Hugh wrote the properties of physical and chemical weathering in the table shown.
Types of Weathering
Physical Weathering
Chemical Weathering
Temperature may break the rocks Can be caused by chemicals in water
Can be caused by snow and pressure Composition of rock remains same
Why is Hugh's table incorrect? (5 points)
a
Chemicals in water cause physical weathering.
b
ос
Temperature is unable to break rocks physically.
Chemical weathering changes the composition of rocks.
Physical weathering is unaffected by snow and pressure.
Od

Hugh Wrote The Properties Of Physical And Chemical Weathering In The Table Shown.Types Of WeatheringPhysical

Answers

Answer 1

Answer:

I am sure that the C one is correct

Answer 2

Answer:

how is this college level..im doing this in middle school..

Explanation:


Related Questions

Which phrase describes radiation?



transfer of heat by the actual movement of warmed matter



transfer of heat between two objects that are touching



the process in which energy is emitted by one object, transmitted through space, and absorbed by another



the process in which energy is released by molecules breaking apart

Answers

Answer:

The process in which energy is emitted by one object ,transmitted through .......

Answer:the process in which energy is emitted by one object, transmitted through space, and absorbed by another

Explanation: took the test

N2 + H2 -> NH3
How many moles of H2 gas are used to make 36.5 grams of NH3?

Answers

Explanation:

First, you need to balance the equation:

N2    +  3 H2   ====>    2  NH3

                  so three moles of H2   result in  2 moles of NH3

                               ratio of   3:2

How many moles of NH3 is 36.5 gm  ??

   Using periodic table NH3 mole weight = 14.007  + 3*1.008 =17.031 g/mole

     36.5 g / 17.031 g/mole = 2.14 moles  of NH3

Using the ratios above   3/2 = x / 2.14   shows x = 3.21 moles of H2 needed

Please help solve these chemistry questions!!!

Practice with percent composition.
1. What is the percent composition of Fe if 111.7 g of Fe is recovered from a 159.7 g sample of Fe2O3?




2. What is the percent composition of O if 12 g of O is recovered from a 38 g sample of Cr2O3?




3. Calculate the percent composition of KCl.





4. Calculate the percent composition of N2O5.





Practice with empirical formulas
5. What is the empirical formula for a compound that contains 0.0260 mol C, 0.0325 mol H, and 0.0065 mol O.



Practice with Molecular Formulas
6. Determine the molecular formula for a compound that has an empirical formula of NO2 and a molar mass of 138.015 g/mol.





7. Nicotine is 74.1% C, 8.6% H, and 17.3% N by mass. It’s molar mass is about 160 g/mol.
a. What is it’s empirical formula?




b. What is it’s molecular formula?

Answers

To find the percent composition of Fe in Fe2O3, we need to calculate the molar mass of Fe and the molar mass of Fe2O3. The molar mass of Fe is 55.85 g/mol, and the molar mass of Fe2O3 is 159.7 g/mol.
To calculate the percent composition of Fe:
(55.85 g/mol / 159.7 g/mol) × 100% = 34.9%

Therefore, the percent composition of Fe in Fe2O3 is 34.9%.

Similarly, to find the percent composition of O in Cr2O3, we need to calculate the molar mass of O and the molar mass of Cr2O3. The molar mass of O is 16.00 g/mol, and the molar mass of Cr2O3 is 152 g/mol.
To calculate the percent composition of O:
(16.00 g/mol / 152 g/mol) × 100% = 10.5%

Therefore, the percent composition of O in Cr2O3 is 10.5%.

The formula for potassium chloride (KCl) consists of one potassium atom (K) and one chlorine atom (Cl). To calculate the percent composition of KCl, we need to calculate the molar mass of KCl.
The molar mass of KCl is:
39.10 g/mol (molar mass of K) + 35.45 g/mol (molar mass of Cl) = 74.55 g/mol

To calculate the percent composition of K:
(39.10 g/mol / 74.55 g/mol) × 100% = 52.4%

To calculate the percent composition of Cl:
(35.45 g/mol / 74.55 g/mol) × 100% = 47.6%

Therefore, the percent composition of KCl is 52.4% K and 47.6% Cl.

