Q1. Name the method of separation that you will apply for separation of the following mixtures? (a) Amnonium chloride from a powdered mixture of sodium chloride and Ammonium chloride.

12.308% of the chemical is sulfur. The compound's whole sulfur content is transformed into barium sulfate. Therefore, the mass for sulfur from barium sulfate will match the mass for sulfur in the compound.

People are not highly poisonous to sulfur. However, consuming far to much sulfur may result in diarrhea or a burning feeling. Sulfur dust inhalation might irritate the airway or make one cough. The eyes and skin may also become irritated by it.

Sulfur can indeed be found in sulfide ores and in nature. It is native to areas close to volcanoes and hot springs. The tenth most common element, sulfur, is found in almost all types of plant and animal life, meteorites, ocean ocean, the humankind's crust, and or the atmosphere.

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Based on the formula for calculating quantity of Heat, the student requires the mass, temperature change and the specific heat capacity of the reaction mixture.

The enthalpy change of a reaction is the amount of heat evolved or absorbed when reactant molecules react to form products.

In the use of a calorimetry to determine the enthalpy of a reaction, the law of conservation of energy is applied.

The quantity of Heat is calculated using the formula below:

Therefore, in addition to the masses of the solutions and the temperature change, the student requires the specific heat capacity of the reaction mixture.

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Answer:

90.71 KJ

Explanation:

From the reaction equation, lead is the cathode while copper was the anode.

Hence;

E°anode = +0.34V

E°cathode = -0.13 V

E°cell =E°cathode - E°anode

E°cell = -0.13 V - 0.34V

E°cell = -0.47 V

But;

ΔG° = -nFE°cell

n= number of electrons transferred = 2

F = Faraday's constant = 96500 C

E°cell = -0.47 V

ΔG° = -(2 * 96500 * (-0.47))

ΔG° = 90,710 J or 90.71 KJ

The standard Gibbs free energy for the reaction

Pb²⁺(aq) + Cu(s) → Pb(s) + Cu²⁺(aq) is 89.3 kJ/mol.

Let's consider the following redox reaction.

Pb²⁺(aq) + Cu(s) → Pb(s) + Cu²⁺(aq)

We can identify both half-reactions.

Reduction (Cathode): Pb²⁺(aq) + 2 e⁻ → Pb(s)    E°red = -0.126 V

Oxidation (Anode): Cu(s) → Cu²⁺(aq) + 2 e⁻       E°red = +0.337 V

We can calculate the standard potential of the cell (E°cell) using the following expression.

E°cell = E°red,cathode - E°red,anode = -0.126 V - 0.337 V = -0.463 V

The standard Gibbs free energy (ΔG°) is a way to measure the spontaneity of a reaction. We can calculate it using the following expression.

ΔG° = − n × F × E°cell =

ΔG° = − 2 mol × (96,485 J/V.mol) × (-0.463 V) × (1 kJ/1000 J) = 89.3 kJ/mol

where,

Since ΔG° > 0, the reaction is not spontaneous.

The standard Gibbs free energy for the reaction

Pb²⁺(aq) + Cu(s) → Pb(s) + Cu²⁺(aq) is 89.3 kJ/mol.

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Answer:

The energy required to evaporate a cup of water (270 g) is approximately 2,215 joules. This is calculated by multiplying the mass of the water by the latent heat of vaporization (2.26 kJ/g) for water.

Explanation:

Answer:2.26 kj

Explanation:

Answer: the answer is B: Minerals dissolve and crystallize! :D

Explanation: hope this helps!

Answer:  D- average change in plant height, divided by, the number of days.

(i had to look up the test you were talking about to find what the answer choices were.)

Hope this helps!

Answer:

Chlorine is more likely to steal a valence electron from sodium.

Explanation:

Sodium is number 11 on the periodic table with one valence electron. Belonging to the first group, it's one of the alkali metal, which are known to be highly reactive. Chlorine is number 17 with seven valence electrons, and it's in the second-to-last group of halogens--also very reactive.

Considering that elements with one valence electron are just about 100% likely to give up electrons to reach a stable state, sodium would be the element that is more likely to lose its valence electron to chlorine. In other words, chlorine would be the electron thief.

The concentration of Cu2+(aq) in the solution is approximately 2.70x10^-7 M in 1.00 L solution contains 4.00×10-4 M Cu(NO3)2 and 3.000×10-3 M ethylenediamine.

To solve for the concentration of Cu2+(aq), we need to first find the concentration of Cu(en)22+ by using the Kf value and the concentration of ethylenediamine.
Kf = [Cu(en)22+]/([Cu2+][en]2)
1.00x10^20 = [Cu(en)22+]/(4.00x10^-4)(3.000x10^-3)^2
[Cu(en)22+] = 2.70x10^-7 M
Now we can use the stoichiometry of Cu(en)22+ and Cu(NO3)2 to find the concentration of Cu2+(aq).
2Cu(NO3)2 + 3en -> Cu(en)22+ + 4NO3-
Since the concentration of Cu(NO3)2 is known, we can set up an equation:
(2 mol Cu(NO3)2/1 L) x (1 mol Cu(en)22+/2 mol Cu(NO3)2) x (2.70x10^-7 M Cu(en)22+) = 2.70x10^-7 M Cu2+(aq)
Therefore, the concentration of Cu2+(aq) in the solution is 2.70x10^-7 M.

