In the game with Green-Bay the Bears lost the game with a touchdown of 40 m range. The hangtime of the ball was 3.2 sec.
a. what was the initial velocity of the ball?
b. what was the maximum height of the ball?
c. what was the final velocity of the ball ?
(physics)​

Answers

Answer 1

The projectile launch allows to find the results for questions about the movement are:

   a) The initial velocity is: vo = 20 m/s with an angle of θ = 51.4º

   b) The maximum height of the ball is:  y = 12.5 m

   c) The final velocity is: vo = 20 m/s with θ = 308.3º

The launch of projectiles is an application of kinematics where there is no acceleration on the x axis and the y axis is the gravity acceleration.

In the attachment we see a diagram of movement, the x-axis is horizontal and the y-axis is vertical.

They indicate that the range was x = 40 m and the ball was in the air t=3.2s.

a) Let's find the horizontal velocity, as there is no acceleration.

         x = v₀ₓ t

         v₀ₓ = \(\frac{x}{t}\)x / t

let's calculate

         v₀ₓ = \(\frac{40}{3.2}\)  

         v₀ₓ = 12.5 m / s

We look for the vertical speed, when the ball reaches the destination its height is zero.

          y = \(v_o_y\) t - ½ g t²

          0 = \(v_o_y\) t - ½ g t²

          0 = t ( \(v_o_y\) - ½ g t)

The solution to this equation is:

           t = 0 s         Exit time.

           \(v_o_y\) - ½ g t = 0

           \(v_o_y\)  = ½ g t

It indicates the time in the air that, because it is a scalar, is the same for the two movements.

Let's calculate

           \(v_o_y\)  = ½ 9.8 3.2

            \(v_o_y\)  = 15.68 m / s

We use the Pythagoras' theorem for the initial velocity modulus.

          v₀ = \(\sqrt{v_{ox}^2 + v_{oy}^2 }\)  

          v₀ = \(\sqrt{12.5^2 + 15.68^2}\)  

          v₀ = 20 m / s

We use trigonometry for the angle.

        tan θ = \(\frac{v_o_y}{v_o_x}\)  

        θ = tam⁻¹ \(\frac{v_o_y}{v_o_x}\)  

        θ = tan⁻¹  \(\frac{15.68}{12.5}\)  

        θ = 51.4º

b) For the maximum height the vertical speed is zero.

           \(v_y^2 = v_{oy}^2 -2g y\)  

           0 = \(0 = v_{oy}^2 -2 g y\)  

           y = \(\frac{v_{oy}^2}{2g}\)

Let's calculate

           y = \(\frac{15.68^2}{2 \ 9.8}\)

           y = 12.5 m

C) The final velocity of the ball.

Since the x-axis there is no acceleration, the velocity is constant.

          vₓ = 12.5 m / s

Let's find the final vertical speed.

         \(v_y = v_{oy} - g t\)

         \(v_y\) = 15.68 - 9.8 3.2

         \(v_y\) = - 15.68 m / s

We are looking for the module.

         v = vₓ² + \(v_y^2\)  

speed gives the same value.

         v = 20 m / s

We use trigonometry for the angle.

        θ'= tan⁻¹  \(\frac{-15.68}{12.5}\)

        θ' = -51.66º

This angle measured from the positive side of the x-axis counterclockwise is:

       θ = 360 - θ'

       θ = 360 - 51.66

       θ = 308.3º

In conclusion, using the launch of projectiles we can find the results for questions about the movement are:

   a) The initial velocity is: vo = 20 m / s with an angle of θ = 51.4º

   b) The maximum height of the ball is: y = 12.5 m

   c) The final velocity is: vo = 20 / s with θ= 308.3º

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In The Game With Green-Bay The Bears Lost The Game With A Touchdown Of 40 M Range. The Hangtime Of The

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Answers

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Vexp does not fit within the calculated error margin comparing to its theoretical value. The answer is H3 measurement is outside three times of the error margin, H6 measurement is outside three times of the error margin.

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Explanation:

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Answers

Explanation:

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Answer:

248 N

Explanation:

Weight= Gravity*mass

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Thank you

Determine the course of action that has the highest EMV for the accompanying tree diagram. (Round your answers to nearest whole number.) V3 60 90 30 40 50 20 60 1y -(45) 45 30 40 50 30 40 50 20 50 EV Alternative A 36.7 43.45 Alternative B Choose Alternative A

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The course of action that has the highest EMV for the accompanying tree diagram is action B.

What is the total EMV resulting in each action?

The total EMV resulting in each action is calculated by using the values given in the tree diagram as follows;

The total EMV resulting in action A is as follows;

EMV = 0 + 60 + 90 + 40 + 44 + 60

EMV = 294

The total EMV resulting in action B  is as follows;

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Thus, from the values obtained in the calculations above, we can conclude that the course of action that has the highest EMV for the accompanying tree diagram is action B.

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Determine the course of action that has the highest EMV for the accompanying tree diagram. (Round your

a ball rolls off a table, with an initial horizontal velocity of 0.75 meters per second. the table is 0.90 meters tall. how far from the base of the table does the ball hit?.

Answers

The ball hits the ground 1.18 meters away from the base of the table.

1. Determine the time it takes for the ball to fall from the table to the ground. Since the only force acting on the ball is gravity, we can use the equation h = (1/\(2)gt^2\), where h is the height, g is the acceleration due to gravity (approximately 9.8 \(m/s^2\)), and t is the time.

  Plugging in the values, we have 0.90 = (1/2)(9.\(8)t^2\). Solving for t, we get t ≈ 0.43 seconds.

2. Calculate the horizontal distance covered by the ball during the time it takes to fall. We can use the equation d = vt, where d is the distance, v is the initial horizontal velocity, and t is the time.

  Substituting the given values, we have d = (0.75 m/s)(0.43 s) ≈ 0.32 meters.

3. Finally, determine the horizontal distance from the base of the table where the ball hits the ground. This distance is equal to the horizontal distance covered by the ball plus the distance from the edge of the table to the base.

  If we assume the ball rolls off the table's edge without any horizontal displacement, then the total distance from the base would be 0.32 meters.

  However, if there is a horizontal displacement, we need more information to calculate the exact distance from the base of the table where the ball hits.

Therefore, without additional information regarding any horizontal displacement, we can conclude that the ball hits the ground approximately 1.18 meters away from the base of the table.

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A 3000 ww carbon dioxide laser emits an infrared laser beam with a wavelength of 10. 6 μmμm. how many photons are emitted per second?

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The answer is photons are emitted per second \(n=1.599 \times 10^{23}$\)

\(E=p x t......(i)\)

and also

\(E=\frac{n h c}{\lambda}.......(ii)\)

\(E=$ Energy$\\P=P_{\text {ower }}$$\\t=$ time\)

\($\begin{aligned} \frac{n h c}{\lambda} &=p t \\ n &=\frac{p_{\lambda t}}{h c} \end{aligned}$\)

\($n=\frac{3000 \times 10.6 \times 10^{-6} \times 1}{6.626 \times 10^{-3} \times 3 \times 10^{8}}$\)

\(n=1.599 \times 10^{23}$\) photons parsec

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Most of the greenhouse gas emissions from this industry are carbon dioxide \($\left(\mathrm{CO}_{2}\right)$\), although there are also minor emissions of nitrous oxide \($\left(\mathrm{N}_{2} \mathrm{O}\right)$\) and methane \($\left(\mathrm{CH}_{4}\right)$\). These gases are generated when fossil fuels like coal, oil, and natural gas are burned to create power.

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the moon's mass is ____?​

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Answer:

7.35..kg

Explanation:

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When a high operating kilovoltage is used, (low/high) subject contrast and (many shades of gray/areas of black and white) are seen on the dental image.
a. Low subject contrast; many shades of gray b. Low subject contrast; areas of black and white
c. High subject contrast; many shades of gray d. High subject contrast; areas of black and white

Answers

We can see here that when a high operating kilovoltage is used, a. Low subject contrast; many shades of gray.

What is dental image?

A dental image refers to a visual representation or picture of the teeth, gums, and surrounding structures in the oral cavity.

Dental images are typically captured using various imaging techniques and equipment to assist in the diagnosis, treatment planning, and monitoring of dental conditions.

A high kilovoltage setting produces an image with decreased or low contrast; the radiograph exhibits many shades of gray. This is because the higher energy x-rays are better able to penetrate tissue, resulting in less variation in the absorption of x-rays by different tissues.

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what is the difference between speed and velocity in physics

Answers

The primary difference between speed and velocity is that speed is a scalar quantity that describes how fast an object is moving, while velocity is a vector quantity that describes how fast an object is moving in a particular direction

Speed and velocity are two critical concepts in physics. They are used to describe the motion of an object. While both describe how fast an object is moving, there are some fundamental differences between the two. Let's explore these differences.

What is speed?

Speed is a scalar quantity that describes how quickly an object moves. It is measured in meters per second (m/s) or kilometers per hour (km/h).

Speed can be calculated using the following formula:

speed = distance ÷ time

For example,

if an object covers a distance of 150 meters in 10 seconds, its speed can be calculated as follows:

Speed = distance ÷ time= 150 meters ÷ 10 seconds= 15 meters per second (m/s)

What is velocity?

Velocity, on the other hand, is a vector quantity that describes how fast an object is moving in a particular direction. It is measured in meters per second (m/s) or kilometers per hour (km/h).

Velocity can be calculated using the following formula:

velocity = displacement ÷ time

For example, if an object travels a displacement of 150 meters in 10 seconds in a specific direction, its velocity can be calculated as follows:

Velocity = displacement ÷ time= 150 meters ÷ 10 seconds= 15 meters per second (m/s) in a specific direction.

In conclusion, the primary difference between speed and velocity is that speed is a scalar quantity that describes how fast an object is moving, while velocity is a vector quantity that describes how fast an object is moving in a particular direction.

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A ventilation fan with a moment of inertia of 0.034 kg×m2 has a net torque of 0.11 n×m applied to it. if it starts from rest, what kinetic energy will it have 8.0 s later?

Answers

kinetic energy 8.0 s later will be 11.35 joules

Given:

inertia,I=0.034kgm²

torque,τ=0.11nm

time,t=8.0s

To find:

kinetic energy,KE

we can find the kinetic energy by using

\(k = \frac{1}{2} iω {}^{2} \)

so firstly we will find ω by finding α

α=τ/I

α=0.11/0.34

=3.23

then we find ω

ω=α×t

=3.23×8

=25.84

\(k = \frac{1}{2}iω {}^{2} \)

k=1/2×0.34×(25.84)2

=1/2×22.70

k=11.35

so kinetic energy is 11.35 joules

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g say you tie a thick, dense rope to a thin, less dense string. if you send a single wave pulse through the string, will it be transmitted through to the rope/and or reflected back into the string? also, which orientation will any transmitted or reflected pulses have relative to the original pulse?

Answers

If you send a single wave pulse through the string, it will be transmitted through to the rope.

Let's consider a thin rope attached to a thick rope, with every rope held at opposite ends via people. And suppose that a pulse is introduced through the person conserving the top of the skinny rope. If that is the case, there will be an incident pulse visiting within the less dense medium toward the boundary with a more dense medium.

A part of the strength carried through the incident pulse is transmitted into the thick rope. The disturbance that keeps shifting to the right is called the transmitted pulse. A part of the energy carried via the incident pulse is reflected and returns toward the left giving up the thin rope. The disturbance that returns to the left after bouncing off the boundary is called the reflected pulse.

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Consider the sinusoidal wave Y(x, t) = sin[2r(0.2t - 4x)]. What are its period, frequency, angular frequency, wave number, wavelength and speed?

Answers

The period of the wave is 0.1 seconds, the frequency is 10 Hz, the angular frequency is 20π rad/s, the wave number is 4π rad/m, the wavelength is 0.5 m, and the speed of the wave is 2 m/s.

The general form of a sinusoidal wave is given by Y(x, t) = A * sin(kx - omega t + phi ), where A is the amplitude, k is the wave number, omega is the angular frequency, t is the time, x is the position, and phi is the phase constant.

Comparing this to the given wave Y(x, t) = sin[2π(0.2t - 4x)], we can extract the following values:

Period: The period T of a wave is the time it takes for one complete cycle. In this case, the coefficient of t in the argument of the sine function is 0.2, so the period is T = 1/0.2 = 0.1 seconds.

Frequency: The frequency f of a wave is the number of cycles per unit time. It is the reciprocal of the period, so f = 1/T = 1/0.1 = 10 Hz.

Angular Frequency: The angular frequency ω is the rate at which the phase of the wave changes with time. It is related to the frequency by omega= 2πf, so omega = 2π(10) = 20π rad/s.

Wave Number: The wave number k is the spatial frequency of the wave, which represents the number of cycles per unit distance. In this case, the coefficient of x in the argument of the sine function is -4, so the wave number is k = -4π rad/m.

Wavelength: The wavelength λ is the distance between two consecutive points in the wave that are in phase. It is related to the wave number by λ = 2π/k = 2π/(-4π) = 0.5 m.

Speed: The speed of a wave is the rate at which a point on the wave moves through space. It is given by the equation v = λf, where λ is the wavelength and f is the frequency. Substituting the values, we get v = (0.5)(10) = 5 m/s.

Therefore, the given sinusoidal wave has a period of 0.1 seconds, a frequency of 10 Hz, an angular frequency of 20π rad/s, a wave number of -4π rad/m, a wavelength of 0.5 m, and a speed of 5 m/s.

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A uniform rod with mass 6M and length 2L is rotating freely around an axis.
(1)
(2)
A) What is the angular velocity at position 1?
B) What is the velocity of the center of mass at position 2, given the angle theta relative to position 1?

Answers

(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.

(2) The velocity of the center of mass at position 2.

(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.

The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.

(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.

Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.

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Applying Newton's Laws
Thalia is drafting a plan to move a large, perfect sphere
concrete sculpture that is in front of her office building.
Describe the considerations Thalia would need to make if
she was drafting a plan to move the sculpture.

Answers

If Thalia is drafting a plan to move a large, perfect sphere concrete sculpture, she would need to consider the following factors:

Weight and size of the sculpture: The weight and size of the sculpture will determine the amount of force required to move it and the type of equipment needed to lift and transport it.
Friction: The amount of friction between the sculpture and the surface it is on will affect how easily it can be moved. Thalia will need to consider how to reduce friction, such as by using lubricants or by placing the sculpture on a smooth surface.
Center of mass: The location of the sculpture's center of mass will play a significant role in determining how the sculpture moves and how it can be balanced during transportation.
Inertia: The sculpture's inertia will make it resist any changes to its motion. Thalia will need to take this into account when planning how to start and stop the movement of the sculpture.

Answer:

Thalia would need to consider Newton's laws of motion, particularly the laws of inertia, force, and acceleration when planning the movement of the sculpture.

Explanation:

Law of Inertia: The law of inertia states that an object at rest will remain at rest, and an object in motion will continue to move in a straight line at a constant velocity, unless acted upon by an unbalanced force. In simpler terms, this law states that an object will remain in its current state of motion (whether it is at rest or moving) unless acted upon by a force. This law is the foundation of the principle of conservation of momentum.Law of Force: The law of force, also known as the second law of motion, states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to the object's mass. This law states that the greater the force applied to an object, the greater the acceleration of the object, and the greater the mass of the object, the smaller the acceleration. The mathematical representation of this law is F=ma, where F is the net force applied on an object, m is the mass of the object, and a is the acceleration of the object.Law of Acceleration: The law of acceleration, which is a consequence of the Law of force, states that the acceleration of an object is the rate of change of its velocity. In other words, acceleration is the change in the speed of an object over time. The mathematical representation of acceleration is a = Δv/Δt, where a is acceleration, Δv is the change in velocity and Δt is the change in time.

In summary, the law of Inertia describes the tendency of an object to maintain its current state of motion, the law of force is the relationship between net force, mass, and acceleration of an object, and the law of acceleration is the rate of change of velocity of an object over time.

Other answer:

Thalia would need to consider several factors when drafting a plan to move the large, perfect sphere concrete sculpture. Some of these considerations include:

Weight and size of the sculpture: Thalia would need to determine the weight and size of the sculpture in order to select the appropriate equipment and personnel for the job.Center of gravity: Thalia would need to determine the center of gravity of the sculpture in order to ensure that it is properly balanced and stable during transport.Friction: Thalia would need to consider the amount of friction between the sculpture and the surface it is resting on, as well as the amount of friction between the sculpture and any equipment used to move it, in order to ensure that the sculpture can be moved safely and efficiently.Force: Thalia would need to apply the appropriate amount of force to move the sculpture, taking into account the weight and size of the sculpture, as well as any friction that may be present.Newton's laws: Thalia would need to consider Newton's laws of motion, particularly the laws of inertia, force, and acceleration when planning the movement of the sculpture.

A coolie carries a load of 500 N to a distance of 100 m on a horizontal platform. The work done by him is
_____?

Answers

Explanation:

\(workdone = force \times distance \\ = 500 \times 100 \\ = 50000 \: J\)

A plant expansion is planned for City of Beaumont. The new design flow rate is 1.2 m³/s. A deep bed monomedia filter with a design loading rate of 575 m³/d. m² of filter is to be used. If each filter box is limited to 50 m² of surface area, how many filter boxes will be required? Check the design loading with one filter box out of service. Propose an alternative design if the design loading rate is exceeded with one filter box out of service.

Answers

One filter box will be required for the plant expansion, but an alternative design needs to be proposed if the design loading rate is exceeded with one filter box out of service.

To determine the number of filter boxes required, we need to calculate the total surface area required and divide it by the maximum surface area per filter box.

Calculate the total surface area required:

Total surface area = Design flow rate / Design loading rate

Total surface area = 1.2 m³/s × 24 × 3600 s / (575 m³/d × 1 d/24h)

Total surface area = 18.67 m²

Determine the number of filter boxes required:

Number of filter boxes = Total surface area / Maximum surface area per filter box

Number of filter boxes = 18.67 m² / 50 m²

Number of filter boxes = 0.37 (round up to the nearest whole number)

Number of filter boxes = 1 (since we cannot have a fraction of a filter box)

Therefore, one filter box will be required to meet the design loading rate.

To check the design loading with one filter box out of service, we need to recalculate the loading rate:

Calculate the new design loading rate:

New design loading rate = Design flow rate / (Number of filter boxes - 1)

New design loading rate = 1.2 m³/s / (1 - 1)

New design loading rate = Undefined

Since the new design loading rate is undefined when one filter box is out of service, an alternative design should be proposed to ensure that the design loading rate is not exceeded. This could involve increasing the number of filter boxes or redesigning the filtration system to accommodate the required flow rate.

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"When a 3.00-g sample of KCl was added to 3.00 × 10^2
g of water in a coffee cup calorimeter, the
temperature decreased by 1.05 °C. How much heat is involved in the dissolution of the KCl? What
assumptions did you make?"

Answers

The specific heat capacity of the water (4.184 J/g°C), and ΔT is the change in temperature (1.05°C). is 13.2 J.

What is specific heat?

Specific heat is the amount of heat required to raise the temperature of one gram of a material by one degree Celsius. It is usually measured in units of joules per gram per degree Celsius (J/g°C). The concept of specific heat is important in many areas of science, including thermodynamics and chemistry. It is used to calculate the amount of energy required to change the temperature of a given mass of a substance, and it is also used to calculate the thermal conductivity of a material.

The heat involved in the dissolution of KCl can be calculated using the following equation:
q = m x c x ΔT
where q is the heat, m is the mass of the KCl (3.00 g), c is the specific heat capacity of the water (4.184 J/g°C), and ΔT is the change in temperature (1.05°C).
Therefore, q = (3.00 g) x (4.184 J/g°C) x (1.05°C)
= 13.2 J.
The assumption made here is that the coffee cup calorimeter is perfectly insulated, so that all the heat gained or lost by the KCl is equal to the heat gained or lost by the water.

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Newton's Laws of Motion and Newton's Law of Gravity explain why?
a) the Earth moves around (orbits) the Sun.
b) the Moon moves around Earth
c) an apple from a tree falls down to ground (as opposed to "rising up into the sky")
d) all of the above

Answers

Answer:

D all of the above

Explanation:

This is because newtons laws of motion explains movement of a body due to a force applied while that of gravity explains motion of a body under gravity and this captures a, b, and c

All the given options are following the Newton's laws of motion and Newton's law of gravity separately. All of the above options are correct. Hence, option (d) is correct.  

The given problem is based upon the Newton's law of motion as well as Newton's law of gravity. So let us analyze each of the given cases as:

(a)

The Earth moves around the Sun : This statement follows the Newton's first law of motion, which says that an object will continue its state of motion, until any external force is being applied on the object. Since, Earth is offered with no net force. Therefore, Newton's law is applicable.

(b)

Moon movers around Earth: This statement also follows the above explanation for the Newton's first law. Which makes moon to revolve around the Earth on an account of no net force. Hence, it will continue its circular motion and hence Newton's law of motion is followed.

(c)

An apple falls from a tree: This statement is based on Newton's law of gravity, which says that every particle in the universe attracts other particles such that the force of attraction is directly proportional to the product of their masses and inversely proportional to square of distance between them. Since, Earth has more mass than apply, therefore Earth will attract the apple downwards.

Thus, we can conclude that all the given options are following the Newton's laws of motion and Newton's law of gravity separately. All of the above options are correct. Hence, option (d) is correct.  

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A copy machine uses a lens to make an image of a page in the physics textbook to print a copy. When the print is regular size, both the book and its image are 16.0 cm from the lens.
What is the focal length of this lens?
If the lens is moved so that it is 24 cm from the book, what is the distance to the new image?
This new image will be magnified, reduced, or the same size compared to the original book?
How do you know?

Answers

We can use the thin lens formula to find the focal length of the lens:

1/f = 1/di + 1/do

where f is the focal length, di is the distance from the lens to the image, and do is the distance from the lens to the object. Since both the object and image are 16.0 cm from the lens, we can substitute do = di = 16.0 cm and solve for f:

1/f = 1/16.0 + 1/16.0
1/f = 1/8.0
f = 8.0 cm

So the focal length of the lens is 8.0 cm.

If the lens is moved so that it is 24 cm from the book, we can use the same formula to find the new distance to the image:

1/f = 1/di + 1/do
1/8.0 = 1/di + 1/24.0
1/di = 1/8.0 - 1/24.0
1/di = 1/12.0
di = 12.0 cm

So the distance from the lens to the new image is 12.0 cm.

To determine whether the new image will be magnified, reduced, or the same size compared to the original book, we can use the magnification formula:

m = -di/do

where m is the magnification. Since the image is inverted, we include a negative sign. We already know that do = 24.0 cm and di = 12.0 cm, so we can substitute these values and solve for m:

m = -di/do
m = -12.0/24.0
m = -0.5

Since the magnification is negative, the image is inverted. And since the magnification is less than 1 in absolute value, the image is reduced compared to the original book.

Weight and mass are different because,

Weight and mass are different because,

Answers

Answer:

Explanation:

The answer is [C]

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