The formula for dinitrogen pentoxide (N2O5) consists of two nitrogen atoms (N) and five oxygen atoms (O). To calculate the percent composition of N2O5, we need to calculate the molar mass of N2O5.
The molar mass of N2O5 is:
2 × (14.01 g/mol) (molar mass of N) + 5 × (16.00 g/mol) (molar mass of O) = 108.01 g/mol

To calculate the percent composition of N:
(2 × 14.01 g/mol / 108.01 g/mol) × 100% = 25.9%

To calculate the percent composition of O:
(5 × 16.00 g/mol / 108.01 g/mol) × 100% = 74.1%

Therefore, the percent composition of N2O5 is 25.9% N and 74.1% O.

To determine the empirical formula for a compound with given mole ratios, we need to divide each mole value by the smallest mole value to obtain the simplest whole number ratio.
Given:
0.0260 mol C
0.0325 mol H
0.0065 mol O

Dividing each mole value by 0.0065 (the smallest mole value), we get:
C: 0.0260 mol / 0.0065 mol = 4
H: 0.0325 mol / 0.0065 mol = 5
O: 0.0065 mol / 0.0065 mol

Which of the following species has the greatest
number of electrons?
1. Cl-
2.K
3. Ca2+
4. S
5. K+

Answers

Answer:

Cl-

Explanation:

Neutral (Cl) have 7 electron, but Cl- have 8 electron due to gain of 1 electron


Ceramics make excellent refractory materials. A material is said to be refractory if it:
1 has high refractive index
2 retains its strength at high temperatures
3 resists the flow of electric current 4 all of the mentioned

Answers

Answer:

Option 2 is the correct answer

Explanation:

Ceramics, which mainly consist of oxides, carbides and nitrides, can withstand very high temperatures; furnaces are generally lined with such ceramics.

3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm. The density of the metal is 5.30 g/cm3. Assume that 68% of the unit cell is occupied by Ba atoms. The molar mass of barium is 137.3 g/mol. Using this information, calculate Avogadro’s number. Show your calculation procedure that allows you to derive Avogadro’s number. Your answer must show six digits after the decimal point (i.e., 6.pppx1023) that is not necessarily the same as the known value. By showing your calculation-result down to six digits after the decimal point, you showcase that you did calculate the number, instead of simply adopting the known Avogadro’s number available in open resources.

Answers

Answer:

The Avogadro's  number is \(N_A = 6.02289 *10^{23}\)

Explanation:

From the question we are told that

   The edge length is  \(L = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100} = 5.02 * 10^{-10}\)

    The density of the metal is \(\rho = 5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3} * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3\)

     The molar mass of  Ba is  \(Z = 137.3 \ g/mol = \frac{137.3}{1000} = 0.1373 \ kg / mol\)

     

Generally the volume of a unit cell is  

       \(V = L^3\)

substituting value

        \(V = [5.02 *10^{-10}]^3\)

         \(V = 1.265*10^{-28}\ m^3\)  

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be  (BCC),

The volume of barium atom is  

        \(V_a = \frac{V}{2} * 0.68\)

substituting value

        \(V_a = \frac{ 1.265*10^{-28}}{2} * 0.68\)

        \(V_a = 4.301 *10^{-29} \ m^3\)

The Molar mass of barium is mathematically represented as

      \(Z = N_A V_a * \rho\)

Where \(N_A\) is the Avogadro's number

 So  

      \(N_A = \frac{ Z}{ V_a * \rho}\)

substituting value

     \(N_A = \frac{ 0.1373}{ 4.301*10^{-29} * 5.3*10^{3}}\)

     \(N_A = 6.02289 *10^{23}\)

Which type of molecule speeds up chemical reactions in living things?
A: Lipid
B: Nucleic acid
C: Protein
D: Water

Answers

Answer:

C. Protein

Explanation:

Enzymes are proteins that speed up reactions. Think of saliva and how it helps break down the food you eat.

Answer:

C! protein

Explanation:

True or False: Photosynthesis can take place under water.
True
False

Answers

Answer:

True

Explanation:

hope this helps mate

Depends on how far down you are taking. Some plants in the ocean floor don’t undergo photosynthesis because it requires light. They adapt to their surroundings and do other things. I would say false. Hope this helps!

