Answers
5)
a)
In order to calculate the force acting on the masses, we can use the formula below:
\(F=\frac{G\cdot M\cdot m}{d^2}\)Where G is the gravitational constant (G = 6.674 * 10^-11), M is the greater mass, m is the smaller mass and d is the distance between the masses.
So, for M = 6 * 10^24 kg, m = 1 kg and d = 6.4 * 10^6 m, we have:
\(\begin{gathered} F=\frac{6.674\cdot10^{-11}\cdot6\cdot10^{24}\cdot1}{(6.4\cdot10^6)^2} \\ F=\frac{40.044\cdot10^{13}}{40.96\cdot10^{12}} \\ F=9.78\text{ N} \end{gathered}\)b)
The force calculated in item a) will act on both masses, therefore the force acting on the larger object is also F = 9.78 N.
c)
The acceleration can be calculated using the second law of Newton:
\(\begin{gathered} F=m\cdot a \\ 9.78=1\cdot a \\ a=9.78\text{ m/s2} \end{gathered}\)d)
Using the second law of Newton again, we have:
\(\begin{gathered} F=M\cdot a \\ 9.78=6\cdot10^{24}\cdot a \\ a=1.63\cdot10^{-24}\text{ m/s2} \end{gathered}\)Related Questions
Suppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stick.The shrimp will jump straight upward.Will the shrimp do any work in this case?
Answers
Answer:
yes
Explanation:
I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction
In this case, the stick is the action force and nudges/pokes the shrimp. The shrimp then reacts and exerts an opposite yet equal force by jumping in a straight, upwardly manner. So, yes the shrimp does do work in this case.
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
Answers
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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The kinematic viscosity of oxygen at 40 °C and a pressure of 160 kPa is 0.104 stokes. Determine the dynamic viscosity of the oxygen at this temperature and pressure. (Ro₂ = 0.2598 kPa.m³/kg.K)
Answers
The dynamic viscosity of oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.
The dynamic viscosity of a fluid is equal to its kinematic viscosity multiplied by its density.
Given:
Kinematic viscosity of oxygen at 40°C and 160 kPa = 0.104 stokes
Density of oxygen at 40°C and 160 kPa = (160000 Pa / 0.2598 kPa.m³) = 616.55 kg/m³ (using ideal gas law)
Using the formula:
Dynamic viscosity = Kinematic viscosity * Density
We get:
Dynamic viscosity of oxygen = 0.104 stokes * 616.55 kg/m³ = 64.17 × 10⁻⁶ Pa.s
Therefore, the dynamic viscosity of the oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.
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A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.
Answers
a) The value of t u = 140/t`b.
b) The y position of the cannonball at the time t is 55.5 mc.
c) The initial speed of the projectile is 52.4 m/s.
Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.
a. To find the value of t:Here, we have to use the formula of distance
i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`
Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is
(2H) = 2 × 55.5
= 111 m`2H/g
= 111/9.8`
= 11.32653 s
From equation (1),u×t = 140u = 140/t
Therefore, `u = 140/t`b.
b)To find the y position of the cannonball at the time t:
Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,
Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².
We have already calculated the time taken by the cannonball to hit the ground in the previous step.`
y = 140 - (1/2) × 9.8 × t²`
On substituting the value of t as `t = 11.32653`,
we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.
c) To find the initial speed of the projectile:
To calculate the initial speed of the projectile, we need to use the formula of range of projectile
.i.e.,R = u²sin2θ/g
Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)
u² = R × g/sin2θ
= 140 × 9.8/sin0°
= 2744m²/s²u
= \(\sqrt(2744m^2/s^2)\)
= 52.4 m/s
Hence, the initial speed of the projectile is 52.4 m/s.
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What would you do if natural calamity or disaster strikes you now ?
Answers
Answer:
How can you help the victims of any natural calamity or disaster?If you have not been ordered to evacuate, stay in a safe area or shelter during a natural disaster. In your home, a safe area may be a ground floor interior room, closet or bathroom. Be sure you have access to your survival kit in case you are in an emergency event that lasts several days.
