How many miles will a person run during a 10 kilometer race?

Answers

Answer 1
A person will run 6 and 1/4 miles during a 10 kilometre race
Answer 2

Answer:

6.2 miles

Explanation:


Related Questions

A moving car hits the breaks and starts to slow down. The car was moving 35 m/s when hitting the breaks and slows at a rate of 7 m/s/s. What is the final velocity of the car after 4 seconds?

Answers

7 miles per second.

It would take 5 seconds to stop because 35 divided by 7 = 5.

It would slow 28 miles in 4 seconds because 7 x 4 = 28.

35 - 28 = 7.

A team of engineers is asked to help a community improve local air qualiy what must a team do before it can begin to identify

Answers

The team of engineers must first define the problem, Option A.

What is air quality?

The term air quality has to do with the overall purity of the air in a certain locality. We know that the air in an area is affected by the activities of the people that reside in that vicinity.

In this case, the team of engineers must first define the problem before they can  improve local air quality in the community.

Missing parts;

A team of engineers is asked to help a community improve local air quality. What must the team do before it can begin to identify possible solutions?

answer choices

Iterate to improve the solution.

Define the problem.

Select one solution.

Model the solution.

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I need the right answer ASAP NO LINKS!!!

I need the right answer ASAP NO LINKS!!!

Answers

The first one!

Hope this helps pls mark as brainliest :)

Answer:

Models change to accommodate new discoveries.

Explanation:

Scientific models are based on current scientific knowledge. This means that when new discoveries are made they are subject to change.

If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.

Answers

We are given the following information about an inelastic collision.

Mass of 1st object = 4 kg

Mass of 2nd object = 10 kg

Initial velocity of 1st object = 25 m/s

Final velocity of both objects = 14 m/s

Initial velocity of 2nd object = ?

In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.

Recall that the total momentum is conserved and given by

\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)

Let us substitute the given values and solve for initial velocity of the body (u2)

\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)

Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s

a boat that can sail at 25m/s in still water heads west in a river with a current of 12m/s due north, how far will the boat travel in 1 minute

Answers

Maybe about 15
Jajajajajajjajajajajsjajja

An unpolarized EM wave is incident on two orthogonal polarizers.
(a) What percentage of the intensity gets through both polarizers?
(b) Is it possible to increase this percentage by inserting another polarizer between the original two?

Answers

Only 50% of the intensity of an unpolarized EM wave can get through two orthogonal polarizers. Inserting another polarizer between the original two cannot increase the percentage of intensity that gets through, but will only decrease it further.


(a) When an unpolarized electromagnetic wave is incident on two orthogonal polarizers, only half of the intensity gets through both polarizers. This is because the first polarizer blocks all the waves that are polarized in a direction perpendicular to its polarization axis, while the second polarizer blocks all the waves that are polarized in a direction parallel to its polarization axis. Since an unpolarized wave has equal components of polarization in all directions, only half of the intensity gets through both polarizers.

(b) It is not possible to increase the percentage of intensity that gets through both polarizers by inserting another polarizer between the original two. In fact, it will only decrease the intensity even further, as the third polarizer will block even more of the waves that are polarized in different directions. The maximum intensity that can get through two polarizers is always half of the original intensity of the unpolarized wave.


In conclusion, only 50% of the intensity of an unpolarized EM wave can get through two orthogonal polarizers. Inserting another polarizer between the original two cannot increase the percentage of intensity that gets through, but will only decrease it further.

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When a circuit is made up of a battery, a bulb,
and a wire, how should the wire run to light up
the bulb?

When a circuit is made up of a battery, a bulb,and a wire, how should the wire run to light upthe bulb?

Answers

When a circuit is made up of a battery, a bulb, and a wire then the wire should run either from the bulb to the battery or from the battery to the bulb to light up the bulb. Hence option C is correct.

An incandescent light bulb, incandescent lamp, or incandescent light globe is an electric light with a heated wire filament. To protect the filament from oxidation, it is encased in a glass bulb with a vacuum or inert gas. Terminals or wires implanted in the glass supply current to the filament. A bulb socket offers mechanical support as well as electrical connections.

Incandescent bulbs are available in a variety of diameters, light outputs, and voltage ratings ranging from 1.5 volts to around 300 volts( A battery of this much Voltage). They do not require any external regulating equipment, have cheap production costs, and can operate on either alternating or direct current.

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If an object moving at 5 m/s accelerates for 30 seconds at a rate of 2
m/s^2, what is its final velocity? *

Answers

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

stars e and f have the same (b-v) color but star e is 3 times brighter than star f when measured using a b filter. how many times is star e brighter than star f when measured using a v filter?

Answers

When measured using a B filter, star E is three times brighter than star F. The brightness ratio of a star is determined by its spectral energy distribution, which describes how its energy is distributed across wavelengths.

The (B-V) color index measures the difference in brightness between the B and V filters, with smaller values indicating bluer stars and larger values indicating redder stars.

To determine how many times star E is brighter than star F when measured using a V filter, we would need to know the relative spectral energy distributions of the two stars and the transmission characteristics of the B and V filters. Without this information, we cannot make a definitive calculation.

To determine how many times star E is brighter than star F when measured using a V filter, we need additional information about their brightness ratio respective spectral energy distributions and the transmission characteristics of the B and V filters.

In general, the brightness of a star can vary across different wavelengths, so a star that is three times brighter than another star in one filter may not necessarily be three times brighter in another filter. The relative brightness in different filters depends on the specific characteristics of the stars' spectra and the transmission curves of the filters used.

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3. Is converting wood into saw dust a reversible change? Give one reason for your answer

Answers

No, conversion of wood to sawdust is an irreversible change, because a block of wood after grounding into sawdust cannot be changed into the same block of wood

an emf of 0.2 v drives an electrical current of 2 ma through a solution of sodium chloride in 1 hour. (a) how much charge has been passed? (b) assuming there is no resistance elsewhere in the circuit, what is the resistance represented by the solution? (c) by what means is the charge carried through the solution?

Answers

(a) The charge passed is equal to the current multiplied by the time, so Q = I * t = 2mA * 1h = 2 C.

(b) The resistance represented by the solution is equal to the voltage divided by the current, so R = V / I = 0.2V / 2mA = 0.1 ohm.

(c) The charge is carried through the solution by the ions present in the solution. The ions carry the charge in the form of either electrons or protons. In the case of sodium chloride, the ions are Na+ and Cl-, which carry the charge in the form of protons and electrons respectively.

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a 5.00kg object is subjected to three forces that give it an acceleration. if two of the three forces are. find the magnitude of the third force vector

Answers

To find the magnitude of the third force vector acting on a 5.00 kg object that is subjected to three forces, we need additional information such as the magnitudes and directions of the two known forces. Without this information, we cannot calculate the magnitude of the third force.

To determine the magnitude of the third force, we need to consider the principles of Newton's second law of motion. According to this law, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this scenario, the object is experiencing an acceleration due to the combined effect of the three forces.

To calculate the magnitude of the third force, we need the magnitudes and directions of the two known forces and their resulting acceleration. However, this information is not provided, making it impossible to perform any calculations to determine the magnitude of the third force.

Without the magnitudes and directions of the two known forces and their resulting acceleration, we cannot calculate the magnitude of the third force vector acting on the 5.00 kg object. Additional information is needed to solve this problem accurately.

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Electric field strength of a point charge is E. What is the electric potential at a point where electric field will be E/4?

Answers

Answer:

Explanation:

We shall find first the distance where electric field is E/4 .

Let the charge be Q and distance be d where electric field is E . From the coulomb's Law

E = k Q / d²

Let distance be d₁ where field is E/4

E/4 = kQ / d₁²

Dividing the two equation

4 = d₁² / d²

d₁ = 2d

We shall have to find Potential at d₁ which is equal to 2 d .

Potential at d₁

V = k Q / 2d

= kQ d / 2d²

= E d / 2 . where d is distance of the point where field is E .

?????? ?????help please

?????? ?????help please

Answers

the answer is d. cassani

An airplane accelerates from a velocity of 25.88 m/s at a constant rate of 4.21 m/s2 over 590.39 m. What is its final velocity?

Answers

The final velocity of the airplane is 75.1 m/s.