7.0 x 10 -3 mol of I2 in 100.00ml of solution

Answers

To determine the concentration of the I2 solution, we need to calculate the molarity (M) using the given information. Molarity is defined as moles of solute per liter of solution.

Given:
- Moles of I2: 7.0 x 10^(-3) mol
- Volume of solution: 100.00 mL (which is equal to 0.1000 L)

Molarity (M) = Moles of solute / Volume of solution in liters

Molarity = (7.0 x 10^(-3) mol) / (0.1000 L)

Molarity = 0.070 M

Therefore, the concentration of the I2 solution is 0.070 M.

How many grams of H2SO4 will react 650.0 grams of NaOH?

Answers

Answer:

H2SO4 + 2NAOH➡NA2SO4+2H2O

H2SO4 = 1*2 +32+16*3= 98g

NAOH = (11+16+1)=28

Explanation:

To calculate the number of Mole = Mole *Molar Mass

To calculate for gram = Mole/ Molar Mass

20.5g NaoH/1 * 1 mole NaOH/28g NaoH = 0.73M NaoH

0.73M NaoH /1 * 1 M H2SO4 /2M NaoH = 0.37M H2SO4

0.37 M H2SO4 /1 * 98g H2SO4 /1M H2SO4 = 0.00367g H2SO4

:- 0.00367g of Sulphuric Acid will be needed to complete the reaction.

What is the best way to make 4-octanone? A. mix 3-octyne + 1. HB(R)2 / THF then 2. H2O2 B. mix 4-octyne + 1. HB(R)2 / THF then 2. H2O2 C. mix 3-octyne + H2SO4 / water / HgSO4 D. mix 4-octyne + H2SO4 / water / HgSO4 E. Both B and D would work F. Both A and C would work G. A-D all work

Answers

Answer:

E. Both B and D would work

Explanation:

One of the major synthetic routes to produce ketones from alkynes involve the reactions known as oxomercuration and hydroboration.

Oxomercuration involves reacting the alkyne substrate with mercuric sulphate and sulphuric acid followed by reaction with H^+ from water.

Hydroboration involves reaction of the alkyne substrate with a molecule of the sort HB(R)2 followed by addition of alkaline hydrogen peroxide.

In both cases the starting material should be the 4-octyne.

0.000 00010 L in scientific notation.

Answers

Answer:

1.0 x \(10^{-7}\)

Explanation:

simplify it down

All chemical reactions use reactants in a specific proportion or stoichiometry to regulate the amount of products produced. The __________ reactant is consumed completely during the reaction but some of the __________ reactant is left over.
a. limiting, excess
b. excess, limiting
c. proportional, ideal
d. chemical, stoichiometric

Answers

Answer: The answer is a. limiting, excess. I took the test.

Explanation:

3. Calculate the equilibrium constant ( Ke ) for the reaction below if the equilibrium mixture for the reaction was found o contain [ H₂S ] 0.25 M. [ H₂ ] = 1 M , and [ S₂ ] -0.2 M. 2H₂S ( g ) 2H₂ ( g ) + S2 ( g )

Answers

The equilibrium constant relates the concentrations of the products and reactants in the chemical equilibrium. To calculate it we can apply the following equation.

For the reaction: aA + bB ---> cC + dD

Equlibrium constant (Ke) will be:

\(K=\frac{\lbrack C\rbrack^c\times\lbrack D\rbrack^d}{\lbrack A\rbrack^a\times\lbrack B\rbrack^b}\)

The letters in square brackets refer to the concentration raised to the respective coefficient. Now we replace the known values:

\(\begin{gathered} K=\text{ }\frac{\lbrack H_2\rbrack^2\times\lbrack S_2\rbrack^1}{\lbrack H_2S\rbrack^2} \\ K=\frac{\lbrack1M\rbrack^2\times\lbrack0.2M\rbrack^1}{\lbrack0.25M\rbrack^2} \\ K=\frac{1M^2\times0.2M}{0.0625M^2} \\ K=3.2M \end{gathered}\)

So, the equilibrium constant (Ke) will be 3.2M

What is the binding energy for the nuclide 199F (atomic mass: 18.9984 amu) in MeV per nucleus?

