Renaldo plans to leave from Atlanta and fly into London (4281 miles). On the return, he will fly back from London to New York City (3470 miles) to visit his aunt. Then Renaldo heads back to Atlanta. Atlanta, New York City, and London do not lie on the same line. Find the range of the total distance Renaldo could travel on his trip.

Answer: 8 x 4

Step-by-step explanation:

if the hat is 4 TIMES the baseball cap then u should multiply. anytime “times” is in a sentence like that it’s an automatic flag/reminder that multiplication is needed

Answer:

D.

Step-by-step explanation:

The matching shirt costs 4 times as much as the cap; The cap is $8. In that case, the question just told us the answer. 4 times $8 = 4*8 or 8*4 = $32. So if you had to determine the cost, the shirt is $32.

Answer:

3/5

Step-by-step explanation:

When you are given an x-intercept, the y value will always be 0.

When you are given a y-intercept, the x value will always be 0.

With the intercepts we are given, we can make two points we can solve for the slope with.

(5, 0)

(0, -3)

Now, find the slope with the formula [ y2-y1/x2-x1 ]

-3-0/0-5

-3/-5

3/5 or 0.6

Best of Luck!

Answer:

0,31

Step-by-step explanation:

l'échelle = mesure plan/mesure réelle

37,5/120 ≈ 0,31

The rate at which the volume is changing when the temperature is increasing at 0.05 K/s and the pressure is increasing at 0.02 kPa/s is approximately -0.000480 V liters per second, according to the given equation PV = 8.317.

To find the rate at which the volume is changing when the temperature is 330 K and increasing at a rate of 0.05 K/s, and the pressure is 24 kPa and increasing at a rate of 0.02 kPa/s, we can use the chain rule of differentiation.

Given:

PV = 8.317

Taking the derivative of both sides with respect to time t, we have:

P(dV/dt) + V(dP/dt) = 0

Since we are looking for the rate at which the volume is changing, we need to solve for (dV/dt):

(dV/dt) = -(V(dP/dt))/P

Substituting the given values at the specific time:

P = 24 kPa

(dP/dt) = 0.02 kPa/s

V = PV/8.317 (from the ideal gas equation)

Substituting these values, we have:

(dV/dt) = -((PV/8.317)(dP/dt))/P

(dV/dt) = -((24V/8.317)(0.02))/24

Simplifying:

(dV/dt) = -0.004V/8.317

(dV/dt) ≈ -0.000480 V

Therefore, the rate at which the volume is changing when the temperature is 330 K and increasing at a rate of 0.05 K/s, and the pressure is 24 kPa and increasing at a rate of 0.02 kPa/s, is approximately -0.000480 V liters per second.

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Answer:

22

Step-by-step explanation:

6+8^2/4

= 6+64/4

= 6+16

=22

Hope this helps :)

Answer: A.

Step-by-step explanation: Brainliest

Answer:

2,160 Hours

Step-by-step explanation:

Ok so usual i would split $540 in half so a number multiplied by two would end up as 540, and i got 270. So since each week we know Phillip earned $270 and $11.25 a hour, we can divide 270 by 11.25, which gives us $24, so that means h = 24, but on week 2 it says Phillip worked 8 hours more on week 2, so that gives us a equation of 8 x 11.25, which comes out to 90, so now we can move on to our final equation, 90 x 24, which equals 2160. Im so sorry if this is wrong

Phillip worked for 20 hours and 28 hours in 1 and 2 weeks respectively.

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate.

Given that, Phillip earns $11.25 per hour. During Week 1, he worked h hours. During Week 2, he worked 8 hours more than Week 1. Phillip earned $540 for both weeks,

The unit rate for the work of Phillip is given, $11.25 per hour.

Therefore, his earning for h hours = $11.25h

For (8+h) hours = $11.25(h+8)

Since, he earned $540 for both weeks,

Therefore,

11.25(h+8) + 11.25h = 540

11.25h + 90 + 11.25h = 540

22.5h = 450

h = 20

h+8 = 28

Hence, Phillip worked for 20 hours and 28 hours in 1 and 2 weeks respectively.

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Answer:

1. 1.25 \(g/cm^{3}\)

2. 1.36 \(g/cm^{3}\)

3. 1.04 \(g/cm^{3}\)

4. 0.79 \(g/cm^{3}\)

Step-by-step explanation:

Density = Mass/Volume

1. 15g/\(12cm^{3}\) = 1.25 \(g/cm^{3}\)

2. 7.5g/\(5.5cm^{3}\) = 1.36 \(g/cm^{3}\)

3. 26g/\(25cm^{3}\) = 1.04 \(g/cm^{3}\)

4.  1350g/\(1700cm^{3}\) = 0.79 \(g/cm^{3}\)

Answer:

1. 1.25

2. 1.36

3. 1.04

4. 0.79

The answer to whether or not it is possible to determine imaginary solutions by examining the graph of p(x)=x^2+1 is no.