What is velocity?

Velocity can be defined as the measurement of rate and direction of motion.

The velocity of a moving object changes with time. Thus, a moving object will have an initial velocity as well as a final velocity.

The formula for final velocity, V is given by the formula below:

v = √(u² + 2as)

where

u = initial velocitya = accelerations = distance or displacement

The values are as follows:

u = 25.88 m/s

a = 4.21 m/s²

s = 590.39 m

Substituting the values

v = √{(25.88)² + 2 * 4.21 * 590.39)}

v = 75.1 m/s

Therefore, the final velocity, v is 75.1 m/s

In conclusion, the final velocity of the airplane is derived from the initial velocity, acceleration, and distance of travel.

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Which property of a transverse wave stays the same even as the wave's
energy and other properties change?
Wavelength
Frequency
Rest position
Amplitude
ent
1 of 8 QUESTIONS
SUBMIT

Answers

The property of a transverse wave that stays the same even as the wave's energy and other properties change is the wavelength.

The correct option to the given question is option a.

The wavelength is the distance between two successive points of the wave that are in phase. As the wave's energy and amplitude change, the distance between two successive points of the wave that are in phase remains the same.

This is because wavelength is determined by the frequency of the wave and the speed of propagation. The frequency of the wave is the number of cycles of the wave that occur in one second, while the speed of propagation is the rate at which the wave travels through a medium.

If the frequency of the wave and the speed of propagation remain the same, then the wavelength will also remain the same even as the wave's energy and other properties change. This property is known as the characteristic of the wave.The amplitude is the maximum displacement of a point on the wave from its rest position. The frequency is the number of cycles of the wave that occur in one second. The rest position is the position of the medium when it is not disturbed.

Hence, wavelength of a transverse wave remains same even as the wave's energy and other properties change.

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How many marshmallows are in 80 bags if each bag hold 24 marshmallows?

Answers

Explanation:

80*24=1920 or 1,920

Just multiply

\(hopethishelpsyou\)

Answer:

jeeze... this would be easier if the numbers were switched

Explanation:

i dont have an answer for ya but put 80x24=? in ur calculator

good luck m8

Question 1 of 10
During an experiment, you take a measurement of 18.3 inches. What is this
measurement in centimeters? 1 in = 2.54 cm.

Answers

the answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters

Answer:

\(46.482 cm\)

Explanation:

\(Since 1 in = 2.54cm\\\\18.3 inches =(18.3 x 2.54) cm\\ =46.482cm\)

describe what living in the southeast is like for many people in both cities and outside of cities.

Answers

Living in the Southeast for many people, both in cities and outside of cities, offers a distinct blend of cultural, geographical, and climatic characteristics.

In cities such as Atlanta, Charlotte, or Miami, residents experience the bustling energy of urban life with a range of amenities, diverse culinary scenes, and thriving cultural attractions. These cities often have vibrant downtown areas, modern infrastructure, and employment opportunities across various industries. Residents can enjoy a mix of entertainment options, including music festivals, sports events, and a vibrant nightlife. However, they may also encounter challenges such as traffic congestion and higher living costs in some areas. Outside of cities, the Southeast region boasts picturesque landscapes and a more relaxed pace of life. Residents can find charming small towns, close-knit communities, and a stronger connection to nature. The region offers stunning coastlines, scenic mountains, and lush forests, providing ample opportunities for outdoor activities like hiking, fishing, and beach outings. Residents often appreciate the Southern hospitality, a slower lifestyle, and a sense of community. Across the Southeast, the climate is generally characterized by hot summers and mild winters, with some areas prone to hurricanes and tropical storms. The region also showcases its rich history, diverse traditions, and a culinary heritage famous for dishes like barbecue, seafood, and soul food.

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A boiling liquid absorbs thermal energy (heat) at a rate of 450 W. The specific latent heat of vaporisation is 2.7 × 106 J / kg

Answers

Explanation:

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Suppose a(t) = 2 measured in seconds. Vt + 4e -5, V(0) = - 4, and S(0) = 5, where act), v(t) and s(t) represent the acceleration, velocity and distance from the starting point of an object. Distance is measured in meters and time is a. Find v(t). b. Find s(t). c. Find the velocity when t = 9. a. v(t) = b. s(t) = C. The velocity is m/sec. (Type an integer or decimal rounded to two decimal places as needed.)

Answers

a) The value of the required velocity is v(t) = t²/2 - 4t + 4e⁻⁵

b) The value of the required distance is S(t) = t³/6 - 2t² + 4e⁻⁵t + 5

c) The value of the velocity when t = 9 is approximately -28.2 m/sec

(a)To find v(t), we need to integrate a(t) first

a(t) = 2∫

a(t) dt = ∫ 2

dt = 2t + C1

Here, C1 is the constant of integration

Next, we need to integrate v(t) by substituting the value of a(t) into it

v(t) = ∫ (2t + C1)

dt= t² + C1t + C2

Here, C2 is another constant of integration

v(0) = - 4⇒ C2 = - 4

Also, given: v(t) = Vt + 4e⁻⁵

Comparing the above two equations:

v(t) = Vt + 4e⁻⁵ = t² + C1t - 4

On differentiating with respect to t, we geta(t) = 2

Therefore, we get the differential equation as:

Vt + 4e⁻⁵ = t² + C1t - 4 - - - - - - (1)

To find v(t), we need to solve this differential equation

Substituting t = 0, in (1), we get

-4 + 4 = 0 + C1(0)⇒ C1 = 0

Therefore, the differential equation becomes:

Vt + 4e⁻⁵ = t² - 4

On differentiating the above equation w.r.t t, we get:

a(t) = 2

Therefore, we get

v(t) = t²/2 - 4t + 4e⁻⁵ - - - - - - (2)

Thus, the required velocity is given by:

v(t) = t²/2 - 4t + 4e⁻⁵

Part (b) To find s(t), we need to integrate v(t) first

v(t) = t²/2 - 4t + 4e⁻⁵∫ v(t)

dt = ∫ (t²/2 - 4t + 4e⁻⁵)

dt= t²/6 - 2t² + 4e⁻⁵t + C3

Here, C3 is the constant of integration

Also, given that S(0) = 5⇒ C3 = 5

Therefore, we get

S(t) = t³/6 - 2t² + 4e⁻⁵t + 5 - - - - - - (3)

Thus, the required distance is given by:

S(t) = t³/6 - 2t² + 4e⁻⁵t + 5

Part (c) To find the velocity when t = 9We can use the value of v(t) obtained in part (a)⇒ v(9) = (9)²/2 - 4(9) + 4e⁻⁵⇒ v(9) = - 28.2 (approx)

Thus, the velocity when t = 9 is -28.2 (approx)m/sec.

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Determine the magnitude of the force that must be applied to a wooden block whose weight has a magnitude of 8N, so that it acquires an acceleration of 0.5 m / s²

Answers

Answer:

F = 0.408 N

Explanation:

It is given that,

Weight of a wooden block, W = 8 N

Weight, W = mg

m is mass of wooden block

\(m=\dfrac{W}{g}\\\\m=\dfrac{8\ N}{9.8\ m/s^2}\\\\m=0.816\ kg\)

Acceleration of the block, a = 0.5 m/s²

Force, F = ma

\(F=0.816\ kg\times 0.5\ m/s^2\\\\F=0.408\ N\)

So, the magnitude of force applied to the wooden block is 0.408 N.

the weight of the buggy was 105N on earth And 40N on mars. Why was the weight of the buggy less on mars than earth?

Answers

Answer: The gravity on Mars is considerably less than it is on Earth, so while the buggy still has the same physical mass, its relative weigh it considerably less.

How can speed and velocity be used to describe motion?

Answers

Answer:

speed described how fast the object moves velocity describes how fast and in what direction its moved..

Turn in homework (need show work):
1. Find the work done against Earth's gravity by a lifter to lift a 40-kg object by 8 m
high. If the lifter takes 16 seconds, what is the power of the lifter?
2. A 2-kg ball moves at 8 m/s. Find the ball's rest energy, kinetic energy, and linear
momentum. When the ball collides into a 4-kg rest ball and then moves together,
what is the speed of the balls?