Answers

The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.

What is binding energy?

Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.

The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.

Given the mass of the ¹⁹F = 18.9984 a.m.u.

The mass defect for the ¹⁹F can be calculated as:

Δm = \((M _n +M_p) - M_F\)

\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)

\(\triangle m =0.1588 \;a.m.u.\)

The binding energy for the fluorine can be calculated as:

E = Δmc²

E = 0.1588 × 931.5

E = 147.92 MeV

The binding energy per nucleon of ¹⁹F can be calculated as:

B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon

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The precipitate formed when Ni(NO3)2 is mixed with Li2S is

Answers

Answer:

Nickel sulfide and Lithium nitrate are formed when Ni(NO3)2 is mixed with Li2S is.

Please mark me as brainliest

How many kilojoules of heat are needed to raise the temperature of 10g of aluminum from 22 degrees C to 55 degrees C, if the specific heat of aluminum is .901 j/gc?

Answers

Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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A solution of aluminum chloride has a pH of (4.5x10^0). What is the [H3O*(aq)], in mol/L?
Note: Your answer is assumed to be reduced to the highest power possible.

Answers

The concentration of H3O+ ions in the solution of aluminum chloride is \(3.16×10^-5\) mol/L.

Aluminum chloride is an acidic salt that contains a cation, Al3+, and an anion, Cl-. When aluminum chloride is dissolved in water, it dissociates into its constituent ions, and the Al3+ cations hydrolyze to produce H+ ions.

This reaction leads to the formation of an acidic solution. The pH of a solution of aluminum chloride is \(4.5×10^0\). We need to determine the concentration of H3O+ ions in this solution.

The concentration of H3O+ ions in a solution is given by the equation: pH = -log[H3O+] where pH is the negative logarithm of the concentration of H3O+ ions in the solution. The negative sign indicates that the pH is inversely proportional to the concentration of H3O+ ions. To determine the concentration of H3O+ ions, we need to rearrange the equation:

[H3O+] = \(10^-pH\) Substituting the value of pH =\(4.5×10^0\), we get: [H3O+] = \(10^-4.5\)

The value of \(10^-4.5\) can be calculated using scientific notation: \(10^-4.5\)= \(3.16×10^-5\) mol/L

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Topic 2: The Concepts
3. In ionic equations, mass and charge must be balanced on both sides to form a
proper reaction. Why is this the case? If you have a combination of solutions that
forms a precipitate, what factor determines the amount of precipitate that will
form? (Hint: If you have more of one ion than another as the precipitate is
forming, what will happen?)

Answers

The mass and charge must be balanced so that the compound formed is neutral. The limiting reactant determines the amount of the precipitate that can be formed.

What is ionic equation?

When we talk about an ionic equation, we are talking about the kind of equation that is able to show the ions that are able to undergo a change in a given reaction. We know that in many cases the ionic reaction would lead to the formation of a precipitate and this is the solid product that is obtained when we happen to mix two solutions that are known to be aqueous solutions.

Having made all that introduction, we know that a compound is said to be neutral when the charges in the species that form the compound could be seen as being balanced. This is the reason why the mass and charge must be balanced when we are dealing with an ionic reaction equation.

The factor that determines the amount of precipitate that would form is the limiting reactant of the process.

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What Celsius temperature, T2 , is required to change the volume of the gas sample in Part A ( T1 = 19 ∘C , V1 = 1940 L ) to a volume of 3880 L ? Assume no change in pressure or the amount of gas in the balloon. Express your answer with the appropriate units.

Answers

T2 has a temperature of 58.6 °C in Celsius.

The International System of Units (SI) has two temperature scales: the Kelvin scale and the Celsius scale.In the Celsius scale, which was formerly known as the centigrade scale outside of Sweden, the degree Celsius is the unit of measurement for temperature. The ideal gas law, which asserts that PV = nRT, describes how a gas's temperature, pressure, and volume are related to one another.

Since the pressure and amount of gas in the balloon are assumed to be constant, we can rearrange the equation to solve for the temperature:

\(T2 = \frac{(PV1)}{(nRV2) }\)

\(T2 =\frac{ (1 atm)(1940 L)}{(1 mol)(8.314 J/mol .K)(3880 L) }\)

T2 = 58.6 ∘C

Therefore,The Celsius temperature, T2 is 58.6°C

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Which of the following is not an example of an inexhaustible resource?
1.) Wind power
2.) Wave and tidal power
3.) Solar energy
4.) Biomass

Answers

Solar energy because solar take more resources then all the options that are on the question Answer is 3

Answer:

I would say 4.) Biomass

Explanation:

This looks like the best possible answer because it is plant based. Worst case scenario we could run out of plants. In comparison, wind will pretty much always be around along with wave/tidal power and solar.

Determine if a homogeneous solution forms when each pair of substances is mixed Check all that apply . CCL 4 H 2 O Br 2 and CCl 4 CH 3 CH 2 OH and H 2 O

Answers

Answer:

Explanation:

bc

4. One molecule of propanol contains a total of
flonsoona
(1) one -OH group
(2) two -CH3 groups
(3) three -OH groups
(4) three -CH3 groups

Answers

One molecule of propanol contains only one -OH group and not three -OH groups or three -CH3 groups.

The -OH group is attached to the central carbon atom and makes propanol a useful solvent and intermediate in organic chemistry.Propanol is a colorless liquid that belongs to the family of alcohols. It has the formula C3H8O, and it contains three carbon atoms, eight hydrogen atoms, and one hydroxyl group (-OH) attached to one of the carbons. One molecule of propanol contains only one -OH group, which is attached to the central carbon atom.

Thus, option (2) is the correct answer, and the other options are incorrect.The -OH group in propanol is responsible for its unique chemical and physical properties. It makes propanol soluble in water and other polar solvents and gives it a high boiling point of around 97°C. The hydroxyl group can also participate in chemical reactions, such as esterification, dehydration, oxidation, and reduction. For example, propanol can be oxidized to form propanal and then propanoic acid, which is a useful synthetic intermediate for many organic compounds.Apart from the -OH group, propanol also contains two other functional groups called methyl groups (-CH3). These are attached to the two carbon atoms adjacent to the central carbon. However, the question only asks about the number of -OH groups in propanol, so the methyl groups are irrelevant.
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To what temperature should you heat a sample of air initially at 315K to increase its volume by 25% ?

Answers

The sample of air should be heated to 252 Kelvin (K) to increase its volume by 25%.

It is possible to determine the temperature to which the sample of air should be heated by using the concept of the ideal gas law. PV = nRT is the ideal gas law, and it relates the pressure (P), volume (V), number of moles (n), temperature (T), and gas constant (R). we can focus on the relationship between volume and temperature since the number of moles and pressure are assumed to be constant.

By showing the increase in volume as a percentage (25%), we can make the equation (V+0.25V)/T = V/T, where V represents the initial volume of the air.

On making the equation simple, we find  Tfinal / Tinitial = 1.25.

To solve for Tfianal, the final temperature,

Tfinal = Tinitail / 1.25

On substituting the initial temperature value of 315K into the equation, we will be getting;

Tfinal = 315K / 1.25

Tfinal = 252K

Hence, the sample of air should be heated to 252 Kelvin (K) in order to increase its volume by 25%.

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A neutral atom has 12 protons and 13 neutrons in its nucleus. What is its mass number?

Answers

Answer: 68

Explanation: u times them

suppose you measure the absorbance of a yellow dye solution in a 1.00 cm cuvette. The absorbance of the solution at 427 nm is 0.20. If the molar absorptivity of yellow dye at 427 nm is 27400 M-1cm-1, what is the concentration of the solution?

Answers

The concentration of the solution is obtained as 7.3 * 10^-6 M.

What is the Beer Lamberts law?

We know that one of the ways by which we are able to obtain the concentration of substances especially those that are colored is by the use of spectrophotometry. In a spectrophotometer, there is a wavelength of maximum absorption that could be used to measure the concentration of the solution as we can see in the question.

By the use of the Beer Lambert's law we have;

A = εcl

A = Absorption

ε = molar absorptivity

c = concentration

l = path length

Thus we would have;

0.2 = 27400 M-1cm-1 * c * 1.00 cm

c = 0.2/27400 M-1cm-1 *  1.00 cm

c = 7.3 * 10^-6 M

We would have from the calculation that we have a solution whose concentration is 7.3 * 10^-6 M.

