how many joules are required to raise the temperature of 32 g of water from 12 °c to 54 °c ?

Answer:

I found this in an article "There is frequently the odor of sulfur. This is due to a reaction between traces of iron in the yolk and sulfur in the white. It happens only when the eggs have been overcooked. Perfectly cooked yolks are moist and deep orange."

Explanation:

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A certain solid metallic element has a density 7.87 g/cm3 and a molar mass of 55.85 g/mol. It crystallizes with a cubic unit cell, with an edge length of 286.7 pm. There are 4 atoms per unit cell in the crystal of this metallic element.

We are given: Density of the element = 7.87 g/cm3Molar mass of the element = 55.85 g/molEdge length of cubic unit cell = 286.7 pm = 286.7 × 10⁻¹² cmWe need to calculate the number of atoms per unit cell. For this, we need to calculate the volume of the unit cell and the volume occupied by one atom in the unit cell.Volume of the cubic unit cell = Edge length³= (286.7 × 10⁻¹²)³ cm³= 2.355 × 10⁻²⁶ cm³We know that, Density of the element = Mass of the element / Volume occupied by the element= (Number of atoms per unit cell) × (Molar mass of the element / Avogadro's number) / (Volume of the unit cell × 1.66 × 10⁻²⁴)where 1.66 × 10⁻²⁴ is the volume occupied by one atom in the unit cell (assuming that the atoms are touching each other along the diagonal of the cube).

Therefore, Number of atoms per unit cell = (Density of the element × Volume of the unit cell × Avogadro's number) / (Molar mass of the element × 1.66)  = (7.87 × 2.355 × 10⁻²⁶ × 6.022 × 10²³) / (55.85 × 1.66) ≈ 4Atoms are arranged in a unit cell in a definite pattern to give a crystalline solid. There are different unit cells (like, simple cubic, body-centered cubic, face-centered cubic, etc.) depending on the way the atoms are arranged. Each unit cell contains a fixed number of atoms. Therefore, by knowing the number of atoms per unit cell, we can determine the arrangement of the atoms in the crystal and the properties of the crystal.

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Answer:

Explanation:

During active transport, molecules move from an area of low concentration to an area of high concentration. This is the opposite of diffusion, and these molecules are said to flow against their concentration gradient.

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

Explanation:

Sodium and Lithium both belongs to same group (Group 1).

Group 1 element have 1 valence electron. That's why Group 1 element contains Na• , Li• one electron on it's atom.

Note -

It's not a dot . It's an electron.

Answer:

The words science and technology can and often are used interchangeably. But the goal of science is the pursuit of knowledge for its own sake while the goal of technology is to create products that solve problems and improve human life. Simply put, technology is the practical application of science.

Explanation:

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Answer:

0.67atm is the new pressure of the gas

Explanation:

To find one condition of a gas when pressure, volume and absolute temperature change we must use combined gas law:

\(\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}\)

Where P is pressure, V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

Replacing:

P₁ = 1.12atm

V₁ = 156mL

T₁ = 28.1°C + 273.15K = 301.25K

P₂ = ?

V₂ = 312mL

T₂ = 87.2°C + 273.15 = 360.35K

1.12atm*156mL / 301.25K = P₂*312mL / 360.35K

P₂ = 0.67atm is the new pressure of the gas

Answer:

Tick

1

2

4

6

Explanation:

magnesium is not a good conductor has some free electrons but it is not used that much in the industries because of other better alternatives.

You can tick number 5 as wlee. Good luck

Answer:

the answer is a

Explanation:

it'sa silver-white an earth metal

Answer:

alll I really know is that it includes smaller pools of water

In the reaction between a monosaccharide and a ferric ion, The carbonyl carbon is oxidized to a carboxyl group, the cupric ion is reduced.

Chemical reactions often involve color changes, temperature changes, gas evolution, or precipitate formation. Simple examples of everyday reactions are digestion, combustion, and cooking. The definition of reaction is a reaction. An example of a reaction is someone stopping their car at a stop sign. noun. response to stimuli.

