How much energy would be saved by adding insulation to ceilings?.

Answers

Answer 1

The amount of energy saved by adding insulation to ceilings depends on several factors such as the climate, size of the house, type of heating and cooling system, and the R-value of the insulation used.

The R-value is a measure of the insulation's ability to resist heat flow. The higher the R-value, the greater the insulation's effectiveness. The US Department of Energy recommends an R-value of at least R-38 for attic insulation in most parts of the United States. According to the Department of Energy, heating and cooling account for 50-70% of the energy used in the average American home. Therefore, by adding insulation to your home's ceiling, you can reduce the amount of energy used for heating and cooling, which translates to lower energy bills and less environmental impact.

In conclusion, adding insulation to ceilings can save a significant amount of energy and reduce heating and cooling costs. The amount of energy saved depends on various factors, such as the R-value of the insulation, climate, and size of the house.

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Related Questions

Using Newton's 2nd law,find the mass if the force is 18 N and the acceleration is 2 m/s/s.

Answers

Answer:

9 kg

Explanation:

According to Newton's second law:

\(f = ma\)

\(m = \frac{f}{a} \)

Given:

f = 18 N

a = 2 m/s^2

Substitute the given values in the formula.

\(m = \frac{18}{2} \)

\(m = 9\)

A modern led light bulb that emits as much visible light as a 75.0-w incandescent only draws 9.50 w of power. how much does it cost to operate this bulb for 24 hours?

Answers

To calculate the cost of operating the LED light bulb for 24 hours, we need to know the cost of electricity per kilowatt-hour (kWh) in your area. The cost of electricity is typically measured in kilowatt-hours, so we need to convert the power consumed by the bulb from watts to kilowatts.

Given that the LED light bulb consumes 9.50 watts of power, we divide this value by 1000 to convert it to kilowatts,Now, we can calculate the energy consumed by the bulb over 24 hours,Energy consumed (in kilowatt-hours) = Power (in kilowatts) * Time (in hours) = 0.00950 kW * 24 hours.Next, we multiply the energy consumed by the cost of electricity per kilowatt-hour to obtain the cost of operating the bulb for 24 hours Cost = Energy consumed (in kilowatt-hours) * Cost of electricity (per kilowatt-hour).Please provide the cost of electricity per kilowatt-hour in your area to determine the exact cost of operating the bulb for 24 hours.

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Explain the main function of components of blood.

Answers

responsible for carrying oxygen and carbon dioxide...

A 2-kg mass placed 30-cm to the left of the fulcrum is balanced by a 2-kg mass placed ______ cm to the right of the fulcrum.

Answers

Answer:

30 cm

Explanation:

0.06 or  \(\frac{1}{15}\)

What is the effort and load arm?

The lever has two “arms”:

The load arm is the portion of the lever directly connected to the load.

The effort arm is the portion of the lever to which we apply the effort, or input force.

The formula of the mechanical advantage(MA) of a lever is given as

MA = load/effort.

Given,

load = 2kg , effort = 30cm

MA = \(\frac{2}{30}\) = \(\frac{1}{15}\)

MA  = 0.06 cm

Therefore,

A 2-kg mass placed 30-cm to the left of the fulcrum is balanced by a 2-kg mass placed  0.06 cm to the right of the fulcrum.

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What are the three longest wavelengths for standing soundwaves in a 122-cm-long tube under the following conditions.
a)The tube is open at both ends.
Enter your answers in descendingorder separated by commas. (answer in m)
b)
The tube is open at one end, closed at theother?

Answers

a) The three longest wavelengths for standing soundwaves in a 122-cm-long tube that is open at both ends are 2.44 m, 1.22 m,0.813 m.

b) The three longest wavelengths for a tube that is open at one end and closed at the other are 4.88 m, 2.44 m, 1.627 m.

Longest wavelengths in 122-cm tube?

To determine the three longest wavelengths for standing soundwaves in a 122-cm-long tube that is open at both ends, we can use the formula:

λ = 2L/n

where λ is the wavelength, L is the length of the tube, and n is the harmonic number.

By substituting the values, we can calculate the wavelengths:

λ1 = 2(122 cm)/1 = 244 cm  = 2.44 m

λ2 = 2(122 cm)/2 = 122 cm = 1.22 m,

λ3 = 2(122 cm)/3 ≈ 81.3 cm = 0.813 m.

Therefore, the three longest wavelengths in descending order are 2.44m, 1.22 m, 0.813m.

Longest wavelengths in closed-open tube?

To determine the three longest wavelengths for a tube that is open at one end and closed at the other, we use the formula:

λ = 4L/n

Following the same process, we can calculate the wavelengths:

λ1 = 4(122 cm)/1 = 488 cm=4.88m

λ2 = 4(122 cm)/2 = 244 cm=2.44m

λ3 = 4(122 cm)/3 ≈ 162.7 cm=1.627m

Therefore, the three longest wavelengths in descending order are 4.88m, 2.44 m, 1.627 m.

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if a beam of radiation containing 1000 x-rays is spread out over a square field that measures 10 inches long and 10 inches wide, what is the concentration of x-rays per square inch?

Answers

By dividing the quantity of x-rays by the total field area, it is possible to determine the concentration of x-rays per square inch. As a result, there are 10 x-rays per square inch when 1000 x-rays are divided by 100 square inches.

High energy, short wavelength electromagnetic radiation is what X-rays are. Since their discovery in 1895 by Wilhelm Conrad Roentgen, they have been applied in numerous fields, such as cancer treatment and medical imaging. X-rays are used in medical imaging to create images of the internal anatomy of the body, including the bones and organs, to aid in the diagnosis of illnesses and injuries. X-rays are used to cure cancer by destroying cancerous cells and reducing tumour size. X-rays can also penetrate a wide range of materials, which makes them valuable in a number of other industries like industrial inspection and security scanning. However, prolonged exposure to X-rays can be hazardous, cause tissue damage, and raise the risk of developing cancer.

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You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
What is the time it takes?
What is the displacement of your car?
What is the acceleration of your car?
Write the equation you will use to solve the problem.
What was your initial velocity?

Answers

Answer:200 5 -20 = v=323

Explanation:

Neutrons traveling at 0.400 m/s are directed through a pair of slits separated by 1.00 mm . An array of detectors is placed 10.0m from the slits.

(c) When a neutron reaches a detector, can we say which slit the neutron passed through? Explain.

Answers

When a neutron is directed through a pair of slits separated by 1.00 mm and reaches a detector 10.0m away, we cannot definitively say which slit the neutron passed through. This is because of a phenomenon called wave-particle duality.

Neutrons, like other particles, can exhibit both wave-like and particle-like behaviors.
When a single neutron passes through the slits, it undergoes diffraction, which causes it to spread out and interfere with itself. This interference pattern is observed on the detector screen. The pattern arises due to the superposition of waves from both slits.
If we could determine which slit the neutron passed through, the interference pattern would not be observed. However, any attempt to determine the slit would disturb the neutron's path, causing it to behave more like a particle and destroying the interference pattern.
In conclusion, due to the wave-particle duality nature of neutrons, when a neutron reaches a detector after passing through a pair of slits, we cannot determine which slit it passed through because doing so would disrupt the interference pattern. This experiment highlights the fascinating behavior of particles at the quantum level.

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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?

Answers

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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As of 2018, how many space probes had flown past Uranus closely enough to take detailed pictures?

Answers

As of my knowledge cutoff in September 2021, no space probes have flown past Uranus closely enough to take detailed pictures.

The only spacecraft that has ever visited Uranus is Voyager 2, which conducted a flyby of the planet in 1986. During the flyby, Voyager 2 captured images and collected data, providing valuable information about the planet and its moons. However, the images obtained were not at a level of detail considered "detailed pictures" by today's standards. It's important to note that my information is accurate up until September 2021, and there may have been new missions or developments since then. For the most up-to-date information, it is recommended to refer to reliable sources or official space agency announcements.

