Lupita y Fernando y Andrés quieren comprar entre los tres una bicicleta que ven todos los días en el aparador de la tienda todo para todos para sus vacaciones le han deseado tanto que decidieron comprarla cada uno sacó cuentas de lo que debería pagar por la bicicleta​

Answer:

∞-9

Step-by-step explanation:

Sydney can row a canoe at a speed of 5 mph in still water.

Let x represent Sydney's speed in still water. When rowing upriver, her effective speed will be (x - 2) mph because she's going against the current, which flows at 2 mph. When rowing downriver, her effective speed will be (x + 2) mph, since she's going with the current.

According to the problem, the time it takes her to row 6 miles upriver is the same as the time it takes her to row 14 miles downriver. We can set up the equation using the formula time = distance / speed:

6 / (x - 2) = 14 / (x + 2)

To solve for x, first cross-multiply:

6(x + 2) = 14(x - 2)

Expand:

6x + 12 = 14x - 28

Now, rearrange and solve for x:

12 + 28 = 14x - 6x

40 = 8x

x = 5

So, Sydney can row a canoe at a speed of 5 mph in still water.

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Driving a personal car would be the most cost-effective mode of transportation for this commute, with a total daily cost of approximately $4.60 ($3.60 for gas + $1 for travel time).

Based on the given information, the most cost-effective mode of transportation for this commute would be to drive a personal car. Taking public transportation or carpooling may be more environmentally friendly options, but they may not save as much money as driving alone.

Assuming an average speed of 60 miles per hour on the highway, the commute would take approximately 20 minutes each way, or 40 minutes round-trip. This means the total cost of travel time for each workday would be $40 ($60/hour x 2/3 hour).

Using a cost calculator such as GasBuddy, we can estimate that the cost of driving 20 miles per day (round-trip) would be around $3.60 per day, assuming an average fuel efficiency of 25 miles per gallon and a gasoline price of $2.50 per gallon.

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To Construct the box-and-whisker plot: Draw a number line, mark the quartiles (Q1, Q2, Q3), and represent the data points with dots or small vertical lines. Connect the lower and upper quartiles with a box, and extend lines (whiskers) from the box to the minimum and maximum values that are not considered outliers.

(a) Data set 1: {0.87, 0.88, 0.91, 0.92, 0.86, 0.91, 0.90, 0.93, 0.82, 0.89, 0.87}

1. Arrange the data in ascending order: 0.82, 0.86, 0.87, 0.87, 0.88, 0.89, 0.90, 0.91, 0.91, 0.92, 0.93.

2. Calculate the quartiles:

  - Q1: The median of the lower half of the data set: Q1 = 0.87.

  - Q2: The median of the entire data set: Q2 = 0.89.

  - Q3: The median of the upper half of the data set: Q3 = 0.91.

3. Calculate the interquartile range (IQR): IQR = Q3 - Q1 = 0.91 - 0.87 = 0.04.

4. Identify any outliers based on the lower and upper fences (values outside Q1 - 1.5 * IQR and Q3 + 1.5 * IQR, respectively).

5. Construct the box-and-whisker plot: Draw a number line, mark the quartiles (Q1, Q2, Q3), and represent the data points with dots or small vertical lines. Connect the lower and upper quartiles with a box, and extend lines (whiskers) from the box to the minimum and maximum values that are not considered outliers.

(b) Data set 2: {98.0, 74.1, 121.2, 103.5, 79.4, 89.3, 79.9, 80.2, 76.4, 109.7, 86.8, 82.1}

Follow the same steps as above to construct the box-and-whisker plot for Data set 2.

The box-and-whisker plots visually represent the distribution of the data sets, providing information about the minimum and maximum values, quartiles, and any outliers present in the data.

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Answer:

y = 8.7

Step-by-step explanation:

Assuming we can use decimal places, y is equal to 8.7.

