Problems:
Show all three steps of using a formula - show the formula, fill in the formula, 8 solve for the answer.
22) Calculate the energy of a photon of radiation with a frequency of 9.50 x 10¹³ Hz.

HINT:
You can make the formula parts larger by dragging them to the size that you prefer. DELETE THIS BOX AFTER READING!
HINT:
To make a superscript, cntrl / cmmd. (period)

Problems:Show All Three Steps Of Using A Formula - Show The Formula, Fill In The Formula, 8 Solve For

Answers

Answer 1

The energy of a photon of radiation with a frequency of 9.50 × 10¹³ Hz is 6.3 × 10⁻²⁰ J.

The Energy that comes from electromagnetic radiation is quantized, It exists in the form of small energy packets known as photons. The energy of a photon is dependent on the frequency at which it is propagating from the source of radiation.

The energy of a photon is given by the equation:

E = hν

here, E is the energy of photon

h is Plancks's constant whose value is 6.626 × 10⁻³⁴ Js

ν is the frequency

According to the question,

given, frequency ν = 9.50 × 10¹³ Hz

therefore,

E = 6.626 × 10⁻³⁴ Js ×  9.50 × 10¹³ Hz      (1 Hz = 1s⁻¹)

E = 6.2947 × 10⁻²⁰ J

E≈ 6.3 × 10⁻²⁰ J

Thus, energy of the photon is 6.3 × 10⁻²⁰ J

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Related Questions

7.0 x 10 -3 mol of I2 in 100.00ml of solution

Answers

To determine the concentration of the I2 solution, we need to calculate the molarity (M) using the given information. Molarity is defined as moles of solute per liter of solution.

Given:
- Moles of I2: 7.0 x 10^(-3) mol
- Volume of solution: 100.00 mL (which is equal to 0.1000 L)

Molarity (M) = Moles of solute / Volume of solution in liters

Molarity = (7.0 x 10^(-3) mol) / (0.1000 L)

Molarity = 0.070 M

Therefore, the concentration of the I2 solution is 0.070 M.

help me please....................

help me please....................

Answers

Answer:

Explanation:

one was important for the other

You are working with a concentrated solution of ammonium hydroxide which place of safety equipment is most important to have on hand

Answers

I would say safety goggles
Lab coat, eye protection and gloves

The following reaction occurs in a car’s catalytic converter.

2 upper N upper O (g) plus 2 upper C upper O (g) right arrow upper N subscript 2 (g) plus 2 upper C upper O subscript 2 (g).

Which answer best describes the reducing and oxidizing processes in this reaction?
NO and CO are both reducing agents.
NO and CO are both oxidizing agents.
The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
The oxidation state of nitrogen in NO changes from 0 to +2, and the oxidation state of carbon in CO changes from +4 to +2 as the reaction proceeds.

Answers

Answer:

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Explanation:

In the catalytic converter, the oxidation number of nitrogen in NO changes from +2 to 0, and of carbon in CO changes from +2 to +4 as the reaction proceeds. Thus, option C is correct.

What is a catalytic converter?

The catalytic converter is a device used in vehicle exhaust to reduce the emission of toxic gas. The reaction in the device occurs to convert the nitric oxide into oxygen and nitrogen.

The redox reaction is given as,

2NO(g) + 2CO(g) → N₂(g) + 2CO₂(g)

In the reduction half of the reaction, the electrons are lost (addition of oxygen) like in carbon monoxide the oxygen is added that changes the number from +2 to +4. CO is a reducing agent that oxidized the carbon atom.

In the reduction half of the reaction, the oxygen is removed (electrons are added) and is shown by NO where the oxygen was lost to form N₂ with oxidation +2 to 0.

Therefore, option C. NO is a reducing agent that reduced nitrogen in the reaction.

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What is the molecular weight of H2O

Answers

Answer:

18.015

Explanation:

Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.

If the sum of the last
number and the middle
number of three consecutive
integersis is 71, then the
Least (smallest) number
mumber must be​

Answers

Answer:

number must be 0000.999

Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Sn2+]=0.0624 M, [Fe3+]=0.0437 M, [Sn4+]=0.00655 M, and [Fe2+]=0.01139 M. Standard reduction potentials can be found in this table.