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Convert 0.592 hm to cm. *

Answers

Answer:

5920 cm

Explanation:

1 hm = 100m

1 m = 100cm

1 hm = 100×100cm = 10000 cm

0.592 hm = 0.592×10000cm = 5920 cm

Good luck !

Please ans fast I will mark brainliest

Please ans fast I will mark brainliest

Answers

Answer:

Electrical energy; chemical energy.

Explanation:

Energy can be defined as the ability (capacity) to do work. The various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.

In this scenario, electrical energy is present in the charger and the cable while we have chemical energy in the battery of the mobile phone.

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

This ultimately implies that, the electrical energy in the charger and cable is used to charge the battery of the mobile phone as chemical energy.

The sled dog in figure drags sleds A and B across the snow. The coefficient of friction between the sleds and the snow is 0.10. (Figure 1) Part A If the tension in rope 1 is 160 N. what is the tension in rope 2? Express your answer to two significant figures and include the appropriate units. T2 = ____N

Answers

The tension in rope 2 (T2) = 288 N.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force applied to it, and inversely proportional to its mass. Mathematically, this can be expressed as:

      F = ma

where F is the net force, m is the mass of the object, and a is its acceleration.

T2 = μmg

= μg(m + m2)

= 0.10 * 9.8 m/s^2 * (60 kg + 20 kg)

= 288 N

When analyzing the motion of objects, it is often useful to consider the forces acting on them. These forces can include gravity, friction, tension, and others. By analyzing the forces, we can determine the net force acting on an object and use Newton's second law to calculate its acceleration.

In the problem you provided, we are given the coefficient of friction between the sleds and the snow, and we are asked to calculate the tension in rope 2 given the tension in rope 1. By considering the forces acting on the sleds and using Newton's second law, we can determine the relationship between the tensions in the ropes and the force of friction, and calculate the tension in rope 2.

Understanding the relationship between forces, acceleration, and mass is essential in many areas of science and engineering, including physics, mechanics, and aerospace engineering. By applying Newton's laws of motion, we can design and optimize systems and devices to perform specific functions and achieve desired outcomes.

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The sled dog in figure drags sleds A and B across the snow. The coefficient of friction between the sleds

what is the angular resolution at 420 nm for a telescope with a 9 meter primary mirror? (just a number, no units) (calculate to 4 decimal places)

Answers

The angular resolution for a telescope with a 9-meter primary mirror at 420 nm is approximately 0.0116 arcseconds.

The angular resolution at 420 nm for a telescope with a 9 meter primary mirror can be calculated using the formula:

angular resolution = 1.22 x wavelength / diameter

where wavelength is in meters and diameter is in meters.

Converting 420 nm to meters gives us 4.2 x 10^-7 meters.

Plugging in the values, we get:

angular resolution = 1.22 x (4.2 x 10^-7) / 9

Simplifying this expression gives us an angular resolution of:

0.00002682 radians (to 4 decimal places)

Angular resolution (in radians) = 1.22 * (wavelength / diameter)

Here, the wavelength (λ) is 420 nm (4.2 x 10^(-7) m) and the diameter (D) of the primary mirror is 9 meters. Plugging these values into the formula, we get:

Angular resolution (in radians) = 1.22 * (4.2 x 10^(-7) m / 9 m)

Angular resolution (in radians) = 5.644 x 10^(-8)

To convert the angular resolution to arcseconds, we can multiply by the conversion factor (206,265 arcseconds per radian):

Angular resolution (in arcseconds) = 5.644 x 10^(-8) radians * 206,265 arcseconds/radian

Angular resolution (in arcseconds) ≈ 0.0116

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You apply a force of 10 N to a grocery cart to get an acceleration of 0.5 m/s2. If you apply a force of 20 N to the same grocery cart, its acceleration will be

Answers

Answer:

It will travel at 1 m/s2

Answer:

It will travel at 1 m/s2

Explanation:

The object having uniform velocity has zero acceleration, why?

Answers

Ans: It measures how much velocity is changing in a given time interval. If the body has uniform velocity, it means velocity is not changing. So the change in velocity is zero. In other words, its acceleration is zero.