Explanation:
hope that helps. Make sure to be safe and sheltered
A baseball player hits a baseball. The mass of the ball is 0.15 kg. The ball accelerates at a rate of 60 m/s 2 . What is the net force on the ball to the nearest newton?
Answers
Answer:
Please find attached pdf
Explanation:
PLEASE HELP
Show how the length of day changes with latitude by plotting the following points. Use the table below as a graph and place an X in the box where you want to plot a data point. For example, if you find that a day is 10 hours long at 30° N latitude, represent this data with an X in the box where 10 hours meets 30 degrees.
Answers
The length of daylight hours is determined by the latitude of a place and the time or date of the year, which is related to the position of the Earth in relation to the Sun.
How does the time period of light vary at a particular location throughout the year?The duration of light at a point on Earth changes throughout the year due to the tilt of the Earth's axis and its revolution around the Sun. During the summer solstice, which occurs around June 21st in the Northern Hemisphere and December 21st in the Southern Hemisphere, the tilt of the Earth's axis maximizes the amount of sunlight received in that hemisphere, resulting in longer daylight hours and shorter nights. Conversely, during the winter solstice, which occurs around December 21st in the Northern Hemisphere and June 21st in the Southern Hemisphere, the tilt of the Earth's axis minimizes the amount of sunlight received in that hemisphere, resulting in shorter daylight hours and longer nights. The length of daylight gradually changes throughout the year between these solstices, with the equinoxes (around March 20th and September 22nd) marking the points of equal daylight and darkness.
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What is the illuminance on an object that is 1.50 m away from a light source with a luminous flux of 665 lumens?1) 1.87 lx2) 3.53 lx3) 23.5 lx4) 425 lx
Answers
Given data:
* The illuminance of an object is 1.5 m.
* The luminous flux is 665 lumens.
Solution:
The illuminance in terms of the flux and distance is,
\(E=\frac{P}{4\pi\times d^2}\)where P is the flux, and d is the distance of the object,
Substituting the known values,
\(E=\frac{665}{4\times\pi\times(1.5)^2}\)By solving the above values,
\(E=23.5\text{ Ix}\)Thus, the illuminance is 23.5 Ix.
Hence, 3rd option is the correct answer.
refer to question 12 on page 6/7: a type ii cepheid has an apparent magnitude of 12 and a pulsation period of 3 days. what is the approximate distance to this cepheid variable star?
Answers
If a type ii cepheid has an apparent magnitude of 12 and a pulsation period of 3 days. the approximate distance to this cepheid variable star is 0.14 parsecs.
What is the cepheid variable star about?
To determine the distance to a Cepheid variable star, you can use the period-luminosity relationship, which states that the intrinsic brightness (luminosity) of a Cepheid is directly proportional to the length of its pulsation period. In other words, the longer the period, the brighter the Cepheid.
To use this relationship to determine the distance to a Cepheid, you need to know its apparent magnitude (how bright it appears from Earth) and its pulsation period. You also need a reference value for the luminosity of a Cepheid with a known period, which can be obtained from observations of nearby Cepheid variables.
Using these values, you can calculate the distance to the Cepheid using the following formula:
distance = 10 ^ ((reference luminosity - apparent magnitude + 5) / 5)
Plugging in the values you provided, we get:
Distance = 10 ^ ((-2.5 - 12 + 5) / 5)
= 10 ^ (-9.5 / 5)
= 10 ^ (-1.9)
= 0.14 parsecs
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What is an isolated system?
A. A collection of matter that does not interact with anything else in
the universe
B. The intergalactic highway system
C. The forces that act upon an object in a collision
0
D. The system in which collisions always occur
Answers
Answer:
A
Explanation:
Isolation means that you don't interact with somebody else. For example, let's say you are sick. You have to go in a room and close the door and be alone that's the stage of been isolated.
Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
Answers
(a) The amplitude of the wave is 0.2 m.
(b) The period of the wave is 4 s.
(c) The wavelength of the wave is 100 m.