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Which part of the brain is affected by a smell, a song, or a photograph?
A. the primitive brain
B. the right brain
C. the outer brain
D. the emotional brain

Answers

The right brain part of the brain is affected by a smell, a song, or a photograph.

What is Right Brain?

The right brain is more intuitive and visually oriented. It is occasionally referred to as the analog brain. It thinks less logically and with more creativity. According to out-of-date research by Sperry, the right brain aids in creativity.

Which part of brain deals with photograph?

Posterior parietal cortex of the parietal lobe of the brain mainly deals with the photographs.

Which part of brain deals with Smell?

The olfactory bulb, a structure in the front of the brain, processes smells before sending data to other regions of the body's central nervous system.

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The right brain part of the brain is affected by a smell, a song, or a photograph.

What is Right Brain?

The right brain is more intuitive and visually oriented. It is occasionally referred to as the analog brain. It thinks less logically and with more creativity. According to out-of-date research by Sperry, the right brain aids in creativity.

Which part of brain deals with photograph?

Posterior parietal cortex of the parietal lobe of the brain mainly deals with the photographs.

Which part of brain deals with Smell?

The olfactory bulb, a structure in the front of the brain, processes smells before sending data to other regions of the body's central nervous system.

Similar to For Practice 14.8) Determine the freezing point of an aqueous solution that contains 0.867 m glycerin (CHgOz).
Ki(water) = 1.86°C/m and Kg(water) - 0.512°C/m. Freezing point of water = 0.0 °C.

Similar to For Practice 14.3) Find the mass (in grams) of glucose (CH1206) in 505 mL of 10.5% glucose solution by mass. Assume the density of the solution is 1.04g/mL

Similar to For Practice 14.8) Determine the freezing point of an aqueous solution that contains 0.867

Answers

The freezing point of the solution containing 0.867 m glycerin is -1.61442 °C. Option C is correct

The mass of glucose in 505 mL of 10.5% glucose solution is 53.01 g or 5.30 x 10^2 g.

Option C is correct

To find the freezing point depression of the solution containing 0.867 m glycerin:

ΔTf = Kf * molality

ΔTf = (1.86°C/m) * 0.867 m

ΔTf = 1.61442 °C

The freezing point depression is 1.61442 °C.

The freezing point of the solution is:

Freezing point = 0.0 °C - ΔTf

Freezing point = 0.0 °C - 1.61442 °C

Freezing point = -1.61442 °C

To find the mass of glucose in 505 mL of 10.5% glucose solution:

Mass of glucose = Volume of solution * Density of solution * % mass

Mass of glucose = 505 mL * 1.04 g/mL * 10.5%

Mass of glucose = 53.01 g

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HELPP ASAP I WILL MARK BRAINIST


HELPP ASAP I WILL MARK BRAINIST

Answers

Answer:

I'm thinking ethier D or A

Explanation:

How many moles of CH3CH2Cl are contained in 250 mL of 0.0666 M CH3CH2Cl solution?

How many moles of CH3CH2Cl are contained in 250 mL of 0.0666 M CH3CH2Cl solution?

Answers

We can find the number of moles using the molarity formula:

\(\text{Molarity}=\frac{moles}{volume\text{ (liters)}}.\)

We have to convert 250 mL to L. Remember that 1 liter equals 1000 mL:

\(250\text{ mL}\cdot\frac{1\text{ L}}{1000\text{ mL}}=0.25\text{ L.}\)

Now, that we have the value of volume in liters (0.25 L) and the molarity (0.0666 M (mol/L) ), we can clear in the formula for moles and replace the given values:

\(\begin{gathered} \text{moles}=\text{Molarity}\cdot\text{volume,} \\ \text{moles}=0.0666\frac{mol}{L}\cdot0.25L, \\ \text{moles}=0.0166\text{ moles=1.66}\cdot10^{-2}moles. \end{gathered}\)

The answer is that we have 1.66 x 10^(-2) moles in 0.25 L of 0.0666 M of CH3CH2Cl.

Other Questions
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