Please help it’s easy will give brainlist !! Thank youu worth a lot be serious pls

Please help its easy will give brainlist !! Thank youu worth a lot be serious pls
Please help its easy will give brainlist !! Thank youu worth a lot be serious pls
Please help its easy will give brainlist !! Thank youu worth a lot be serious pls

Answers

Answer:

Part 1

Stationary

Part 2

20 Newtons

Part 3

Force

Part 4

4.0 m/s²

Part 5

Normal

Part 6

Cart m

Part 7

The gravitational force is less than magnetic force

Explanation:

Part 1

The position time graph of the object is an horizontal straight line passing across the top of the position 3 boxes vertically up from the origin

As the time increases by the units of number boxes to the left, the position of the object does not change and remains at the 3 boxes up above the origin, therefore, the object is stationary

Part 2

By Newton's third law of motion, the action action obtained from a force is equal to the reaction given to the force, therefore, we have;

The force exerted by the student on the scale = The force exerted by the scale on the student = 20 N

Part 3

A force is a the directional push on an object or pull from the object as a form of interaction with another object which tends to alter or maintain the motion of the object

Part 4

The given parameters are'

The mass of block A = 1.0 kg

The mass of block B = 2.0 kg

Both blocks, "A" and "B" are initially at rest

The applied horizontal force, F = 12-N

The nature of the surface over which the blocks move = Smooth surface

Force, F = Mass, m × Acceleration, a

F = m × a

The blocks two blocks experience a common acceleration, a

The combined mass of the two blocks, m = 1.0 kg + 2.0 kg = 3.0 kg

m = 3.0 kg

Therefore, a = F/m = 12-N/(3.0 kg) = 4 m/s²

Part 5

A normal force is a force acting perpendicularly to a surface that supports the weight of an object

Part 6

The given parameters are;

M = 2 kg

The mass of the left cart attached to the spring = M = 2 kg

The mass of the right cart attached to the spring = 2·M = 2 × 2 kg = 4 kg

Therefore, given that the force exerted by one cart on the other after the spring is removed, we have;

Force, F = M × a₁ = 2·M × a₂

Where;

a₁ = The average acceleration of the cart with mass, M

a₂ = The average acceleration of the cart with mass, 2·M

M × a₁ = 2·M × a₂

∴ a₁ = 2·a₂

The acceleration, a₁, of car M = 2 × The acceleration, a₂, of car 2·M

The acceleration of cart M is two times the acceleration of cart 2·M

Cart M will experience a greater average acceleration

Part 7

For the top magnet of two magnets placed two magnets arranged so that one is on top the other, to be held in the air with a space between the two magnets, the gravitational force pulling the top magnet down, is less than the repelling magnetic force between the two magnets.

A 75.6-kg circus performer is fired from a cannon that is elevated at an angle of 37.2° above the horizontal. The cannon uses strong elastic bands to propel the performer, much in the same way that a slingshot fires a stone. Setting up for this stunt involves stretching the bands by 2.70 m from their unstrained length. At the point where the performer flies free of the bands, his height above the floor is the same as the height of the net into which he is shot. He takes 2.34 s to travel the horizontal distance of 26.9 m between this point and the net. Ignore friction and air resistance and determine the effective spring constant of the firing mechanism.

Answers

Answer:

The effective spring constant of the firing mechanism is approximately 21.804 N/m

Explanation:

The mass of the circus performer, m = 75.6 kg

The angle of elevation above the horizontal, θ = 37.2°

The instrument the cannon uses to propel the performer = Strong elastic band

The length by which the band stretches, x = 2.70 m

The height of the performer above the floor at the point the performer flies free of the bands = The height of the net into which he is shot

The time he takes to travel the horizontal distance between the point he is shot and the net, t = 2.34 s

The horizontal distance between the the point he is shot and the net, dₓ = 26.9 m