Sn2+(aq)+2Fe3+(aq)↽−−⇀ Sn4+(aq)+2Fe2+(aq)

So far my incorrect answers have been:
0.28
0.798
0.178
0.142
0.881
0.61
and 0.812

Answers

Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

How to the cell potential of galvanic cell?

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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If the components of a solution are in the same state, which one is the solvent?​

Answers

Answer:

Usually, the substance present in the greatest amount is considered the solvent.

Scientists have developed a new way to extract natural gas, called hydraulic fracturing, or fracking. Which of these is a positive impact of this method?

A. Decreased habitat
B. Decreased earthquakes
C. Increased supply
D. Increased demand​

Answers

Answer:

The answer is C if its wrong you can report my answer I'm 100% sure its C

The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is ________ J. The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is ________ J. 0.950 145 113 1450 113000

Answers

The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is  113.30 J. Option D

The kinetic energy of an object can be calculated using the formula: KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity or speed of the object.

Given:

Mass (m) = 23.2 g = 0.0232 kg

Speed (v) = 98.7 m/s

Substituting these values into the formula, we can calculate the kinetic energy:

KE = (1/2)(0.0232 kg)(98.7 m/s)^2

KE = (1/2)(0.0232 kg)(9756.09 m^2/s^2)

KE ≈ 113.30 J

Therefore, the kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is approximately 113.30 J.

It's worth noting that the question is repeated twice, but the answer remains the same. The kinetic energy of the object is determined by its mass and speed, and both calculations yield the same result. Option D

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when the temperature of an ideal gas is increased from 27C to 927C then kinetic energy increases by

Answers

Answer:

The rms speed of its molecules becomes. (T) has become four times. Therefore, v_(rms) will become two times,...

In what part of the atom do alpha or beta particles originate?

Answers

Answer:

Nucleus

Explanation:

they originate in the nucleus

Which list contains renewable natural resources found in Florida?
wind, sunlight, water
oranges, wind, water, limestone
oil, sand, sunlight, water
sand, oil, limestone, oranges

Answers

Answer:

the answer is wind sun and water

Natural resources

The answer is B

Florida of course has oranges and water because it has fertile soil and is a peninsula, it also has wind from the oceanic currents, and Florida is sitting on large slabs of limestone.

-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:​

Answers

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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6.67 x 10-3 g of arsenic (As) is found in a 0.600 L sample of water. If the density of this
sample is 1.00 g/mL, what is the concentration of arsenic in ppm?

Answers

ppm = mg/L = mg/kg

6.67 x 10⁻³ g = 6.67 mg

ppm = 6.67 mg : 0.6 L = 11.12

What is the electron configuration for magnesium (Mg)?

O A. 1s²2s²2p²356
B. 15²25²3s23p6
C. 3s²3p 3d
D. 1s²2s²2p63s²

Answers

Answer:

D is correct.(1s22s22p63s2)

The answer is D 1s2 2s2 2p6 3s2

Write chemical equations for these reactions. a. When solid naphthalene (C10H2)(C10H2) bums in air, the reaction yields gaseous carbon dioxide and liquid water. b. Bubbling hydrogen sulfide gas through manganese(ll) chloride dissolved in water results in the formation of the precipitate manganese(II) sulfide and hvdrochloride acid. c. Solid magnesium reacts with nitrogen gas to produce solid magnesium nitride. d. Heating oxygen difluoride gas yields oxygen gas and fluorine gas.

Answers

The chemical equations for these reactions are as follows

a. C10H8 + 12 O2 → 10 CO2 + 4 H2O

b. H2S(g) + MnCl2(aq) → MnS(s) + 2 HCl(aq)

c. 3 Mg(s) + N2(g) → Mg3N2(s)

d. 2 OF2(g) → 2 O2(g) + F2(g)

a. Naphthalene is a hydrocarbon with the chemical formula C10H8. When it is heated in the presence of oxygen (air), it undergoes combustion. The reaction produces carbon dioxide (CO2) and water (H2O) as the products. The combustion of naphthalene is an example of a combustion reaction.

b. Chemical reaction takes place when hydrogen sulphide gas (H2S) is bubbled through a manganese(II) chloride (MnCl2) solution dissolved in water. The result of the reaction is a precipitate of hydrochloric acid (HCl) and manganese(II) sulphide (MnS). It is an example of a double displacement or precipitation reaction.

c. Chemical reaction takes place when solid magnesium (Mg) is heated in the presence of nitrogen gas (N2). Solid magnesium nitride (Mg3N2) is the end result of the reaction. It is an example of a synthesis reaction.

d. Heat causes a chemical reaction in oxygen difluoride gas (OF2) that results in the production of oxygen gas (O2) and fluorine gas (F2). The decomposition of oxygen difluoride gas into oxygen and fluorine gases upon heating is an example of a decomposition reaction.

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1) If I have 8 moles of a gas at a pressure of 15.6 atm and a volume of 42 liters, what
is the temperature?

Answers

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas. The ideal gas law is given by:

PV = nRT

where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)

We can rearrange this equation to solve for the temperature:

T = PV / (nR)

Plugging in the given values, we get:

T = (15.6 atm) x (42 L) / (8 mol x 0.0821 L·atm/mol·K)

Simplifying this expression, we get:

T = 758.16 K

Therefore, the temperature of the gas is 758.16 K.

what are thetypes of luminous flame

Answers

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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How many grams of rock salt, NaCl, do you need to add to a 3.78 kg of ice, to get the temperature
to drop to -19C?

Answers

1129.9 grams of rock salt, NaCl needs to be added to a 3.78 kg of ice, to get the temperature to drop to -19C .

What is freezing point depression?

Freezing point depression refers to a property of solutions where addition of a solute lowers the normal freezing point of the solvent.

The Blagden's Law given as the equation above is used to determine the freezing point depression of ice:

\(ΔT = iK_fm\)

where;

ΔT = Change in temperature in °Ci = van 't Hoff factorKf = molal freezing point depression constantm = molality of the solute in mol solute/kg solvent.

For NaCl, i = 2

Kf for water/ice = 1.86 °C kg/mol

molalityof NaCl = (mass/molar mass

l)/kg of ice

mass of NaCl = molality × mass of ice × molar mass

molar mass of NaCl = 58.5

mass of ice = 3.78 kg

Let molality of NaCl = m

ΔT = 19 °C

Substituting the values:

19 = 2 x 1.86 °C kg/mol x m

m = 5.11 mol/kg

mass of NaCl = 5.11 × 3.78 × 58.5

mass of NaCl = 1129.9 g

Therefore, the mass in grams of rock salt, NaCl that needs to be added to a 3.78 kg of ice, to get the temperature to drop to -19C is 1129.9 g

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Please help solve these chemistry questions!!!

Practice with percent composition.
1. What is the percent composition of Fe if 111.7 g of Fe is recovered from a 159.7 g sample of Fe2O3?




2. What is the percent composition of O if 12 g of O is recovered from a 38 g sample of Cr2O3?




3. Calculate the percent composition of KCl.





4. Calculate the percent composition of N2O5.





Practice with empirical formulas
5. What is the empirical formula for a compound that contains 0.0260 mol C, 0.0325 mol H, and 0.0065 mol O.



Practice with Molecular Formulas
6. Determine the molecular formula for a compound that has an empirical formula of NO2 and a molar mass of 138.015 g/mol.





7. Nicotine is 74.1% C, 8.6% H, and 17.3% N by mass. It’s molar mass is about 160 g/mol.
a. What is it’s empirical formula?




b. What is it’s molecular formula?

Answers

To find the percent composition of Fe in Fe2O3, we need to calculate the molar mass of Fe and the molar mass of Fe2O3. The molar mass of Fe is 55.85 g/mol, and the molar mass of Fe2O3 is 159.7 g/mol.
To calculate the percent composition of Fe:
(55.85 g/mol / 159.7 g/mol) × 100% = 34.9%

Therefore, the percent composition of Fe in Fe2O3 is 34.9%.

Similarly, to find the percent composition of O in Cr2O3, we need to calculate the molar mass of O and the molar mass of Cr2O3. The molar mass of O is 16.00 g/mol, and the molar mass of Cr2O3 is 152 g/mol.
To calculate the percent composition of O:
(16.00 g/mol / 152 g/mol) × 100% = 10.5%

Therefore, the percent composition of O in Cr2O3 is 10.5%.