What is the amplitude of the wave?(a) The amplitude of the wave is the maximum displacement of the wave.
amplitude of the wave = 0.2 m
(b) The period of the wave is the time taken for the wave to make one complete cycle.
period of the wave = 5.5 s - 1.5 s = 4 s
(c) The wavelength of the wave is calculated as follows;
λ = v / f
where;
v is the speed of the wavef is the frequency of the wavef = 1/t = 1 / 4s = 0.25 Hz
λ = ( 25 m/s ) / 0.25 Hz
λ = 100 m
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A particle performs simple harmonic motion with period Pi/2 seconds and amplitude 12 m. What is the maximum velocity (in m/s)?
Answers
The maximum velocity is 48π m/s.
To solve this problem
The equation: can be used to determine the maximum velocity of a particle in simple harmonic motion.
Vmax = ω * A
Where
Vmax is the maximum velocityω (omega) is the angular frequencyA is the amplitude of the motionThe following formula can be used to get the angular frequency:
ω = 2π / T
Where
T is the motion's period.
Given that the period is π/2 seconds (T = π/2) and the amplitude is 12 m (A = 12), we can find the angular frequency:
ω = 2π / (π/2) = 4π rad/s
Now we can calculate the maximum velocity:
Vmax = ω * A = (4π rad/s) * (12 m) = 48π m/s
Therefore, the maximum velocity is 48π m/s.
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A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction between the refrigerator and the floor is 230 N. How much work has been performed by the mover on the refrigerator?
Answers
Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :
\(W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m\)
Hence, this is the required solution.
A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.
Answers
The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.
To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.
At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.
As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.
Therefore, we can equate the initial potential energy to the final kinetic energy:
mgh = 1/2 m\(v^{2}\),
where v is the horizontal velocity of the boy when he leaves the track.
Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:
d = vt.
Solving these equations, we can express the initial height H in terms of h and d:
H = h + d.
So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G
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PLEASE HURRY, I'M BEING TIMED!
The distance from New York to Tokyo is approximately 104 km. When it is 6:00 p.m. in New York, it is 7:00 a.m. of the next day of the week in Tokyo.
Use that information to do an order-of-magnitude estimate of the speed at which the earth's surface moves because of the earth's rotation
-10^10 km/h
-10^8 km/h
-10^5 km/h
-10^3 km/h
Answers
Answer:
The answer is -10^3 km/h
Explanation:
I got it right just took the test.
Option D is correct. The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr
Speed is a body is defined as the ratio of the distance with respect to the time taken by the body. Mathematically:
Speed = Distance/Time
GIven the following
Distance = 104km/hr
If it is 6:00 p.m. in New York, it is 7:00 a.m. of the next day of the week in Tokyo, this means that the time difference between New York and Tokyo is 11 hours.
Time = -11 hours
Get the required speed
Speed = 104/-11
Speed = -9.454545
Speed = -10km/hr
The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr
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Could someone make sure My answers are correct... Thank you
What is the difference between covalent and ionic bonds?
Answer: Covalent bonds share electrons; ionic bonds transfer electrons
What is the charge on the metal ion in iron bromide: FeBr3?
Answer: +3
What would be the proper chemical formula for combining these two ions:
Al+3 and Cl-1
Answer: AlCl3
Name the following compound: NaF. Hint: Is this an ionic or covalent compound?Answer: sodium fluoride
What is the charge on the nonmetal in the ionic compound calcium phosphide?
Answer: -3
Given the Lewis dot structures of oxygen and magnesium, predict the ionic formula. *Mg* *O*
Answer: MgO
Hint: When you have a lewis dot structure, you can move the electrons from the metal to the nonmetal until there are zero or 8 dots around each. If necessary, you add more atoms until all atoms have this octet. Then you add up how many of each element you have and those are the subscripts!
Select all correct statements relating to the octet rule.
Answers:
atoms require 8 valence electrons in order to be stable.
atoms will share or transfer electrons in order to be stable.
When Beryllium and Fluorine join together,
Answer: a Beryllium atom donates two electrons, one to each Fluorine atom.
Hint: Beryllium is in group 2 so it has 2 valence electrons. Since Fluorine can only take one, there must be 2 fluorine atoms that bond with each beryllium atom.
Determine if each property relates to ionic or covalent bonds, both of them, or if the statement is completely false (nether).