Answers

The work done against Earth's gravity by a lifter is 3136 J.

The power of the lifter is 196 J/s.

The ball's rest energy is 0 J,

The kinetic energy is 64 J.

The linear momentum of the ball is 16 kgm/s.

The speed of the balls after collision is 2.67 m/s.

Work done against gravity by the object

The work done against gravity by the object is equal to change in the potential energy of the object.

W = -ΔP.E

W = -mg(hf - hi)

W = -40 x 9.8(0 - 8)

W = 3136 J

Power of the lifter

Power = Energy / time

Power = 3136J / 16 s

Power = 196 J/s

Kinetic energy of the ball

K.E = ¹/₂mv²

K.E = ¹/₂(2)(8²)

K.E = 64 J

Linear momentum of the ball

P = mv

P = 2 x 8

P = 16 kgm/s

Speed of the balls after collision

v = P/(m₁ + m₂)

v = (16 kgm/s) / (2 kg + 4 kg)

v = (16)/(6)

v = 2.67 m/s

Thus, the work done against Earth's gravity by a lifter is 3136 J.

The power of the lifter is 196 J/s.

The ball's rest energy is 0 J,

The kinetic energy is 64 J.

The linear momentum of the ball is 16 kgm/s.

The speed of the balls after collision is 2.67 m/s.

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In school, Brendan has been conditioned to get up from his seat every time he hears the school bell ring. Brendan was sitting at McDonalds eating with friends, when a loud sound similar to the school bell rang from the kitchen. Without even thinking, Brendan jumped out of his seat at McDonalds.



Label the following for this scenario:

a. Unconditioned Stimulus (US)_

b. Conditioned Stimulus (CS)_

c. Unconditioned Response (UR)_

d. Conditioned Response (CR)_

Answers

Answer:

US: the bell ringing

CS:get up when hearing the bell

UR:standing after hearing the bell

CR:hearing the bell in mcdonalds and standing up

Explanation:

US: the bell ringing

CS: get up when hearing the bell

UR: standing after hearing the bell

CR: hearing the bell in Mcdonald's and standing up

Who's eligible for the third stimulus test?

commonly, a taxpayer will qualify for the overall quantity if they have an adjusted gross income of up to $ 75,000 for singles and married individuals submitting a separate go back, as much as $112,500 for heads of family, and as much as $150,000 for married couples submitting joint returns and surviving spouses.

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What is the field strength an object of mass 3. 3g is in to give the object a weight of 0. 96?

Answers

Field strength refers to the magnitude of the gravitational field strength or acceleration due to gravity. It is measured in newtons per kilogram (N/kg) and can be denoted by the symbol ‘g.' Field strength plays a vital role in calculating the weight of an object.

Object of mass 3.3g is in to give the object a weight of 0.96By using the formula of weight, we can calculate the field strength of an object. Weight (W) is the product of mass (m) and the acceleration due to gravity (g) of the object.W = m x gWhere,W = 0.96N (weight of the object)M = 3.3g (mass of the object)G = acceleration due to gravityWe know that 1N = 1000gTherefore, 0.96N = 960gUsing the above formula and substituting the given values,960g = 3.3g x gSolving for g, we get,g = 960g / 3.3gg = 290.91 N/kgTherefore, the field strength of an object with a mass of 3.3g that is required to give the object a weight of 0.96N is 290.91 N/kg.

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Final answer:

The field strength experienced by the object is 290.91 m/s².

Explanation:

The field strength an object experiences is determined by the gravitational force acting on it. The weight of an object is given by the equation w = mg, where w is the weight, m is the mass of the object, and g is the acceleration due to gravity.

Given that the weight of the object is 0.96 N, and the mass of the object is 3.3 g (or 0.0033 kg), we can use the equation w = mg to find the field strength (g). Rearranging the equation, we have g = w/m = 0.96 N / 0.0033 kg = 290.91 m/s².

So, the field strength experienced by the object is 290.91 m/s².

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How much horizontal force is needed to pull a block(m=20kg) so that the block will have an
acceleration of 3m/s on a rough surface? The coefficient of kinetic friction uk is 0.4.

Answers

Hi there!

