If the distance of a galaxy is 2,000 Mpc, how many years back into the past are we looking when we observe this galaxy

The mass of the egg = 0.23 kg

The force, F = 16 N

The acceleration, a = 68.6 m/s²

The relationship between the force (F), acceleration (a), and mass (m) is:

F = ma

Substitute F = 16, a = 68.6, and solve for m

16 = 68.6m

m = 16/68.6

m = 0.23 kg

Answer:

Negative 3

Explanation:

Bc scientific notation is the zeros either ahead or behind the actual numbers

Answer:

-3

Explanation:

Answer:

20.4375 seconds.

Explanation:

Wattage = Work / time

Work = f * d

F = mass * acceleration

mass = 5000 kg

acceleration = force of gravity

acceleration = 9.81

Force = 5000 * 9.81

Force = 49050 N

Work = F * d

d = 2.5

Work = 49050 * 2.5

Work = 122625 Joules

Wattage = Work / time

time = work / wattage

wattage = 6000 watts

time = 122625 / 6000

time = 20.4375 seconds.

The angular speed of the ride is 0.533π rad/s.

The speed of an object, which is a scalar quantity in everyday usage and kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time.

Given that, to complete one rotation the ride takes 3.75 sec.

The angle traversed in one revolution is 2π.

In physics, the rotational velocity or angular velocity also referred to as the angular frequency vector, is a pseudovector that illustrates how quickly an object's angular position or orientation changes over time.

The formula of angular speed is  ω = θ /t

Here  θ = 2π and  t = 3.75

The angular speed is

ω = 2π/3.75

ω = 0.533π rad/s

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This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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Answer:

decomposition reaction

Explanation:

decomposition reactions occurs when one substance breaks down, or decomposes, into two or more substances

The magnitude of car's displacement is 17.78 m.

Given that, distance travelled due north is 11.8 m

Distance travelled due east is 13.3 m

As it is said that the car travels north and then east, it forms the two sides of a right-angled triangle. The magnitude of third side is the magnitude of car's displacement.

From Pythagoras theorem, the expression for car's displacement can be written as,

AC² = AB² + BC²

where, AB and BC are the sides of the right triangle

AC is the displacement of the car

Making AC as subject, we have,

AC = √(AB² + BC²) = √(11.8² + 13.3²) = √(139.24 + 176.89) = 17.78 m

Thus, the magnitude of car's displacement is 17.78 m.

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Answer:43.6°

Explanation:

Refractive index=n=1.45

Critical angle=c

n=1/sinc

1.45=1/sinc

Cross multiply

1.45sinc=1

Divide both sides by 1.45

(1.45sinc)/1.45=1/1.45

sinc=0.6897

c=sin(inverse)(0.6897)

c=43.6°

Critical angle is 43.6°

A synostosis develops at the ends of the tibia and fibula to help hold them together. synostosis, or the fusion of separate bones, occurs at the ends of the tibia and fibula, during the fusion of the mandibular bones, and when the two maxillary bones unite to form the hard palate.

Among the given options, the examples that represent a bony joint or synostosis are:

A synostosis develops at the ends of the tibia and fibula to help hold them together.

An infant is born with right and left mandibular bones, but they soon fuse into a single bone.

When the two maxillary bones unite to form the anterior two-thirds of the hard palate, a synostosis develops.

A synostosis at the ends of the tibia and fibula refers to the fusion or joining of these two bones, resulting in a bony joint. This fusion provides stability and strength to the leg.

In the case of an infant being born with separate right and left mandibular bones, they eventually fuse together into a single bone. This fusion of the mandible represents a synostosis, forming the lower jaw bone.

The fusion of the two maxillary bones to form the anterior two-thirds of the hard palate is another example of a synostosis. The maxillary bones fuse during development to create a single, solid structure that forms the hard palate in the roof of the mouth.

In summary, synostosis, or the fusion of separate bones, occurs at the ends of the tibia and fibula, during the fusion of the mandibular bones, and when the two maxillary bones unite to form the hard palate.

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Answer:

No

Explanation:

walking requires friction because if friction did not exist we would slide around without stopping

Answer:

Infared light

Explanation:

We will have the following:

First, we remember that:

So:

So, the change in length of the rod is approximately 4.41 mm.

The current flowing through each wire is the experiment's independent variable because it is the one that the experimenter is actively manipulating and controlling.

The resistance is influenced by the wire's thickness, so the thicker the wire, the lower the resistance. Because less water can flow through a narrower pipe in a given length, there is more resistance in a narrower pipe.

