Radium decays to form radon. Which equation correctly describes this decay? Superscript 226 Subscript 88 Baseline Upper R a right arrow Superscript 222 Subscript 84 Baseline Upper R n + Superscript 4 Subscript 4 Baseline Upper H e Superscript 226 Subscript 88 Baseline Upper R a right arrow Superscript 222 Subscript 86 Baseline Upper R n + Superscript 0 Subscript negative 1 Baseline e Superscript 226 Subscript 88 Baseline Upper R a right arrow Superscript 222 Subscript 86 Baseline Upper R n + Superscript 0 Subscript + 1 Baseline e Superscript 226 Subscript 88 Baseline Upper R a right arrow Superscript 222 Subscript 86 Baseline Upper R n + Superscript 4 Subscript 2 Baseline Upper H e

Answer:

Koh of 60 and a half

Explanation:

Answer:

1)Mixture is the combination of substance

2)There are two types of mixture such as heterogeneous mixture and homogeneous mixture

3)foreg=Salt solution ,sedimentation

Pure substance

1)Pure substances are also called elements

2)They are made up of small atoms

3)for eg= oxygen,Venadium ,Iron,Oxygen

Answer:

3.11 mg

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 2.6 hr

Original amount (N₀) = 49.7 mg

Time (t) = 10.4 hr

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 2.6 hr

Time (t) = 10.4 hr

Number of half-lives (n) =?

n = t / t½

n = 10.4 / 2.6

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the amount remaining. This can be obtained as illustrated below:

Original amount (N₀) = 49.7 mg

Number of half-lives (n) = 4

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2⁴ × 49.7

N = 1/16 × 49.7

N = 0.0625 × 49.7

N = 3.11 mg

Therefore, the amount remaining is 3.11 mg

Answer:

1.09

Explanation:

Keep in mind that the volume of the solution changes during this titration, so to compute the amount of hydronium that is neutralized during this addition of base (in order to calculate the final pH of the solution), we must calculate the moles of all species in solution initially present. Because both NaOH and HCl ionize completely:initial mol OH−=mol NaOH=(0.0050 L)(0.10 molL)=0.00050 mol OH−initial mol H3O+=mol HCl=(0.050 L)(0.10 molL)=0.0050 mol H3O+The acid is in excess, so all of the OH− present will neutralize an equivalent amount of H3O+, forming water. Thus we simply subtract the moles of hydroxide from the moles of hydronium in solution to find the resultant moles of H3O+ after this neutralization:final mol H3O+= initial mol H3O+−initial mol OH−final mol H3O+=0.0050 mol−0.00050 mol=0.0045 mol H3O+We now calculate the total volume of the solution by adding the volumes of acid and base initially combined: 0.050 L+0.0050 L=0.055 LTo get [H3O+], we divide the final moles of hydronium by the final solution volume:[H3O+]=final mol H3O+ total volume=0.0045 mol0.055 L≈0.08181molLFinally, to find pH:pH=−log[H3O+]=−log(0.08181)=1.09Since the hydronium concentration is only precise to two significant figures, the logarithm should be rounded to two decimal places.

Answer:Lymphatic malformations (LM), also known as lymphangiomas, are characterized by the overgrowth of lymphatic vessels during pre- and postnatal development.

A balanced equation may be used to describe this reaction:

HC=C(aq) + H2O(l) ⇌ H3C+C-(aq) + OH-(aq)

The Brnsted-Lowry hypothesis is an acid-base reaction theory that was separately proposed in 1923 by Johannes Nicolaus Brnsted and Thomas Martin Lowry. In a chemistry, a Brnsted-Lowry base is a molecule or ion that accepts a hydrogen ion. Because a hydrogen ion is often referred to as a proton, acids and bases are proton donors and acceptors, according to the Brnsted-Lowry definition.

Here,

The acetylide ion (HC=C) acts as a Brønsted-Lowry base in water, accepting a proton from water to form an acetylene cation (H3C+C-):

HC=C + H2O ⇌ H3C+C- + OH-

This reaction can be written as a balanced equation:

HC=C(aq) + H2O(l) ⇌ H3C+C-(aq) + OH-(aq)

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Answer:

D. 110 Joules

Explanation:

Work = Force x Distance

The given force here is 55 Newtons, and the distance the object moved against the force is 2 meters.

Therefore 2 x 55 = 110 Joules of Work.

Hope this helped!

As per the given data, 1.6 grams of oxygen reacted in this experiment.

To calculate the amount of oxygen that reacted in the experiment, we need to determine the difference in the mass of X oxide (X,O) formed and the mass of X initially used.

Given:

Mass of X = 4.6 g

Mass of X oxide (X,O) = 6.2 g

To find the amount of oxygen that reacted:

Mass of oxygen = Mass of X oxide - Mass of X

= 6.2 g - 4.6 g

= 1.6 g

Therefore, 1.6 grams of oxygen reacted in this experiment.

Calculate the mass of 1 mole of X:

Given that the mass of X is 4.6 g, we can calculate the molar mass of X by dividing the mass by the number of moles:

Molar mass of X = Mass of X / Number of moles of X

Molar mass of X = 4.6 g / 0.1 mol

Molar mass of X = 46 g/mol

Therefore, the mass of 1 mole of X is 46 grams.

Thus, the answer is 46 grams.

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Answer:The concentration of the reactants. The more concentrated the faster the rate.

Temperature.

Physical state of reactants.

The presence (and concentration/physical form) of a catalyst (or inhibitor)

Light.

There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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Wear personal defence tools, follow the guidelines and be careful with chemicals. Measure 14.72g of \(H_2SO_4\), dissolve in distilled water, and make up to 400mL in a volumetric flask.

1. Always wear appropriate personal protective equipment such as gloves, goggles, and lab coat.

2. Read and follow the instructions carefully before handling any chemical.

3. Handle the chemicals in a well-ventilated area to prevent inhalation of harmful fumes.

To prepare a 0.2M solution of tetraoxosulphate (VI) acid in a \(400cm^3\)  volumetric flask:

Calculate the amount of tetraoxosulphate (VI) acid required using the formula:

Mass = (Molarity x Volume x Molecular weight) / 1000

Where:

Molarity = 0.2M

Volume =\(400cm^3\)

Molecular weight = (4x16) + 32 + (6x16) = 98g/mol

Mass = (0.2 x 400 x 98) / 1000 = 7.84g

Weigh out 7.84g of tetraoxosulphate (VI) acid using a balance.

Transfer the weighed tetraoxosulphate (VI) acid into the \(400cm^3\) volumetric flask using a funnel.

Add distilled water to the flask until the volume reaches the \(400cm^3\) mark on the neck of the flask.

Stopper the flask and mix the solution thoroughly by inverting the flask several times.

It is important to specify the density of the tetraoxosulphate (VI) acid, as this will affect the mass required for the solution. In this case, the percentage purity of the acid is also given, which can be used to calculate the actual mass of the tetraoxosulphate (VI) acid needed.

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Answer

(2) pentene

Explanation

Double carbon-carbon bonds (unsaturation) are found in alkenes. Alkenes are hydrocarbons that contain carbon-carbon double bonds. Their general formula is CnH2n for molecules with one double bond (and no rings).

Therefore, the only molecule with a double carbon-carbon bond is:

(2) pentene

Explanation:

Hope this somewhat helped:

a. The equation for the reaction of weak acid, C6H5CO2H, with water is: C6H5CO2H + H2O <=> C6H5CO2^- + H3O^+. We can assume that all the C6H5CO2H has reacted with water to form C6H5CO2^- and H3O^+.

The pH is defined as -log(H30^+ concentration), where H30^+ is the hydronium ion, a measure of the acidic strength of the solution. At the equivalence point, all the C6H5CO2H has reacted with the NaOH to form C6H5CO2^- and Na^+. The stoichiometry of the reaction can be determined by balanced the reaction using the information given.

C6H5CO2H + NaOH <=> C6H5CO2^- + Na^+

This reaction tells us that one mole of C6H5CO2H will react with one mole of NaOH to form one mole of C6H5CO2^- and one mole of Na^+.

Answer: False

Explanation: The equilibrium constant (K_eq) is the ratio of product and reactant concentrations (or activities) at equilibrium, expressed as [products]/[reactants]. K_eq is a constant that shows the extent of a reaction at equilibrium.

Answer:

For example, the equilibrium constant of concentration (denoted by Kc) of a chemical reaction at equilibrium can be defined as the ratio of the concentration of products to the concentration of the reactants, each raised to their respective stoichiometric coefficients.

Explanation:

if it helped u please mark me a brainliest :))

Answer:

O nome "transição" vem da posição dos elementos na tabela, representando a transição do grupo 2 ao 13, pela sucessiva adição de elétrons ao orbital d. Elementos de transição externa (ou somente elementos de transição):

Answer:

sadgsddagd

Explanation:

how are you doing?

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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Answer:

aluminum i think

Explanation:

Circuits C and D are parallel circuits. Therefore, options C and D are correct.

Parallel circuits are a type of electrical circuit configuration where multiple components are connected in parallel to the same power source. In a parallel circuit, each component has its own separate path for current to flow. It allows independent current flow through each component.

In a parallel circuit, the components, such as resistors, lamps, or other electrical devices, are connected side by side, with each component having its own branch or "loop" connecting it to the power source.

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In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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The society with the least negative effects on the environment is probably the one with a small population, traditional farming methods, no access to contemporary technology, and self-sufficient food production.

This is due to the fact that their way of living is less dependent on modern infrastructure and technology, both of which have a negative impact on the environment. Additionally, their agricultural methods are probably more environmentally friendly and sustainable.

The environmental effects of the other societies on the list would all be greater. Because of the use of fossil fuels and the production of products that require a lot of resources, a big, industrialized society with high levels of consumption would have a significant carbon footprint.

It would still take a lot of resources to maintain its infrastructure and create products in a less populous, highly industrialized society with moderate consumption levels, which would have a negative effect on the environment.

Given that the size of the population alone would necessitate significant resource consumption and infrastructure development, a big population with moderate industrialization and consumption levels would also have a big effect on the environment.

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The doctor would then be aware of Greg's weight of 108.6 kg.

Typically, you won't be allowed to eat or drink for six hours prior to the procedure, although you can drink water. Moreover, you should refrain from intense activity for 24 hours before to your consultation. It's wise to dress comfortably and loosely.

The internal organs and tissues of your body are depicted in great detail by a CT scan. A PET scan can be more sensitive than other imaging procedures and can detect aberrant activity. Also, it can cause your body to alter sooner. PET-CT scans are used by doctors to reveal more details about the cancer.

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Answer:

56.67 g of NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

N₂ + 3H₂ —> 2NH₃

Next, we shall determine the masses of N₂ and H₂ that reacted and the mass of NH₃ produced from the balanced equation. This is illustrated below:

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of H₂ = 1 × 2 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

Molar mass of NH₃ = 14 + (3×1) = 14 + 3 = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

SUMMARY:

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂ to produce 34 g of NH₃

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂.

Therefore, 80 g of N₂ will react with = (80 × 6)/28 = 17.14 g of H₂.

We can see from the calculation made above that a higher mass (i.e 17.14 g) of H₂ than what was given (i.e 10 g) is required to react completely with 80 g of N₂. Thus, H₂ is the limiting reactant and N₂ is the excess reactant.

Finally, we shall determine the maximum mass of ammonia (NH₃) produced from the reaction.

To obtain the maximum mass of NH₃, the limiting reactant will be used because all of it is consumed in the reaction.

The limiting reactant is H₂ and the maximum mass of NH₃ can be obtained as follow:

From the balanced equation above,

6 g of H₂ reacted to produce 34 g of NH₃.

Therefore, 10 g of H₂ will react to produce = (10 × 34)/6 = 56.67 g of NH₃.

Therefore, 56.67 g of NH₃ is produced from the reaction.

Answer:

Your answer will be C

Explanation:

hope this helps

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm.

To calculate the pressure exerted by a column of mercury, we can use the formula:

Pressure = density * gravity * height

Given:

Density of mercury = 13.6 g/cm³

Height of the mercury column = 760 mm = 76 cm

Acceleration due to gravity = 9.8 m/s²

First, we need to convert the height of the mercury column from centimeters to meters:

Height = 76 cm * (1 m / 100 cm) = 0.76 m

Now, we can calculate the pressure:

Pressure = 13.6 g/cm³ * 9.8 m/s² * 0.76 m

To ensure consistent units, we need to convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³):

Density = 13.6 g/cm³ * (1 kg / 1000 g) * (1 cm³ / (1e-6 m³))

Density = 13600 kg/m³

Plugging in the values into the pressure formula:

Pressure = 13600 kg/m³ * 9.8 m/s² * 0.76 m

Pressure = 99992.8 Pa

We can express the pressure in terms of atmospheric pressure:

1 atm = 101325 Pa (approximately)

To compare the pressure with atmospheric pressure, we can convert 99992.8 Pa to atm:

Pressure in atm = 99992.8 Pa / 101325 Pa/atm

Pressure in atm ≈ 0.987 atm

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm. Since atmospheric pressure near sea level is approximately 1 atm, this calculation supports the claim that atmospheric pressure near sea level is equivalent to the pressure exerted by a column of mercury about 760 mm high.

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Answer:

0.00000000000000084

Explanation:

The new  concentration = 2 M

Dilution is a process of decreasing the concentration of a solution by adding a number of solvents

Can be formulated

M₁V₁=M₂V₂

M₁ = Initial Molarity

V₁ = Initial volume

M₂ = Final Molarity (after dilution)

V₂ = Final volume (after dilution)

V₁=5 L

V₂=10 L

M₁=4 M

The new  concentration(M₂) :

\(\tt M_2=\dfrac{V_1.M_1}{V_2}\\\\M_2=\dfrac{5\times 4}{10}\\\\M_2=2~M\)

Answer:

Q = 202.05 J

Explanation:

Given data:

Mass of iron = 75 g

Initial temperature = 295 K

Final temperature = 301 K

Specific heat capacity of iron = 0.449 J/g.K

Heat required = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = 301 K - 295 K

ΔT  = 6K

Q = 75 g ×0.449 J/g.K × 6K

Q = 202.05 J

Answer:

it's an example of a closed circuit