The formula for potassium chloride (KCl) consists of one potassium atom (K) and one chlorine atom (Cl). To calculate the percent composition of KCl, we need to calculate the molar mass of KCl.
The molar mass of KCl is:
39.10 g/mol (molar mass of K) + 35.45 g/mol (molar mass of Cl) = 74.55 g/mol

To calculate the percent composition of K:
(39.10 g/mol / 74.55 g/mol) × 100% = 52.4%

To calculate the percent composition of Cl:
(35.45 g/mol / 74.55 g/mol) × 100% = 47.6%

Therefore, the percent composition of KCl is 52.4% K and 47.6% Cl.

The formula for dinitrogen pentoxide (N2O5) consists of two nitrogen atoms (N) and five oxygen atoms (O). To calculate the percent composition of N2O5, we need to calculate the molar mass of N2O5.
The molar mass of N2O5 is:
2 × (14.01 g/mol) (molar mass of N) + 5 × (16.00 g/mol) (molar mass of O) = 108.01 g/mol

To calculate the percent composition of N:
(2 × 14.01 g/mol / 108.01 g/mol) × 100% = 25.9%

To calculate the percent composition of O:
(5 × 16.00 g/mol / 108.01 g/mol) × 100% = 74.1%

Therefore, the percent composition of N2O5 is 25.9% N and 74.1% O.

To determine the empirical formula for a compound with given mole ratios, we need to divide each mole value by the smallest mole value to obtain the simplest whole number ratio.
Given:
0.0260 mol C
0.0325 mol H
0.0065 mol O

Dividing each mole value by 0.0065 (the smallest mole value), we get:
C: 0.0260 mol / 0.0065 mol = 4
H: 0.0325 mol / 0.0065 mol = 5
O: 0.0065 mol / 0.0065 mol

1. What determines the chemical and physical properties of an element?

2. How are chemical and physical properties the same, how are they different?

Answers

Answer:

Chemical properties of each element are determined by the element's electronic configuration, and particularly by its outermost valence electrons. .

What is the product of the unbalanced equation below?
Ca(s) + O2(g)

A. CaO2(5)
B. Cao(s)
C. 2Ca(s) + O2(9)
D. Ca20(s)

Answers

B. Cao(s) (Calcium oxide)

The balanced equation would be:

Ca(s) + O2(g) --> Cao(s)

It is the product of Calcium oxide.

What is the product of the reaction between sodium and chlorine?

The product of the reaction between sodium and chlorine is sodium chloride (NaCl). When sodium (Na) and chlorine (Cl) react, they form an ionic bond, with the sodium atom losing one electron to the chlorine atom. This forms a positively charged sodium ion (Na+) and a negatively charged chloride ion (Cl-), which are held together by electrostatic attraction to form the compound sodium chloride. It is a white crystalline solid and is commonly known as table salt.

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Describe how to prepare 400 grams of a 15% (mass/mass) aqueous solution of KBr.

Answers

Dissolve 60g of potassium bromide in 340g of water to produce 15% (mass/mass) aqueous solution of potassium bromide.

Here we have to prepare a total of 400 g of solution. Aqueous solution means the solvent we use here is water.

So to prepare 400 g of 15% aqueous solution of potassium bromide, we need to find out how many grams of potassium bromide need to be dissolved in water and how many grams of water must be used.

Here the weight percent is given, that is 15%

       15/100 = weight of potassium bromide/ 400 g

       0 .15      = weight of potassium bromide / 400

      weight of potassium bromide needed = 0.15 × 400

                                                                       =  60 g

So, we calculated the required amount of potassium bromide as 60 grams. The total weight of the solution to be made is 400 grams.

So amount of water required = 400 - 60

                                                =  340 g

So we need to mix 60 grams of potassium bromide in 340 grams of water to get a 15% (mass/mass) aqueous solution.

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What quantity in moles of Li₂S will be required to completely react with 45.0 mL of 0.100 M Fe(NO₃)₃?
3 Li₂S(aq) + 2 Fe(NO₃)₃(aq) → Fe₂S₃(s) + 6 LiNO₃(aq)

Answers

Moles of Li₂S will be required to completely react with 45.0 mL of 0.100 M Fe(NO₃)₃ is 0.00675 moles.

