Assuming no air resistance, the maximum range that John's shotput can travel is achieved when it is launched at an angle of 45 degrees with respect to the ground.
This is known as optimal launch angle for a projectile thrown at a fixed speed. The actual distance traveled by the shotput will depend on its initial speed and other factors such as the height from which it is launched and local gravitational acceleration. The maximum range can be calculated using following formula:
R = (v^2/g) * sin(2θ)
where R is the maximum range, v is the initial speed of the shotput, g is the gravitational acceleration (assumed to be constant), and θ is the launch angle (measured from the horizontal).
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--The complete question is, Assuming no air resistance, how far will John's shotput travel and at what angle should he release it in order to achieve the maximum range, according to the principles of projectile motion?---
a cyclist covers a distance of 750m in 2 min 30sec what is the speed in km/hr of the cyclist?
Answer:
hey mate your answer is here
Place the following types of electromagnetic radiation in order from LOWEST energy
to HIGHEST energy?
(A) visible light (B) gamma rays (C) radio waves
1. А, С, В
2.С, А, В
3.В, С, А
4.С, В, А
Placing the electromagnetic radiation in order from the lowest energy to the highest energy : ( 2 ) C,A,B
Electromagnetic spectrumIn the electromagnetic spectrum the electromagnetic radiation with the shorter wavelength possess a higher energy while the electromagnetic radiation with a longer wavelength possess the lower energy.
The electromagnetic radiation as listed in the question with the longest wavelength is the radio waves therefore it possess the lowest energy while the radiation with the shortest wavelength is the gamma rays therefore it possess the highest energy.
Hence we can conclude that Placing the electromagnetic radiation in order from the lowest energy to the highest energy : ( 2 ) C,A,B
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Which of the following values are needed to solve for the heat capacity of a heated unknown solid when it is placed in a coffee cup calorimeter? Select all that apply.
A. The initial temperature of the water
B. The initial temperature of the solid
C. The mass of the solid
D. The mass of the water in the cup
E. The final temperature of the system
The initial temperature of the solid, the mass of the solid, the mass of the water in the cup, and the final temperature of the system are needed to solve for the heat capacity of a heated unknown solid when it is placed in a coffee cup calorimeter.
The heat capacity is the amount of heat required to raise the temperature of a system by one degree Celsius (or one Kelvin). When an unknown solid is heated and placed in a coffee cup calorimeter, the following values are needed to calculate its heat capacity: Initial temperature of the solid, Mass of the solid, Mass of the water in the cup, Final temperature of the system.
The calorimeter is used to measure the amount of heat gained or lost by the system (the solid and the water in the cup) during the process. The change in temperature of the system is used to calculate the heat gained or lost by the solid.
Therefore, the initial temperature of the solid, the mass of the solid, the mass of the water in the cup, and the final temperature of the system are needed to solve for the heat capacity of the heated unknown solid.
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12 x cos 50 = ?
Does anyone have the answer ? I forgot my my calculator.
12 x cos 50 = 7.713451316...
high voltage wiring connection scheme for a dual voltage 3 phase motor is
A dual voltage 3-phase motor can operate at two different voltage levels, typically referred to as the low voltage (LV) and high voltage (HV) settings. To connect a dual voltage motor in the high voltage configuration, a specific wiring scheme is required. Here's a brief explanation of the connection scheme:
Start by identifying the motor's voltage rating and make sure it is set to the high voltage setting.
The motor will have multiple sets of winding terminals labeled for different voltage levels. Locate the high voltage winding terminals.
Connect the three phases of the power supply to the corresponding phases of the motor winding. This is typically done using wire connectors or terminal blocks.
Make sure to connect the correct phase to the corresponding terminal (e.g., L1 to L1, L2 to L2, L3 to L3).
Verify that the connections are secure and properly insulated to prevent any electrical hazards.
Once the motor is connected, it can be energized using the high voltage power supply.
Always refer to the motor's manufacturer instructions and follow appropriate safety precautions when making electrical connections. It is recommended to consult a professional electrician or motor technician for specific guidance on wiring a dual voltage motor.