Function is a block of code that performs a specific task. It is a reusable code that can be called multiple times with different parameters. Functions are an important part of programming because they allow you to reuse code and make your code more organized and efficient. Functions also make it easier to debug code, as errors can be contained to a single function instead of spreading throughout the entire program.

The graph of this function does not contain any imaginary solutions, instead it is a parabola with its vertex at the origin and its axis of symmetry being the y-axis. This can be seen from the graph, as the graph is symmetrical about the y-axis and does not contain any points in the fourth quadrant, meaning that any solutions that would fall in this quadrant would be imaginary.

In addition, imaginary solutions cannot be determined from this graph, as the imaginary solutions would not be visible on the graph. Imaginary solutions are solutions that are not real, meaning they are not visible on the graph, as they do not exist in the real number system. This is because the graph only displays real number solutions, not imaginary ones.
Therefore, it is not possible to determine imaginary solutions by examining the graph of p(x)=x^2+1, as the graph only displays real number solutions, and imaginary solutions cannot be seen on the graph.

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Answer:

The lesson ends at 5:15 pm.

Answer:

Her piano lesson ends at 5:15pm

Hope it helps:)

Considering the linear function described, 500 liters of fuel were initially in the tank.

A linear function is modeled by:

y = mx + b

In which:

Researching this problem on the internet and looking at the graph, we have that when x = 0, y = 500, that is, the y-intercept is of 500. From the bullet points, the y-intercept is the initial value, hence 500 liters of fuel were initially in the tank.

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Answer:

To convert from slope intercept form y = mx + b to standard form Ax + By + C = 0, let m = A/B, collect all terms on the left side of the equation and multiply by the denominator B to get rid of the fraction.

explanation:

pls make me brainliest

Answer:

a

Step-by-step explanation:

Divide $85.50 by 6

$85.50/6 = $14.25

Therefore, the rate per hour for renting the scooter is $14.25

Answer:

Step-by-step explanation:

Find the graph attached. The formula for finding the equation of a line is expressed as:

y = mx+c

m is the slope

c is the intercept (point where the line cuts the y axis)

m = y2-y1/x2-x1

Using the coordinate (1,22) and (4, 40) to calculate the slope of the line, we will have:

m = 40-22/4-1

m = 18/3

m = 6

For the intercept:

From the grapg, it can be seen that the line cuts the y axis at y = 18. Hence the intercept c = 18

The equation of the line will be:

y = 6x+18

Substitute y = 134 into the formula to get x as shown:

134 = 6x+18

134-18 = 6x

116 = 6x

x = 116/6

x = 19.33

Answer:

64 5/6 is in simplest form. The decimal form of this equation is 64.8333333. The improper fraction of this equation is 389/6

Step-by-step explanation:

64 5/6 is a fraction already in simplest form. However, we can convert it into decimal form. We can change it to its decimal form,  64.8333333, by dividing 5 by 6 (0.8333333) and adding it to 64. Finally, we can turn this fraction into an improper fraction, 389/6. First, you multiply 64 by 6 (384) and then add the remain 5 to get 389. Since this mean 389 parts of 6, we end up with 389/6.

Answer:

3\(\sqrt{5\\\)

Step-by-step explanation:

The number of bears living in the area after 17 years is; 22555

We are given the function;

f(t) = 103/(1 + 26e^(-0.31t))

Where f(t) is a function that models the number of bears living in the area after t period of years.

Thus, to find the number of bears living in the area after 17 years, we will just substitute 17 for t in the given function to get;

f(17) = 103/(1 + 26e^(-0.31*17))

f(17) = 103/0.00456653759

f(17) ≈ 22555 bears

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The requried factor of the given expression aⁿ +aⁿ⁺¹ is given as aⁿ and (1 + a)

A number or algebraic expression that evenly divides another number or expression—i.e., leaves no remainder—is referred to as a factor.

Here,
Given expression,
= aⁿ +aⁿ⁺¹

In order to factor the above expression we are using the property,
x²  = x¹ (x¹)

So,
= aⁿ + a.aⁿ

Now, taking aⁿ common,

= aⁿ(1 + a)

So, aⁿ and (1 + a) are the requried factors.