The reaction is as follows :

3 Li₂S(aq) + 2 Fe(NO₃)₃(aq) → Fe₂S₃(s)  + 6 LiNO₃(aq)

Molarity = mol / V in L

Molarity = 0.100 M

Volume = 45.0 mL = 0.045 L

now , putting the values in formula :

M = mol / V

mol = M × V

moles = 0.100 × 0.045

moles = 0.0045 moles of Fe(NO₃)₃

from the equation it is clear that :

2 moles of Fe(NO₃)₃ react with 3 moles of  Li₂S

therefore, 0.0045 moles of Fe(NO₃)₃ react with = (3 × 0.0045 ) / 2

                                                                               = 0.00675 moles of Li₂S

Thus, Moles of Li₂S will be required to completely react with 45.0 mL of 0.100 M Fe(NO₃)₃ is 0.00675 moles.

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The pOH of a solution is 6.0. Which statement is correct?
Use pOH = -log[OH-] and PH+pOH = 14.
The pH of the solution is 20.0.
O The concentration of OH ions is 1.0 x 108 M.
The concentration of OH ions is 1.0 x 106 M.
O The pH of the solution is 8.0.
A

Answers

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

how many neurons does atom in the model shown below have
a.2
b.9
c.10
d.16

how many neurons does atom in the model shown below havea.2b.9c.10 d.16

Answers

The atom in the model has 9 neurons.
It would probably be B

If an object is traveling 400m/s, how long in hours will it take to reach 950.5km?

Answers

Answer:

Let's find out time using musically to we not less X elation times T um Sylvia 120 kilometer are and be known to get 70-kilometer bar are jobless acceleration. Relax. The relation is six housing kilometers where R squared times D and solving 40 t is equal to one divided by 120 hours which is equal to 32nd. Let's find a distance traveled using s is equal to a snot. Let's be not times de lis. How 50 square off 80 Um, A. Sees the exploration of car Times T's were no, that's like in numbers. So a distance is equal to 70 uh, kilometer, but are into one divided by 120 hard is less, one divided by two into x elation of God. It is a 6000-kilometer bar are square, are in duty square will t swear. He's one divided by 120 holes where so t is equal to 0.79 kilometers

Explanation:

HELP PLEASE!
When phenol dissolves in water, a few (no all) of the molecules ionize H+ from the -OH group. This makes it
O a reducing agent
O an oxidizing agent
O a weak acid
a weak base

HELP PLEASE!When phenol dissolves in water, a few (no all) of the molecules ionize H+ from the -OH group.

Answers

Answer: a weak acid

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases. Oxidizing agent is the substance which itself gets reduced by gaining electrons and thus oxidize others.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced. Reducing agent is the substance which itself gets oxidized by losing electrons and thus reduces others.

Weak acids are those substances which dissociate partially to give \(H^+\) ions when dissolved in water.

\(C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+\)

Weak bases are those substances which dissociate partially to give \(OH^-\) ions when dissolved in water.

\(NH_4OH\rightleftharpoons NH_4^++OH^-\)

An isotope of hydrogen, known as Tritium (hydrogen-3), has a half-life of 12 years. If a sample of tritium was prepared 60 years ago, what was its original mass if its current mass is 0.42 micrograms?

Options for answers:
a.) 1.7mg b.) 13.4mg c.) 6.7mg d.) 26.8mg e.) 3.4mg

Answers

The original mass of Tritium (hydrogen-3) was 13.4mg if its current mass is 0.42 micrograms.

The formula for radioactive decay is given by:

N = N0 x (1/2)^(t/T)

where,

N = final number of radioactive atoms

N0 = initial number of radioactive atoms

t = time elapsed

T = half-life of the radioactive substance

Let's substitute the given values into the formula:

0.42 μg = N0 x (1/2)^(60/12)

0.42 μg = N0 x (1/2)^5

0.42 μg = N0 x 1/32

N0 = 0.42 μg x 32

N0 = 13.44 μg

Therefore, the original mass of the tritium sample was 13.44 micrograms.

What is radioactive decay?

Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting ionizing radiation, such as alpha particles, beta particles, and gamma rays. This process can result in a change in the number of protons and/or neutrons in the nucleus, leading to the transformation of one element into another. The rate of decay is typically characterized by a half-life, which is the time required for half of the atoms in a sample to decay.

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