There are two types of irreducible representations of the group G of order 27: those of degree 1 and those of degree 3. The correct option is (a)
Given, G is a non-abelian group of order 27.
Therefore, its only possible composition series is as follows:`G -> Z(G) -> 1`.Therefore, G has exactly one non-trivial normal subgroup which is Z(G).Hence, G/Z(G) is a simple group of order 3.Using Schur’s lemma, it can be shown that the only irreducible representations of this group are of dimension 1 and 2.Hence, any irreducible representation of G must have degree either 1 or 3.Using the character table of G, it can be shown that there are 8 irreducible representations of degree 1 and 6 irreducible representations of degree 3.(b) There are three conjugacy classes of G.
If $\pi$ denotes a permutation representation of G on a set of order 27, then the size of each conjugacy class is equal to the size of the orbit of the corresponding permutation under $\pi$.For degree 1 irreducible representations of G, the corresponding permutation representations are permutation representations on one element.
For degree 3 irreducible representations of G, the corresponding permutation representations are permutation representations on three elements.There are eight degree 1 irreducible representations of G which correspond to the trivial representation and the 7 characters which take non-trivial values on Z(G).
Hence, there is only one conjugacy class of G for these characters.There are six degree 3 irreducible representations of G which correspond to the 6 non-trivial characters which take the same values on all non-central elements of G.
Hence, there are only two conjugacy classes of G for these characters.
One of these classes consists of the elements of G of order 3, and the other class consists of the elements of G of order 9.Therefore, the total number of conjugacy classes of G is 3.
There are two types of irreducible representations of the group G of order 27: those of degree 1 and those of degree 3. There are 8 irreducible representations of degree 1 and 6 irreducible representations of degree 3. The total number of conjugacy classes of G is 3. Therefore, the correct option is (a)
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What causes atoms to bond together
?!?
Answer:
electrostatic attraction
Explanation:
Atoms form chemical bonds with other atoms when there's an electrostatic attraction between them. This attraction results from the properties and characteristics of the atoms' outermost electrons, which are known as valence electrons.
ILL GIVE BRAINLY AND THIS IS 15 POINTS PLZZZ HELPPPPPP
The best thermal insulators _____________________.
have free electrons.
are metals.
conduct heat well.
are gases.
Answer:
have free electrons
Explanation:
they are loosely bound and free to move through the material
An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?
The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,
F = kx
Therefore,
k = F/x
We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,
K = 50.174/0.25 N/m
K = 200.696 N/m
Therefore, The Spring Constant is 200.696 N/m
On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:
h = \(1/2 kx^{2}\)
We know that k=200.696 N/m and x=0.25 m. Therefore the height is:
h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)
h = 2.5087 m
Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
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Experiment 1 Understanding of low voltage electrical apparatus 1. Purpose of the experiment 1) Master the usage of common electrical tools. 2) Master the common identification methods of low pressure. 3) Master the function of low-voltage electrical apparatus and their correct application. 2. Experiment contents and requirements Observe common low-voltage apparatus, understand their structure, and be able to draw electrical symbols and write text symbols. 3. Experiment report and content 1) Purchase the uniform standard experimental report paper in the academic affairs office. 2) Fill in according to the items specified in the test report. 3) Draw the electrical symbols and write the text symbols according to the observed low-voltage electrical components. 4) According to the observed low-voltage electrical components, the basic working principle and function are briefly described
Experiment 1 Understanding of low voltage electrical apparatus: Purpose of the experiment1) Master the usage of common electrical tools.2) Master the common identification methods of low pressure.3) Master the function of low-voltage electrical apparatus and their correct application. Experiment contents and requirements
The experiment requires observing common low-voltage apparatus and understanding their structure. The following requirements are required:1. Drawing electrical symbols2. Writing text symbols3. Describing the basic working principle and function of low-voltage electrical components that are observed in the experiment report and content for the experiment report, follow this steps:1. Purchase the uniform standard experimental report paper in the academic affairs office.2. Fill in according to the items specified in the test report.3. Draw the electrical symbols and write the text symbols according to the observed low-voltage electrical components.4.
According to the observed low-voltage electrical components, the basic working principle and function are briefly described.
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what generalization can you make about the relative speeds that the sun and the stars move through the sky over the course of a day?
The generalization that can be made about the relative speeds that the sun and the stars move through the sky over the course of a day is that the sun appears to move much slower than the stars. This is because the sun is much closer to Earth than the stars, so its movement is more noticeable.
The stars, on the other hand, are much farther away and their movement is less noticeable.