The five basic types of chemical reactions are combination, decomposition, single exchange, double exchange, and combustion. By analyzing the reactants and products of a particular reaction, we can classify them into one of these categories. Some responses fit into multiple categories. It is modeled after the old Italian reaction, the French response, derived from the medieval Latin response (nominative to react). It is a noun of action formed in Late Latin from the past participle stem of the Latin reader.

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The given statement \(Fe_2O_3\) and \(Al_2O_3\) have similar chemical properties is  False.

While both  \(Fe_2O_3\) (iron oxide) and  \(Al_2O_3\)  (aluminum oxide) are metal oxides, they have different chemical properties due to the difference in the nature of the metal cations they contain. \(Fe_2O_3\) is a red-brown solid that is insoluble in water and acidic solutions, but soluble in strong acids. It is commonly used as a pigment, and also has applications in the production of steel and other iron-based materials.

\(Al_2O_3\) ,  on the other hand, is a white crystalline solid that is also insoluble in water, but is stable in both acidic and basic solutions. It has a wide range of applications, including as a refractory material, a catalyst support, and an abrasive.

In summary, while  \(Fe_2O_3\) and  \(Al_2O_3\)  are both metal oxides, they have different chemical properties and therefore have different uses and applications.

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The fraction of tetrahedral interstitial sites occupied by carbon atoms in the iron-carbon alloy, we can use the weight percent (wt%) of carbon provided.

First, let's assume we have 100 grams of the alloy. Since it contains 0.2 wt% carbon, we have 0.2 grams of carbon.
Next, we need to calculate the molar mass of carbon, which is 12.01 g/mol. Dividing the mass of carbon (0.2 g) by its molar mass (12.01 g/mol) gives us the number of moles of carbon present.

Now, we need to calculate the number of tetrahedral interstitial sites. In a crystal lattice structure, there are 4 interstitial sites per atom. Therefore, the number of tetrahedral interstitial sites is 4 times the number of iron atoms in the alloy.
To find the number of carbon atoms, we multiply the number of moles of carbon by Avogadro's number (6.022 x 10^23 atoms/mol).
Finally, to determine the fraction of occupied sites, we divide the number of carbon atoms by the number of tetrahedral interstitial sites.

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Answer:

Temperatures in the mesosphere decrease with altitude. There are few gas molecules in the mesosphere to absorb the Sun's radiation, the heat source is the stratosphere below. The mesosphere is extremely cold.

Explanation:

Explanation:

քʀa ʋċ ʀɛsքօռɖɛʀ ɛ sօ ʟɛʀ ɛ ɛռtɛռɖɛʀ օ զʊɛ ʋċ զʊɛʀ ʋɛʀ ռa քɛʀɢʊռta aɨ ʋċ քɛsզʊɨsaʀ օ զʊɛ ʋօċɛ զʊɛʀ ʋɛʀ ɛ ʀɛsքօռɖɛ օxɛ

Answer:

41.88375 g Fe

Explanation:

Using stoichiometry, we can do this problem. First, we put our given. Then we create an equation using the molar mass of Fe (found on the periodic table, which was 55.845 g Fe), and the resulting equation is:

\(0.75 mol Fe * \frac{55.845 g Fe}{1 mol Fe}\)

The mol Fe's cancel, and leave us with:

41.88375 g Fe

Good luck.

Answer:

d

Explanation:

Answer:

D

Explanation:

help me on my work please

Direct expansion systems require the vapour exiting the evaporator to be superheated to avoid liquid slugging, to improve the effectiveness of the evaporator and to maintain the stability of the compressor. (B) Forced draft and induced draft evaporators differ in the way air is introduced into them. (C) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant. (ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant and H2O is not classified as a refrigerant. (D) The partial pressure of hydrogen in the evaporator is 1.6 mmHg.