In programming, += is often used as a substitute for y = y + x (example)

Therefore, y = y + 3.7, and since y = 5, y = 5 + 3.7, y = 8.7

Answer:

Call x is childrens

Call y is adults

x + y = 386 (1)

1,75x + 2,5y = 807,5 (2)

(1) => x = 386 - y => (2) 1,75 ( 386-y )+2,5y = 807,5

0,75y=132 => y = 176 and x = 210

Step-by-step explanation:

The average velocity for the time period is -15 feet per second

The velocity of the ball = 31 feet / seconds

The function of the height is

y = 31t - 23t^2

Time period beginning when t = 1 and lasting .01 s, .005 s, .002 s, .001 s

The average velocity = f(1.01) - f(1) / 1.01 - 1

f(t) = 31t - 23t^2

f(1.01) = 31(1.01) - 23(1.01)^2

= 31.31 - 23.46

= 7.85 feet per second

Similarly

f(1) = 31(1) - 23(1)^2

= 31 - 23

= 8 feet per second

The average velocity =  7.85 - 8 / 1.01 - 1

= -0.15 / 0.01

= -15 feet per second

Hence, the average velocity for the time period is -15 feet per second

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Answer:

i) 0.1056

ii) 0.105

iii) 0.1

iv) 0.1056

Step-by-step explanation:

0.36, to the power of 2 (0.36×0.36) is 0.1296

0.1296-0.03×0.8=0.1056

Answer:

love jacobt tremblay

Step-by-step explanation:

Answer:

16.33

Step-by-step explanation:

I hope this was right!

The probability that the price of toothpaste remains fixed for more than 3 months is generally low. However, when inflation is high, the probability becomes even lower.

Toothpaste is a consumer good that is affected by various economic factors, including inflation. Inflation is the rate at which the general price level of goods and services in an economy is increasing. When inflation is high, the prices of goods and services tend to rise rapidly, and therefore, the probability that the price of toothpaste will remain fixed for more than three months becomes lower.

Furthermore, toothpaste is a product that is subject to constant innovation, with companies frequently introducing new formulations, flavors, and packaging. The constant innovation in the industry implies that prices are subject to change frequently. Additionally, toothpaste is a commodity that is not considered a necessity, and therefore, its demand is elastic. As such, companies may opt to adjust their prices to meet consumer demand, which further lowers the probability that toothpaste prices will remain fixed for an extended period.

Overall, the probability that toothpaste prices remain fixed for more than three months is generally low. However, when inflation is high, the probability becomes even lower, given that prices tend to fluctuate rapidly during such periods. Toothpaste is also subject to constant innovation, which implies that prices are subject to change frequently, while the elastic demand for toothpaste further lowers the probability that prices will remain fixed.

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Answer:

The height of the pyramid is 2cm

Step-by-step explanation:

From the complete question, we have:

Marble Dimension:

\(Length = Width = 6cm\)

\(Height = 8cm\)

Pyramid

\(Length = Width = 6cm\)

Volume = 1/4th of the volume of the marble

Required

The height of the pyramid

First, calculate the volume of the Marble

\(Volume = Length * Width *Height\)

So:

\(V_1 = 6cm * 6cm * 8cm\)

\(V_1 = 288cm^3\)

Calculate the volume of the Pyramid

\(Volume = Length * Width *Height\)

\(V_2 = 6cm * 6cm * h\ cm\)

\(V_2 = 36cm^2 h\)

From the question, we understand that:

\(V_2 = \frac{V_1}{4}\)

So, we have:

\(36cm^2h = \frac{288cm^3}{4}\)

\(36h = \frac{288cm}{4}\)

\(36h = 72cm\)

Solve for h

\(h = \frac{72cm}{36}\)

\(h =2cm\)

So, the matrix representation of the given system of linear first-order differential equations is: X' = [1 2; 3 0] X + [ -4e^(2t); 0 ].

To write the given system of linear first-order differential equations in matrix form, we can define the vector of variables X as X = [x, y].

The system can then be represented as:

X' = AX + B

where X' is the derivative of X with respect to the independent variable, A is the coefficient matrix, X is the vector of variables, and B is the vector of constant terms.