Another way to think about this is to consider the fact that the Earth is rotating on its axis. As the Earth rotates, the sun appears to move across the sky at a relatively slow speed because it is close to Earth. The stars, however, are much farther away and their movement is not as noticeable. This is why the stars appear to move much faster than the sun over the course of a day.
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are brought close together?
5. What happens when like magnetic poles
Answer:
When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges. Like charges repel, and unlike charges attract.
On average how fast does the radiation spread from an atom-bomb?
Answer:
around 30 grays
Explanation:
Hope this helps :)
Sun has an eective temperature of about 5800 kelvins. What is the peak wavelength emitted by the sun?
By Wien's displacement law we can conclude that, the peak wavelength emitted by the sun for 5800K temperature is 499nm.
To find the answer, we have to know about Wien's distribution law.
How to find the maximum wavelength?The black-body radiation curve for various temperatures will peak at various wavelengths that are inversely proportional to the temperature, according to Wien's displacement law.It is given that, Sun has an active temperature of about 5800 kelvins.Thus, by Wien's distribution law, the maximus wavelength is,\(wavelength*T=2.898*10^{-3}mK\\wavelength=\frac{2.898*10^{-3}mK}{5800K}=499nm.\)
Thus, by Wien's displacement law we can conclude that, the peak wavelength emitted by the sun for 5800K temperature is 499nm.
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How are solar flares different from solar prominences.
Answer:
What is the difference between a prominence and a solar flare? A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.
Explanation:
Which of the following statements about speed limits in North Carolina is correct?a. Unless otherwise posted, the speed inside a city is 35 mphb. Unless otherwise posted, the speed limit for a school activity bus is 25 mphc. Both A and Bd. Neither A nor B
The correct statement about speed limits in North Carolina is: both A and B.
In North Carolina, unless otherwise posted, the speed limit inside a city is 35 mph (statement A), and the speed limit for a school activity bus is 25 mph (statement B). Therefore, both statements A and B are correct. In North Carolina, the default speed limit for urban areas, unless otherwise indicated by posted signs, is 35 mph. This helps ensure safe driving in city environments where there are more pedestrians, intersections, and potential hazards. Similarly, the speed limit for school activity buses, unless otherwise posted, is set at 25 mph to prioritize the safety of students and accommodate the slower speed needed for frequent stops and potential loading/unloading situations. Overall, both statements A and B accurately describe the speed limits in North Carolina, indicating that the speed inside a city is 35 mph and the speed limit for a school activity bus is 25 mph.
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a 10ft branch is used to raise a 300 lbs. rock. if the branch is under the rock at the end and 3 ft from the fulcrum, how much effort would be needed?
To determine the effort needed to raise the 300 lbs rock using a 10ft branch as a lever, we can apply the principle of the lever and the concept of torque.
The formula for calculating torque is:
Torque = Force × Distance
In this case, the fulcrum is acting as the pivot point, and the effort is applied at the end of the branch. The weight of the rock is the resistance, acting 3 ft from the fulcrum. Let's denote the effort as "E" and the unknown torque as "T."
Since the system is in equilibrium, the torque exerted by the effort must equal the torque exerted by the weight of the rock:
Torque of Effort = Torque of Weight
E × 10ft = 300 lbs × 3 ft
E × 10 = 900
E = 90 lbs
Therefore, an effort of 90 lbs would be needed to raise the 300 lbs rock using the 10ft branch as a lever, with the rock positioned 3 ft from the fulcrum.
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What is the direction of net force at all points in the projectile's path?
The direction of net force at all points in the projectile's path is downwards towards the ground.
F = m a
F = Force
m = Mass
a = Acceleration
F ∝ a
The direction of net force is influenced by the direction of acceleration.
In a projectile motion, if the air resistance is considered negligible, there will be no acceleration in horizontal direction. Because, there will be no forces acting in horizontal direction. The only force acting on the projectile is the force of gravity. Gravity pulls the object downwards throughout its motion. So the direction of net force will be downwards at all points in the projectile's path.
Therefore, the direction of net force at all points in the projectile's path is downwards towards the ground.
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A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration
Answer:
1 m/s²
Explanation:
From the question,
Using
a = (v-u)/t.................... Equation 1
Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.
Given: v = 15 m/s, u = 5 m/s, t = 10 s
Substitute these values into equation 1
a = (15-5)/10
a = 10/10
a = 1 m/s²
Hence the acceleration of the bicycle is 1 m/s²
A marble was sent down a ramp into a solo cup. The first time the solo cup moved 20 cm. The second time the solo cup moved 24 cm. The third time the cup moved 16 cm. What is the average movement of the cup?
Answer:
20
Explanation:
The average of the movement is 20+24+16/2 = 20cm
Answer:
.................................................................................................... .................
Explanation:
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suppose that the internal energy of a system has been increased, resulting in an increase in the temperature of the system. which of the following is the cause of this change?
No, according to the first law, whether a certain amount of energy is added by doing work on the system or by adding heat, the internal energy will change in the same way.
A thermodynamic system's total internal energy is defined as the energy it possesses. It consists of both internal kinetic energy and potential energy contributions, and it is the energy required to develop or prepare the system in its current internal condition. The system's energy gains and losses resulting from modifications to its internal state are tracked by this mechanism. It excludes all external energies from surrounding force fields as well as the kinetic energy of the system's overall motion. The first law of thermodynamics, which is based on the idea that an isolated system's internal energy is constant, is stated as the law of conservation of energy. An vast quality is the internal energy.
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A driver of a car traveling at 15.0 m/s applies the brakes, causing a uniform acceleration of -2.0 m/s squared. How long does it take the car to accelerate to a final speed of 10.0 m/s? How far has the car moved during the braking period?
Answer:
a) 2.5secs
b) 31.25m
Explanation:
a) From the question, we are given;
Initial speed u = 15m/s
Final speed v = 10.0m/s
Acceleration =-2.0m/s²
Required
How long it takes take the car to accelerate (Time t)
Using the equation of motion
v = u+ at
10 = 15+(-2)t
10 = 15-2t
10-15 = -2t
-5 = -2t
t = 5/2
t = 2.5secs
Hence it takes the car 2.5secs to accelerates.
b) We are to find distance S
Using the equation
S = ut + 1/2at²
S = 15(2.5)+1/2(-2)(2.5)²
S = 37.5-6.25
S = 31.25m
Hence the car as moved by 31.25m during the breaking period.
Hiii I think the answer might be 3.3 seconds,not exaclty sure tho
David is 60 years old, has moderate financial health, a short time horizon, and a low risk tolerance.
David's investment strategy should reflect his financial goals, time horizon, and risk tolerance.
David is a 60-year-old individual with moderate financial health, meaning he has a stable financial situation but may have some debt or other financial obligations. He has a short time horizon, which suggests he may need his funds in the near future for retirement or other expenses.
He has a low risk tolerance, indicating that he is unwilling to take significant risks with his investments and may prefer safer, more conservative options. Based on these factors, David may want to consider investments that prioritize capital preservation, such as bonds or fixed-income securities. He may also want to work with a financial advisor to create a diversified portfolio that balances his need for stability with potential returns.
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on a highway without median dividers, you must stop at least 10 feet away from a stopped school bus, even if the bus is going in the opposite direction.
In most US states, drivers are required to stop when a school bus stops, except if it has a median divider, to allow children to cross the road safely.
These laws were established to minimize the likelihood of a child being struck by a motor vehicle while entering or exiting a school bus on a busy road. The majority of school buses are equipped with stop signals and flashing lights to inform drivers when to stop and when it is safe to proceed.
The law, however, varies by state. In some states, drivers must stop both ways, regardless of whether the bus is on the other side of the street or not. In most states, including Georgia, you must stop if you are behind the bus or on the same side of the street.
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The distance between earth and sun is 15000000km. Light takes 499 seconds to reach earth from sun. Calculate the speed of light from the data provided. Mention the unit as well.
Answer:
The speed of light is 30,060,120.24048 m/s.
Explanation:
15000000 km into m
1 km = 1000m
15000000 km = 15000000 × 1000 m
= 15000000000m
speed = distance travelled / time taken
or, speed = 15000000000/499 m/s
so, speed = 30,060,120.24048m/s
To solve the problem we must know about the relationship between Speed, distance, and Time.
What is the relationship between Speed, distance, and Time?We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
The speed of the light is 30,060.12 km/sec.
Given to us
The distance between the earth and the sun is 15000000km Light takes 499 seconds to reach earth from the sun.We know that speed can be described as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
Therefore,
What is the speed of the light?\(\text{Speed of light} = \dfrac{\text{Distance between the earth and the sun}}{\text{Time taken by the light to travel the distance}}\)
Substitute the value,
\(\text{Speed of light} = \dfrac{15,000,000\ km}{499\ seconds}\)
\(\text{Speed of light} = 30,060.12\ km/sec\)
Hence, the speed of the light is 30,060.12 km/sec.
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The scientific reference for the knee cap is the Patella. true or false
Answer:
True.
Explanation:
The kneecap is scientificlaly referenced as the Patella.
What are the factors that change the pattern observed on a screen during Young’s double-slit experiment?
The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.
The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:
1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.
2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.
3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.
4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.
5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.
When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.
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what is the period of a water wave with a frequency of 0.5 Hz?
Is the acceleration of the object at angles less than 90° greater than less than or equal to the acceleration due to gravity?
Answer:
g = 9.8 meters/second2 = 32.2 feet/second2
Acceleration is a vector, meaning it has a direction and a magnitude, so this equation really boils down to g, an acceleration straight down toward the center of the Earth. The fact that Fgravity = mg is important because it says that the acceleration of a falling body doesn’t depend on its mass:
F gravity = ma = mg
In other words, ma = mg.
Because a = g, a heavier object doesn’t fall faster than a lighter one. Gravity gives any freely falling body the same acceleration downward (g near the surface of Earth), assuming that no other forces, such as air resistance, are present.
Explanation:
which interior zone of uranus and neptune do we suspect contains the electrically conducting fluid that is responsible for planetary magnetic fields?
We hypothesize that the interior zone of uranus and neptune, which is a zone of liquid water with dissolved ammonia and methane, contains the conducting fluid that is responsible for planetary magnetic fields.
An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.
Methane and nitrate are two components essential to the quality of biogas. It is feasible to test both using a single TDLAS device because their spectral signatures are reasonably similar. Methane is extremely corrosive when combined with water and can harm pipelines.
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a simple formula for the distance traveled (x in meters) by an air car traveling a track uses the initial starting point (x0 in meters), the initial velocity (v0 in units meters per second), and the acceleration (a in units meters per second squared), and the time traveled (t in seconds).
The simple formula for the distance travelled ( in m ) by the air car is s = \(V_{0}\) t + 1 / 2 at² which is an equation of motion.
According to equations of motion,
s = ut + 1 /2 at²
where,
s = Distance travelled
u = Initial velocity
t = Time travelled
a = Acceleration
Given that,
u = \(V_{0}\)
s = \(V_{0}\) t + 1 / 2 at²
Equations of motion are used to describe position of an object as a function of time. It is done using acceleration, velocity, distance and time.
Therefore, the simple formula for the distance travelled is s = \(V_{0}\) t + 1 / 2 at²
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Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the area of each of his shoes is 6cm x 25cm.
(Take 1kg of weight = 10N)
Answer:
P = 1333.33 N
Explanation:
The pressure exerted by the boy on the floor can be calculated by the following equation:
\(P = \frac{F}{A}\)
where,
P = Pressure exerted by the boy = ?
F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)
A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)
A = 2(0.06 m x 0.25 m) = 0.03 m²
Therefore,
\(P = \frac{40\ N}{0.03\ m^2}\\\\\)
P = 1333.33 N
(b)
On what factor does the mechanical advantage of a simple machine depend?
(a) N/m
B.
Very short answer questions,
1.
What is the principle of simple machine?
2.
3.
The efficiency of simple machine is 75%. What does it mean?
4.
S.
What is lever?
In how many classes is lever classified?
Write the name of a simple machine used to change the direction of force.
6.
0
Reliant Science - 9
Answer:
B. 1. The factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort
2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both
3. A 75% efficiency of a simple machine means that the power of the frictional force is one quarter of the power of the input force
4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be applied
5. There are three classes of lever
6. A pulley
Explanation:
B. 1. For simple machines, we have the Ideal Mechanical Advantage, IMA, given as follows;
\(IMA = \dfrac{F_r}{F_e} = \dfrac{d_e}{d_r}\)
Where;
\(F_r\) = The resistance force (The load)
\(F_e\) = The effort force
\(d_e\) = The distance moved by the effort
\(d_r\) = The distance the load is moved
Therefore, the factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort
2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both
3. The mechanical efficiency of a simple machine, η, can be expressed as follows;
\(\eta =\dfrac{P_{out}}{P_{in}}\)
Where;
\(P_{out}\) = The power at output
\(P_{in}\) = The input power
\(P_{in}\) = \(P_{out}\) + \(P_{friction}\)
\(P_{friction}\) = The frictional force's power
Therefore, an efficiency of 75% means that we have;
\(P_{out}\) = η × \(P_{in}\) = 0.75 × \(P_{in}\) = 0.75·\(P_{in}\)
From which we have;
\(P_{in}\) = \(P_{out}\) + \(P_{friction}\) = 0.75·\(P_{in}\) + \(P_{friction}\)
∴ \(P_{friction}\) = \(P_{in}\) - 0.75·\(P_{in}\) = 0.25·\(P_{in}\)
Therefore, 75% efficiency of a simple machine means that the power of the frictional force is 0.25 × (or one quarter of) the power of the input force
4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be applied
5. There are three classes of lever
(a) First class lever (b) Second class lever and (c) Third class lever
6. A pulley
A pulley acts by lifting a load upward from a downward applied force.
Explanation:
B. 1. The factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort
2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both
3. A 75% efficiency of a simple machine means that the power of the frictional force is one quarter of the power of the input force
4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be applied
5. There are three classes of lever
6. A pulley
Explanation:
B. 1. For simple machines, we have the Ideal Mechanical Advantage, IMA, given as follows;
IMA = \dfrac{F_r}{F_e} = \dfrac{d_e}{d_r}IMA=
F
e
F
r
=
d
r
d
e
Where;
F_rF
r
= The resistance force (The load)
F_eF
e
= The effort force
d_ed
e
= The distance moved by the effort
d_rd
r
= The distance the load is moved
Therefore, the factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort
2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both
3. The mechanical efficiency of a simple machine, η, can be expressed as follows;
\eta =\dfrac{P_{out}}{P_{in}}η=
P
in
P
out
Where;
P_{out}P
out
= The power at output
P_{in}P
in
= The input power
P_{in}P
in
= P_{out}P
out
+ P_{friction}P
friction
P_{friction}P
friction
= The frictional force's power
Therefore, an efficiency of 75% means that we have;
P_{out}P
out
= η × P_{in}P
in
= 0.75 × P_{in}P
in
= 0.75·P_{in}P
in
From which we have;
P_{in}P
in
= P_{out}P
out
+ P_{friction}P
friction
= 0.75·P_{in}P
in
+ P_{friction}P
friction
∴ P_{friction}P
friction
= P_{in}P
in
- 0.75·P_{in}P
in
= 0.25·P_{in}P
in
Therefore, 75% efficiency of a simple machine means that the power of the frictional force is 0.25 × (or one quarter of) the power of the input force
4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be applied
5. There are three classes of lever
(a) First class lever (b) Second class lever and (c) Third class lever
6. A pulley
A pulley acts by lifting a load upward from a downward applied force.
a. is wrong. What is the answer!?? Im so confused
Given:
a.
\(60.0\text{ mg}\)b.
\(0.354\text{ cm}\)To find:
a. mg into km
b. cm into nm
Explanation:
a.
\(\begin{gathered} 60.0\text{ mg} \\ =60.0\times10^{-6}\text{ kg} \\ =6.0\times10^{-5}\text{ kg} \\ =0.00006\text{ kg} \end{gathered}\)Hence,
\(60.0\text{ mg=0.00006 kg}\)b.
\(\begin{gathered} 0.354\text{ cm} \\ =0.354\times10^{-2}\text{ m} \\ =0.354\times10^7\times10^{-9}\text{ m} \\ =3540000\text{ nm} \end{gathered}\)Hence,
\(0.354\text{ cm=3540000 nm}\)Explain the relationship between the frequency, energy, and wavelength of a wave.
Answer:
Explanation:
The energy equation is E=hv
Using insert sort on the following array: v = [82; 91; 13; 92; 64; 10]; after two full insert process, what is the resultant array?
The resultant array is v = [10; 13; 82; 91; 92; 64].
To perform an insertion sort, we start with the first element of the array and iterate through the remaining elements. For each element, we compare it with the elements before it and insert it in the correct position.
Given the array v = [82; 91; 13; 92; 64; 10], let's perform two full insert processes:
1. First insert process:
- v = [82; 91; 13; 92; 64; 10]
- Compare 91 with 82. Since 91 is greater, no change is needed.
- Compare 13 with 91 and 82. Move 13 to the beginning of the array.
- v = [13; 82; 91; 92; 64; 10]
2. Second insert process:
- v = [13; 82; 91; 92; 64; 10]
- Compare 82 with 13. Since 82 is greater, no change is needed.
- Compare 91 with 82 and 13. Since 91 is greater, no change is needed.
- Compare 92 with 91, 82, and 13. Move 92 to the end of the array.
- Compare 64 with 92, 91, 82, and 13. Move 64 to the correct position between 13 and 82.
- Compare 10 with 64, 92, 91, 82, and 13. Move 10 to the beginning of the array.
- v = [10; 13; 82; 91; 92; 64]
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