Match the property of a sound wave to the correct definition.

Match The Property Of A Sound Wave To The Correct Definition.

Answers

Answer 1

Answer:

amplitude: how dense the medium is in the compression part of the wave, and how empty the rarefied area is

frequency: the number od wavelengths that pass a position in 1 second

pitch: the quality of the sound that is most likely linked to the frequency of the sound wave

period: the amount of time it takes one wave length to pass by a position

loudness: the quality of the sound most closely linked to the amplitude of the sound waves

Answer 2

The correct match for the column 1 with the column 2 is A-1,B-2,C-4,D-3,E-5. All definitions are related to sound wave.

What is wave?

A wave is a phenomenon that flows across a material medium without leaving any lasting mark.

A disturbance that travels through a medium with a transfer of matter and without a transfer of energy best describes a wave.

A. Amplitude - 1.how dense the medium is in the compression part of the wave, and how empty the rarefied area is

B. Frequency: 2. The number of wavelengths that pass a position in 1 second.

C. Pitch: 4. The quality of the sound, that, is most likely linked to the frequency of the sound wave.

D. Period -3. The amount of time it takes one wave length to pass by a position.

E.loudness-5. The quality of the sound, most closely linked to the amplitude of the sound waves.

Hence,the correct match for the column 1 with the column 2 is A-1,B-2,C-4,D-3,E-5.

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Related Questions

12.17 A baseball has a circumference of 914 in. and a weight of 514 ounces. At 95 mph determine a. the Reynolds number P b. the drag force C. the type of flow (see the illustration for Problem 12.7)

Answers

The Reynolds number of the baseball is 2.15 × 10⁹, the drag force acting on the baseball is 2.18 N and the type of flow around the baseball is turbulent.

Given, The circumference of a baseball, C = 914 in

The weight of the baseball, w = 514 oz

The velocity of the baseball, V = 95 mph The Reynolds number, R can be calculated using the formula, R = \(\frac{\rho VD}{\mu}\)

Where ρ is the density of air, D is the diameter of the baseball, and μ is the dynamic viscosity of air.

At standard conditions of temperature and pressure, the density and dynamic viscosity of air are ρ = 1.2 kg/m3 and μ = 1.8 × 10⁻⁵ kg/m s, respectively.

The diameter of the baseball can be found using the relation, C = πD ⇒ D = \(\frac{C}{\pi}\)

Putting in the values, D = \(\frac{914}{\pi}\) = 291.2 in.

Now, converting D to meters, D = 291.2/39.37 = 7.39 m.

Now, substituting the given values in the Reynolds number equation, R = \(\frac{1.2 × 7.39 × 95 × 0.3048}{1.8 × 10^{-5}}\)= 2.15 × 10⁹

The type of flow can be determined from the Reynolds number. For R > 2 × 10⁵⁰⁰⁰, the flow is considered turbulent, while for R < 2 × 10⁵, the flow is considered laminar.

In this case, R > 2 × 10⁵, hence the flow around the baseball is turbulent.

The drag force, F can be found using the formula,F = \(\frac{1}{2}ρVC_{d}A\)

Where Cd is the drag coefficient and A is the cross-sectional area of the baseball.

The cross-sectional area of the baseball is given by, A = \(\frac{\pi D^2}{4}\)

Substituting the values, A = \(\frac{\pi (291.2)^2}{4 × 39.37^2}\) = 0.408 m²

Now, the drag coefficient can be estimated using the Reynolds number, for which the drag coefficient chart is given. From the chart, Cd ≈ 0.35.

Substituting the given values, F = \(\frac{1}{2}ρVC_{d}A\)= \(\frac{1}{2} × 1.2 × 95 × 0.3048 × 0.35 × 0.408\)= 2.18 N

Hence, the drag force acting on the baseball at 95 mph is 2.18 N.

Therefore, the Reynolds number of the baseball is 2.15 × 10⁹, the drag force acting on the baseball is 2.18 N and the type of flow around the baseball is turbulent.

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12. Which of the following is accurate when discussing specific heat?
O A. Specific heat values for solids will never vary for different ranges of temperature.
B. Specific heat values for liquids will never vary for different ranges of temperature.
C. The specific heat of a gas can be measured at constant volume only.
D. The specific heat of a gas can be measured at constant pressure.

Answers

D. The specific heat of a gas can be measured at constant pressure.

How to determine the accurate statement about specific heat

By definition, the specific heat capacity of a substance is the heat capacity of a sample of the substance divided by its mass, also known as massic heat capacity.

Water has a high specific heat, which means that it takes more energy to raise the temperature of water than other substances.

For gaseous substances, their specific heats can be measured at constant pressure.

Using the above as a guide, we have the following:

The accurate statement about specific heat is (d)

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A Ford Shleby GT 500 has a horsepower of 760 hp. What is that is Watts? DO NOT include units - just the numeric answer. I QUESTION 15 An object of mass 100 kg is moved with an acceleration of 10 m/2, and goes fron an initial position of 10 m to a final position of 30 m. What work was done on the object? DO NOT include units - just the numeric answer.

Answers

the work done on the object is 20000 J.

The conversion factor from horsepower to watts is 1 hp = 746 watts.

Therefore, the Ford Shelby GT 500's horsepower of 760 hp can be converted to watts as follows:

760 hp × 746 watts/hp = 567760 watts

To convert horsepower to watts, you simply need to multiply the number of horsepower by the conversion factor of 746 watts/hp.So, the numeric answer for 760 hp in watts is 567760.

According to the work-energy principle, the work done on an object is equal to the change in kinetic energy. Mathematically, the work-energy principle can be represented as follows:

W = ΔKHere, W represents the work done on the object, and ΔK represents the change in kinetic energy of the object.

The change in kinetic energy can be calculated using the following formula:

ΔK = (1/2)mvf² - (1/2)mvi²

Here, m represents the mass of the object, vi represents the initial velocity of the object, and vf represents the final velocity of the object. In this case, the object is initially at rest (vi = 0), so the formula can be simplified to

:ΔK = (1/2)mvf²

Now, we can use the following kinematic equation to calculate the final velocity of the object:

vf² = vi² + 2ax

Here, a represents the acceleration of the object, x represents the displacement of the object, and vi represents the initial velocity of the object. Plugging in the given values, we get:

vf² = 0 + 2(10 m/s²)(30 m - 10 m)vf² = 400 m²/s²vf = 20 m/s

Now, we can plug in the values of m and vf to calculate the change in kinetic energy:

ΔK = (1/2)(100 kg)(20 m/s)²ΔK = 20000 JSo, the numeric answer for the work done on the object is 20000 J.

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Mrs. Botts applies brakes on a car help it to decelerate at the rate of -0.80m/s2. What distance is required to stop the car when it is moving 17 m/s.

Answers

Answer:

Explanation:

vf=0

vi = 17

a = -0.8

Δx = ?

vf^2 = vi^2 + 2 a Δx

Δx = (vf^2 - vi^2) / 2a

Δx = (0-17^2) / 2 (-0.8)

Δx = 180.625 m

A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the skater slide before he stops?

Answers

Answer:

d = 120 [m]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.

The mechanical energy is equal to the sum of the potential energy plus the kinetic energy.  As the track is horizontal there is no unevenness, in this way, there is no potential energy.

E₁ + W₁₋₂ = E₂

where:

E₁  = mechanical energy in the initial state [J] (units of Joules)

W₁₋₂ = work done between the states 1 and 2 [J]

E₂  = mechanical energy in the final state = 0

E₁ = Ek = kinetic energy [J]

E₁ = 0.5*m*v²

where:

m = mass = 60 [kg]

v = initial velocity = 12 [m/s]

Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.

W₁₋₂ = -f*d

where:

f = friction force = 36 [N]

d = distance [m]

Now we have:

0.5*m*v² - (f*d) = 0

0.5*60*(12)² - (36*d) = 0

4320 = 36*d

d = 120 [m]

How far away from the surface of earth does the acceleration due to gravity will be inclined by 36% of its value on the surface of earth? Radius of earth is 6400 km

Answers

Answer:

1,600 km

Explanation:

since the acceleration due to gravity reduces by 36%, it means that (1 - 36%) of acceleration still remains:

g' = 64g/100

using the acceleration formula:

g' = g x [R² / (R + height)²]

64g/100 = g x [R² / (R + height)²]

64/100 = R² / (R + height)²

√(64/100) = √[R² / (R + height)²]

8/10 = R / (R + height)

8 (R + height) = 10R

8R + 8height = 10R

8height = 2R

height = 2R / 8 = R / 4

R = 6,400 km

height = 6,400 km / 4 = 1,600 km

Answer:

The acceleration due to gravity will be inclined 1600 KM by 36% of its value on the surface of earth

Being interested in penguins, Paul wanted to study the effect of fast food hamburgers on the weight of penguins. After many trials of trying to get the penguins to eat the burgers, Paul became frustrated at the fact that the penguins were losing weight and not eating any of the burgers. Why was Paul's experiment not a complete waste of time and resources?

A) Paul got to spend time with the penguins. Eliminate
B) There was nothing valuable gained from this.
C) The penguins were overweight and needed to lose weight.
D) Paul found that fast food burgers cause penguins to lose weight.

Answers

Answer:

Paul found that fast food burgers cause penguins to lose weight.

Explanation:

Why is it important to try to use as many renewable resources as possible?

Answers

Answer:

It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.

The shortest path between two points is:

1) displacement

2) breadth

Answers

Answer:

the shortest path between two points is displacement..

Explanation:

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The shorts path between two points is displacement.

which will have longer shadow: ben whose height is 5 feet tall and 2 inches or his brother mike who is 6 feet and 2 inches when they both stand under the sun around 10am? i need help asap and anyone get my answer now i will give branliest

Answers

Answer: I believe his brother, Mike, who is 6'2, will have the longer shadow.

Which statement best describes what happens during a solar eclipse?

A. The Sun casts a shadow directly on Earth and the Moon.

B. Earth passes directly between the Sun and the Moon.

C. The Moon passes directly between Earth and the Sun.

D. Earth casts a shadow directly on the Sun and the Moon.​

Answers

Answer: A.

Explanation:

Solar eclipse happens when Sun casts a shadow directly on Earth and the Moon. Option A is correct.

What is solar eclipse?

A solar eclipse occurs when the Sun throws a shadow directly on Earth and the Moon.

When the Sun throws a shadow directly on the Earth and the Moon, it is called a solar eclipse.

Hence,option A is correct.

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T/F Adams and Leverrier predicted the position of Neptune, based on its perturbations of uranus

Answers

The following statement “Adams and Leverrier predicted the position of Neptune, based on its perturbation analysis of uranus.” is True.

Adams and Leverrier independently predicted the position of Neptune based on their observations of the perturbations in the orbit of Uranus. In the mid-19th century, astronomers noticed that Uranus was not moving exactly as predicted by Newtonian mechanics, suggesting the presence of an unknown celestial body influencing its orbit.

Using mathematical calculations and perturbation analysis, John Couch Adams (an English mathematician) and Urbain Le Verrier (a French mathematician) separately predicted the existence and approximate position of Neptune. Their predictions led to the actual discovery of Neptune in 1846.

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Which of these things do you NOT want to have in your experiment? *
-A dependent variable
-An independent variable
-A constant
-A confound

Answers

You don't want a confound

- A cylinder of volume 5.0 x 103 cm3 contains air at a pressure of 8.0 x 105 Pa.
A leak develops so that air gradually escapes from the cylinder until the air in the cylinder
is at atmospheric pressure. The pressure of the atmosphere is 1.0 x 105 Pa.
Calculate the volume of the escaped air, now at atmospheric pressure. Assume that the
temperature stays constant.

Answers

Answer:

10

Explanation:

if you put 10 your right

someone please help with these 2 questions, please add a reason on why that is your answer!!

someone please help with these 2 questions, please add a reason on why that is your answer!!

Answers

Explanation:

for the car question

the answer is

that the box on the roof will slip forward when the car hits the wooden box

because the box on the car roof is in motion

when the car hit the wooden block

the wooden block will try to stop the car

due to which the speed of the car will be decelerated but the box will try to continue its motion so it will move forward due to inertia of the box

and the answer for the 2nd question is that

the sand bucket will provide more resistance to the change in motion because along with the bucket the sand will also try to not change their state of rest so due to their inertia the sand bucket will provide more resistance than the simple bucket


Which image illustrates the bouncing of a light wave off of a surface?
A
B
с
D
A. A
B. B
C. C

Which image illustrates the bouncing of a light wave off of a surface?ABDA. AB. BC. C

Answers

Answer:

The answer is A good luck :P

Answer:

A

Explanation:

The light Bounces off because it is reflecting off glass or anything else

Step 1: Write down the equation needed to solve for velocity. Velocity = wavelength x frequency Step 2: Place the known measurements into the equation. Step 3: Solve the equation. Carefully put the numbers into your calculator. Recheck your answers! It is very easy to hit the wrong button on your calculator. Remember to use correct SI units. Huge waves in the ocean, are studied by scientists and researchers. Ships have reported waves with a height of 25 meters high! These waves are said to be about 25 meters long. Assuming that these waves travel at speeds of 6.5 m/s, determine their frequency.

Answers

The frequency of these waves is approximately 25 Hz.

Given the following information:nHuge waves in the ocean, are studied by scientists and researchers. Ships have reported waves with a height of 25 meters high! These waves are said to be about 25 meters long. Assuming that these waves travel at speeds of 6.5 m/s, determine their frequency.

The equation needed to solve for velocity is: Velocity = wavelength x frequency

Step 1: Rearrange the formula and solve for frequency as follows: frequency = velocity / wavelength

Step 2: We are given the velocity of the wave, which is 6.5 m/s. We can also calculate the wavelength using the formula: Velocity = wavelength x frequency

Rearranging the formula to solve for wavelength: wavelength = velocity / frequency ..wavelength = 6.5 m/s / 25 m (since the wavelength is given as 25 meters)wavelength = 0.26 m

Now that we know both the velocity and wavelength, we can substitute them into the formula:f = v / λf = 6.5 m/s / 0.26 mf ≈ 25 Hz . Therefore, the frequency of these waves is approximately 25 Hz.

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Please help I'm so lost.
Erbium-165 has a half-life of 10.4 hours. If you start with 1,000 grams of erbium-165, how much time will it take to have 125 grams of erbium-165 left in the sample?

A. 41.6 hours
B. 31.2 hours
C. 10.4 hours
D. 20.8 hours

Answers

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

What is half life?

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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Acceleration is caused by a force acting on a mass.​

Answers

Answer:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Explanation:

ples give a crown

G 13% part (g) using the numbers from the previous step, give a numeric answer for the time in seconds that elapse when the package, initially at rest, travels a distance of 2. 25 m down the ramp

Answers

The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.

From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:

Δx = (vf² - vi²) / 2a

Substituting the values, we get:

2.25 = (1.38² - 0) / (2 * 0.087)

Solving for time (t), we get:

t = 2.25 * 0.087 / 1.897

t ≈ 0.104 seconds

Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.

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When a bat hits a baseball, what is transferred from the bat to the ball?​

Answers

Answer:

kinetic energy

Explanation:

a wooden box is sitting on a table. the normal force on the box from the table is 75 n. a second identical box is placed on top of the first box. the normal force on the first box by the table will

Answers

The normal force on the first box from the table will stay at 75 N even after a second box is placed on top of it.

The normal force is a contact force that is determined by the weight of the object, as well as the interaction between the two surfaces in contact. The regular force that the table normally applies to the first box will stay unchanged because the weight of the box has not changed.

The normal force, which is equivalent in strength to gravity's force and acts in the opposite direction, is a force that is perpendicular to the surface of contact. The box is prevented from dropping through the table's surface by this reactionary force.

In other words, the normal force is equivalent to the object's weight, which in this instance is 75 N.

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!!! i'll give brainliest to whoever can answer this for me !!!

you have to match the letters in the picture to the list of energy types

!!! i'll give brainliest to whoever can answer this for me !!!you have to match the letters in the picture

Answers

Answer:

you have to match the letters in the picture to the list of energy types

does the system's kinetic energy increase, decrease, or stay the same? or is there not enough information to tell? explain. match the words in the left column to the appropriate blanks in the sentences on the right.

Answers

Answer: A process occurs in which a system's potential energy increases while the environment does work on the system. The kinetic energy of a system decreases while its potential energy and thermal energy are unchanged.

Explanation: When a process occurs, the potential energy of the system increases while the environment does some work on the system. In this case, the kinetic energy of the object decreases while the potential energy and thermal energy of the system remains unchanged. This is because kinetic energy is used in doing work.

Just copy and paste. Hope this helps :D

how much does a change in mass affect the kinetic energy of two balls of comparable diameter?​

Answers

Answer:

Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.

A coal seem is located 170 m underground. If the average density of the overlying rocks is 2600 kg/m3, answer the followings:
Hints:
* The vertical stress is calculated as follows: g*depth*density of the overlying rocks (g is ground acceleration and equal to 9.8).
* For part c Excel can be used to quickly reach the answer.
a) The vertical pressure applied on each square meter of the coal seem (the vertical stress).
b) If we extract the coal by room and pillar method by following pattern: 4.3m by 4.3m pillars and the rooms or entries between pillars are 4.7 meters wide on both dimensions. Then, how much would be the vertical stress on the remining coal.
c) There is another coal seam in the same region, but it is located 300 m underground. If the maximum vertical stress bearing capacity of the coal is 20 MPa, then how the rooms and pillars should be designed for the maximum recovery. In other words, how much would be the dimensions of pillars and the entries between them? (consider a 9 m2 grid as part b).
d) What are the other factors that should be taken into account for designing the pillars and can affect their load bearing capacity?

Answers

The vertical pressure applied on each square meter of the coal seam can be calculated using the formula g * depth * density. If the coal is extracted using a room and pillar method, the vertical stress on the remaining coal can be determined based on the given dimensions.

a) To calculate the vertical pressure on each square meter of the coal seam, we use the formula: vertical stress = g * depth * density. Given that the depth is 170 m and the density of the overlying rocks is \(2600 kg/m^3\), the vertical stress can be calculated as follows: vertical stress = \(9.8 m/s^2\) * \(170 m * 2600 kg/m^3\). By performing the calculation, the answer can be obtained.

b) Extracting the coal using the room and pillar method with 4.3 m by 4.3 m pillars and 4.7-meter-wide rooms or entries between the pillars will result in vertical stress on the remaining coal. The vertical stress can be calculated using the same formula as in part A but with the new dimensions provided. Using Excel can simplify the calculation process and provide the answer quickly.

c) Considering another coal seam located 300 m underground with a maximum vertical stress-bearing capacity of 20 MPa, the dimensions of the pillars and entries should be determined for maximum recovery. To calculate the dimensions, we need to consider a \(9 m^2\) grid, as mentioned in part b. By using the formula from part b, the vertical stress on the remaining coal can be calculated, and the dimensions can be determined accordingly.

d) When designing the pillars, several factors should be taken into account that can affect their load-bearing capacity. Some of these factors include the geological characteristics of the rock and coal formations, the presence of natural fractures or faults, the stability of the surrounding strata, the stress redistribution during mining, and the potential for roof collapse or pillar failure. Proper consideration and analysis of these factors are crucial to ensure the safe and efficient design of pillars in underground mining operations.

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b) The speed, c, of longitudinal waves in a stretched wire is given by the equation

Answers

Speed = Wavelength * Frequency

what causes waves to slow down: change in wave’s wavelength or change in its frequency and y?

Answers

Answer:

Although the wave slows down, its frequency remains the same, due to the fact that its wavelength is shorter. When waves travel from one medium to another the frequency never changes.

Select True or False for the following statements about electric field lines.
(a) Electric field lines do not begin or end in a charge free region except at infinity.
(b) Electric field lines may cross.
(c) Electric field lines make circles around positive charge.
(d) Electric field lines point outwards from positive charge.
(e) Electric field lines point inwards towards negative charge.
(f) Where the electric field lines are dense the electric field must be weak.
(g) A positive point charge released from rest will initially accelerate.

Answers

1) A things along the way charge will initially accelerate down an E-field line when it is released from rest: TRUE.

When the force of the electrostatic potential that generates the field is applied to the electric field lines, they all point in the exact direction that will produce a positive test charge.

2) E-Field lines encircle positive charges in circles: FALSE.

With the exception of infinity, E-Field lines begin with positive charges and end with negative charges.

3) E-field lines are oriented inward and toward electrostatic repulsion: TRUE

Negative charges attract positive charges, therefore the positive test charging will move in the direction of the negative charges as the E-field lines move along trajectory that would include a positive drug test charge.

4) E-Field vector may intersect: FALSE

If they crossed, it would imply that the electric potential may be developing variably at the exact spot, which is not conceivable because the E-Field seems to be the gradient of both the electrostatic attraction (thus they have always had the direction of the highest change of potential).

5) Positive charges have E-Field lines pointing outward: TRUE

According to the previous explanation, the E-field traces follow the path that a positive test charges would take if it were to produce the field. As a result, if a positive charge creates the field, the analysis suggests would move away from it, and the field lines would then point outward.

6) The E-field must really be weak when the E-field margins are dense: FALSE

According to tradition, the density of the E-field lines indicates the strength of the field as the E-field arcs are inversely correlated with the charge that generates the field.

7) Except at infinity, E-field fibers do not start or finish in a zone that is free of charges. TRUE.

E-field lines can begin in a location that is devoid of charges since they start at positively charged ions and end at negative charges, with the exception of infinity.

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A negative charge, q1, of 6 µC is 0. 002 m north of a positive charge, q2, of 3 µC. What is the magnitude and direction of the electrical force, Fe, applied by q1 on q2? magnitude: 8 × 101 N direction: south magnitude: 8 × 101 N direction: north magnitude: 4 × 104 N direction: south magnitude: 4 × 104 N direction: north.

Answers

Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

What is electrical force?

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is

q₁ is the negative charge = 6 µC=6×10⁻⁶ C

q is the positive charge = 3 µC=3×10⁻⁶ C

r is the distance between the charges=0.002 m

\(F_E\) is the electric force =?

The value of electric force will be;

\(\rm F_E= \frac{Kq_1q_2}{r^2} \\\\ F_E= \frac{9\times 10^9\times 6\times 10^{-6}\times3\times10^{-6}}{(0.002)^2}\\\\ \rm F_E=4.05\times10^4\;N\)

Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

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Answer:

DDDD

Explanation:

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