For the given system:

x' = x + 2y - 4e^(2t)

y' = 3x

The matrix form of the system becomes:

X' = [1 2; 3 0] X + [ -4e^(2t); 0 ]

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Answer:

\(5k^2-4k>0\)

\(k(5k-4)>0\)

In the image attached, you want the values above 0. Thus, the values of k would be in the red area, which is

\(k<0\) or \(k>\frac{4}{5}\)

9514 1404 393

Answer:

  y = 1/2x + 1

Step-by-step explanation:

The slope of the line is "rise"/"run", where "rise" is the vertical distance between two points separated by a horizontal distance of "run".

Here, two points are marked that are 4 units apart horizontally (run = 4). The right-most point is 2 units above the left-most point (rise = 2). The slope between these points is ...

  m = rise/run = 2/4 = 1/2

The line crosses the y-axis at y=1, so the "y-intercept" is b=1.

These values can be put into the "slope-intercept form" equation for a line.

  y = mx + b . . . . . . line with slope m and y-intercept b

  y = 1/2x + 1 . . . . . matches the required answer form

The value of `c` is `1/ (24 π)`.b. The expected value `E[X] = 1/ (120 π)` and the variance `Var[X] = 1/ (7200 π^2)`

Given, X be a random variable with density `f(x) = cx^5 e^ (−5x)` for `x > 0` and `f(x) = 0` for `x ≤ 0`.a) Find c.Integration of the function `f(x)` with limits `0 to ∞` is equal to `1`.Thus, ∫f(x) dx (limit 0 to ∞) = 1 `=> ∫c x^5 e^-5x dx (limit 0 to ∞) = 1`Solving, we get `c= 1/ (24 π)`Therefore, the value of `c` is `1/ (24 π)`b) Compute E[X] and Var[X]We have, `f(x) = cx^5 e^ (-5x)`E[X] = `∫ x f(x) dx` (limit 0 to ∞)`=> ∫ x (1/ (24 π)) x^5 e^-5x dx` (limit 0 to ∞)Substitute `u = x^6` and `du = 6x^5 dx`We get,E[X] = `(1/ (24 π))  ∫(u^(1/6)) e^(-5 (u^(1/6))) du` (limit 0 to ∞)Substitute `t = -5u^(1/6)` and `dt = (-5/6) (u^(-5/6)) du`We get,E[X] = `(1/ (24 π))  ∫(-1/5) e^(t) dt` (limit -∞ to 0) = `1/ (24 π*5) = 1/ (120 π)`.

Therefore, the expected value `E[X] = 1/ (120 π)`Var[X] = E[X^2] - (E[X])^2We have,`E[X^2] = ∫(x^2) f(x) dx` (limit 0 to ∞)`=> ∫(x^2) (1/ (24 π)) x^5 e^-5x dx` (limit 0 to ∞)`=> (1/ (24 π))  ∫x^7 e^-5x dx` (limit 0 to ∞)Substitute `u = x^8` and `du = 8x^7 dx`We get,E[X^2] = `(1/ (24 π))  ∫(u^(1/8)) e^(-5 (u^(1/8))) du` (limit 0 to ∞)Substitute `t = -5u^(1/8)` and `dt = (-5/8) (u^(-7/8)) du`We get,E[X^2] = `(1/ (24 π*5))  ∫(-1/5) e^(t) dt` (limit -∞ to 0) = `1/ (24 π*25) = 1/ (600 π)`Therefore, `E[X^2] = 1/ (600 π)`Putting the values of `E[X]` and `E[X^2]` in `Var[X]` formula, we get,Var[X] = `(1/ (600 π)) - (1/ (120 π))^2`Var[X] = `1/ (7200 π^2)`Therefore, the variance `Var[X] = 1/ (7200 π^2)`Hence, the solution is as follows:a. The value of `c` is `1/ (24 π)`.b. The expected value `E[X] = 1/ (120 π)` and the variance `Var[X] = 1/ (7200 π^2)`.

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No, percentages are not inherently proportional.

Proportionality refers to a constant ratio between two quantities, meaning that as one quantity increases or decreases, the other also changes in a predictable and consistent manner.