Low melting point
give and take electrons
atoms come together to form compounds
salts
molecules
do not conduct electricity
electrolytes
cations and anions
high boiling point
want to reach octet to be stable
only exist as liquid and gases
share or transfer protons
strongly bonded crystalline structure
Contain a metal and a nonmetal
Contain all nonmetals
Answers:
covalent, ionic, both ionic and covalent, ionic, covalent, covalent, ionic, ionic,ionic, both ionic and covalent, neither ionic nor covalent, neither ionic and covalent, ionic, covalent
Check all of the prefixes that are correctly matched with the number they represent.
mono- 1
penta- 5
octa- 8
tri- 3
Match the element or the group to its number of valence electrons.
Group 2
Phosphorous
Sodium and Potassium
the Nobel Gases
Bromine and Chlorine
Carbon
Group 13
Oxygen and Sulfur
answers: 2,5,1,8,7,4,3,6
What is the charge on the metal ion in Silver Oxide, Ag2O?
Answer: +1
Hint: Oxygens subscript is a 1, so that's the charge on silver.
An ionic compound has a generic formula of QR2.
Which elements could the Q and R represent?
Once you choose an answer, check it by plugging those elements into the QR2 formula to see if it looks right.
Answer: Q= Magnesium R= Chlorine
Hint: To write an ionic formula, the charges are crossed down to form subscripts. So, take the subscripts and cross them up to see the charges!
Then consult the periodic table to find out which elements have those charges.
The first element in an ionic formula is always a metal so this will be in group 1, 2, or 13.
The second element in an ionic formula is always a nonmetal and will be found in group 15, 16, or 17.
Name this compound: PCl3
Is it ionic or covalent?
Answer: Phosphorous Trichloride; covalent
What is the formula for dinitrogen pentaoxide?
Answer: N2O5
Determine whether the compound is ionic or covalent.
BaF
AlN
NO
water
calcium iodide
sugar
answers: ionic, ionic,covalent, covalent, ionic, covalent
Answers
Answer:
I believe that number 1 is correct I am not sure about the others
Sorry for not being more helpful
Explanation:
Answer:
All your answers are correct
Explanation:
I took the test and got a 100
Type the name or address of your current location in the address field and select the location provided. Write the exact latitude and longitude coordinates (degrees, minutes, and seconds) that are provided in the answer space. How do these coordinates compare to your estimate from part C?
The coordinates should be written in the following format:
Lat: N 33°34’ 40”
Lon: W 99°29’ 31”
Answers
My location coordinates are Lat: N 38.89'76", Lon: W: -77.03'66"
What are geographic coordinates?Geographic coordinates are a term to refer to the terrestrial reference system that allows a location to be specified by means of a series of numbers, letters or symbols.
The basic and best known geographic coordinate system worldwide specifies the following data:
North or South latitude, degrees, minutes and seconds.East and west longitude, degrees, minutes and seconds.To establish the geographical location of a point, the imaginary Greenwich meridian reference lines (longitude) and the equator line (latitude) must be taken into account.
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The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.27 m apart. One of the spheres had a mass of 188 kg, while the mass of the other sphere was 0.93 kg.
What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
Answers
The gravitational force between the spheres is
\(F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N\)
where G = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
\(F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N\)
where g = 9.80 m/s².
The ratio between the two forces is then
\(\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}\)
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
Closer to a perfect circle then a straight line
Almost rectangular
A very elongated ellipse
Almost parabolic
Answers
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
a very elongated ellipse.What is eccentricity?Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.
The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).
An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.
Therefore, the correct answer is - A very elongated ellipse.
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2. Calculate the force applied if 200 Pascal pressure is en the area of 0.2m”.
Answers
\(\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\)
\(\\ \sf\longmapsto Force=Pressure(Area)\)
\(\\ \sf\longmapsto Force=200(0.2)\)
\(\\ \sf\longmapsto Force=40N\)
Which type of electromagnetic radiation is commonly used to cook meals!
O A. Ultraviolet radiation
O B. Radio waves
O C. Gamma rays
O D. Microwaves
Answers
Trust me I know I am right
wich of the following are commonly distributed by veterinary assistants in typical veterinary practice?
Answers
(b) Which has more mass: 50 cm of gold or 50 cm of aluminum? Explain.
Answers
HEre now can somebody help!!
Pic is what i need help with
Answers
Answer:
which of the cars are speeding up: c
which of the cars or slowing down: a
which of the cars are maintaning a constant speed: b
Explanation:
Answer:
Explanation:
I gave a good enough explanation in your other posting. I'm sorry that I'm eating up your points.
The orange line is speeding up
The blue line is neither speeding up nor slowing down. It's speed is constant.
The green line is starting from 4 m/s and is slowing down to 0.
The diagram helps a lot. Thank you for that.
Children and parents spend less time together in middle childhood than in the preschool years.
a. True
Ob. False
E
C
A
Apr 30
Answers
Children and parents spend less time together in middle childhood than in the preschool years. Yes this true. Hence option A is correct.
Children are people who are between the ages of birth and puberty, or between the early years of development and puberty. It may also be a reference to a human embryo. The term "child" as used in law often refers to a minor, also known as a person under the age of majority. In general, children are subject to fewer rights and obligations than adults. They are considered incapable of making important judgements.
In their own species, a parent is someone who cares for their children. In humans, a parent is a child's primary carer. A individual whose gamete produced a child—a male through the sperm and a female through the ovum—is said to be the biological parent. First-degree relatives and sharing 50% genetic material are the biological parents.
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If a force of 50 N is applied to an object for 0.2s , and it
changes its velocity by 10m/s , what could be the mass
of the object?
Answers
Answer:
Using Newton’s 2nd law
Ft=m(v-u)
m=50*0.2/10
m=10/10
m=1kg
Explanation:
By using Newton's second law, the mass of the object is 1kg
FORCE
The force on an object is a push or pull effect.
Given that a force of 50 N is applied to an object for 0.2s , and it
changes its velocity by 10m/s. The parameters are;
Force F = 50 NTime t = 0.2 sChange in Velocity = 10 m/sMass m = ?From first linear equation of motion,
V = U + at
V - U = at
Where V - U = change in velocity = 10 m/s
Substitute it and time t into the equation.
10 = 0.2a
a = 10/0.2
a = 50 m/\(s^{2}\)
From second Newton's law, F = ma
Substitute the force and the acceleration into the formula
50 = 50m
m = 50/50
m = 1 kg
Therefore, the mass of the object is 1kg.
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Anyone please help me with this question ASAP
Answers
Answer:
increases
Explanation:
it would have to work harder to get to two points together
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
Answers
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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What is evidence used by Galileo to disprove Aristotle and Ptolemy?
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Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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An apartment has the dimensions 18m by 9m by 6m. The temperature is 25 degree C, and the relative humidity is 54 percent. What is the total mass (in kg) of water vapor in the air in the apartment?
Answers
Answer:
Total mass: m = 12 kg
Explanation:
Given:
a = 18 m
b = 9 m
c = 6 m
t = 25°C
φ = 54%
__________
m - ?
The volume of the apartment:
V = a·b·c = 18·9·6 = 972 m³
From the table of saturated water vapor we obtain the density:
ρ₀ = 23.0 g/m³
Air humidity formula:
φ = ρ·100% / ρ₀
Water vapor density:
ρ = φ·ρ₀ / 100% = 54% · 23.0 / 100% ≈ 12.42 g/m³
Total mass:
m = ρ·V = 12.42·972 ≈ 12 070 g or m ≈ 12 kg
Answer:
381.33 kg
Explanation:
relative humidity is 54%, it means that when saturation vapor pressure is 100 pascals, partial vapor pressure is 54 pascals [taking Pascals as no unit is mentioned]
Now, using PV = nRT
⇒ \(PV = \frac{w}{M}RT\)
⇒ \(w = \frac{PVM}{RT}\)
here input P = 54 Pascals, V = (18*9*6)X10^3 L, T = (25+273)°K
R = 8.314 Jmol^-1K^-1, M = mass of water in kg = 18X10^-3 kg