need help again thank you
<3

Solution:

Consider the following inequality:

this is equivalent to:

this is equivalent to:

solving for 3x, this is equivalent to:

this is equivalent to:

solving for x, we get:

in interval notation, this is equivalent to:

the solution set on the real line is:

More than once a week: 0.11

Once a week: 0.51

Every other week: 0.26

Every three weeks: 0.05

Less often than every three weeks: 0.07

To make a relative frequency distribution, follow these steps:

Count the number of occurrences of each category in the data. In this case, 11% of the 251 participants responded "more than once a week", so the number of occurrences for this category is 0.11 * 251 = 27.61 (rounded to 28). Similarly, 51% of the participants responded "once a week", so the number of occurrences for this category is 0.51 * 251 = 127.51 (rounded to 128). And so on for the other categories.

Divide the number of occurrences for each category by the total number of participants. In this case, the total number of participants is 251, so the relative frequency for "more than once a week" is 28 / 251 = 0.11. The relative frequency for "once a week" is 128 / 251 = 0.51. And so on for the other categories.

And that's it! These are the relative frequencies for each category in the data.

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Approximately 34.658 Hispanic females out of 26,000 to have this particular disease.

A woman or girl who identifies as Hispanic or Latino, which usually refers to persons of Spanish-speaking origin or lineage from Latin America or Spain, is referred to as a "Hispanic female."

The proportion of Hispanic females with the disease is 1 in 750, which can be expressed as:

1 / 750 = 0.001333

This means that for every 750 Hispanic females, one is expected to have the disease.

To calculate the expected number of Hispanic females with the disease in a group of 26,000, we can multiply the proportion by the total number of Hispanic females:

0.001333 * 26,000 = 34.658

So we would expect approximately 34.658 Hispanic females out of 26,000 to have this particular disease.

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1. Jada's data set has a mean of 5, Diego's data set has a mean of 6, and Lin's data set has a mean of 4.

2. The data set that has the greatest variability is Lin's data set because it has the highest standard deviation of 3.6.

In Mathematics and Geometry, the mean for this set of data can be calculated by using the following formula:

Mean = [F(x)]/n

Question 1.

In this scenario and exercise, we would determine the mean of the three data sets based on the number of text messages sent by Jada, and Diego, and Lin over 6 days as follows;

Mean number of text for Jada = (4 + 4 + 4 + 6 + 6 + 6)/6

Mean number of text for Jada = 30/6

Mean number of text for Jada = 5.

Mean number of text for Diego = (4 + 5 + 5 + 6 + 8 + 8)/6

Mean number of text for Diego = 36/6

Mean number of text for Diego = 6.

Mean number of text for Lin = (1 + 1 + 2 + 2 + 9 + 9)/6

Mean number of text for Lin = 24/6

Mean number of text for Lin = 4.

Question 2.

In Statistics, variability is a measure of the spread of a data set. Also, we would use standard deviation to determine the variability in each data set as follows;

Standard deviation = √(1/n × ∑(xi - u₁)²)

Standard deviation for Jada = √(1/6 × [(4 - 5)² + (4 - 5)² + (4 - 5)² + (6 - 5)² + (6 - 5)² + (6 - 5)²]

Standard deviation for Jada = √(6/6) = 1

Standard deviation for Diego = √(1/6 × [(4 - 6)² + (5 - 6)² + (5 - 6)² + (6 - 6)² + (8 - 6)² + (8 - 6)²]

Standard deviation for Diego = √(14/6) = 1.53

Standard deviation for Lin = √(1/6 × [(1 - 4)² + (1 - 4)² + (2 - 4)² + (2 - 4)² + (9 - 4)² + (9 - 4)²]

Standard deviation for Lin = √(76/6) = 3.6

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The following percentages are listed below:

In this question we have seven cases of real life situations in which percentages are used. Mathematically speaking, percentages are represented by the following expression:

x = r / r' × 100       (1)

Where:

Now we proceed to determine quantities related to percentages:

2.8 mm as a per cent of 2.24 cm

x = (2.8 mm / 22.4 mm) × 100 %

x = 12.5 %

What per cent of 1.5 m is 60 cm?

x = (60 cm / 150 cm) × 100 %

x = 40 %

What per cent of 2 kg is 125 g?

x = (125 g / 2000 g) × 100

x = 6.25 %

What per cent of R 6 to 40 p?

x = (40 / 600) × 100

x = 6.667 %

What per cent of a day is 10 h?

x = (10 h / 24 h) × 100

x = 41.667 %

What per cent of 7 1 / 3 m in 5 1 / 2 m ?

x = [(11 / 2) / (22 / 3)] × 100 %

x = 75 %

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The five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

Measures of statistical dispersion, or the spread of the data, include the interquartile range. In addition to the IQR, other names for it include the midspread, middle 50%, fourth spread, and H-spread.

To find the five-number summary and interquartile range for this data set, we first need to find the quartiles.

