Listed following is a set of statements describing individual stars or characteristics of stars. Match these to the appropriate object category.a. Red Giant or Supergiant Starts.b. Main-sequence starsc. White dwarfs1. Very cool but very luminous2. Found in the upper right of the H-R diagram3. The majority of stars in our galaxy4. The Sun, for example5. A very hot and very luminous star6. not much larger in radius than Earth7. Very hot but very dim

Answer:

(B) 80 ohms

Explanation:

Since the circuit is a series connection, simply add the two resistances together to get 80 ohms.

Explanation:

yeah what is your question

Answer:

If the speed of the object varies at all over the interval, the instantaneous velocity will sometimes be greater than the average velocity

Explanation:

When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

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Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

A. Wearing appropriate running shoes for your environment is an example of being proactive in your workouts.

There are several ways to become proactive in workouts:

(1) Set specific goals: Setting specific and measurable fitness goals can help you stay focused and motivated. It can also help you track your progress and make necessary adjustments to your workout routine.

(2) Plan your workouts: Planning your workouts ahead of time can help you stay organized and committed to your fitness routine. This can include scheduling your workouts in advance and creating a workout plan that targets your specific goals.

(3) Track your progress: Tracking your progress can help you stay motivated and see how far you've come. This can include keeping a workout journal, taking progress photos, or using a fitness tracker.

(4) Stay consistent: Consistency is key when it comes to achieving fitness goals. Set a regular workout schedule and stick to it as much as possible.

(5) Listen to your body: Pay attention to how your body feels during and after workouts. If something doesn't feel right, make adjustments or seek guidance from a fitness professional.

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Sinkholes formation is one feature of karst topography. The top of a cave falls if it develops large enough and its top extends near enough to the surface.

Karst topography is a type of natural environment formed mostly by chemical weathering by water, resulting in caves, sinkholes, cliffs, and steep-sided hills known as towers.

The top of a cave falls if it develops large enough and its top extends near enough to the surface. Sinkholes are formed as a result of this, and they are one of the most distinguishing aspects of karst terrain.

When water absorbs carbon dioxide from the atmosphere and ground, it becomes carbonic acid.

Hence, sinkholes  formation is one feature of karst topography

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Answer: A) Caves

Explanation:

Answer:

gpe gained = 60J

Explanation:

gravitational potential energy  =  mass * gravity * height

gpe =  2 kg * 10 N * 3 m

gpe = 60J

Answer:

I think it's a repulsive force

The wavelength of a wave with frequency of 100.2Khz is 2.99 × 10³m.

Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.

The wavelength is often designated in physics as λ, and corresponds to the velocity of the wave divided by its frequency as follows:

λ = v/f

Where;

According to this question, the frequency of a wave is 100.2KHz, which is equivalent to 1.002 × 10⁵Hz.

λ = 3 × 10⁸ ÷ 1.002 × 10⁵

λ = 2.99 × 10³m

Therefore, 2.99 × 10³m is the wavelength of the wave.

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The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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Answer:

Explanation:

ω = v / R

where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .

Given v = 150 m/s ; R =.10 m

ω = 150 / .10

= 1500 radian /s .

Final angular speed is 1500 radian /s .

In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 8.00 cos (5t + π / 8) where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. cm (b) At t = 0, find velocity of the piston. cm/s (c) At t = 0, find acceleration of the piston. cm/s2 (d) Find the period and amplitude of the motion. period s amplitude cm

(a) 7.392cm

(b) -15.32 cm/s

(c) -184cm/s²

(d) 0.4πs and 8.00cm

The general equation of a simple harmonic motion (SHM) is given by;

x(t) = A cos (wt + Φ)        --------------(i)

Where;

x(t) = position of the body at a given time t

A =  amplitude or maximum displacement during oscillation

w = angular velocity

t = time

Φ = phase constant.

Given from question:

x(t) = 8.00 cos (5t + π / 8)         ---------------(ii)

(a) At time t = 0;

The position, x(t), of the body (piston) is given by substituting the value of t = 0 into equation (ii) as follows;

x(0) = 8.00 cos (5(0) + π / 8)

x(0) = 8.00 cos (π /8)

x(0) = 8.00 x 0.924

x(0) = 7.392 cm

Therefore, the position of the piston at time t = 0 is 7.392cm

(b) To get the velocity, v(t), of the piston at t = 0, first differentiate equation (ii) with respect to t as follows;

v(t) = \(\frac{dx(t)}{dt}\)

v(t) = \(\frac{d(8.00cos(5t + \pi / 8 ))}{dt}\)

v(t) = 8 (-5 sin (5t + π / 8))

v(t) = -40sin(5t + π / 8)     --------------------(iii)

