(a) Briefly describe the phenomena of superheating and supercooling.(b) Why do these phenomena occur?

CaCO3 is the slightly soluble ionic compounds contain anions that will influence the pH of the resulting solution.

CaCO3 is slightly soluble in water, and it will dissolve to produce a small amount of calcium ions and carbonate ions. Carbonate ions can act as a weak base and can affect the pH of the solution. The other two compounds, HgF2 and CoS, are insoluble in water and will not dissociate into ions. Therefore, they will not affect the pH of the solution.

A substance that dissolves in water to produce an acidic solution is known as an acidic substance. An ionic compound that dissolves in water to produce a solution with a pH greater than 7 is known as a basic substance. A substance that dissolves in water to produce a solution with a pH of exactly 7 is known as a neutral substance.

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Answer:

The bell and the Eiffel tower

Answer:

64cm^3

Explanation:

To get the volume just multiple 4*4*4

Due to their stronger metallic bonding and more compact atomic structure, the transition elements have higher melting and boiling temperatures and are often denser than the alkali metals.

Elements from Group 1 have similar properties. All of them are supple silver metals. These metals are extremely reactive and have low melting temperatures due to their low ionisation energy. As you descend the chart, this family becomes more reactive.

The d orbitals of transitional elements are only partially filled. A transition element is defined by IUPAC as an element that may form stable cations and has an electron d subshell that is only partly filled.

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Answer:

Li3N

Explanation:

Li+N2=Li3N.........................

Answer:

4 Li(s)+O2(g) → 2 Li2O(s)

Explanation:

its right

The enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

The enthalpy of the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) can be calculated by summing the enthalpies of the individual reactions involved. The given information provides the enthalpy change for the decomposition of CaCO3 (s) and the combustion of C (s) to form CO2 (g). By combining these reactions, the enthalpy change for the overall reaction can be determined.

The given reactions are:

CaCO3 (s) -> CaO (s) + CO2 (g) (H = 178.1 kJ)

C (s, graphite) + O2 (g) -> CO2 (g) (H = -393.5 kJ)

To calculate the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g), we need to subtract the enthalpy change of reaction 2 from the enthalpy change of reaction 1. Since the enthalpy change is an extensive property, we can subtract the enthalpies directly:

ΔH = H(reaction 1) - H(reaction 2)

= 178.1 kJ - (-393.5 kJ)

= 178.1 kJ + 393.5 kJ

= 571.6 kJ

Therefore, the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

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Answer:

3.5 cubic centimeters

Explanation:

To determine the original concentration, we can use the equation C1V1 = C2V2. Using the given values,

(1) we find that the original gold chloride concentration was 0.52 M.

(2) By plugging in the values into the equation 0.87 M x 0.30 L = 0.30 M x V2, we can solve for V2, which results in V2 = 0.87 L.

in (3) As a result,the new concentration is found to be 0.65 M.

1. To find the original concentration, we can use the equation C1V1 = C2V2, where C1 is the original concentration, V1 is the original volume, C2 is the final concentration, and V2 is the final volume. Given that C2 = 0.26M, V2 = 1.0L, and V1 = 0.50L, we can solve for C1.
Using the equation, we have C1 x 0.50L = 0.26M x 1.0L. Solving for C1, we get C1 = (0.26M x 1.0L) / 0.50L = 0.52M. Therefore, the original gold chloride concentration was 0.52M.
2. To find the volume of water needed to achieve a concentration of 0.30M, we can again use the equation C1V1 = C2V2. Given that C1 = 0.87M, C2 = 0.30M, and V1 = 0.30L, we need to find V2.
By applying the given equation 0.87M x 0.30L = 0.30M x V2 and solving for V2, we find that V2 is equal to (0.87M x 0.30L) / 0.30M, resulting in V2 = 0.87L.
3. To find the new concentration after increasing the volume of water in solution we can again use the equation C1V1 = C2V2. Given that C1 = 1.3M, V1 = 0.40L, and V2 = 0.80L, we need to find C2.
Using the equation, we have 1.3M x 0.40L = C2 x 0.80L. Solving for C2, we get C2 = (1.3M x 0.40L) / 0.80L = 0.65M. Therefore, the new concentration is 0.65M.