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que cantidad de calor absorbe una masa de hielo de 200kg que esta a 0°C para fundirse totalmente?
Answer:
m - 200 kg
ti - 0⁰c
clF - 79,7kcal, kg ( calor latente de fusión)
pf - 0⁰c
formulas:
QL- cL.m
solución - Ap camosla ecqación.
QL- (79,7 kcal,kg) .200 kg
Resultado ,la cantidad de calor absorbe lamasa de hieloes
Q2 -15,940 kcal
During a collision with another car, the occupants of a minivan initially travelling at 4.0 m/s come to a complete stop in 0.5 s. What was the acceleration of the occupants of the minivan?
a) 8.0 m/s2
b) –8.0 m/s2
c) 2.0 m/s2
d) –2.0 m/s2
Answer: b) - 8.0 \(m/s^{2}\)
Explanation: Acceleration is a vector indicating a rate an object's velocity changes over time:
a = \(\frac{v}{t}\)
and its SI unit is \(m/s^{2}\)
For the minivan to stop, it takes a period of 0.5s:
a = \(\frac{4.0}{0.5}\)
a = 8.0 \(m/s^{2}\)
As a vector, acceleration has magnitude (8\(m/s^{2}\)) and direction. Since it is stopping, the minivan has a direction opposite to the other car, which means acceleration is negative. So: a = \(- 8.0 m/s^{2}\).
10 POINTS!
Match these items.
1 .
Oersted
De Magnete
2 .
magnetite
iron oxide
3 .
domain
man-made magnet
4 .
lines of force
strength decreases rapidly with distance
5 .
electromagnet
lines representing the strength and direction of magnetic field
6 .
supermagnet
drop or hammer
7 .
demagnetize
small region within a magnet
8 .
inverse square
current-carrying wire has a magnetic field
9 .
William Gilbert
very cold
Answer:
inverse square – strength decreases rapidly with distance
super magnet – very cold
magnetite – iron oxide
domain – a small region within a magnet
William Gilbert – De Magnete
electromagnet – man-made magnet
demagnetize – drop or hammer
lines of force – lines representing the strength and direction of magnetic field
Oersted – current-carrying wire has a magnetic field
Explanation:
You're welcome.
19.Which of the following is the best definition of heat?Select one:a. The amount of energy transferred between 2 groups of molecules at the same high temperatures.b. The amount of energy transferred between 2 groups of molecules at the same low temperatures.c. The amount of energy transferred between 2 groups of molecules at different temperatures.d. All of the above.
c. The amount of energy transferred between 2 groups of molecules at different temperatures.
Heat transfer is given with a difference of temperatures
a sound wave leaves its source and is traveling through air. the reflected wave returns 0.5 second later. what is the distance from the source to the reflector?
The distance from the source to the reflector is approximately 171.5 meters when a sound wave leaves its source and is traveling through the air.
To determine the distance from the source to the reflector, we can use the speed of sound in air.
The speed of sound in air is approximately 343 meters per second at room temperature and normal atmospheric conditions.
Since the reflected wave returns 0.5 seconds later, it means that the sound wave traveled twice the distance from the source to the reflector.
Using the formula: Distance = Speed × Time, we can calculate the distance.
Distance = Speed of sound × Time
Distance = 343 m/s × 0.5 s
Distance = 171.5 meters
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Is it true that an object moves in a a circle at a constant speed will also have a constant velocity ?
Answer:
true
Explanation:
because the speed at which the object is moving in the circle depends on the effort used
What force is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25?
Answer:
Any force greater than 24.5 N
Explanation:
To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.
I hope I helped correct me if im wrong
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
First, we will calculate the normal force (N), which, in a horizontal surface, has the same magnitude and opposite sense as the weight (W) of the sled.
\(|N| = |W| = m \times g = 10 kg \times \frac{9.8m}{s^{2} } = 98 N\)
where,
m: mass of the sledg: Earth's gravityThen, we will calculate the friction force (f) using the following expression.
\(f = \mu \times N = 0.25 \times 98 N = 25 N\)
According to Newton's first law of motion, for the sled to move at a constant velocity, the sum of the force exerted (F) on the sled and the friction force (f) must be zero.
\(F + f = 0\\F = -f\\F = -25 N\\|F| = 25 N\)
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
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A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline on the block? Answer in units of N.
Answer:
Explanation:
The sum of the pore along the plane is expressed according to Newton's law
Fn-Ff = ma
Fn is the moving force
Ff = nR = frictional force
m is the Mass
a is the acceleration
Substitute the given values
Fn - nR = ma
Fn - tan31°(mgcostheta) =3.9(9.8)
Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)
Fn - tan31(38.22cos31)= 38.22
Fn - 32.76tan31 = 38.22
Fn-19.68 = 38.22
Fn = 38.22+19.68.
Fn = 57.90N
Hence Fn (moving force) of the inclined block is 57.90
A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A: 2.27 J. B :5.44 J. C :21.76 J. D :53.312 J
Answer:
The gravitational potential energy of a squirrel is 53.312 J.
Explanation:
We have,
Mass of a squirrel is 0.68 kg
It is placed at a height of 8 m above the ground.
It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :
\(E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J\)
So, the gravitational potential energy of a squirrel is 53.312 J.
Give an example of periods (periodic table)
Answer:
helium, hydrogen, nitrogen, oxygen,iron,uranium,
Explanation:
there are 118 elements but here are some
Urea gets from body cells to the blood plasma by diffusion through the tissue fluid. Explain what this means?
Answer:
Glucose diffuse from the blood plasma, across the capillary walls to the tissue fluid, and then to the cell.
Glucose diffuse from the blood plasma, across the capillary walls to the tissue fluid, and then to the cell. The waste product urea diffuse from the cells of the liver to the tissue fluid, and then across the capillary walls into the blood plasma.
11 12 13 14 15 16 17 18 19 20
TIME REMAINING
01:40:56
Who described atoms as small spheres that could not be divided into anything smaller?
Bohr
Dalton
Rutherford
Thomson
Answer:
jhon Dalton described it
Explanation:
hope it works out for you
if please mark brainiest
John Dalton described atoms as small spheres that could not be divided into anything smaller.
Who was John Dalton?John Dalton is the scientist who described atoms as small spheres that could not be divided into anything smaller. He proposed his atomic theory in 1803, which included the postulate that all matter is composed of tiny, indivisible particles called atoms. D
Dalton's theory also stated that atoms of different elements are unique in their mass and chemical properties and combine in simple whole-number ratios to form compounds. Dalton's model of the atom was a solid, indivisible sphere that was the smallest possible unit of an element.
While this model has been refined and updated with new discoveries, Dalton's contributions laid the foundation for the modern understanding of atomic structure and chemical reactions.
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Which statements describe how self-reflection can benefit students? Check all that apply. It allows students to better understand what they are learning. It ensures that students understand what they are learning. It helps students perform better on tests and homework assignments. It helps students recognize when they need help in class. It helps students save time when studying for tests.
Answer:
a c d
Explanation:
yeet
Answer:
a c d
Explanation:
Do you think the number of asteroid samples a pod is carrying could make a difference?.
Yes, the number of asteroid samples a pods is carrying will make a difference. The number of asteroids carrying the pods will make a difference because the objects will differ in their million mass due to the number of pods present.
still, but the objects have the different million mass, the object with lower mass will have a lesser change in haste(velocity), If the same strength force is wielded on two objects. Forces affect stir because they can change an objects stir.
The number of asteroids carrying the pods will make a difference because the objects will differ in their million mass due to the number of pods present.
When the million mass of two objects differ, though the same strength of the force is wielded on both the million mass their haste changes as the million mass affect the haste of the object.
Still, they stop or their haste would be constant, If one of the object's mass is lesser than one also the lesser mass object will have further haste compared to the object with the lower mass and if million mass of both the object is the same.
Therefore, it is true that the number of asteroid samples a pod is carrying could make a difference.
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Sofia goes on a hike on a trail that is 10 km long. She starts at 2:00pm and ends at 5:00pm. The end of the trail is 300m north of the beginning of the trail. What is Sofia's average velocity? (Velocity= displacement/time) Question 12 options: 100 m/hr S 30 m/hr S. 01 m/hr S 3. 3 m/hr S.
