9 and the hypotenuse of that of the RIGHT triangle.

Since these two are seen as similar triangles,

y/35 = 6/7.9

⇒y = 26.58

⇒ y ≈ 27 ft

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Answer:

x = 4

Step-by-step explanation:

3(2x + 1) = 18 + 4x - 7

First distribute 3 by multiplying it by 2x and 1.

= 6x + 3 = 18 + 4x - 7

Then, add any like terms.

= 6x + 3 = 11 + 4x

 -4x                -4x

= 2x + 3 = 11

         -3    -3

= 2x = 8

 /2     /2

x = 4