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Properties of carbon that explain its presence as a basic element of organic compounds - Catenation and Tetravalent.

Carbon is a chemical element with the symbol C and atomic number 6 (it contains 6 protons in its nucleus). As a member of group 14 in the periodic table, it is non-metallic and tetravalent – ​​making four electrons available to form covalent chemical bonds.

The most common isotope of carbon has 6 protons and 6 neutrons and has an atomic mass of 12.0107 AMU. Its basic electronic configuration is 1s22s22p2.

Properties of carbon that explain its presence as a basic element of organic compounds -

Carbon has the ability to form very long chains of strong and stable interconnecting C-C bonds. This property, called catenation allows carbon to form an almost infinite number of compounds.

Carbon has an affinity for bonding with other small atoms, including other carbon atoms, through the formation of stable covalent bonds. Despite the fact that it is present in a huge number of compounds, carbon is weakly reactive compared to other elements under normal conditions.

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Answer:

A physical property is an aspect of matter that can be observed or measured without changing its chemical composition. Examples of physical properties include molecular weight.

A chemical property may only be observed by changing the chemical identity of a substance. In other words, the only way to observe a chemical property is by performing a chemical reaction

Explanation:

Properties of matter

The properties of matter are classified into; (I) Physical and, (ii) Chemical properties.

Physical properties: A physical property is an aspect of matter that can be observed or measured without changing its chemical composition. Examples of physical properties include molecular weight, density, color, melting and boiling point, etc.

Chemical properties: A chemical property may only be observed by changing the chemical identity of a substance. In other words, the only way to observe a chemical property is by performing a chemical reaction. This property measures the potential for undergoing a chemical change. Examples of chemical properties include and oxidation states, acidic or basic properties, flammability, heat of combustion, etc.

Answer:

Noble Gases B

Explanation:

The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore, they rarely react with other elements since they are already stable.

To get 120 gallons of a solution that is 50% acid, the chemist should mix 60 gallons of the 20% acid solution with 60 gallons of the 65% acid solution.

To determine the quantities of the two solutions needed, we can set up an equation based on the acid content and the total volume of the solution. Let's assume x represents the amount (in gallons) of the 20% acid solution and y represents the amount (in gallons) of the 65% acid solution.

Since the total volume of the final solution is 120 gallons, we have the equation:

x + y = 120   --- Equation 1

Next, we need to consider the acid content in the mixture. The acid content in the 20% acid solution is 20% of x, while the acid content in the 65% acid solution is 65% of y. The acid content in the final solution should be 50% of the total volume (120 gallons), so we have another equation:

(20/100) * x + (65/100) * y = (50/100) * 120   --- Equation 2

Simplifying Equation 2, we get:

0.2x + 0.65y = 60   --- Equation 3

Now, we can solve the system of equations formed by Equations 1 and 3 to find the values of x and y.  By solving the equations, we find that x = 60 and y = 60. This means that the chemist should mix 60 gallons of the 20% acid solution with 60 gallons of the 65% acid solution to obtain 120 gallons of a solution that is 50% acid.

Therefore, the chemist should mix 60 gallons of the 20% acid solution with 60 gallons of the 65% acid solution to obtain the desired solution.

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Answer:

The temperature is kept constant. What new volume does the gas occupy? Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa.

Explanation:

Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question we have

\(density = \frac{20}{40} \\ \)

We have the final answer as

Hope this helps you

Answer:

Arcuate: A fan-shaped delta, bowed or curved.

Cuspate: V-shaped delta.

Bird-foot: Outstretched claws delta

Inverted: The narrow end of delta, or river delta.

Waves: Large or regular shaped waves delta.

Tires: Round shaped delta

River estuary: A landform deposited by sediment

Explanation:

Answer:

False

Explanation:

Metamorphic rocks form when rocks are subjected to high heat, high pressure, hot mineral-rich fluids or, more commonly, some combination of these factors.