(a) Direct expansion systems are those in which the refrigerant in the evaporator evaporates directly into the space to be cooled or frozen. The evaporator superheat is used to make sure that only vapor and no liquid is carried over into the suction line and compressor. Superheating is required for the following reasons :

(b) Forced draft and induced draft evaporators differ in the way air is introduced into them. In an induced draft evaporator, a fan or blower is positioned at the top of the evaporator, and air is drawn through the evaporator from the top. In a forced draft evaporator, air is propelled through the evaporator by a fan or blower that is located at the bottom of the evaporator. Forced draft evaporators are frequently used in direct expansion systems because they allow for better control of the air temperature. Because the air is directed upward through the evaporator and out of the top, an induced draft evaporator is less effective at keeping the air at a uniform temperature throughout the evaporator.

(c) (i) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant.

(ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant.

(iii) H2O is not classified as a refrigerant.

(d) The function of hydrogen gas in an absorption refrigeration system (NH3/H2O/H2) is to increase the heat of reaction between ammonia and water.

The pressure of hydrogen gas in the evaporator of an absorption refrigeration system can be determined using the formula, Pa/Pb = (Ta/Tb)^(deltaS/R),

where Pa = partial pressure of hydrogen in the evaporator, Ta = evaporating temperature, Tb = condensing temperature, Pb = partial pressure of hydrogen in the absorber, deltaS = entropy change between the absorber and evaporator, R = gas constant.

Substituting the given values, Ta = −2.0 ∘C = 271 K ; Tb = 38.0 ∘C = 311 K ; Pb = atmospheric pressure = 1 atm ;

deltaS = 4.7 kJ/kg K ; R = 8.314 kJ/mol K

we get, Pa/1 atm = (271/311)^(4.7/8.314)

Pa = 0.021 atm or 1.6 mmHg

Therefore, the partial pressure of hydrogen in the evaporator is 1.6 mmHg.

Thus, Direct expansion systems require the vapour exiting the evaporator to be superheated to avoid liquid slugging, o improve the effectiveness of the evaporator and to maintain the stability of the compressor. (B) Forced draft and induced draft evaporators differ in the way air is introduced into them. (C) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant. (ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant and H2O is not classified as a refrigerant. (D) The partial pressure of hydrogen in the evaporator is 1.6 mmHg.

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The moles of water in 45.9 g  is 2.54 mol.

The moles are defined as the mass of substance with respect to the molar mass. The moles of sample are given by:

\(\rm Moles=\dfrac{Mass}{Molar\;mass}\)

The molar mass is the sum of mass of each element in the formula unit. The molar mass of water is 18.02 g/mol.

The given mass of water is 45.9 g.

Substitute the values for the moles of water:

\(\rm Moles=\dfrac{45.9 \;g}{18. 02 \;g/mol}\\\\ Moles=2.54\;mol\)

The moles of water in 45.9 g  is 2.54 mol.

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The carbonyl carbon in a carboxylic acid gives a 13C signal in the same region as a carbonyl carbon from a ketone or aldehyde in the range of 200 ppm.

The given statement is True.

An organic molecule known as an aldehyde is one in which the carbonyl group is joined to a carbon atom at the end of a carbon chain. A carbonyl group is linked to a carbon atom in the carbon chain to form an organic molecule known as a ketone. The 13C NMR peaks of aldehydes and ketones are easily distinguished and can be found in the 190 to 215 ppm range.

The carbon skeleton itself, not merely the proton bonded to it, is what the 13C NMR is directly about. We can determine how many different carbons or sets of equivalent carbons by counting the signals. We can determine how many hydrogen atoms are linked to each carbon by counting the signals that split.

A C-13 nucleus can be either aligned with or opposed to an external magnetic field because it behaves like a tiny magnet. Once more, with greater energies, the alignment that is in opposition to the field is less stable.

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It can be assumed that it is within the acceptable range for domestic use. Rapid temperature changes or high temperatures can also cause damage to pipes and fittings.

Task 3a: Discuss the significance of the measured water parameters collected from Hardap Dam for aquatic life.Water parameters are chemical, biological and physical characteristics of the water. They are important indicators of the quality of water. Hardap Dam is a habitat for a variety of aquatic life such as fish, birds, plants and insects. The measured water parameters for different depths include oxygen, pH and temperature.The concentration of oxygen in the water is crucial to aquatic life. Oxygen is required for respiration by aquatic animals. The surface oxygen concentration of 7.5 mg/L measured in Hardap Dam is adequate for most aquatic life. However, some fish species require higher concentrations of dissolved oxygen to survive. As water depth increases, the oxygen concentration decreases.

This can be seen in the decreasing oxygen concentration at depths below the surface. Low oxygen concentration can lead to suffocation of aquatic life, changes in species composition and nutrient cycling.PH is a measure of the acidity or alkalinity of water. Aquatic life requires a pH range of 6.5-9.0 to survive. The pH of 7.9 measured at the surface of Hardap Dam indicates that the water is slightly alkaline. The pH values for the deeper water layers were not provided but it can be assumed that they are likely to be similar. Extreme pH values can lead to stress and death of aquatic organisms.Temperature is an important parameter that influences the metabolic rates of aquatic organisms. Temperature affects the solubility of oxygen and other gases in water. It also determines the rate of biochemical reactions in organisms. The temperature of the water at the surface of Hardap Dam was not provided.

However, it can be assumed that it is within the range of tolerance for most aquatic organisms.

As water depth increases, temperature decreases. Rapid temperature changes or high temperatures can cause stress and death in aquatic organisms. Task 3b: Evaluate the significance of the measured water parameters in relation to the use of Hardap Dam water for domestic purposes.Water is a critical resource for human survival. Hardap Dam supplies water to communities for domestic purposes. The water quality is important to prevent the spread of diseases and illness. The measured water parameters for different depths of the dam include oxygen, pH and temperature.

These parameters affect the suitability of the water for domestic use.Oxygen concentration in the water is important for the removal of pollutants and odours. The surface oxygen concentration of 7.5 mg/L measured in Hardap Dam is adequate for this purpose. As the water depth increases, oxygen concentration decreases. Low oxygen concentration can lead to unpleasant tastes and odours in the water.PH is important for the taste and aesthetics of water. The pH of 7.9 measured at the surface of Hardap Dam is within the acceptable range for domestic use. Extreme pH values can cause water to taste bitter or metallic.

Changes in pH can also affect the corrosion of pipes and fittings.Temperature can affect the growth of microorganisms in the water. High temperatures can promote the growth of harmful bacteria such as E. coli. The temperature of the water at the surface of Hardap Dam was not provided. However, it can be assumed that it is within the acceptable range for domestic use. Rapid temperature changes or high temperatures can also cause damage to pipes and fittings.

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If an empty graduated cylinder has a mass of 31.780g. then, 50.0ml of an unknown liquid are added and the mass increases to 72.810g. then the  density of the unknown liquid is 0.8206 g/cc.

We must use the following formula to determine the density of the unidentified liquid:

density equals mass/volume

The mass of the liquid that has been added to the graduated cylinder must first be ascertained. We may achieve this by deducting the mass of the liquid-filled cylinder from the mass of the empty cylinder:

Mass of liquid equals mass of cylinder with liquid minus mass of cylinder with no liquid.

liquid mass = 72.810 g - 31.780 g

liquid mass is 41.030 g.

The volume of the liquid added, which is 50.0 mL, may then be calculated.

We can now enter these values into the density formula as follows:

The formula for density is mass/volume: 41.030 g/50 mL.

Since 1 millilitre (mL) equals 1 cubic centimetre (cc), we can simplify the units by converting to 1 cc:

densities equal 41.030 g per 50.0 cc

We can finally determine the density:

0.8206 g/cc is the density.

As a result, the unknown liquid has a density of 0.8206 g/cc.

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Answer:

a i believe

Explanation:

a

Answer:

Oxygen is relatively insoluble in water

Explanation:

Answer: Yes

Explanation:

Oxygen is relatively insoluble in water, its solubility being only 264 µM at 25 °C. That explains in part why you (and fish) require dedicated oxygen carriers in your blood to transfer sufficient oxygen around your body.

The resolution between Peak A and Peak B is approximately 55.71.

First, we need to calculate the peak width at half height (W1/2) for Peak A. The formula to do this is:
W1/2 = 2.35482 * sigma
Before we use the formula, we need to convert sigma from seconds to minutes by dividing it by 60:
sigma (in minutes) = 1.50 sec / 60 = 0.025 min
Now we can calculate W1/2 for Peak A:
W1/2 = 2.35482 * 0.025 min ≈ 0.0587 min
Next, we'll calculate the resolution between Peak A and Peak B. The formula for resolution is:
Resolution = (trB - trA) / ((W1/2A + W1/2B) / 2)
We have all the values needed:
trA = 2.75 min
trB = 3.15 min
W1/2A = 0.0587 min
W1/2B = 0.0988 min
Now we can calculate the resolution:
Resolution = (3.15 - 2.75) / ((0.0587 + 0.0988) / 2) ≈ 4.385 / 0.07875 ≈ 55.71

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The periodic properties of the d-block elements differ from the main group elements in that they are less sensitive and less reactive.

The periodic table is divided into blocks; s-block, p-block, f-block, and d-block. The d-block elements are also known as transition metals.

The s and p-block elements are known as the main group elements. Compared to these, the d-block elements have some different properties because of their partially filled d-orbitals.

However, the d-block elements still have many similar properties. These elements can still displace hydrogen from dilute acid and some of them can react with water under appropriate conditions.

The first row of these transition metals are found to be more reactive than the second and third row. However, they are not as reactive as the s-block and p-block elements.

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5. To solve question 5, we need to know the molecular formula of Uraninite, which is UO2.

So we need to know the molar mass of U and of O. We can look for it at the periodic table.

Molar mass of Uranium: 238.02891 g/mol

Molar mass of Oxygen: 15.999 g/mol

In the compound, we have 1 uranium and 2 oxygen.

So to calculate the percent of Uranium, we use a rule of 3:

270.03 ---- 100% (It is the molar mass of the compound)

238.0289 ---- x% (It is the molar mass of uranium)

270.09 * x = 238.0289 * 100

x = 23,802.89/270.09

x = 88.13%

So the percent of uranium in uraninite is 88.13%

Now for oxygen:

We have 2 atoms of oxygen in UO2, so we need to multiply its molar mass by 2: 15.999*2 = 31.998

Now we do the same rule of 3:

270.03 ---- 100% (It is the molar mass of the compound)

31.998 ---- x% (It is the molar mass of 2 atoms of oxygen)

x = 11.72%

The percent of oxygen in uraninite is 11.72%

Answer: As a second follow up to Question 3, uraranite is 88.13% uranium and 11.72% oxygen by mass.

The reaction of 1-ethylcycloheptene with MCPBA (meta-chloroperoxybenzoic acid) followed by sodium methoxide in methanol leads to the formation of an epoxide.

MCPBA is a peracid that is commonly used to convert alkenes into epoxides through an epoxidation reaction. It adds an oxygen atom to the double bond of the alkene, resulting in the formation of an oxirane ring.

In this case, when 1-ethylcycloheptene reacts with MCPBA, an epoxide is formed. The specific product will depend on the regiochemistry and stereochemistry of the starting compound. Without further information on the exact structure and conditions of the reaction, it is difficult to determine the exact product.

However, the general product can be represented as an epoxide derived from 1-ethylcycloheptene:

Epoxide

1−ethylcycloheptene+MCPBA+NaOMe/MeOH→Epoxide

The exact position and stereochemistry of the epoxide ring would be determined by the specific structure of 1-ethylcycloheptene and the reaction conditions used.

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