Recall Newton's Second Law:
\(\Sigma F = ma\)

∑F = Net force (N)
m = mass (kg)

a = acceleration (m/s²)

The block will be experiencing two forces; a tension force in the direction of its acceleration (+) and a friction force (-).

\(\Sigma F = T - F_K\)

The equation for kinetic friction force is:
\(F_K = \mu mg\)

Using Newton's Second Law:
\(ma = T - \mu mg\)

Plug in the givens and solve for 'T':

\(T = ma + \mu mg\\ \\ T = m(a + \mu g)\\ \\ T = 20(3 + 0.4(9.8)) = \boxed{138.4 N}\)

through what potential difference δv must electrons be accelerated so they will have the same energy as the x-ray in part a?

Answers

To determine the potential difference (δV) required to accelerate electrons to have the same energy as the x-ray in part A, we need to understand that the energy of an electron is given by the equation E = qδV, where E is the energy, q is the charge of the electron, and δV is the potential difference.

In part A, the energy of the x-ray was mentioned, but the specific value is not provided. However, we can assume that the energy of the x-ray is given by E = hf, where h is Planck's constant (approximately 6.63 x 10^-34 J·s) and f is the frequency of the x-ray.

To have the same energy as the x-ray, the energy of the electron should be equal to the energy of the x-ray. Therefore, we can equate the two equations:

qδV = hf

Since we are solving for δV, we can rearrange the equation as:

δV = hf/q

The value of q is the charge of an electron, which is approximately \(-1.6 x 10^-19 C.\)
Now, let's consider an example to illustrate how to calculate the potential difference. Suppose the x-ray has a frequency of 5 x 10^18 Hz.

Using the given values, we can calculate δV as follows:

\(δV = (6.63 x 10^-34 J·s * 5 x 10^18 Hz) / (-1.6 x 10^-19 C)\)

After performing the calculations, we find that δV is approximately \(-1.64 x 10^5 V.\)
Therefore, to accelerate electrons to have the same energy as the x-ray in part A, a potential difference of approximately \(-1.64 x 10^5\)volts (V) is required.

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the electrons need to be accelerated through a potential difference of approximately 6.25 x 10^16 volts (V) to have the same energy as the x-ray in part A.

Explanation :

To determine the potential difference (δV) through which electrons must be accelerated to have the same energy as the x-ray in part A, we need to consider the energy equation for electrons in an electric field.

The energy (E) of an electron is given by the equation: E = qδV, where q is the charge of an electron.

Since we want the electrons to have the same energy as the x-ray, we can equate their energies:

E(electron) = E(x-ray)

qδV = E(x-ray)

Now, we know that the energy of an x-ray is typically measured in electron volts (eV). Let's say the energy of the x-ray is E(x-ray) = 10 keV (10,000 eV).

To find the potential difference, we need to rearrange the equation:

δV = E(x-ray) / q

Substituting the known values, we get:

δV = 10,000 eV / charge of an electron

The charge of an electron is approximately 1.6 x 10^(-19) C.

Therefore, the potential difference (δV) required for the electrons to have the same energy as the x-ray is:

δV ≈ 10,000 eV / (1.6 x 10^(-19) C)

Calculating this value, we get:

δV ≈ 6.25 x 10^16 V

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1.The circuit of a motor racing track is 3 km in length. In a race, a car goes 25 times round the
circuit in 30 minutes.
What is the average speed of the car?
A 75km/hour
B 90 km/hour
C 150 km/hour
D750 km/hour

Answers

If indeed the circuit of a vehicle racing circuit is 3 km long, the cruising velocity of the automobile is 75 km/h. A car completes 25 laps of the track in a race, which lasts 30 minutes.

What speed is typical?

The total distance something has traveled is multiplied by the amount of time it took to traverse that distance to arrive at its average speed. Speed is the current rate of movement of something. Average speed is the speed that a vehicle travels at on average over the course of a trip.

Which three methods are used to determine average?

The three primary average types are mean, median, and mode. Each of these methods operates a little bit differently and frequently yields typical values that are slightly different. The most widely used average is the mean. The mean value is obtained by adding up the all values and dividing the result by the total number of values.

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