This question is reffering to sedimentary rocks, so it's false.

Answer:

Weathering (breaking down rock) and erosion (transporting rock material) at or near the earth's surface breaks down rocks into small and smaller pieces. When the molten rock cools it forms an igneous rock. Metamorphic rocks can form from either sedimentary or igneous rocks.

Explanation:

True

There are approximately 1.387 moles in 25 grams of water (1) and 134.46 grams in 4.5 moles of Li₂O (2).

1. To calculate the number of moles, we need to divide the given mass of water by the molar mass of water, which is approximately 18.015 g/mol.

Number of moles = 25 grams / 18.015 g/mol

≈ 1.387 moles

Therefore, there are approximately 1.387 moles in 25 grams of water.

2. To calculate the mass in grams, we need to multiply the number of moles by the molar mass of Li₂O, which is approximately 29.88 g/mol.

Mass in grams = 4.5 moles x 29.88 g/mol

≈ 134.46 grams

Therefore, there are approximately 134.46 grams in 4.5 moles of Li₂O.

3. To determine the number of molecules in 23 moles of oxygen, we can use Avogadro's number, which states that there are 6.022 x 10²³ molecules in one mole of any substance. Therefore, for 23 moles of oxygen, we can calculate:

Number of molecules = 23 moles x 6.022 x 10²³ molecules/mole

= 1.38646 x 10²⁵ molecules

So, there are approximately 1.38646 x 10²⁵ molecules in 23 moles of oxygen.

4. To determine the number of moles in 3.4 x 10²³ molecules of H₂SO₄, we can use Avogadro's number. Since one mole contains 6.022 x 10²³ molecules, we can calculate:

Number of moles = (3.4 x 10²³ molecules) / (6.022 x 10²³ molecules/mole)

= 0.564 moles

So, there are approximately 0.564 moles in 3.4 x 10²³ molecules of H₂SO₄.

5. To determine the number of molecules in 25 grams of NH₃, we need to convert grams to moles using the molar mass of NH₃. The molar mass of NH₃ is 17.03 g/mol.

Number of moles = 25 grams / 17.03 g/mol

≈ 1.468 moles

Using Avogadro's number, we can calculate the number of molecules:

Number of molecules = (1.468 moles) x (6.022 x 10²³ molecules/mole)

= 8.831 x 10²³ molecules

So, there are approximately 8.831 x 10²³ molecules in 25 grams of NH₃.

The complete question is:

Answer the following questions:

1) How many moles are in 25 grams of water?

2) How many grams are in 4.5 moles of Li₂O?

3) How many molecules are in 23 moles of oxygen?

4) How many moles are in 3.4 x 10²³ molecules of H₂SO₄?

5) How many molecules are in 25 grams of NH₃ ?

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the third one

seeeeeee

To determine the oxidation state of each species, we need to assign a charge to each atom based on the electronegativity difference between the elements and assuming that electrons in bonds are shared equally.

The oxidation state of Ba²⁺ is +2, as it has lost two electrons to become a cation.

The oxidation state of S in SO₃²⁻ is +4, as oxygen has an oxidation state of -2 and the overall charge of the ion is -2. Therefore, sulfur must have a +4 oxidation state to balance the charges.

The oxidation state of S in SO₄²⁻ is +6, as oxygen has an oxidation state of -2 and the overall charge of the ion is -2. Therefore, sulfur must have a +6 oxidation state to balance the charges.

The oxidation state of Zn in ZnSO₄ is +2, as oxygen has an oxidation state of -2 and the overall charge of the ion is 0. Therefore, zinc must have a +2 oxidation state to balance the charges.