As the question depicts the trail is 10Km long but the end of the trail is 300m north from the beginning, Here the average velocity comes out to be 100m/hr.
What is Velocity?Velocity is defined as the displacement covered by an object or a body in unit time interval.
From the problem, it is clear that the distance is 10Km but the displacement comes out to be 300m.
The time from 2:00 pm to 5:00 pm is a total of 3hours.
Now, the velocity is determined from the following formula
\(V=\dfrac{d}{t}\)
here,
d= displacement
t= time
So, by putting values in above formula we get,
\(V=\dfrac{300 m}{3 hrs}\)
\(V=100m/hr\)
So, the average velocity of Sofia is 100m/hr
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Who was Nikola Tesla?
Answer:
Nikola Tesla was a Serbian-American inventor, electrical engineer, mechanical engineer, and futurist best known for his contributions to the design of the modern alternating current electricity supply system.
If you pull a permanent magnet rapidly away from a tank circuit, what is likely to happen in that circuit?.
Answer:
attract the magnetic ratio engine light of rock level
Two forces are applied to a car in an effort to accelerate it, as shown below. The first force, F1 = 310 N, is applied at an angle = 32° to the forward dashed line. The second force, F2 = 464 N, is applied at an angle = 13° to the forward dashed line.
(a) What is the resultant of these two forces?
______N at _____ ° to the _____
(b) If the car has a mass of 2850 kg, what acceleration does it have? (Disregard friction.)
_____m/s2 at ______ ° to the _____
a ) The resultant of these two forces is 715.92 N at 4.4° to the right of the forward dashed line
b ) If the car has a mass of 2850 kg, its acceleration is 0.25 m / s²
Resolving F1 into its vertical and horizontal component,
F1y = F1 cos θ
F1y = 310 * cos 32°
F1y = 263.5 N
F1x = F1 sin θ
F1x = 310 * sin 32°
F1x = 164.3 N
Resolving F2 into its vertical and horizontal component,
F2y = F2 cos θ
F2y = 464 * cos 13°
F2y = 450.1 N
F2x = F2 sin θ
F2x = 464 * sin 13°
F2x = 106.72 N
∑ Fx = F1x - F2x
∑ Fx = 164.3 - 106.72
∑ Fx = 57.58 N
∑ Fy = F1y + F2y
∑ Fy = 263.5 + 450.1
∑ Fy = 713.6 N
R² = ( ∑ Fx )² + ( ∑ Fy )²
R² = ( 57.58 )² + ( 713.6 )²
R² = 3315.46 + 509224.96
R = 715.92 N
tan θ = ∑ Fy / ∑ Fx
tan θ = 713.6 / 57.58
tan θ = 12.39
θ = 85.6° ( With the horizontal )
With the forward dashed line,
θ = 90 - 85.6
θ = 4.4° ( To the right of the forward dashed line )
F = m a
F = Force
m = Mass
a = Acceleration
m = 2850 Kg
a = F / m
a = 715.92 / 2850
a = 0.25 m / s²
Therefore,
a ) The resultant of these two forces is 715.92 N at 4.4° to the right of the forward dashed line
b ) If the car has a mass of 2850 kg, its acceleration is 0.25 m / s²
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A person walking in high heals can damages the floor by making small dimples in the
floor since all their weight is concentrated on the tip of the high heal. It the person
weighs 81 kg and the high of the tip of the high heal is 3.5 cm2, what is the force over
the floor?
SHOW WORK IF POSSIBLE TANKS A LOT
Answer:
2 314.28571 kg / m
Explanation:
divide
and you see
A flat surface of area 2.50 m
2
is rotated in a uniform electric field of magnitude E=6.00×10
5
N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. N+m
2
/C (b) Determine the electric flux through this area when the electric field is parallel to the surfuce. N⋅m
2
/C
As per the details given, the electric flux through the area when the electric field is perpendicular to the surface is 1.50 × \(10^6 Nm^2/C\). The electric flux through the area when the electric field is parallel to the surface is zero (0 N⋅\(m^2\)/C).