By using the Kf value and the stoichiometry of Cu(en)22+ and Cu(NO3)2, we were able to find the concentration of Cu2+(aq) in the solution.

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Answer:

is this exam.. are you coping..

Answer: The answer is 41.5 C

(45.0 g)(x - 20 C) = (22.3 g)(85 C - x )

45.0x + 900 C = 1895.5 C - 22.3x

+22.3 x - 900 C = -900 C + 22.3 x

67.3x = 2795.5

2795.5 / 67.3 = 41.54 C

Explanation:

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

Answer: The organic reactant is 1,3-propanedithiol. This molecule contains two thiol groups (-SH) separated by a three-carbon chain. In the presence of iodine, the thiol groups are oxidized to the corresponding disulfide (-S-S-) bonds. One of the thiol groups can then be protected with a suitable reagent such as acetone or dimethoxyethane to give a thioketal.

Protecting groups are commonly used in organic synthesis to selectively mask certain functional groups. They allow for specific reactions to occur at desired sites without interfering with other functional groups present in the molecule. In the case of the thioketal product shown, the protecting group used is likely an acetone ketal. This involves reacting one of the thiol groups with acetone in the presence of acid to form a ketal, which protects the thiol from further reaction while allowing the other thiol to react with iodine.

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\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)

\(\qquad \tt \rightarrow \:7 \)

____________________________________

\( \large \tt Solution \: : \)

Iodine (I) has 7 electrons in its outermost shell, so the lewis dot symbol for I has 7 dots ( representing 7 valance electrons )

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The electric potential energy of this configuration of charges is −71.92 nJ, which when rounded to two decimal places is −150 nJ.

Diagram of carbon dioxide:

        O

      //

O = C = O

      \\

         O

In the given diagram, the two oxygen atoms have a charge of −2e, and the carbon atom has a charge of +4e.

The electric potential energy of this configuration of charges is given by the equation:

Electric potential energy = (kq1q2) / d

where k is Coulomb's constant, q1 and q2 are the charges of the two point charges, and d is the distance between them.

The value of k is 8.99 × 109 Nm2/C2, q1 and q2 are −2e and +4e respectively, and the distance between them is 116.3 pm + 232.6 pm = 348.9 pm = 3.489 × 10⁻⁹ m.

The electric potential energy of this configuration of charges is:

Electric potential energy = (kq1q2) / d= (8.99 × 10⁹ × (-2e) × 4e) / (3.489 × 10⁻⁹)

                                         = -71.92 × 10⁻⁹ J

                                         = -71.92 nJ (rounded to two decimal places)

Therefore, the electric potential energy of this configuration of charges is −71.92 nJ, which when rounded to two decimal places is −150 nJ.

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The concentration of Ba(OH)2 is 0.1224 M. After neutralization, [Ba2+] is 0.1224 M, and [Cl-] is 0.2448 M.


1. Balanced molecular equation: Ba(OH)2 (aq) + 2HCl (aq) → BaCl2 (aq) + 2H2O (l)
2. Calculate the moles of HCl: Moles = Molarity * Volume = 0.1108 M * 0.03327 L = 0.003684 moles HCl
3. Moles of Ba(OH)2: Since the ratio between HCl and Ba(OH)2 is 2:1, moles of Ba(OH)2 = 0.003684 / 2 = 0.001842 moles
4. Concentration of Ba(OH)2: M = moles / volume = 0.001842 moles / 0.030 L = 0.1224 M
5. Concentration of Ba2+ and Cl-: Since the ratio of Ba2+ to Ba(OH)2 is 1:1, [Ba2+] = 0.1224 M. The ratio of Cl- to HCl is 1:1, so moles of Cl- = 2 * moles of HCl = 0.007368 moles. [Cl-] = moles / total volume = 0.007368 moles / (0.030 L + 0.03327 L) = 0.2448 M.

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In a shallow cylindrical lake with a radius of 4 km and an average water height of 5 m, a type A exhaust basin recorded a total water loss of 4.5 cm during a summer month.

The task is to calculate the evaporation of the lake and the volume of lake water in cubic meters for that specific time period, assuming an evaporation coefficient of 0.7. To calculate the evaporation of the lake, we first convert the recorded water loss from centimeters to meters. The total water loss is 4.5 cm, which is equal to 0.045 meters.

The evaporation from the lake can be determined by multiplying the water loss by the evaporation coefficient. In this case, the evaporation coefficient is given as 0.7. So, the evaporation from the lake is calculated as:

Evaporation = Water loss * Evaporation coefficient

Evaporation = 0.045 m * 0.7 = 0.0315 m

Therefore, the evaporation of the lake during the specified time period is 0.0315 cubic meters.To calculate the volume of lake water, we need to consider the shape of the lake, which is a shallow cylinder. The formula for the volume of a cylinder is:

Volume = π * radius^2 * height

Given that the radius of the lake is 4 km (4000 m) and the average water height is 5 m, we can calculate the volume of the lake as:

Volume = π * (4000 m)^2 * 5 m = 251,327,412 m^3

Therefore, the volume of lake water for the specific time period is approximately 251,327,412 cubic meters.

