Answer:
Explanation:
The main difference between these two is that a star has a solid rock and gas surface, while a comet has tail of dust and gas. A star is a giant mass of rock and gas that follows a set eliptical path. Comets on the other hand are made of ice and dust with some gases and usually travel in a straight path. This is why they have a tail of dust and gas which is the ice burning up behind it as it travels at extremely high speeds.
Answer: A: A star has a solid rock and gas surface, while a comet has tail of dust and gas.
Explanation:
To test the effectiveness of a new nutrient supplement one group of identical mice is given the supplement and the other group is not given any thing .which is the most complete list of the parts of the
experiment presented in this scenario.
The most complete list of the parts of the experiment presented in this scenario include:
Dependent variableExperimental groupControl group.What is Experiment?This refers to the procedures which are performed in other to support or refute a hypothesis. It is also used to ascertain the authenticity of the claim by other people such as scientists etc who review it.
In the scenario given, we were told that the group of identical mice is given the supplement and the other group is not given any thing which means that the control group is the one which wasn't given anything while the ones who were given something is the experimental group.
The dependent variable is the supplement which was given to the mice and is therefore the reason why option B was chosen as the correct choice.
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The temperature at which carbon dioxide sublimes is about 195 K. What is this
temperature in units of degrees Celsius?
-78° Celsius is the temperature in units of degrees Celsius.
What is temperature?Temperature is the measure of hotness or coldness expressed in terms of any of several scales, including Fahrenheit and Celsius.
195 Kelvin = 195 - 273.15 = -78.15 Celsius.
-78° Celsius is the temperature in units of degrees Celsius.
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Stamples of heterogeneous equilibria. FeO(s) + CO(g) = Fe(s) + CO₂(g) II. H₂(g) L₂(g) = 2HI(g) III. CO₂(g) + C(s) = 2CO(g) IV. N₂(g) 3H₂(g) + 2NH3(g) Identify I.
An example of heterogeneous equilibrium is:
I. FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g)What is heterogeneous equilibrium?Heterogeneous equilibrium refers to an equilibrium state in a chemical reaction where the reactants and products exist in different physical states or phases. It occurs when substances in different phases, such as solids, liquids, and gases, are involved in a chemical reaction.
Considering the given equations:
The equation I: FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g) represents a heterogeneous equilibrium.
This is because the reactants and products involve different phases (solid and gas). FeO is a solid (s), CO is a gas (g), Fe is a solid (s), and CO₂ is a gas (g). The reaction involves the conversion of a solid and a gas to another solid and a gas, and the equilibrium is established between these different phases.
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HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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Tectonic plates are huge pieces of HHEOITERPSL __________________ that slowly move on the HHTNSESEPROAE ____________________.
Tectonic plates are huge pieces of EARTH'S LITHOSPHERE that slowly move on the ASTHENOSPHERE.
What is tectonic plate?A tectonic plate is a large, rigid slab of solid rock that makes up the Earth's outermost layer, known as the lithosphere. The lithosphere is broken up into a series of tectonic plates that are in constant motion, driven by the flow of the Earth's mantle beneath them. There are several major tectonic plates, including the North American, South American, African, Eurasian, Australian, Pacific, and Antarctic plates, as well as several smaller plates. The movement of tectonic plates is responsible for a variety of geological phenomena, such as earthquakes, volcanic eruptions, mountain building, and the formation of oceanic trenches and ridges. The theory of plate tectonics provides the framework for understanding the dynamics of the Earth's crust and how it has evolved over time.
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what properties of a natural resource make it useful for humans as a materials or energy source?
The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.
What are natural resources?The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.
Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.
Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.
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0.542 grams of an unknown gas is added to a 3.0 Liter vessel. The temperature is 28°C and the pressure is 16 psi. Which of the following could be the gas added to thevessel?N2HeH2O2ArO F2Kr
Answer: the unknown gas mentioned by the question is He
Explanation:
The question requires us to identify the gas (choosing from a list given), considering the information provided.
The following data was provided by the question:
mass of gas = m = 0.542 g
volume of gas = V = 3.0 L
temperature = T = 28 °C
pressure of gas = P = 16 psi
To solve this problem, we'll need to go through the following steps:
1) Calculate the number of moles of gas considering the volume, temperature and pressure given (note that we'll need to convert the pressure and temperature to the appropriate units);
2) Calculate the molar mass of the unknown gas from the mass given by the question and the number of moles calculated;
3) Compare the molar mass obtained to the list of gases provided.
Next, we'll go through these steps to solve the problem:
1) We can apply the equation of ideal gases, shown below, to calculate the number of moles of gas using the information provided by the question:
\(P\times V=n\times R\times T\)where R is the constant of gases (0.08205 L.atm/K.mol.
Rearranging this equation to calculate n (number of moles), we'll have:
\(n=\frac{P\times V}{R\times T}\)Note that, due to the units of R (L.atm/K.mol), we'll need to convert the temperature from °C to Kelvin and the pressure from psi to atm:
\(\begin{gathered} T(K)=T(°C)+273.15 \\ T(K)=28°C+273.15=301.15K \end{gathered}\)\(1atm=14.696psi\rightarrow P=16psi\times\frac{1psi}{14.696atm}=1.09atm\)Therefore, the volume, temperature and pressure that will be applied to the equation of gases are, respectively, 3.0 L, 301.15K and 1.09 atm:
\(n=\frac{P\times V}{R\times T}\rightarrow n=\frac{1.09atm\times3.0L}{0.08205atm.L/K.mol\times301.15K}=0.13mol\)Therefore, the amount of unknown gas in the container is 0.13 mol.
2) Next, we must use the mass given (0.542g) and number of moles calculated (0.13 mol) to obtain the molar mass of the gas.
Knowing that the number of moles of a substance can be obtained by dividing the mass of the sample by its molar mass, we can write:
\(\begin{gathered} number\text{ of moles \lparen mol\rparen = }\frac{mass\text{ \lparen g\rparen}}{molar\text{ mass \lparen g/mol\rparen}}\rightarrow n=\frac{m}{M} \\ M=\frac{m}{n} \end{gathered}\)Thus, applying the values obtained so far:
\(M=\frac{m}{n}=\frac{0.542g}{0.13mol}=4.1g/mol\)Therefore, the molar mass of the unknown gas is 4.1 g/mol.
3) At last, we must compare the molar mass obtained with the gases provided by the question. Among the gases given, only He presents molar mass close to the value obtained (molar mass of He gas = 4.00 g/mol).
Therefore, the unknown gas mentioned by the question is He.
How much work is done by a person who lifts a weight 2 meters off of the ground by using a force of 55 Newtons?
O 27.5 Joules
O 57 Joules
53 Joules
O 110 Joules
Answer:
D. 110 Joules
Explanation:
Work = Force x Distance
The given force here is 55 Newtons, and the distance the object moved against the force is 2 meters.
Therefore 2 x 55 = 110 Joules of Work.
Hope this helped!
Use the dropdown menus to complete the following statements explaining the concept of freezing point depression.
Hint: It may be helpful to review the introduction section of FPD in your lab manual.
In a pure solvent ____
The presence of solute ___
The solvent's freezing point ___
In a pure solvent, the freezing point is a constant. The presence of solute causes the freezing point of the solvent to decrease. The solvent's freezing point is depressed.
A solution's freezing point is lower than that of the pure solvent's. This indicates that freezing can only take place when a solution is lowered to a lower temperature than the pure solvent. Road salting in water is a relatively prevalent example of this occurrence in daily life. At 0°C, pure water freezes. In a pure solvent, the freezing point is the temperature at which the solvent will form a solid. The presence of solute particles interferes with the ability of the solvent molecules to form a solid, causing the freezing point to decrease. The solvent's freezing point is thus lowered or "depressed" by the addition of solute particles.
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In an experiment, a student wants to increase the rate of a reaction that involves gases. Which change to the reactants would accomplish this?
The change to the reactants that would accomplish increase in reaction rate is increase in concentration of reactant.
Reaction rate is the speed at which a chemical reaction proceeds.
It is expressed in terms of either the concentration of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time.
Here, a student wants to increase the rate of a reaction that involves gases.
The increase in reaction rate will be result of increase in concentration of reactant.
In case of gases, it can be done via:
Increasing the pressure and decreasing the volume.
Hence, the change to the reactants that would accomplish increase in reaction rate is increase in concentration of reactant. Increasing the pressure and decreasing the volume are ways to accomplish this.
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*Will give Brainliest* What is the average atomic mass of one molecule of methane, which has one 12C atom and four 1H atoms?
Answer:
The atomic mass of methane (CH4)is 12 amu for the carbon plus 4 x 1 amu for the four hydrogens, for a total of 16 amu. Therefore, the molar mass of methane is 16g.
How does the conflict in this passage develop a theme?
Mrs. Linde creates a conflict by promising something she cannot give to Krogstad, which develops the theme that empty promises can destroy relationships.
Krogstad continues the conflict by choosing clearing his name over having a life with Mrs. Linde, which develops the theme that you must often choose yourself over others.
Krogstad creates a conflict by deceiving Mrs. Linde about his intentions, which develops the theme that, in love, actions speak louder than words.
Mrs. Linde resolves the conflict by committing to a new life with Krogstad, which develops the theme that new beginnings are always possible.
Answer:
The answer is option D
Explanation:
This is because Mrs. Linde resolves the conflict by committing to a new life with Krogstad, which develops the theme that new beginnings are always possible.
The conflict in this passage develops a theme, as Mrs. Linde resolves the conflict by committing to a new life with Krogstad, which develops the theme that new beginnings are always possible. Option D.
What is conflict?A conflict is defined as a battle or disagreement. A dispute over parenting techniques is an example of conflict, the two parties not seeing eye to eye.
In conclusion, The passages conflict develops the theme that new beginnings are always possible.
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how do you balance this equation
2h2s+3o2+so2
The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.
The unbalanced equation is:
2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)
Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)
Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:
2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
To remove the fractional coefficient, we can multiply all coefficients by 2:
4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:
4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
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When zinc reacts with copper sulfate solution, zinc sulfate solution and copper are formed.(i) An experiment was carried out to measure the temperature change when zinc powder reactswith copper sulfate solution.initial temperature of copper sulfate solution = 20 °Cfinal temperature of mixture after the reaction = 46 °CExplain what the temperature readings show about the type of heat change that occurs duringthis reaction.
The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.
In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.
The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.
During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.
The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.
The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.
In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.
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Nitrogen (iv) oxide is passed through the combustion tube before copper is heated.Give a reason for this?
to generate steam which act on copper
how much of ethene gas (C2H4) is contained in a 19.8 L tank that has a pressure of 2.52 atm at a temperature of 306 K
1.98 moles of ethene gas is contained in a 19.8 L tank that has a pressure of 2.52 atm at a temperature of 306 K.
What is an ideal gas law ?The ideal gas law states that the pressure, temperature and volume of a gas are associate to each other. It is also called as real gas law.
Given:
Volume = 19.8 L
Pressure = 2.52 atm
Temperature = 306 K
Number og moles of ethene gas = ?
R = gas constant = 0.0821
According to ideal gas law,
PV = nRT
n = PV/RT
By substituting given values in above equation and we get
n = 2.52 × 19.8 / 0.0821 × 306
n = 1.98 moles
Thus, 1.98 moles of ethene gas is contained in a 19.8 Litre.
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Which of the following molecules has a bent shape?
O A. CO2
O B. H20
O C. BeCl2
O D. NH3
The average birth weight of domestic cats is about 3 ounces. Assume that the distribution of birth weights is Normal with a standard deviation of 0 4 ounce.
a. Find the birtn weight of cats at the 90th percentile.
b. Find the birth weight of cats at the 10th percentile
The birth weight of cats at the 90th percentile would be approximately 3.7 ounces. b. The birth weight of cats at the 10th percentile would be approximately 2.3 ounces.
What are the methods of calculating weight?There are three main methods of calculating weight:
1. Balance Beam Scale: A balance beam scale is an example of a mechanical weighing system. It uses a set of calibrated weights to measure the weight of an object.
2. Digital Scale: A digital scale uses an electronic or digital readout to display the weight of an object.
3. Calipers: Calipers are devices used to measure the distance between two points, such as thickness or diameter. They come in various sizes and shapes, depending on the type of measurement the user wants to take.
What is birth weight?Birth weight is the weight of a baby at the time of birth. It is usually measured soon after delivery, with a special baby scale, though sometimes the baby's weight is estimated. The normal range of birth weight is anywhere between 5 lbs 8 oz and 10 lbs, though preterm or premature babies may be significantly lighter. A baby's birth weight is important because it can provide a clue to the baby's overall health. High birth weights may indicate an underlying medical condition, and low birth weights can be a sign of premature or difficult delivery and health risks associated with such a delivery.
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Which type of government is specific to a city or town? state-federal municipal administrative
Answer:
municipal
Explanation:
I got state and federal wrong and after it told me it was municipal and if you where wondering I got the answers wrong on purpose to answer this one the fastest but at least I am going you the correct answer not like other people who just say a answer just because they want to but I actually got the right answer but yeah. BYEEEEEE
Answer:
municipal
Explanation:
did it and got it right
i hope you have you a great day
How might a problem with Lucille’s respiratory system or circulatory system make it difficult for Lucille to play soccer?
A certain shade of blue has a frequency of 7.08×1014 Hz. What is the energy of exactly one photon of this light? Planck's constant ℎ=6.626×10−34 J⋅s.
Answer:
We have the final answer as
\(4.69 \times {10}^{ - 19} \: \: J\)
Explanation:
To find the energy of a photon of this light we use the formula
E = hfwhere
E is the energy
f is the frequency
h is the Planck's constant which is
6.626 × 10-³⁴ Js
From the question
f = 7.08×10¹⁴ Hz
We have
E = 7.08×10¹⁴ × 6.626 × 10-³⁴
We have the final answer as
\(4.69 \times {10}^{ - 19} \: \: J\)
Hope this helps you
Rank the following atoms in order of decreasing electronegativity.
a. Na, Li, K
b. K, Sc, Ca
c. As, Sn, S
In the first option , the order of decrease in electronegativity is Li, Na and K. In second option, the order is Ca, K, Sc The order in the third group is S, As, Sn.
What is electronegativity ?Electronegativity of an atom is the ability of its nucleus to attracts the share pair of electrons towards it. Elements like, fluorine, oxygen, nitrogen etc .are highly electronegative.
In periodic table, along a period electronegativity increases. Whereas down group, electronegativity decreases. The first groups elements are Li, Na , K and Cs and Fr. Hence, electronegativity decreases from Li to K.
Among, K, Sc and Ca, Ca is comparatively electronegative than K. Sc is a transition metal and not electronegative. In the last group the S is mot electronegative than As more than Sn.
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A lab technician dilutes 230 mL of a 4.0 mol/L sodium chloride solution to a final volume of 990 mL. What is the final concentracion of this solution? Pls provide your answer.
PLSS HELP
The final concentration of the solution would be 0.93 M.
Dilution problemAccording to the dilution principle, the number of moles before dilution must be equal to the number of moles after dilution. This can be mathematically represented by:
\(m_1v_1 = m_2v_2\)
Where \(m_1\) and \(m_2\) are initial and final concentrations, while \(v_1\) and \(v_2\) are initial and final volumes of the solution.
In this case:
\(m_1\) = 4.0 M
\(v_1\) = 230 mL
\(v_2\) = 990 mL
Substituting each of these variables into the dilution equation and making the final concentration the subject of the formula, we have:
\(m_2\) = \(m_1v_1/v_2\)
= 4x230/990
= 0.93 M
In other words, the final concentration after diluting 230 mL of a 4.0 mol/L sodium chloride soltuion to a final volume of 990 mL would be 0.93 M.
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Mathematical Representations Quick Check
How does the formation of water from hydrogen and oxygen demonstrate the conservation of mass? (1 point)
Storm
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same
number of atoms as the reactants.
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of atoms as the reactants
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
What is the conservation of mass?The conservation of mass is a fundamental principle in physics and chemistry that states that the total mass of a system remains constant, regardless of any changes that take place within the system. In other words, mass cannot be created or destroyed, only transformed from one form to another.
This law applies to both physical and chemical processes, and is a key concept in fields such as thermodynamics, mechanics, and material science. It forms the basis for our understanding of the behavior of matter and energy in the universe, and is widely used in scientific and engineering calculations and experiments.
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Answer:
1. the reactants and the products have the same number of atoms of the same elements
2. the mass of one titanium atom is equal to the mass of four carbon atom
3. The atomic mass of the reactants equals the atomic mass of the product, and the product has the same number of atoms as the reactants.
4. 80amu
5. A molecule with two atoms combined with a molecule with three atoms to produce a molecule with a mass of 84 u.
Explanation: got 100% hope you get the same!
I have 4 oribitals and 6 valence electrons
Which element am i?
answer choices
a. Lead (Pb) I’m a metal
b. Selenium (Se) i’m metal
c. Lead (Pb) I’m a nonmetal
d. selenium (Se) I’m a non metal
Answer:
d. selenium (Se) I’m a non metal
Explanation:
What we know about the element in view is that it has:
4 orbitals
6 valence electrons
The orbitals are the energy levels in the element.
Valence electrons are the outermost shell electrons.
The orbitals tells us the periods in which an element belongs. Since we have 4 orbitals, this suggests that our element belongs to the 4th period.
The number of valence electrons tells us the group in which the element could be found. Since we have 6 valence electrons, the group number is 6.
Therefore, the element is period 4 and group 6 is selenium. Selenium is a non-metal.
Is SiO2 London Dispersion, Dipole-Dipole, or Hydrogen Bonding?
Answer: SiO2 has more electrons and stronger London dispersion forces.
SiO2 is non-polar and has covalent bonds.What is the Mass in grams of 1 formula unit or molecule of epsom salt MgSO4●7H2O?
MgSO4.7H2O
First of all, we need to calculate the molar mass of this molecule, using the periodic table.
Let's take each atomic mass of the elements that form this molecule from the periodic table.
Mg = 24.30 u
S = 32.06
O = 15.99 u
H = 1.007 u
Now, we have to do this:
Molar mass (g/mol) = 1 x 24.30 + 1 x 32.06 + 4 x 15.99 + 14 x 1.007 + 7 x 15.99
Molar mass = 246.3 g/mol
We have to be careful with this result because 246.3 g is the mass of 1 mole of MgSO4.7H2O and we want the mass of 1 formula unit or molecule.
Pay attention to this:
1 mole of MgSO4.7H2O = 246.3 g = 6.022 x 10^23 formula units or molecules of MgSO4.7H2O
(We want the mass of 1 molecule and we have just calculated the mass of 6.022x10^23 molecules)
----------------------------------------------------------------------------------------------------------------
For 1 formula unit or molecule:
246.3 g of MgSO4.7H2O ------------- 6.022 x 10^23 formula units or molec.
x ------------- 1 formula unit or molec.
\(x\text{ = }\frac{1formula\text{ unit x 246.3 g}}{6.022x10^{23}formula\text{ units}}=4.09x10^{-22}g\)Answer: The mass of 1 formula unit or molecule of MgSO4.7H2O = 4.09x10^-22 g
A graduated cylinder contains 50.0 ml of water. A 23.5 g piece of unknown metal is carefully dropped into the cylinder. When
the metal is completely covered with water, the water rises to the 53.4 ml mark. What is the density of the unknown piece of
metal in g/ml?
To find the density of the unknown piece of metal, we can use the formula:
Density = mass / volume.
How to find the density ?The volume of the metal can be calculated by deducting the starting water volume (50.0 ml) from the final water volume (53.4 ml) after the metal is introduced. We know the mass of the unknown metal is 23.5 g.Volume of metal = 53.4 ml - 50.0 ml = 3.4 ml.Now we can substitute the values into the density formula: Density = 23.5 g / 3.4 ml = 6.9 g/ml.Therefore, the density of the unknown piece of metal is 6.9 g/ml.To know more about density , check out :
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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."
Here are possible words that can be made from this jumbled word:
Sky: Referring to the atmosphere above the Earth.
Zig: Describing a series of sharp turns or angles.
Text: Referring to written or printed words.
Six: The number following five and preceding seven.
It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.
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a tightly packed box of crackers contains 250 g of crackers and measures 7.0cm X 17.0.cm X 19.0 cm. what is the average density in kilograms per liter of the crackers in the package? Assume that the unused volume is negligible.
The average density in kilograms per litre of the crackers that measures 7.0cm X 17.0.cm X 19.0 cm is 0.1105Kg/L.
How to calculate average density?The density of a substance is a measure of the mass of matter contained by a unit volume. The density of a substance can be calculated using the following formula:
D = m/v
Where;
D = densitym = massv = volumeAccording to this question, a tightly packed box of crackers contains 250 g of crackers and measures 7.0cm X 17.0.cm X 19.0 cm.
Volume = 7.0cm X 17.0.cm X 19.0 cm = 2261cm³
1 cubic centimetre = 0.001 litre
2261cm³ = 2.261L
Density of the crackers = 0.25kg ÷ 2.261L
Density = 0.1105Kg/L
Therefore, the average density in kilograms per litre of the crackers that measures 7.0cm X 17.0.cm X 19.0 cm is 0.1105Kg/L.
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