(a) The electric flux through the area may be determined when the electric field is perpendicular to the surface using the formula:
Φ = E * A * cos(θ)
Φ = (6.00 × \(10^5\) N/C) * (2.50 \(m^2\)) * cos(0°)
Φ = 1.50 × \(10^6 Nm^2/C\)
The electric flux through the area when the electric field is perpendicular to the surface is 1.50 × \(10^6 Nm^2/C\).
(b) The electric flux across the region is zero when the electric field is parallel to the surface.
This is due to the fact that the electric field lines are parallel to the surface, and no component of the electric field perpendicular to the surface contributes to the flux.
Thus, when the electric field is parallel to the surface, the electric flux across the region is zero (0 N⋅\(m^2\)/C).
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An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons. Determine the net force acting on the object:
Explanation:
Draw a free body diagram. There are two forces: weight force pulling down and air resistance pushing up.
Sum the forces in the y direction:
∑F = 50 N − (30 kg) (10 m/s²)
∑F = -250 N
The Sankey diagrams below show the energy transfers in two light bulbs. How much energy is wasted by light bulb 2?
Answer:
The amount of energy wasted by light bulb 2 = 70 J
Explanation:
Sankey diagrams are used to graphically indicate the proportional flow rate of a quantity
The labelled Sankey diagrams, here, indicate the energy transfers in two light bulbs, light bulb 1 and light bulb 2
From the labelled Sankey diagrams, we have;
For light bulb 1, the input energy = 80 J
The useful energy = 40 J
The wasted energy = 80 - 40 = 40 J
For light bulb 2, the input energy = 80 J
The useful energy = 10 J
Therefore, the wasted energy = 80 - 10 = 70 J
The amount of energy wasted by light bulb 2 = 70 J.
70 Joules of energy is wasted by light bulb 2 whereas bulb 1 wasted 40 joules of energy.
Bulb 1 uses 40 joules of energy out of 80 joules of energy and 40 joules of energy are wasted out of 80 joules of energy while on the other hand, bulb 2 uses 10 joules of energy as useful energy and 70 joules of energy are wasted out of 80 joules of energy.
According to the image, bulb 2 wasted more energy than bulb 1 so we can conclude that 70 joules of energy is wasted by bulb 2 out of 80 joules of energy.
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Answer:
D
Explanation:
A soccer ball kicked with a force of 12.5 N accelerates at 6.2 m/s’ to the right. What is the mass of the ball? Answer in units of kg.
Answer:
m = 2.01[kg]
Explanation:
This problem can be solved using Newton's second law which tells us that the force applied on a body is equal to the product of mass by acceleration.
\(F =m*a\)
where:
F = force = 12.5 [N]
m = mass [kg]
a = acceleration = 6.2 [m/s²]
\(12.5=m*6.2\\m = 2.01[kg]\)
A 10 kg mass is held in equilibrium by two cables (shown in red). The mass is centered within the 4.0 m horizontal dimension. If h2 = 2 find the tension in the cables.
The tension in each cable is approximately 49 N.
To find the tension in the cables, we can analyze the forces acting on the 10 kg mass in equilibrium. Since the mass is centered within the 4.0 m horizontal dimension, we can assume that the tension in each cable is equal.
Let's denote the tension in each cable as T. Since the mass is in equilibrium, the sum of the vertical forces acting on it must be zero.
Considering the vertical forces, we have:
T - T - mg = 0
Since the tension in each cable is equal and directed upwards, the vertical components cancel each other out. Therefore, we can rewrite the equation as:
-2T - mg = 0
We know that the mass (m) is 10 kg and the acceleration due to gravity (g) is approximately 9.8 m/s^2. Substituting these values into the equation, we get:
-2T - (10 kg)(9.8 m/s^2) = 0
Simplifying the equation, we have:
-2T - 98 N = 0
To solve for T, we isolate it on one side of the equation:
-2T = 98 N
T = 98 N / -2
T ≈ -49 N
The negative sign indicates that the tension in the cables is directed downward. However, tension is typically considered a positive quantity, so we can take the absolute value to obtain the magnitude of the tension.
Therefore, the tension in each cable is 49 N.
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