Step 1: Find the median (Q2)

When a data collection is sorted from least to largest, the median is the midway value. Since there are 12 values in this data set, the median is the average of the sixth and seventh values:

Median (Q2) = (41 + 46)/2 = 43.5

Step 2: Find the lower quartile (Q1)

The lower quartile is the median of the lower half of the data set. Since there are 6 values below the median, we take the median of those values:

Q1 = (32 + 32)/2 = 32

Step 3: Find the upper quartile (Q3)

The upper quartile is the median of the upper half of the data set. Since there are 6 values above the median, we take the median of those values:

Q3 = (50 + 51)/2 = 50.5

Now we have all the information we need to construct the five-number summary and interquartile range:

Minimum: 29

Lower quartile (Q1): 32

Median (Q2): 43.5

Upper quartile (Q3): 50.5

Maximum: 53

Interquartile range (IQR) = Q3 - Q1 = 50.5 - 32 = 18.5

the five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

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The requried ball reached a maximum height of approximately 62 feet

Let the ball is thrown vertically upward, we can use the following formula to find the maximum height it reaches:

\(h(t) = -16t^2 + vt + h_0\)

here, h(t) is the height of the ball at time t, v is the initial velocity of the ball (in feet per second), and h0 is the initial height of the ball (in feet). We can also use the fact that the ball remains in the air for 3.8 seconds, which means that the time it takes to reach the maximum height is half of that or 1.9 seconds.

At the highest point, the ball's velocity is zero, so we can find the initial velocity by setting v = 0 in the above formula and solving for h₀:

h₀ = h(t) + 16t²

   = 4 + 16(1.9)²

   ≈ 4 + 57.76

   ≈ 61.76

Therefore, the ball reached a maximum height of approximately 62 feet

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Answer:

4

Step-by-step explanation:

(h-3)2

(5-3)2 (substitution)

(2)2 (subtraction)

4 (multiplication)

Given the triangles EFG and HIJ, you can identify that:

By definition, two triangles are similar if the lengths of the corresponding sides are in proportion and their corresponding angles are congruent.

In this case, you can identify that you know two pairs of corresponding sides. Then, you can find in they are in proportion. Set up that:

Substituting values and simplifying, you get:

Notice that they are in proportion.

You can also identify that the corresponding angles F and I are congruent because they have equal measure.

Therefore, since you know that two sides are proportionate and the included angles are congruent, you can conclude that the triangles are similar, based on the Side-Angel-Side Theorem (SAS).

Hence, the answer is: Third option.

Answer: 6,001 milliliters

Step-by-step explanation: 6 Liter translates to 6,000 milliliters, which is 1 less than 6,001 milliliters.

Answer:

I believe 6 liters is more.

Step-by-step explanation:

PLEASE TYPE FULL QUESSTION

Answer:

Step-by-step explanation:

Cf +1/2=EA

As per the given perimeter of the rectangular area, the maximum area without fencing is 788544 square feet.

Perimeter of rectangle

Perimeter of the rectangle is defined as the total length or distance around the boundary of a rectangle.

And the formula that is used to measure the perimeter of the rectangle is

P = L x B

Where

L refers the length

B refers the breadth

Given,

A farmer has 1776 feet of fencing available to enclose a rectangular area bordering a river.

Here we need to find if  no fencing is required along the river, then what will be the dimensions of the fenced area that will maximize the area.

Let us consider L and W be the length and width of the rectangular respectively.

And also, let the river run along L.

So, the perimeter to be covered by fence is written as,

=> P = L + 2W.

Therefore, when we apply the value of perimeter in it, then we get,

=> 1776 =L + 2W

Here we need the value of L, so, the equation is rewritten as,

=> L = 1776 - 2W

Now, we have to apply these value on the area formula, then we get,

A = (1776-2W) x W

When we simplify it, then we get,

=> A = 2700W-2W²

This is in the form of quadratic equation.

So, let us assume that the vertex of the rectangular at maximum area will give maximum width.

Then it can be obtained as, (W,A),

where the value of

W = -b/2a

Here the value of b = 1776 and a = -2

By applying these values on the formula, then we get the value of W as,

=> W = -1776/2*(-2)

=> W = -1776/-4

=> W = 444ft.

Therefore, the length is

=> L = 1776 - 2(444)

=> L = 1776 - 888

=> L = 888

Maximum area, A=888*888 = 788544 square feet.

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True statement for Protecting classified data is classified material must be appropriately marked.

Classified information being transmitted from one commission office to another shall be protected with a classified document cover sheet and hand delivered by an appropriately cleared person to another appropriately cleared person.

Classified information is material that a government body deems to be sensitive information that must be protected. Access is restricted by law or regulation to particular groups of people with the necessary security clearance and need to know, and mishandling of the material can incur criminal penalties.

Data classification is broadly defined as the process of organizing data by relevant categories so that it may be used and protected more efficiently. Data classification involves tagging data to make it easily searchable and trackable.  

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Using the parallelogram law to find m, the value of m is 50°.

The parallelogram law states that the sum of the squares for a parallelogram's four sides is equal to the sum of the squares for its two diagonals.

The parallelogram must have equal opposed sides in Euclidean geometry.