Now, substitute t=0 into the equation as follows;

v(0) = -40 sin(5(0) + π / 8)

v(0) = -40 sin(π / 8)

v(0) = -40 x 0.383

v(0) = -15.32 cm/s

Therefore, the velocity of the piston at time t = 0 is -15.32 cm/s

(c) To find the acceleration a(t) of the piston at t = 0, first differentiate equation (iii), which is the velocity equation, with respect to t as follows;

a(t) = \(\frac{dv(t)}{dt}\)

a(t) = \(\frac{d(-40sin (5t + \pi /8))}{dt}\)

a(t) = -200 cos (5t + π / 8)

Now, substitute t = 0 into the equation as follows;

a(0) = -200 cos (5(0) + π / 8)

a(0) = -200 cos (π / 8)

a(0) = -200 x 0.924

a(0) = -184.8 cm/s²

Therefore, the acceleration of the piston at time t = 0 is -184cm/s²

(d) To find the period, T, first, let's compare equations (i) and (ii) as follows;

x(t) = A cos (wt + Φ)                   --------------(i)

x(t) = 8.00 cos (5t + π / 8)         ---------------(ii)

From these equations it can be deduced that;

Amplitude, A = 8.00cm

Angular velocity, w = 5 rads/s

But;

w = \(\frac{2\pi }{T}\)           [Where T = period of oscillation]

=> T = \(\frac{2\pi }{w}\)

=> T = \(\frac{2\pi }{5}\)

=> T = 0.4π s

Therefore, the period and amplitude of the piston's motion are respectively 0.4πs and 8.00cm

Explanation:

time = distance / velocity

We know that distance = 910 km and velocity = 90 km/h.

t = d / v

t = 910 km / 90 km/h

t = 10.11 hrs

The object traveled for 10.11 hours long. Hope this helps, thank you !!

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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The pressure exerted by Clive in N/cm² when he stands on one foot, given that one foot is 180 cm² and he has a mass of 72 Kg, is 3.92 N/cm²

We'll begin by obtaining the weight of Clive. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

W = 72 × 9.8

W = 705.6 N

Finally, we shall determine the pressure exerted. Details below:

Pressure exerted  = Weight of Clive  / Area

Pressure exerted = 705.6 / 180

Pressure exerted = 3.92 N/cm²

Thus, from the calculation made above, we can conclude that the pressure exerted is 3.92 N/cm²

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The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

Gravity is a fundamental force of nature that exists between all objects that have mass or energy. It is the force that pulls two objects towards each other, and it is what keeps objects like planets, stars, and galaxies in their orbits.

The force of gravity is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This means that the greater the mass of the objects and the closer they are to each other, the greater the force of gravity between them.

Gravity is responsible for many phenomena that we observe in our daily lives, such as keeping us and other objects on the surface of the Earth, causing tides in the ocean, and making objects fall to the ground when we drop them. It is also a key concept in the fields of astronomy and astrophysics, as it is what allows us to understand the motion and behavior of celestial objects in the universe.

Hence, The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

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Explanation:

a) It will weigh less because of its distance from the block.

b) torque = W1×d1 = (10N)(0.25m) = 2.5 N-m

c) torque = W2×d2 = W2×(0.50m)

d) W2×d2 = W1×d1

W2 = (d1/d2)W1

= 5 N

Answer:

Explanation:

In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.

So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

that's b

Explanation:

Explanation:

Let the initial speed of 2nd stone is u2 and final speed of it be v2.

Using the equation

v= u + at for the 2nd stone

We get

14.7=u2 + 10t (a=g, acceleration due to gravity)

14.7=0 +10t

Or, t= 1.47s

This is the time taken by 2nd stone to reach 14.7m/s

Now,

Total time for 1st stone=1.04 + 1.47= 2.51s

Using the equation

\(s = ut + \frac{1}{2} at {}^{2} \)

for distance travelled by 1st stone

s1=u2t + 1/2at²

u2=0 (initially it was also at rest)

\(s1 = \frac{1}{2} \times 10 \times 2.51 {}^{2} \)

therefore S = 31. 5005m

Distance travelled by 2nd stone

\(s2 = u2 + \frac{1}{2} at {}^{2} \)

\(s2 = \frac{1}{2} \times 10 \times 1.47 {}^{2} \)

therefore S2 = 10.8m

Therefore,

Distance between the stones is= s1 - s2 = 31.5005–10.8 = 20.7005

Ans:- 20.7m

The forces acting on the skier is 602.1 N in perpendicular direction and 421.6 N in parallel direction.

The forces acting on the skier at the inclination of the slope is calculated by applying Newton's second law of motion as shown below.

There are two forces acting on the skier;

The perpendicular force is calculated as;

Fn = mg cosθ

where;

Fn = 75 kg x 9.8 m/s² x cos (35)

Fn = 602.1 N

The parallel force on the skier;

F = mg sinθ

F = 75 kg x 9.8 m/s² x sin (35)

F = 421.6 N

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Here is the complete question

The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,900,000 . Determine the horizontal shear stress at point H, which is located L  = 20 mm below the centriod

The missing image which is the remaining part of this question is attached in the image below.