Percentages, on the other hand, represent a portion or fraction of a whole in relation to 100. They are relative measures that are often used to compare values or express proportions. While percentages can be used to indicate proportions, the relationship between percentages and the underlying quantities they represent is not necessarily proportional.

For example, if you have two quantities, A and B, and you express them as percentages, such as A = 50% and B = 25%, the percentages alone do not indicate a proportional relationship between A and B. In this case, A is twice as large as B, but the percentage values alone do not convey this information.

Proportionality is determined by the relationship between the actual values of the quantities being compared, rather than the percentage representations.

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Answer:368

Step-by-step explanation:

The maximum area that the material would cover is 640, 000 square yards

A rate of change is a rate that describes how one quantity changes in relation to another quantity. If x is the independent variable and y is the dependent variable, then

rate of change = change in y / change in x

if 3200 yards was used for fencing, then 3200 yards is perimeter

and perimeter of a rectangle = 2( L + B)

so that,

2(L + B) = 3200

L + B = 1600

express L in terms of B

L = 1600 - B

Area(A) = L X B

A = L X B

substitute L = 1600 -B

A = (1600 - B) x B

multiply out

A = 1600B - \(B^{2}\)

for maximum area,

\(\frac{dA}{dB}\) = 0

But dA / dB = 1600 - 2B

1600 - 2B = 0

2B =1600

B = 1600/2

B = 800 yards

L = 1600 - B

L = 1600 - 800

L = 800 yards

Area = L X B

A = 800 x 800

A = 640,000 square yards

In conclusion, he maximum area is  640,000 square yards and the dimensions are 800 yards by 800 yards

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The measure of angle C is 122 degrees.

We have given that,

In triangle ABC, m∠A=23° and m∠B=33°

We have to determine the remaining angle of the triangle.

The sum of the angles in a triangle is 180 degrees.

Therefore we get

angle A+ angle B+ angle C= 180 degrees

23+33+angle C=180

angle C=180-56

angle C=122

Therefore the measure of angle C is 122 degrees.

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As the sample size increases, the standard deviation decreases, and the distribution of the sample mean becomes more concentrated around the population mean.

Increasing the sample size has a significant effect on the mean and standard deviation of all possible sample mean hours worked per week at home. The sample size is the number of observations in the sample, and the sample mean is the average of those observations.

When the sample size is large, the sample mean becomes a better estimate of the population mean. This is because a large sample size reduces the sampling error, which is the difference between the sample mean and the population mean.Standard deviation is a measure of how spread out the data is.

When the sample size is large, the standard deviation becomes a better estimate of the population standard deviation. This is because a large sample size reduces the standard error, which is the difference between the sample standard deviation and the population standard deviation.

Increasing the sample size makes the mean more accurate and reduces the variability of the sample mean. As the sample size increases, the standard deviation decreases, and the distribution of the sample mean becomes more concentrated around the population mean.

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Answer:

B.

Step-by-step explanation:

Answer:

Step-by-step explanation:

6x2−7x−5 / 2x+1

=    6x2−7x−5 / 2x+1

=    (3x−5)(2x+1)  / 2x+1

=3x−5

The first five terms of the expression are -7,-3,1,5, and 9.

The sequence in which every next number is the addition of the constant quantity in the series is termed the arithmetic progression

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that , F(1) = -3 and F(n) = F(n-1) + 4. Calculate the first term of the sequence,

F(1) = F(1-1) + 4

-3 = F(0) + 4

F(0) = -7

The common difference is calculated as,

d = -3 - 7

d = 4

The third term will be, -3 + 4 = 1

The fourth term will be, 1 + 4 = 5

The fifth term will be, 5 + 4 = 9

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Answer:

D

Step-by-step explanation:

Substitute the f(x) and g(x) into f/g

\(\frac{\sqrt[3]{3x} }{5x+2}\)

To find the domain,

Get the denominator of the fraction so 5x + 2 and equal it to 0 and find x

5x + 2 = 0

5x = -2

x = \(\frac{-2}{5}\)