Therefore, the horizontal component of the velocity, vₓ, can be found with the following kinematic equation of motion;

vₓ = dₓ/t

∴ vₓ = 2.70 m/(2.34 s) = (15/13) m/s

By the resolution of the initial velocity, 'v', into the horizontal and vertical component, we have;

The horizontal component, vₓ = v × cos(θ)

∴ v = vₓ/(cos(θ))

v = (15/13)/(cos(37.2°)) ≈ 1.45

The initial velocity, v ≈ 1.45 m/s

The kinetic energy given to the circus performer by the elastic band, K.E., is given as follows;

K.E. = (1/2)·m·v²

Where;

m = The mass of the performer = 75.6 kg

v = The velocity given to the performer ≈ 1.45 m/s

∴ K.E. ≈ (1/2) × 75.6 × 1.45² ≈ 79.475

∴ K.E. ≈ 79.475 J

The kinetic energy, K.E., given to the performer, (1/2)×m×v² = The kinetic energy of the elastic band = (1/2)×k×x²

Where;

k = The effective spring constant of the firing mechanism

x = The extension of the sling = 2.70 m

Therefore, we get;

K.E. = (1/2)·m·v² = (1/2)·k·x²

∴ K.E. ≈ 79.475 J = (1/2) × 75.6 × 1.45² = (1/2) × k × (2.70 m)²

∴ 79.475 J ≈ (1/2) × k × (2.70 m)²

k = 79.475 J/((1/2) × (2.70 m)²) ≈ 21.804 N/m

The effective spring constant of the firing mechanism, k ≈ 21.804 N/m.

An object of mass 10 kg, initially at rest, experiences a constant horizontal acceleration of 4 m/s2 due to the action of a resultant force applied for 20 s. Determine the total amount of energy transfer by work, in kj.

Answers

So, the total energy value that has been transferred by work is 32 kJ.

Introduction

Hi ! In this question, I will help you. Work is the amount of force exerted to cause an object to move a certain distance from its starting point. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

\( \boxed{\sf{\bold{W = F \times s}}} \)

With the following condition :

W = work (J)F = force (N)s = shift or displacement (m)

Now, because in this question, the "s" is not directly known, whereas it is known that the initial velocity is zero, the object has an acceleration, and is moving in certain time intervals. Then, use this formula to find the value of "s" !

\( \boxed{\sf{\bold{s = \frac{1}{2} \times a \times t^2}}} \)

With the following condition :

s = shift or displacement (m)a = acceleration (m/s²)t = interval of the time (s)

Problem Solving

We know that :

a = acceleration = 4 m/s²t = interval of the time = 20 sm = mass = 10 kg

What was asked :

W = work = ... kJ

Step by Step :

Calculate value of force by multiple m and a

\( \sf{F = m \times a} \)

\( \sf{F = 10 \times 4} \)

\( \sf{\bold{F = 40 \: N}} \)

Calculate value of shift or displacement

\( \sf{s = \frac{1}{2} \times a \times t^2} \)

\( \sf{s = \frac{1}{\cancel 2} \times \cancel 4 \:_2 \times 20^2} \)

\( \sf{s = 2 \times 400} \)

\( \sf{\bold{s = 800 \: m}} \)

Last, calculate the value of work

\( \sf{W = F \times s} \)

\( \sf{W = 40 \times 800} \)

\( \boxed{\sf{W = 32,000 \: J = 32 \: kJ}} \)

So, the total energy value that has been transferred by work is 32 kJ.

Someone HELP if the displacement is in the start and it ends in the same spot then would It be 0?

Someone HELP if the displacement is in the start and it ends in the same spot then would It be 0?

Answers

Answer:

Yes

Explanation:

Displacement is equal to the final position of X minus the initial position of X.

Diamonds have a density of 3.5 g/cm3. How big is a diamond that has a mass of 0.10
g?
Hint: density = mass/volume

Answers

Answer:

So, let x be the volume in cubit centimeters.

the mass is to the volume is as the mass is to the volume

3.5g /(1 cm3) = 0,1g / (x cm3)

Cross-multiply to get:

3.5x = 0.1

x = 0.1 / 3.5 (divide both sides by 3.5)

x = 0.028571 cm3 (you probably should round this, but diamonds are expensive !

the volume v of diamond is approximately 0.02857 gm/cm³

What is volume ?

Volume is a three dimensional space occupy by the body of particular shape. Generally expressed in cubic meter.

So, let v be the volume of diamond in cubic centimeters and

the mass of diamond is given as 0.10 gm.

Density of diamond is calculated as :

\(\begin{aligned}\rho&= \frac{m}{v}\\v&=\frac{0.1}{3.5}\\&=0.02857\: gm/cm^{3} \end{aligned}\)

Therefore, the volume v of diamond is approximately 0.02857 gm/cm³  

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_______ increases when air faces greater resistance against an object with a larger surface area. (4 letters)

Answers

The term that increases when air faces greater resistance against an object with a larger surface area is drag.

The drag force is created when a solid object moves through a fluid (liquid or gas), such as air, and experiences resistance to its motion.Drag can be affected by various factors, including the object's shape and surface area. In general, objects with larger surface areas will experience more drag than those with smaller surface areas because they create more friction with the surrounding fluid. For example, a flat, wide object like a barn door will experience more drag than a narrow object like a pencil because it has a larger surface area. Similarly, a parachute will experience a large amount of drag because of its large surface area, which creates a significant amount of friction with the air molecules around it.In order to minimize drag and increase efficiency, engineers and designers often try to create streamlined objects with minimal surface area. This can be seen in the design of cars, airplanes, and even swimsuits used by competitive swimmers. By minimizing drag, these objects are able to move more quickly and with less effort through their respective fluids.

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An object's
planet.
will remain constant throughout the universe, but its
If you increase the mass of a planet, what happens to its gravity?
If the gravity on a planet decreases, what happens to the weight of an object on that planet?

Answers

The planet of an item will remain constant across the planet, but if you give it more mass, the gravitational force increases while the acceleration due to gravity remains constant.

What is the difference between mass and weight?

The mass of the body is defined as the amount of matter a body has. It is denoted by m and its unit is kg. Mass is the quantity on which a lot of physical quantity depends.

Weight is defined as the amount of force an object exerts on the surface. It is given as the product of mass and the gravitational pull.

Mass is an independent quantity it never depends on the other. While weight is a dependent quantity that depends upon the gravitational pull.

The value of gravitational pull is different in the different parts of the universe. For example, on the earth, the value of gravitational acceleration is 9.81 m/sec².While on the moon it is g/6.

Weight is change according to the place or surrounding while the mass of the body is constant everywhere.

The planet of an item will remain constant across the cosmos, but if you give it more mass, the gravitational force increases while the acceleration of gravity remains constant.

If a planet's gravity weakens, the weight of that planet will likewise be altered. With an increase in mass, weight also rises.

Hence, the gravitational force increases while the acceleration due to gravity remains constant for the given case.

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How did Galileo increase public support for Copernicus’s model?

by publishing his work in Italian
by using data collected by Tycho Brahe
by explaining why planets appear to move backward
by arguing that Earth’s rotation makes objects appear to move in the sky

Answers

Galileo increases public support for Copernicus's model by publishing his work in Italian. Thus option a is correct.

Copernicus's model has been the heliocentric model of the universe given by Nicolaus Copernicus. According to the model, the sun has been the center of the universe, and the planets are revolving around the Sun in a circular path, and at a constant speed.

This idea of Copernicus has been against religious belief and thus has not been accepted. However, the development of Keplar's law helps in the better understanding of Copernicus's model.

Galileo increases public support for Copernicus's model by publishing his work in Italian. Thereby finally the model has been published in 1543. Thus option a is correct.

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Answer: The answer is: by publishing his work in Italian

Explanation: credit to the guy above me!

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the block is subjected to a force v that produces a deflection of δ = 0.12 cm . what is the applied force?

Answers

Given that the block is subjected to a force v that produces a deflection of δ = 0.12 cm. We are to find the applied force.Let the force applied be F. Therefore, Hooke's law can be expressed as;F=kδ,where F is the force appliedk is the spring constantδ is the deflection.

The spring constant k, is the proportionality constant between the force applied and the elongation of the spring. Mathematically, we have;

k= F/δ

= (mg)/δ

Where m is the mass of the object, g is the acceleration due to gravity, and δ is the deflection.Substituting the value of k in the expression for Hooke's law, we have;

F=kδ

= ((mg)/δ) δ

= mgThus, the force applied is F = mg.However, the mass of the block is not given. Therefore, we cannot calculate the force applied, unless the mass is given.Basically, we have used Hooke's Law in solving the problem that was given. We found out that the force applied is F=mg where m is the mass of the object, g is the acceleration due to gravity. Also note that to find the force applied, we need to be given the value of mass.

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earth’s land areas, oceans, and atmosphere maintain fairly constant average temperatures. what is the best explanation for these constant average temperatures?

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The Earth's land areas, oceans, and atmosphere maintain fairly constant average temperatures due to a process called the Earth's heat balance, which refers to the balance between the amount of energy the Earth absorbs from the Sun and the amount of energy the Earth radiates back into space.

The Earth's heat balance is maintained by a number of processes that regulate the temperature of the Earth's surface, including:

Insolation: The Earth absorbs energy from the Sun in the form of electromagnetic radiation, known as insolation. Greenhouse effect: The Earth's atmosphere contains gases that trap some of the heat radiating from the Earth's surface, preventing it from escaping into space. Heat transfer: Heat is transferred from the warmer equatorial regions to the cooler polar regions through a variety of mechanisms, including conduction, convection, and radiation.Albedo: The reflectivity of the Earth's surface, known as albedo, plays a role in the Earth's heat balance.

Overall, the Earth's heat balance is maintained by a complex interplay of processes that regulate the temperature of the Earth's surface and atmosphere.

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Number of atoms present in 1 mole of oxygen atom

Answers

Answer:

1 mole of every substance has 6.022 × 10^23 particles. This is called Avagadro's constant

6. Why would the electrons spend most of their time close to the nucleus?

Answers

Electrons spend most of their time close to the nucleus because they are attracted to the positively charged protons in the nucleus by the electromagnetic force.

This force causes the electrons to move in an orbit around the nucleus, much like planets orbiting around the sun.

The closer an electron is to the nucleus, the stronger the attractive force between them. This results in the electrons being tightly bound to the nucleus, and they tend to spend most of their time in the lowest energy level, known as the ground state. In this state, the electrons are as close to the nucleus as possible, which is why they spend most of their time in that region.

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The MMPI is an example of a(n) _____.
A. personality inventory
B. projective test
C. self-esteem test
D. inkblot test

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The MMPI is an example of a(n) A. personality inventory.

A personality inventory is a form of self-evaluation, frequently a standardised questionnaire, that provides insights into a person's personality. These exams can aid in determining a person's strengths and limitations in a variety of areas, as well as their social traits, motives, and attitudes. A person's ideal career can be identified using personality inventories, which can also be used for psychological evaluations. Understanding their motivations or their strengths and limitations might help these people determine whether a job is a good fit for them. You can evaluate your personality and potential career alternatives using a variety of popular types of personality assessments.

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Describe how the wavelength of a wave changes if the wave slows down but its frequency does not change.

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Answer:

If the wave slows down with no change in frequency, the wavelength decreases.

If the wave slows down with no change in frequency, then the wavelength decreases.

What is a wave?

A wave is defined as the disturbance that has the ability to transfer energy from one point to another in a medium.

The properties of a wave are given as;

Wavelength can be defined as the distance that is observed between adjacent points in an identical cycle of a waveform.

Frequency is the number of cycles of a wave that can occur per minute time.

Time period can be defined as the time it takes for a complete cycle of wave to occur.

Wave speed can be defined as the distance a wave travels in a given amount of time.

Amplitude can be defined as the distance from the centre line (or the still position) to the top of a crest or to the bottom of a trough.

When there is a change in the speed of the wave then the length of the wave would decrease.

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