Due to the alloy composition of nichrome wire, its resistance is quite high. Because of this, it generates a lot of heat when current flows through it, making it extremely hot to the touch.

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Entropy is a thermodynamic property that describes the degree of disorder or randomness of a system. It is often described as a measure of a system's lack of energy to do useful work.

2. An open system is one that can exchange matter and energy with the environment. A closed system is a system that can exchange energy, but not matter, with the environment.

3. To calculate the operating time of a machine at 5000 joules per 100 watts of power, you can use the following equation: time = work / power. Adding the values gives Time = 5000J / 100W = 50 seconds.

4. The minimum speed that a 10 kg cart must travel to reach the top of a 15 m hill can be calculated using conservation of energy. A cart's potential energy at the top of the hill is equal to its kinetic energy at the bottom of the hill. So we use the equation potential energy = kinetic energy mgh = 1/2 mv^2. where m is the mass of the cart, g is the gravitational acceleration, h is the height of the hill, and v is the velocity. . of cars on the hill. Solving for v, we get v = √(2gh) = √(2 * 9.81 m/s^2 * 15 m) = 17.2 m/s.

5. The work required to accelerate a 10.0 kg block from rest to 5.00 m/s in 5 seconds can be calculated by the equation: Work = (1/2)mv^2, where m is the mass of the block and v is terminal velocity. Entering a value gives work = (1/2) * 10.0 kg * (5.00 m/s)^2 = 125 J.

6. The percentage of energy that must be supplied to keep the car moving at a constant speed of 10 m/s with a force of 70 N can be calculated by the following equation: power = force x velocity. Entering a value gives Power = 70N * 10m/s = 700W.

7. The power produced when 30 joules of work is done in 3.0 seconds can be calculated using the equation: power = work/hour. Adding the values gives Power = 30J / 3.0s = 10W.

8. If a force of 20 N is applied to a 40 kg skater for 0.3 seconds, the magnitude of the impulse acting on the 40 kg skater can be calculated using the following equation: Impulse = force x time. Adding the values gives Impulse = 20 N * 0.3 s = 6 N-s.

9. The force required to lift a 300 N crate up a 1.5 m high shelf at a constant speed of 1.5 m/s for 3.0 seconds can be calculated using the following equation: force = work/hour. Work done equals change in potential energy, mgh = 300 N * 9.81 m/s^2 * 1.5 m = 4414.5 J. Adding the values gives Power = 4414.5J / 3.0s = 1472W.

10. For 55.0 kilograms diving exempted from diving platform:

-3.00 meters of dose: on = mgh = (55.0 kg) (9.81 mg) (9.81 m / s) (9.81 m / s) (3.00 m / s) (3 , 00 m) (3.00 m) = 1614.15 J

At the altitude of -1.00 meters, the potential energy is associated with sleep: pe = mgh = (55.0 kg) (9.81 mg) (9.81 m / s) (9.81 m / s) (1 , 00 m) (1.00 m) (1.00 m) = 539.45 J

-Korea Energy is at an altitude of 1.00 meters.

11. For pulses of 1.6 × 106 N-C, 1.6 × 106 N-C, for 5000 kg in the north:

-Pulse (p) = mass (m) x speed (v)

-Recondition, speed (V) = p / m = (1.6 × 106 n-s) / (5000 kg) = (5000 kg) = 320 m / s (debt)

12. In the case of Newton's net power, the weight of 5.0 kg is 5.0 kg.

-In impulse (j) sallishisonf j = fat = (20 n) (5.0 s) = 100 n-s

-The size of the pulse is the same as the change of the moment (δp), the mass of the object and the change of the object and ΔV. -pure form of the shape is stable, as it can use an athletic comparison, which accelerates the installation. Since F = ma, we can substitute this into the kinematic equation to get Δv = F/m * Δt = (20 N) / (5.0 kg) * (5.0 s) = 20 m/s.

Therefore, both the magnitude of the moment and the change in momentum are 100 N-s. For a person going up a 700 N elevator at an average speed of 2 meters per second for 8 seconds:

- The change in gravitational potential energy (ΔPE) of a person can be found using the equation ΔPE = mgh.

where m is the person's mass, g is the acceleration due to gravity, and h is the change in height.

As the elevator rises, the change in height is given by h = vt = (2m/s) * (8s) = 16m. - Therefore, the change in gravitational potential energy of a person is ΔPE = (700 N) * (9.81 m/s^2) * (16 m) = 108928.8 J.

13. Among the following cases, an orbiting satellite has the largest momentum because its momentum (p) is equal to its mass (m) and its velocity (v), and its mass is much greater than the other bodies mentioned, and its velocity it is much bigger because it orbits the Earth. Big.

14. A 1 kg object with the largest momentum of the objects below is moving with a speed of 220 m/s. This is because momentum is equal to mass times velocity.

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Answer:

a device for repeatedly generating static electricity by induction.

Explanation:

Answer:

A student becomes negatively charged because of the friction between his socks and the carpet. ... The electrons get rubbed and move towards the carpet so the carpets electrons move away and the student becomes negatively charged.

The same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.

Let us understand what these terms mean:

In statistical analysis, multicollinearity is the high correlation among predictors in a regression model. It is problematic because of its adverse effects on the model, including making it difficult to determine the effect of an independent variable, coefficients becoming insensitive to small changes in the model, and reducing the reliability of the model.

In regression analysis, independent predictors are those variables that contribute to the prediction of the dependent variable or outcome, and their inclusion in the model improves the accuracy of the prediction of the model.

In a regression model, it is an assumption that predictors are independent, which means that the predictors have little to no correlation with each other. If this assumption is violated, it is known as multicollinearity.

Therefore, the same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.

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The conversion from meters to astronomical units is done by dividing the average distance by 1. 5 × 10^11.

Just as different areas of human endeavor has different units, the unit of length in astronomy is astronomical units. The astronomical unit is defined as the distance between the center of the earth and the sun.

To  solve a problem using the equation for Kepler's third law, Enrico must convert the average distance of Mars from the Sun from meters into astronomical units. This is done by dividing the average distance by 1. 5 × 10^11.

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Please find attached photograph for your answer. Do comment whether it is useful or not.

choice 3 because the arrow has to be downward for as. and if the divers want to live, the vx has to be going right and not 0 or they would hit the rocks. I hope it's right!

Answer:

A kg of cotton is heavier.

Explanation:

Because in air, cotton gets upthrust that's why weighing machine gives less weight than its actually have.

for eg: If cotton has 800g weight, the machine shows a kg(1kg) when measure in air due to upthrust.

I hope this will be helpful for you.

Answer: Due to atmospheric pressure 1 Kg of Cotton is slightly heavier than 1 kg of Iron.

Explanation: According to me cotton will be more lighter as air is a fluid and Archimedes principal applies on it. As cotton occupies more volume it will feel more up thrust and more loss in weight. That cotton is more heavier .

So the best way to show this is with a diagram

As shown here, the sun's light is blocked by the moon. This prevents the Earth from getting the sun's light

So the correct answer is A

Answer:

The answer is A: Light from the sun is blocked from earths surface by the moon

Explanation:

hope this helps

According to  the given statement The force exerted by the string on the object is 2.7 N.

Any item travelling in a circular direction has a tangential velocity, which is its linear speed. On a turntable, a point in the centre moves less distance in a full rotation than a point near the outside edge.

Tangential velocity is determined by dividing the circle's circumference by the time required for one complete rotation: 2*pi*r/t. The formula V = w * r, where w (omega) is the angular velocity of the rotating object and r is the radius of the circle, also relates it to angular velocity.

m = 0.9 kg

r = 3m

v = 3m/s

Force (f) = mv2/r

Now ,putting values

force (f) = \(\frac{0.9 k g \times\left(3 \mathrm{~ms}^{-1}\right)^2}{3 \mathrm{~m}}\)

F = 2.7 N

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The inclination of a system refers to the angle between the plane of the system and the plane of the sky as seen from Earth. A system with greater amplitude will have larger variations in brightness and thus will be easier to observe.

The amplitude of a system depends on the geometry of the system and the angle at which it is viewed. For example, a system viewed edge-on (i.e. with an inclination of 90°) will have a larger amplitude than a system viewed face-on (i.e. with an inclination of 0°), because the edge-on view will show more of the system's structure and produce larger variations in brightness.

Therefore, if we assume that systems with greater amplitude are easier to observe, we would be more likely to observe a system with an inclination near 90° than one with an inclination near 0°. This is because an edge-on view would produce larger variations in brightness, making the system easier to detect and study. However, it is important to note that the inclination angle is just one factor affecting the detectability of a system, and other factors such as distance, size, and brightness also play a role.

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Answer:

d) 2Fr

Explanation:

We know that the work done in moving the charge from the right side to the left side in the k shell is W = ∫Fdr from r = +r to -r. F = force of attraction between nucleus and electron on k shell. F = qq'/4πε₀r² where q =charge on electron in k shell  -e and q' = charge on nucleus = +e. So, F = -e × +e/4πε₀r² = -e²/4πε₀r².