Answer:

The horizontal shear stress at point H is  \(\mathbf{\tau_H \approx 42.604 \ N/mm^2}\)

Explanation:

Given that :

The internal shear force V  =  80 kN = 80 × 10³ N

The moment of inertia = 64,900,000

The length = 20 mm below the centriod

The horizontal shear stress  \(\tau\) can be calculated by using the equation:

\(\tau = \dfrac{VQ}{Ib}\)

where;

Q = moment of area above or below the point H

b = thickness of the beam = 10  mm

From the centroid ;

Q = \(Q_1 + Q_{2}\)

Q = \(A_1y_1 + A_{2}y_{2}\)  

Q = ( ( 70 × 10) × (55) + ( 210 × 15) (90 + 15/2) ) mm³

Q = ( ( 700) × (55) + ( 3150 ) ( 97.5)  ) mm³

Q = ( 38500 +  307125 ) mm³

Q = 345625 mm³

\(\tau_H = \dfrac{VQ}{Ib}\)

\(\tau_H = \dfrac{80*10^3 * 345625}{64900000*10 }\)

\(\tau_H = \dfrac{2.765*10^{10}}{649000000 }\)

\(\tau_H = 42.60400616 \ N/mm^2\)

\(\mathbf{\tau_H \approx 42.604 \ N/mm^2}\)

The horizontal shear stress at point H is  \(\mathbf{\tau_H \approx 42.604 \ N/mm^2}\)

Answer:

a

Explanation:

ajjkiikkkkkhglutfgkitfgghiiij

Answer:

R = (-2î − 6ĵ + 10k^)m

Explanation:

We are given;

D = (2î − 6ĵ)

Now, we want to find R such that,

D + R = −5Dĵ

Plugging in (2î − 6ĵ) for D in the R equation gives;

(2î − 6ĵ) + R = -5(2î − 6ĵ)j

(2î − 6ĵ) + R = -10k + 0

This is because in vector multiplication, i × j = k and j × j = 0

Thus;

(2î − 6ĵ) + R = -10k

Making R the subject gives;

R = -2î − 6ĵ + 10k^

Thus, the displacement vector R is;

R = (-2î − 6ĵ + 10k^)m

Answer:

Explanation:

4

The magnitude and direction of the resultant force on q3 is;

F_net = 32.2 N in the direction of q3

We are given;

q1 = +2 μC = 2 × 10^(-6) C

q2 = -3 μC = -3 × 10^(-6) C

q3 = +4 μC = 4 × 10^(-6) C

Now,from the given image, charges q1 and q2 attract charge q3.

Formula for force on a charge is;

F = (kq1 * q2)/r²

Where;

k = 9 × 10^(9) N.m²/C²

Thus;

F_y = kq1*q3/(r1)²

We have;

q1 = 2 × 10^(-6) C

r1 = 5 cm = 0.05 m

q3 = 4 × 10^(-6) C

Thus;

F_y = (9 × 10^(9) × 2 × 10^(-6) × 4 × 10^(-6))/(0.05^(2))

F_y = 28.8 N

Similarly;

F_x = kq2*q3/(r2)²

r2 = 5/(tan 30)

r2 = 8.66 cm = 0.0866 m

F_x = (9 × 10^(9) × -3 × 10^(-6) × 4 × 10^(-6))/(0.0866^(2))

F_x = -14.4 N

Thus, magnitude of resultant force is;

F_net = √((28.8)² + (-14.4)²)

F_net = √1,036.8

F_net = 32.2 N

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Yes! The second one is one of the constant acceleration equations. We know that our X and Y values are independent of each other, which is why Y doesn't matter here. We only care about the X position value since X and Y are independent! (This is an extremely important rule, trust me)

Therefore, we don't need to calculate a Y velocity or anything like that. We only need Y because we need to find time t. We can use Y to calculate time because although X and Y are independent of each other, they do share the same time traveled!

We know that \(V_{0,y}\) = 0, since the car wasn't moving vertically initially. We also know Y initial is 100 and Y final is 0 when it hits the ground! The last thing we know is that the acceleration of any item in free fall is (usually) -9.81. Therefore, using the original Y equation that your teacher gave, we can plug things in and solve for time!

\(y_f=y_i+v_it+\frac{1}{2}at^2\\0=100+(0)t+\frac{1}{2}(-9.81)t^2\\-100=-4.905t^2\\t^2=20.39\\t=4.52\)t = 4.52s

(Your teacher simplified the Y equation a little, so it may look slightly different from mine. I started at the original Y equation)

Now we have time! So now we can use the other equation your teacher provided. Again, remember, even though the car is now traveling through the air vertically, that does not affect its x velocity! The car is still traveling at 50m/s!

Therefore, we can just plug and chug!:

x = vt

x = (50)(4.52)

x = 226m

I hope this helps!