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Answer:

influence of a business invironment

1. The differential equation satisfied by y(t) is:  dy/dt = 0.6 kg/min

The amount of salt in the tank after t minutes can be represented by the function y(t). We need to find the differential equation that y satisfies.
Initially, the tank contains 100 L of pure water, which means there is no salt in the tank. As time passes, a solution with a salt concentration of 0.3 kg/L is added at a rate of 7 L/min. The salt concentration in the tank will increase with the addition of this solution.
At the same time, the solution is drained from the tank at a rate of 5 L/min. This will result in a decrease in the salt concentration in the tank.
To find the differential equation satisfied by y(t), we need to consider the rate of change of salt in the tank.
Rate of change of salt in the tank = Rate of salt added - Rate of salt drained
The rate of salt added is given by the product of the concentration of the solution (0.3 kg/L) and the rate at which the solution is added (7 L/min). So, the rate of salt added = 0.3 kg/L * 7 L/min.

The rate of salt drained is given by the product of the concentration of the solution (0.3 kg/L) and the rate at which the solution is drained (5 L/min). So, the rate of salt drained = 0.3 kg/L * 5 L/min.

Therefore, the differential equation satisfied by y(t) is:
dy/dt = (0.3 kg/L * 7 L/min) - (0.3 kg/L * 5 L/min)

Simplifying the equation:
dy/dt = 2.1 kg/min - 1.5 kg/min
dy/dt = 0.6 kg/min

So, the differential equation satisfied by y(t) is:
dy/dt = 0.6 kg/min

2. The amount of salt in the tank after 40 minutes is 24 kilograms.

To find the amount of salt in the tank after 40 minutes, we can solve the differential equation.

dy/dt = 0.6 kg/min

Integrating both sides with respect to t:
∫dy = ∫0.6 dt

Integrating, we get:
y = 0.6t + C

To find the value of C, we can use the initial condition that the tank initially contains 100 L of pure water, which means there is no salt. So, at t = 0, y = 0.

Substituting these values into the equation:
0 = 0.6(0) + C
C = 0

Therefore, the equation becomes:
y = 0.6t

Now, we can find the amount of salt in the tank after 40 minutes by substituting t = 40 into the equation:
y = 0.6(40)
y = 24 kg


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The interstellar matter is the hydrogen and the helium will gives the narrow absorption lines in the spectra of the some stars.

The interstellar matter is composed of the multiple phases that will distinguished by the whether matter is the  ionic, atomic, or the molecular, and the temperature and the density of the matter. The interstellar medium is the composed the primarily, of the hydrogen atom , followed by the helium atom with the trace amounts of the carbon, the oxygen, and the nitrogen.

The matter will creates the narrow absorption of the lines in the spectra of the some of the stars.

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The isomer with the higher equilibrium vapor pressure at 20 celsius is the cis-isomer of 1,2-dichloroethene. This is because the cis-isomer has a more symmetrical structure, with the two chlorine atoms on the same side of the double bond, which allows for stronger intermolecular forces of attraction between molecules.

These stronger intermolecular forces lead to a higher boiling point and vapor pressure.
On the other hand, the trans-isomer has a less symmetrical structure, with the two chlorine atoms on opposite sides of the double bond, which leads to weaker intermolecular forces of attraction between molecules. As a result, the trans-isomer has a lower boiling point and vapor pressure than the cis-isomer.
Overall, the molecular structure of each isomer plays a critical role in determining its vapor pressure. The more symmetrical the structure, the stronger the intermolecular forces and the higher the vapor pressure. In this case, the cis-isomer has a more symmetrical structure and thus has a higher equilibrium vapor pressure at 20 celsius.

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Answer:

a. CH2(NH2)COOH

\(molecular \: mass = (12 \times 2) + (5 \times 1) + (14 \times 1) + (16 \times 2) \\ = 24 + 5 + 14 + 32 \\ = 75 \: grams\)

b. H2SO4

\(molecular \: mass = (2 \times 1) + 32 + (16 \times 4) \\ = 2 + 32 + 64\\ = 98 \: grams\)

Answer:

0.342 moles

145 moles

0.0239 moles

0.498 moles

Explanation:

To solve this you only need to follow this rule:

N = n x Na. For solving this questions, you just need to divide this values for Avogadro's Coasting, and it's done. Hope it helped!