If ABCD is a parallelogram, then AB = DC and AD = BC, the parallelogram law is stated as:

2(AB)² + 2 (BC)² = (AC)² + (BD)²

If the parallelogram is a rectangle, the parallelogram law is stated as:

2(AB)² + 2 (BC)² = 2(AC)²

The value of the unknown angles in the parallelogram are as follows:

CED = 180 - (60 + 33 + 37)

CED = 50°

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Answer:

y=2/4x+4.5

Step-by-step explanation:

Use rise over run to get 2/4 and the line splits 4 and 5 to get 4.5

Hope this Helps :)

Answer:

Step-by-step explanation:

Unsure

AE= 17.4 to nearest tenth

Step-by-step explanation:

Opposite + hypotenuse = SOH / sin

Sin 31 = 6/h

xh, then ÷ sin31

H= 6/sin31

H= 11.649....(a or b & 6 being a or b)

a^2 + b^2 = c^2

c = 13.1

Actually it's not a right-angle triangle

180 - 13+31 (or 44) = 136 degrees

Cosine rule: a^2=b^2+c^2 - 2bc cosA

AE = root 11.649...^2 + 7^2 - 2x11.649...x7xcos136

= 17.3791......

AE= 17.4 to nearest tenth

Hope this helps!

The speed of the faster cyclist is 30 mph.

Two cyclists, distance = 90 miles.

let the speed of one cyclist is = x and

let the speed of the other cyclist = 2x

time after which both the cyclists will meet = 3 hours.

Since they are travelling towards each other the effective speed = 2x ₊ x

= 3x

we know that time = distance/speed

3 = 90/3x

3x = 30

x = 10 mph speed of one cyclist.

speed of the other cyclist will be 3x = 3 × 10 = 30 mph

The speed of the fastest cyclist is 30 mph.

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The slope of the line is 7/9

It is important to note that the equation of a line is represented as;

y = mx + c

Where;

The formula for calculating the slope of a line is expressed as;

Slope, m = y₂ - y₁/x₂ - x₁

Now, let's substitute the values into the formula from the points given we have;

Slope, m =1 -(-6)/ -3 - (-6)

expand the bracket

Slope, m = 1 + 6/ 3 + 6

add the values

Slope, m = 7/9

Hence, the value is 7/9

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The equation which correctly represents the given situation as required to be determined is; Choice C; w = 5 × 15.

It follows from the task content that the equation which correctly represents the Given situation is to be determined.

Since the intention is to buy 5 tickets in which case; each ticket costs 15 dollars; we have that;

Since the total amount of dollars they have is w dollars; The equation which holds true for the situation is; w = 5 × 15.

Consequently, answer choice C; w = 5 × 15 is correct.

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Answer:

C. yes, 20 = 20

Step-by-step explanation:

the equation is y=4x and from the coordinates (5,20) we can see that x =5 and y = 20

substituting in the original equation we must check if

20 = 4(5)

20 = 20

left = right

yes it is a solution

The slope of the tangent line is:

a = (df(x1)/dx)

The slope of the normal one is:

a' = -1/(df(x1)/dx)

For any function y = f(x), we define the slope of the tangent line at the point x as the derivative evaluated in x.

So if we want to find the slope of the tangent line at the point (x1, y1), we just need to differentiate and evaluate in x1, then the slope will be given by:

df(x1)/dx

And the normal slope is the slope of the perpendicular line, two slopes are perpendicular if the product is -1, then:

a*(df(x1)/dx) = -1

a = -1/(df(x1)/dx)

Where df/dx reffers to the derivative of f(x).

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

\((\stackrel{x_1}{65}~,~\stackrel{y_1}{149})\qquad (\stackrel{x_2}{105}~,~\stackrel{y_2}{221}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{221}-\stackrel{y1}{149}}}{\underset{\textit{\large run}} {\underset{x_2}{105}-\underset{x_1}{65}}} \implies \cfrac{ 72 }{ 40 } \implies \cfrac{ 9 }{ 5 }\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{149}=\stackrel{m}{ \cfrac{ 9 }{ 5 }}(x-\stackrel{x_1}{65})\implies y-149=\cfrac{ 9 }{ 5 }x-117 \\\\\\ y=\cfrac{ 9 }{ 5 }x-117+149\implies \boxed{y=\cfrac{ 9 }{ 5 }x+32} \\\\\\ \stackrel{\textit{Celsius is 70, so x = 70}}{y=\cfrac{ 9 }{ 5 }(70)+32}\implies \boxed{y = 158}\)

Answer:

0,4

Step-by-step explanation:

Subtract the points

Given:

A local school installed a new flagpole that has two lights on both sides of the flagpole that are 40 feet from each other.

As shown in the figure the flagpole is in the middle between the lights

And the distance between the lights = 40

So, the distance (x) which represents the distance between the flagpole and the light = half of the distance between the lights

So,

So, the answer will be the value of x = 20 feet

Answer:

47*

Step-by-step explanation:

Each corner of the square is 90*

angle CBE + angle ABE = 90*

fill in the blanks

43 + x = 90

subtract 43 from both sides

x = 47*

Answer:

f(x)

=(x-4)[6(x^2)+23x+20]

=(x-4)(2x+5)(3x+4)

x=4,-2/5,-3/4