Therefore it's D

Answer: Accounting profit=$90,000 and Economic profit loss= $28,500

Step-by-step explanation:

Accounting profit = Total revenue - Explicit costs Accounting profit = ($65 × 4,000) - ($50,000 + $120,000) Accounting profit = $260,000 - $170,000 Accounting profit = $90,000

Economic profit = Total revenue - (Explicit costs + Implicit costs) Economic profit = ($65 × 4,000) - ($50,000 + $120,000 + Forgone interest on savings + Forgone wages) Economic profit = ($65 × 4,000) - [$50,000 + $120,000 + (0.06 x $25,000) + $60,000] Economic profit (loss) = $28,500

An equation of the line that satisfies the given conditions is x = 2y + 13.

To find the equation of the line that passes through the point (-9, -11) and is perpendicular to the line passing through (-6, 1) and (-2, -1), we can use the slope-point form of a line.

First, we find the slope of the line passing through (-6, 1) and (-2, -1). The slope of this line can be found using the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Plugging in the values, we have:

m = (-1 - 1) / (-2 - (-6)) = -2 / 4 = -1/2

The slope of a line perpendicular to this line has a negative reciprocal, so the slope of the line through (-9, -11) that is perpendicular to this line is 1/2.

Next, we use the point-slope form of a line to find the equation of the line:

y - y1 = m (x - x1)

where (x1, y1) is a point on the line and m is the slope.

Plugging in the values, we have:

y - (-11) = 1/2 (x - (-9))

Expanding and simplifying, we get:

y + 11 = 1/2 (x + 9)

Multiplying both sides by 2, we get:

2y + 22 = x + 9

Subtracting 9 from both sides, we get:

2y + 13 = x

So, the equation of the line that satisfies the given conditions is:

x = 2y + 13

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Answer:

a

Step-by-step explanation:

most likely the answer is a because we have (10,4), 10 being the domain(X-Intercept) and 4 being range(Y-Intercept)

if we substitute the value of X in option a with 10, we get a value of 3.7 as shown in the picture which can be can be converted to 4

Answer:

\(\textsf{B.} \quad \dfrac{2 +\sqrt{12}}{2}\)

\(\textsf{C.} \quad 1\)

\(\textsf{E.} \quad \dfrac{2-\sqrt{12}}{2}\)

Step-by-step explanation:

If f(x) is a polynomial, and f(a) = 0, then (x – a) is a factor of f(x).

If the coefficients in a polynomial add up to 0, then (x - 1) is a factor.

Given polynomial function:

\(f(x)=x^3-3x^2+2\)

Sum the coefficients:

\(\implies 1-3+2=0\)

As the sum of the coefficients equals one, (x - 1) is a factor the polynomial.

Find the other factor by dividing the polynomial by (x - 1):

\(\large \begin{array}{r}x^2-2x-2\phantom{)}\\x-1{\overline{\smash{\big)}\,x^3-3x^2+2\phantom{)}}}\\{-~\phantom{(}\underline{(x^3-x^2)\phantom{-)..)}}\\-2x^2+2\phantom{)}\\-~\phantom{()}\underline{(-2x^2+2x)\phantom{}}\\-2x+2\phantom{)}\\\phantom{)}-~\phantom{()}(-2x+2)\\\end{array}\)

Therefore, the factored form of the polynomial is:

\(f(x)=(x-1)(x^2-2x-2)\)

To find the roots, set the function to zero and solve for x.

Set the first factor to zero and solve for x:

\(\implies (x-1)=0 \implies x=1\)

Set the second factor to zero and solve for x using the quadratic formula:

\(\implies x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\)

\(\implies x=\dfrac{-(-2) \pm \sqrt{(-2)^2-4(1)(-2)}}{2(1)}\)

\(\implies x=\dfrac{2 \pm \sqrt{12}}{2}\)

Answer:

Nonlinear

Step-by-step explanation:

Answer:

Linear

Step-by-step explanation:

A linear equations is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables.

In this case, the degree of variable y is 1 and the degree of variable x is 1.

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