Thus, the requried factor of the given expression aⁿ +aⁿ⁺¹ is given as aⁿ and (1 + a)

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Answer:

1.75 × 10⁶

Step-by-step explanation:

7,000,000 ÷ 4 = 1750000

Which is 1.75 × 10⁶ in standard form

a.  P(X ≤ 2) = 0.77

b.  P(X = 1 or X = 2) = 0.60

c.  P(X > 0) = 0.83

d. The cumulative probability distribution function for X is given in the table.

(a) The probability of a randomly selected student holding two or fewer jobs during the past year is given by the sum of the probabilities of holding 0, 1, or 2 jobs:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.35 + 0.25 = 0.77

Therefore, P(X ≤ 2) = 0.77.

(b) The probability of a randomly selected student holding either one or two jobs during the past year is given by the sum of the probabilities of holding 1 or 2 jobs:

P(X = 1 or X = 2) = P(X = 1) + P(X = 2) = 0.35 + 0.25 = 0.60

Therefore, P = 0.60.

(c) The probability of a randomly selected student holding at least one job during the past year is the complement of the probability of holding no jobs:

P(X > 0) = 1 - P(X = 0) = 1 - 0.17 = 0.83

Therefore, P(X > 0) = 0.83.

(d) The cumulative probability distribution function for X is the sum of the probabilities up to and including the value k:

P(X ≤ k) = ∑P(X = i) for i = 0 to k

Using the given probabilities, we can fill in the table:

k   0    1    2    3    4

P(X ≤ k) 0.17 0.52 0.77 0.93 1.00

Therefore, the cumulative probability distribution function for X is:

P(X ≤ k) = 0.17 for k = 0

P(X ≤ k) = 0.52 for k = 1

P(X ≤ k) = 0.77 for k = 2

P(X ≤ k) = 0.93 for k = 3

P(X ≤ k) = 1.00 for k = 4

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In this simulation experiment, the population distribution represents the lifetimes of a certain type of electronic control and the density curve in the figure represents the population distribution.

The distribution is skewed and follows a lognormal distribution with an expected value of ln(X) equal to 3 and a variance of ln(X) equal to 0.16. The experiment consisted of 500 replications and examined different sample sizes: n = 5, n = 10, n = 20, and n = 30.

The density curve in the figure represents the population distribution, with an expected value of E(A) equal to 21.7584 and a variance of V(X) equal to 82.1449. The histograms shown illustrate the distribution of sample means for the different sample sizes. Additionally, a normal probability plot from MINITAB is included for the x-values based on a sample size of n = 30, allowing for an assessment of the normality assumption for the sample means.

These visual representations provide valuable insights into the characteristics of the simulated experiment's population distribution, as well as the behavior of the sample means for different sample sizes.

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The complete question is:

Consider a simulation experiment in which the population distribution is quite skewed. The figure below shows the density curve for lifetimes of_a certain type of electronic control [this is actually a lognormal distribution with E(ln(X)) = 3 and V(ln(X)) = 0.16]. The statistic of interest is the sample mean X. The experiment utilized 500 replications and considered these sample sizes: n = 5, n = 10, n = 20, and n = 30. The resulting histograms along with a normal probability plot from MINITAB for the x values based on n = 30 are shown in the figures below. Density curve for the simulation experiment (E(A) = 21.7584, V(X) = 82.1449].

The standard normal curve, also known as the standard normal distribution or the z-distribution, is a specific probability distribution that follows a bell-shaped curve. The area under the standard normal curve to the right of z = 3 is approximately 0.0013.

For the area under the standard normal curve to the right of z = 3, we need to calculate the cumulative probability from z = 3 to positive infinity.

The standard normal distribution, also known as the z-distribution, has a mean of 0 and a standard deviation of 1. It is a symmetric bell-shaped curve that represents the distribution of standard scores or z-scores.

Using statistical tables or software, we can find the cumulative probability associated with z = 3, which represents the area under the curve to the left of z = 3.

The cumulative probability for z = 3 is approximately 0.9987.

For the area to the right of z = 3, we subtract the cumulative probability from 1.

Therefore, the area to the right of z = 3 is approximately 1 - 0.9987 = 0.0013.

In conclusion, the area under the standard normal curve to the right of z = 3 is approximately 0.0013.

This means that the probability of randomly selecting a value from the standard normal distribution that is greater than 3 is approximately 0.0013 or 0.13%.

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Answer:

Rr = 51 : 68

Step-by-step explanation:

Answer: line ZX is congruent to line VX (option 4)

Step-by-step explanation:

We already know <X is congruent to <X, we also know that line YX is congruent to line XW. Now all we need is one more line adjacent to X which is going to be ZX ad VX

Answer:

Step-by-step explanation:

Answer:

The slope of AB = slope of CD and slope of BC = slope of DA

Hope this helps!

Step-by-step explanation: