How has earth change during our current era?

Answer:

It would be 1.695%

The big difference between science and pseudo-science is a difference in attitude. While a pseudo-science is set up to look for evidence that supports its claims, a science is set up to challenge its claims and look for evidence that might prove it false

Answer:

I would say you are correct.

Explanation:

Answer:

I believe it'll be A (even though you chose it already).

Explanation:

Answer:

a. 82.68 g b. 9.8 min

Explanation:

a. The amount of gold deposited by 5 A current in 2 hrs 15 mins

Since charge Q = It where I = current = 5 A and time = 2 hrs 15 mins = 2 × 60 min + 15 min = 120 + 15 min = 135 min = 135 × 60 s = 8100 s

Q = 5 A × 8100 s

= 40500 C

Also, Q = nF where n = number of moles of gold deposited and F = Faraday's constant = 96500 C

n = Q/F = 40500 C/96500 C = 0.4195 moles ≅ 0.42 mole

Now n = m/M where m = mass of gold and M = molar mass of gold = 197

m = nM

= 0.42 × 197 g

= 82.68 g

b. The time taken for 6g of gold to be deposited.

We first find the number of moles of gold in 6g of gold

Since n = m/M and m = 6 g

n = 6/197 = 0.0305 mole

Q = It = nF

t = nF/I

= 0.0305 mol × 96500 C/5 A

= 2939.09 mol C

= 587.82 s

Changing t to minutes

587.82/60 s = 9.8 min

Answer:

Matter cannot be created or destroyed in chemical reactions.

Explanation:

Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions

Answer:

Mass is conserved in chemical reactions because the atoms are just rearranged. Any atoms of an element that you have in the reactants is still there in the products, just combined differently with other atoms. The mass of an atom is the same before and after the reaction, so the total mass of the reactants and products is equal.

Explanation:

Got the question right on an assignment

A compound forms a dense yellow precipitate when treated with iodine and sodium hydroxide. the compound must be: Acetophenone methyl ketone.

Sodium hydroxide is every now and then known as caustic soda or lye. it's by far a common ingredient in cleaners and soaps. At room temperature, sodium hydroxide is white, odorless strong. Liquid sodium hydroxide is colorless and has no odor. it could react violently with strong acids and with water.

Sodium hydroxide, also known as lye and caustic soda, is an inorganic compound with the formula NaOH. it is a white stable ionic compound that includes sodium cations Na⁺ and hydroxide anions OH⁻.

Manufacturers may additionally use sodium hydroxide to provide soaps, rayon, paper, products that explode, dyes, and petroleum merchandise. different obligations which can use sodium hydroxide include processing cotton cloth, steel cleaning and processing, oxide coating, electroplating, and electrolytic extraction.

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Wine was produced 37 years ago (1984 as usual year 15,2021) that is shown in the calculations below.

Reaction rate is calculated using the formula rate = Δ[C]/Δt, where Δ[C] is the change in product concentration during time period Δt. The rate of reaction can be observed by watching the disappearance of a reactant or the appearance of a product over time.

The time can be represented as follows:

t= 2.303\∧ log A0/A

∧= 0.693/t 1/2

The rate of a reaction is proportional to the reciprocal of the time taken. Rate α 1 time Rate is inversely proportional to time. Units: s-1, min-1 etc.

The given parameters are as follows:

t1/2=12.3

A0=5.5

A=0.688

t= 2.303/(0.693/12.3) log (5.5/0.688)

t=36.9

t=37 years

Thus, wine was produced 37 years ago (1984 as usual year 15,2021)

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Answer:

Transition metals (Group C) have different numbers of valence electrons compared to the other groups mentioned. Therefore option C is correct.

Transition metals (Group 3-12) have varying numbers of valence electrons. This is because their valence electrons are located in more than one energy level or subshell.

The number of valence electrons for transition metals can range from 1 to 12, depending on the specific element within the group. The varying numbers of valence electrons in transition metals contribute to their diverse chemical properties and ability to form multiple oxidation states.

Therefore, transition metals (Group C) have different numbers of valence electrons compared to the other groups mentioned.

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A laboratory owned by a company other than the physician's practice is typically referred to as an "independent laboratory" or an "external laboratory." These laboratories are separate entities from the physician's practice and may provide various diagnostic, testing, or research services. They operate independently and may serve multiple healthcare providers or organizations.

Independent laboratories play a crucial role in the healthcare industry by offering specialized testing, advanced technologies, and expertise that may not be available within a physician's practice. They often handle a wide range of laboratory services, including clinical chemistry, microbiology, pathology, genetic testing, and more.

Physicians and healthcare providers may send patient samples or specimens to independent laboratories for analysis and diagnostics. The results obtained from these laboratories can aid in accurate diagnoses, treatment decisions, and monitoring of patient health.

Overall, independent laboratories contribute to the comprehensive healthcare system by providing specialized laboratory services and collaborating with healthcare providers to deliver quality patient care.

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It requires 7458 calories of heat to raise the temperature of 225 grams of water from 10.5°C to 43.7°C.

To calculate the amount of heat required to raise the temperature of a substance, we can use the formula Q = m * C * ΔT, where Q represents the heat, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.

In this case, we have 225 grams of water, a specific heat capacity of 1.00 cal/g°C, and a temperature change of 33.2°C (from 10.5°C to 43.7°C).

Plugging these values into the formula:

Q = 225 g * 1.00 cal/g°C * 33.2°C

Q = 7458 cal

Therefore, it requires 7458 calories of heat to raise the temperature of 225 grams of water from 10.5°C to 43.7°C.

This calculation is based on the specific heat capacity of water, which is the amount of heat energy required to raise the temperature of water by 1°C per gram. The specific heat capacity of water is relatively high compared to other substances, which is why it takes a significant amount of heat to raise its temperature.

It's important to note that the specific heat capacity of water can vary slightly with temperature, but for practical purposes, we often assume a constant value of 1.00 cal/g°C.

By using the given values and the formula for heat, we can accurately determine the amount of heat required for this specific temperature change in the given mass of water.

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Answer:

C- transforemed or changed

Explanation:

matter can be changed by application of heat or cold

Answer:

A. the burning of fossil fuels within the Sun

Explanation:

Answer:

Basing on explanations below;

1. Endothermic reactions have a positive enthalpy while Exothermic reactions have a negative enthalpy.

2. Endothermic reactions take place in high temperatures while Exothermic reactions take place in low temperatures.

When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.

When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.

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The required volume of water to make the dilute solution of 0.5 M is 188 mL.

Required volume of water to dilute the stock solution will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

On putting values from the question to the above equation, we get

V₂ = (2)(47) / (0.5) = 188mL

Hence required volume of water is 188 mL.

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Yes, a reaction occurred. The net ionic equation for the reaction is Mg²+(aq) + 2 NH⁴+(aq) → Mg(NH³)²+(aq) + 2 H₂O(l).

This reaction is an acid-base neutralization reaction between the magnesium nitrate (Mg²+(aq) + 2NO³-(aq)) and the ammonium carbonate (2 NH⁴+(aq) + CO³ 2-(aq)).

The products of this reaction are a water molecule and a magnesium ammonium carbonate (Mg(NH³)²+) ion, which forms a milky white precipitate.

The precipitate is insoluble and is separated from the clear and colorless solution by centrifugation. The reaction is reversible and can be represented by the following equation: Mg(NH³)²+(aq) + 2 H₂O(l) → Mg²+(aq) + 2 NH⁴+(aq) + CO³ 2-(aq).

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25.8 g of NH₄NO₃ decomposed to produce 32.3 L of water vapor.  71.4 g of NH₄NO₃ are needed to produce 10.0 L of O₂.

a) To determine the number of liters of water vapor produced, we first need to calculate the moles of NH₄NO₃ that decompose:

The molar mass of NH₄NO₃ is:

M(NH₄NO₃) = 14.01 g/mol (N) + 4(1.01 g/mol) (H) + 3(16.00 g/mol) (O) = 80.05 g/mol

The moles of NH₄NO₃ can be calculated as:

moles NH₄NO₃  = mass/molar mass = 25.8 g / 80.05 g/mol = 0.322 moles  NH₄NO₃

From the balanced equation, we see that 4 moles of H₂O are produced for every 2 moles of  NH₄NO₃  that decompose, so we can calculate the moles of H₂O produced as:

moles H₂O = 4/2 x moles NH₄NO₃ = 4/2 x 0.322 = 0.644 moles H₂O

Finally, we can use the ideal gas law to calculate the volume of water vapor produced at 350 degrees C and 0.950 atm:

PV = nRT

V = nRT/P

V = (0.644 mol) (0.0821 L·atm/mol·K) (623 K) / (0.950 atm) = 32.3 L

Therefore, 25.8 g of NH₄NO₃ decomposed to produce 32.3 L of water vapor.

b) To determine the grams of NH₄NO₃ needed to produce 10.0 L of O2, we can use the same approach, starting with the ideal gas law:

The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.

The moles of O2 needed to produce 10.0 L can be calculated as:

moles O2 = V/STP = 10.0 L / 22.4 L/mol = 0.446 moles O2

From the balanced equation, we see that 2 moles of  NH₄NO₃ decompose to produce 1 mole of O2, so we can calculate the moles of NH₄NO₃ needed as:

moles NH₄NO₃= 2/1 x moles O2 = 2/1 x 0.446 = 0.892 moles NH4NO3

Finally, we can use the molar mass of NH4NO3 to calculate the grams needed:

mass NH₄NO₃ = moles NH₄NO₃ x molar mass = 0.892 mol x 80.05 g/mol = 71.4 g

Therefore, 71.4 g of NH₄NO₃ are needed to produce 10.0 L of O₂.

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Answer:

B; 229g of Zn

Explanation:

To convert mol of Zn, we must find the atomic mass of Zn. This is 65.38.

Multiply 3.5 mol of zn by 65.38.

3.50 mol of Zn*65.38g = 228.83g of Zn

Therefore, the mass = 229g of Zn

Answer:

The total number of protons and neutrons in the nucleus of an atom is called mass number.

Answer:

mass number also called nucleon number and it's the total number of neutron and proton in an atomic nucleus.

✅Magnetic materials are always made of metal, but not all metals are magnetic. Iron is magnetic, so any metal with iron in it will be attracted to a magnet. Steel contains iron, so a steel paperclip will be attracted to a magnet too. Most other metals, for example aluminium, copper and gold, are NOT magnetic.

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sedimentary rocks are rocks that are combined from other rocks pressed into one.

The specifics of when a month starts differ from calendar to calendar; some rely on new, entirety, or crescent moons, while others do complex computations.

In contrast with solar calendars, which annual cycles are only based on the solar year, a lunar calendar includes a calendar built on the monthly phases of the Moon's aspects (synodic months, lunations). The Islamic calendar is the most extensively used lunar calendar.

A lunisolar calendar, in which the lunar months come into alignment to the solar year by some process of intercalation, such as by inserting a leap month, is distinguished from a strictly lunar calendar. The specifics of when a month starts differ from calendar to calendar; some rely on new, entirety, or crescent moons, while others do complex computations.

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The polypeptide formed by the letters L, I, V, and E, is shown in the image attached below. these letters represent the amino acids Leucine, Isoleucine, Valine, and Glutamate. On the other hand, its pI, isoelectric point, is 3.13.

The isoelectric point (pI) is the pH at which a molecule carries no net electrical charge. It can be calculated using the formula: pI = (pKa₁ + pKa₂) / 2, where pKa₁ and pKa₂ are the pKa values of the two most closely related ionizable groups.

The ionizable groups are:

In this case, the two most closely related ionizable groups are the carboxylic acid group (COOH) with a pKa of 2.19 and the side chain carboxyl group (R-COOH) with a pKa of 4.07. Using these values in the formula above, we get:

So, the isoelectric point for this molecule is approximately 3.13.


Finally, to form a peptide bond, two amino acids are joined together by a condensation reaction, in which the alpha-carboxyl group of one amino acid reacts with the alpha-amino group of another amino acid, releasing a molecule of water. This reaction is catalyzed by an enzyme called peptidyl transferase, which is present in ribosomes. The resulting bond between the two amino acids is a peptide bond, which links the carboxyl group of one amino acid to the amino group of the other amino acid, forming a peptide chain. This process is repeated over and over to create a polypeptide.

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The statement "An acetylene cylinder is filled with a monolithic filler and acetone before acetylene gas is pumped into it." is True. When storing acetylene gas, it is commonly done in specialized cylinders to ensure safety.

These cylinders are designed to contain the acetylene gas at high pressure. Prior to filling the cylinder with acetylene gas, a monolithic filler material, often porous material like diatomaceous earth, is placed inside the cylinder. The purpose of the filler material is to provide a large surface area for the acetone to be absorbed.

Acetone is then added to the cylinder. Acetone has the ability to dissolve acetylene gas more effectively than plain gas alone. It acts as a solvent and helps to stabilize the acetylene gas inside the cylinder. The presence of acetone ensures that the acetylene gas is stored safely and prevents it from becoming unstable or explosive.

Once the monolithic filler and acetone are in place, the cylinder is ready to be filled with acetylene gas. The gas is pumped into the cylinder, and due to the properties of the filler and acetone, it is absorbed and stored within the cylinder. This process allows for the safe transportation and storage of acetylene gas, reducing the risk of accidents or explosions associated with this highly reactive gas.

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To find the solubility of AgCl in a solution of MsCl2, we need to use the common ion effect. MsCl2 will dissociate in water to form Ms+ and Cl- ions. The Cl- ions will combine with the Ag+ ions from the dissociation of AgCl to form more AgCl, which will reduce the solubility of AgCl.

The balanced equation for the dissociation of AgCl is:

AgCl(s) ⇌ Ag+(aq) + Cl-(aq)

The Ksp expression for this reaction is:

Ksp = [Ag+][Cl-]

We know that the Ksp of AgCl is 1.8 x 10^-10. Let's assume that x is the solubility of AgCl in the presence of MsCl2.

In the presence of MsCl2, the Cl- concentration will be [Cl-] = [Cl-]initial + [Cl-]dissociated = 2[Cl-]initial, where [Cl-]initial is the initial concentration of Cl- ions from MsCl2.

Since the Ag+ concentration is equal to the Cl- concentration in a saturated solution of AgCl, we can write:

Ksp = [Ag+]^2 = (2[Cl-]initial + x)^2

Solving for x, we get:

x = (-2[Cl-]initial ± √(4[Cl-]initial^2 + 4Ksp))/2

We can simplify this equation to:

x = (-[Cl-]initial ± √([Cl-]initial^2 + Ksp))/1

Substituting the values, we get:

x = (-[Cl-]initial ± √([Cl-]initial^2 + 1.8 x 10^-10))/1

Therefore, the solubility of AgCl in a solution of MsCl2 can be calculated using the above equation.

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Answer:B

Explanation: