In NH3+H2O > NH4OH which is being oxidized and which is being reduced?​

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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The surface area of the carbon adsorbent is approximately 2.63 x 10³ square meters per gram.

To calculate nm and K from the given information, use the equation for the Langmuir isotherm:

q/n = 1/K (P/P₀) + 1/nm

​

where:

q = amount of gas adsorbed (mmol/g)

n = amount of gas adsorbed per unit mass of adsorbent (mmol/g)

K = equilibrium constant

P = pressure (kPa)

P0 = saturation pressure (kPa)

nm = maximum adsorption capacity (mmol/g)  

From the given data:

Gradient = 0.391 g mmol-1

Intercept = 0.168 kPa g mmol-1

Comparing this with the Langmuir isotherm equation, we can equate the gradient and intercept to the corresponding terms:

Gradient = 1/nm

Intercept = 1/K

Solving for nm and K:

nm = 1/Gradient = 1/0.391  mmol/g

K = 1/Intercept = 1/0.168  kPa g mmol-1

Now, to determine the surface area, use the equation:

Surface area = nm x Avogadro's number x area per molecule

Given:

N₂ occupies 1.62 x 10⁻¹⁹ m²/molecule

Surface area = nm x 6.022 x 10²³ x 1.62 x 10⁻¹⁹ m²/molecule

Substituting the value of nm:

Surface area = (1/0.391) mmol/g x 6.022 x 10²³ x 1.62 x 10⁻¹⁹ m²/molecule

To convert mmol to moles, divide by 1000.

Surface area = (1/0.391) mol/g x (1/1000) x 6.022 x 10²³ x 1.62 x 10⁻¹⁹m²/molecule

Surface area ≈ 2.63 x 10³ m²/g

Therefore, the surface area of the carbon adsorbent is approximately 2.63 x 10³ square meters per gram.

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The solubility of\(LaF_3\) in water is 3.04 x 10^-6 mol/L.

The solubility of \(LaF_3\) in water can be determined using the Ksp expression:

\(Ksp = [La^{3+}][F^-]^3\)

Where \([La^{3+}]\)and \([F^-]\) are the molar concentrations of the \(La^{3+}\) and \(F^-\) ions in the solution.

Since each \(LaF_3\) formula unit dissociates into one \(La^{3+}\) ion and three \(F^-\) ions, the molar solubility of \(LaF_3\) can be represented as x. Thus, the molar concentrations of \(La^{3+}\) and \(F^-\) ions in the solution can be written as x and 3x, respectively.

Substituting these values into the Ksp expression gives:

Ksp = x*(3x)^3 = 27x^4

Now, we can solve for x:

x = (Ksp/27)^(1/4)

= (2 x 10^-19 / 27)^(1/4)

= 3.04 x 10^-6 mol/L

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Answer:

The atomic number of sulfur is 16, which means a neutral sulfur atom has 16 protons and 16 electrons.

When sulfur gains two electrons to form a -2 charged anion, it now has 16 protons and 18 electrons (-2 charge means 2 more electrons than protons).

Therefore, there would be 18 electrons in a -2 charged anion of sulfur.

Answer:

Evaporation is a change of phase from liquid to gas explained as follows : When particles in the liquid phase are heated, they gain kinetic energy and move faster and further apart.

Answer:

c. product

i had the test

The period is equal to the number of shells present in an atom.

The group number is equal to the number of valence electrons.

A period in the periodic table is a row of chemical elements.

The horizontal rows (which Mendeleev called series) are called periods and the vertical columns, are groups.

Elements having similar outer electronic configurations in their atoms are arranged in vertical columns.

The period indicates the value of n for the outermost or valence shell. The period is equal to the number of shells present in an atom. To find a period, the no. of shells =no. of periods.

Example: Na- 2,8,1 - Three shells are there, so period no. is 3.

Calcium - 2,8,8,2 - Four shells are there, so period no. is 4.

To determine the group, we need to understand some rules:

1. If the element is in s block, then the group number is equal to the number of valence electrons.

Example: Mg(12) - 2,8,2

Group = no. of valence electrons = 2

2. If the element is in the p block, then the number of the group can be determined by the formula: (number of valence electrons + 10).for groups.

Example: S(16) - 2,8,6

Group = no. of valence electrons+ 10 = 6+ 10 = 16

3. If the element is in the d block, then the number of the group can be determined by the formula: number of electrons in(n−1)d subshell + (number of electrons in (n)s subshell).

Example: Fe(26):

\([Ar]3d^64s^2\)

Group = number of electrons in(n−1)d subshell + (number of electrons in (n)s subshell) = 6+2 = 8

4. If the element is in the f block, then the number of the group is always 3.  Example: Cerium (58) belongs to the 3rd group.

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Answer:613 grams

Explanation: Moles = \(\frac{Mass (G)}{Molar Mass (G/mol)}\)  

Li: 6.94 g/mol

O: 16 g/mol

H: 1.0078 g/mol

the sum of all equals the molar mass of LiOH

The molar Mass of LiOH is 23.95 g/mol

therefore   25.6 x\(\frac{23.95 g/mol}{1 g}\) = 613 g

Hope this helps!

The factor that  doesn’t change the resistance of a wire is pressure. option A.

Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.

The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.

Hence option A is correct.

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missing part;

The pressure

The length of the resistor.

The thickness of the resistor.

The temperature of the conductor.

Answer:

2

Explanation

It seems logical

Answer:

the answer is 373

Explanation:

K=°C + 273

K=100+273=373

The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.

Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.

The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.

Given the mass of the ¹⁹F = 18.9984 a.m.u.

The mass defect for the ¹⁹F can be calculated as:

Δm = \((M _n +M_p) - M_F\)

\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)

\(\triangle m =0.1588 \;a.m.u.\)

The binding energy for the fluorine can be calculated as:

E = Δmc²

E = 0.1588 × 931.5

E = 147.92 MeV

The binding energy per nucleon of ¹⁹F can be calculated as:

B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon

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The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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Explanation:

The nucleus of an atom is held together by the strong nuclear force that binds together protons and neutrons. Although the strong nuclear force is the strongest of the four fundamental forces, it acts only over very short - typically nuclear - distances. It binds together the protons and neutrons in the nucleus.

Answer Element

Explanation:

An element is a pure substance that cannot be separated into simpler substances by chemical or physical means.

Answer:

An Element

Explanation:

An Element is a pure substance that is made up of same kind of atoms and cannot be broken down into simpler forms by any known chemical means.

Join in tracks are designed with extra space to allow for friction in hot weather

Answer:

Joints in train tracks are designed with extra space to allow for expansion and contraction of the track material in hot weather.

There are certain kind of elements that are present in periodic table.

Any elements are harmful, some are radioactive, few are noble gases. Hence, N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺ are isoelectronic species.

Periodic Table: Periodic table is a table in which we find elements with properties like metals, nonmetals, metalloids and radioactive element arranges in increasing atomic number.

It helps to a scientist to know what the different types of elements are present in periodic table so that they will discover the new elements that are not being discovered yet.

Isoelectronic kind are elements or ions that have the same number of electrons. the ions N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺, all have same number of electrons that is 10 electrons.

Hence, N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺ are isoelectronic species.

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Answer:

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

The equilibrium constant (Kc) for the given reaction is approximately 16.448. The value of Kc indicates the relative concentrations of reactants and products at equilibrium. In this case, a Kc greater than 1 suggests that the products (H2 and P4) are favored at equilibrium, indicating that the forward reaction is more favorable.

To determine the equilibrium constant (Kc) for the given reaction:

4PH3(g) ↔ 6H2(g) + P4(g)

We can write the equilibrium constant expression based on the stoichiometric coefficients:

Kc = ([H2]^6 * [P4]) / ([PH3]^4)

Substituting the given equilibrium concentrations:

[PH3] = 0.250 M

[H2] = 0.580 M

[P4] = 0.750 M

We can plug in these values into the equilibrium constant expression:

Kc = ([0.580]^6 * [0.750]) / ([0.250]^4)

Kc = (0.0860128 * 0.750) / (0.00390625)

Kc = 16.448

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The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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Answer:

Mass = 0.32 g

Explanation:

Given data:

Mass of CH₄ = ?

Volume of CH₄ = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Temperature = 273 K

Pressure = 1 atm

Solution:

Volume of CH₄:

500 mL (500 mL× 1L/1000 mL= 0.5 L)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm× 0.5 L = n×0.0821 atm.L/ mol.K  × 273 K

0.5 atm.L = n×22.4 atm.L/ mol

n = 0.5 atm.L / 22.4 atm.L/ mol

n = 0.02 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.02 mol × 16 g/mol

Mass = 0.32 g

a. Titration Curve:

On the x-axis, label it as "Volume of HCl added (mL)"

On the y-axis, label it as "pH"

b. Equivalence Point:

The equivalence point is the point in the titration where the moles of acid (HCl) added are stoichiometrically equivalent to the moles of base (unknown base) present initially. In the given data, the equivalence point can be estimated to be around 25.0 mL of HCl added. This is where the pH drops dramatically from 7.88 to 5.28, indicating the neutralization of the base.

c. Calculation of Kb Value:

To determine the Kb value, we need to find the pOH at half-neutralization, where half the volume of the equivalent point has been reached. In this case, the half-neutralization volume is 12.5 mL (half of 25 mL).

From the data, we can observe that at 12.5 mL of HCl added, the pH is 9.26.

pOH = 14 - pH = 14 - 9.26 = 4.74

pOH = -log[OH-]

[OH-] = 10^(-pOH)

[OH-] = 10^(-4.74)

To find [OH-] in moles per liter (M), we need to convert mL to L.

[OH-] = 10^(-4.74) mol/L

Now, since we know that at the equivalence point, the concentration of the acid (HCl) is 0.10 M, we can use the stoichiometry of the reaction to determine the concentration of the base (unknown base).

From the balanced equation:

HCl + OH- → H2O + Cl-

1 mole of HCl reacts with 1 mole of OH-

0.10 M (HCl) = [OH-] M (unknown base)

Therefore, Kb = [OH-][unknown base] / [base]

Kb = (10^(-4.74) mol/L)(0.10 M) / (0.10 M - 10^(-4.74) M)

Simplify and calculate Kb.

c. Selection of Indicator:

Based on the given pKa ranges of the indicators, the indicator phenolphthalein (pKa range: 8.3 - 10.0) would be appropriate for this titration. The reason is that the pH at the equivalence point is expected to be around 7, which is well within the range of phenolphthalein's color change. Bromophenol Blue and Methyl Red have lower pKa values and would not be suitable for indicating the equivalence point in this particular titration.

d. Calculation of Molarity and % Ionization of the Weak Base Solution:

To calculate the molarity of the weak base solution, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

At the half-neutralization point, [A-] = [HA], and the pH is 9.26.

9.26 = pKa + log([A-]/[HA])

The pKa can be determined using the pOH at half-neutralization:

pKa = 14 - pOH = 14 - 4.74 = 9.26

9.26 = 9.26 + log([A-]/[HA])

log([A-]/[HA]) = 0

[A-]/[HA] = 10^0 = 1

Since [A-] = [HA], the concentration of the weak base (before titration) is equal to the concentration of its conjugate acid.

Therefore, the molarity of the weak base solution is 0.10 M.

To calculate the % ionization of the weak base, we can use the formula:

% Ionization = ([A-]/[HA]) × 100

% Ionization = (1/0.10) × 100

% Ionization = 1000%

Note: The % ionization may exceed 100% in cases where the concentration of the conjugate acid is very small compared to the concentration of the weak base.

The expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P\(r^4\))/(8ηl) ∆t.

To derive an expression for the volume of liquid flowing per unit time through a cylindrical tube, we can apply the principles of fluid mechanics, considering the pressure gradient, viscosity coefficient, and tube radius.

The volume flow rate (Q) is defined as the volume of fluid passing through a cross-sectional area per unit time. In this case, we will consider the flow through a cylindrical tube of radius r and length l.

The Hagen-Poiseuille equation describes the flow rate in terms of the pressure gradient (∆P), viscosity coefficient (η), and tube dimensions:

Q = (π∆P \(r^4\))/(8ηl)

where k = π/8 is a constant.

To derive the expression for the volume of liquid flowing per unit time (∆V/∆t), we need to multiply the flow rate (Q) by the time interval (∆t):

∆V/∆t = Q ∆t

= (π∆P \(r^4\))/(8ηl) ∆t

Now, if we assume a constant pressure difference (∆P) and substitute k = π/8, the expression becomes:

∆V/∆t = (k∆P \(r^4\))/(ηl) ∆t

Simplifying further:

∆V/∆t = (π∆P\(r^4\))/(8ηl) ∆t

So, the expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P \(r^4\))/(8ηl) ∆t.

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Answer:

A mixture of ethane and ethene occupies 40 litre at 1.00 atm and at 400 K.The mixture reacts completely with 130 g of O2 to produce CO2 and H2O . Assuming ...

Missing: 32 ‎Br2

The specific heat capacity of the given metal is 0.1234 J/g°C.

The specific heat capacity of a metal is the electricity required to elevate one kilogram (kg) of the cloth by one diploma Celsius (°C).

The specific heat capacity of a substance is the heating ability of a pattern of the substance divided by means of the mass of the pattern, also every so often called massic heat ability. precise warmth capability is a measure of the amount of heat power required to change the temperature of 1 kg of a material by 1 k.

q = m x C x DT

q = m x C x ( T f - T i )

q = amount of heat energy gained or lost by a substance

m = mass of the sample

C = heat capacity ( J oC⁻¹g⁻¹ or J K⁻¹ g⁻¹ )

T f = final temperature

T i = initial temperature

-q metal = q water

-(mCΔT) = mCΔT

-( mC (T f-T i ) =  mC( T f-T i )

- (240 g x C x (27°C-150°C) =  150g(4.18J/g°C ) × ( 27°C-21°C )

- ( 240g × C × -127 °C = 150 × 4.18 × 6°C

C =  150 × 4.18 × 6°C / 240g × -127 °

C = 3762 / 30480

C = 0.1234 J/g°C

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Yes, that statement is generally correct. A scientific law is a statement that describes a phenomenon or pattern in nature, often expressed mathematically, without attempting to explain why it occurs. A scientific theory, on the other hand, is a well-substantiated explanation for a set of phenomena, based on empirical evidence and scientific reasoning.

A scientific law summarizes what happens in a particular situation, often in the form of an equation or formula, whereas a scientific theory attempts to explain why it happens.

For example, the law of gravity describes the attraction between masses, but it does not explain why this attraction occurs. In contrast, the theory of general relativity attempts to explain the underlying principles of gravity, including its effects on the curvature of space-time.

It's worth noting that both scientific laws and scientific theories are based on empirical evidence, but they serve different purposes in scientific inquiry. Laws describe what happens in a particular situation, while theories attempt to explain why it happens.

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Answer:

3. d

4. c

5. i

6. h

7. a

8. g

9. j

10. b

11. e

12. f

Explanation:

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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