In one experiment, you measured the potential difference across a resistor as a capacitor discharged through it. You then plotted the natural logarithm of the voltage vs time (in seconds), and from the equation of the best fit line you measured the time constant of the RC circuit. If the equation of that line is ln open vertical bar V close vertical bar equals negative 0.027 t plus 2.5 , what is the time constant of the circuit?

The law of conservation of angular momentum is particularly relevant in astronomy because it helps us understand how celestial objects move and interact in the universe.

Angular momentum is the product of an object's rotational inertia and its rotational velocity. According to the law of conservation of angular momentum, the total angular momentum of a system remains constant unless acted upon by an external force.

One example of how the conservation of angular momentum is part of our understanding of astronomical phenomena is in the formation of planetary systems. As a cloud of gas and dust collapses under its own gravity to form a star, the conservation of angular momentum causes the cloud to spin faster and flatten into a disk. This disk of material eventually forms into planets orbiting the central star. Without the conservation of angular momentum, the planets would not be able to maintain their stable orbits and the formation of planetary systems would be drastically different.

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Answer:

no

Explanation:

because it cannot be represented by a sine or cosine curve.

Answer: D

Explanation: it seem right to me I really don't know if this right but I hope this helps

Answer:

Explanation:

1.5/30 = x/250

x = 12.5 m

Radius of the circular loop is 0.0091m.

Magnetic field is the area around a magnet where the magnetism influence is felt .

B =(μ)I/2r

μ= Magnetic permeability =4(π)*10^(-7)

I= current flowing through the loop

r= radius of the loop

=0.0091m

Thus, we can conclude that the radius of the loop is 0.0091m .

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Simpson will it take 112 / 17 km to drive 560 km on a perfectly straight highway.

You can replace this computation with d = rt, which stands for "distance equals rate times time." To calculate speed or rate, use the speed formula, s = d/t, which asserts that speed is equal to distance divided by time.

The difference between speed and velocity is the amount of distance an object covers in a given amount of time and in a certain direction. Speed is a scalar quantity while velocity is a vector.

We know that:

v = 85

d = 560

Substitute

v = 85

d = 560 into formula d = v x t  :

560 = 85t

Cross out the common factor: 112 / 17 km

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Answer:

10%

Explanation:

Efficiency = work done / energy used

e = (10 m × 100 N) / (10,000 J)

e = 0.1

The efficiency is 0.1, or 10%.

Answer:

Leave onions in cold water for about 15 minutes! Takes out the chemical reaction in the onion's defense system.

Explanation:

This is what people NEED to know for cooking... Lol :)

To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.

In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:

Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians

To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:

Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians

Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.

Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.

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Answer:

20 kg

Explanation:

The kinetic energy (KE) of an object is given by:

KE = (1/2) * m * v^2

Where m is the mass of the object, and v is its velocity.

We can rearrange this formula to solve for the mass:

m = 2 * KE / v^2

Plugging in the values given:

m = 2 * 1000 J / (10 m/s)^2

m = 20 kg

Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.

a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

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Answer:

Explanation:

The refractive index of liquid with respect to glass =  sin of Angle of incidence in glass / (sin of angle of refraction in liquid )

The refractive index of liquid with respect to glass = sin 40 / sin 55

refractive index of liquid / refractive index of glass = sin 40 / sin 55

refractive index of liquid / 1.60 = sin 40 / sin 55

refractive index of liquid = 1.6 x sin40 / sin 55

= 1.6 x .642 / .819

= 1.254 .  

The pressure at the upper level of a water flow into the house by means of pipe is 1081 kPa.

Calculate the cross-sectional area of the lower pipe:

A₁ = πr₁²

where:

A₁ = cross-sectional area of the lower pipe (m²)

π = mathematical constant (3.14)

r₁ = radius of the lower pipe (m)

A₁ = π(0.12 m)² = 0.0452 m²

Calculate the cross-sectional area of the upper pipe:

A₂ = πr₂²

where:

A₂ = cross-sectional area of the upper pipe (m²)

π = mathematical constant (3.14)

r₂ = radius of the upper pipe (m)

A₂ = π(0.06 m)² = 0.0113 m²

Calculate the flow rate per unit area:

q = Q/A

where:

q = flow rate per unit area (m³/s)

Q = flow rate (m³/s)

A = cross-sectional area (m²)

q = 6 m³/s / 0.0452 m² = 13.28 m²/s

Calculate the velocity of the water in the lower pipe:

v₁ = q/A₁

where:

v₁ = velocity of the water in the lower pipe (m/s)

q = flow rate per unit area (m³/s)

A₁ = cross-sectional area of the lower pipe (m²)

v₁ = 13.28 m²/s / 0.0452 m² = 29.3 m/s

Calculate the velocity of the water in the upper pipe:

v₂ = q/A₂

where:

v₂ = velocity of the water in the upper pipe (m/s)

q = flow rate per unit area (m³/s)

A₂ = cross-sectional area of the upper pipe (m²)

v₂ = 13.28 m²/s / 0.0113 m² = 117.0 m/s

Calculate the head loss:

hL = (v₁² - v2₂²) / 2g

where:

hL = head loss (m)

v₁ = velocity of the water in the lower pipe (m/s)

v₂ = velocity of the water in the upper pipe (m/s)

g = acceleration due to gravity (9.8 m/s²)

hL = (29.3 m/s)² - (117.0 m/s)² / 2(9.8 m/s²) = 23.2 m

Calculate the pressure at the upper level:

p₂ = p₁ + ρghL

where:

p₂ = pressure at the upper level (Pa)

p₁ = pressure at the lower level (Pa)

ρ = density of water (1000 kg/m³)

g = acceleration due to gravity (9.8 m/s²)

hL = head loss (m)

p₂ = 400 kPa + 1000 kg/m³(9.8 m/s²)(23.2 m) = 1081 kPa

Therefore, the pressure at the upper level is 1081 kPa.

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Answer:

mechanical energy.

Explanation:

When the body of the violin and the strings vibrate and make sound

Answer:

Deep ocean trenches, volcanoes, island arcs, submarine mountain ranges, and fault lines.

Explanation:

To apply the right-hand rule to torque issues, point your right hand in the direction of the position vector (r or d), then turn your fingers in the direction of the force, and your thumb in the direction of the torque.

Torque is the rotating counterpart of linear force in physics and mechanics. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect. It shows a force's capacity to cause a change in the rotational motion of the body.

It is to be noted that Rotational force or torque, as the name implies, guarantees that an item rotates. It, therefore, represents the force acting on the vehicle's drive shaft as it spins. Force (N), on the other hand, linearly accelerates things. The power of an engine is the product of force and the rate at which that force acts.

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If the current in a wire increases from 5A to 10A, the magnetic field generated will also be doubled.

Hi ! I will help you to discuss about "magnetic field around a conducting wire". A conducting wire that carried electric current can generate amount of magnetic fields. In a standard winding condition, the increase number of electric current will be proportional to the increase number of the generated magnetic field. In other condition, the increase in distance (between center of field with a point) will be inversly proportional to the increase in the generated magnetic field. So, the magnetic field that generated around a current-carrying wire can be expressed in the following equation.

\( \boxed{\sf{\bold{B = \frac{\mu_0 \cdot I}{2\pi \cdot d}}}}\)

With the following condition:

We can assume that:

We know that :

What was asked ?

Step by step :

\( \sf{B_1 : B_2} \)

\( \sf{\frac{\cancel{\mu_0} \cdot I_1}{\cancel{2\pi} \cdot d_1} : \frac{\cancel{\mu_0} \cdot I_2}{\cancel{2\pi} \cdot d_2}} \)

\( \sf{\frac{I_1}{d_1} : \frac{I_2}{d_2}} \)

\( \sf{\frac{I_1}{\cancel d} : \frac{I_2}{\cancel d}} \)

\( \sf{I_1 : I_2} \)

\( \boxed{\sf{\bold{1 : 2}}} \)

From the above comparison, we can see that the ratio of the magnetic field at a point will be the same as the ratio of the current flowing through the conducting wire is 1 : 2. So, The magnetic field generated will also be doubled.

Here is a draft of the worksheet for the three main plate boundary types:

Plate Boundary (Movement)      Convergent (Colliding)

Diagram

        ||

        ||

        ||

Lithosphere (Created or Destroyed)  

       Created

Geologic Process      Mountain building

Real World Example

        Himalayas (Along India-Eurasia plate boundary in Asia)

References        

APA reference for research      

Plate Boundary (Movement)        Divergent (Separating)

Diagram

          |||||

Lithosphere (Created or Destroyed)      

        Destroyed  

Geologic Process        

         Volcanic eruptions and rift valleys

Real World Example  

        Mid-Atlantic Ridge (Between North America and Europe plates)

References        

         APA reference          

Plate Boundary (Movement)     Transform (Sliding)

Diagram

          |||||||||

Lithosphere (Created or Destroyed)  

       Neither          

Geologic Process  

       Earthquakes

Real World Example        

         San Andreas Fault (California, USA along Pacific-North America plates)

References

          APA reference

24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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The correct statement about dwarf planet locations is :

Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt.

A dwarf planet is described as a small planetary-mass object that is in direct orbit of the Sun, smaller than any of the eight classical planets but still a world in its own.

There are as of now five formally grouped dwarf planets in our solar system and they include:

Ceres, Pluto, Haumea, Makemake and Eris.

Ceres location is that it is situated inside the asteroid belt between the orbits of Mars and Jupiter, while the other smaller person planets are situated in the external nearby planetary group in, or close to, the Kuiper belt.

Another six articles are in all likelihood predominate planets, yet are sitting tight for official grouping, and there might be upwards of 10,000 diminutive person planets in the solar system.

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Complete question:

Which statement about dwarf planet locations is correct?

Eris is found in the Kuiper Belt and Makemake, Haumea, Ceres, and Pluto are found in the asteroid belt.

Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt.

Ceres and Pluto are found in the Kuiper Belt and Makemake, Eris, and Haumea are found in the asteroid belt.

Haumea and Makemake are found in the asteroid belt and Pluto, Ceres, and Eris are found in the Kuiper Belt.

Answer:

4000J

Explanation:

Given parameters:

Force  = 400N

Distance  = 10m

Unknown:

Work done  = ?

Solution:

Work done is the force applied to move a body in a specific direction.

      Work done  = Force x distance

So;

    Work done = 400 x 10 = 4000J

Answer:

c

Explanation:

Answer:

I think it expands

Explanation:

Answer:

E. remain unchanged

Explanation:

Answer:

\(28\; \rm m \cdot s^{-1}\).

Explanation:

Apply the SUVAT equation \(\left(v^2 - u^2) = 2\, a \, x\), where:

Assume that going downwards corresponds to a positive displacement. For this question:

Solve this equation for \(v\):

\(\displaystyle v = \sqrt{2\, a\, x + u^2} = \sqrt{2\times 9.8 \times 40} = 28\; \rm m \cdot s^{-1}\).

In other words, the rock reached a velocity of \(28\; \rm m\cdot s^{-1}\) (downwards) right before it hits the ground.

Let \(v\) be the velocity (in \(\rm m \cdot s^{-1}\)) of this rock right before it hits the ground. Under the assumptions of this question, it would take a time of \(t = (v / 9.8)\) seconds for this rock to reach that velocity if it started from rest and accelerated at \(9.8\; \rm m \cdot s^{-2}\).

Note that under these assumptions, the acceleration of this rock is constant. Therefore, the average velocity of this rock would be exactly one-half the sum of the initial and final velocity. In other words, if \(u\) denotes the initial velocity of this rock, the average velocity of this rock during the fall would be:

\(\displaystyle \frac{u + v}{2}\).

On the other hand, \(u = 0\) because this stone is released from rest. Therefore, the average velocity of this rock during the fall would be exactly \((v / 2)\).

The displacement of an object over a period of time is equal to the length of that period times the average velocity over that period. For this rock, the length of this fall would be \(t = (v / 9.8)\), while the average velocity over that period would be \((v / 2)\). Therefore, the displacement (in meters) of the rock during the entire fall would be:

\(\displaystyle \left(\frac{v}{2}\right) \cdot \left(\frac{v}{9.8}\right) = \frac{v^2}{19.6}\).

That displacement should be equal to the change in the height of the rock, \(40\; \rm m\):

\(\displaystyle \frac{v^2}{19.6} = 40\).

Solve for \(v\):

\(v = 28\; \rm m \cdot s^{-1}\).

Once again, the speed of the rock would be \(28\;\rm m \cdot s^{-1}\) right before it hits the ground.

If the angular velocity id doubled, then the linear speed of the boy will be doubled.

As we know,

If a body is rotating in a circular path, it will have an angular as well as linear velocity.

The angular velocity is responsible for rotation and the linear velocity is responsible for changing the direction in a circular manner.

The angular velocity W is related to the linear velocity V as,

W = V/R

Let us say this is equation 1,

Where R is the radius of the merry go round,

Now if the angular velocity is doubled,

W' = V'/R

Let us say this is equation 2.

On dividing equation 1 and 2,

W/W' = V/V'

As we know, W' = 2W.

1/2 = V/V'

V' = 2V.

The linear velocity will increase by a factor of 2.

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The required  speed of the center of mass of the two-car system is 10 m/s.

Option(2) is corret.

The reason is simple. Velocity is the percentage of time an object moves along a path, and Velocity is the speed and direction of an object's movement.

The mathematical calculation of velocity is relatively simple, the average velocity of an object is calculated by dividing the distance traveled by the time it took the object to travel that distance. Velocity, on the other hand, is mathematically complex and can be calculated in different ways depending on what information is available about the object's motion. In its simplest form, the average velocity is calculated by dividing the change in position (Δr) by the change in time (Δt).

Let the mass of cars which is same is M,

Speed (V1) = 30 m/s

Speed (V2) = -10 m/s

Then,

Speed of center of mass = MV1 + MV2/2M

Speed of center of mass = M(30) + M(-10)/2M

Speed of center of mass = 30M - 10M/2M

Speed of center of mass = 20M/2m

Speed of center of mass = 10 m/s

Thus, Speed of center of mass is 10 m/s

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At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

Assuming that the two charges are of equal magnitude and opposite sign and that the distance between them is d, the electric field at the point indicated by the dot can be found using Coulomb's law:

\(E = kq/r^2\)

where k is Coulomb's constant (\(8.99 *10^9 N m^2/C^2\)), q is the magnitude of the charge, and r is the distance between the charges.

Since the charges are of equal magnitude, the net charge at the point indicated by the dot is zero, so we only need to consider the electric field due to one of the charges. Let's assume that we want to find the electric field due to the positive charge.

The distance between the positive charge and the point indicated by the dot is r = d/2. Therefore, the electric field at that point is:

\(E = kq/(d/2)^2 = 4kq/d^2\)

The direction of the electric field is radial, pointing away from the positive charge and toward the negative charge. At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

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Answer:

P = VI

Explanation:

the power is equal to the current × voltage

Answer:

P = V • I

Explanation:

Power = Voltage • Current