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The muscles of the stomach crush food that has entered the stomach cavity is a physical change. The correct option is D. a physical change.

Digestion is the breakdown of food material in the stomach, which produce energy.

Digestion includes a chemical and physical process. The food is digested by the chemicals present in the stomach.

Thus, the correct option is D. a physical change, only.

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Answer:

Silver —Ag — Argentum

Explanation:

pls mark as brainliest

Answer:

Explanation:

The symbol of the element silver is Ag. It is derived from the Latin word "argentum". Silver is also used for making jewellery.

Answer:

True

Explanation:

It is true that every element in the periodic table follows the Aufbau's principle.

The principle states that "the sublevels with lower energies are filled up before those with higher energies".

Answer:False

Explanation:

Molality is defined as the "moles solute/kg solvent." Therefore, the correct option is (b).

What is Molality?

Molality (m) is a measure of the concentration of a solute in a solution, and is defined as the number of moles of solute per kilogram of solvent.

The equation for molality is:

m = moles of solute / mass of solvent in kg

Concentration is the ability to focus one's attention and mental effort on a specific task or activity. It involves filtering out distractions and staying attentive to the task at hand. The level of concentration can vary depending on the person, the task, and the environment.

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Formal charge = valence electrons - Number of non bonding electrons - number of shared electrons ÷ 2

A formal charge (F.C.) is the charge assigned to an atom in a molecule in the covalent view of bonding, assuming that electrons in all chemical bonds are shared equally between the atoms, regardless of their relative electronegativity.

The formal charge is generally the difference between an atom's number of valence electrons in its neutral free state and the number allocated to that atom in a Lewis dot structure.

When choosing the optimum Lewis structure or also called as the  predominant resonance structure  for a molecule, it is important to keep the formal charge on each of the atoms as low as feasible.

The following equation can be used to compute the formal charge of an atom in a molecule:

Formal charge = valence electrons - Number of non bonding electrons - number of shared electrons ÷ 2

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Answer:

reactants

Explanation:

The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

The mole fraction of benzoic acid in the solution is 0.855.

What is benzoic acid?

Benzoic acid is a white solid which is a carboxylic acid based on benzene.

The vapor pressure of the benzoic acid solution and the mole fraction of the solute are directly proportional to each other i.e.

Pt = x P°s

Here t = total pressure

s = solvent

Given:

Vapor pressure of diethyl ether = 400.0 torr

Vapor pressure of the solution = 342 torr

Now substituting the values in the formula

342 =   x 400

= 342 / 400

 = 0.855

Thus, the mole fraction of benzoic acid is 0.855

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Answer:

Presence of an Electrolyte

Metal Surface

Oxygen or Other Oxidizing Agent

Difference in Potential

Electrochemical Pathway

Explanation:

The concentration of \(\rm Ca^ {2+}\) when \(\rm Ag_2SO_4_\ {(s)}\) begins to precipitate is 0.0500 M, when sodium sulfate is slowly added to a solution.

Concentration is a measure of the amount of solute dissolved in a given amount of solvent or solution.

When sodium sulfate is added to the solution, it reacts with the calcium ions to form calcium sulfate, which is insoluble and precipitates out of the solution. The balanced equation for the reaction is:

\(\rm Ca^{2+} + SO_4^{2-} \rightarrow CaSO_4\)

The solubility product constant (Ksp) of calcium sulfate is \(4.93 \times 10^{-5}\) .

\(\rm Ag_2SO_4_\ {(s)}\) is also formed by the reaction of \(\rm Ag^+\)and \(\rm SO_4^{2-}\), but it is not used up until all \(\rm Ca^ {2+}\) ions are consumed.

Therefore, \(\rm Ag_2SO_4_\ {(s)}\) does not precipitate until all \(\rm Ca^ {2+}\) ions have reacted.

The concentration of \(\rm Ca^ {2+}\)when \(\rm Ag_2SO_4_\ {(s)}\) begins to precipitate can be calculated using the Ksp expression for \(\rm CaSO_4\):

\(\rm Ksp = [Ca^{2+}][SO_4^{2-} ]\)

Since the reaction is 1:1, the concentration of \(\rm Ca^ {2+}\) is equal to the initial concentration of \(\rm Ca^ {2+}\) before any reaction occurs.

Therefore, the concentration of \(\rm Ca^ {2+}\) when \(\rm Ag_2SO_4_\ {(s)}\) begins to precipitate is 0.0500 M.

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Answer:

Explanation:

To find the number of moles given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

\(n = \frac{2.8 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.65116279069...\)

We have the final answer as

Hope this helps you

Explanation:

19/9 F -1 (19 is stacked over 9 next to F) #protons: 9, #neutrons: 10, #electrons: 10

55/26 Fe +3, atomic #: 26, mass #: 55, #protons: 26, #neutrons: 29, #electrons: 23