We now evaluate the integral from r = +r to -r

W = ∫Fdr

= ∫(-e²/4πε₀r²)dr

= -∫e²dr/4πε₀r²

= -e²/4πε₀∫dr/r²

= -e²/4πε₀ × -[1/r] from r = +r to -r

W = e²/4πε₀[1/-r - 1/+r] = e²/4πε₀[-2/r} = -2e²/4πε₀r.

Since F = -e²/4πε₀r², Fr = = -e²/4πε₀r² × r = = -e²/4πε₀r and 2Fr = -2e²/4πε₀r.

So W = -2e²/4πε₀r = 2Fr.

So, the amount of work done to bring an electron (q = −e) from right side of hydrogen nucleus to left side in the k shell is W = 2Fr

Given :

Our weight is 600 Newton on the earth.

To Find :

How far should you go from the center of the earth so that it will be 300 Newton​.

Solution :

Acceleration due to gravity at depth d is given by :

\(g' = g( 1 - \dfrac{d}{R_e})\)

At earth surface, mg = 600 N   ...1)

At depth d, mg' = 300 N            ...2)

Dividing 1) and 2), we get :

\(\dfrac{g}{g'} = \dfrac{600}{300}\\\\\dfrac{g}{g'} = 2\\\\g = 2g'\\\\g = 2\times g\times ( 1 - \dfrac{d}{R_e} )\\\\1 - \dfrac{d}{R_e} = \dfrac{1}{2} \\\\d = \dfrac{R_e}{2}\)

Therefore, we should go in the depth of distance half the radius of earth.

Answer:

h = 0.047 m

Explanation:

It is given that,

Radius of an air bubble is 0.0003 m

The surface tension of water is \(7\times 10^{-2}\ N/m\)

We need to find the depth at which an air bubble of radius 0.0003 m will  remain in equilibrium in water. Let it is given by h.

Pressure due to surface tension is given by :

\(P=\dfrac{2T}{R}\) .....(1)

T is surface tension

Also, pressure due to a height is given by :

\(P=\rho gh\)

So, equation (1) becomes :

\(\rho g h=\dfrac{2T}{R}\)

So,

\(h=\dfrac{2T}{\rho gR}\)          

\(h=\dfrac{2\times 7\times 10^{-2}}{10^3\times 9.8\times 0.0003}\\\\h=0.047\ m\)

So, the depth is 0.047 m.

The tangential speed of the tip of the bat is 2.2 m/sec.

Any item travelling in a circular direction has a tangential velocity, which is its linear speed. In one full round of a turntable, a point at the outside edge travels further than a point close to the center.

The formula for tangential velocity is given by-

\(V_{r}\) = rω

r = radius of the circular path (m)

ω = angular speed

According to the question;

The angular speed of bat is  2. 0 rad/s.

The length of the bat is equal to radius of circular path = 1.1 m.

Angular speed = angular displacement/time

ω = Ф/t

2 = Ф/t

(∵ Ф = s/r); s is the actual distance travelled.

2 = s/(r×t)

s/t = r×2

    = 1.1×2

s/t = 2.2

v = 2.2 (∵ s/t = v)

Therefore, the tangential speed of the tip of the bat is v = 2.2 m/sec.

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1.7×10^2 m

The student was 1.7×10^2 m far from the speaker.

The distance that sound waves travel is mostly influenced by the temperature and pressure of the ocean, even though sound travels through water at a far faster rate than it does through air.

The change in pressure that a sound wave causes when it is measured at a particular location is related to the amplitude of the wave. If the amplitude grows, the sound is heard as louder, and if it drops, it is heard as quieter.

The pace at which a wave moves has nothing to do with its amplitude. Waves A and B move forward at the same speed. Only changes in the characteristics of the medium a wave travels through can change its speed.

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To calculate the distance between the loudspeaker and the student, we can use the speed of sound in air, which is approximately 340 meters per second (m/s) at standard temperature and pressure (STP).

The formula to calculate distance is:

distance = speed x time

where distance is the distance between the loudspeaker and the student, speed is the speed of sound in air, and time is the delay that was observed between the time the sound wave left the loudspeaker and the time it reached the student.

distance = 340 m/s x 0.50 s

distance = 170 m

So, the distance between the loudspeaker and the student is 170 meters.

This answer corresponds to (2) 91.7 x 102m.

It's worth mentioning that sound speed can be affected by temperature, humidity, and atmospheric pressure which can cause slight variations from the standard 340 m/s at STP.

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